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  • How to extract a couple marked strings from a line (python)

    - by GoJian
    My Friends, I spent quite some time on this one... but cannot yet figure out a better way to do it. I am coding in python, by the way. So, here is a line of text in a file I am working with, for example: "ref|ZP_01631227.1| 3-dehydroquinate synthase [Nodularia spumigena CCY9414]..." How can I extract the two strings "ZP_01631227.1" and "Nodularia spumigena CCY9414" from the line? The pairs of "| |" and brackets are like markers so we know we want to get the strings in between the two... I guess I can probably loop over all the characters in the line and do it the hard way. It just takes so much time... Wondering if there is a python library or other smart ways to do it nicely? Thanks to all!

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  • RealPath returns an empty string

    - by Abs
    Hello all, I have the following which just loops through the files in a directory and echo the file names. However, when I use realpath, it returns nothing. What am I doing wrong: if ($handle = opendir($font_path)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != "a.zip") { echo $file.'<br />';//i can see file names fine echo realpath($file);// return empty string?! } } closedir($handle); } Thanks all for any help on this. ~I am on a windows machine, running php 5.3 and apache 2.2.

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  • How can I do the multiple replace in python?

    - by prosseek
    As asked and answered in HERE, I need to replace '[' with '[[]', and ']' with '[]]'. I tried to use s.replace(), but as it's not in place change, I ran as follows to get a wrong anwser. path1 = "/Users/smcho/Desktop/bracket/[10,20]" path2 = path1.replace('[','[[]') path3 = path2.replace(']','[]]') pathName = os.path.join(path3, "*.txt") print pathName -- /Users/smcho/Desktop/bracket/[[[]]10,20[]]/*.txt How can I do the multiple replace in python? Or how can I replace '[' and ']' at the same time?

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  • Concatenate String to Evernote Markup Language (ENML) in python

    - by Adam the Mediocre
    I am looking to add a string containing the user's text input to the note.content of my note. After reading, I have found how to add resources, but I don't want the resource to be an attachment, I want it to be the actual text. Here is some of the code: title= self.textEditTitle.text() body= self.textEditBody.text() auth_token = "secret stuff!" client = EvernoteClient(token=auth_token, sandbox=True) note_store = client.get_note_store() nBody = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" nBody += "<!DOCTYPE en-note SYSTEM \"http://xml.evernote.com/pub/enml2.dtd\">" nBody += "<en-note>%s</en-note>" % body note = Types.Note() note.title = title note.content= nBody Any advice would be great, as I'm just starting out with this api and it looks like it's full of potential once I figure it out! Here is what I have been mostly reading from: http://dev.evernote.com/documentation/cloud/chapters/ENML.php

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  • jquery textarea custom tags replacement

    - by Tim
    Hi all, I'm basically trying to create my own tags - and replace them with the right HTML tags. So {B} {/B} would turn into <b> </b> I have only got so far with this, here: http://www.nacremedia.com/text2.htm Use the [B] button to bold stuff the current selection... it creates two bold tags and one closing for some reason. I'm so close! But I just need a bit of direction to get the final bugs out - can anyone please help?? Also, if there is a better way of doing this altogether then I am more than welcome to new ideas.

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  • Parse multiple filters in SQL

    - by Jeff Meatball Yang
    I have a problem parsing a stored procedure parameter in the form: declare @S varchar(100) set @S = '4=2,24=1534' Here's the query: select cast(idx as varchar(100)) 'idx' , value , SUBSTRING(value, 1, charindex(value, '=')+1) 'first' , SUBSTRING(value, charindex(value, '=')+1, LEN(value)-charindex(value, '=')-1) 'second' from Common.SplitToTable(@S, ',') -- returns (idx int, value varchar(max)) where len(value) > 0 But here is the result I get: idx value first second 0 4=2 4 4= 1 24=1534 2 24=153 Here's what I expected: idx value first second 0 4=2 4 2 1 24=1534 2 1534 Help?

