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  • Database insertion not happening

    - by Pramod Setlur
    int i=0; ContentValues values = null; for ( SortedMap.Entry<Integer, String> entry : mapDefect.entrySet() ) { if( i++ < count ) continue; if( i < arrlst.size() ) { values = new ContentValues(); Log.d("MAP", "Id :"+entry.getKey()+"Des :"+entry.getValue()+"Co :"+ arrlst.get(i)); values.put( MARKER_COORD, arrlst.get( i ) ); values.put( MARKER_ID, entry.getKey() ); values.put( DEFECT_DESCRIPTION, entry.getValue() ); values.put( IMAGE_ID_F, imageID + 1 ); Log.d( "Err", "in insertNewDefectsDescription" ); long rowId = db.insert( TABLE_DEFECTS, null, values ); long rowId1 = rowId; i++; } } So, I want to access the arraylist only after the count variable, which is why the:- if(i++<count) continue; But, when I insert a break point at the 'insert' line, it is not working. The line is not executing at all, and hence the data is not being inserted into the database. What has gone wrong?? The 'values' are null.

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  • Problems with Database Search Code (asp.net vb)

    - by Phil
    Here is a sample of my database search code: Dim sql As String = "Select * From Table Where " Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim andor As Boolean = AndOr1.SelectedValue 'selection can be AND or OR (0 / 1) 'Code for when the user selects AND If NameSearch.Text.ToString IsNot String.Empty And andor = 0 Then sql += "Surname LIKE '%" & name & "%' AND " End If If EmailSearch.Text.ToString IsNot String.Empty And andor = 0 Then sql += "Email LIKE '%" & email & "%' AND " End If If CitySearchBox.Text.ToString IsNot String.Empty And andor = 0 Then sql += "City LIKE '%" & city & "%' AND " End If 'Code for when the user selects OR If NameSearch.Text.ToString IsNot String.Empty And andor = 1 Then sql += "(Surname LIKE '%" & name & "%' OR " End If If EmailSearch.Text.ToString IsNot String.Empty And andor = 1 Then sql += "Email LIKE '%" & email & "%') OR " End If If CitySearchBox.Text.ToString IsNot String.Empty And andor = 1 Then sql += "(City LIKE '%" & city & "%' OR " End If sql = CleanString(sql) End Sub When the user selects AND (as andor.selectedvalue(0)) then the sql is produced fine like this; Select * From Table Where Surname LIKE '%test%' AND Email LIKE '%test%' AND City LIKE '%test%' But if the user selects OR (as andor.selectedvalue(1)), nothing is outputted except; Select * From Table Where Im sure the controls have values so are not string.empty and when the user selects OR the correct value 1 is being assigned to andor.

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  • Adding with PHP to a MySQL database

    - by shinjuo
    I am pretty new to PHP and I am trying to make an inventory database. I have been trying to make it so that a user can enter a card ID and then amount the want to add to the inventory and have it update the inventory. For example someone could type in test and 2342 and it would update test. Here is what I have been trying with no success: add.html <body> <form action="add.php" method="post"> Card ID: <input type="text" name="CardID" /> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> </body> </html> add.php <?php $link = mysql_connect('tulsadir.ipowermysql.com', 'cbouwkamp', '!starman1'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("tdm_inventory", $link); $add = $_POST[Add] mysql_query("UPDATE cardLists SET AmountLeft = '$add' WHERE cardID = 'Test'"); echo "test successful"; mysql_close($link); ?>

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  • Database locking: ActiveRecord + Heroku

    - by JP
    I'm building a Sinatra based app for deployment on Heroku. You can imagine it like a standard URL shortener but where old shortcodes expire and become available for new URLs (I realise this is a silly concept but its easier to explain this way). I'm representing the shortcode in my database as an integer and redefining its reader to give a nice short and unique string from the integer. As some rows will be deleted, I've written code that goes thru all the shortcode integers and picks the first free one to use just before_save. Unfortunately I can make my code create two rows with identical shortcode integers if I run two instances very quickly one after another, which is obviously no good! How should I implement a locking system so that I can quickly save my record with a unique shortcode integer? Here's what I have so far: Chars = ('a'..'z').to_a + ('A'..'Z').to_a + ('0'..'9').to_a CharLength = Chars.length class Shorts < ActiveRecord::Base before_save :gen_shortcode after_save :done_shortcode def shortcode i = read_attribute(:shortcode).to_i return '0' if i == 0 s = '' while i > 0 s << Chars[i.modulo(CharLength)] i /= 62 end s end private def gen_shortcode shortcode = 0 self.class.find(:all,:order=>"shortcode ASC").each do |s| if s.read_attribute(:shortcode).to_i != shortcode # Begin locking? break end shortcode += 1 end write_attribute(:shortcode,shortcode) end def done_shortcode # End Locking? end end

