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  • How to create an "edit" url for a restful resouce?

    - by Freewind
    In my partial template, there is a varible named "resource", it may be a question or an answer. I want to build a link to edit it, but when I use it, I don't know what it is, so I can't write: <%=link_to 'edit', edit_question_url(resource)%> or <%=link_to 'edit', edit_answer_url(resource)%> I wonder if there is such a method, say "url_for_edit()", can be used as: <%=link_to 'edit', url_for_edit(resource)%> Is there such a method?

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  • CDI SessionScoped Bean instance remains unchanged when login with different user

    - by Jason Yang
    I've been looking for the workaround of this problem for rather plenty of time and no result, so I ask question here. Simply speaking, I'm using a CDI SessionScoped Bean User in my project to manage user information and display them on jsf pages. Also container-managed j_security_check is used to resolve authentication issue. Everything is fine if first logout with session.invalidate() and then login in the same browser tab with a different user. But when I tried to directly login (through login.jsf) with a new user without logout beforehand, I found the user information remaining unchanged. I debugged and found the User bean, as well as the HttpSession instance, always remaining the same if login with different users in the same browser, as long as session.invalidate() not invoked. But oddly, the session id did modified, and I've both checked in Java code and Firebug. org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c69a71d19f369d08b5dddbea2ef0] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue=org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c6ab4b0c51ee0a649ef696faef75] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue = org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = com.sun.faces.renderkit.ServerSideStateHelper.LogicalViewMap : attrValue = {-4968076393130137442={-7694826198761889564=[Ljava.lang.Object;@43ff5d6c}} attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 Above block contains two successive logins and their Session info. We can see that the instance(1st row) the same while session id(2nd row) different. Seems that session object is reused to contain different session id and CDI framework manages session bean life cycle in accordance with the session object only(?). I'm wondering whether there could be only one server-side session object within the same browser unless invalidated? Since I'm adopting j_security_check I fancy intercepting it and invalidating old session is not so easy. So is it possible to accomplish the goal without altering the CDI+JSF+j_security_check design that one can relogin with different account in the same or different tab within the same browser? Really look forward for your response. More info: Glassfish v3.1 is my appserver.

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  • Spring Roo from WSDL?

    - by Tom O'Brien
    Hi folks, Spring Roo + GWT is very exciting but I'd like to use an existing Web Service as a backend so I was wondering if there is any way to configure Roo to use a WSDL as the starting point rather than the entity description (and have it wire in the Jax-WS calls to the service). Thanks!

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  • Castle Windsor XML configuration for WCF proxy using WCF Integration Facility

    - by andreyg
    Hi everybody! Currently, we use programming registration of WCF proxies in Windsor container using WCF Integration Facility. For example: container.Register( Component.For<CalculatorSoap>() .Named("calculatorSoap") .LifeStyle.Transient .ActAs(new DefaultClientModel { Endpoint = WcfEndpoint.FromConfiguration("CalculatorSoap").LogMessages() } ) ); Is there any way to do the same via Windsor XML configuration file. I can't find any sample of this on google. Thanks in advance

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  • Detect same image names {iPhone SDK}

    - by Momeks
    hi , i want create image animation , i have 50 images with png format now i want set images name ... something like this but doesnt work ! my images name are : iamge_0000 to image_0050 NSArray *myImages = [NSArray arrayWithObjects: [UIImage imageNamed:@"image_%d.png"], //image named doesnt work ??!?!?!?

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  • iPhone: Speeding up a search that's polling 17,000 Core Data objects

