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  • Scrollable list items in jQuery

    - by Giles B
    Hi Guys, I have a list of 4 items and the ul has a background image that makes the second item look as though it has an arrow behind it. I want to be able to scroll the items up or down when they are clicked to the second items position so for example when I click the fourth item the whole list scrolls up so the fourth item is then postioned over the top of the background image and all the other items will be sitting in the same order above it. I have tried using jQuery Tools with the circular option selected but it clones the first an last item and i end up with a gap when i get to the bottom and I also cant make each item selectable to scroll the list up or down. Here is the code for the list <div id="priceGuide"> <ul id="priceRegion"> <li><a href="#">North & Midlands</a></li> <li><a href="#">London, north of the river</a></li> <li><a href="#">London, south of the river</a></li> <li><a href="#">South & South East</a></li> </ul><!-- /priceRegion --> </div><!-- /priceGuide --> Any help is most appreciated. Thanks Giles

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  • Can't access a map member from a pointer

    - by fjfnaranjo
    Hi. That's my first question :) I'm storing the configuration of my program in a Group->Key->Value form, like the old INIs. I'm storing the information in a pair of structures. First one, I'm using a std::map with string+ptr for the groups info (the group name in the string key). The second std::map value is a pointer to the sencond structure, a std::list of std::maps, with the finish Key->Value pairs. The Key-Value pairs structure is created dynamically, so the config structure is: std::map< std::string , std::list< std::map<std::string,std::string> >* > lv1; Well, I'm trying to implement two methods to check the existence of data in the internal config. The first one, check the existence of a group in the structure: bool isConfigLv1(std::string); bool ConfigManager::isConfigLv1(std::string s) { return !(lv1.find(s)==lv1.end()); } The second method, is making me crazy... It check the existence for a key inside a group. bool isConfigLv2(std::string,std::string); bool ConfigManager::isConfigLv2(std::string s,std::string d) { if(!isConfigLv1(s)) return false; std::map< std::string , std::list< std::map<std::string,std::string> >* >::iterator it; std::list< std::map<std::string,std::string> >* keyValue; std::list< std::map<std::string,std::string> >::iterator keyValueIt; it = lv1.find(s); keyValue = (*it).second; for ( keyValueIt = keyValue->begin() ; keyValueIt != keyValue->end() ; keyValueIt++ ) if(!((*keyValueIt).second.find(d)==(*keyValueIt).second.end())) return true; return false; } I don't understand what is wrong. The compiler says: ConfigManager.cpp||In member function ‘bool ConfigManager::isConfigLv2(std::string, std::string)’:| ConfigManager.cpp|(line over return true)|error: ‘class std::map<std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::less<std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, std::allocator<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > >’ has no member named ‘second’| But it has to have the second member, because it's a map iterator... Any suggestion about what's happening? Sorry for my English :P, and consider I'm doing it as a exercise, I know there are a lot of cool configuration managers.

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  • garbled items in a horizontal list with css

    - by Pradyut Bhattacharya
    Hi I have made a page in which i m using a list to display the items horizontally Now i can see the result in the page here But when i drag and make the browser window short i get a garbled list as in the scrren-shot here http://pradyut.dyndns.org/WebApplicationSecurity/people_ss.JPG I m using a css in the list as : - #navlist li { padding: 1em; float: left; list-style-type: none; } at the end of the list i m using a clearing div #clear-both { clear: both; } Any help Thanks Pradyut

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  • Combining List<>'s in .NET

    - by Maxim Z.
    I have a few List< objects that hold many objects of one specific type. My goal is to combine these List<'s into one List<. Of course, I could just loop through each List's contents and add them into one final List, but is there a more efficient way?

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  • How to populate List<string> with Datarow values from single columns...

    - by James
    Hi, I'm still learning (baby steps). Messing about with a function and hoping to find a tidier way to deal with my datatables. For the more commonly used tables throughout the life of the program, I'll dump them to datatables and query those instead. What I'm hoping to do is query the datatables for say column x = "this", and convert the values of column "y" directly to a List to return to the caller: private List<string> LookupColumnY(string hex) { List<string> stringlist = new List<string>(); DataRow[] rows = tblDataTable.Select("Columnx = '" + hex + "'", "Columny ASC"); foreach (DataRow row in rows) { stringlist.Add(row["Columny"].ToString()); } return stringlist; } Anyone know a slightly simpler method? I guess this is easy enough, but I'm wondering if I do enough of these if iterating via foreach loop won't be a performance hit. TIA!

