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  • Django form and User data

    - by Dean
    I have a model that looks like this: class Client(models.Model): name = models.CharField(max_length=100, primary_key=True) user = models.ForeignKey(User) class Contract(models.Model): title = models.CharField(max_length=100, primary_key=True) start_date = models.DateField() end_date = models.DateField() description = models.TextField() client = models.ForeignKey(Client) user = models.ForeignKey(User) How can i configure a django form so that only clients associated with that user show in the field in the form? My initial thought was this in my forms.py: client = forms.ModelChoiceField(queryset=Client.objects.filter(user__username = User.username)) But it didn't work. So how else would I go about it?

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  • Tricky model inheritance - Django

    - by RadiantHex
    Hi folks, I think this is a bit tricky, at least for me. :) So I have 4 models Person, Singer, Bassist and Ninja. Singer, Bassist and Ninja inherit from Person. The problem is that each Person can be any of its subclasses. e.g. A person can be a Singer and a Ninja. Another Person can be a Bassist and a Ninja. Another one can be all three. How should I organise my models? Help would be much appreciated!

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  • How to load models in the extended MY_Router class in codeigniter

    - by askkirati
    I am not able to load models to the extended My_Router class in codeigniter. Below is my code: class MY_Router extends CI_Router { function MY_Router() { parent::CI_Router(); } function _validate_request($segments) { // Does the requested controller exist in the root folder? if (file_exists(APPPATH.'controllers/'.$segments[0].EXT)) { return $segments; } // Is the controller in a sub-folder? if (is_dir(APPPATH.'controllers/'.$segments[0])) { // Set the directory and remove it from the segment array $this->set_directory($segments[0]); $segments = array_slice($segments, 1); if (count($segments) > 0) { // Does the requested controller exist in the sub-folder? if ( ! file_exists(APPPATH.'controllers/'.$this->fetch_directory().$segments[0].EXT)) { show_404($this->fetch_directory().$segments[0]); } } else { $this->set_class($this->default_controller); $this->set_method('index'); // Does the default controller exist in the sub-folder? if ( ! file_exists(APPPATH.'controllers/'.$this->fetch_directory().$this->default_controller.EXT)) { $this->directory = ''; return array(); } } return $segments; } // Let's check if there are category segments $category_routes = $this->category_routing($segments); if($category_routes !== FALSE) { return $category_routes; } $user_routes = $this->user_routing($segments); if($user_routes != FALSE) { return $user_routes; } show_404($segments[0]); } function category_routing($segments) { $this->load->model('category_model'); if($this->category_model->category_exist($segments[0])) { //if only category if(count($segments)==1) { return array('category', 'category_browse', $segments[0]); } //category pagination if(count($segments)==2 and is_numeric($segments[1])) { return array('category','category_browse', $segments[0], $segments[1]); } //category upcoming if(count($segments)==2 and $segments[1] == 'upcoming') { return array('category','upcoming', $segments[0]); } //category upcoming pagination if(count($segments)==3 and $segments[1] == 'upcoming' and is_numeric($segments[3])) { return array('category','upcoming', $segments[0], $segments[3]); } //category top if(count($segments)==3 and $segments[1] == 'top') { return array('category','top', $segments[0], $segments[2]); } //category top pagination if(count($segments)==4 and $segments[1] == 'top' and is_numeric($segments[3])) { return array('category','top', $segments[0], $segments[3]); } } return FALSE; } function user_routing($segments) { $this->load->model('dx_auth/users', 'user_model'); if($this->user_model->check_username($segments[0])) { //only profile if(count($segments)==1) { return array('user','profile',$segments[0]); } //all friends if(count($segments)==2 and $segment[1]=='allfriends') { return array('user','allfriends',$segments[0]); } //all subscribers if(count($segments)==2 and $segment[1]=='allsubscribers') { return array('user','allsubscribers',$segments[0]); } //all subscription if(count($segments)==2 and $segment[1]=='allsubscriptions') { return array('user','allsubscriptions',$segments[0]); } } return FALSE; } } I have tried loading the models by using get_instance function provided by codeigniter but seems like it doesnot work. All i need is load the models in extended system library.

