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  • Boost::Spirit::Qi autorules -- avoiding repeated copying of AST data structures

    - by phooji
    I've been using Qi and Karma to do some processing on several small languages. Most of the grammars are pretty small (20-40 rules). I've been able to use autorules almost exclusively, so my parse trees consist entirely of variants, structs, and std::vectors. This setup works great for the common case: 1) parse something (Qi), 2) make minor manipulations to the parse tree (visitor), and 3) output something (Karma). However, I'm concerned about what will happen if I want to make complex structural changes to a syntax tree, like moving big subtrees around. Consider the following toy example: A grammar for s-expr-style logical expressions that uses autorules... // Inside grammar class; rule names match struct names... pexpr %= pand | por | var | bconst; pand %= lit("(and ") >> (pexpr % lit(" ")) >> ")"; por %= lit("(or ") >> (pexpr % lit(" ")) >> ")"; pnot %= lit("(not ") >> pexpr >> ")"; ... which leads to parse tree representation that looks like this... struct var { std::string name; }; struct bconst { bool val; }; struct pand; struct por; struct pnot; typedef boost::variant<bconst, var, boost::recursive_wrapper<pand>, boost::recursive_wrapper<por>, boost::recursive_wrapper<pnot> > pexpr; struct pand { std::vector<pexpr> operands; }; struct por { std::vector<pexpr> operands; }; struct pnot { pexpr victim; }; // Many Fusion Macros here Suppose I have a parse tree that looks something like this: pand / ... \ por por / \ / \ var var var var (The ellipsis means 'many more children of similar shape for pand.') Now, suppose that I want negate each of the por nodes, so that the end result is: pand / ... \ pnot pnot | | por por / \ / \ var var var var The direct approach would be, for each por subtree: - create pnot node (copies por in construction); - re-assign the appropriate vector slot in the pand node (copies pnot node and its por subtree). Alternatively, I could construct a separate vector, and then replace (swap) the pand vector wholesale, eliminating a second round of copying. All of this seems cumbersome compared to a pointer-based tree representation, which would allow for the pnot nodes to be inserted without any copying of existing nodes. My question: Is there a way to avoid copy-heavy tree manipulations with autorule-compliant data structures? Should I bite the bullet and just use non-autorules to build a pointer-based AST (e.g., http://boost-spirit.com/home/2010/03/11/s-expressions-and-variants/)?

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  • Styling individual menu links in Joomla!

    - by jonos
    Using Joomla, I have a flat list menu (see image) and am using separator links with images to separate the menu links. I'd like to style the menu links (not the separator links) so that they are lifted up slightly and are sitting more centrally among the separator images. Can anybody help with this?

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  • Why am I getting a " instance has no attribute '__getitem__' " error?

    - by Kevin Yusko
    Here's the code: class BinaryTree: def __init__(self,rootObj): self.key = rootObj self.left = None self.right = None root = [self.key, self.left, self.right] def getRootVal(root): return root[0] def setRootVal(newVal): root[0] = newVal def getLeftChild(root): return root[1] def getRightChild(root): return root[2] def insertLeft(self,newNode): if self.left == None: self.left = BinaryTree(newNode) else: t = BinaryTree(newNode) t.left = self.left self.left = t def insertRight(self,newNode): if self.right == None: self.right = BinaryTree(newNode) else: t = BinaryTree(newNode) t.right = self.right self.right = t def buildParseTree(fpexp): fplist = fpexp.split() pStack = Stack() eTree = BinaryTree('') pStack.push(eTree) currentTree = eTree for i in fplist: if i == '(': currentTree.insertLeft('') pStack.push(currentTree) currentTree = currentTree.getLeftChild() elif i not in '+-*/)': currentTree.setRootVal(eval(i)) parent = pStack.pop() currentTree = parent elif i in '+-*/': currentTree.setRootVal(i) currentTree.insertRight('') pStack.push(currentTree) currentTree = currentTree.getRightChild() elif i == ')': currentTree = pStack.pop() else: print "error: I don't recognize " + i return eTree def postorder(tree): if tree != None: postorder(tree.getLeftChild()) postorder(tree.getRightChild()) print tree.getRootVal() def preorder(self): print self.key if self.left: self.left.preorder() if self.right: self.right.preorder() def inorder(tree): if tree != None: inorder(tree.getLeftChild()) print tree.getRootVal() inorder(tree.getRightChild()) class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): return self.items[len(self.items)-1] def size(self): return len(self.items) def main(): parseData = raw_input( "Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) " ) tree = buildParseTree(parseData) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + preorder(tree)) print( "The post order is: ", + inorder(tree)) main() And here is the error: Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) ( 1 + 2 ) Traceback (most recent call last): File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 108, in main() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 102, in main tree = buildParseTree(parseData) File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 46, in buildParseTree currentTree = currentTree.getLeftChild() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 15, in getLeftChild return root[1] AttributeError: BinaryTree instance has no attribute '__getitem__'