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  • Not able to insert data in the database from a form in php

    - by Prashant Baid
    I am not able to insert data into my data, i dont know what the problem is. Here is the code: mysql_select_db("mitestore", $con); */ if ((isset($_POST['product_name'])) && (strlen(trim($_POST['product_name'])) 0)) { $product_name = stripslashes(strip_tags($_POST['product_name'])); $sql="INSERT INTO sell (product_name) VALUE ('$_POST[product_name]')"; } else {$product_name = 'Please enter the product name.';} if ((isset($_POST[''])) && (strlen(trim($_POST['how_old'])) 0)) { $how_old = stripslashes(strip_tags($_POST['how_old'])); $sql="INSERT INTO sell (how_old) VALUE ('$_POST[how_old]')"; } else {$how_old = 'Please enter how old your product is';} if ((isset($_POST['which_block'])) && (strlen(trim($_POST['which_block'])) 0)) { $which_block = stripslashes(strip_tags($_POST['which_block'])); $sql="INSERT INTO sell (which_block) VALUE ('$_POST[which_block]')"; } else {$which_block = 'Please enter which block are you from';} if ((isset($_POST['room_no'])) && (strlen(trim($_POST['room_no'])) 0)) { $room_no = stripslashes(strip_tags($_POST['room_no'])); $sql="INSERT INTO sell (room_no) VALUE ('$_POST[room_no]')"; } else {$room_no = 'Please enter the room no:';} if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Success!"; mysql_close($con) ? Initially i had this code and it worked for me. mysql_select_db("database", $con); $sql="INSERT INTO sell ( product_name, how_old , selling_price, negotiable, which_block, room_no) VALUES ('$_POST[product_name]','$_POST[how_old]','$_POST[selling_price]','$_POST[negotiable]','$_POST[which_block]','$_POST[room_no]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your product is added."; mysql_close($con) ? But i don't know how to validate each field individually.

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  • A little confused about MVC and where to put a database query

    - by jax
    OK, so my Joomla app is in MVC format. I am still a little confused about where to put certain operations, in the Controller or in the Model. This function below is in the controller, it gets called when &task=remove. Should the database stuff be in the Model? It does not seem to fit there because I have two models editapp (display a single application) and allapps (display all the applications), now which one would I put the delete operation in? /** * Delete an application */ function remove() { global $mainframe; $cid = JRequest::getVar( 'cid', array(), '', 'array' ); $db =& JFactory::getDBO(); //if there are items to delete if(count($cid)){ $cids = implode( ',', $cid ); $query = "DELETE FROM #__myapp_apps WHERE id IN ( $cids )"; $db->setQuery( $query ); if (!$db->query()){ echo "<script> alert('".$db->getErrorMsg()."');window.history.go(-1); </script>\n"; } } $mainframe->redirect( 'index.php?option=' . $option . '&c=apps'); } I am also confused about how the flow works. For example, there is a display() function in the controller that gets called by default. If I pass a task, does the display() function still run or does it go directly to the function name passed by $task?

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  • Storing data in a MySQL database using MySQL & PHP

    - by comma
    I'm new to PHP and MySQL and I'm trying to store a users entered data from the following fields $skill, $experience, $years which a user can also add additional fields of $skill, $experience, $years if needed so in instead of 1 of each field there might be multiples of each field. I was wondering how can I store the fields in my MySQL database using PHP and MySQL? I have the following script but I know its wrong. can some one help me fix the script listed below? Here is the PHP and MySQL code. $skill = serialize($_POST['skill']); $experience = serialize($_POST['experience']); $years = serialize($_POST['years']); for (($s = 0; $s < count($skill); $s++) && ($x = 0; $x < count($experience); $x++) && ($g = 0; $g < count($years); $g++)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = "INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill[$s] . "', '" . $experience[$x] . "', '" . $years[$g] . "')"; if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } } Here is my MySQL table. CREATE TABLE learned_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill TEXT NOT NULL, experience TEXT NOT NULL, years INT NOT NULL, PRIMARY KEY (id) ); CREATE TABLE u_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, users_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) );

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  • Error or not and insert to database mysql