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  • Weird characters at the beginning of a LPTSTR? C++

    - by extintor
    I am using this code to get the windows version: define BUFSIZE 256 bool config::GetOS(LPTSTR OSv) { OSVERSIONINFOEX osve; BOOL bOsVersionInfoEx; ZeroMemory(&osve, sizeof(OSVERSIONINFOEX)); osve.dwOSVersionInfoSize = sizeof(OSVERSIONINFOEX); if( !(bOsVersionInfoEx = GetVersionEx ((OSVERSIONINFO *) &osve)) ) return false; TCHAR buf[BUFSIZE]; StringCchPrintf(buf, BUFSIZE, TEXT("%u.%u.%u.%u"), osve.dwPlatformId, osve.dwMajorVersion, osve.dwMinorVersion, osve.dwBuildNumber); StringCchCat(OSv, BUFSIZE, buf); return true; } And I am testing it with: LPTSTR OSv= new TCHAR[BUFSIZE]; config c; c.GetOS(OSv); MessageBox(OSv, 0, 0); And in the msgbox I get something like this äì5.1.20 (where 5.1.20 is = to OSv) but the first 2 or 3 chars are some weird characters that I don't know when they came from. Even stranger, if I call that second piece again it shows it ok, it only show the weird characters the first time I execute it. Does someone has an idea what's going on here?

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  • convert an int to list of individual digitals more faster?

    - by user478514
    All, I want define an int(987654321) <= [9, 8, 7, 6, 5, 4, 3, 2, 1] convertor, if the length of int number < 9, for example 10 the list will be [0,0,0,0,0,0,0,1,0] , and if the length 9, for example 9987654321 , the list will be [9, 9, 8, 7, 6, 5, 4, 3, 2, 1] >>> i 987654321 >>> l [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> z = [0]*(len(unit) - len(str(l))) >>> z.extend(l) >>> l = z >>> unit [100000000, 10000000, 1000000, 100000, 10000, 1000, 100, 10, 1] >>> sum([x*y for x,y in zip(l, unit)]) 987654321 >>> int("".join([str(x) for x in l])) 987654321 >>> l1 = [int(x) for x in str(i)] >>> z = [0]*(len(unit) - len(str(l1))) >>> z.extend(l1) >>> l1 = z >>> l1 [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> a = [i//x for x in unit] >>> b = [a[x] - a[x-1]*10 for x in range(9)] >>> if len(b) = len(a): b[0] = a[0] # fix the a[-1] issue >>> b [9, 8, 7, 6, 5, 4, 3, 2, 1] I tested above solutions but found those may not faster/simple enough than I want and may have a length related bug inside, anyone may share me a better solution for this kinds convertion? Thanks!

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  • Excel macro to change external data query connections - e.g. point from one database to another

    - by Rory
    I'm looking for a macro/vbs to update all the external data query connections to point at a different server or database. This is a pain to do manually and in versions of Excel before 2007 it sometimes seems impossible to do manually. Anyone have a sample? I see there are different types of connections 'OLEDB' and 'ODBC', so I guess I need to deal with different formats of connection strings?

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  • Invoking a function call in a string in an Oracle Procedure

    - by DMS
    Hello, I writing an application using Oracle 10g. I am currently facing this problem. I take in "filename" as parameter of type varchar2. A sample value that filename may contain is: 'TEST || to_char(sysdate, 'DDD')'. In the procedure, I want to get the value of this file name as in TEST147. When i write: select filename into ffilename from dual; I get the value ffilename = TEST || to_char(sysdate, 'DDD') whick makes sense. But how can I get around this issue and invoke the function in the string value? Help appreciated. Thanks.

