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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • Find groups with both validated, unvalidated users

    - by Matchu
    (Not my real MySQL schema, but illustrates what needs done.) Users can belong to many groups, and groups have many users. users: id INT validated TINYINT(1) groups: id INT name VARCHAR(20) groups_users: group_id INT user_id INT I need to find groups that contain both validated and unvalidated users (validated being 1 or 0, respectively), in order to perform a specific manual maintenance task. There are thousands of users, all belong to at least one group, but a group usually only has 2-5 users. This is a live production server, so I could probably craft a query myself, but the last one I tried took a matter of minutes before I killed it. (I'm not one of those brilliant SQL wizards.) I suppose I could take the server down for maintenance, but, if possible, a query that gets this job done in a matter of seconds would be fantastic. Thanks!

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  • What's the most common scenario for Cocoa app setup during first launch?

    - by Eimantas
    I am creating an app and I would like a user to set some obligatory preferences during first app launch. What is the most common scenario to achieve this? Should I set some user defaults to see if the app has been setup? Also - if I determine that the app is being launched for the first time - how should I display "Setup" window? If I load it from the separte xib file - how will I deffer the display of main app window?

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  • Asp.Net MVC Handle Drop Down Boxes that are not part of the Model

    - by Pino
    I have a small form which the user must fill in and consists of the following fields. Name (Text) Value (Text) Group (Group - Is a list of option pulled from a database table) Now the Model for this View looks like so, public string Name { get; set; } public string Value { get; set; } public int GroupID { get; set; } Now the view is Strongly Typed to the above model. What method would one use to populate the drop down list? Since the data is not contained within the Model (It could be contained in the Model) should we be using Temp/View data? A HTML Helper? What would be the ideal way to achieve this.

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  • MySQL different versions other results.

    - by kuba
    hey, i have 2 version of mysql on windows 5.1.39-community and on linux 5.1.39-log i execute a query: SELECT `o`.`idOffer`, `o`.`offer_date`, `p`.`factory`, `c`.`short` AS `company`, `s`.`name` AS `subcategory`, `ct`.`name` AS `category`, count( (select count(1) from product where idProduct=idOffer group by idOffer) ) as b FROM `Offer` AS `o` LEFT JOIN `Product` AS `p` ON o.idOffer = p.idOffer LEFT JOIN `company` AS `c` ON o.company = c.id LEFT JOIN `Subcategory` AS `s` ON s.idSubcategory = o.idSubcategory LEFT JOIN `Category` AS `ct` ON ct.idCategory = s.idCategory WHERE (o.idOffer = p.idOffer) GROUP BY `o`.`idOffer` on windows it works as it suppose, but on linux it says: ERROR 1242 (21000): Subquery returns more than 1 row is it any way to get it worked on linux without any mysql updates/downgrades ?

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  • A linq join combined with a regex

    - by Geert Beckx
    Is it possible to combine these 2 queries or would this make my code too complex? Also I think there should be a performance gain by combining these queries since I think in the near future my source table could be over 11000 records. This is what i came up with so far : Dim lit As LiteralControl ' check characters not in alphabet Dim r As New Regex("^[^a-zA-Z]+") Dim query = From o In source.ToTable _ Where r.IsMatch(o.Field(Of String)("nam")) lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", "0-9", query.Count)) plhAlpabetLinks.Controls.Add(lit) Dim q = From l In "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToLower.ToCharArray _ Group Join o In source.ToTable _ On l Equals o.Field(Of String)("nam").ToLowerInvariant(0) Into g = Group _ Select l, g.Count ' iterate the alphabet to generate all the links. For Each letter In q.AsEnumerable lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", letter.l, letter.Count)) plhAlpabetLinks.Controls.Add(lit) Next Kind regards, G.

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  • how to add column in SQL Query that incl. LEFT OUTER JOIN

    - by radbyx
    I have this Query: SELECT p.ProductName, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID = dt.ProductID ORDER BY p.ProductName; It works like it should, but now I need to SELECT "State" out too. The tricky part is, that I only want the lastest "TimeStamp" where "State" was false. But now I also need the "State" for the lastest "TimeStamp". I tried this: SELECT p.ProductName, dt.State, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp, State FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID =dt.ProductID ORDER BY p.ProductName; But it didn't work, because it gave me the "State" for the lastest "TimeStamp". So I hope there is some clever heads out there that can help me. I'm guessing that this is either very simple or very hard to solve.

