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  • how to write this typical mysql query( ho to use subquery column into main query)

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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  • PHP & MySQL submit error message problem

    - by peakUC
    When I submit a new name and not a new avatar I get the following avatar error message Please upload a .gif, .jpeg, .jpg or .png image!. I want to be able to send a new name only without having to upload a new avatar each time I submit the form without getting the avatar error message Please upload a .gif, .jpeg, .jpg or .png image! can someone help me fix this problem? Here is the php code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['first_name']))); $user_id = '3'; if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if($_FILES["avatar"]["type"] == "image/gif" || $_FILES["avatar"]["type"] == "image/jpeg" || $_FILES["avatar"]["type"] == "image/jpg" || $_FILES["avatar"]["type"] == "image/png" || $_FILES["avatar"]["type"] == "image/pjpeg") { if (file_exists("../members/" . $user_id . "/images/" . $_FILES["avatar"]["name"])) { echo '<p class="error">' . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))) . ' already exists! '; } else if($_FILES["avatar"]["name"] == TRUE) { move_uploaded_file($_FILES["avatar"]["tmp_name"], "../members/" . $user_id . "/images/" . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"]))))); $avatar = mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))); } } else if($_FILES["avatar"]["type"] != "image/gif" || $_FILES["avatar"]["type"] != "image/jpeg" || $_FILES["avatar"]["type"] != "image/jpg" || $_FILES["avatar"]["type"] != "image/png" || $_FILES["avatar"]["type"] != "image/pjpeg") { echo '<p class="error">Please upload a .gif, .jpeg, .jpg or .png image!</p>'; } } else if($_FILES['avatar']['size'] >= 5242880) { echo '<p class="error">Please upload a smaller pic!</p>'; } else if($_FILES["avatar"]["name"] == NULL) { $avatar = NULL; } if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, avatar) VALUES ('$user_id', '$first_name', '$avatar')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', avatar = '$avatar' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } }

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  • Unique Key in MySql

    - by Vinodtiru
    I have a table with four Columns. Col1, Col2, Col3, and Col4. Col1, Col2, Col3 is string and Col4 is a integer primary key with Auto Increment. Now my requirement is to have unique combination of Col2 and Col3. I mean to say like. Insert into table(Col1,Col2,Col3) Values('val1','val2','val3'); Insert into table(Col1,Col2,Col3) Values('val4','val2','val3'); the second statement has to throw error as the same combination of 'val2','val3' is present in the table. But i cant make it as a primary key as i need a auto increment column and for that matter the col4 has to be primary. Please let me know a approach by which i can have both in my table. Any kind of help is appreciated. Thanks.

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  • [Newbie] How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • How to display multiple cell entries individually from a MySQL database and using PHP

    - by Jake
    I have a column called post_tags where there is sometimes one tag entry and sometimes multiple tags stored. These are separated by * symbols. I want to display these out to the screen one by one. If there were just one item inside the cell I would have used: $query = mysql_query("SELECT post_tags FROM posts WHERE id=$id"); while ($result = mysql_fetch_assoc($query)) { $result['post_tags']; } But how can I display each entry individually when there are multiple ones in one cell (is this what the explode function is for)?

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  • effective retrieve for a voting system in PHP and MySQL

    - by Adnan
    Hello, I have a system where registered users can vote up/vote down comment for a picture. Something very similar to SO's voting system. I store the votes in a table with values as such; vote_id | vote_comment_id | vote_user_id | vote_date | vote_type Now I have few a question concerned the speed and efficiency for the following; PROB: Once a user opens the picture page with comments I need, if that user has already voted UP/DOWN a comment to show it like; "you voted up" or "you voted down" next to the comment (in SO it the vote image is highlighted) MY POSSIBLE SOL: Right now when I open a picture page for each comment I loop thru, I loop thru my table of votes as well and check if a user has voted and show the status (I compare the vote_user_id with the user's session). How efficient is this? Anyone have a better approach to tackle this kind of problem?

