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  • How to avoid hard-coded credentials in Sharepoint webpart?

    - by Bryan
    I am building a Sharepoint web part that will be used by all users, but can only be modified by admins. The web part connects to a web service which needs credentials. I hard coded credentials in the web part's code. query.Credentials = new System.Net.NetworkCredential("username", "password", "domain"); query is an instance of the web service class This may not be a good approach. In regard with security, the source code of the web apart is available to people who are not allowed to see the credentials. In normal ASP.net applications, credentials can be written into web.config and encrypted. A web part doesn't have a .config file associated. There is a application-level .config file for the whole sharepoint site, but I don't want to modify it for a single webpart. I wonder if there is a webpart-specific way to solve the credential problem? Say we provide a WebBrowsable property of that web part so that privileged users can modify credentials. If this is desirable, how should I make the property displayed in a password ("*") rather than in plain text? Thanks.

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  • problem configure JBoss to work with JNDI(2)

    - by Spiderman
    in continuation to the question from last week: http://stackoverflow.com/questions/2828237/problem-configure-jboss-to-work-with-jndi I'm trying to bind datasource in JBoss and use it in my application. In my struggling, I already managed to avoid the javax.naming.NameNotFoundException by: 1. using in java new InitialContext().lookup(connection); instead of new JndiObjectFactoryBean().setJndiName(connection); 2. changing the connection name from: 'jndi-name' to 'java:jndi-name' Now the problem is that the datasouce that I get from the lookup is null. I created the datsource file: <datasources> <local-tx-datasource> <jndi-name>bilby</jndi-name> <connection-url>jdbc:oracle:myURL</connection-url> <driver-class>oracle.jdbc.OracleDriver </driver-class> <user-name>myUsername</user-name> <password>myPassword</password> <exception-sorter-class- name>org.jboss.resource.adapter.jdbc.vendor.OracleExceptionSorter</exception-sorter-class-name> <metadata> <type-mapping>Oracle9i</type-mapping> </metadata> </local-tx-datasource> </datasources> and put it under \server\default\deploy\oracle-ds.xml I get during runtime the line: 18:37:56,560 INFO [ConnectionFactoryBindingService] Bound ConnectionManager 'jb oss.jca:service=DataSourceBinding,name=bilby' to JNDI name 'java:bilby' So my question is - why do I get null as my datasource???

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  • c# Sending emails with authentication. standard approach not working

    - by Ready Cent
    I am trying to send an email using the following very standard code. However, I get the error that follow... MailMessage message = new MailMessage(); message.Sender = new MailAddress("[email protected]"); message.To.Add("[email protected]"); message.Subject = "test subject"; message.Body = "test body"; SmtpClient client = new SmtpClient(); client.Host = "mail.myhost.com"; //client.Port = 587; NetworkCredential cred = new NetworkCredential(); cred.UserName = "[email protected]"; cred.Password = "correct password"; cred.Domain = "mail.myhost.com"; client.Credentials = cred; client.UseDefaultCredentials = false; client.Send(message); Mailbox unavailable. The server response was: No such user here. This recipient email address definitely works. To make this account work I had to do some special steps in outlook. Specifically, I had to do change account settings - more settings - outgoing server - my outgoing server requires authentication & use same settings. I am wondering if there is some other strategy. I think the key here is that my host is Server Intellect and I know that some people on here use them so hopefully someone else has been able to get through this. I did talk to support but they said with coding issues I am on my own :o

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  • Servlet Security question about j_security_check, j_username and j_password

    - by Nitesh Panchal
    Hello, I used jdbcRealm in my web application and it's working fine. I defined all constraints also in my web.xml. Like all pages of url pattern /Admin/* should be accessed by only admin. I have a login form with uses standard j_security_check, j_username and j_password. Now, when i type Admin/home.jsf it rightly redirects me login.jsf and there when i type the password i am redirected to home.jsf. This works alright but problem comes i directly go to login.jsf and then type password and username. This time it again redirects me to login.jsf. Is there any way through which i can specify which page to go when successful login is there? I need to specify different different pages for different roles. For Admin, it is /Admin/home.jsf for general users it is /General/home.jsf because login form is shared between different type of users. Where do i specify all these things? Secondly, i want to have a remember me checkbox at the end of login form. How do i do this? By default, it is submitted to j_security_check servlet and i have no control over its execution. Please help. This doesn't seem so hard but looks like i am missing something.