    - by Azzyh
    Why wont this work? <?php include "top.php"; include "connect.php"; if(isset($_POST["submit"])) { $error = ""; if(empty($_POST["name"])) { $error .= "Du glömde märket!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att bedömma märket!<br>"; if(empty($_POST["worth"])){ $error .= "Du glömde att välja vilken klass den hör till!<br>"; if(empty($_POST["username"])){ $error .= "Du glömde att skriva ditt namn!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att skriva någonting?!!<br>"; }}}}} if(!empty($error)){ echo $error; }else{ $name = $_POST["name"]; $rating = $_POST["rating"]; $worth = $_POST["worth"]; $favorite = $_POST["favorite"]; $username = $_POST["username"]; $description = $_POST["description"]; mysql_query("INSERT INTO brands (name, rating, worth, favorite, username, description) VALUES ('$name', '$rating', '$worth', '$favorite', '$username', '$description')"); echo "<span style='color: green'>Yir yir, <a href='brand.php'>klicka här för att gå till Märken.</a></span>"; } } It doesnt come with errors it just say the succeed message like it has inserted to database

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  • Processing a database queue across multiple threads - design advice

    - by rwmnau
    I have a SQL Server table full of orders that my program needs to "follow up" on (call a webservice to see if something has been done with them). My application is multi-threaded, and could have instances running on multiple servers. Currently, every so often (on a Threading timer), the process selects 100 rows, at random (ORDER BY NEWID()), from the list of "unconfirmed" orders and checks them, marking off any that come back successfully. The problem is that there's a lot of overlap between the threads, and between the different processes, and their's no guarantee that a new order will get checked any time soon. Also, some orders will never be "confirmed" and are dead, which means that they get in the way of orders that need to be confirmed, slowing the process down if I keep selecting them over and over. What I'd prefer is that all outstanding orders get checked, systematically. I can think of two easy ways do this: The application fetches one order to check at a time, passing in the last order it checked as a parameter, and SQL Server hands back the next order that's unconfirmed. More database calls, but this ensures that every order is checked in a reasonable timeframe. However, different servers may re-check the same order in succession, needlessly. The SQL Server keeps track of the last order it asked a process to check up on, maybe in a table, and gives a unique order to every request, incrementing its counter. This involves storing the last order somewhere in SQL, which I wanted to avoid, but it also ensures that threads won't needlessly check the same orders at the same time Are there any other ideas I'm missing? Does this even make sense? Let me know if I need some clarification.

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  • CodeIgnither OAuth 2.0 database setup for users and access_tokens

    - by xref
    Per this question I am using CodeIgniter and OAuth 2 in an attempt to provide SSO for internal users of my webapp, ideally verifying them against their Google Apps account. No registrations or anything, just existing users. Using the CI oauth2 spark I'm getting back from Google an OAuth token similar to below: OAuth2_Token_Access Object ( [access_token:protected] => dp83.AHSDj899sDHHD908DHFBDjidkd8989dDHhjjd [expires:protected] => 1349816820 [refresh_token:protected] => [uid:protected] => ) And using that token I can retrieve some user info from Google: [uid] => 3849450385394595 [nickname] => this_guy [name] => This Guy [first_name] => This [last_name] => Guy [email] => [email protected] [location] => [image] => [description] => [urls] => Array ( ) Now to allow the 15 people or so who will be using the webapp currently to log in, do I need to create a users table in the mysql database with their email address as a key? Then compare the email which just came back from the Google OAuth request and see if it exists in my users table? What about the Google access_token, do I store that now along with the email which already existed in the users table? Related: How would I go about verifying the user automatically in the future against that access_token so they don't have to go through the whole OAuth approval process with Google again?

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  • Saving form values to database after a user logs in

    - by redfalcon
    Hi. We have a form with ratings to submit for a certain restaurant. After the user has entered some values and wants to submit them, we check whether the user is logged in or not. If not, we display a login form and let the user put in his account data and redirect him to the restaurant he wanted to submit a rating for. The problem is, that after he successfully logged in himself, the submitted values are not saved to the database (which works fine if the user is already logged in). So I wondered if it is possible, to somehow save the data although the user is not logged in. I thought of maybe saving the filled values in a variable and have then automatically re-entered after we redirected the user. But I guess this wont work because we use before_filter :login_required, :only => [ :create ] So we couldnt even access the filled in values, since we display the login-form before the method has processed the values in the form, right? Any idea how we can make rails to save the values or at least have them automatically re-entered to the form? Thanks!