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  • mysql create table help with unique

    - by Matt
    I'm trying to create a table, and can't figure out how to assign two columns to be unique.. I know how to alter a table thats already created, but how do you do it in the create.. im after a create if not exist col1 TEXT, col2 TEXT, col3 TEXT unique(col1, col2) ^very rough basic but you get the idea

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  • mysql database normalization question

    - by Chocho
    here is my 3 tables: table 1 -- stores user information and it has unique data table 2 -- stores place category such as, toronto, ny, london, etc hence this is is also unique table 3 -- has duplicate information. it stores all the places a user have been. the 3 tables are linked or joined by these ids: table 1 has an "table1_id" table 2 has an "table2_id" and "place_name" table 3 has an "table3_id", "table1_id", "place_name" i have an interface where an admin sees all users. beside a user is "edit" button. clicking on that edit button allows you to edit a specific user in a form fields which has a multiple drop down box for "places". if an admin edits a user and add 1 "places" for the user, i insert that information using php. if the admin decides to deselect that 1 "places" do i delete it or mark it as on and off? how about if the admin decides to select 2 "places" for the user; change the first "places" and add an additional "places". will my table just keep growing and will i have just redundant information? thanks.

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  • MySql: Problem when using a temporary table

    - by Alex
    Hi, I'm trying to use a temporary tables to store some values I need for a query. The reason of using a temporary table is that I don't want to store the data permanently so different users can modify it at the same time. That data is just stored for a second, so I think a temporary table is the best approach for this. The thing is that it seems that the way I'm trying to use it is not right (the query works if I use a permanent one). This is an example of query: CREATE TEMPORARY TABLE SearchMatches (PatternID int not null primary key, Matches int not null) INSERT INTO SearchMatches (PatternID, Matches) VALUES ('12605','1'),('12503','1'),('12587','2'),('12456','1'), ('12457','2'),('12486','2'),('12704','1'),(' 12686','1'), ('12531','2'),('12549','1'),('12604','1'),('12504','1'), ('12586','1'),('12548','1'),('12 530','1'),('12687','2'), ('12485','1'),('12705','1') SELECT pat.id, signatures.signature, products.product, versions.version, builds.build, pat.log_file, sig_types.sig_type, pat.notes, pat.kb FROM patterns AS pat INNER JOIN signatures ON pat.signature = signatures.id INNER JOIN products ON pat.product = products.id INNER JOIN versions ON pat.version = versions.id INNER JOIN builds ON pat.build = builds.id INNER JOIN sig_types ON pat.sig_type = sig_types.id, SearchMatches AS sm INNER JOIN patterns ON patterns.id = sm.PatternID WHERE sm.Matches <> 0 ORDER BY sm.Matches DESC, products.product, versions.version, builds.build LIMIT 0 , 50 Any suggestion? Thanks.

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  • mysql: how to set max_allowed_packet for shared hosting?

    - by Sadi
    Hello, I need to set (increase) max_allowed_packet. But the problem is I am using a shared hosting. So, I can not access the .ini or .cnf file. Also I can not use the SET command. How can I am able to set a value (actually increase) for the max_allowed_packet, without asking the hosting support. I have no SSH access there. EDIT: I am trying to use VB 4.0.3. In there the attachment size is limited by it. So, I do not think splitting the file can be an option in this case. Thank you Sadi

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  • redirect user, then log his visit using php and mysql

    - by Bart van Heukelom
    I have a PHP redirect page to track clicks on links. Basically it does: - get url from $_GET - connect to database - create row for url, or update with 1 hit if it exists - redirect browser to url using Location: header I was wondering if it's possible to send the redirect to the client first, so it can get on with it's job, and then log the click. Would simply switching things around work?

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  • complex MySQL Order by not working