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  • Optimize slow ranking query

    - by Juan Pablo Califano
    I need to optimize a query for a ranking that is taking forever (the query itself works, but I know it's awful and I've just tried it with a good number of records and it gives a timeout). I'll briefly explain the model. I have 3 tables: player, team and player_team. I have players, that can belong to a team. Obvious as it sounds, players are stored in the player table and teams in team. In my app, each player can switch teams at any time, and a log has to be mantained. However, a player is considered to belong to only one team at a given time. The current team of a player is the last one he's joined. The structure of player and team is not relevant, I think. I have an id column PK in each. In player_team I have: id (PK) player_id (FK -> player.id) team_id (FK -> team.id) Now, each team is assigned a point for each player that has joined. So, now, I want to get a ranking of the first N teams with the biggest number of players. My first idea was to get first the current players from player_team (that is one record top for each player; this record must be the player's current team). I failed to find a simple way to do it (tried GROUP BY player_team.player_id HAVING player_team.id = MAX(player_team.id), but that didn't cut it. I tried a number of querys that didn't work, but managed to get this working. SELECT COUNT(*) AS total, pt.team_id, p.facebook_uid AS owner_uid, t.color FROM player_team pt JOIN player p ON (p.id = pt.player_id) JOIN team t ON (t.id = pt.team_id) WHERE pt.id IN ( SELECT max(J.id) FROM player_team J GROUP BY J.player_id ) GROUP BY pt.team_id ORDER BY total DESC LIMIT 50 As I said, it works but looks very bad and performs worse, so I'm sure there must be a better way to go. Anyone has any ideas for optimizing this? I'm using mysql, by the way. Thanks in advance Adding the explain. (Sorry, not sure how to format it properly) id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY t ALL PRIMARY NULL NULL NULL 5000 Using temporary; Using filesort 1 PRIMARY pt ref FKplayer_pt77082,FKplayer_pt265938,new_index FKplayer_pt77082 4 t.id 30 Using where 1 PRIMARY p eq_ref PRIMARY PRIMARY 4 pt.player_id 1 2 DEPENDENT SUBQUERY J index NULL new_index 8 NULL 150000 Using index

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  • How should I join these 3 SQL queries in Oracle?

    - by Nazgulled
    I have these 3 queries: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url FROM movies m WHERE m.mid = 1; SELECT AVG(rating) FROM movie_ratings WHERE mid = 1; SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1; And I need to join them into a single query. I was able to do it like this: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url, AVG(rating) average, COUNT(rating) count FROM movies m INNER JOIN movie_ratings mr ON m.mid = mr.mid WHERE m.mid = 1 GROUP BY title, year, MovieGenres(m.mid), MovieDirectors(m.mid), MovieWriters(m.mid), synopsis, poster_url; But I don't really like that "huge" GROUP BY, is there a simpler way to do it?

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  • How to read ident and it's value from registry?

    - by user367856
    i have store a list of items from gridView into registry as below: * frmPOSConfigSet.tblCatItems.First; while not frmPOSConfigSet.tblCatItems.Eof do begin RegItemSetting.WriteString('stk Group\Candy', frmPOSConfigSet.tblCatItemsCODE.Text, frmPOSConfigSet.tblCatItemsSPHOTO.Text); frmPOSConfigSet.tblCatItems.Next; end; * [In Registry Editor] stk Group - Candy - YUPI_GUM_HB , c:\Users\chai\Pictures\POS Item Images\image1.jpg - YUPI_GUM_SBKISS , c:\Users\chai\Pictures\POS Item Images\image2.jpg After i close the form and open again, all values in gridView is gone, how to retrieve the ident (eg. YUPI_GUM_HB) and it's value (eg.c:\Users\chai\Pictures\POS Item Images\image1.jpg) from registry to the gridView when load the form?

