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• regular expression for challenge value

  - by Salman

  Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

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• Regular expression from font to span (size and colour) and back (VB.NET)

  - by chapmanio

  Hi, I am looking for a regular expression that can convert my font tags (only with size and colour attributes) into span tags with the relevant inline css. This will be done in VB.NET if that helps at all. I also need a regular expression to go the other way as well. To elaborate below is an example of the conversion I am looking for: <font size="10">some text</font> To then become: <span style="font-size:10px;">some text</span> So converting the tag and putting a "px" at the end of whatever the font size is (I don't need to change/convert the font size, just stick px at the end). The regular expression needs to cope with a font tag that only has a size attribute, only a color attribute, or both: <font size="10">some text</font> <font color="#000000">some text</font> <font size="10" color="#000000">some text</font> <font color="#000000" size="10">some text</font> I also need another regular expression to do the opposite conversion. So for example: <span style="font-size:10px;">some text</span> Will become: <font size="10">some text</font> As before converting the tag but this time removing the "px", I don't need to worry about changing the font size. Again this will also need to cope with the size styling, font styling, and a combination of both: <span style="font-size:10px;">some text</span> <span style="color:#000000;">some text</span> <span style="font-size:10px; color:#000000;">some text</span> <span style="color:#000000; font-size:10px;">some text</span> I apprecitate this is a lot to ask, I am hopeless with regular expressions and need to find a way of making these conversions in my code. Thanks so much to anyone that can/is willing to help me!

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• extract variables from an expression using javascript regexp

  - by powerboy

  For example, here is a string representing an expression: var str = 'total = sum(price * qty) * 1.09875'; I want to extract variables (i.e., 'total', 'price' and 'qty' but not 'sum' since 'sum' is a function name) from this expression. What is the regexp pattern in javascript? Variable name consists of letters, digits, or the underscore, beginning with letters or the underscore.

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• Regular Expression - Block Spam

  - by Immanuel

  Could someone lead me on finding a regular expression that blocks a comma separated list of Spam words I already have? The regular expression needs to match a string with the spam word list I already have. Not that it matters, but I am using PHP.

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• Regular expression that matches valid IPv6 addresses

  - by Readonly

  I'm having trouble writing a regular expression that matches valid IPv6 addresses, including those in their compressed form (with "::" or leading zeros omitted from each byte pair). Can someone suggest a regular expression that would fulfill the requirement? I'm considering expanding each byte pair and matching the result with a simpler regex.

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• Regular Expression

  - by TiagoDias

  Hi all, I cannot manage to get a working regular expression (for use in ASP.NEt Validataor) for the following criteria: - I want all chars from A-Z a-z 0-9 - I don't want the Enter key I have the expression: [\w\s,.-/]*[^\n] but that don't works. Please give-me a hint, Thanks.

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• C# Lambda expression syntax: are brackets necessary?

  - by DevNovice

  I'm new in C# and earlier I saw the lambda expression is like (params) => { expression;} but in LINQ, I saw examples like IEnumerable<string> customerFirstNames = customers.Select(cust => cust.FirstName); No brackets. Are they the same or is there any difference? Thanks a lot.

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• Regular expression using + problem in js

  - by Karthik

  I am using regular expression. In phone validation, i have to use the "+" sign in that. How to provide the + sign in regular expression. Because + sign indicates one or more of preceding character(s). Whether i will provide like this + ?

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• C# Lambda expression syntax, is brackets necessary?

  - by DevNovice

  I'm new in C# and earlier I saw the lambda expression is like (params) = { expression;} but in LINQ, I saw examples like IEnumerable customerFirstNames = customers.Select(cust = cust.FirstName); No brackets. Are they the same or is there any difference? Thanks a lot.

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• simple method that checks text is email with regular expression

  - by user223863

  Can't believe how difficult this seems to be all I want to is to validate a user inout using javascript to make sure that it is an email address. But can't get it to work: I am using: //validates a regulaer expression Utilities2.prototype.validateEmail = function(stringToValidateArg) { alert('about to check regexp'); var regExpPattern = /^[a-zA-Z0-9._-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,4}$/; alert(regExpPattern.test(stringToValidateArg)); } But this always returns false, any ideas why is it because of the regular expression?

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• Help needed in writing regular expression using TCL

  - by user330727

  Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}

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• Help needed in writing regular expression -- TCL

  - by user330727

  Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL i) ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}] I want to write an another regexp which catches/matches only the following string wherever comes ii) (XYZ) My trial: [regexp {^X([Y]*)Z$}]

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• nginx dynamic servername with regular expression doesn't work for co.uk

  - by redn0x

  I'm trying to setup a nginx server which dynamically loads content from a folder for a domain. To do this I'm using regular expressions in the server name like so: server_name ((?<subdomain>.+)\.)?(?<domain>.+)\.(?<tld>.*); This will create a 3 variables for nginx to use later on, for example when using the following url: test.foo.example.com this will evaluate to: $subdomain = test.foo $domain = example $tld = com The problem arises when the co.uk top-level domain is used. In this case when using the url test.foo.example.co.ukit will evaluate to: $subdomain = test.foo.cedira $domain = co $tld = uk How can I edit the regular expression so that it will also work for co.uk?