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  • Using $this when not in object context--i am using the latest version of php and mysql

    - by user309381
    This is user.php: include("databse.php");//retrieving successfully first name and lastname from databse file into user.php class user { public $first_name; public $last_name; public static function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return ""; } } } ?> Other php file, index.php: <?php include(databse.php); include(user.php); $record = user::find_by_id(1); $object = new user(); $object->id = $record['id']; $object->username = $record['username']; $object->password = $record['password']; $object->first_name = $record['first_name']; $object->last_name = $record['last_name']; // echo $object->full_name(); echo $object->id;// successfully print the id echo $object->username;//success fully print the username echo->$object->full_name();//**ERROR:Using $this when not in object context** ?>

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  • ASP.NET MVC 2 user input to SQL 2008 Database problems

    - by Rob
    After my publish in VS2010 the entire website loads and pulls data from the database perfectly. I can even create new users through the site with the correct key code, given out to who needs access. I have two connection strings in my web.config file The first: <add xdt:Transform="SetAttributes" xdt:Locator="Match(name)" name="EveModelContainer" connectionString="metadata=res://*/Models.EdmModel.EveModel.csdl|res://*/Models.EdmModel.EveModel.ssdl|res://*/Models.EdmModel.EveModel.msl;provider=System.Data.SqlClient;provider connection string=&quot;Data Source=localhost;Initial Catalog=fleet;Persist Security Info=True;User ID=fleet;Password=****&quot;" providerName="System.Data.EntityClient" /> The second: <add xdt:Transform="SetAttributes" xdt:Locator="Match(name)" name="ApplicationServices" connectionString="Data Source=localhost;Initial Catalog=fleet;Persist Security Info=True;User ID=fleet;Password=****;MultipleActiveResultSets=True" /> The first one is the one that is needed to post data with the main application, EveModelContainer. Everything else is pulled using the standard ApplicationServices connection. Do you see anything wrong with my connectionstring? I'm at a complete loss here. The site works perfectly on my friends server and not on mine... Could it be a provider issue? And if I go to iis 7's manager console, and click .net users I get a pop up message saying the custom provider isn't a trusted provider do I want to allow it to run at a higher trust level. I'm at the point where I think its either my string or this trusted provider error... but I have no clue how to add to the trusted provider list... Thank you in advance!!!

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  • odd nullreference error at foreach when rendering view

    - by giddy
    This error is so weird I Just can't really figure out what is really wrong! In UserController I have public virtual ActionResult Index() { var usersmdl = from u in RepositoryFactory.GetUserRepo().GetAll() select new UserViewModel { ID = u.ID, UserName = u.Username, UserGroupName = u.UserGroupMain.GroupName, BranchName = u.Branch.BranchName, Password = u.Password, Ace = u.ACE, CIF = u.CIF, PF = u.PF }; if (usersmdl != null) { return View(usersmdl.AsEnumerable()); } return View(); } My view is of type @model IEnumerable<UserViewModel> on the top. This is what happens: Where and what exactly IS null!? I create the users from a fake repository with moq. I also wrote unit tests, which pass, to ensure the right amount of mocked users are returned. Maybe someone can point me in the right direction here? Top of the stack trace is : at lambda_method(Closure , User ) at System.Linq.Enumerable.WhereSelectArrayIterator`2.MoveNext() at ASP.Index_cshtml.Execute() Is it something to do with linq here? Tell me If I should include the full stack trace.

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  • INSERT INTO table doesn't work???