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  • List of resources to learn cassandra

    - by Alfred
    Hi all, Lately I have been reading a lot of blog topics about big sites(facebook, twitter, digg, reddit to name a few) using cassandra as their datastore instead of MysqL. I would like to gather a list of resources to learn using cassandra. Hopefully some videos or podcasts explaining how to use cassandra. My list Twissandra - Twissandra is an example project, created to learn and demonstrate how to use Cassandra. Running the project will present a website that has similar functionality to Twitter WTF is a supercolumn - WTF is a SuperColumn? An Intro to the Cassandra Data Model I hope there are resources to watch howto use cassandra. Many thanks, Alfred

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  • Pass elements of a list as arguments to a function in python

    - by Wilduck
    I'm building a simple interpreter in python and I'm having trouble handling differing numbers of arguments to my functions. My current method is to get a list of the commands/arguments as follows. args = str(raw_input('>> ')).split() com = args.pop(0) Then to execute com, I check to see if it is in my dictionary of command- code mappings and if it is I call the function I have stored there. For a command with no arguments, this would look like: commands[com]() However, if a command had multiple arguments, I would want this: commands[com](args[0],args[1]) Is there some trick where I could pass some (or all) of the elements of my arg list to the function that I'm trying to call? Or is there a better way of implementing this without having to use python's cmd class?

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  • Python dictionary key missing

    - by Greg K
    I thought I'd put together a quick script to consolidate the CSS rules I have distributed across multiple CSS files, then I can minify it. I'm new to Python but figured this would be a good exercise to try a new language. My main loop isn't parsing the CSS as I thought it would. I populate a list with selectors parsed from the CSS files to return the CSS rules in order. Later in the script, the list contains an element that is not found in the dictionary. for line in self.file.readlines(): if self.hasSelector(line): selector = self.getSelector(line) if selector not in self.order: self.order.append(selector) elif selector and self.hasProperty(line): # rules.setdefault(selector,[]).append(self.getProperty(line)) property = self.getProperty(line) properties = [] if selector not in rules else rules[selector] if property not in properties: properties.append(property) rules[selector] = properties # print "%s :: %s" % (selector, "".join(rules[selector])) return rules Error encountered: $ css-combine combined.css test1.css test2.css Traceback (most recent call last): File "css-combine", line 108, in <module> c.run(outfile, stylesheets) File "css-combine", line 64, in run [(selector, rules[selector]) for selector in parser.order], KeyError: 'p' Swap the inputs: $ css-combine combined.css test2.css test1.css Traceback (most recent call last): File "css-combine", line 108, in <module> c.run(outfile, stylesheets) File "css-combine", line 64, in run [(selector, rules[selector]) for selector in parser.order], KeyError: '#header_.title' I've done some quirky things in the code like sub spaces for underscores in dictionary key names in case it was an issue - maybe this is a benign precaution? Depending on the order of the inputs, a different key cannot be found in the dictionary. The script: #!/usr/bin/env python import optparse import re class CssParser: def __init__(self): self.file = False self.order = [] # store rules assignment order def parse(self, rules = {}): if self.file == False: raise IOError("No file to parse") selector = False for line in self.file.readlines(): if self.hasSelector(line): selector = self.getSelector(line) if selector not in self.order: self.order.append(selector) elif selector and self.hasProperty(line): # rules.setdefault(selector,[]).append(self.getProperty(line)) property = self.getProperty(line) properties = [] if selector not in rules else rules[selector] if property not in properties: properties.append(property) rules[selector] = properties # print "%s :: %s" % (selector, "".join(rules[selector])) return rules def hasSelector(self, line): return True if re.search("^([#a-z,\.:\s]+){", line) else False def getSelector(self, line): s = re.search("^([#a-z,:\.\s]+){", line).group(1) return "_".join(s.strip().split()) def hasProperty(self, line): return True if re.search("^\s?[a-z-]+:[^;]+;", line) else False def getProperty(self, line): return re.search("([a-z-]+:[^;]+;)", line).group(1) class Consolidator: """Class to consolidate CSS rule attributes""" def run(self, outfile, files): parser = CssParser() rules = {} for file in files: try: parser.file = open(file) rules = parser.parse(rules) except IOError: print "Cannot read file: " + file finally: parser.file.close() self.serialize( [(selector, rules[selector]) for selector in parser.order], outfile ) def serialize(self, rules, outfile): try: f = open(outfile, "w") for rule in rules: f.write( "%s {\n\t%s\n}\n\n" % ( " ".join(rule[0].split("_")), "\n\t".join(rule[1]) ) ) except IOError: print "Cannot write output to: " + outfile finally: f.close() def init(): op = optparse.OptionParser( usage="Usage: %prog [options] <output file> <stylesheet1> " + "<stylesheet2> ... <stylesheetN>", description="Combine CSS rules spread across multiple " + "stylesheets into a single file" ) opts, args = op.parse_args() if len(args) < 3: if len(args) == 1: print "Error: No input files specified.\n" elif len(args) == 2: print "Error: One input file specified, nothing to combine.\n" op.print_help(); exit(-1) return [opts, args] if __name__ == '__main__': opts, args = init() outfile, stylesheets = [args[0], args[1:]] c = Consolidator() c.run(outfile, stylesheets) Test CSS file 1: body { background-color: #e7e7e7; } p { margin: 1em 0em; } File 2: body { font-size: 16px; } #header .title { font-family: Tahoma, Geneva, sans-serif; font-size: 1.9em; } #header .title a, #header .title a:hover { color: #f5f5f5; border-bottom: none; text-shadow: 2px 2px 3px rgba(0, 0, 0, 1); } Thanks in advance.