    - by randombits
    I have a class that conforms to UISearchDisplayDelegate and contains a UISearchBar. This view is responsible for allowing the user to poll a store of about 17,000 objects that are currently managed by Core Data. Everytime the user types in a character, I created an instance of a SearchOperation (subclasses NSOperation) that queries Core Data to find results that might match the search. The code in the search controller looks something like: - (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope { // Update the filtered array based on the search text and scope in a secondary thread if ([searchText length] < 3) { [filteredList removeAllObjects]; // First clear the filtered array. [self setFilteredList:NULL]; [self.tableView reloadData]; return; } NSDictionary *searchdict = [NSDictionary dictionaryWithObjectsAndKeys:scope, @"scope", searchText, @"searchText", nil]; [aSearchQueue cancelAllOperations]; SearchOperation *searchOp = [[SearchOperation alloc] initWithDelegate:self dataDict:searchdict]; [aSearchQueue addOperation:searchOp]; } And my search is rather straight forward. SearchOperation is a subclass of NSOperation. I overwrote the main method with the following code: - (void)main { if ([self isCancelled]) { return; } NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"MyEntity" inManagedObjectContext:managedObjectContext]; NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; [fetchRequest setEntity:entity]; NSPredicate *predicate = NULL; predicate = [NSPredicate predicateWithFormat:@"(someattr contains[cd] %@)", searchText]; [fetchRequest setPredicate:predicate]; NSError *error = NULL; NSArray *fetchResults = [managedObjectContext executeFetchRequest:fetchRequest error:&error]; [fetchRequest release]; if (self.delegate != nil) [self.delegate didFinishSearching:fetchResults]; [pool drain]; } This code works, but it has several issues. It's slow. Even though I have the search happening in a separate thread other than the UI thread, querying 17,000 objects is clearly not optimal. If I'm not careful, crashes can happen. I set the max concurrent searches in my NSOperationQueue to 1 to avoid this. What else can I do to make this search faster? I think preloading all 17,000 objects into memory might be risky. There has to be a smarter way to conduct this search to give results back to the user faster.

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  • Connect to Mongodb in python

    - by SpawnCxy
    I'm a little confused by the document when I tried to connect to the Mongodb.And I find it's different from mysql.I want to create a new database named "mydb" and insert some posts into it.The follows is what I'm trying. from pymongo.connection import Connection import datetime host = 'localhost' port = 27017 user = 'ucenter' passwd = '123' connection = Connection(host,port) db = connection['mydb'] post = {'author':'mike', 'text':'my first blog post!', 'tags':['mongodb','python','pymongo'], 'date':datetime.datetime.utcnow()} posts = db.posts posts.insert(post) #print str(db.collection_names()) And I got an error as pymongo.errors.OperationFailure: database error: unauthorized.How can I do the authorizing part?Thanks.

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  • Why can't I use __getattr__ with Django models?

    - by Joshmaker
    I've seen examples online of people using __getattr__ with Django models, but whenever I try I get errors. (Django 1.2.3) I don't have any problems when I am using __getattr__ on normal objects. For example: class Post(object): def __getattr__(self, name): return 42 Works just fine... >>> from blog.models import Post >>> p = Post() >>> p.random 42 Now when I try it with a Django model: from django.db import models class Post(models.Model): def __getattr__(self, name): return 42 And test it on on the interpreter: >>> from blog.models import Post >>> p = Post() ERROR: An unexpected error occurred while tokenizing input The following traceback may be corrupted or invalid The error message is: ('EOF in multi-line statement', (6, 0)) --------------------------------------------------------------------------- TypeError Traceback (most recent call last) /Users/josh/project/ in () /Users/josh/project/lib/python2.6/site-packages/django/db/models/base.pyc in init(self, *args, **kwargs) 338 if kwargs: 339 raise TypeError("'%s' is an invalid keyword argument for this function" % kwargs.keys()[0]) -- 340 signals.post_init.send(sender=self.class, instance=self) 341 342 def repr(self): /Users/josh/project/lib/python2.6/site-packages/django/dispatch/dispatcher.pyc in send(self, sender, **named) 160 161 for receiver in self._live_receivers(_make_id(sender)): -- 162 response = receiver(signal=self, sender=sender, **named) 163 responses.append((receiver, response)) 164 return responses /Users/josh/project/python2.6/site-packages/photologue/models.pyc in add_methods(sender, instance, signal, *args, **kwargs) 728 """ 729 if hasattr(instance, 'add_accessor_methods'): -- 730 instance.add_accessor_methods() 731 732 # connect the add_accessor_methods function to the post_init signal TypeError: 'int' object is not callable Can someone explain what is going on? EDIT: I may have been too abstract in the examples, here is some code that is closer to what I actually would use on the website: class Post(models.Model): title = models.CharField(max_length=255) slug = models.SlugField() date_published = models.DateTimeField() content = RichTextField('Content', blank=True, null=True) # Etc... Class CuratedPost(models.Model): post = models.ForeignKey('Post') position = models.PositiveSmallIntegerField() def __getattr__(self, name): ''' If the user tries to access a property of the CuratedPost, return the property of the Post instead... ''' return self.post.name # Etc... While I could create a property for each attribute of the Post class, that would lead to a lot of code duplication. Further more, that would mean anytime I add or edit a attribute of the Post class I would have to remember to make the same change to the CuratedPost class, which seems like a recipe for code rot.

