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• extract variables from an expression using javascript regexp

  - by powerboy

  For example, here is a string representing an expression: var str = 'total = sum(price * qty) * 1.09875'; I want to extract variables (i.e., 'total', 'price' and 'qty' but not 'sum' since 'sum' is a function name) from this expression. What is the regexp pattern in javascript? Variable name consists of letters, digits, or the underscore, beginning with letters or the underscore.

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• Regular expression from font to span (size and colour) and back (VB.NET)

  - by chapmanio

  Hi, I am looking for a regular expression that can convert my font tags (only with size and colour attributes) into span tags with the relevant inline css. This will be done in VB.NET if that helps at all. I also need a regular expression to go the other way as well. To elaborate below is an example of the conversion I am looking for: <font size="10">some text</font> To then become: <span style="font-size:10px;">some text</span> So converting the tag and putting a "px" at the end of whatever the font size is (I don't need to change/convert the font size, just stick px at the end). The regular expression needs to cope with a font tag that only has a size attribute, only a color attribute, or both: <font size="10">some text</font> <font color="#000000">some text</font> <font size="10" color="#000000">some text</font> <font color="#000000" size="10">some text</font> I also need another regular expression to do the opposite conversion. So for example: <span style="font-size:10px;">some text</span> Will become: <font size="10">some text</font> As before converting the tag but this time removing the "px", I don't need to worry about changing the font size. Again this will also need to cope with the size styling, font styling, and a combination of both: <span style="font-size:10px;">some text</span> <span style="color:#000000;">some text</span> <span style="font-size:10px; color:#000000;">some text</span> <span style="color:#000000; font-size:10px;">some text</span> I apprecitate this is a lot to ask, I am hopeless with regular expressions and need to find a way of making these conversions in my code. Thanks so much to anyone that can/is willing to help me!

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• Regular Expression - Block Spam

  - by Immanuel

  Could someone lead me on finding a regular expression that blocks a comma separated list of Spam words I already have? The regular expression needs to match a string with the spam word list I already have. Not that it matters, but I am using PHP.

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• Regular expression that matches valid IPv6 addresses

  - by Readonly

  I'm having trouble writing a regular expression that matches valid IPv6 addresses, including those in their compressed form (with "::" or leading zeros omitted from each byte pair). Can someone suggest a regular expression that would fulfill the requirement? I'm considering expanding each byte pair and matching the result with a simpler regex.

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• Regular Expression

  - by TiagoDias

  Hi all, I cannot manage to get a working regular expression (for use in ASP.NEt Validataor) for the following criteria: - I want all chars from A-Z a-z 0-9 - I don't want the Enter key I have the expression: [\w\s,.-/]*[^\n] but that don't works. Please give-me a hint, Thanks.

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• C# Lambda expression syntax: are brackets necessary?

  - by DevNovice

  I'm new in C# and earlier I saw the lambda expression is like (params) => { expression;} but in LINQ, I saw examples like IEnumerable<string> customerFirstNames = customers.Select(cust => cust.FirstName); No brackets. Are they the same or is there any difference? Thanks a lot.

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• Regular expression using + problem in js

  - by Karthik

  I am using regular expression. In phone validation, i have to use the "+" sign in that. How to provide the + sign in regular expression. Because + sign indicates one or more of preceding character(s). Whether i will provide like this + ?

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• C# Lambda expression syntax, is brackets necessary?

  - by DevNovice

  I'm new in C# and earlier I saw the lambda expression is like (params) = { expression;} but in LINQ, I saw examples like IEnumerable customerFirstNames = customers.Select(cust = cust.FirstName); No brackets. Are they the same or is there any difference? Thanks a lot.

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• simple method that checks text is email with regular expression

  - by user223863

  Can't believe how difficult this seems to be all I want to is to validate a user inout using javascript to make sure that it is an email address. But can't get it to work: I am using: //validates a regulaer expression Utilities2.prototype.validateEmail = function(stringToValidateArg) { alert('about to check regexp'); var regExpPattern = /^[a-zA-Z0-9._-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,4}$/; alert(regExpPattern.test(stringToValidateArg)); } But this always returns false, any ideas why is it because of the regular expression?

