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  • UNC path to a folder on my local computer

    - by xt_20
    Hi all, What's the UNC path to a folder on my local computer, and how can I access it? I have tried: 1. Security for the folder -- set to Everyone Full Control (for now!) 2. Sharing permissions -- set to Everyone Full Control (for now!) I can see the folder in \, but can't go in ( is not accessible.) Error message: "You might not have permission to use this network resource. Contact the administrator of this server to find out if you have access pernmissions. The network location cannot be reached. For information about network troubleshooting, see Windows Help." My computer is not connected to a network.

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  • length of captured packets more than MTU

    - by kumar
    Hi, I m running iperf between two machines (linux) and I can observe the mtu of both the interfaces connected is 1500. I ran tcpdump to capture packets and I observed some packets have "length as 2962"....how come this is possible with mtu as only 1500? Please clarify. Thanks! Note: flags field is set as DF. and proto is TCP

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  • On a local network, are you able to password protect certain folders and how (in windows xp)?

    - by Derek
    I have a local network set up for my small office which consists of me, the manager, my wife, the secretary, and a few sales people/others. I would like to share passwords over the network and other such things privately to my wife, the secretary, but would not like the sales people and others to have access to it, yet I need the others to have access to other folders/documents that I'd like to share. How would I go about doing this if not by password? Thanks in advance

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  • Can an application affect TCP retransmits

    - by sipwiz
    I'm troubleshooting some communications issues and in the network traces I am occasionally coming across TCP sequence errors. One example I've got is: Server to Client: Seq=3174, Len=50 Client to Server: Ack=3224 Server to Client: Seq=3224, Len=50 Client to Server: Ack=3224 Server to Client: Seq=3274, Len=10 Client to Server: Ack=3224, SLE=3274, SRE=3284 Packets 4 & 5 are recorded in the trace (which is from a router in between the client and server) at almost exactly the same time so they most likely crossed in transit. The TCP session has got out of sync with the client missing the last two transmissions from the server. Those two packets should have been retransmitted but they weren't, the next log in the trace is a RST packet from the Client 24 seconds after packet 6. My question is related to what could be responsible for the failure to retransmit the server data from packets 3 & 5? I would assume that the retransmit would be at the operating system level but is there anyway the application could influence it and stop it being sent? A thread blocking or put to sleep or something like that?

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  • Facebook insights for websites does not match on-site Facebook button counts

    - by Will
    I use Facebook Insights for websites and Facebook buttons on my site. However, the data reported by the two do not match. It always seems to be the case that the count reported by the buttons is significantly higher than the count reported in Facebook Insights. For example, this page http://www.appmyworld.com/blog/top-5-iphone-and-ipad-apps-of-the-week-10412.html has a count of 52 for Facebook which is made up of 19 likes, 21 shares and 12 comments according to AddThis and confirmed by http://sharedcount.com However, going into Facebook Insights for my website and looking at that specific page it shows only 4 total actions which is made up of 1 like and 3 shares. At the very least I would expect it to show a total count of 40 made up of 19 likes and 21 shares (I'm not sure it would track the 12 comments). Any thoughts on why this may be happening? My concern is if our website is not getting credit for the Facebook activity?

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  • How to create an adhoc network between laptops in java?

    - by Muaz
    Hello, I want to create an adhoc between labtops were they will communicate using wireless communication. I will use java for this but still I do not know how to start.. I think I'll have to use sockets for the connections right? How will a laptop notice other laptops in its local network or the other way around? Do i need a server to handle the communication between laptops? Another thing, how to broadcast a message from one laptop to other laptops in the network? Please reply as soon as you can. Any help will be appreciated. Thanks in advance.

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  • How can I enable/disable network connection options programmatically

    - by nikie
    When I open the properties on a network connnection on windows, I see this dialog: In this dialog, in the check-listbox I can enable or disable options like "File or printer sharing", "client for microsoft networks" or network filter drivers. My question is: How can I enable/disable these options programatically? I didn't find anything that looks like this in the WMI documentation and I couldn't find any other Win32 API for this. I would prefer a C Win32 API or WMI interface, but a solution using any programming language is welcome. The question is language-agnostic.

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  • Discovering maximum packet size

    - by ereOn
    I'm working on a network-related project and I am using DTLS (TLS/UDP) to secure communications. Reading the specifications for DTLS, I've noted that DTLS requires the DF flag (Don't Fragment) to be set. On my local network if I try to send a message bigger than 1500 bytes, nothing is sent. That makes perfect sense. On Windows the sendto() reports a success but nothing is sent. I obviously cannot unset the DF flag manually since it is mandatory for DTLS and i'm not sure whether the 1500 bytes limit (MTU ?) could change in some situations. I guess it can. So, my question is : "Is there a way to discover this limit ?" If not, what would be the lowest possible value ? My software runs under UNIX (Linux/MAC OSX) and Windows OSes so different solutions for each OS are welcome ;) Many thanks.

