Search Results

Search found 6908 results on 277 pages for 'username 4567'.

Page 20/277 | < Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >

  • Get with the ajax data into a php file

    - by Max Torstensson
    I'm trying to build a login system with ajax and php. I use a log-view where I then save the data in ajax which brings into my doLogin.php (php file). My problem is that php file should never be any ajax data for when I build it into a class and a function VIEW: public function DoLoginBox() { //inloggning form-tagg... return '<p>&nbsp;</p> <div id="content"> <h1>Login Form</h1> <form id="form1" name="form1" action="Handler/doLogin.php" method="post"> <p> <label for="username">Username: </label> <input type="text" name="username" id="username" /> </p> <p> <label for="password">Password: </label> <input type="password" name="password" id="password" /> </p> <p> <input type="submit" id="login" name="login" /> </p> </form> <div id="message"></div> </div>'; } AJAX: <script type="text/javascript"> $(document).ready(function() { $("#login").click(function() { var action = $("#form1").attr('action'); var form_data = { username: $("#username").val(), password: $("#password").val(), is_ajax: 1 }; $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') $("#form1").slideUp('slow', function() { $("#message").html("<p class='success'>You have logged in successfully!</p>"); }); else $("#message").html("<p class='error'>Invalid username and/or password.</p>"); } }); return false; }); }); </script PHP: <?php require_once ("UserHandler.php"); class DoLogingHandler{ public function Login (){ $is_ajax = !empty($_REQUEST['is_ajax']); if(isset($is_ajax) && $is_ajax) { $username = $_REQUEST['username']; $password = $_REQUEST['password']; $UserHandler = new UserHandler(); $UserHandler -> controllDB($username,$password); if($username == 'demo' && $password == 'demo') { echo "success"; } } } } ` $DoLogingHandler = new DoLogingHandler(); $DoLogingHandler-Login(); ?

    Read the article

  • Is there an easy way to add a secure file upload form (username, password, select file) to a website

    - by user346602
    Hi, I am very new to website design. Have an architect who wants his clients to enable his clients to upload (ftp - but don't know if http could be a better alternative?) files (plans etc.) to him, through the website I'm designing for him. I have seen similar things available on printers websites... I have seen uploadify, but it requires flash (I can only code HTML, CSS and a tiny bit of PHP), and don't think it is a secure option. I have also seen net2ftp, but don't really understand how it works. Any direction would be sincerely appreciated.

    Read the article

  • Davical + LDAP + NTLM

    - by slavizh
    I have set up a Davical server on CentOS. I've configured it to use LDAP and the users use their usernames and passwords to authenticate to the Davical server. I am using Lightning as client software for calendaring. Using Lightning requires entering username and password everytime, so I decided to set NTLM. I want my users who are logging in the domain to use the calendar server trough Lightning without entering username and password. I've set up NTLM on the Davical server. But when a user trys to reach the calendar trough Lightning first the server asks for NTLM username and password and then ask for the LDAP username and password. It becomes something like double authentication. The problem is that NLTM requires domain\username and passowrd and Davical trough LDAP requires only username and password. So my questions are: Is there a way to change something in Davical so that Davical trough LDAP to requires domain\username and passwords authentication? That way may be trough NTLM the second authentication will proceed silently and the users will user Lightning without entering usernames and passwords Is there a way I can make this double authentication to become one and to use only NTLM? P.S. We have Samba domain with LDAP server and our users use Thunderbird for their mail and I want to put Lightning too. That way they will have calendar service. But I don't want they to enter username and password for the calendar every time they log in. I know they can save that password but that is not an option for my organization.

    Read the article

  • How to Access User Directory shared by Apache on OS X Mountain Lion?