    - by Les Reynolds
    Here is the select statement I'm using. The problem happens with the sorting. When it is like below, it only sorts by t2.userdb_user_first_name, doesn't matter if I put that first or second. When I remove that, it sorts just fine by the displayorder field value pair. So I know that part is working, but somehow the combination of the two causes the first_name to override it. What I want is for the records to be sorted by displayorder first, and then first_name within that. SELECT t1.userdb_id FROM default_en_userdbelements as t1 INNER JOIN default_en_userdb AS t2 ON t1.userdb_id = t2.userdb_id WHERE t1.userdbelements_field_name = 'newproject' AND t1.userdbelements_field_value = 'no' AND t2.userdb_user_first_name!='Default' ORDER BY (t1.userdbelements_field_name = 'displayorder' AND t1.userdbelements_field_value), t2.userdb_user_first_name; Edit: here is what I want to accomplish. I want to list the users (that are not new projects) from the userdb table, along with the details about the users that is stored in userdbelements. And I want that to be sorted first by userdbelements.displayorder, then by userdb.first_name. I hope that makes sense? Thanks for the really quick help! Edit: Sorry for disappearing, here is some sample data userdbelements userdbelements_id userdbelements_field_name userdbelements_field_value userdb_id 647 heat 1 648 displayorder 1 - Sponsored 1 645 condofees 1 userdb userdb_id userdb_user_name userdb_emailaddress userdb_user_first_name userdb_user_last_name 10 harbourlights [email protected] Harbourlights 1237 Northshore Blvd, Burlington 11 harbourview [email protected] Harbourview 415 Locust Street, Burlington 12 thebalmoral [email protected] The Balmoral 2075 & 2085 Amherst Heights Drive, Burlington

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  • PHP + SQL Server or VB.NET + MySQL

    - by Muhammad Mussnoon
    Can someone suggest that out of the two mentioned (odd?) combinations, which is less odd, or in other words, is less trouble to work with + maintain. If it helps, the system is going to have two front-ends - one web application and one desktop application. The desktop application is going to be coded using VB.NET, and the web application in PHP. There's really no reason why the desktop application can't be replaced by a web application as well - except that one of the programmers seem to really want to code it in VB.... However, none of us have experience working with either of these pairs (you could easily call us n00bs), so we are a bit apprehensive to start. P.S. hosting service will be gotten from some provider and not be on the client's own server.

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  • MySQL problem: How to get desired rows.

    - by Joonas Köppä
    I have been trying to solve this problem for 2 hours now but I cant understand the solutions others have given people with a similar problem. Ive seen some answers but can't apply it to my own needs. I have a table of users and their times in different sports events. I need to make a scoretable that shows the user with the best time, second best etc. The table before sorting and retrieving looks as follows: | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 05:03:12 | 2010-12-03 | | Jack | 03:53:19 | 2010-12-04 | | Simon | 03:22:59 | 2010-12-02 | | Simon | 04:01:11 | 2010-12-09 | | Peter | 03:19:17 | 2010-12-06 | '''''''''''''''''''''''''''''''''''''''''''''' | Name | Time | Date | '''''''''''''''''''''''''''''''''''''''''' | Jack | 03:07:13 | 2010-12-01 | | Peter | 03:19:17 | 2010-12-06 | | Simon | 03:22:59 | 2010-12-02 | '''''''''''''''''''''''''''''''''''''''''' I know answers to this problem lie in another question asked on this very site: CLICK HERE I just have no idea how to apply it to fullfill my needs. Help is highly appreciated. Thank you -Joonas

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  • PHP, MySQL: Receive email, auto search in DB & send email based on the results

    - by Devner
    Hi all, Visitors can contact staff by means of contact form (visitor needs to submit email as well). This will be stored in DB. Now considering that staff responds to this message, the reply from the staff would be sent to the visitors email directly. Say if the user wants to follow up on the message sent by the staff, I would like the visitor to just hit the reply button in his email service & send me his questions on the same topic, but just retain the ID in the Subject line. So when the visitor send this email, I would like to receive the email & at the same time, try to search in my DB if the ID that is present in the email subject, actually exists in the system. If yes, that would be sent back to the same staff member who handled the response previously or it would be assigned to a new staff member. That being said, I was thinking of how to do this. The part where I am really held up is when the staff receives the actual email from the visitors email, how can I check the DB? Say I am/staff is receiving emails at [email protected]. When visitor sends reply email, then it would be sent to [email protected]. How can I check to see if the ID in the subject line of the email that I received at [email protected], actually exists in my DB in my website? This is where I am really stuck. Looking forward for your replies. Thank you.

