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  • Enterprise ASP.NET MVC application architecture

    - by Ben
    I am still trying to figure out the right architecture for a complex ASP.NET MVC web application. I looked in a lot of example code and everywhere it's done differently. I would really appreciate your thoughts on this. Another Question: Would you use Linq to SQL or the Entity Framework? Thanks, -Ben

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  • Eclipse Debug Mode disrupting SQL Server 2005 Stored Procedure access

    - by Sathish
    We have a strange problem in our team. When a developer is using Eclipse in Debug mode, SQL Server 2005 blocks other developers from accessing a stored procedure. Debug session typically involves opening Hibernate session to persist an entity which could be accessing a stored procedure used for Primary key generation. Debugging is done in business logic code and rarely in JDBC stored procedure call. Is there any way to configure SQL server or the stored procedure so that other developers are not blocked?

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  • Reading from an embedded resource stream

    - by shadeMe
    I've been trying to access an image resource named "IndexPointer.jpg" in an embedded RESX file called "Images.resx". GetManifestResourceNames() returns a single value - SCtor.Images.resources". Assembly::GetExecutingAssembly()-GetManifestResourceStream("SCtor.Images.resources.IndexPointer.jpg") only returns a nullptr. Obviously, I've got the manifest name wrong. What would be the correct one ?

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  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

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  • Does Java have an equivalent to .NET resource (.resx) files for localization?

    - by frankadelic
    Does Java have an equivalent to .NET resource (.resx) files for localization? In .NET, you can define resources as key-value pairs within a standard XML document. The resource files are named according to the culture. For example: myresources.resx myresources.en-us.resx myresources.fr-fr.resx myresources.de-de.resx Is there an equivalent in Java? Are the similar naming conventions used for files?

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  • EntityManagerFactory error on Websphere

    - by neverland
    I have a very weird problem. Have an application using Hibernate and spring.I have an entitymanger defined which uses a JNDI lookup .It looks something like this <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="persistenceUnitName" value="ConfigAPPPersist" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true" /> <property name="generateDdl" value="false" /> <property name="databasePlatform" value="org.hibernate.dialect.Oracle9Dialect" /> </bean> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.WebSphereDataSourceAdapter"> <property name="targetDataSource"> <bean class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="jdbc/pmp" /> </bean> </property> </bean> This application runs fine in DEV. But when we move to higher envs the team that deploys this application does it successfully initially but after a few restarts of the application the entitymanager starts giving this problem Caused by: javax.persistence.PersistenceException: [PersistenceUnit: ConfigAPPPersist] Unable to build EntityManagerFactory at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:677) at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:132) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:224) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:291) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1368) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1334) ... 32 more Caused by: org.hibernate.MappingException: **property mapping has wrong number of columns**: com.***.***.jpa.marketing.entity.MarketBrands.$performasure_j2eeInfo type: object Now you would say this is pretty obvious the entity MarketBrands is incorrect. But its not it maps to the table just fine. And the same code works on DEV. Also the jndi cannot be incorrect since it deploys and works fine initially but throws uo this error after a restart. This is weird and not very logical. But if someone has faced this or has any idea on what might be causing this Please!! help The persistence.xml for the persitence unit has very little <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="ConfigAPPPersist"> <!-- commented code --> </persistence-unit> </persistence>

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  • What good alternatives are there to Google Charts?

    - by Rhubarb
    I have been experimenting with Google charts. Are there any alternatives that are reasonably as expressive but can be installed locally on your own web server? I don't like the idea of relying on an outside entity for a feature to work. Even if it is for cost, it would be preferable. Any suggestions?

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  • Am I using EJBs properly?