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  • binary search tree recursive subtree in java

    - by Art Peterson
    Can anyone point me to a code example (java preferably) or psuedocode that uses recursion to return a subtree that contains all nodes with keys between fromKey and toKey. So if I was to call Tree.subtree(5,10) it should return all nodes in the BST that have keys between 5 and 10 inclusive - but I can't use loops or helper methods...only recursive calls to the subtree method, which takes fromKey and toKey as parameters. Thanks!

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  • asp.net mvc tree view with checkbox

    - by mazhar
    Ok I am looking for a solution in mvc2 where i can have tree view generated where after that i can checked the nodes I want to enter the value in the database. Can anyone point me to something? Basically I am assigning features to a particular group.(I have a group admin whom I can assign the manage user add edit delete,manage groups delete,manage teacher add edit feature Can someone point me to some other technique that i can implement?

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  • Android Source Code Tree Structure

    - by Walidix
    I have downloaded Android source code but I don't find the "Kernel Directory" in the top level directory of the source code tree. Is it normal ???? or is it missing ??? /mydroid$ find . -name kernel ./bionic/libc/kernel ./vendor/htc/sapphire-open/kernel ./vendor/htc/dream-open/kernel ./dalvik/libcore/luni-kernel/src/test/java/tests/api/org/apache/harmony/kernel ./dalvik/libcore/luni-kernel/src/main/java/org/apache/harmony/kernel ./prebuilt/android-arm/kernel ./prebuilt/android-x86/kernel ./device/htc/passion/kernel

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  • Parse XML tree with no id using LINQ to XML

    - by Danny
    Requirement I want to read a XML tree, fill my objects with encountered attributes and after every run a method (insert it into my db). The amount of parents is not specified, also the order is not specified, it could be, address-death-death-address-address for example Input file Overview: <Root> <Element> <Element2> <Parent> <Child> <Grandchild> <Grandchild> </Child> </Parent> </Element2> </Element1> </Root> Full example: <?xml version="1.0" encoding="utf-8" ?> <Root> <Element1> <Element2> <Parent> <Child> <Grandchild> <number>01</number> <name>Person</name> <Rows> <Row> <number>0110</number> <name>ID</name> <value>123456789</value> </Row> </Rows> </Grandchild> <Grandchild> <number>08</number> <name>Address</name> <Rows> <Row> <number>1110</number> <name>street</name> <value>first aveneu</value> </Row> <Row> <number>1120</number> <name>streetnumber</name> <value>345</value> </Row> <Row> <number>1130</number> <name>zip</name> <value>2938PS</value> </Row> <Row> <number>1160</number> <name>country</name> <value>Germany</value> </Row> </Rows> </Grandchild> </Child> </Parent> <Parent> <Child> <Grandchild> <number>01</number> <name>Person</name> <Rows> <Row> <number>0110</number> <name>ID</name> <value>987654321</value> </Row> </Rows> </Grandchild> <Grandchild> <number>06</number> <name>Death</name> <Rows> <Row> <number>0810</number> <name>date</name> <value>2012-01-03</value> </Row> <Row> <number>0820</number> <name>placeOfDeath</name> <value>attic</value> </Row> <Row> <number>0830</number> <name>funeral</name> <value>burrial</value> </Row> </Rows> </Grandchild> </Child> </Parent> </Element2> </Element1> </Root> Desired result After encounter of parent determine type of grandchild (number 6 is death number 8 is address) Every parent has ALWAYS grandchild number 1 'Person', the second grandchild is either death or address. reading first parent Person person = new Person(); person.ID = value; <--- filled with 123456789 person.street = value; <--- filled with first aveneu person.streetnumber = value; <--- filled with 345 person.zip = value; <--- filled with 2938PS person.country = value; <--- filled with germany person.DoMethod(); // inserts the value in db Continue reading next parent. Person person = new Person(); person.ID = value; <--- filled with 987654321 person.date = value; <--- filled with 2012-01-03 person.placeOfDeath = value; <--- filled with attic person.funeral = value; <--- filled with burrial person.DoMethod(); // insert the values in db Continue reading till no parents found EDIT: how do I target the name element of the second grandchild for every child? Like address or death Code/Credit I got no further then this, with help of Daniel Hilgarth: Linq to XML (C#) parse XML tree with no attributes/id to object The XML tree has changed, and I am really stuck.. in the meantime I try to post new working code...

