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  • Setting up RADIUS + LDAP for WPA2 on Ubuntu

    - by Morten Siebuhr
    I'm setting up a wireless network for ~150 users. In short, I'm looking for a guide to set RADIUS server to authenticate WPA2 against a LDAP. On Ubuntu. I got a working LDAP, but as it is not in production use, it can very easily be adapted to whatever changes this project may require. I've been looking at FreeRADIUS, but any RADIUS server will do. We got a separate physical network just for WiFi, so not too many worries about security on that front. Our AP's are HP's low end enterprise stuff - they seem to support whatever you can think of. All Ubuntu Server, baby! And the bad news: I now somebody less knowledgeable than me will eventually take over administration, so the setup has to be as "trivial" as possible. So far, our setup is based only on software from the Ubuntu repositories, with exception of our LDAP administration web application and a few small special scripts. So no "fetch package X, untar, ./configure"-things if avoidable. UPDATE 2009-08-18: While I found several useful resources, there is one serious obstacle: Ignoring EAP-Type/tls because we do not have OpenSSL support. Ignoring EAP-Type/ttls because we do not have OpenSSL support. Ignoring EAP-Type/peap because we do not have OpenSSL support. Basically the Ubuntu version of FreeRADIUS does not support SSL (bug 183840), which makes all the secure EAP-types useless. Bummer. But some useful documentation for anybody interested: http://vuksan.com/linux/dot1x/802-1x-LDAP.html http://tldp.org/HOWTO/html_single/8021X-HOWTO/#confradius UPDATE 2009-08-19: I ended up compiling my own FreeRADIUS package yesterday evening - there's a really good recipe at http://www.linuxinsight.com/building-debian-freeradius-package-with-eap-tls-ttls-peap-support.html (See the comments to the post for updated instructions). I got a certificate from http://CACert.org (you should probably get a "real" cert if possible) Then I followed the instructions at http://vuksan.com/linux/dot1x/802-1x-LDAP.html. This links to http://tldp.org/HOWTO/html_single/8021X-HOWTO/, which is a very worthwhile read if you want to know how WiFi security works. UPDATE 2009-08-27: After following the above guide, I've managed to get FreeRADIUS to talk to LDAP: I've created a test user in LDAP, with the password mr2Yx36M - this gives an LDAP entry roughly of: uid: testuser sambaLMPassword: CF3D6F8A92967E0FE72C57EF50F76A05 sambaNTPassword: DA44187ECA97B7C14A22F29F52BEBD90 userPassword: {SSHA}Z0SwaKO5tuGxgxtceRDjiDGFy6bRL6ja When using radtest, I can connect fine: > radtest testuser "mr2Yx36N" sbhr.dk 0 radius-private-password Sending Access-Request of id 215 to 130.225.235.6 port 1812 User-Name = "msiebuhr" User-Password = "mr2Yx36N" NAS-IP-Address = 127.0.1.1 NAS-Port = 0 rad_recv: Access-Accept packet from host 130.225.235.6 port 1812, id=215, length=20 > But when I try through the AP, it doesn't fly - while it does confirm that it figures out the NT and LM passwords: ... rlm_ldap: sambaNTPassword -> NT-Password == 0x4441343431383745434139374237433134413232463239463532424542443930 rlm_ldap: sambaLMPassword -> LM-Password == 0x4346334436463841393239363745304645373243353745463530463736413035 [ldap] looking for reply items in directory... WARNING: No "known good" password was found in LDAP. Are you sure that the user is configured correctly? [ldap] user testuser authorized to use remote access rlm_ldap: ldap_release_conn: Release Id: 0 ++[ldap] returns ok ++[expiration] returns noop ++[logintime] returns noop [pap] Normalizing NT-Password from hex encoding [pap] Normalizing LM-Password from hex encoding ... It is clear that the NT and LM passwords differ from the above, yet the message [ldap] user testuser authorized to use remote access - and the user is later rejected...

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  • Use spring tag in XSLT

    - by X-Pippes
    I have a XSL/XML parser to produce jsp/html code. Using MVC model I need to accees spring library in order to perform i18n translation. Thus, given the xml <a> ... <country>EN</country> ... </a> and using <spring:message code="table_country_code.EN"/> tag, choose based on the browser language, the transalation into England, Inglaterra, etc... However, the XSL do not support <spring:message> tag. The idea is to have a XSLT with something like this <spring:message code="table_country_code.><xsl:value-of select="country"/>"/>` I also tried to create the spring tag in Java when I make a parse to create the XML but I sill have the same error. ERROR [STDERR] (http-0.0.0.0-8080-1) file:///C:/Software/Jboss/jboss-soa-p-5/jboss-as/bin/jstl:; Line #5; Column #58; The prefix "spring" for element "spring:message" is not bound. How can I resolve?