    - by schluchc
    When trying to access the local user web page on localhost/~username, I get a "403 Forbidden". The system web page in /Library/WebServer/Documents is accessible on localhost/ though, so I assume Apache is working fine. I know that this problem has been discussed several times, also on superuser. I implemented and checked all I could find, but I still couldn't solve the problem and would be glad if someone had a suggestion for this particular case: sudo apachectl -t returns Syntax OK. I have a username.conf file in /etc/apache2/users/: <Directory "/Users/username/Sites/"> Options Indexes MultiViews FollowSymLinks AllowOverride AuthConfig Limit Order allow,deny Allow from all </Directory> as proposed here [SuperUser] and in several other tutorials. The permissions of the username.conf file are -rw-r--r-- root wheel, as they should be. The httpd.conf is unchanged and therefore contains the line Include /private/etc/apache2/extra/httpd-userdir.conf. That file in turn contains UserDir Sites Include /private/etc/apache2/users/*.conf <IfModule bonjour_module> RegisterUserSite customized-users </IfModule> So the httpd*.conf files should be ok. The permissions of /Users/username/Sites is drwxr-xr-x 10 username staff and -rw-r--r--@ 1 username staff for the index.html. In the error log I simply get a [Sun Nov 25 22:14:32 2012] [error] [client 127.0.0.1] (13)Permission denied: access to /~username/ denied. And yes, after each change I did the sudo apachectl restart. Any help no how to solve the problem or how to further analyze it would be highly appreciated!

    Read the article

  • XMPP SASL authentication on Ejabberd with PHP

    - by bucabay
    I'm trying to authenticate with an XMPP server using SASL. /** * Send Authentication, SASL * @return Bool * @param $username String * @param $password String */ function authenticate($username, $password) { $this->username = $username; $this->password = $password; var_dump($username, $password, $this->domain); $auth = base64_encode($username.'@'.$this->domain."\u0000".$username."\u0000".$password); $xml = '<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">'.$auth.'</auth>'; if ($this->write($xml)) { if ($xml = $this->listen(1, true)) { if (preg_match("/<success/i", $xml)) { $this->authenticated = $this->_sendStream(); } } } $this->events->trigger('authenticate', $this->authenticated); return $this->authenticated; } The XMPP server however responds with: <failure xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><bad-protocol/></failure> This is against an Ejabberd server. When I open the XMPP stream, it advertises: <stream:features><starttls xmlns='urn:ietf:params:xml:ns:xmpp-tls'/><mechanisms xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><mechanism>DIGEST-MD5</mechanism><mechanism>PLAIN</mechanism></mechanisms><register xmlns='http://jabber.org/features/iq-register'/></stream:features> So it seams to me that SASL - PLAIN should work. I have a JavaScript version, that works perfectly on OpenFire server. (I can't test it on Ejabberd at the moment) sendAuthentication: function() { clearTimeout(XMPP.sendAuthentication_timer); var auth = Base64.encode(XMPP.username+'@'+XMPP.domain+'\u0000'+XMPP.username+'\u0000'+XMPP.password); mySocket.events.receive.observe(XMPP.receivedAuthSuccess, function() { mySocket.send('<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">' + auth + '</auth>'); }); } So I can't get why the PHP version is not working.

    Read the article

  • log in using fitnesse

    - by user1513027
    This is a basic HTTP encoding and formatting question. I need to log in from a RESTFixture to a PHP web service. I need to pass in the account, username, and password, as POST variables just as a login page does. Wireshark shows that my login page formats it as accountNumber=accounttest&username=usertest&password=passtest When I do that in the test, I get a POST array of $_POST: Array ( [accountNumber] => accounttest [amp;username] => usertest [amp;password] => passtest ) That would work but the "amp;" obviously makes it so that PHP doesn't find the username. Content type is the same for both live and the test. [CONTENT_TYPE] = application/x-www-form-urlencoded Here are a few other formats I've tried with results. In all three cases, it fails to parse so all fields end up in one array entry. input: accountNumber=accounttest%amp;username=usertest%amp;password=passtest Result: $_POST: Array ( [accountNumber] = accounttest%amp;username=usertest%amp;password=passtest ) input: accountNumber=accounttest;username=usertest;password=passtest Result: $_POST: Array ( [accountNumber] => accounttest;username=usertest;password=passtest ) input: accountNumber=accounttest%26username=usertest%26password=passtest Result: $_POST: Array ( [accountNumber] = accounttest&username=usertest&password=passtest ) So the last one correctly converts the %26 to &, but doesn't break the items apart into array elements.