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  • Assigning values to the lable through database depending on listbox values

    - by SurajVitekar
    I want to assign the values of five labels from database regarding to values selected in listbox. The db query returns single column with multiple records. Please help. I'm working with C# 2010 and MS SQL. My current code is: private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { try { String c1, c2; c1 = "NULL"; MessageBox.Show("LB index :"+listBox1.SelectedIndex.ToString()); //p = listBox1.SelectedItem.ToString(); SqlConnection con = new SqlConnection(); con.ConnectionString = "Data Source=localhost;Initial Catalog=eVoting;Integrated Security=True;Pooling=False"; con.Open(); MessageBox.Show("List bOx sect :"+listBox1.SelectedValue.ToString()); SqlCommand cmd = new SqlCommand("select Firstname from candidates where position ='" + listBox1.SelectedValue.ToString() + "'", con); int index = 0; SqlDataReader reader = cmd.ExecuteReader(); while(reader.Read()) { if (index == 0) { c1 = reader[index].ToString(); radioButton1.Text = c1; } if (index == 1) { c1 = reader[index].ToString(); radioButton2.Text = c1; } if (index == 2) { c1 = reader[index].ToString(); radioButton3.Text = c1; } if (index == 3) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 4) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 5) { c1 = reader[index].ToString(); radioButton5.Text = c1; } MessageBox.Show("c1 :" + c1); index++; } } catch (Exception E) { } }

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  • Problem with SqlLite database in Qt SDK 1.0.2

    - by Risino
    Hi I have a problem with SqlLite database. Here is my code: void incomeDialog::on_add_pushButton_clicked() { int a = ui->income_lineEdit->text().toInt(); int b = ui->other_lineEdit->text().toInt(); int c = (a+b); db = QSqlDatabase::addDatabase("QSQLITE"); db.setDatabaseName("money.db"); QSqlQuery query(db); query.exec("create table Income" "(Month TEXT, Payment NUMBER, Other NUMBER, Together NUMBER)"); query.prepare("INSERT INTO Income values (?,?,?,?)"); query.addBindValue(ui->comboBox->currentText()); query.addBindValue(ui->income_lineEdit->text().toInt()); query.addBindValue(ui->other_lineEdit->text().toInt()); query.addBindValue(c); query.exec(); } I use qt sdk 1.0.2. After building shows errors: Undefined reference to 'QSqlDatabase::addDatabase(QString const&, QString const&)... all errors is similar (Undefined reference to 'QSqlDatabase:: Do you have any idea how to repair it?

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  • Create Dynamically table at runtime & save it in database

    - by user1548245
    I have written a code for creating table. It displays table structure on GUI form, but what I want is, when I enter values into table it should be stored in database table too. My code: <?php function display($column,$rows) { echo "<table border='1' align='center'>"; for ($iii = 0;$iii <$_POST['column'];$iii++) { echo "<tr>".$jjj."</tr>"; //display no. of <tr> for ($jjj = 0; $jjj <$_POST['rows'];$jjj++) { echo "<td>" ."<input type=\"text\" name='$iii'>"."</td>"; } } echo "</table>"; } ?>

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  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

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  • fetching the label text from database in C#

    - by Yilmaz Paçariz
    private void button5_Click(object sender, EventArgs e) { SqlConnection conn = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='1'", conn); conn.Open(); label1.Text = cmd.ExecuteReader().ToString(); conn.Close(); SqlConnection conn1 = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd1 = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='2'", conn1); conn1.Open(); label2.Text = cmd1.ExecuteReader().ToString(); conn1.Close(); SqlConnection conn2 = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd2 = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='3'", conn2); conn2.Open(); label3.Text = cmd2.ExecuteReader().ToString(); conn2.Close(); } I am developing a small project in C#... Using Visiual Studio 2010... I want to fetch the label texts from database in order to change the user interface language with a button... I wrote this code but there is a problem in SQLDATAREADER in label text parts it shows System.Data.SqlClient.SqlDataReader I cant fix, could you help me?