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  • Modify on-the-fly verbose_name in a model field on django admin

    - by PerroVerd
    Hi I have this sample model working with the admin class Author(models.Model): name = models.CharField(_('Text in here'), max_length=100) with verbose_name set as ugettext_lazy 'Text in here', but sometimes, depending on the site_id i want to present a diferent verbose name, so I modified the init in this way def __init__(self, *args, **kwargs): super(Author, self).__init__(*args, **kwargs) #some logic in here self._meta.get_field('name').verbose_name = _('Other text') It works, displaying the 'Other text' instead the 'Text in here'... except for the very first time the author/add view is used. ¿Is it the right way to do it? ¿How can i fix the first time problem? Thanks in advance

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  • Django - categories & sub-categories

    - by Bluey
    Some advice needed on how I can structure my models for my site. I have seen this post from Django project but still a little lost. Also come across Django-MPTT - but that's no help and possibly overkill. I'm looking to have categories & subcategories that are shown in the URLs like this: mysite.com/Level1/Maths/Calculations/Addition/ mysite.com/Level3/English/ mysite.com/Level2/English/Storytelling/ In my admin interface I'm looking to have drop downs for each level of category or subcategory. Also at each level I will be querying items (another model) like get all items that have the category 'Level1' AND 'Maths'. There could also be a situation where I have five or more subcategories. How is it best to create my models for best performance? It it worth using tagging instead?

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  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

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  • Getting weird python error when I run a simple django script in Eclipse, not happening in console

    - by Rhubarb
    I am running a basic script that sets up the django environment by itself, to enable me to test the ORM features of django without having to implement web pages. The script then imports one of the types defined in my models. This error doesn't happen when I run this script from iPython, only from eclipse. Simply doing this import causes a weird exception like the following: Exception AttributeError: "'NoneType' object has no attribute 'print_exc'" in <bound method Signal._remove_receiver of <django.dispatch.dispatcher.Signal object at 0x026802B0>> ignored My script is as follows: from django.core.management import setup_environ import settings setup_environ(settings) from stats.models import Person for p in Person.objects.all(): print p.Name

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  • How do I prevent a ManyToManyField('self') from linked an object to itself?

    - by dyve
    Consider this model (simplified for this question): class SecretAgentName(models.Model): name = models.CharField(max_length=100) aliases = ManyToManyField('self') I have three names, "James Bond", "007" and "Jason Bourne". "James Bond" and "007" are aliases of each other. This works exactly like I want it to, except for the fact that every instance can also be an alias of itself. This I want to prevent. So, there can be many SecretAgentNames, all can be aliases of each other as long as "James Bond" does not show up as an alias for "James Bond". Can I prevent this in the model definition? If not, can I prevent it anywhere else, preferably so that the Django Admin understands it?

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  • How can I call model methods or properties from Django Admin?

    - by kg
    Is there a natural way to display model methods or properties in the Django admin site? In my case I have base statistics for a character that are part of the model, but other things such as status effects which affect the total calculation for that statistic: class Character(models.Model): base_dexterity = models.IntegerField(default=0) @property def dexterity(stat_name): total = self.base_dexterity total += sum(s.dexterity for s in self.status.all()]) return total It would be nice if I could display the total calculated statistic alongside the field to change the base statistic in the Change Character admin page, but it is not clear to me how to incorporate that information into the page.

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  • How do I use constructor dependency injection to supply Models from a collection to their ViewModels