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  • Splitting a string into new rows in R

    - by user3703195
    I have a data set like below: Country Region Molecule Item Code IND NA PB102 FR206985511 THAI AP PB103 BA-107603 / F000113361 / 107603 LUXE NA PB105 1012701 / SGP-1012701 / F041701000 IND AP PB106 AU206985211 / CA-F206985211 THAI HP PB107 F034702000 / 1010701 / SGP-1010701 BANG NA PB108 F000007970/25781/20009021 I want to split based the string values in ITEMCODE column on / and create a new row for each entry. For instance, the desired output will be: Country Region Molecule Item Code New row IND NA PB102 FR206985511 FR206985511 THAI AP PB103 BA-107603 / F000113361 / 107603 F000113361 107603 BA-107603 LUXE NA PB105 1012701 / SP-1012701 / F041701000 1012701 SP-1012701 F041701000 IND AP PB106 AU206985211 / CA-F206985211 AU206985211 CA-F206985211 THAI HP PB107 F034702000 / 1010701 / SP-1010701 F034702000 1010701 SP-1010701 BANG NA PB108 F000007970/25781/20009021 F000007970 25781 20009021 I tried the below code library(splitstackshape) df2=concat.split.multiple(df1,"Plant.Item.Code","/", direction="long") but got the Error "Error: memory exhausted (limit reached?)" When i tried strsplit() i got the below error message. Error in strsplit(df1$Plant.Item.Code, "/") : non-character argument Any help from you will be appreciated.

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  • Structure's with strings and input

    - by Beginnernato
    so i have the following structure and function that add's things to the function - struct scoreentry_node { struct scoreentry_node *next; int score; char* name; } ; typedef struct scoreentry_node *score_entry; score_entry add(int in, char* n, score_entry en) { score_entry r = malloc(sizeof(struct scoreentry_node)); r->score = in; r->name = n; r->next = en; return r; } i have input that take it in the following main file: int score; char name[]; int main(void) { score_entry readin = NULL; while(1) { scanf("%s%d", name, &score); readin = add(score, name, readin); // blah blah I dont know why but when input a name it gets added to readin, but when i input another name all the name's in readin have this new name for example: input: bob 10 readin = 10 bob NULL jill 20 readin = 20 jill 10 jill NULL I dont know why bob disappear's... any reason why it does that ?

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  • Cocoa - Localized string from NSDate, NSCalendarDate...

    - by SirRatty
    I'm using NSDate to get a string such as "18 Jun 09", with code: NSDate *theDate = [NSDate date]; NSString *dateString = [theDate descriptionWithCalendarFormat:@"%d %b %y" timeZone:nil locale: nil]; This works, but only results in an English output. I need the output to be localized in the user's default language. Does Cocoa (Mac OS X 10.4, 10.5 in this case) provide a facility for this localization or do I have to manually localize for each case of day and & month names my self? (I have provided a locale, but although that does provide a locale-specific ordering of the date, it does not appear to do any localization of day-month names.)

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  • mysql: get all rows into 1 column

    - by andufo
    hi, i have 3 tables: post (id_post, title) tag (id_tag, name) post_tag (id_post_tag, id_post, id_tag) Lets suppose that id_post 3 has 4 linked tags 1,2,3,4 (soccer, basket, tennis and golf). Is there a way to return something like this in ONE row? col 1 id_post = 3 col 2 tags = soccer basket tennis golf Thanks

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  • Why does strlen not working for me?

    - by tushar
    char p[4]={'h','g','y'}; cout<<strlen(p); This code prints 3. char p[3]={'h','g','y'}; cout<<strlen(p); This prints 8. char p[]={'h','g','y'}; cout<<strlen(p); This again prints 8. Please help me as I can't figure out why three different values are printed by changing the size of the array.

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  • #include <string> adding ~43 KB to my exe

    - by Lienau
    I'm using Code::Blocks to write my program and when I include <string> (or <iostream>) the size of my exe grows. My program is very simple and I need to keep it small <20kb. I'm pretty sure this is happening because of the C++ Standards Committee swapped the old .h versions for many new libraries without the .h. But how would I keep it from adding the ~43kb? Are there settings for Code::Blocks so that it wont add the extra kb or is there another native lib I can use?

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  • order array containing text and numbers

    - by ptrn
    I'm looking for the easiest way to sort an array that consists of numbers and text, and a combination of these. E.g. '123asd' '19asd' '12345asd' 'asd123' 'asd12' turns into '19asd' '123asd' '12345asd' 'asd12' 'asd123' This is going to be used in combination with the solution to another question I've asked here. The sorting function in itself works, what I need is a function that can say that that '19asd' is smaller than '123asd'. I'm writing this in JavaScript.

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