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  • LINQ to SQL - database relationships won't update after submit

    - by Quantic Programming
    I have a Database with the tables Users and Uploads. The important columns are: Users -> UserID Uploads -> UploadID, UserID The primary key in the relationship is Users -> UserID and the foreign key is Uploads -> UserID. In LINQ to SQL, I do the following operations: Retrieve files var upload = new Upload(); upload.UserID = user.UserID; upload.UploadID = XXX; db.Uploads.InsertOnSubmit(upload) db.SubmitChanges(); If I do that and rerun the application (and the db object is re-built, of course) - if do something like this: foreach(var upload in user.Uploads) I get all the uploads with that user's ID. (like added in the previous example) The problem is, that my application, after adding an upload an submitting changes, doesn't update the user.Uploads collection. i.e - I don't get the newly added uploads. The user object is stored in the Session object. At first, I though that the LINQ to SQL Framework doesn't update the reference of the object, therefore I should simply "reset" the user object from a new SQL request. I mean this: Session["user"] = db.Users.Where(u => u.UserID == user.UserID).SingleOrDefault(); (Where user is the previous user) But it didn't help. Please note: After rerunning the application, user.Uploads does have the new upload! Did anyone experience this type of problem, or is it normal behavior? I am a newbie to this framework. I would gladly take any advice. Thank you!

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  • database design - empty fields

    - by imanc
    Hey, I am currently debating an issue with a guy on my dev team. He believes that empty fields are bad news. For instance, if we have a customer details table that stores data for customers from different countries, and each country has a slightly different address configuration - plus 1-2 extra fields, e.g. French customer details may also store details for entry code, and floor/level plus title fields (madamme, etc.). South Africa would have a security number. And so on. Given that we're talking about minor variances my idea is to put all of the fields into the table and use what is needed on each form. My colleague believes we should have a separate table with extra data. E.g. customer_info_fr. But this seams to totally defeat the purpose of a combined table in the first place. His argument is that empty fields / columns is bad - but I'm struggling to find justification in terms of database design principles for or against this argument and preferred solutions. Another option is a separate mini EAV table that stores extra data with parent_id, key, val fields. Or to serialise extra data into an extra_data column in the main customer_data table. I think I am confused because what I'm discussing is not covered by 3NF which is what I would typically use as a reference for how to structure data. So my question specifically: - if you have slight variances in data for each record (1-2 different fields for instance) what is the best way to proceed?

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  • JQuery datepicker icon trigger broken after inserting data to database

    - by crisgine callano
    at first i got to load my icon for the JQuery datepicker but after i insert the value to my database the icon image is broken. im using Codeigniter framework. here's my html code: <!DOCTYPE HTML> <html lang="en-US"> <head> <meta charset="UTF-8"> <title>CRUD</title> <?php echo link_tag(base_url() . 'css/ui-lightness/jquery-ui-1.8.23.custom.css'); ?> </head> <body> <div> <?php echo form_label('BDay:', 'bday'); $data = array( 'name' => 'bday', 'id' => 'datepicker' ); echo form_input($data); ?> </div> </body> </html> and here's my jscript: <script> $(function() { $( "#datepicker" ).datepicker({ changeMonth: true, changeYear: true, showOn: "button", buttonImage: "<?php echo base_url() . '/images/icons/calendar_24.png' ?>", buttonImageOnly: true, onSelect: function(dateText, inst){ $("input[name='bday']").val(dateText); } }); }); am i missing something? thanks!

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • php import larg table to phpmyadmin database

    - by safaali
    hi, I am so worry :( I dropped one of the tables from the database accidentally. fortunately, I have back-up. (I have used the "Auto backup for mysql") The back-up of the table is stored as .txt file (56 Megabytes) on my PC. I tried to import it by PhpMyAdmin and the import failed because the file is too large to import. then I uploaded the file to /home/tablebk directory. I have some experiences in php. I know that I would import it with this code, but i don't know the sql statment for this import. what is have to put as $line variable? please help me :( :( <?php $dbhost = 'localhost'; $dbuser = 'mysite'; $dbpw = 'password'; $dbname = 'databasename'; $file = @fopen('country.txt', 'r'); if ($file) { while (!feof($file)) { $line = trim(fgets($file)); $flag = mysql_query($line); if (isset($flag)) { echo 'Insert Successfully<br />'; } else { echo mysql_error() . '<br/>'; } flush(); } fclose($file); } echo '<br />End of File'; ?>

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  • SharePoint 2007 - Content deployment and swapping content database

    - by Mel Lota
    Hi all, I'm currently working on a SharePoint 2007 site which is setup to allow clients to author content on a staging server and then this is automatically pushed up to the live environment via content deployment. The content deployment is setup in the 'Content deployment jobs and paths' in central admin. Now the problem I've got is that it seems that historically there have been a mixture of full and incremental deployments done to the live site collection which according to Stefan Goßner's best practices post (http://blogs.technet.com/stefan_gossner/pages/content-deployment-best-practices.aspx) is a bad idea due to the fact that things soon become out of sync. It's gotten to the point where the content deployment has just stopped working and incremental or full deployments are throwing errors in the logs. What I'm thinking is that I probably need to perform a full content deployment to an empty site collection and then somehow switch the new clean site collection with the current live one. I was wondering if anybody has any experience with this and could provide any pointers, I'm currently investigating the feasibility of performing the clean content deployment and then switching the live content database with the new one, however in my tests I've found that as soon as I switch content databases, the incremental deployment still fails. Any help much appreciated. (Note: I did post this on SharePoint Overflow as well, but thought I'd put it on here in case anybody else has any ideas) Cheers

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  • Automatically update php loop with data pulled from database

    - by John Svensson
    SQL STRUCTURE CREATE TABLE IF NOT EXISTS `map` ( `id` int(11) NOT NULL AUTO_INCREMENT, `x` int(11) NOT NULL, `y` int(11) NOT NULL, `type` varchar(50) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; http://localhost/map.php?x=0&y=0 When I update the x and y via POST or GET, I would like to pull the new data from the database without refreshing the site, how would I manage that? Could someone give me some examples, because I am really stuck here. <?php mysql_connect('localhost', 'root', ''); mysql_select_db('hol'); $startX = $_GET['x']; $startY = $_GET['y']; $fieldHeight = 6; $fieldWidth = 6; $sql = "SELECT id, x, y, type FROM map WHERE x BETWEEN ".$startX." AND ".($startX+$fieldWidth). " AND y BETWEEN ".$startY." AND ".($startY+$fieldHeight); $result = mysql_query($sql); $positions = array(); while ($row = mysql_fetch_assoc($result)) { $positions[$row['x']][$row['y']] = $row; } echo "<table>"; for($y=$startY; $y<$startY+$fieldHeight; $y++) { echo "<tr>"; for($x=$startX; $x<$startX+$fieldWidth; $x++) { echo "<td>"; if(isset($positions[$x][$y])) { echo $positions[$x][$y]['type']; } else { echo "(".$x.",".$y.")"; } echo "</td>"; } echo "</tr>"; } echo "</table>"; ?>

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  • Create ImageButton programatically depending on local database records

    - by user2507920
    As i described in title, i have a local db in sqlite. I want to create ImageButton parametrically. How many times is local database loop executing? Please see code below : RelativeLayout outerRelativeLayout = (RelativeLayout)findViewById(R.id.relativeLayout2_making_dynamically); db.open(); Cursor c = db.getAllLocal_Job_Data(); if(c!=null){ if(c.moveToFirst()){ do { RelativeLayout innerRelativeLayout = new RelativeLayout(CalendarActivity.this); innerRelativeLayout.setGravity(Gravity.CENTER); ImageButton imgBtn = new ImageButton(CalendarActivity.this); imgBtn.setBackgroundResource(R.drawable.color_001); RelativeLayout.LayoutParams imageViewParams = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); imgBtn.setLayoutParams(imageViewParams); // Adding the textView to the inner RelativeLayout as a child innerRelativeLayout.addView(imgBtn, new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); outerRelativeLayout.addView(innerRelativeLayout, new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); } while (c.moveToNext()); } } db.close(); But when i run the project, i can see only one button created there. I think there are many buttons but here image button is creating on last created image button. I think i should use android:layout_toRightOf with previous created button but i cant find how to place it here. I have tried some ideas but it did not change any thing. So please anybody has any idea to solve my problem then please share it with me.

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  • Multiple ID's in database

    - by eric
    I have a database that contains a few tables such as person, staff, member, and supporter. The person table contains information about every staff, member, and supporter. The information it contains is name,address,email, and telephone. I also created an id that is the primary key. My issue is that I also have an primary key ID for staff, member, and supporter. For instance, in the person table is John with id 1. He is a supporter so in the supporter table is pID(for person id)to reference back to John with all his information and ID(for supporter ID). pID references to the person table and every person has an ID incremented by 1 starting at 1. supporter ID is for every supporter and also starts at 1 and is incremented by 1. Is it possible to have in the supporter table pID = 1 and supporter ID = 1? Another person may have a pID = 26 and supporter ID = 5. Or will supporter ID have to be different than the pID and be something like "sup"? So you would have pID = 1 and supporter ID = sup1 or pID = 26 and supporter ID = sup5

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