    - by GraemeF
    I'm using constructor dependency injection in my WPF application and I keep running into the following pattern, so would like to get other people's opinion on it and hear about alternative solutions. The goal is to wire up a hierarchy of ViewModels to a similar hierarchy of Models, so that the responsibility for presenting the information in each model lies with its own ViewModel implementation. (The pattern also crops up under other circumstances but MVVM should make for a good example.) Here's a simplified example. Given that I have a model that has a collection of further models: public interface IPerson { IEnumerable<IAddress> Addresses { get; } } public interface IAddress { } I would like to mirror this hierarchy in the ViewModels so that I can bind a ListBox (or whatever) to a collection in the Person ViewModel: public interface IPersonViewModel { ObservableCollection<IAddressViewModel> Addresses { get; } void Initialize(); } public interface IAddressViewModel { } The child ViewModel needs to present the information from the child Model, so it's injected via the constructor: public class AddressViewModel : IAddressViewModel { private readonly IAddress _address; public AddressViewModel(IAddress address) { _address = address; } } The question is, what is the best way to supply the child Model to the corresponding child ViewModel? The example is trivial, but in a typical real case the ViewModels have more dependencies - each of which has its own dependencies (and so on). I'm using Unity 1.2 (although I think the question is relevant across the other IoC containers), and I am using Caliburn's view strategies to automatically find and wire up the appropriate View to a ViewModel. Here is my current solution: The parent ViewModel needs to create a child ViewModel for each child Model, so it has a factory method added to its constructor which it uses during initialization: public class PersonViewModel : IPersonViewModel { private readonly Func<IAddress, IAddressViewModel> _addressViewModelFactory; private readonly IPerson _person; public PersonViewModel(IPerson person, Func<IAddress, IAddressViewModel> addressViewModelFactory) { _addressViewModelFactory = addressViewModelFactory; _person = person; Addresses = new ObservableCollection<IAddressViewModel>(); } public ObservableCollection<IAddressViewModel> Addresses { get; private set; } public void Initialize() { foreach (IAddress address in _person.Addresses) Addresses.Add(_addressViewModelFactory(address)); } } A factory method that satisfies the Func<IAddress, IAddressViewModel> interface is registered with the main UnityContainer. The factory method uses a child container to register the IAddress dependency that is required by the ViewModel and then resolves the child ViewModel: public class Factory { private readonly IUnityContainer _container; public Factory(IUnityContainer container) { _container = container; } public void RegisterStuff() { _container.RegisterInstance<Func<IAddress, IAddressViewModel>>(CreateAddressViewModel); } private IAddressViewModel CreateAddressViewModel(IAddress model) { IUnityContainer childContainer = _container.CreateChildContainer(); childContainer.RegisterInstance(model); return childContainer.Resolve<IAddressViewModel>(); } } Now, when the PersonViewModel is initialized, it loops through each Address in the Model and calls CreateAddressViewModel() (which was injected via the Func<IAddress, IAddressViewModel> argument). CreateAddressViewModel() creates a temporary child container and registers the IAddress model so that when it resolves the IAddressViewModel from the child container the AddressViewModel gets the correct instance injected via its constructor. This seems to be a good solution to me as the dependencies of the ViewModels are very clear and they are easily testable and unaware of the IoC container. On the other hand, performance is OK but not great as a lot of temporary child containers can be created. Also I end up with a lot of very similar factory methods. Is this the best way to inject the child Models into the child ViewModels with Unity? Is there a better (or faster) way to do it in other IoC containers, e.g. Autofac? How would this problem be tackled with MEF, given that it is not a traditional IoC container but is still used to compose objects?

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  • How to register a model in django-tagging anywhere not in the applications?

    - by culebrón
    Is it possible to register a model in django-tagging not in tagging app, nor in my app? The standard way is to edit apps/myapp/models.py this way: from apps import tagging tagging.register(MyModel) I want to keep both applications without changes, for example, to be able to pull new versions and just replace them. So I tried putting this into project settings.py, in the end, but of course this fails. from apps.myapp.models import MyModel from apps import tagging tagging.register(MyModel) (This fails when importing MyModel.) Any other way?

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  • model (3ds) stats & snapshot in linux

    - by acidzombie24
    I want to write an app that takes in a model filename via cmd line, create a list of stats (poly count, scaling, as much as possible or maybe the stats that i would like) and to load the model with its textures (with anything else) and draw it from multiple position to save the images as pngs. How would i do this? are there utils i can use to extract data from models? how about drawing the models? my server does not have a desktop or video card, would no video HW be a problem?

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  • default model field attribute in Django

    - by Rosarch
    I have a Django model: @staticmethod def getdefault(): print "getdefault called" return cPickle.dumps(set()) _applies_to = models.TextField(db_index=True, default=getdefault) For some reason, getdefault() is never called, even as I construct instances of this model and save them to the database. This seems to contradict the Django documentation: Field.default The default value for the field. This can be a value or a callable object. If callable it will be called every time a new object is created. Am I doing something wrong? Update: Originally, I had this, but then I switched to the above version to debug: _applies_to = models.TextField(db_index=True, default=cPickle.dumps(set())) I'm not sure why that wouldn't work.

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  • Django - how to make ImageField/FileField optional?

    - by ilya
    class Product(models.Model): ... image = models.ImageField(upload_to = generate_filename, blank = True) When I use ImageField (blank=True) and do not select image into admin form, exception occures. In django code you can see this: class FieldFile(File): .... def _require_file(self): if not self: raise ValueError("The '%s' attribute has no file associated with it." % self.field.name) def _get_file(self): self._require_file() ... Django trac has ticket #13327 about this problem, but seems it can't be fixed soon. How to make these field optional?