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• Help needed in writing regular expression using TCL

  - by user330727

  Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}

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• Help needed in writing regular expression -- TCL

  - by user330727

  Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL i) ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}] I want to write an another regexp which catches/matches only the following string wherever comes ii) (XYZ) My trial: [regexp {^X([Y]*)Z$}]

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• nginx dynamic servername with regular expression doesn't work for co.uk

  - by redn0x

  I'm trying to setup a nginx server which dynamically loads content from a folder for a domain. To do this I'm using regular expressions in the server name like so: server_name ((?<subdomain>.+)\.)?(?<domain>.+)\.(?<tld>.*); This will create a 3 variables for nginx to use later on, for example when using the following url: test.foo.example.com this will evaluate to: $subdomain = test.foo $domain = example $tld = com The problem arises when the co.uk top-level domain is used. In this case when using the url test.foo.example.co.ukit will evaluate to: $subdomain = test.foo.cedira $domain = co $tld = uk How can I edit the regular expression so that it will also work for co.uk?

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• String manipulation of type String substitution in mathematical expression

  - by Peterstone

  Imagine something like exp(49/200)+(x-49/200) I want to pass as argument of the function "roundn" whatever operation that is not a addtion or a subtraction So my expresion became roundn(exp(roundn(49/200,n)),n)+(x - roundn(49/200,n) Well the expression I want to manipulate is this: exp(49/200)+exp(49/200)*(x-49/200)+1/2*exp(49/200)*(x-49/200)^2+1/6*exp(49/200)*(x- 49/200)^3+1/24*exp(49/200)*(x-49/200)^4+1/120*exp(49/200)*(x-49/200)^5+1/720*exp(49/200)*(x-49/200)^6+1/5040*exp(49/200)*(x-49/200)^7+1/40320*exp(49/200)*(x-49/200)^8+1/362880*exp(49/200)*(x-49/200)^9+1/3628800*exp(49/200)*(x-49/200)^10+1/39916800*exp(49/200)*(x-49/200)^11 I´m looking for a method (That include whatever program) not based in lenguage programming, as much batch or somithing like that... Thank you!

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• Regular Expression to replace part of URL in XML file

  - by Richie086

  I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

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• Misbehavior in regular expression in VIM

  - by poissonbreaker

  I am having a problem with a regular expression on vim. I have a pattern as follows: http:\/\/\(\w\+\.\?\)\+ [matches http://(AS MANY WORDS FOLLOWED BY DOT OR NOT ENCOUNTERS) e.g. http://wd1.wd2.com] I have a text as follows: http://wd1.wd2.com/wd3 I am trying to make this substitution on it: s/\(http:\/\/\)\(\w\+\.\?\)\+/\1wd4.wd5.com and the result is http://wd4.wd5.com /wd3 (Notice the white space inserted at the end of the replacement) How can I avoid having this inserted space? I am afraid is a bug in the regexp engine but I am not sure.

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• Convert Dynamic to Type and convert Type to Dynamic

  - by Jon Canning

  public static class DynamicExtensions     {         public static T FromDynamic<T>(this IDictionary<string, object> dictionary)         {             var bindings = new List<MemberBinding>();             foreach (var sourceProperty in typeof(T).GetProperties().Where(x => x.CanWrite))             {                 var key = dictionary.Keys.SingleOrDefault(x => x.Equals(sourceProperty.Name, StringComparison.OrdinalIgnoreCase));                 if (string.IsNullOrEmpty(key)) continue;                 var propertyValue = dictionary[key];                 bindings.Add(Expression.Bind(sourceProperty, Expression.Constant(propertyValue)));             }             Expression memberInit = Expression.MemberInit(Expression.New(typeof(T)), bindings);             return Expression.Lambda<Func<T>>(memberInit).Compile().Invoke();         }         public static dynamic ToDynamic<T>(this T obj)         {             IDictionary<string, object> expando = new ExpandoObject();             foreach (var propertyInfo in typeof(T).GetProperties())             {                 var propertyExpression = Expression.Property(Expression.Constant(obj), propertyInfo);                 var currentValue = Expression.Lambda<Func<string>>(propertyExpression).Compile().Invoke();                 expando.Add(propertyInfo.Name.ToLower(), currentValue);             }             return expando as ExpandoObject;         }     }

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• Documentation often ommits to specify which flavour of regular expression to use, so is there a default flavour that we should all be familiar with?

  - by JW01

  Often I come across documentation that says "use a regular expression here" I have to spend quite some time digging around trying to work out which regular expression format they are expecting. As far as I can tell, there are many types of regular expression. But, at my last place of work I was made to feel stupid when I suggested adding some text to our User Documentation to specify the type of regular expression to be used. When someone says "a regular expression" what is the regular expression syntax most people expect and where is it documented? Update: I was prompted to single-out some examples - but no disrespect to these great projects: eregi docs page is not particularly helpful in explaining expected syntax. Nor can I easily work out the syntax expected here if i just land on the page from a search. No explicit mention of the regular expression pattern expected by PatternExpectation() on the SimpleTest page. etc. etc. here is a highly voted SO answer that seems to assume there is only one flavour of regular expressions.