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  • iPhone: Grouping records in multiple UITableView views

    - by Nic Hubbard
    Let me first say, I know how to create sections and group records within a UITableView. What I am wanting to do is something similar to creating a photo album. So, I have all my data objects coming from core data, and, I want to be able to create a custom group, such as "My Trip to Mexico" and "First Birthday". Then, the user should be able to add objects/records into new sections/albums. So, basically the user is creating custom sections with their own custom names, and then choosing what records should go into that section/album. So, I am just wondering what is the best way to do this? I am thinking that I would just create some extra attributes for my core data model. Or, would I create a whole new "Album Section" object, and somehow use that? Point me in the right direction. :)

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  • Adding tables to sql server result in Domain\user.name.tablename

    - by Ryan Howe
    Our app uses migratordotnet to modify the backing SQL Server 2005 database. This works great 99% of the time but we are running into an issue. We have a client that is using and Active Directory group for sql server login and when new tables are added it creates them as Domain\login.table_name. What permissions are needed to be given to the AD group to add the tables as dbo.table_name? This does not happen in with all of our clients with similar configurations so I must be missing something.

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  • Drop duplicated axis label in Flex Chart

    - by Sean Chen
    Hi, All. I use LineChart in Flex with horizontal category axis and I need drop duplicated category label on the chart. The data I use are like that: {Product: "C1", Store: "S1", Profit: "1500}, {Product: "C2", Store: "S1", Profit: "1000}, {Product: "C3", Store: "S2", Profit: "800}, {Product: "C4", Store: "S2", Profit: "1200}, {Product: "C5", Store: "S3", Profit: "1800} Beacuse I set horizontalAxis.categoryField = "Store" , the chart show label "S1,S1,S2,S2,S3" on ths axes. However, both C1 and C2 data point group on the second "S1" category (as same as C3,C4 on second S2). If I accept group data point on the same x-poistion, is there any idea to drop duplicated label?

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  • SPF blocking some emails. How to complete disable it?

    - by Rafael Colucci
    We have configured a SMTP server on IIS. We have not configured any SPF rule. Some emails are going straight to the badmail folder. Most of them have this error message: Address does not pass the Sender Policy Framework Is there any way to disable that? I know this is insecure and spammers could use it to send spam, but I really need it to be disabled for now until I have configured and tested the SPF correctly.

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  • How to determine JAVA_HOME on Debian/Ubuntu?

    - by Witek
    On Ubuntu it is possible to have multiple JVMs at the same time. The default one is selected with update-alternatives. But this does not set the JAVA_HOME environment variable, due to a debian policy. I am writing a launcher script (bash), which starts a java application. This java application needs the JAVA_HOME environment variable. So how to get the path of the JVM which is currently selected by update-alternatives?

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  • some examples for using specific searchalgorithm

    - by Robert
    I could understand the following search algorithms: Constraint Satisfaction with Arc Consistency, Uninformed search A* Search MinMax I would understand the definition and working principles of the above algorithm,but could you please give me some real world examples that the above algorithms will be suitable?My idea would be: For CSP with Arc Consistency,assign students to groups that each group must contain both technical and management students,and no 2 technical students in a same group. Uniformed Search: search for a file under UNIX directoy. A* Search: search a way (staring from home) to go to mulitple stores to buy things then get back home with minimum total travelling time. MinMax:Go or other Chess. Please correct me if I am wrong.

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  • windows 2008 server login screen remote desktop

    - by Marki
    how can I access a GRAPHICAL login screen (like on earlier Windows versions, or like VNC) instead of the Username/Password prompt via RDP? I'm asking because we have several servers where we have no passwords but the shutdown/reboot option is given via group policy on the login screen. Thus, instead of having to go the hardware console I'd like to be able to perform reboot/shutdown actions via terminal services. Regards, Marki

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • Any way to optimize this MySQL query?