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  • li element background colors and overflow scrolling

    - by user17753
    I created a simple html source, and applied a small CSS style sheet to it: html { width: 100%; } body { font-family: Calibri, Tahoma, Geneva, sans-serif; padding: 20px; } pre { padding: 0; margin: 0 auto; border: 1px solid #888; font-family: Menlo,Monaco,Consolas,monospace; color: #000; width: 80%; overflow: auto; } pre li { white-space: pre; } ol { margin-top: 0; margin-bottom: 0; /* IE indents via margin-left */ color: #979797; background: #E3E3E3; } .li1 { background: #F5F5F5 } .li2 { background: #eee } I have an ordered list inside a pre-formatted tag. Every other list element is either given the class attribute li1 or li2 (the purpose of which is to alternate the colors). The list elements need the white-space: pre because the white space before and after the text node is important. The pre is to be 80% of the containing element (which ends up being 80% of the window's width). In the event of overflow in the x dimension, I want scrolling. I did all this in the above CSS, and it almost works. The issue I am having is that the background colors of the list elements don't extend with the content. They seem to be capped to the original width of the pre and/or ol element as demonstrated in the following picture where I scroll all the way right as possible: I tinkered with the CSS for a while, but I cannot determine the root cause for this or the fix. Looking for some advice on this one, thanks. Complete source with the issue is as below, NOTE: to would-be editors of the below code the pre element is intended to be on a single line as it's pre-formatted text, and formatting it otherwise would change things. <!DOCTYPE html> <html> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <title>Test Site</title> <style type="text/css"> html { width: 100%; } body { font-family: Calibri, Tahoma, Geneva, sans-serif; padding: 20px; } pre { padding: 0; margin: 0 auto; border: 1px solid #888; font-family: Menlo,Monaco,Consolas,monospace; color: #000; width: 80%; overflow: auto; } pre li { white-space: pre; } ol { margin-top: 0; margin-bottom: 0; /* IE indents via margin-left */ color: #979797; background: #E3E3E3; } .li1 { background: #F5F5F5 } .li2 { background: #eee } </style> </head> <body> <pre class="php"><ol><li class="li1">pre a &#123; text-decoration: none &#125;</li><li class="li2">pre a:hover &#123; background: #C8C8C8 }</li><li class="li1">pre li &#123; white-space: pre; &#125;</li><li class="li2">&nbsp;</li><li class="li1">.php ol &#123; margin-top: 0; margin-bottom: 0; /* IE indents via margin-left */</li><li class="li2"> color: #979797; background: #E3E3E3; }</li><li class="li1">&nbsp;</li><li class="li2">&nbsp;</li><li class="li1">&nbsp;</li><li class="li2">.php .li1 &#123; background: #F5F5F5 }</li><li class="li1">.php .li2 &#123; background: #eee }</li><li class="li2">&nbsp;</li><li class="li1">&nbsp;</li><li class="li2">.php .st0 &#123; color: #C0C } /* string content */</li><li class="li1">.php .st_h &#123; color: #F0C } /* string content single quoted */</li><li class="li2">.php .sy0 &#123; color: #000 } /* semi-colon, operators */ </li><li class="li1">.php .br0 &#123; color: #000 } /* parens */</li><li class="li2">.php .kw2 &#123; color: #00F } /* php tags */</li><li class="li1">.php .sy1 &#123; color: #00F } /* php tags */</li><li class="li2">.php .nu0 &#123; color: #F00 } /* numbers */</li><li class="li1">.php .kw3 &#123; color: #096 } /* core language functions */</li><li class="li2">.php .re0 &#123; color: #09F; font-weight: bold; } /* variables */</li><li class="li1">.php .kw1 &#123; color: #069; font-weight: bold; } /* control statements? */</li><li class="li2">.php .kw4 &#123; color: #069; font-weight: bold; } /* bool? */</li><li class="li1">.php .co1 &#123; color: #FF8400 } /* Forward slash comments */</li></ol></pre> </body> </html>

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  • Python: Indexing list for element in nested list

    - by aquateenfan
    I know what I'm looking for. I want python to tell me which list it's in. Here's some pseudocode: item = "a" nested_list = [["a", "b"], ["c", "d"]] list.index(item) #obviously this doesn't work here I would want python to return 0 (because "a" is an element in the first sub-list in the bigger list). I don't care which sub-element it is. I don't care if there are duplicates, e.g., ["a", "b", "a"] should return the same thing as the above example. Sorry if this is a dumb question. I'm new to programming.

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  • clear div clearing the page to the end in jquery ui tabs...

    - by Pradyut Bhattacharya
    I have set up a list using this css... #navlist li { list-style-type: none; padding: 7px; float: left; } I have shown the page using jquery ui with other div containers... the page here the page named friend.jsp?all=true Im using a clearing div... .clear { clear:left; overflow:hidden; height:1px; } Now when i use a clearing div i get the page like this... the clearing div is clearing up to the end of the page... but on the 1st tab, that is on the freinds tab, when i m not using a clearing div i get the tab pane with no height... Any help with setting up a css for ui tabs or with setting up the list without float:left thanks Pradyut

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  • How to drill down with jQuery?

    - by Timothy Reed
    I'm new to jQuery so sorry if this sounds stupid but I'm having truble drilling down to other elemnts. Paticularly I want to fade in the .menu li a:hover class with jquery. .menu { padding:0; margin:0; list-style:none; } .menu li { float:left; margin-left:1px; } .menu li a { display:block; height:44px; line-height:40px; padding:0 5px; float:right; color:#fff; text-decoration:none; font-family:"Palatino Linotype", "Book Antiqua", Palatino, serif; font-size:12px; font-weight:bold; } .menu li a b { text-transform:uppercase; } .menu li a:hover { color:#E4FFC5; background: url(../images/arrow.png) no-repeat center bottom; } .current { background: url(../images/arrow.png) no-repeat center bottom; font-size:16px; font-weight:bold; } .spacer p { display:block; height:44px; line-height:40px; padding:0 5px; float:right; color:#fff; text-decoration:none; font-family:"Palatino Linotype", "Book Antiqua", Palatino, serif; font-size:12px; font-weight:bold; } <ul class="menu"> <li class="current"><a href="index.html">Home</a></li> <li class="spacer"> <p>|</p> </li> <li><a href="#">Mission &amp; Values </a></li> <li class="spacer"> <p>|</p> </li> <li><a href="#">Caregivers</a></li> <li class="spacer"> <p>|</p> </li> <li><a href="#">Special Programs </a></li> <li class="spacer"> <p>|</p> </li> <li><a href="#">Enployment</a></li> <li class="spacer"> <p>|</p> </li> <li><a href="#">Contact</a></li> </ul> <script type="text/javascript"> $(function() { $('a').mouseover(function() { $('.logo').animate ({opacity:'0.6'}, 'normal'); }); $('a').mouseout (function() { $('.logo').animate ({opacity:'1'}, 'normal'); $('.menu li a:hover').fadeIn ('slow'); }); </script>

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  • How to switch position of two items in a Python list?

    - by mikl
    I haven’t been able to find a good solution for this problem on the net (probably because switch, position, list and Python are all such overloaded words). It’s rather simple – I have this list: ['title', 'email', 'password2', 'password1', 'first_name', 'last_name', 'next', 'newsletter'] I’d like to switch position of 'password2' and 'password1' – not knowing their exact position, only that they’re right next to one another and password2 is first. I’ve accomplished this with some rather long-winded list-subscripting, but I wondered if someone could come up with something a bit more elegant?

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  • Linked List Sorting with Strings In C

    - by user308583
    I have a struct, with a Name and a single Node called nextName It's a Singly Linked list, and my task is to create the list, based on alphabetical order of the strings. So iff i enter Joe Zolt and Arthur i should get my list structured as Joe Than Joe Zolt Than Arthur Joe Zolt I'm having trouble implementing the correct Algorithm, which would put the pointers in the right order. This is What I have as of Now. Temp would be the name the user just entered and is trying to put into the list, namebox is just a copy of my root, being the whole list if(temp != NULL) { struct node* namebox = root; while (namebox!=NULL && (strcmp((namebox)->name,temp->name) <= 0)) { namebox = namebox->nextName; printf("here"); } temp->nextName = namebox; namebox = temp; root = namebox; This Works right now, if i enter names like CCC BBB than AAA I Get Back AAA BBB CCC when i print But if i put AAA BBB CCC , When i print i only get CCC, it cuts the previous off.

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  • Easy way to check if item is in list?

    - by befall
    Hey guys, I'm writing a search algorithm in C++, and one of the things I need to do is have a few if statements that check cells above, below, left of, and right of. Each time a cell is found to be open and added to the stack, I want it added to a list of cells already checked. I want to be able to say in the if loop if(thisCell is not in checkedCells). Any simple ideas? Thanks!

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  • click li, go to next li

    - by steve
    Can't find a simple solution to this, I know it's easy and I've tried a few things but I can't quite get it to work. I'm currently working with a sidescrolling site and I want every time you click an image (contained in an li) it scrolls to the next li. I have jQuery plugin localscroll so it smoothly goes from one to the next, and that's working. I need to now write a code that triggers jQuery to utilize the localscroll function and go to the next li. Right now I have this, but I know it's not right: $(document).ready(function () { var gallery = $('.wrapper ul li') $(gallery).click(function() { $.localscroll().next(li); }); });

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  • Creating a list in Python- something sneaky going on?

    - by GlenCrawford
    Apologies if this doesn't make any sense, I'm very new to Python! From testing in an interpreter, I can see that list() and [] both produce an empty list: >>> list() [] >>> [] [] From what I've learned so far, the only way to create an object is to call its constructor (__init__), but I don't see this happening when I just type []. So by executing [], is Python then mapping that to a call to list()?

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  • not able to get a processed list in jquery variable

    - by Pradyut Bhattacharya
    I have html list <ol id="newlist"> <li>Test <ol> <li>1</li> <li>2</li> <li>3</li> </ol> </li> <li>Another test <ol> <li>1</li> </ol> </li> <li>Cool Test <ol> <li>1</li> <li>2</li> </ol> </li> </ol> Now i have hidden the list using the css... #newlist li { display:none; list-style: none; } I want to display the list and the only the descendants which have greater than 1 descendants... the output should be... Test 1 2 3 Another test Cool Test 1 2 I have used jquery and able to get the output... the code i used... $("ol#newlist > li").show(); for (var i = 0; i < $("ol#newlist > li").length; i++) { if ($("ol#newlist > li:eq(" + i + ") ol > li").length > 1) $("ol#newlist > li:eq(" + i + ") ol > li").show(); } the sample page here Now i want all the list in a single variable like i can get the lis in a variable... var $li = $("ol#newlist > li"); but the code $li.add($("ol#newlist > li:eq(" + i + ") ol > li")); is not working... the sample page here Please help... Thanks Pradyut India

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  • jQuery How do I move an element inside of another element

    - by TripWired
    Hi I'm using grails navigation plugin and when it generates menus it put the sub navigation underneath the main menu, but i'm making my menu a vertical menu so i don't want the sub menu under the whole menu i want it under the active element. Example: this is how it generate the menu and sub menu <ul class="mainmenu"> <li>item1</li> <li>item2</li> <li>item3</li> </ul> <ul class="submenu"> <li>item1</li> <li>item2</li> <li>item3</li> </ul> What i want is: <ul class="mainmenu"> <li>item1 <ul class="submenu"> <li>item1</li> <li>item2</li> <li>item3</li> </ul> </li> <li>item2</li> <li>item3</li> </ul> Since i don't know of a way to make grails nav plugin do this i guess i'll have to make jquery do it after it's generated. Any ideas?

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  • unable to apply jquery filter

    - by Pradyut Bhattacharya
    Hi I m un-animating a list using this code... function unanimate_li(){ $li.filter(':last') .animate({ height: 'hide', opacity: 'hide' }, 1000, function(){ unanimate_li(); }); $li = $li.not(':last'); } I have set up the li using this code $li = $("ol#update > li"); $li = $li.filter(':gt(4)').filter(':lt('+ size + ')'); Now when i try to do this i cannot get the 5th li(4th on zero based) to remove It removes the sixth li The example here And when the second time i do the update it goes on to infinite loop I cannot understand why

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