    Read the article

  • Membership.Updateuser not really updating the database.

    - by Shimrod
    Hi everybody, I'm currently working on a membership system for my web application, which is based on forms authentication from the framework. I created some users with the integrated tool, and the login is perfectly working. But now what I want to do is to give administrator the capability to create, modify, delete users. So here is what I've got right now: Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim muc As MembershipUserCollection = Membership.GetAllUsers() ComboBox1.DataSource = muc ComboBox1.DataValueField = "UserName" ComboBox1.DataTextField = "UserName" ComboBox1.DataBind() End Sub Protected Sub ComboBox1_SelectedIndexChanged(ByVal sender As Object, ByVal e As EventArgs) Handles ComboBox1.SelectedIndexChanged Dim userName As String = ComboBox1.SelectedValue Dim mu As MembershipUser = Membership.GetUser(userName) Dim userRoles As String() = Roles.GetRolesForUser(userName) tbComments.Text = mu.Comment tbEmail.Text = mu.Email lblUserName.Text = mu.UserName End Sub Protected Sub Button1_Click(ByVal sender As Object, ByVal e As EventArgs) Handles Button1.Click Dim userName As String = ComboBox1.SelectedValue Dim mu As MembershipUser = Membership.GetUser(userName) If Not mu Is Nothing Then Try mu.Comment = tbComments.Text Membership.UpdateUser(mu) mu.Email = tbEmail.Text Membership.UpdateUser(mu) mu.IsApproved = True Membership.UpdateUser(mu) mu = Nothing Catch ex As Exception Console.WriteLine(ex.ToString()) End Try End If DetailPanel.Visible = False End Sub The problem is that the record doesn't seem to be updated in the database. I made the multiple calls to Membership.UpdateUser after reading this blog entry, but it didn't change anything. A strange think I noticed while debugging, is that when I enter the Button1_Click method, Membership.GetUser(userName) returns me values from my precedent attempt ! I don't really understand what I'm missing. Does someone have a clue ? Thanks in advance !

    Read the article

  • Java reading xml element without prefix but within the scope of a namespace

    - by wsxedc
    Functionally, the two blocks should be the same <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <userInfo> <username>superuser</username> <password>qapass</password> </userInfo> </ns1:login> </soapenv:Body> ----------------------- <soapenv:Body> <ns1:login xmlns:ns1="urn:soap.sof.com"> <ns1:userInfo> <ns1:username>superuser</ns1:username> <ns1:password>qapass</ns1:password> </ns1:userInfo> </ns1:login> </soapenv:Body> However, how when I read using AXIS2 and I have tested it with java6 as well, I am having a problem. MessageFactory factory = MessageFactory.newInstance(); SOAPMessage soapMsg = factory.createMessage(new MimeHeaders(), SimpleTest.class.getResourceAsStream("LoginSoap.xml")); SOAPBody body = soapMsg.getSOAPBody(); NodeList nodeList = body.getElementsByTagNameNS("urn:soap.sof.com", "login"); System.out.println("Try to get login element" + nodeList.getLength()); // I can get the login element Node item = nodeList.item(0); NodeList elementsByTagNameNS = ((Element)item).getElementsByTagNameNS("urn:soap.sof.com", "username"); System.out.println("try to get username element " + elementsByTagNameNS.getLength()); So if I replace the 2nd getElementsByTagNameNS with ((Element)item).getElementsByTagName("username");, I am able to get the username element. Doesn't username have ns1 namespace even though it doesn't have the prefix? Am I suppose to keep track of the namespace scope to read an element? Wouldn't it became nasty if my xml elements are many level deep? Is there a workaround where I can read the element in ns1 namespace without knowing whether a prefix is defined?

    Read the article

  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

    Read the article

  • Sending a password securely using gwt and app engine?