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• String manipulation of type String substitution in mathematical expression

  - by Peterstone

  Imagine something like exp(49/200)+(x-49/200) I want to pass as argument of the function "roundn" whatever operation that is not a addtion or a subtraction So my expresion became roundn(exp(roundn(49/200,n)),n)+(x - roundn(49/200,n) Well the expression I want to manipulate is this: exp(49/200)+exp(49/200)*(x-49/200)+1/2*exp(49/200)*(x-49/200)^2+1/6*exp(49/200)*(x- 49/200)^3+1/24*exp(49/200)*(x-49/200)^4+1/120*exp(49/200)*(x-49/200)^5+1/720*exp(49/200)*(x-49/200)^6+1/5040*exp(49/200)*(x-49/200)^7+1/40320*exp(49/200)*(x-49/200)^8+1/362880*exp(49/200)*(x-49/200)^9+1/3628800*exp(49/200)*(x-49/200)^10+1/39916800*exp(49/200)*(x-49/200)^11 I´m looking for a method (That include whatever program) not based in lenguage programming, as much batch or somithing like that... Thank you!

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• Regular Expression to replace part of URL in XML file

  - by Richie086

  I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

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• Misbehavior in regular expression in VIM

  - by poissonbreaker

  I am having a problem with a regular expression on vim. I have a pattern as follows: http:\/\/\(\w\+\.\?\)\+ [matches http://(AS MANY WORDS FOLLOWED BY DOT OR NOT ENCOUNTERS) e.g. http://wd1.wd2.com] I have a text as follows: http://wd1.wd2.com/wd3 I am trying to make this substitution on it: s/\(http:\/\/\)\(\w\+\.\?\)\+/\1wd4.wd5.com and the result is http://wd4.wd5.com /wd3 (Notice the white space inserted at the end of the replacement) How can I avoid having this inserted space? I am afraid is a bug in the regexp engine but I am not sure.

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• Convert Dynamic to Type and convert Type to Dynamic

  - by Jon Canning

  public static class DynamicExtensions     {         public static T FromDynamic<T>(this IDictionary<string, object> dictionary)         {             var bindings = new List<MemberBinding>();             foreach (var sourceProperty in typeof(T).GetProperties().Where(x => x.CanWrite))             {                 var key = dictionary.Keys.SingleOrDefault(x => x.Equals(sourceProperty.Name, StringComparison.OrdinalIgnoreCase));                 if (string.IsNullOrEmpty(key)) continue;                 var propertyValue = dictionary[key];                 bindings.Add(Expression.Bind(sourceProperty, Expression.Constant(propertyValue)));             }             Expression memberInit = Expression.MemberInit(Expression.New(typeof(T)), bindings);             return Expression.Lambda<Func<T>>(memberInit).Compile().Invoke();         }         public static dynamic ToDynamic<T>(this T obj)         {             IDictionary<string, object> expando = new ExpandoObject();             foreach (var propertyInfo in typeof(T).GetProperties())             {                 var propertyExpression = Expression.Property(Expression.Constant(obj), propertyInfo);                 var currentValue = Expression.Lambda<Func<string>>(propertyExpression).Compile().Invoke();                 expando.Add(propertyInfo.Name.ToLower(), currentValue);             }             return expando as ExpandoObject;         }     }

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• Documentation often ommits to specify which flavour of regular expression to use, so is there a default flavour that we should all be familiar with?

  - by JW01

  Often I come across documentation that says "use a regular expression here" I have to spend quite some time digging around trying to work out which regular expression format they are expecting. As far as I can tell, there are many types of regular expression. But, at my last place of work I was made to feel stupid when I suggested adding some text to our User Documentation to specify the type of regular expression to be used. When someone says "a regular expression" what is the regular expression syntax most people expect and where is it documented? Update: I was prompted to single-out some examples - but no disrespect to these great projects: eregi docs page is not particularly helpful in explaining expected syntax. Nor can I easily work out the syntax expected here if i just land on the page from a search. No explicit mention of the regular expression pattern expected by PatternExpectation() on the SimpleTest page. etc. etc. here is a highly voted SO answer that seems to assume there is only one flavour of regular expressions.

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• Noob Droid Question regarding random number

  - by Pete Herbert Penito

  Brand new to droid programming, but would love to learn as much as possible, so I finally got my emulator working correctly, I even got a hello world button to work, I'm attempting to make this button display a random number, I've googled this and came up with this code: Random generator = new Random(); int n = generator.nextInt(n); I fixed the Random function by including some Random java utility. I'm assuming this code above goes in the .java file of the project, so my button code looks as follows (tested and works): PopUpText.makeText(v.getContext(), "Hello World", PopUpText.LENGTH_LONG).show(); I figured I could replace "Hello World" with n to display the number in the box, however the following error is stopping the compile: The local variable n may not have been initialized Any ideas why this is happening? Any advice would be hugely appreciated.