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  • how to refresh/reload dhtmlx grid

    - by steve
    I am using dhtmlx grid.I have two grids named grid1,grid2. I have loaded the two grids using json object. If i select one record in the grid1 and click on the button that record has to load in the second record.I am able to load that selected record in the second grid using document.location.reload(true);with this, the total page is refreshing.but i want to refresh grid2 only. I want to refresh grid2 only after click on the button.how can i refresh/reload grid2.

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  • How can I add dynamic field in the model in django ?

    - by Wu Jie
    Hello, I'm using django to create a application download site. I try to write a model, that the admin can add the different download content dynamically in the admin page. For example I have a software named foobar, it have 3 different version: 1.1, 1.2, 1.3. I would like the user can admin the model by using an add button to add the download link with a download version. But I don't know how to do this in django.

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  • method names with fluent interface

    - by deamon
    I have a Permissions class with methods in fluent style like this: somePermissions.setRead(true).setWrite(false).setExecute(true) The question is, whether I should name these methods set{Property} or only {property}. The latter would look like this: somePermissions.read(true).write(false).execute(true) If I look at these methods separately I would expect that read reads something, but on the other hand it is closer to the intention to have something like named paramaters like in Scala: Permission(read=true, write=false, execute=true)

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  • How to rename model

    - by samuil
    I made a mistake early in development, and named one of my models with plural noun (Users instead of User). Is there an easy way to rename it and corresponding controller (similar to generating it with script/generate way)?

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  • Core Data and NSDate

    - by Pierre
    Hi ! I read this post but I don't really understand the code... I have a core data database with an Entity and some attributes. One of them is named "myDate" and has for type NSDate. Now I want to to display each date but eliminate dates with same day-month-year and display them ascendantly . Have you got an idea? Thanks a lot !

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  • Usernames are evil. How can I make Restful Authentication only require an email address and password

    - by Koning WWWWWWWWWWWWWWWWWWWWWWW
    As the title says: how can I use the Restful Authentication Plugin with Ruby on Rails. When I want to create a new user, it requires me to set the (wrong-named, confusing field) login (= username), email address and password. However, I want, like Facebook does, to require the user to enter only an email address and password, not a username. People will also login with this email address. Can anyone help me?