    - by manyxcxi
    My table looks like this: `MyDB`.`Details` ( `id` bigint(20) NOT NULL, `run_id` int(11) NOT NULL, `element_name` varchar(255) NOT NULL, `value` text, `line_order` int(11) default NULL, `column_order` int(11) default NULL ); I have the following SELECT statement in a stored procedure SELECT RULE ,TITLE ,SUM(IF(t.PASSED='Y',1,0)) AS PASS ,SUM(IF(t.PASSED='N',1,0)) AS FAIL FROM ( SELECT a.line_order ,MAX(CASE WHEN a.element_name = 'PASSED' THEN a.`value` END) AS PASSED ,MAX(CASE WHEN a.element_name = 'RULE' THEN a.`value` END) AS RULE ,MAX(CASE WHEN a.element_name = 'TITLE' THEN a.`value` END) AS TITLE FROM Details a WHERE run_id = runId GROUP BY line_order ) t GROUP BY RULE, TITLE; *runId is an input parameter to the stored procedure. This query takes about 14 seconds to run. The table has 214856 rows, and the particular run_id I am filtering on has 162204 records. It's not on a super high power machine, but I feel like I could be doing this more efficiently. My main goal is to summarize by Rule and Title and show Pass and Fail count columns.

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  • getting userbase vote average and individual user's vote in the same query?

    - by Andrew Heath
    Here goes: T1 [id] [desc] 1 lovely 2 ugly 3 slender T2 [id] [userid] [vote] 1 1 3 1 2 5 1 3 2 2 1 1 2 2 4 2 3 4 In one query (if possible) I'd like to return: T1.id, T1.desc, AVG(T2.vote), T2.vote (for user viewing the page) I can get the first 3 items with: SELECT T1.id, T1.desc, AVG(T2.vote) FROM T1 LEFT JOIN T2 ON T1.id=T2.id GROUP BY T1.id and I can get the first, second, and fourth items with: SELECT T1.id, T1.desc, T2.vote FROM T1 LEFT JOIN T2 ON T1.id=T2.id WHERE T2.userid='1' GROUP BY T1.id but I'm at a loss as to how to get all four items in one query. I tried inserting a select as the fourth term: SELECT T1.id, T1.desc, AVG(T2.vote), (SELECT T2.vote FROM T2 WHERE T2.userid='1') AS userVote etc etc but I get an error that the select returns more than one row... Help? My reason for wanting to do this in one query instead of two is that I want to be able to sort the data within MySQL rather than one it's been split into a number of arrays.

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  • Cocos2d-iPhone: CCSprite positions differ between Retina & non-Retina Screens

    - by bobwaycott
    I have a fairly simple app built using cocos2d-iphone, but a strange positioning problem that I've been unable to resolve. The app uses sprite sheets, and there is a Retina and non-Retina sprite sheet within the app that use the exact same artwork (except for resolution, of course). There are other artwork within the app used for CCSprites that are both standard and -hd suffixed. Within the app, a group of sprites are created when the app starts. These initially created CCSprites always position identically (and correctly) on Retina & non-Retina screens. // In method called to setup sprites when app launches // Cache & setup app sprites [[CCSpriteFrameCache sharedSpriteFrameCache] addSpriteFramesWithFile: @"sprites.plist"]; sprites = [CCSpriteBatchNode batchNodeWithFile: @"sprites.png"]; hill = [CCSprite spriteWithSpriteFrameName: @"hill.png"]; hill.position = ccp( 160, 75 ); [sprites addChild: hill z: 1]; // ... [create more sprites in same fashion] // NOTE: All sprites created here have correct positioning on Retina & non-Retina