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  • Expression Tree Binary Expression for an 'In' operation

    - by Adam Driscoll
    I'm trying to build an expression tree (still) but getting further! I need to create a BinaryExpression to perform an 'In' comparison between a Member and a collection of items. Hence, the expression should return true if the member is contained within the items. This obviously does not exist: Expression.MakeBinary(ExpressionType.In, memberExpression, constantExpression); constantExpression is a ConstantExpression of type IEnumerable while memberExpression is a MemberExpression of type T. How would I create such an expression?

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  • is there anyway to clean up old svn directories and files from old source code tree

    - by oo
    i have been sent a directory tree of source code that i want to import into my subversion repository. The issue is that at some point this code was in a different subversion repository. There are a huge number of directories and subdirectories and i basically want to clean up all of the subversion .svn folders before i attempt to import to a new repository and i dont want svn to get confused. is there anyway to clean out a directory structure to remove all svn references?

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  • Sorting tree with other column in SQL Server 2008

    - by bodziec
    Hi, I have a table which implements a tree using hierarchyid column Sample data: People \ Girls \1\ Zoey \1\1\ Kate \1\2\ Monica \1\3\ Boys \2\ Mark \2\1\ David \2\2\ This is the order using hierarchyid column as sort column I would like to sort data using hierarchyid but also using name so it would look like this: People \ Boys \2\ David \2\2\ Mark \2\1\ Girls \1\ Kate \1\2\ Monica \1\3\ Zoey \1\1\ Is there a simple solution to do this? Czy da sie to zrobic w jednym zapytaniu sql ?

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  • nearest neighbor - k-d tree - wikipedia proof.

    - by user123930
    On the wikipedia entry for k-d trees, an algorithm is presented for doing a nearest neighbor search on a k-d tree. What I don't understand is the explanation of step 3.2. How do you know there isn't a closer point just because the difference between the splitting coordinate of the search point and the current node is greater than the difference between the splitting coordinate of the search point and the current best?

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  • How do I present a RichFaces tree with a specific node already expanded

    - by Brummo
    I have a JSF page that displays a RichFaces Treeview, from a TreeNodeImpl model generated in the backing bean. Now I want the page to display initially with a specific node expanded / selected. Preferrably this expansion should be controlled from the backing bean (no javascript wizardry) The whole tree has been generated at the time of initialization of the backing bean Is this possible? I have seen mentioning of TreeState, is that the way to go?

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  • process tree

    - by Robert
    I'm looking for an easy way to find the process tree (as shown by tools like Process Explorer), in C# or other .Net language. It would also be useful to find the command-line arguments of another process (the StartInfo on System.Diagnostics.Process seems invalid for process other than the current process). I think these things can only be done by invoking the win32 api, but I'd be happy to be proved wrong. Thanks! Robert

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  • Tree Widgets on Rails

    - by Joe
    I would like to find some help building a tree interface in Rails. I've tried using jsTree but am having trouble integrating it properly into Rails. Thanks.

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  • Why am I getting tree conflicts in subversion?

    - by Greg
    I had a feature branch of my trunk and was merging changes from my trunk into my branch periodically and everything was working fine. Today I went to merge the branch back down into the trunk and any of the files that were added to my trunk after the creation of my branch were flagged as a "tree conflict". Is there any way to avoid this in the future? I don't think these are being properly flagged. Thanks.

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