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  • Provisioning api jpa

    - by user268515
    Hi i tried the following code Appsprovisioning.java public void calluser() throws AppsForYourDomainExceptiion IOException, { for(UserEntry userEntry : retrieveAllUsers().getEntries()) { m[x]= userEntry.getTitle().getPlainText(); x++; } try { for(int i=0;i<x;i++) { String sd=m[i]; stud greeting1 = new stud(sd); em.persist(greeting1); System.out.println("jk"); } } finally { em.close(); } public UserFeed retrieveAllUsers()throws ,ServiceException, IOException{ userService = new UserService("Myapplication"); userService.setUserCredentials("[email protected]","xxxxxxxx"); URL retrieveUrl = new URL("https://www.google.com/a/feeds/montfortperungudi.edu.in/user/2.0/"); UserFeed allUsers = new UserFeed(); UserFeed currentPage; Link nextLink; do { currentPage = userService.getFeed(retrieveUrl, UserFeed.class); allUsers.getEntries().addAll(currentPage.getEntries()); nextLink = currentPage.getLink(Link.Rel.NEXT, Link.Type.ATOM); if (nextLink != null) { retrieveUrl = new URL(nextLink.getHref()); } } while (nextLink != null); return allUsers; } } Servlet.java public class servlet extends HttpServlet { private static final long serialVersionUID = 1L; private static final Logger log = Logger.getLogger(servlet.class.getName()); // EntityManager em=null; AppsProvisioning aa=new AppsProvisioning(); public void doGet(HttpServletRequest req, HttpServletResponse resp)throws IOException { //em = EMFService.get().createEntityManager(); try { aa.calluser(); }catch(Exception e){ System.out.println("SEF "+e);} finally { // em.clear(); // em.close(); } } } Table Creation import javax.persistence.Entity; import javax.persistence.Id; @Entity(name="stud") public class stud { @Id private String fathername; public stud(String fathername) {// TODO Auto-generated constructor stub this.fathername=fathername; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } } I cant able to store all the users in the table.. Its returning Session out error.

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  • What is massively parallel processing (MPP) ?

    - by HotTester
    Ever since Microsoft introduced sql-server version code-named "Madison" the massively parallel processing (MPP) has got into picture. What exactly is it and how does sql-server is going to benefit from it ? Further is massively parallel processing (MPP) related to parallel computing ? I read about Madison here and about parallel computing here. Thanks in advance.

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  • Hibernate mapping, on a unmapped class

    - by Jan
    Hi, I' ve got 2 tables... Challenge and ChallengeYear, ChallengeYear is only to create a list of years in challenge. I only want to make Challenge an entity, containing a list of List years. Is this possible? I've looked in to @SecondaryTable together with @JoinColumn and @OneToMany, but neither of those can do the trick, or i am overlooking something. Can someone help me? Greetings, Jan

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  • Labeled fixtures for associations in Rails 3 broken

    - by elsurudo
    After upgrading to Rails 3, fixtures that refer to other labelled fixtures (for relationships) stop working. Instead of finding the actual fixture with that name, the fixture label is interpreted as a string. Example: # Dog.yml sparky: name: Sparky owner: john # Person.yml john: name: John Where Dog "belongs to" person. The error message is: SQLite3::SQLException: table dogs has no column named 'owner'

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  • Rails Scaffold problem # undefined method `edit_pais_path'

    - by Bruno Cordeiro
    I created a scaffold of named pais (This is a word in Portuguese of Brazil and is the same that country), i created using the follow command: ruby script\generate scaffold pais name:string abreviattion:string First I changed the inflections to my local idiom, like that: inflect.plural /^([a-zA-z]*)s$/i, '\1ses' #The plural of Pais is Paises And when I tryied to open the page on http://localhost:3000/paises I'm receiving the follow error: undefined method `edit_pais_path' for #<ActionView::Base:0x387fdf4> Thanks in advance.

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  • Run all SQL files in a directory

    - by Khalil Dahab
    I have a number of .sql files which I have to run in order to apply changes made by other developers on an SQL Server 2005 database. The files are named according to the following pattern: 0001 - abc.sql 0002 - abcef.sql 0003 - abc.sql ... Is there a way to run all of them in one go?

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  • Enum values doubts?

    - by maddy
    Hi all, Is there any possible way to do any arithmetic operations on enum values enum Type{Zero=0,One,Two,Three,Four,Five,Six,Seven,Eight,Nine}; main() { enum Type Var = Zero; for(int i=0;i<10;i++) { switch(Var) { case Zero: /*do something*/ case One: /*Do something*/ ..... } Var++;(I know that this increment is not possible,But is there anyway by which we can have this variable named Var increment. regards maddy

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  • CSS Calendar Display

    - by Steven
    I created my own custom date picker consisting of an ASP TextBox, Button, and Calendar complete with CSS styles, javascript code, and event handling vb code. I want to use this date picker multiple times on my form. I know the wrong way to do this would be to copy all the code and just adjust each name accordingly. How can I put those controls, styles, and code into a single entity?

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