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• Why isn't one of the constant buffers being loaded inside the shader?

  - by Paul Ske

  I however got the model to load under tessellation; only problem is that one of the constant buffers aren't actually updating the shader's tessellation factor inside the hullshader. I created a messagebox at the rendering point so I know for sure the tessellation factor is assigned to the dynamic constant buffer. Inside the shader code where it says .Edges[1] = tessellationAmount; the tessellationAmount is suppose to be sent from the dynamic buffer to the shader. Otherwise it's just a plain box. In better explanation; there's a matrixBuffer, cameraBuffer, TessellationBuffer for constant. There's a multiBuffer array that assigns the matrix, camera, tesselation. So, when I set the Hull Shader, PixelShader, VertexShader, DomainShader it gets assigned by the multibuffer. E.G. devcon-HSSetConstantBuffers(0,3,multibuffer); The only way around the whole ideal would be to go in the shader and change how much the edges tessellate and inside the edges as well with the same number. My question is why wouldn't the tessellationBuffer not work in the shader?

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• Illegal start of expression?

  - by Fraser

  I'm trying to build a simple Android app that increments a number displayed every time a button is pressed, but I can't work out how to fix the "illegal start of expression" error I keep getting. My code: package com.clicker; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class Clicker extends Activity { private int clickerNumber = 0; private TextView clickerText; private Button clickerButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); clickerText = (TextView)findViewById(R.id.clickerText); final Button clickerButton = (Button)findViewById(R.id.clickerButton); clickerButton.setOnClickListener(new View.OnClickListener()); { public void onClick(); { clickerNumber = clickerNumber++; clickerText.setText(Integer.toString(clickerNumber)); } } } } And compiler output: compile: [javac] Compiling 2 source files to /home/fraser/Applications/Android/Code/Clicker/bin/classes [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:24: ')' expected [javac] clickerButton.setOnClickListener(new View.OnClickListener(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: ';' expected [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:29: ';' expected [javac] clickerText.setText(Integer.toString(clickerNumber))); [javac] ^ [javac] 5 errors

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• .NET Regular Expression to find actual words in text

  - by Mehdi Anis

  I am using VB .NET to write a program that will get the words from a suplied text file and count how many times each word appears. I am using this regular expression:- parser As New Regex("\w+") It gives me almost 100% correct words. Except when I have words like "Ms Word App file name is word.exe." or "is this a c# statment If(ab?1,0) ?" In such cases I get [word & exe] AND [If, a, b, 1 and 0] as seperate words. it would be nice (for my purpose) that I received word.exe and (If(ab?1,0) as words. I guess \w+ looks for white space, sentence terminating punctuation mark and other punctuation marks to determine a word. I want a similar regular Expression that will not break a word by a punctuation mark, if the punctuation mark is not the end of the word. I think end-of-word can be defined by a trailing WhiteSpace, Sentence terminating Punctuation (you may think of others). if you can suggest some regular expression 9for VB .NET) that will be great help. Thanks.

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• Moq.Mock<T> - how to setup a method that takes an expression

  - by Paul

  I am Mocking my repository interface and am not sure how to setup a method that takes an expression and returns an object? I am using Moq and NUnit Interface: public interface IReadOnlyRepository : IDisposable { IQueryable<T> All<T>() where T : class; T Single<T>(Expression<Func<T, bool>> expression) where T : class; } Test with IQueryable already setup, but don't know how to setup the T Single: private Moq.Mock<IReadOnlyRepository> _mockRepos; private AdminController _controller; [SetUp] public void SetUp() { var allPages = new List<Page>(); for (var i = 0; i < 10; i++) { allPages.Add(new Page { Id = i, Title = "Page Title " + i, Slug = "Page-Title-" + i, Content = "Page " + i + " on page content." }); } _mockRepos = new Moq.Mock<IReadOnlyRepository>(); _mockRepos.Setup(x => x.All<Page>()).Returns(allPages.AsQueryable()); //Not sure what to do here??? _mockRepos.Setup(x => x.Single<Page>() //---- _controller = new AdminController(_mockRepos.Object); }

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• Regular expression, excluding .. in suffix of email addy

