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  • How do I remove the time from printpreview dialog?

    - by Albo Best
    Here is my code: Imports System.Data.OleDb Imports System.Drawing.Printing Namespace Print Public Class Form1 Inherits System.Windows.Forms.Form Dim PrintC As PrinterClass Dim conn As OleDb.OleDbConnection Dim connectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=..\\db1.mdb" Dim sql As String = String.Empty Dim ds As DataSet Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load FillDataGrid() '//create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) End Sub Private Sub FillDataGrid() Try Dim dt As New DataTable Dim ds As New DataSet ds.Tables.Add(dt) Dim da As New OleDbDataAdapter con.Open() da = New OleDbDataAdapter("SELECT * from klient ", con) da.Fill(dt) con.Close() dataGrid.DataSource = dt.DefaultView Dim dTable As DataTable For Each dTable In ds.Tables Dim dgStyle As DataGridTableStyle = New DataGridTableStyle dgStyle.MappingName = dTable.TableName dataGrid.TableStyles.Add(dgStyle) Next ' DataGrid settings dataGrid.CaptionText = "TE GJITHE KLIENTET" dataGrid.HeaderFont = New Font("Verdana", 12) dataGrid.TableStyles(0).GridColumnStyles(0).Width = 60 dataGrid.TableStyles(0).GridColumnStyles(1).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(2).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(3).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(4).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(5).HeaderText = "" dataGrid.TableStyles(0).GridColumnStyles(5).Width = -1 Catch ex As Exception MessageBox.Show(ex.Message) End Try End Sub Private Sub btnPrint_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPrint.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) PrintDocument1.Print() End Sub Private Sub btnPreview_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPreview.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) ''preview Dim ps As New PaperSize("A4", 840, 1150) ps.PaperName = PaperKind.A4 PrintDocument1.DefaultPageSettings.PaperSize = ps PrintPreviewDialog1.WindowState = FormWindowState.Normal PrintPreviewDialog1.StartPosition = FormStartPosition.CenterScreen PrintPreviewDialog1.ClientSize = New Size(600, 600) PrintPreviewDialog1.ShowDialog() End Sub Private Sub PrintDocument1_PrintPage(ByVal sender As System.Object, ByVal e As System.Drawing.Printing.PrintPageEventArgs) Handles PrintDocument1.PrintPage 'print grid Dim morepages As Boolean = PrintC.Print(e.Graphics) If (morepages) Then e.HasMorePages = True End If End Sub End Class End Namespace This is how data looks in DataGrid (that's perfect)... and here is how it looks when I click PrintPreview. (I don't want the time to appear there, the "12:00:00" part. in database the date is stored as Short Date (10-Dec-12) Can somebody suggest a way around that? Imports System Imports System.Windows.Forms Imports System.Drawing Imports System.Drawing.Printing Imports System.Collections Imports System.Data Namespace Print Public Class PrinterClass '//clone of Datagrid Dim PrintGrid As Grid '//printdocument for initial printer settings Private PrintDoc As PrintDocument '//defines whether the grid is ordered right to left Private bRightToLeft As Boolean '//Current Top Private CurrentY As Single = 0 '//Current Left Private CurrentX As Single = 0 '//CurrentRow to print Private CurrentRow As Integer = 0 '//Page Counter Public PageCounter As Integer = 0 '/// <summary> '/// Constructor Class '/// </summary> '/// <param name="pdocument"></param> '/// <param name="dgrid"></param> Public Sub New(ByVal pdocument As PrintDocument, ByVal dgrid As DataGrid) 'MyBase.new() PrintGrid = New Grid(dgrid) PrintDoc = pdocument '//The grid columns are right to left bRightToLeft = dgrid.RightToLeft = RightToLeft.Yes '//init CurrentX and CurrentY CurrentY = pdocument.DefaultPageSettings.Margins.Top CurrentX = pdocument.DefaultPageSettings.Margins.Left End Sub Public Function Print(ByVal g As Graphics, ByRef currentX As Single, ByRef currentY As Single) As Boolean '//use predefined area currentX = currentX currentY = currentY PrintHeaders(g) Dim Morepages As Boolean = PrintDataGrid(g) currentY = currentY currentX = currentX Return Morepages End Function Public Function Print(ByVal g As Graphics) As Boolean CurrentX = PrintDoc.DefaultPageSettings.Margins.Left CurrentY = PrintDoc.DefaultPageSettings.Margins.Top PrintHeaders(g) Return PrintDataGrid(g) End Function '/// <summary> '/// Print the Grid Headers '/// </summary> '/// <param name="g"></param> Private Sub PrintHeaders(ByVal g As Graphics) Dim sf As StringFormat = New StringFormat '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = 0 To PrintGrid.Columns - 1 '//set header alignment Select Case (CType(PrintGrid.Headers.GetValue(i), Header).Alignment) Case HorizontalAlignment.Left 'left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX -= PrintGrid.Headers(i).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX += PrintGrid.Headers(i).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY = CurrentY + CType(PrintGrid.Headers.GetValue(0), Header).Height End Sub Private Function PrintDataGrid(ByVal g As Graphics) As Boolean Dim sf As StringFormat = New StringFormat PageCounter = PageCounter + 1 '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = CurrentRow To PrintGrid.Rows - 1 Dim j As Integer For j = 0 To PrintGrid.Columns - 1 '//set cell alignment Select Case (PrintGrid.Cell(i, j).Alignment) '//left Case HorizontalAlignment.Left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center '//right Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX -= PrintGrid.Cell(i, j).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text '//Draw text by alignment g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX += PrintGrid.Cell(i, j).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY += PrintGrid.Cell(i, 0).Height CurrentRow += 1 '//if we are beyond the page margin (bottom) then we need another page, '//return true If (CurrentY > PrintDoc.DefaultPageSettings.PaperSize.Height - PrintDoc.DefaultPageSettings.Margins.Bottom) Then Return True End If Next Return False End Function End Class End Namespace