screens When a user taps the screen a certain way, a method is called that creates another group of CCSprites (on- and off-screen), animating them all in. One of these sprites, hand, is always positioned identically (and correctly) on Retina & non-Retina screens. The others (a group of clouds) successfully create & animate, but their positions are correct only on Retina displays. On a non-Retina display, each cloud has incorrect starting positions (incorrect for x, y, or sometimes both), and their ending positions after animation are also wrong. I've included the responsible code below from the on-touch method that creates the new sprites and animates them in. Again, it works as expected on a Retina display, but incorrectly on non-Retina screens. The CCSprites used are created in the same way at app-start to setup all the initial sprites in the app, which always have correct positions. // Elsewhere, in a method called on touch // Create clouds cloud1 = [CCSprite spriteWithSpriteFrameName: @"cloud_1.png"]; cloud1.position = ccp(-150, 320); cloud1.scale = 1.2f; cloud2 = [CCSprite spriteWithSpriteFrameName: @"cloud_2.png"]; cloud2.position = ccp(-150, 335); cloud2.scale = 1.3f; cloud3 = [CCSprite spriteWithSpriteFrameName: @"cloud_4.png"]; cloud3.position = ccp(-150, 400); cloud4 = [CCSprite spriteWithSpriteFrameName: @"cloud_5.png"]; cloud4.position = ccp(-150, 420); cloud5 = [CCSprite spriteWithSpriteFrameName: @"cloud_3.png"]; cloud5.position = ccp(400, 350); cloud6 = [CCSprite spriteWithSpriteFrameName: @"cloud_1.png"]; cloud6.position = ccp(400, 335); cloud6.scale = 1.1f; cloud7 = [CCSprite spriteWithSpriteFrameName: @"cloud_2.png"]; cloud7.flipY = YES; cloud7.flipX = YES; cloud7.position = ccp(400, 380); // Create hand hand = [CCSprite spriteWithSpriteFrameName:@"hand.png"]; hand.position = ccp(160, 650); [sprites addChild: cloud1 z: 10]; [sprites addChild: cloud2 z: 9]; [sprites addChild: cloud3 z: 8]; [sprites addChild: cloud4 z: 7]; [sprites addChild: cloud5 z: 6]; [sprites addChild: cloud6 z: 10]; [sprites addChild: cloud7 z: 8]; [sprites addChild: hand z: 10]; // ACTION!! [cloud1 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(70, 320)]]; [cloud2 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(60, 335)]]; [cloud3 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(100, 400)]]; [cloud4 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(80, 420)]]; [cloud5 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(250, 350)]]; [cloud6 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(250, 335)]]; [cloud7 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(270, 380)]]; [hand runAction: handIn]; It may be worth mentioning that I see this incorrect positioning behavior in the iOS Simulator when running the app and switching between the standard iPhone and iPhone (Retina) hardware options. I have not been able to verify this occurs or does not occur on an actual non-Retina iPhone because I do not have one. However, this is the only time I see this odd positioning behavior occur (the incorrect results obtained after user touch), and since I'm creating all sprites in exactly the same way (i.e., [CCSprite spriteWithSpriteFrameName:] and then setting position with cpp()), I would be especially grateful for any help in tracking down why this single group of sprites are always incorrect on non-Retina screens. Thank you.