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• Random number within a range based on a normal distribution

  - by ConfusedAgain

  I'm math challenged today :( I want to generate random numbers with a range (n to m, eg 100 to 150), but instead of purely random I want the results to be based on the normal distribution. By this I mean that in general I want the numbers "clustered" around 125. I've found this random number package that seems to have a lot of what I need: http://beta.codeproject.com/KB/recipes/Random.aspx It supports a variety of random generators (include mersiene twister) and can apply the generator to a distribution. But I'm confused... if I use a normal distribution generator the random numbers are from roughly -6 to +8 (apparently the true range is float.min to float.max). How do a scale that to my required range?

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• Illegal start of expression?

  - by Fraser

  I'm trying to build a simple Android app that increments a number displayed every time a button is pressed, but I can't work out how to fix the "illegal start of expression" error I keep getting. My code: package com.clicker; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class Clicker extends Activity { private int clickerNumber = 0; private TextView clickerText; private Button clickerButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); clickerText = (TextView)findViewById(R.id.clickerText); final Button clickerButton = (Button)findViewById(R.id.clickerButton); clickerButton.setOnClickListener(new View.OnClickListener()); { public void onClick(); { clickerNumber = clickerNumber++; clickerText.setText(Integer.toString(clickerNumber)); } } } } And compiler output: compile: [javac] Compiling 2 source files to /home/fraser/Applications/Android/Code/Clicker/bin/classes [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:24: ')' expected [javac] clickerButton.setOnClickListener(new View.OnClickListener(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: ';' expected [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:29: ';' expected [javac] clickerText.setText(Integer.toString(clickerNumber))); [javac] ^ [javac] 5 errors

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• Recognizing terminals in a CFG production previously not defined as tokens.

  - by kmels

  I'm making a generator of LL(1) parsers, my input is a CoCo/R language specification. I've already got a Scanner generator for that input. Suppose I've got the following specification: COMPILER 1. CHARACTERS digit="0123456789". TOKENS number = digit{digit}. decnumber = digit{digit}"."digit{digit}. PRODUCTIONS Expression = Term{"+"Term|"-"Term}. Term = Factor{"*"Factor|"/"Factor}. Factor = ["-"](Number|"("Expression")"). Number = (number|decnumber). END 1. So, if the parser generated by this grammar receives a word "1+1", it'd be accepted i.e. a parse tree would be found. My question is, the character "+" was never defined in a token, but it appears in the non-terminal "Expression". How should my generated Scanner recognize it? It would not recognize it as a token. Is this a valid input then? Should I add this terminal in TOKENS and then consider an error routine for a Scanner for it to skip it? How does usual language specifications handle this?

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• .NET Regular Expression to find actual words in text

  - by Mehdi Anis

  I am using VB .NET to write a program that will get the words from a suplied text file and count how many times each word appears. I am using this regular expression:- parser As New Regex("\w+") It gives me almost 100% correct words. Except when I have words like "Ms Word App file name is word.exe." or "is this a c# statment If(ab?1,0) ?" In such cases I get [word & exe] AND [If, a, b, 1 and 0] as seperate words. it would be nice (for my purpose) that I received word.exe and (If(ab?1,0) as words. I guess \w+ looks for white space, sentence terminating punctuation mark and other punctuation marks to determine a word. I want a similar regular Expression that will not break a word by a punctuation mark, if the punctuation mark is not the end of the word. I think end-of-word can be defined by a trailing WhiteSpace, Sentence terminating Punctuation (you may think of others). if you can suggest some regular expression 9for VB .NET) that will be great help. Thanks.

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• Moq.Mock<T> - how to setup a method that takes an expression

  - by Paul

  I am Mocking my repository interface and am not sure how to setup a method that takes an expression and returns an object? I am using Moq and NUnit Interface: public interface IReadOnlyRepository : IDisposable { IQueryable<T> All<T>() where T : class; T Single<T>(Expression<Func<T, bool>> expression) where T : class; } Test with IQueryable already setup, but don't know how to setup the T Single: private Moq.Mock<IReadOnlyRepository> _mockRepos; private AdminController _controller; [SetUp] public void SetUp() { var allPages = new List<Page>(); for (var i = 0; i < 10; i++) { allPages.Add(new Page { Id = i, Title = "Page Title " + i, Slug = "Page-Title-" + i, Content = "Page " + i + " on page content." }); } _mockRepos = new Moq.Mock<IReadOnlyRepository>(); _mockRepos.Setup(x => x.All<Page>()).Returns(allPages.AsQueryable()); //Not sure what to do here??? _mockRepos.Setup(x => x.Single<Page>() //---- _controller = new AdminController(_mockRepos.Object); }

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• Regular expression, excluding .. in suffix of email addy

  - by user1754700

  This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

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