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  • C question on functions

    - by benjamin button
    some times i see that functions are defined as below: read_dir(dir) char *dir; { DIR * dirp; struct dirent *d; /* open directory */ dirp = opendir(dir); ......... so on here what is the importance of the statement char *dir; what is the intension behind declaring the pointer soon after the function name and then starting the function body.

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  • Perl code -need some understanding.

    - by benjamin button
    Hi i have a perl code below: foreach (@tmp_cycledef) { chomp; my ($cycle_code, $close_day, $first_date) = split(/\|/, $_,3); $cycle_code =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; $close_day =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; $first_date =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; #print "$cycle_code, $close_day, $first_date\n"; $cycledef{$cycle_code} = [ $close_day, split(/-/,$first_date) ]; } the value of tmp_cycledef comes from output of an sql query: select cycle_code,cycle_close_day,to_char(cycle_first_date,'YYYY-MM-DD') from cycle_definition d order by cycle_code; can anybody tell me what exactly is happening inside the for loop? thanks in advance.

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  • why is my reputation deducted? [closed]

    - by benjamin button
    hi, yesterday i had a reputation more than 2600. today when i opened the site it suddenly reduced to 1574!!!!. but i am not able to figure out how and why did it get reduced? this question is probably concerned to the administrators or any regular user can present their opinion!. could anybody please tell?

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  • storing an integral value in a pointer variable while declaration

    - by benjamin button
    int main() { int *d=0; printf("%d\n",*d); return 0; } this works fine. >cc legal.c > ./a.out 0 if i change the statement int *d=0; to int *d=1; i see the error. cc: "legal.c", line 6: error 1522: Cannot initialize a pointer with an integer constant other than zero. so its obvious that it will allow only zero.i want to know what happens inside the memory when we do this int *d=0 which is making it valid syntax. I am just asking this out of curiosity!

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  • What's happening in this Perl foreach loop?

    - by benjamin button
    I have this Perl code: foreach (@tmp_cycledef) { chomp; my ($cycle_code, $close_day, $first_date) = split(/\|/, $_,3); $cycle_code =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; $close_day =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; $first_date =~ s/^\s*(\S*(?:\s+\S+)*)\s*$/$1/; #print "$cycle_code, $close_day, $first_date\n"; $cycledef{$cycle_code} = [ $close_day, split(/-/,$first_date) ]; } The value of tmp_cycledef comes from output of an SQL query: select cycle_code,cycle_close_day,to_char(cycle_first_date,'YYYY-MM-DD') from cycle_definition d order by cycle_code; What exactly is happening inside the for loop?

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  • Perl -check for uninitialized value

    - by benjamin button
    I am doing the below in a perl script: my @pm1_CS_missing_months = `sqlplus -s $connstr \@DLmissing_months.sql`; it takes the output of an sql query. if i have to check for no rows selected,how could i do it? i want to do like this: if(no rows selected) { do this; }

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  • percentage of memory used used by a process

    - by benjamin button
    percentage of memory used used by a process. normally prstat -J will give the memory of process image and RSS(resident set size) etc. how do i knowlist of processes with percentage of memory is used by a each process. i am working on solaris unix. addintionally ,what are the regular commands that you use for monitoring processes,performences of processes that might be very useful to all!

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  • sql query need a help.

    - by benjamin button
    If i have a table with two fields.customer id and order. let's say i have in total order ID 1,2,3,4 all the customer can have all the four orders.like below 1234 1 1234 2 1234 3 1234 4 3245 3 3245 4 5436 2 5436 4 you can see above that 3245 customer doesnt have order id 1 and 2. how could i print in the query output like 3245 1 3245 2 5436 1 5436 3 EDIT: i dont order table but i have list of order's like we can hard code it in the query(1,2,3,4) i dont have an orders table.

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  • What's wrong with this statement in perl?