    - by user246114
    Hi, I set up session handling on a google app project. This is supposed to allow my users to login and maintain state across pages. I just dumped it into the default greeting service to try it out: public class GreetingServiceImpl extends RemoteServiceServlet implements GreetingService { public void sessionTest(String username) { HttpSession session = getThreadLocalRequest().getSession(false); session.setAttribute("username", username); } } then attempting to pull it out in my landing project.jsp page: <% String username = null; HttpSession mysession = request.getSession(false); if (mysession.getAttribute("username") != null) { username = (String)mysession.getAttribute("username"); } else { username = "(not logged in yet)"; } <p>You are: <%= username %> </p> %> It works, but I don't know how to send the data in sessionTest() securely. If I were sending the user's password in there too, it would be in the clear. This would be ok (I think) if I was using https, but google app engine does not allow you to use https under custom domains (like www.mysite.com), they have to be under the (mysite.appspot.com) domain. I'm kind of stuck here - how do we send passwords securely? If I was using php, I think I could use digest authentication (I'm not too experienced here) - can we do something like that with gwt + gae? Thanks

    Read the article

  • Expressjs route param as variable in main app

    - by MoDFoX
    For my app I have two route set up, app.get('/', routes.index); app.get('/:name', routes.index); I would like it to be so that if I don't specify a param, say just go to appurl.com (localhost:3000), it would load a default user, but if I do specify a param(localhost:3000/user), use that as the variable "username" in the following function (placed after my routes). (function getUser(){ var body = '', username = 'WillsonSM', options = { host: 'ws.audioscrobbler.com', port: 80, path: '/2.0/?method=user.gettopartists&user=' + username + '&format=json&limit=20&api_key=APIKEYGOESHERE' }; require('http').request(options, function(res) { res.setEncoding('utf8'); res.on('data', function(chunk) { body += chunk; }); res.on('end', function() { body = JSON.parse(body); artists = body.topartists.artist; }); }).end(); })(); Along with this I have my route set up like so: exports.index = function(req, res){ res.render('index', { title: 'LasTube' }); username = req.params.name; console.log(username); }; unfortunately setting username there to req.params.name does not seem to be accessible from the main app function. My question is: How can I set expressjs/nodejs to use the parameter set via /name when available, and just use a default - in this example "WillsonSM" if not available. I've tried taking "username" out of the main app, and just leaving it in the function, but username becomes undefined, as it is inaccessible from the route, and the app will not run. I can spit out "username" via the routes console.log, so assigning it there is not an issue, but as I am new to expressjs, I am unaware of how I should go about doing this. I have tried all I can think of and find from looking around the internet. Also, if there is a better way of doing this, or I am doing something wrong, please let me know. If I've left out any information, just throw in a comment and I'll try to address it.

    Read the article

  • Use jQuery.post() result in javascript function

    - by Juvlius
    I've got no clue how to do the following, so I wasn't sure what to search for either. For validating my registration form I've a javascript function that checkes the existence of the inserted username in the database onblur of the username textfield. function checkUsername(username){ $.post("checkmail.php", {mail: mailcheck} , function(data){ var $response=$(data); var response = $response.filter('#mail-response').text(); if(response == "taken") { document.getElementById('username').style.borderColor = rood; valid = false; } }); } This works fine, but now I want to validate it again onsubmit of the form in case users decide to submit an existing username. function validateForm() { var valid = true; //checks different fields //now check voor username existence var username = document.getElementById('username').value; checkUsername.call(username); if (!valid) { return false; } else { return true; } } I'm not familiar enough with Javascript to get this working. Probably thinking in the wrong direction...

    Read the article

  • Why does PHP create these log entries on every page access?

    - by HXCaine
    My server's error log (in cPanel) has an entry for every single time a PHP page is loaded that looks like this (where 'username' has been substituted for my actual username): [2012-06-09 09:02:07]: info: [usr/grp]: username/username cmd: /home/username/public_html/error.php php: /usr/local/php53/bin/php I know it's only an 'info' message but it's filling up my error log. It can't be related to the content of my PHP files because it even happens when I load a page with this as its content: <?php phpinfo(); ?> Any ideas on what it means or if I can get rid of it?