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  • Rails: keeping DRY with ActiveRecord models that share similar complex attributes

    - by Greg
    This seems like it should have a straightforward answer, but after much time on Google and SO I can't find it. It might be a case of missing the right keywords. In my RoR application I have several models that share a specific kind of string attribute that has special validation and other functionality. The closest similar example I can think of is a string that represents a URL. This leads to a lot of duplication in the models (and even more duplication in the unit tests), but I'm not sure how to make it more DRY. I can think of several possible directions... create a plugin along the lines of the "validates_url_format_of" plugin, but that would only make the validations DRY give this special string its own model, but this seems like a very heavy solution create a ruby class for this special string, but how do I get ActiveRecord to associate this class with the model attribute that is a string in the db Number 3 seems the most reasonable, but I can't figure out how to extend ActiveRecord to handle anything other than the base data types. Any pointers? Finally, if there is a way to do this, where in the folder hierarchy would you put the new class that is not a model? Many thanks.

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  • acts_as_solr isn't updating associated models in Rails

    - by Trey Bean
    I'm using acts_as_solr for searching in a project. Unfortunately, the index doesn't seem to be updated for the associated models when a model is saved. Example: I have three models: class Merchant < ActiveRecord::Base acts_as_solr :fields => [:name, :domain, :description], :include => [:coupons, :tags] ... end class Coupon < ActiveRecord::Base acts_as_solr :fields => [:store_name, :url, :code, :description] ... end class Tag < ActiveRecord::Base acts_as_solr :fields => [:name] ... end I use the following line to perform a search: Merchant.paginate_by_solr(params[:q], :per_page => PER_PAGE, :page => [(params[:page] || 1).to_i, 1].max) For some reason though, after I add a coupon that contains the word 'shoes' in the description, a query for 'shoes' doesn't return the merchant associated with the coupon. The association all work and if I run rake solr:reindex, the search then returns the new coupon. Do I need to update the index for Merchant each time a new coupon is created? Do I have to update the index for the whole class or can I just update the associated merchant? Shouldn't this be done automatically? Thanks for any input.

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  • Rails: Create method available in all views and all models

    - by smotchkkiss
    I'd like to define a method that is available in both my views and my models Say I have a view helper: def foo(s) "hello #{s}" end A view might use the helper like this: <div class="data"><%= foo(@user.name) %></div> However, this <div> will be updated with a repeating ajax call. I'm using a to_json call in a controller returns data like so: render :text => @item.to_json(:only => [...], :methods => [:foo]) This means, that I have to have foo defined in my Item model as well: class Item def foo "hello #{name}" end end It'd be nice if I could have a DRY method that could be shared in both my views and my models. Usage might look like this: Helper def say_hello(s) "hello #{s}" end User.rb model def foo say_hello(name) end Item.rb model def foo say_hello(label) end View <div class="data"><%= item.foo %></div> Controller def observe @items = item.find(...) render :text => @items.to_json(:only=>[...], :methods=>[:foo]) end IF I'M DUMB, please let me know. I don't know the best way to handle this, but I don't want to completely go against best-practices here. If you can think of a better way, I'm eager to learn!

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  • Rails nested models and data separation by scope

    - by jobrahms
    I have Teacher, Student, and Parent models that all belong to User. This is so that a Teacher can create Students and Parents that can or cannot log into the app depending on the teacher's preference. Student and Parent both accept nested attributes for User so a Student and User object can be created in the same form. All four models also belong to Studio so I can do data separation by scope. The current studio is set in application_controller.rb by looking up the current subdomain. In my students controller (all of my controllers, actually) I'm using @studio.students.new instead of Student.new, etc, to scope the new student to the correct studio, and therefore the correct subdomain. However, the nested User does not pick up the studio from its parent - it gets set to nil. I was thinking that I could do something like params[:student][:user_attributes][:studio_id] = @student.studio.id in the controller, but that would require doing attr_accessible :studio_id in User, which would be bad. How can I make sure that the nested User picks up the same scope that the Student model gets when it's created? student.rb class Student < ActiveRecord::Base belongs_to :studio belongs_to :user, :dependent => :destroy attr_accessible :user_attributes accepts_nested_attributes_for :user, :reject_if => :all_blank end students_controller.rb def create @student = @studio.students.new @student.attributes = params[:student] if @student.save redirect_to @student, :notice => "Successfully created student." else render :action => 'new' end end user.rb class User < ActiveRecord::Base belongs_to :studio accepts_nested_attributes_for :studio attr_accessible :email, :password, :password_confirmation, :remember_me, :studio_attributes devise :invitable, :database_authenticatable, :recoverable, :rememberable, :trackable end