  - by user1754700

  This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

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• Linq generic Expression in query on "element" or on IQueryable (multiple use)

  - by Bogdan Maxim

  Hi, I have the following expression public static Expression<Func<T, bool>> JoinByDateCheck<T>(T entity, DateTime dateToCheck) where T : IDateInterval { return (entityToJoin) => entityToJoin.FromDate.Date <= dateToCheck.Date && (entityToJoin.ToDate == null || entityToJoin.ToDate.Value.Date >= dateToCheck.Date); } IDateInterval interface is defined like this: interface IDateInterval { DateTime FromDate {get;} DateTime? ToDate {get;} } and i need to apply it in a few ways: (1) Query on Linq2Sql Table: var q1 = from e in intervalTable where FunctionThatCallsJoinByDateCheck(e, constantDateTime) select e; or something like this: intervalTable.Where(FunctionThatCallsJoinByDateCheck(e, constantDateTime)) (2) I need to use it in some table joins (as linq2sql doesn't provide comparative join): var q2 = from e1 in t1 join e2 in t2 on e1.FK == e2.PK where OtherFunctionThatCallsJoinByDateCheck(e2, e1.FromDate) or var q2 = from e1 in t1 from e2 in t2 where e1.FK == e2.PK && OtherFunctionThatCallsJoinByDateCheck(e2, e1.FromDate) (3) I need to use it in some queries like this: var q3 = from e in intervalTable.FilterFunctionThatCallsJoinByDateCheck(constantDate); Dynamic linq is not something that I can use, so I have to stick to plain linq. Thank you Clarification: Initially I had just the last method (FilterFunctionThatCallsJoinByDateCheck(this IQueryable<IDateInterval> entities, DateTime dateConstant) ) that contained the code from the expression. The problem is that I get a SQL Translate exception if I write the code in a method and call it like that. All I want is to extend the use of this function to the where clause (see the second query in point 2)

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• OrderBy Linq.Expression as parameter = (Of Func(Of T,IComparable)) to perform LinqToEntity is not working

  - by NicoJuicy

  I'd like to get this working: Call: (Count & Page are used for pagination, so Count = 20 and Page = 1 for example, for the first 20 values). Sorting should be by name LeverancierService.GetLeveranciers(Function(el) el.Name, Count, Page) Equivalent in c#: LeverancierService.GetLeveranciers(el= el.Name, Count, Page) Method that gives an error (parameters shown above): Public Overridable Function GetAllPaged(orderby As Expression(Of Func(Of T, IComparable)), ByVal Count As Integer, ByVal Page As Integer) As IEnumerable(Of T) Return dbset.OrderBy(orderby).Skip((Page - 1) * Count).Take(Count).ToList() End Function Already tried changing it to this, but it gives the same error: Public Overridable Function GetAllPaged(Of TOrderBy)(orderby As Expression(Of Func(Of T, TOrderBy)), ByVal Count As Integer, ByVal Page As Integer) As IEnumerable(Of T) Return dbset.OrderBy(orderby).Skip((Page - 1) * Count).Take(Count).ToList() End Function Error: Unable to cast the type 'System.String' to type 'System.IComparable'. LINQ to Entities only supports casting Entity Data Model primitive types. Any idea how to do this? Extra info: I'm in a DDD-layered application, so the parameter should stay the same as the called method is an overridden interface (eg. if i change this, i have to do this for 200 times or so, because it's in VB.Net and not in C# (= 1 change) ) I know there is a way to change the expression to a string and then use DLinq (= Dynamic Linq), but that's not how it should be.

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• How to write an R function that evaluates an expression within a data-frame

  - by Prasad Chalasani

  Puzzle for the R cognoscenti: Say we have a data-frame: df <- data.frame( a = 1:5, b = 1:5 ) I know we can do things like with(df, a) to get a vector of results. But how do I write a function that takes an expression (such as a or a > 3) and does the same thing inside. I.e. I want to write a function fn that takes a data-frame and an expression as arguments and returns the result of evaluating the expression "within" the data-frame as an environment. Never mind that this sounds contrived (I could just use with as above), but this is just a simplified version of a more complex function I am writing. I tried several variants ( using eval, with, envir, substitute, local, etc) but none of them work. For example if I define fn like so: fn <- function(dat, expr) { eval(expr, envir = dat) } I get this error: > fn( df, a ) Error in eval(expr, envir = dat) : object 'a' not found Clearly I am missing something subtle about environments and evaluation. Is there a way to define such a function?

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