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  • How to create TestContext for Spring Test?

    - by HDave
    Newcomer to Spring here, so pardon me if this is a stupid question. I have a relatively small Java library that implements a few dozen beans (no database or GUI). I have created a Spring Bean configuration file that other Java projects use to inject my beans into their stuff. I am now for the first time trying to use Spring Test to inject some of these beans into my junit test classes (rather than simply instantiating them). I am doing this partly to learn Spring Test and partly to force the tests to use the same bean configuration file I provide for others. In the Spring documentation is says I need to create an application context using the "TestContext" class that comes with Spring. I believe this should be done in a spring XML file that I reference via the @ContextConfiguration annotation on my test class. @ContextConfiguration({"/test-applicationContext.xml"}) However, there is no hint as to what to put in the file! When I go to run my tests from within Eclipse it errors out saying "failed to load Application Context"....of course.

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  • Spring validation has error in XML document from ServletContext resource

    - by user1441404
    I applied spring validation in my registration page .but the follwing error are shown in my server log of my app engine server. javax.servlet.UnavailableException: org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 22 in XML document from ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 22; columnNumber: 30; cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'property'. My code is given below : <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd > <beans:bean name="/register" class="com.my.registration.NewUserRegistration"> <property name="validator"> <bean class="com.my.validation.UserValidator" /> </property> <beans:property name="formView" value="newuser"></beans:property> <beans:property name="successView" value="home"></beans:property> </beans:bean> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> </beans:beans>

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  • What does sub error code 568 mean for Ldap Error 49 with Active Directory

    - by Dean Povey
    I am writing some Java code that authenticates to Active Directory using SASL GSSAPI. Mostly this code is working fine but for one user I am getting the response: javax.naming.AuthenticationException: [LDAP: error code 49 - 8 0090304: LdapErr: DSID-0C0904D1, comment: AcceptSecurityContext error, data 568, v1772 ] I know that 49 means this is an authentication failure, and that the relevant sub code is 568, but I am only aware of the following meanings for that data: 525 - user not found 52e - invalid credentials 530 - not permitted to logon at this time 532 - password expired 533 - account disabled 701 - account expired 773 - user must reset password So far I am unable to find an authorative source of these error codes from Microsoft (this list is pieced together from forum posts) and I can't find anything for that 568 error. Does anyone know what it means?

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  • ldap vbscript : msExchOmaAdminWirelessEnable is randomly missing on different accounts

    - by phill
    In my script: Function getDescript (strname, uname) Set MyUser = GetObject ("LDAP://cn=" & uname & ",ou=" & strname & ",DC=tms-1,DC=net") getDescript = myUser.Get("msExchOmaAdminWirelessEnable") End Function uname = "Bob Gardner" strname = "bgConsultants" WScript.Echo "wireless enable: " & getDescript(strname, uname) I have noticed some users in the same OU sometimes do and sometimes don't have the msExchOmaAdminWirelessEnable attribute when I check it in sysinternals' ACtive Directory Explorer. All users are in the same OU and the exchange 2003 server has sp2 installed. Anyone might know why this is? Update: I figured out that if I disable and re-enable the Outlook Mobile Access setting for each user, the msExchOmaAdminWirelessEnable attribute shows up again for those users missing that attribute...weird..

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  • Access Git Repository using Eclipse and Netbeans Plugins with LDAP Users

    - by ukrania
    Hello everyone! I've configure a git server. I need to use ssh because I've defined permissions using users of my domain, using LDAP. Only users with permissions could read a project. So, the links to access my repositories are like that: ssh://[email protected]@hostname/var/git/repo.git When I clone, commit or push a project using linux git commands or using tortoisegit on windows, there is no problem, everything works as expected. However, I've tried to clone a project using plugins from Eclipse (EGit) and Netbeans (NBGit), with no success. Seems that they can't recognize the host. I've accessed using a user from the server (not from the domain) and it cloned the project perfectly. Seems that the plugins assume that the host is everything after the first @. Do you know how I can solve this problem? There are any other Git plugins for those IDEs? Thanks for your answers. Best Regards, ukrania

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  • How to improve my LDAP schema?