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  • Get the count of A -> B and B->A without duplicates

    - by TomGasson
    I have a table like so: index|from | to ------------------ 1 | ABC | DEF 2 | ABC | GHI 3 | ABC | GHI 4 | ABC | JKL 5 | ABC | JKL 6 | ABC | JKL 7 | DEF | ABC 8 | DEF | GHI 9 | DEF | JKL 10 | GHI | ABC 11 | GHI | ABC 12 | GHI | ABC 13 | JKL | DEF And I need to count how the total times between the points (regardless of direction) to get the result: A | B | count ----------------- ABC | DEF | 2 ABC | GHI | 5 ABC | JKL | 3 DEF | GHI | 1 DEF | JKL | 2 So far I can get: SELECT `a`.`from` as `A`, `a`.`to` as `B`, (`a`.`count` + `b`.`count`) as `count` FROM (SELECT `from`, `to`, count(*) as `count` FROM `table` GROUP BY 1,2) `a` LEFT OUTER JOIN (SELECT `from`,`to`, count(*) as `count` FROM `table` GROUP BY 1,2) `b` ON `a`.`from` = `b`.`to` AND `a`.`to` = `b`.`from` But I'm unsure how to remove the A/B swapped duplicates.

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  • Union All Won't work in stored procedure

    - by MyHeadHurts
    ALTER PROCEDURE [dbo].[MyStoredProcedure1] @YearToGet int AS Select Division, SDESCR, DYYYY, Sum(APRICE) ASofSales, Sum(PARTY) AS ASofPAX, Sum(NetAmount) ASofNetSales, Sum(InsAmount) ASofInsSales, Sum(CancelRevenue) ASofCXSales, Sum(OtherAmount) ASofOtherSales, Sum(CXVALUE) ASofCXValue From dbo.B101BookingsDetails Where Booked <= CONVERT(int,DateAdd(year, @YearToGet - Year(getdate()), DateAdd(day, DateDiff(day, 1, getdate()), 0) ) ) and (DYYYY = @YearToGet) Group By SDESCR, DYYYY, Division Having (DYYYY = @YearToGet) Order By Division, SDESCR, DYYYY union all SELECT DIVISION, SDESCR, DYYYY, SUM(APRICE) AS YESales, SUM(PARTY) AS YEPAX, SUM(NetAmount) AS YENetSales, SUM(InsAmount) AS YEInsSales, SUM(CancelRevenue) AS YECXSales, SUM(OtherAmount) AS YEOtherSales, SUM(CXVALUE) AS YECXValue FROM dbo.B101BookingsDetails Where (DYYYY=@YearToGet) GROUP BY SDESCR, DYYYY, DIVISION ORDER BY DIVISION, SDESCR, DYYYY The error I am getting is Msg 156, Level 15, State 1, Procedure MyStoredProcedure1, Line 36 Incorrect syntax near the keyword 'union'. But my goal here is the user inputs a year for example 2009, my first query will get all the sales made in 2009 to the same date it is was yesterday 12/23/2009, while the second query is getting 2009 totals up to dec 31 2009. I want the columns to be side by side not in one column

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  • Conflicting ip routes with local table on attaching a virtual network interface

    - by user1071840
    I have an EC2 instance with these ip rules: $ sudo ip rule show 0: from all lookup local 32766: from all lookup main 32767: from all lookup default I can attach an elastic network interface to it with a private IP. Say the IP of my machine is 10.1.3.12 and the IP of the interface is 10.1.1.190. As soon as I attach the interface to my machine a new entry is added to the routing policy and local routing table: sudo ip rule show 0: from all lookup local 32765: from 10.1.1.190 lookup 10003 32766: from all lookup main 32767: from all lookup default $ sudo ip route show table local broadcast 10.1.1.0 dev eth3 proto kernel scope link src 10.1.1.190 local 10.1.1.190 dev eth3 proto kernel scope host src 10.1.1.190 broadcast 10.1.1.255 dev eth3 proto kernel scope link src 10.1.1.190 broadcast 10.1.3.0 dev eth0 proto kernel scope link src 10.1.3.12 local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 broadcast 10.1.3.255 dev eth0 proto kernel scope link src 10.1.3.12 broadcast 127.0.0.0 dev lo proto kernel scope link src 127.0.0.1 local 127.0.0.0/8 dev lo proto kernel scope host src 127.0.0.1 local 127.0.0.1 dev lo proto kernel scope host src 127.0.0.1 broadcast 127.255.255.255 dev lo proto kernel scope link src 127.0.0.1 I can send traffic to this ENI directly from a host that can have the same IP as the host the ENI is attached to. This is where the problem starts. I ran tcpdump on the port in question and saw multiple SYNs going to the ENI with src '10.1.3.12' and destination '10.1.1.190' but didn't see even a single ACK. In my understanding if ACKs were being sent from the ENI they'd have destination as 10.1.3.12 i.e. the same as the local machine's IP and such packets will now be routed as local packets matching local routing policy: local 10.1.3.12 dev eth0 proto kernel scope host src 10.1.3.12 I'd like to send all the packets originating from 10.1.1.190 (my ENI) to go back on the same interface i.e. eth3 in this case. Contents of the nee table 10003 are: $ sudo ip route show table 10003 default via 10.1.1.1 dev eth3 I think I can do the following: I don't know if its possible but probably decrease the priority of local table so the packets match the table 10003. Use iptables to mangle these packets and update the local table route to include the mark information But I'm not sure if these are the right approaches.

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  • How do I create a point system in a Rails app that assigns points to users and non-authenticated-use

    - by codyvbrown
    I'm building a question and answer application on top of twitter and I'm hitting some snags because I'm inevitably dealing with two classes of users: authenticated and non-authenticated. The site enable users to give points to other users, who may or may not be authenticated, and I want to create a site-wide point system where the application stores and displays this information on their profile. I want to save this point data to the user because that would be faster and more efficient but non-authenticated users aren't in our system, we only have the twitter handle. So instead we display the points in our system like this: @points = point.all( :select => "tag, count(*) AS count", # Return tag and count :group => 'tag', # Group by the tag :order => "2 desc", :conditions => {:twitter_handle => params[:username]}) Is there a better way to do this? Is there a better way to associate data with non-authenticated users?

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