    - by benjamin button
    print "$_", join(',',sort keys %$h),"\n"; It's giving me an error below: Use of uninitialized value in string at missing_months.pl line 36. 1,10,11,12 this print statement is present in a for loop as below: foreach my $num ( sort keys %hash ) { my $h = $hash{$num}; print "$_", join(',',sort keys %$h),"\n"; }

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  • storing an integer constant other than zero in a pointer variable

    - by benjamin button
    int main() { int *d=0; printf("%d\n",*d); return 0; } this works fine. >cc legal.c > ./a.out 0 if i change the statement int *d=0; to int *d=1; i see the error. cc: "legal.c", line 6: error 1522: Cannot initialize a pointer with an integer constant other than zero. so its obvious that it will allow only zero.i want to know what happens inside the memory when we do this int *d=0 which is making it valid syntax. I am just asking this out of curiosity!

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  • Why do I get strange output from Perl using SQL?

    - by benjamin button
    Here is my Perl code: foreach my $line (@tmp_field_validation) { chomp $line; my ($cycle_code,$cycle_month,$cycle_year)= split /\s*\|\s*/, $line; $cycle_code=~ s/^\s*(.*)\s*$/$1/; $cycle_month=~ s/^\s*(.*)\s*$/$1/; $cycle_year=~ s/^\s*(.*)\s*$/$1/; print "$line\n"; print "$cycle_code|$cycle_month|$cycle_year"; } Here is the output: 1 10 2009 1 10 2009|| What's wrong over here? I expected the pipes to be between the variables. Why are the pipes getting printed after all the three variables?

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  • How do I use Perl to parse the output of the sqlplus command?

    - by benjamin button
    I have an SQL file which will give me an output like below: 10|1 10|2 10|3 11|2 11|4 . . . I am using this in a Perl script like below: my @tmp_cycledef = `sqlplus -s $connstr \@DLCycleState.sql`; after this above statement, since @tmp_cycledef has all the output of the SQL query, I want to show the output as: 10 1,2,3 11 2,4 How could I do this using Perl?

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  • sorting group of lines

    - by benjamin button
    I have a text file like below iv_destination_code_10 TAP310_mapping_RATERUSG_iv_destination_code_10 RATERUSG.iv_destination_code_10 = WORK.maf_feature_info[53,6] iv_destination_code_2 TAP310_mapping_RATERUSG_iv_destination_code_2 RATERUSG.iv_destination_code_2 = WORK.maf_feature_info[1,6] iv_destination_code_3 TAP310_mapping_RATERUSG_iv_destination_code_3 RATERUSG.iv_destination_code_3 = WORK.maf_feature_info[7,6] iv_destination_code_4 TAP310_mapping_RATERUSG_iv_destination_code_4 RATERUSG.iv_destination_code_4 = WORK.maf_feature_info[13,6] iv_destination_code_5 TAP310_mapping_RATERUSG_iv_destination_code_5 RATERUSG.iv_destination_code_5 = WORK.maf_feature_info[19,6] iv_destination_code_6 TAP310_mapping_RATERUSG_iv_destination_code_6 RATERUSG.iv_destination_code_6 = WORK.maf_feature_info[29,6] iv_destination_code_7 TAP310_mapping_RATERUSG_iv_destination_code_7 RATERUSG.iv_destination_code_7 = WORK.maf_feature_info[35,6] iv_destination_code_8 TAP310_mapping_RATERUSG_iv_destination_code_8 RATERUSG.iv_destination_code_8 = WORK.maf_feature_info[41,6] iv_destination_code_9 TAP310_mapping_RATERUSG_iv_destination_code_9 RATERUSG.iv_destination_code_9 = WORK.maf_feature_info[47,6] combination of three lines form a unit: iv_destination_code_9 TAP310_mapping_RATERUSG_iv_destination_code_9 RATERUSG.iv_destination_code_9 = WORK.maf_feature_info[47,6] is one unit. iv_destination_code_9 9 indicates the number by which i have to sort 10 9 8.... i need a shell script/awk which will sort the units in a descending order. how is it possible?

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  • Session state server saying extended class no serializable

    - by jenson-button-event
    I am storing an object in session state (using local session state server), class def is: [Serializable] public class ExtendedOAuth2Parameters : OAuth2Parameters but the service is still reporting: Unable to serialize the session state. In 'StateServer' and 'SQLServer' mode, ASP.NET will serialize the session state objects, and as a result non-serializable objects or MarshalByRef objects are not permitted. [SerializationException: Type 'Google.GData.Client.OAuth2Parameters' in Assembly 'Google.GData.Client, Version=2.1.0.0, Culture=neutral, PublicKeyToken=04a59ca9b0273830' is not marked as serializable.] How to get around it?

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  • Fill in missing values in a SELECT statement

    - by benjamin button
    If i have a table with two fields.customer id and order. let's say i have in total order ID 1,2,3,4 all the customer can have all the four orders.like below 1234 1 1234 2 1234 3 1234 4 3245 3 3245 4 5436 2 5436 4 you can see above that 3245 customer doesnt have order id 1 and 2. how could i print in the query output like 3245 1 3245 2 5436 1 5436 3 EDIT: i dont have order table but i have list of order's like we can hard code it in the query(1,2,3,4) i dont have an orders table.

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