    Read the article

  • tomcat6 manager

    - by Bary W Pollack
    I've just installed Ubuntu 10.04 LTS Server with LAMP support. Tomcat6 seems to run ok. But, I am unable to get into the manager-webapp... I've updated the tomcat-users.xml file: <?xml version='1.0' encoding='utf-8'?> <tomcat-users> <role rolename="tomcat"/> <role rolename="role1"/> <role rolename="manager"/> <role rolename="admin"/> <user username="tomcat" password="tomcat" roles="tomcat,manager,admin"/> <user username="both" password="tomcat" roles="tomcat,role1"/> <user username="role1" password="tomcat" roles="role1"/> <user username="admin" password="admin" roles="manager,admin"/> </tomcat-users> But, no matter what I try, it keeps rejecting my username/password combo. What might I be missing?

    Read the article

  • How to setup Cocos2D-X (Android) under Mac OS X?

    - by Beast
    Hi I've made a small game for iPhone that I also want to run on Android but I'm having problems setting up Cocos2D-X for Android. I've downloaded and installed Android SDK and NDK (under my "/Users/username/Android"). Installed all necessary packages under SDK and created an Emulator. Copied Cocos2D-x under "/Users/username/cocos2dx". Installed Eclipse IDE with ADT Plugin. Opened "Users/username/cocos2dx/tests/build_native.sh" and changed "NDK_ROOT_LOCAL=/Users/username/Android/android-ndk", "COCOS2DX_ROOT_LOCAL=/Users/username/cocos2dx" to the values shown. On running the script using Terminal it compiles test project. What's next?

    Read the article

  • set focus in unfilled edittext how can implemented android application

    - by narasimha
    hi I am implementing one application gust i am adding validations in login page implemented then two fields required username and password button login i am applying validations then focus are not getting then set focus in unfilled edittext if(Username.contentEquals("")) { > Toast.makeText(LBS.this, "Please enter > username ",Toast.LENGTH_SHORT).show(); > } else { if( pwd.contentEquals("")) > Toast.makeText(LBS.this, "Please enter > password ",Toast.LENGTH_SHORT).show(); > else > try { ........................... } not filling username then filling password then username entered some toast displayed fine focus are entered in username edittext this is the problem how can implemented focus in unfilled username

    Read the article

  • how to get data in sheet2 from sheet1 in excel

    - by romen-leung
    I have two worksheets, Sheet1 Column A = Deptname Column B = Headname Column C = Username Sheet2 Column A = Headname (???) Column B = Username Column C = UserID "Headname" column in Sheet2 is blank and what I wanted to do is to get "Headname" from Sheet1 by using "Username". I have tried to use VLookup but it did not work if username in Sheet1 and Sheet2 is not exactly same. E.G, given two differents Username as shown on below. Username in Sheet1 is "Jenny Oh" and "Chan Shu Mei" Username in Sheet2 is "ITC - Jenny Ong" and "IA: Chan Shu Mei" Any ideas whether it can be done? Thankf in advance for any help.

    Read the article

  • Import SQL dump into MySQL

    - by BryanWheelock
    I'm confused how to import a SQL dump file. I can't seem to import the database without creating the database first in MySQL. This is the error displayed when database_name has not yet been created: username = username of someone with access to the database on the original server. database_name = name of database from the original server $ mysql -u username -p -h localhost database_name < dumpfile.sql Enter password: ERROR 1049 (42000): Unknown database 'database_name' If I log into MySQL as root and create the database, database_name mysql -u root create database database_name; create user username;# same username as the user from the database I got the dump from. grant all privileges on database_name.* to username@"localhost" identified by 'password'; exit mysql then attempt to import the sql dump again: $ mysql -u username -p database_name < dumpfile.sql Enter password: ERROR 1007 (HY000) at line 21: Can't create database 'database_name'; database exists How am I supposed to import the SQL dumpfile?