    - by asmaier
    Hello, I have a OpenLDAP Database and it holds some project objects that look like dn: cn=Proj1,ou=Project,ou=ua,dc=org cn: Proj1 objectClass: top objectClass: posixGroup member: 001ag member: 002ag System: ABEL System: PCx Budget: ABEL:1000000:0.3 Budget: PCx:300000:0.3 One can see that the Budget attribute is a ":"-separated string, where the first part holds the name of the system the budget is for, the second part holds some budget (which may change every month) and the last entry is a conversion factor for the budget of that system. Seeing this, I thought this is bad database design, since attribute values should always be atomic. But how can I improve that in LDAP, so that I can do a direct ldapsearch or a direct ldapmodify of the budget of System "ABEL" instead of writing a script, that will have to parse and split the ":"-separated string?

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  • How to use SQLErrorCodeSQLExceptionTranslator and DAO class with @Repository in Spring?

    - by GuidoMB
    I'm using Spring 3.0.2 and I have a class called MovieDAO that uses JDBC to handle the db. I have set the @Repository annotations and I want to convert the SQLException to the Spring's DataAccessException I have the following example: @Repository public class JDBCCommentDAO implements CommentDAO { static JDBCCommentDAO instance; ConnectionManager connectionManager; private JDBCCommentDAO() { connectionManager = new ConnectionManager("org.postgresql.Driver", "postgres", "postgres"); } static public synchronized JDBCCommentDAO getInstance() { if (instance == null) instance = new JDBCCommentDAO(); return instance; } @Override public Collection<Comment> getComments(User user) throws DAOException { Collection<Comment> comments = new ArrayList<Comment>(); try { String query = "SELECT * FROM Comments WHERE Comments.userId = ?"; Connection conn = connectionManager.getConnection(); PreparedStatement stmt = conn.prepareStatement(query); stmt = conn.prepareStatement(query); stmt.setInt(1, user.getId()); ResultSet result = stmt.executeQuery(); while (result.next()) { Movie movie = JDBCMovieDAO.getInstance().getLightMovie(result.getInt("movie")); comments.add(new Comment(result.getString("text"), result.getInt("score"), user, result.getDate("date"), movie)); } connectionManager.closeConnection(conn); } catch (SQLException e) { e.printStackTrace(); //CONVERT TO DATAACCESSEXCEPTION } return comments; } } I Don't know how to get the Translator and I don't want to extends any Spring class, because that is why I'm using the @Repository annotation

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  • Binary search of unaccesible data field in ldap from python

    - by EricR
    I'm interested in reproducing a particular python script. I have a friend who was accessing an ldap database, without authentication. There was a particular field of interest, we'll call it nin (an integer) for reference, and this field wasn't accessible without proper authentication. However, my friend managed to access this field through some sort of binary search (rather than just looping through integers) on the data; he would check the first digit, check if it was greater or less than the starting value, he would augment that until it returned a true value indicating existence, adding digits and continuing checking until he found the exact value of the integer nin. Any ideas on how he went about this? I've access to a similarly set up database.

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  • How to use LDAP for authentication in Tomcat with Custom Authorization

    - by djc4
    Hello, I'm using JNDIRealm with Tomcat for authentication, which at the moment works fine. However, we do not store any roles in the LDAP, so all authenticated users are not returning any roles. This sends user's to an HTTP 401 failed authorization page. I'd like to assign an "Admin" role to any and all user's who authenticate successfully. Here is my fragment from my web.xml file. SecurityConstraint Resource Resource *.jsp GET POST Admin FORM login.jsp loginError.jsp Admin Should I be using a JAASRealm with custom LoginModule? After the realm calls the authenticate() method and returns success, should I override another method to explicitly set the RolePrincipal to "Admin" so that authorization succeeds? Please help! Thanks, Andy

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  • spring classloader isolation problem on jboss

    - by mkosm
    Hi, i have two ears deployed on jboss with proper classloaders isolation settings. When seam bean call spring beans which make some queries on database everything works fine, but when spring quartz job bean is invoked and execute tries to execute database queries then there is a problem because spring tries too use hibernate jar from other ear and exception is thrown! It is clearily spring classloader isolation problem. Did anyone meet such a problem? How to ensure isolation?