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  • In python, changing MySQL query based on function variables

    - by ensnare
    I'd like to be able to add a restriction to the query if user_id != None ... for example: "AND user_id = 5" but I am not sure how to add this into the below function? Thank you. def get(id, user_id=None): query = """SELECT * FROM USERS WHERE text LIKE %s AND id = %s """ values = (search_text, id) results = DB.get(query, values) This way I can call: get(5) get(5,103524234) (contains user_id restriction)

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  • Fetch data from multiple MySQL tables

    - by Jon McIntosh
    My two tables look like this: TABLE1 TABLE2 +--------------------+ +--------------------+ |field1|field2|field3| and |field2|field4|field5| +--------------------+ +--------------------+ I am already running a SELECT query for TABLE1, and assorting all of the data into variables: $query = "SELECT * FROM TABLE1 WHERE field2 = 2"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $field1 = $row['field1']; $field2 = $row['field2']; $field3 = $row['field3']; } } What I want to do is get the data from 'field4' on TABLE2 and add it to my variables. I would want to get field4 WHERE field2 = 2

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  • Mysql data convert

    - by Sergio
    Is it possible to do DATE_SUB( ".$date." , INTERVAL 100 DAY ) if the type of the column where the date is stored is varchar(255) or I need to convert that column to "DATE" type?

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  • MySQL GROUP BY and JOIN

    - by christian
    Guys what's wrong with this SQL query: $sql = "SELECT res.Age, res.Gender, answer.*, $get_sum, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females FROM Respondents AS res INNER JOIN Answers as answer ON answer.RespondentID=res.RespondentID INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY res.Age ORDER BY res.Age ASC"; the $get_sum is an array of sql statement derived from another table: $sum[]= "SUM(CASE WHEN answer.Answer=".$db->f("id")." THEN 1 else 0 END) AS item".$db->f("id"); $get_sum = implode(', ', $sum); the query above return these values: Age: 20 item1 0 item2 1 item3 1 item4 1 item5 0 item6 0 Subtotal for Age 20 3 Age: 24 item1 2 item2 2 item3 2 item4 2 item5 1 item6 0 Subtotal for Age 24 9 It should return: Subtotal for Age 20 1 Subtotal for Age 24 2 In my sample data there are 3 respondents 2 are 24 yrs of age and the other one is 20 years old.

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  • Collaborative filtering in MySQL ?

    - by user281434
    Hi I'm trying to develop a site that recommends items(fx. books) to users based on their preferences. So far, I've read O'Reilly's "Collective Intelligence" and numerous other online articles. They all, however, seem to deal with single instances of recommendation, for example if you like book A then you might like book B. What I'm trying to do is to create a set of 'preference-nodes' for each user on my site. Let's say a user likes book A,B and C. Then, when they add book D, I don't want the system to recommend other books based solely other users experience with book D. I wan't the system to look up similar 'preference-nodes' and recommend books based on that. Here's an example of 4 nodes: User1: 'book A'->'book B'->'book C' User2: 'book A'->'book B'->'book C'->'book D' user3: 'book X'->'book Y'->'book C'->'book Z' user4: 'book W'->'book Q'->'book C'->'book Z' So a recommendation system, as described in the material I've read, would recommend book Z to User 1, because there are two people who recommends Z in conjuction with liking C (ie. Z weighs more than D), even though a user with a similar 'preference-node', User2, would be more qualified to recommend book D because he has a more similar interest-pattern. So does any of you have any experience with this sort of thing? Is there some things I should try to read or does there exist any open source systems for this? Thanks for your time! Small edit: I think last.fm's algorithm is doing exactly what I my system to do. Using the preference-trees of people to recommmend music more personally to people. Instead of just saying "you might like B because you liked A"

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  • Count Distinct With IF in MySQL?

    - by user1600801
    I need to do a query with count distinct and IF, but the results always are 0. What I need to do, is count the different users from a table in different months, using IF. My individual query, for one month is this: SELECT COUNT(DISTINCT(idUsers)) AS num_usuarios FROM table01 WHERE date1='201207' But I need to get the results by different months in the same query. What I'm trying to do is this: SELECT IF(date1=(201207), count(distinct(idUsers)), 0) as user30, IF(fecha1=(201206), count(distinct(idUsers)), 0) as user60, IF(fecha1=(201205), count(distinct(idUsers)), 0) as user90, IF(fecha1=(201204), count(distinct(idUsers)), 0) as user120, IF(fecha1=(201203), count(distinct(idUsers)), 0) as user150 FROM table01 But the all the results are always 0.

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