    - by kgrad
    I am using a JEE6 stack including JPA 2.0, JSF 2.0, EJB 3.1 etc. The way my architecture is setup is the following: I have JPA annotated DAOs using hibernate as my JPA provider. I have JSF Managed beans which correspond to my facelet/xhtml pages. I have EJBs that handle all of my database requests. My XHTML pages have JSF EL which make calls to my Managed beans. My managed beans contain references to my DAO entities which are managed by EJBs. For example, I have a user entity which is mapped to a db table. I have a user EJB which handles all CRUD operations that return Users. I have a page that edits a user. The highlevel workflow would be: navigate to user edit page - EL calls a method located in the managed bean that loads a user. The method calls userEJB.loadUser(user) from the EJB to get the user from the database. The user is edited and submit - a function is called in the managed bean which calls a function in the EJB to save the user. etc. I am running into issues accessing my data within my JSF pages using EJBs. I am having a lot of problems with lazy initialization errors, which I believe is due to how I have set things up. For example, I have a Client entity that has a List of users which are lazily loaded. In order to get a client I call a method in my EJB which goes to the database, finds a client and returns it. Later on i wish to access this clients list of users, in order to do so i have to go back to the EJB by calling some sort of method in order to load those users (since they are lazily loaded). This means that I have to create a method such as public List<User> getUserListByClient(Client c) { c = em.merge(c); return c.getUserList(); } The only purpose of this method is to load the users (and I'm not even positive this approach is good or works). If i was doing session management myself, I would like just leave the session open for the entire request and access the property directly, this would be fine as the session would be open anyway, there seems to be this one extra layer of indirection in EJBs which is making things difficult for me. I do like EJBs as I like the fact that they are controlled by the container, pooled, offer transaction management for free etc. However, I get the feeling that I am using them incorrectly, or I have set up my JSF app incorrectly. Any feedback would be greatly appreciated. thanks,

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  • Spring Roo from WSDL?

    - by Tom O'Brien
    Hi folks, Spring Roo + GWT is very exciting but I'd like to use an existing Web Service as a backend so I was wondering if there is any way to configure Roo to use a WSDL as the starting point rather than the entity description (and have it wire in the Jax-WS calls to the service). Thanks!

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  • display wait gif until image is fully loaded

    - by Dimitris Baltas
    Most popular browsers, while rendering an image, they display it line-by-line top-to-bottom as it loads. I have a requirement that a wait gif should be displayed while the image is loading. When the image is fully loaded then it should be displayed instead of the wait gif. If it helps, the site is http://farros.gr, main image: /images/bg.jpg and the div containing the image is named #main-content-image.

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  • SOAP-ERROR: Parsing WSDl

    - by Pinu
    In my ASP.NET website I am trying to comsume a webserice and I and getting the following error: SOAP-ERROR: Parsing WSDL: Couldn't load from 'https://usaepay.com/soap/gate/3213EA2A/usaepay.wsdl' : failed to load external entity "https://usaepay.com/soap/gate/3213EA2A/usaepay.wsdl" Any idea on how to resolve it. Thanks, Pinaz.

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  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

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  • how to get all controls of win form?

    - by Shailesh
    i have a win form named A , A contains lots of different controls ,first contains a main groubbox and this groupbox countains lots of table and others group boxes. i want to find a control which has tab index 9(example) in form A but i dont know which groubox contains this control. how i found this control. regards Shailesh

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  • Error after installing Django (supposed PATH or PYTHONPATH "error")

    - by illuminated
    Hi all, I guess this is a PATH/PYTHONPATH error, but my attempts failed so far to make django working. System is Ubuntu 10.04, 64bit: mx:~/webapps$ cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=10.04 DISTRIB_CODENAME=lucid DISTRIB_DESCRIPTION="Ubuntu 10.04 LTS" Python version: 2.6.5: @mx:~/webapps$ python -V Python 2.6.5 When I run django-admin.py, the following happens: mx:~/webapps$ django-admin.py Traceback (most recent call last): File "/usr/local/bin/django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core Similar when I import django in python shell: mx:~/webapps$ python Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import django Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named django >>> quit() More details: mx:~/webapps$ python -c "from distutils.sysconfig import get_python_lib; print get_python_lib()" /usr/lib/python2.6/dist-packages Within python shell: Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/usr/lib/python2.6/dist-packages/django', '/usr/local/lib/python2.6/dist-packages/django/bin', '/usr/local/lib/python2.6/dist-packages/django', '/home/petra/webapps', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages/PIL', '/usr/lib/pymodules/python2.6'] django-admin.py can be found here: mx:~/webapps$ locate django-admin.py ~/install/sources/Django-1.2.1/build/lib.linux-i686-2.6/django/bin/django-admin.py ~/install/sources/Django-1.2.1/build/scripts-2.6/django-admin.py ~/install/sources/Django-1.2.1/django/bin/django-admin.py /usr/local/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.pyc and in the end this doesn't help: export PYTHONPATH="/usr/lib/python2.6/dist-packages/django:$PYTHONPATH" nor this: export PYTHONPATH="/usr/local/lib/python2.6/dist-packages/django:$PYTHONPATH" How to solve this !? Thanks all in advance! :)

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  • Detect same image names {iPhone SDK}

    - by Momeks
    hi , i want create image animation , i have 50 images with png format now i want set images name ... something like this but doesnt work ! my images name are : iamge_0000 to image_0050 NSArray *myImages = [NSArray arrayWithObjects: [UIImage imageNamed:@"image_%d.png"], //image named doesnt work ??!?!?!?