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  • one two-directed tcp socket OR two one-directed? (linux, high volume, low latency)

    - by osgx
    Hello I need to send (interchange) a high volume of data periodically with the lowest possible latency between 2 machines. The network is rather fast (e.g. 1Gbit or even 2G+). Os is linux. Is it be faster with using 1 tcp socket (for send and recv) or with using 2 uni-directed tcp sockets? The test for this task is very like NetPIPE network benchmark - measure latency and bandwidth for sizes from 2^1 up to 2^13 bytes, each size sent and received 3 times at least (in teal task the number of sends is greater. both processes will be sending and receiving, like ping-pong maybe). The benefit of 2 uni-directed connections come from linux: http://lxr.linux.no/linux+v2.6.18/net/ipv4/tcp_input.c#L3847 3847/* 3848 * TCP receive function for the ESTABLISHED state. 3849 * 3850 * It is split into a fast path and a slow path. The fast path is 3851 * disabled when: ... 3859 * - Data is sent in both directions. Fast path only supports pure senders 3860 * or pure receivers (this means either the sequence number or the ack 3861 * value must stay constant) ... 3863 * 3864 * When these conditions are not satisfied it drops into a standard 3865 * receive procedure patterned after RFC793 to handle all cases. 3866 * The first three cases are guaranteed by proper pred_flags setting, 3867 * the rest is checked inline. Fast processing is turned on in 3868 * tcp_data_queue when everything is OK. All other conditions for disabling fast path is false. And only not-unidirected socket stops kernel from fastpath in receive

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  • Should I close sockets from both ends?

    - by Roman
    I have the following problem. My client program monitor for availability of server in the local network (using Bonjour, but it does not rally mater). As soon as a server is "noticed" by the client application, the client tries to create a socket: Socket(serverIP,serverPort);. At some point the client can loose the server (Bonjour says that server is not visible in the network anymore). So, the client decide to close the socket, because it is not valid anymore. At some moment the server appears again. So, the client tries to create a new socket associated with this server. But! The server can refuse to create this socket since it (server) has already a socket associated with the client IP and client port. It happens because the socket was closed by the client, not by the server. Can it happen? And if it is the case, how this problem can be solved? Well, I understand that it is unlikely that the client will try to connect to the server from the same port (client port), since client selects its ports randomly. But it still can happen (just by chance). Right?

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  • Gathering mac addresses with Python

    - by William
    Hi, is there a good way to gather the mac addresses of machines on a local network using Python. If it helps I'm trying to execute this python script from the DHCP server for the network. I'm new to Python but would it be a bad idea to look at the DHCP leases file for this info? I'd like to use this inside a Django app eventually. Thanks.

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  • Basic Client-Server Design for persistent connections?

    - by cam
    Here's as far as I understand it: Client & Server make connection Client sends server data Server interprets data, sends client data So on, and so forth, until client sends disconnect signal. I'm just wondering about implementation. Step 2 and 3 are confusing to me, maybe I'm over-complicating it. Is there anymore to interpreting the data than a giant switch statement? Any good books on client/server design? Specifically talking about multithreaded servers, scalability, and message design (byte 1 = header info, byte 2 = blah blah, etc)? Specifically geared towards C++.

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  • one two-directed tcp socket of two one-directed? (linux, high volume, low latency)

    - by osgx
    Hello I need to send (interchange) a high volume of data periodically with the lowest possible latency between 2 machines. The network is rather fast (e.g. 1Gbit or even 2G+). Os is linux. Is it be faster with using 1 tcp socket (for send and recv) or with using 2 uni-directed tcp sockets? The test for this task is very like NetPIPE network benchmark - measure latency and bandwidth for sizes from 2^1 up to 2^13 bytes, each size sent and received 3 times at least (in teal task the number of sends is greater. both processes will be sending and receiving, like ping-pong maybe). The benefit of 2 uni-directed connections come from linux: http://lxr.linux.no/linux+v2.6.18/net/ipv4/tcp_input.c#L3847 3847/* 3848 * TCP receive function for the ESTABLISHED state. 3849 * 3850 * It is split into a fast path and a slow path. The fast path is 3851 * disabled when: ... 3859 * - Data is sent in both directions. Fast path only supports pure senders 3860 * or pure receivers (this means either the sequence number or the ack 3861 * value must stay constant) ... 3863 * 3864 * When these conditions are not satisfied it drops into a standard 3865 * receive procedure patterned after RFC793 to handle all cases. 3866 * The first three cases are guaranteed by proper pred_flags setting, 3867 * the rest is checked inline. Fast processing is turned on in 3868 * tcp_data_queue when everything is OK. All other conditions for disabling fast path is false. And only not-unidirected socket stops kernel from fastpath in receive

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  • data path (travel) of tcp data from "write" syscall downto I/O registers programming

    - by osgx
    Hello Is there a good overview of tcp data path in Linux (2.6, not 2.4 if the path actually differ)? Where is a packet on different stages of tcp/ip stack handling? How packet is packed to tcp segment, then ip packet. How it is transmitted to network card? (with series of I/O regs write and DMA?) Is it transmitted to network card in the "write" syscall handler (with some deep callstack) or is it transmitted at some other moment?