    Read the article

  • Use of Java constructors in persistent entities

    - by Mr Morgan
    Hello I'm new to JPA and using persistence in Java anyway and I have two questions I can't quite work out: I have generated tags as: @JoinColumn(name = "UserName", referencedColumnName = "UserName") @ManyToOne(optional = false) private User userName; @JoinColumn(name = "DatasetNo", referencedColumnName = "DatasetNo") @ManyToOne(optional = false) private Dataset datasetNo; But in one of the constructors for the class, no reference is made to columns UserName or DatasetNo whereas all other columns in the class are referenced in the constructor. Can anyone tell me why this is? Both columns UserName and DatasetNo are 'foreign keys' on the entity Visualisation which corresponds to a database table of the same name. I can't quite work out the ORM. And when using entity classes, or POJO, is it better to have class variables like: private User userName; Where an instance of a class is specified or simply the key of that class instance like: private String userName; Thanks Mr Morgan.

    Read the article

  • User not being saved, SharedPreferences

    - by Lars
    Hi i have a inlogscreen (inlogdialog.xml), which includes 2 EditText (username, passwd) and i have a CheckBox (saveuser) with which the user can decide weather to save the username or not. On the mainform (main.xml) i have a listner for these 3 values: private class OnReadyListener implements MyCustomForm.ReadyListener { public void ready(String user, String pass, boolean save) { username = user; password = pass; } } Now i first want to save the username through SharedPreferences but it doesn`t get saved, can someone help me please? If i check with system.out.println, the username is present in String username. SharedPreferenes code in main.xml: public static final String USERNM = ""; private SharedPreferences mPrefs; ....... @Override protected void onPause() { Editor e = mPrefs.edit(); e.putString(USERNM, username); <---- e.commit(); Toast.makeText(this, "Items saved.", Toast.LENGTH_SHORT).show(); super.onPause(); }

    Read the article

  • Passing variables to functions in Python

    - by brno792
    Im writing test scripts in python for selenium web testing. How do I pass parameters through a python function to call in a later function? I first have a login test function. Then I have a new user registration function. Im trying to pass the Username and Password I use in the registration function to the testLogin function that I call inside the testRegister function. This is my python code: userName = "admin" password = "admin" #pass username and password variables to this function def testLogin(userName,password): browser = webdriver.Firefox() browser.get("http://url/login") element = browser.find_element_by_name("userName") element.send_keys(userName) element = browser.find_element_by_name("userPassword") element.send_keys(password) element.send_keys(Keys.RETURN) browser.close() # test registration def testRegister(): browser = webdriver.Firefox() browser.get("http://url/register") #new username variable newUserName = "test" element = browser.find_element_by_name("regUser") element.send_keys(newUserName) #new password variable newUserPassword = "test" element = browser.find_element_by_name("regPassword") element.send_keys(newUserPassword) # #now test if user is registered, I want to call testLogin with the test user name and pw. testLogin(newUserName,newUserPassword) browser.close()

    Read the article

  • clean method for validation

    - by apoorva
    hi.. i have the following form class with corresponding clean methods... class SOFIATMUserLogin(forms.Form): Username=forms.CharField(label='Username') Password=forms.CharField(label='Password', widget=forms.PasswordInput) def clean_Username(self): user=self.cleaned_data['Username'] try: SOFIALogin.objects.get(UserName=user) except Exception: raise forms.ValidationError('Username invalid...') def clean_Password(self): upass=self.cleaned_data['Password'] In the clean_Password method i wish to check if the password entered for the valid username is correct... So i need to get the Username value... How can i access this in clean_Password method... Please assist!!!!

    Read the article

  • jquery ajax form function(data)

    - by RussP
    Can some one please tell me where I have gone wrong. What ever I do I get the answer "no" JQuery to send data to php query $j.post("logincheck.php",{ username:$j('#username').attr('value'), password:$j('#password').attr('value'), rand:Math.random() } , function(data) { if(data=='yes') {alert('yes');} else {alert('no');} } ); Here is the php query if(isset($_POST['username'])): $username = $_POST['username']; $password = $_POST['password']; $posts = mysql_query("SELECT * FROM users WHERE username='$username'"); $no_rows = mysql_num_rows($posts ); while($row = mysql_fetch_array($posts)): print 'yes'; endwhile; else: print 'no'; //header('location: index.php'); endif; endif; Thank in adance

    Read the article

< Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >