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  • Zend models and database relathionships

    - by user608341
    Hi people, i'm starting with Zend Framework and I'm a little bit confused with models and relathionships (one-to-many, many-to-many etc). The "Zend Framework Quick Start" says to create a Zend_Db_Table, a Data Mapper and finally our model class Suppose we have a database like this: table A ( id integer primary key, name varchar(50) ); table B ( id integer primary key, a_id integer references A ); then, i'll create: Application_Model_DbTable_A extends Zend_Db_Table_Abstract, Application_Model_AMapper, Application_Model_A, Application_Model_DbTable_B extends Zend_Db_Table_Abstract, Application_Model_BMapper, Application_Model_B, if I understood, i've to store the references informations in Application_Model_DbTable_A: protected $_dependentTables = array('B'); and Application_Model_DbTable_B: protected $_referenceMap = array( 'A' => array( 'columns' => array('a_id'), 'refTableClass' => 'A', 'refColums' => array('id') ) ); and my models class: class Application_Model_A { protected $_id; protected $_name; public function __construct(array $options = null) { if(is_array($options)) { $this->setOptions($options); } } public function __set($name, $value) { $method = 'set' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } $this->$method($value); } public function __get($name) { $method = 'get' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } return $this->$method(); } public function setOptions(array $options) { $methods = get_class_methods($this); foreach ($options as $key => $value) { $method = 'set' . ucfirst($key); if (in_array($method, $methods)) { $this->$method($value); } } return $this; } public function setName($name) { $this->_name = (string) $name; return $this; } public function getName() { return $this->_name; } public function setId($id) { $this->_id = (int) $id; return $this; } public function getId() { return $this->_id; } class Application_Model_B { protected $_id; protected $_a_id; public function __construct(array $options = null) { if(is_array($options)) { $this->setOptions($options); } } public function __set($name, $value) { $method = 'set' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } $this->$method($value); } public function __get($name) { $method = 'get' . $name; if (('mapper' == $name) || !method_exists($this, $method)) { throw new Exception('Invalid property'); } return $this->$method(); } public function setOptions(array $options) { $methods = get_class_methods($this); foreach ($options as $key => $value) { $method = 'set' . ucfirst($key); if (in_array($method, $methods)) { $this->$method($value); } } return $this; } public function setA_id($a_id) { $this->_a_id = (int) $a_id; return $this; } public function getA_id() { return $this->_a_id; } public function setId($id) { $this->_id = (int) $id; return $this; } public function getId() { return $this->_id; } it's that right?

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  • Django ORM leaves opened connections

    - by cleg
    I'm using django ORM with Postgres. After any operations with models (e.g. simple select) in postgres appears new opened connection in IDLE state. I've tried all possible transaction manipulations, I've tried calling connection.close() manually. All useless. And sooner or later, I'm recieveing "FATAL: connection limit exceeded for non-superusers" message. What can I've made wrong?

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  • Filtering manager for django model, customized by user

    - by valya
    Hi there! I have a model, smth like this: class Action(models.Model): def can_be_applied(self, user): #whatever return True and I want to override its default Manager. But I don't know how to pass the current user variable to the manager, so I have to do smth like this: [act for act in Action.objects.all() if act.can_be_applied(current_user)] How do I get rid of it by just overriding the manager? Thanks.

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  • Extended Django base-class with multiple instances

    - by Gijs
    I'm modeling a simple movie database using Django. models.py defines a base model Person. I extend Person into Actor and Director, which works as I imagined. Persons must be unique. When (in the Admin) I create an instance of Actor, and this person is also a Director, it won't save because of the unique = True. Any ideas how to solve this problem? (generic foreign keys?) Thx

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  • In Django Combobox choices, how do you lookup description from short value?

    - by MikeN
    In Django models/forms the choices for a combobox often look like this: food_choices = (("",""), ("1", "Falafel"), ("2", "Hummus"), ("3", "Eggplant Stuff, Babaganoush???"), So the value to be stored in the database will be 1/2/3, but the displayed value on the form will be the long description. When we are working in code outside a form, how can we quickly lookup the long description given the short value stored in the model? So I want to map short values to long values: print foo("1") "Falafel"

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  • Django: name of many to many items in the admin interface

    - by Adam
    I have a many to many field, which I'm displaying in the django admin panel. When I add multiple items, they all come up as "ASGGroup object" in the display selector. Instead, I want them to come up as whatever the ASGGroup.name field is set to. How do I do this? My models looks like: class Thing(Model): read_groups = ManyToManyField('ASGGroup', related_name="thing_read", blank=True) class ASGGroup(Model): name = CharField(max_length=63, null=True) But what I'm seeing the m2m widget display is:

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  • Model associations

    - by Kalyan M
    I have two models Library and Book. In my Library model, I have an array - book_ids. The primary key of Book model is ID. How do I create a has_many :books relation in my library model? This is a legacy database we are using with rails. Thanks.

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  • List of Django model instance foreign keys losing consistency during state changes.

    - by Joshua
    I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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  • Keeping track of changes - Django

    - by RadiantHex
    Hi folks!! I have various models of which I would like to keep track and collect statistical data. The problem is how to store the changes throughout time. I thought of various alternative: Storing a log in a TextField, open it and update it every time the model is saved. Alternatively pickle a list and store it in a TextField. Save logs on hard drive. What are your suggestions?

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  • BI with Django?

    - by Helmut
    Is there a way to develop Bi (Business Intelligence) solutions with Django? Therefore it should be possible to define models with more than one Datasource. Is anybody out there who has experienced BI with Django? How could it work ?

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  • How do I store multiple copies of the same field in Django?

    - by Alistair
    I'm storing OLAC metadata which describes linguistic resources. Many of the elements of the metadata are repeatable -- for example, a resource can have two languages, three authors and four dates associated with it. Is there any way of storing this in one model? It seems like overkill to define a model for each repeatable metadata element -- especially since the models will only have one field: it's value.

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  • Django - 2 fields unique together

    - by webvulture
    Suppose, I want to record say poll choices by users everyday. In this case, i have a table named vote which has columns poll , choice and user-id . So how can i out the constraint (maybe in the django models or wherever possible) that poll and user-id both should not be the same for any entry but like the same user can vote for various different polls once and obviously various users can vote for the same poll. I hope I am clear.

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  • django url from another template than the one associated with the view-function

    - by dana
    Heyy there, i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from another template than the one associated with the def-view that has this url. How should i do that? i have to put two render_to_response to one same function, in order to render the objects from both models? thank you!

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  • Loading from pickled data causes database error with new saves

    - by hibbie
    In order to save time moving data I pickled some models and dumped them to file. I then reloaded them into another database using the same exact model. The save worked fine and the objects kept their old id which is what I wanted. However, when saving new objects I run into nextval errors. Not being very adept with postgres, I'm not sure how to fix this so I can keep old records with their existing ID while being able to continue adding new data. Thanks, Thomas

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  • SQL commands generated in Django by running sqlall

    - by k-g-f
    In my Django app, I just ran $ python manage.py sqlall and I see a lot of SQL statements that look like this, when describing FK relationships: ALTER TABLE `app1_model1` ADD CONSTRAINT model2_id_refs_id_728de91f FOREIGN KEY (`model2_id`) REFERENCES `app1_model2` (`id`); Where does "7218de91f" come from? I would like to know because I'd like to manually write SQL statements to accompany models changes in the app so that my db's can be kept up to date.

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  • How do games make money? What models do they use?

    - by cable729
    I'm trying to research the ways in which games make money. I want to know more about the models they use (free/premium, trial/subscription, free-to-play with micro-transactions, etc.). In addition, I want information on which models work for which games, what models are best for which age groups, etc. I've tried my best to find information, and Google hasn't turned anything up at all. I think I'll stop by my University's library and see if there's anything there. This may seem like a broad question, but I'm looking for links and titles of books, not typed-out answers.

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  • Looking for articles/books on: How do games make money? What models do they use?

    - by cable729
    I'm trying to research the ways in which games make money. I want to know more about the models they use (free/premium, trial/subscription, free-to-play with micro-transactions, etc.). In addition, I want information on which models work for which games, what models are best for which age groups, etc. I've tried my best to find information, and Google hasn't turned anything up at all. I think I'll stop by my University's library and see if there's anything there. This may seem like a broad question, but I'm looking for links and titles of books, not typed-out answers.

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  • How should I implement the repository pattern for complex object models?

    - by Eric Falsken
    Our data model has almost 200 classes that can be separated out into about a dozen functional areas. It would have been nice to use domains, but the separation isn't that clean and we can't change it. We're redesigning our DAL to use Entity Framework and most of the recommendations that I've seen suggest using a Repository pattern. However, none of the samples really deal with complex object models. Some implementations that I've found suggest the use of a repository-per-entity. This seems ridiculous and un-maintainable for large, complex models. Is it really necessary to create a UnitOfWork for each operation, and a Repository for each entity? I could end up with thousands of classes. I know this is unreasonable, but I've found very little guidance implementing Repository, Unit Of Work, and Entity Framework over complex models and realistic business applications.

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  • Jinja2 returns "None" string for Google App Engine models

    - by Brian M. Hunt
    Google App Engine models, likeso: from google.appengine.ext.db import Model class M(): name = db.StringProperty() Then in a Jinja2 template called from a Django view with an in instance of M passed in as m: The name of this M is {{ m.name }}. When m is initialized without name being set, the following is printed: The name of this M is None. The preferable and expected output (and the output when using Django templates) would be/is: The name of this M is . Do you know why this is happening, and how to get the preferred & expected output?

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  • Re-using unit tests for models using STI

    - by TenJack
    I have a number of models that use STI and I would like to use the same unit test to test each model. For example, I have: class RegularList < List class OtherList < List class ListTest < ActiveSupport::TestCase fixtures :lists def test_word_count list = lists(:regular_list) assert_equal(0, list.count) end end How would I go about using the test_word_count test for the OtherList model. The test is much longer so I would rather not have to retype it for each model. Thanks.

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  • Rails transaction: save data in multiple models.

    - by smotchkkiss
    my models class Auction belongs_to :item belongs_to :user, :foreign_key => :current_winner_id has_many :auction_bids end class User has_many :auction_bids end class AuctionBid belongs_to :user end current usage An item is displayed on the page, the user enters an amount and clicks bid. Controller code might look something like this: class MyController def bid @ab = AuctionBid.new(params[:auction_bid]) @ab.user = current_user if @ab.save render :json => {:response => 'YAY!'} else render :json => {:response => 'FAIL!'} end end end desired functionality This works great so far! However, I need to ensure a couple other things happen. @ab.auction.bid_count needs to be incremented by one. @ab.user.bid_count needs to be incremented by one @ab.auction.current_winner_id needs to be set to @ab.user_id That is, the User and the Auction associated with the AuctionBid need values updated as well in order for the AuctionBid#save to return true.

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