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  • How to implement thread timeout in J2ME?

    - by lilo
    I am using Connector in J2ME and found that sometimes it take a very long time to send a request, and sometime it may halt the whole process. So I try to put code related to Connector in a thread and try to set timeout to the thread. But I found out that it's very difficult to do this in J2ME because there's no join(long) in J2ME. Is there any way to do this? Or any better way to deal with network connection in J2ME? Thanks a lot in advance.

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  • Why do sockets not die when server dies? Why does a socket die when server is alive?

    - by Roman
    I try to play with sockets a bit. For that I wrote very simple "client" and "server" applications. Client: import java.net.*; public class client { public static void main(String[] args) throws Exception { InetAddress localhost = InetAddress.getLocalHost(); System.out.println("before"); Socket clientSideSocket = null; try { clientSideSocket = new Socket(localhost,12345,localhost,54321); } catch (ConnectException e) { System.out.println("Connection Refused"); } System.out.println("after"); if (clientSideSocket != null) { clientSideSocket.close(); } } } Server: import java.net.*; public class server { public static void main(String[] args) throws Exception { ServerSocket listener = new ServerSocket(12345); while (true) { Socket serverSideSocket = listener.accept(); System.out.println("A client-request is accepted."); } } } And I found a behavior that I cannot explain: I start a server, than I start a client. Connection is successfully established (client stops running and server is running). Then I close the server and start it again in a second. After that I start a client and it writes "Connection Refused". It seems to me that the server "remember" the old connection and does not want to open the second connection twice. But I do not understand how it is possible. Because I killed the previous server and started a new one! I do not start the server immediately after the previous one was killed (I wait like 20 seconds). In this case the server "forget" the socket from the previous server and accepts the request from the client. I start the server and then I start the client. Connection is established (server writes: "A client-request is accepted"). Then I wait a minute and start the client again. And server (which was running the whole time) accept the request again! Why? The server should not accept the request from the same client-IP and client-port but it does!

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  • What's pcap_pkthdr there for?

    - by httpinterpret
    Code snippet from here: void packet_handler(u_char *param, const struct pcap_pkthdr *header, const u_char *pkt_data) { .... /* retireve the position of the ip header */ ih = (ip_header *) (pkt_data + 14); //length of ethernet header .... What's const struct pcap_pkthdr *header for, when do we need it, how is it populated (since there is no such info in the packet itself as below)?

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  • Question about POP3 message termination octet

    - by user361633
    This is from the POP3 RFC. "Responses to certain commands are multi-line. In these cases, which are clearly indicated below, after sending the first line of the response and a CRLF, any additional lines are sent, each terminated by a CRLF pair. When all lines of the response have been sent, a final line is sent, consisting of a termination octet (decimal code 046, ".") and a CRLF pair. If any line of the multi-line response begins with the termination octet, the line is "byte-stuffed" by pre-pending the termination octet to that line of the response. Hence a multi-line response is terminated with the five octets "CRLF.CRLF". When examining a multi-line response, the client checks to see if the line begins with the termination octet. If so and if octets other than CRLF follow, the first octet of the line (the termination octet) is stripped away. If so and if CRLF immediately follows the termination character, then the response from the POP server is ended and the line containing ".CRLF" is not considered part of the multi-line response." Well, i have problem with this, for example gmail sometimes sends the termination octet and then in the NEXT LINE sends the CRLF pair. For example: "+OK blah blah" "blah blah." "\r\n" That's very rare, but it happens sometimes, so obviously i'm unable to determine the end of the message in such case, because i'm expecting a line that consists of '.\r\n'. Seriously, is Gmail violating the POP3 protocol or i'm doing something wrong? Also i have a second question, english is not my first language so i cannot understand that completely: "If any line of the multi-line response begins with the termination octet, the line is "byte-stuffed" by pre-pending the termination octet to that line of the response. Hence a multi-line response is terminated with the five octets "CRLF.CRLF"." When exactly CRLF.CRLF is used? Can someone gives me a simple example? The rfc says that is used when any line of the response begins with the termination octet. But i don't see any lines that starts with '.' in the messages that are terminated with CRLF.CRLF. I checked that. Maybe i don't understand something, that's why i'm asking.

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  • Multiple HTTP requests using sockets in java

    - by codeomnitrix
    How could i send multiple http requests from my java program using sockets. actually i have tried as: import java.net.*; import java.io.*; class htmlPageFetch{ public static void main(String[] args){ try{ Socket s = new Socket("127.0.0.1", 80); DataInputStream dIn = new DataInputStream(s.getInputStream()); PrintWriter dOut = new PrintWriter(s.getOutputStream(), true); dOut.println("GET /mytesting/justCheck.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); boolean more_data = true; String str; int i = 0; while(more_data){ str = dIn.readLine(); if(str==null){ //Now server has stopped sending data //So now write again the inputs dOut.println("GET /mytesting/justCheck1.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); continue; } System.out.println(str); } }catch(IOException e){ } } } But when I send the request again it was not processed? Thank in advance.

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