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  • Sencha 2 : Sync models with hasMany associations in LocalStorage

    - by Alytrem
    After hours and hours trying to do this, I need your help. I have to models : Project and Task. A project hasMany tasks and a task belong to a project. Everyting works well if you don't use a store to save these models. I want to save both tasks and projects in two stores (TaskStore and ProjectStore). These stores use a LocalStorage proxy. I tried many things, and the most logical is : Ext.define('MyApp.model.Task', { extend: 'Ext.data.Model', config: { fields: [ { name: 'name', type: 'string' }, { dateFormat: 'd/m/Y g:i', name: 'start', type: 'date' }, { dateFormat: 'd/m/Y g:i', name: 'end', type: 'date' }, { name: 'status', type: 'string' } ], belongsTo: { model: 'MyApp.model.Project' } } }); Ext.define('MyApp.model.Project', { extend: 'Ext.data.Model', alias: 'model.Project', config: { hasMany: { associationKey: 'tasks', model: 'MyApp.model.Task', autoLoad: true, foreignKey: 'project_id', name: 'tasks', store: {storeId: "TaskStore"} }, fields: [ { name: 'name', type: 'string' }, { dateFormat: 'd/m/Y', name: 'start', type: 'date' }, { dateFormat: 'd/m/Y', name: 'end', type: 'date' } ] } }); This is my "main" : var project = Ext.create("MyApp.model.Project", {name: "mojo", start: "17/03/2011", end: "17/03/2012", status: "termine"}); var task = Ext.create("MyApp.model.Task", {name: "todo", start: "17/03/2011 10:00", end: "17/03/2012 19:00", status: "termine"}); project.tasks().add(task); Ext.getStore("ProjectStore").add(project); The project is added to the store, but task is not. Why ?!

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  • Using multiple Qt (SQL) Models

    - by radix07
    I have a near real-time application that I am using Qt and an SQLite database to run. I am curious if it is safe to have two separate models access a database at once. I know 2 separate views can access a model just fine, but I can't find any document addressing this. I also realize that SQLite is thread safe for reading, so I don't see a real issue to doing this from the SQLite part of things... Basically I want to use a QSqlTableModel to do the real-time read and write in the background and at the same time use a QSqlQueryModel to give the user desired data. Since I may be doing lots of filtering in the background using the table model I can't use it as the main view as well. I have gotten this to work for the most part, but am not sure if this is the best way to do this. If the models act like multiple SQL queries I don't believe this should be an issue, but I would like to know from someone I bit more knowledgeable about this stuff since this is pretty new to me. Thanks

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  • forms problem in django 1.1

    - by alexarsh
    I have the following form: class ModuleItemForm2(forms.ModelForm): class Meta: model = Module_item fields = ('title', 'media', 'thumb', 'desc', 'default', 'player_option') The model is: class Module_item(models.Model): title = models.CharField(max_length=100) layout = models.CharField(max_length=5, choices=LAYOUTS_CHOICE) media = models.CharField(help_text='Media url', max_length=500, blank=True, null=True) conserv = models.ForeignKey(Conserv, help_text= 'Redirect to Conserv', blank=True, null=True) conserve_section = models.CharField(max_length=100, help_text= 'Section within the redirected Conserv', blank=True, null=True) parent = models.ForeignKey('self', help_text='Upper menu.', blank=True, null=True) module = models.ForeignKey(Module, blank=True, null=True) thumb = models.FileField(upload_to='sms/module_items/thumbs', blank=True, null=True) desc = models.CharField(max_length=500, blank=True, null=True) auto_play = models.IntegerField(help_text='Auto start play (miliseconds)', blank=True, null=True) order = models.IntegerField(help_text='Display order', blank=True, null=True) depth = models.IntegerField(help_text='The layout depth', blank=True, null=True) flow_replace = models.IntegerField(blank=True, null=True) default = models.IntegerField(help_text='The selected sub item (Note: Starting from 0)', blank=True, null=True) player_options = models.CharField(max_length=1000, null=True, blank=True) In my view I build form: module_item_form2 = ModuleItemForm2() print module_item_form2 And I get the following error on the print line: 'NoneType' object has no attribute 'label' It works fine with django 1.0.2. I see the error only in django 1.1. Do you have an idea what am I doing wrong? Regards, Arshavski Alexander.

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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