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  • WinForms binding

    - by Anthony
    I have some controls bound to a BindingSource control. I want to do a calculation when the value changes in one control and set the result on another control. Do i update the textbox the property is bound to or do i update the underlying entity which would update the control anyway(i hope)? When i change textbox A...textbox B is updated with the new calculated result..this works fine...but i have noticed that when i Leave textbox A..textbox B reverts back to its original value...what is going on here!

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  • sorl-thumbnail: random name in Thumbnail field

    - by xRobot
    I want to use str(uuid.uuid4()) instead of the name uploaded. I have this model: class foo(models.Model): pic = ThumbnailField(upload_to='pics', size=(200, 200)) I am uploading hello_world.jpg and I should save these named versions should be saved for example in 4ba9b397-da69-4307-9bce-e92887e84d2f.jpg. How can I do that?

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  • Multiple foreign keys to same table using Elixir

    - by Suvir
    Hello, I am new to ORMs in general. I have a table (lets call it Entity) with columns -- ID expression type ( can be 'long_word', 'short_word' or 'sentence' ) Often, the first two types occur in a 'sentence', so, I want to maintain another table which maps 'Sentences' to 'long_word' or 'short_word' using the 'ID' field. All i need is another table with 2 'Integer fields' referring to 'ID' as a foreign key. But, how do i do this in Elixir? Thanks a lot...

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  • Android calculator with button click

    - by rynwtts
    I am trying to calculate a field named lblAnswer by adding values txtA + txtB. I am fairly new to the android development world and would like to know what is the best way of going about this. I have already added the necessarily edit fields to the GUI. I am now working in the java file to try and create the method. This method has been named doCalc. Here is what I have thus far. public void doCalc() { lblAnswer = txtA + txtB; } It has been suggested that I add more code here is the full code. Thank you for that suggestion. Here is the Java File. package com.example.wattsprofessional; import android.app.Activity; import android.os.Bundle; import android.view.Menu; public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.activity_main, menu); return true; } public void doCalc() { lblAnswer = txtA + txtB; Double.parseDouble(txtA.getText().toString()); lblAnswer.setText"t } and here is the xml file. <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" tools:context=".MainActivity" > <EditText android:id="@+id/txtA" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentTop="true" android:layout_centerHorizontal="true" android:layout_marginTop="40dp" android:ems="10" android:hint="Write Here" android:inputType="numberDecimal" > <requestFocus /> </EditText> <EditText android:id="@+id/txtB" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignLeft="@+id/txtA" android:layout_below="@+id/txtA" android:layout_marginTop="32dp" android:ems="10" android:hint="Second Here" android:inputType="numberDecimal" /> <Button android:id="@+id/button1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerHorizontal="true" android:layout_centerVertical="true" android:text="@string/calculate" android:onClick="doCalc"/> <TextView android:id="@+id/lblAnswer" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@+id/button1" android:layout_centerHorizontal="true" android:layout_marginTop="50dp" android:text="TextView" /> </RelativeLayout>

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  • how to create internal frame in netbeans platform?

    - by joseph
    I created class NewProject extends JInternalFrame. Then I create New...Action named "NEW", localised in File menu. I put code NewProject p = new NewProject(); p.setVisible(true); to the ActionPerformed method of the action. But when I run the module and click "NEW" in file menu, nothing appears. Where can be problem?

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  • running python script with cron

    - by paulo
    hey guys, im trying to run a python script after every 5 minutes using cron, inside the script is a django import import django when running the crontab i get mailed the following error ImportError: No module named django this is what the crontab file looks like: [email protected] */5 * * * * /usr/bin/python /Users/paulo/Desktop/ashtanga/ping/sender.py do anyone of you know whats causing this ? btw i do have django insalled version 1.2, python 2.6, and MacOX 10.6

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  • Accessing other controls by name in a Silverlight ControlTemplate

    - by Chris S
    I have a custom control that inherits from ContentControl. Inside the generic.xaml file is a simple Grid with 2 rows: Row 1 - A toggle button Row 2 - A StackPanel with a TextBlock, named "Stackpanel1" The ToggleButton has its own nested ControlTemplate which has VisualStates for Checked/Unchecked. Is it possible to reference "Stackpanel1" from inside the ToggleButton's control template somehow? In order to show or hide the stackpanel.

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