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  • Where to put default-servlet-handler in Spring MVC configuration

    - by gigadot
    In my web.xml, the default servlet mapping, i.e. /, is mapped to Spring dispatcher. In my Spring dispatcher configuration, I have DefaultAnnotationHandlerMapping, ControllerClassNameHandlerMapping and AnnotationMethodHandlerAdapter which allows me to map url to controllers either by its class name or its @Requestmapping annotation. However, there are some static resources under the web root which I also want spring dispatcher to serve using default servlet. According to Spring documentation, this can be done using <mvc:default-servlet-handler/> tag. In the configuration below, there are 4 candidate locations that I marked which are possible to insert this tag. Inserting the tag in different location causes the dispatcher to behave differently as following : Case 1 : If I insert it at location 1, the dispatcher will no longer be able to handle mapping by the @RequestMapping and controller class name but it will be serving the static content normally. Cas 2, 3 : It will be able to handle mapping by the @RequestMapping and controller class name as well as serving the static content if other mapping cannot be done successfully. Case 4 : It will not be able to serve the static contents. Therefore, Case 2 and 3 are desirable .According to Spring documentation, this tag configures a handler which precedence order is given to lowest so why the position matters? and Which is the best position to put this tag? <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <context:annotation-config/> <context:component-scan base-package="webapp.controller"/> <!-- Location 1 --> <!-- Enable annotation-based controllers using @Controller annotations --> <bean id="annotationUrlMapping" class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <!-- Location 2 --> <bean id="controllerClassNameHandlerMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/> <!-- Location 3 --> <bean id="annotationMethodHandlerAdapter" class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <!-- Location 4 --> <mvc:default-servlet-handler/> <!-- All views are JSPs loaded from /WEB-INF/jsp --> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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  • How can I get access to spring container?

    - by Antony
    I have a spring container running, and I have class with which I want to have access to the bean created inside spring container. The class I have is not registered with the spring container. One thing I can do is that I can use MethodInvoker to call a static method, so I will have access to static field (this would be a bean from spring container) in my class always. Do we have class like WebapplicationContextUtils for a application that is not web?

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  • Spring 3 simple extentionless url mappings with annotation-based mapping - impossible?

    - by caerphilly
    Hi, I'm using Spring 3, and trying to set up a simple web-app using annotations to define controller mappings. This seems to be incredibly difficult without peppering all the urls with *.form or *.do Because part of the site needs to be password protected, these urls are all under /secure. There is a <security-constraint> in the web.xml protecting everything under that root. I want to map all the Spring controllers to /secure/app/. Example URLs would be: /secure/app/landingpage /secure/app/edit/customer/{id} each of which I would handle with an appropriate jsp/xml/whatever. So, in web.xml I have this: <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/secure/app/*</url-pattern> </servlet-mapping> And in despatcher-servlet.xml I have this: <context:component-scan base-package="controller" /> In the Controller package I have a controller class: package controller; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; import org.springframework.web.servlet.ModelAndView; import javax.servlet.http.HttpServletRequest; @Controller @RequestMapping("/secure/app/main") public class HomePageController { public HomePageController() { } @RequestMapping(method = RequestMethod.GET) public ModelAndView getPage(HttpServletRequest request) { ModelAndView mav = new ModelAndView(); mav.setViewName("main"); return mav; } } Under /WEB-INF/jsp I have a "main.jsp", and a suitable view resolver set up to point to this. I had things working when mapping the despatcher using *.form, but can't get anything working using the above code. When Spring starts up it appears to map everything correctly: 13:22:36,762 INFO main annotation.DefaultAnnotationHandlerMapping:399 - Mapped URL path [/secure/app/main] onto handler [controller.HomePageController@2a8ab08f] I also noticed this line, which looked suspicious: 13:25:49,578 DEBUG main servlet.DispatcherServlet:443 - No HandlerMappings found in servlet 'dispatcher': using default And at run time any attempt to view /secure/app/main just returns a 404 error in Tomcat, with this log output: 13:25:53,382 DEBUG http-8080-1 servlet.DispatcherServlet:842 - DispatcherServlet with name 'dispatcher' determining Last-Modified value for [/secure/app/main] 13:25:53,383 DEBUG http-8080-1 servlet.DispatcherServlet:850 - No handler found in getLastModified 13:25:53,390 DEBUG http-8080-1 servlet.DispatcherServlet:690 - DispatcherServlet with name 'dispatcher' processing GET request for [/secure/app/main] 13:25:53,393 WARN http-8080-1 servlet.PageNotFound:962 - No mapping found for HTTP request with URI [/secure/app/main] in DispatcherServlet with name 'dispatcher' 13:25:53,393 DEBUG http-8080-1 servlet.DispatcherServlet:677 - Successfully completed request So... Spring maps a URL, and then "forgets" about that mapping a second later? What is going on? Thanks.

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  • What does the Spring framework do? Should I use it? Why or why not?

    - by sangfroid
    So, I'm starting a brand-new project in Java, and am considering using Spring. Why am I considering Spring? Because lots of people tell me I should use Spring! Seriously, any time I've tried to get people to explain what exactly Spring is or what it does, they can never give me a straight answer. I've checked the intros on the SpringSource site, and they're either really complicated or really tutorial-focused, and none of them give me a good idea of why I should be using it, or how it will make my life easier. Sometimes people throw around the term "dependency injection", which just confuses me even more, because I think I have a different understanding of what that term means. Anyway, here's a little about my background and my app : Been developing in Java for a while, doing back-end web development. Yes, I do a ton of unit testing. To facilitate this, I typically make (at least) two versions of a method : one that uses instance variables, and one that only uses variables that are passed in to the method. The one that uses instance variables calls the other one, supplying the instance variables. When it comes time to unit test, I use Mockito to mock up the objects and then make calls to the method that doesn't use instance variables. This is what I've always understood "dependency injection" to be. My app is pretty simple, from a CS perspective. Small project, 1-2 developers to start with. Mostly CRUD-type operations with a a bunch of search thrown in. Basically a bunch of RESTful web services, plus a web front-end and then eventually some mobile clients. I'm thinking of doing the front-end in straight HTML/CSS/JS/JQuery, so no real plans to use JSP. Using Hibernate as an ORM, and Jersey to implement the webservices. I've already started coding, and am really eager to get a demo out there that I can shop around and see if anyone wants to invest. So obviously time is of the essence. I understand Spring has quite the learning curve, plus it looks like it necessitates a whole bunch of XML configuration, which I typically try to avoid like the plague. But if it can make my life easier and (especially) if make it can make development and testing faster, I'm willing to bite the bullet and learn Spring. So please. Educate me. Should I use Spring? Why or why not?

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  • View Body not showing in Spring 3.2

    - by Dennis Röttger
    I'm currently trying to get into Java Web Development in general in Spring more specifically. I've set up my project as follows - hello.jsp: <html> <head> <title>Spring 3.0 MVC Series: Hello World - ViralPatel.net</title> </head> <body> <p>ABC ${message}</p> </body> </html> HelloWorldController.java: package controllers; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; System.out.println(message); return new ModelAndView("hello", "message", message); } } web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> </web-app> spring-servlet.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:component-scan base-package="controllers" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> </beans> I can start up the Server just fine and navigate to hello.html, which is resolved by the servlet to give me hello.jsp, the title of the .jsp shows (Spring 3.0 MVC Series: etc. etc.), alas, the body does not. Not the JSTL-Variable and not the "ABC" either. I've implemented jstl-1.2 in my lib-folder.

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  • ldap login form works, but need to add active-directory group access

    - by Brad
    I created a form that asks you to log in, then verifies the user/pass against the ldap server/active-directory, if successful, it creates a session, which will be checked on every page. Now I want to check the session, which is the username of the person who is logged in, and do a search for them using ldap_search, so I can check what group they belong to and pass that group thru a function to verify that they can view that page. Each page will accessible to a certain group or groups of users, which those groups are defined within Active Directory. I am unsure on how I can do that using ldap_search, or maybe that is just one piece of the puzzle I am trying to solve. Any help is appreciated - thank you! In the example code below, it is seeing if the user belongs to the student active-directory group (I do not know if this code works, but it should give you an idea of what I want to accomplish). $filter = "CN=StudentCN=Users,dc=domain,dc=control"; $result = ldap_search($ldapconn,$filter,$valid_session_username); if($result == TRUE) { print $valid_session_username.' does have access to this page'; } else { print $valid_session_username.' does NOT have access to this page'; }

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  • How to Configure OpenLDAP on Ubuntu 10.04 Server

    - by user3215
    I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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  • How to determine the Kerberos realm from an LDAP directory?

    - by tstm
    I have two Kerberos realms I can authenticate against. One of them I can control, and the other one is external from my point of view. I also have an internal user database in LDAP. Let's say the realms are INTERNAL.COM and EXTERNAL.COM. In ldap I have user entries like this: 1054 uid=testuser,ou=People,dc=tml,dc=hut,dc=fi shadowFlag: 0 shadowMin: -1 loginShell: /bin/bash shadowInactive: -1 displayName: User Test objectClass: top objectClass: account objectClass: posixAccount objectClass: shadowAccount objectClass: person objectClass: organizationalPerson objectClass: inetOrgPerson uidNumber: 1059 shadowWarning: 14 uid: testuser shadowMax: 99999 gidNumber: 1024 gecos: User Test sn: Test homeDirectory: /home/testuser mail: [email protected] givenName: User shadowLastChange: 15504 shadowExpire: 15522 cn: User.Test userPassword: {SASL}[email protected] What I would like to do, somehow, is to specify per-user basis to which authentication server / realm the user is authenticated against. Configuring kerberos to handle multiple realms is easy. But how to I configure other instances, like PAM, to handle the fact that some users are from INTERNAL.COM and some from EXTERNAL.COM? There needs to be an LDAP lookup of some kind where the realm and the authentication name is fetched from, and then the actual authentication itself. Is there a standardized way to add this information to LDAP, or look it up? Are there some other workarounds for a multi-realm user base? I might be ok with a single realm solution, too, as long as I can specify the user name - realm -combination for the user separately.

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  • Can My Personal GMail Query A Remote LDAP Server?

    - by Maarx
    I have a personal GMail account, from which I frequently send e-mail to a great many various users of a specific business. The corporation has been kind enough to provide me with the credentials to access their LDAP server, with which I would like my GMail web client to be able to auto-complete partial addresses or names for which that LDAP server has an entry. Is there any way I can get a personal GMail account (or it's corresponding entire Google account) account to incorporate an LDAP server into it's Contacts? If I cannot get it to query dynamically and on-demand, is there an idiot-proof way (assuming the client permits, which they may not) to query the LDAP server for it's entire database, save it, and bulk import it to GMail? Perhaps, even, something I could set to repeat periodically (weekly, perhaps), without human interaction? If I did the latter, I assume it would be trivial to import all of these contacts under a single category that could be easily manipulated from within the GMail web-based client. I have been a staunch user and supporter of the GMail web-based client since it's instantiation, but this one is kind of a deal-breaker for me. If it's impossible, what do you suggest I do?

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  • Spring Security: how to implement Brute Force Detection (BFD)?

    - by Kdeveloper
    My web applications security is handled by Spring Security 3.02 but I can't find any out of the box support for Brute Force Detection. I would like to implement some application level BFD protection. For example by storing failed login attempt per user in the database (JPA). The attacked user accounts could then get a lockout period or a forced account re-activation by e-mail. What's the best way to implement this with Spring Security? Does any body have example code or best practices on this?

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  • Client timeout when using WCF through Spring.net

    - by Khash
    I'm using WCF through Spring.net WCF integration link text This works relatively fine, however it seems that WCF and Spring get in each other's way when instantiating client channels. This means that only a single client channel is created for a service and therefore the clients get a timeout after the configured timeout is expired since the same client channel has been open since it was instantiated by Spring. To make the matters worst, once a channel goes to a fault state, it affect all users of that service since spring doesn't create a new channel for each user. Has anyone managed to use WCF and Spring.net work together without these issues?

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  • How to make Spring accept non-void setters?

    - by Chris
    Hi, I have an API which I am turning into an internal DSL. As such, most methods in my PoJos return a reference to this so that I can chain methods together declaratively as such (syntactic sugar). myComponent .setID("MyId") .setProperty("One","1") .setProperty("Two","2") .setAssociation(anotherComponent) .execute(); My API does not depend on Spring but I wish to make it 'Spring-Friendly' by being PoJo friendly with zero argument constructors, getters and setters. The problem is that Spring seems to not detect my setter methods when I have a non-void return type. The return type of this is very convenient when chaining together my commands so I don't want to destroy my programmatic API just be to compatible with Spring injection. Is there a setting in Spring to allow me to use non-void setters? Chris

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