    - by Joann
    I found a tutorial from nettuts and it has a source code in it so tried implementing it in my site.. It is working now. However, it doesn't have a Registration system so I am making one. The thing is, as I have expected, my code is not working... It doesn't seem to know how to INSERT into the database. Here's the function that inserts data into the db. function register_User($un, $email, $pwd) { $query = "INSERT INTO users( username, password, email ) VALUES(:uname, :pwd, :email) LIMIT 1"; if($stmt = $this->conn->prepare($query)) { $stmt->bind_param(':uname', $un); $stmt->bind_param(':pwd', $pwd); $stmt->bind_param(':email', $email); $stmt->execute(); if($stmt->fetch()) { $stmt->close(); return true; } else return "The username or email you entered is already in use..."; } } I have debugged the connection to the database from within the class, it says it's connected. I tried using this method instead: function register($un, $email, $pwd) { $registerquery = $this->conn->query( "INSERT INTO users(uername, password, email) VALUES('".$un."', '".$pwd."', '".$email."')"); if($registerquery) { echo "<h4>Success</h4>"; } else { echo "<h4>Error</h4>"; } } And it echos "Error"... Can you please help me pen point the error in this??? :(

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  • Inserting variables into a query string - it won't work!

    - by Jonesy
    Basically i have a query string that when i hardcode in the catalogue value its fine. when I try adding it via a variable it just doesn't pick it up. This works: Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=WaspTrackAsset_NROI;User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") This doesn't: Public Sub GetWASPAcr() connection.Open() Dim dt As New DataTable() Dim username As String = HttpContext.Current.User.Identity.Name Dim sqlCmd As New SqlCommand("SELECT WASPDatabase FROM dbo.aspnet_Users WHERE UserName = '" & username & "'", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) If dt.Rows.Count > 0 Then For i As Integer = 0 To dt.Rows.Count - 1 If dt.Rows(i)("WASPDatabase") Is DBNull.Value Then WASP = "" Else WASP = "WaspTrackAsset_" + dt.Rows(i)("WASPDatabase") End If Next End If connection.Close() End Sub Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=" & WASP & ";User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") When I debug the catalog is empty in the query string but the WASP variable holds the value "WaspTrackAsset_NROI" Any idea's why? Cheers, jonesy

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  • To OpenID or not to OpenID? Is it worth it?

    - by Eloff
    Does OpenID improve the user experience? Edit Not to detract from the other comments, but I got one really good reply below that outlined 3 advantages of OpenID in a rational bottom line kind of way. I've also heard some whisperings in other comments that you can get access to some details on the user through OpenID (name? email? what?) and that using that it might even be able to simplify the registration process by not needing to gather as much information. Things that definitely need to be gathered in a checkout process: Full name Email (I'm pretty sure I'll have to ask for these myself) Billing address Shipping address Credit card info There may be a few other things that are interesting from a marketing point of view, but I wouldn't ask the user to manually enter anything not absolutely required during the checkout process. So what's possible in this regard? /Edit (You may have noticed stackoverflow uses OpenID) It seems to me it is easier and faster for the user to simply enter a username and password in a signup form they have to go through anyway. I mean you don't avoid entering a username and password either with OpenID. But you avoid the confusion of choosing a OpenID provider, and the trip out to and back from and external site. With Microsoft making Live ID an OpenID provider (More Info), bringing on several hundred million additional accounts to those provided by Google, Yahoo, and others, this question is more important than ever. I have to require new customers to sign up during the checkout process, and it is absolutely critical that the experience be as easy and smooth as possible, every little bit harder it becomes translates into lost sales. No geek factor outweighs cold hard cash at the end of the day :) OpenID seems like a nice idea, but the implementation is of questionable value. What are the advantages of OpenID and is it really worth it in my scenario described above?

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  • CMD Prompt > FTP Size Command

    - by Samuel Baldus
    I'm developing a PHP App on IIS 7.5, which uses PHP FTP commands. These all work, apart from ftp_size(). I've tested: cmd.exe > ftp host > username > password > SIZE filename = Invalid Command However, if I access the FTP site through an Internet Browser, the filesize is displayed. Do I need to install FTP Extensions, and if so, which ones and where do I get them? Here is the PHP Code: <?php // FTP Credentials $ftpServer = "www.domain.com"; $ftpUser = "username"; $ftpPass = "password"; // Unlimited Time set_time_limit(0); // Connect to FTP Server $conn = @ftp_connect($ftpServer) or die("Couldn't connect to FTP server"); // Login to FTP Site $login = @ftp_login($conn, $ftpUser, $ftpPass) or die("Login credentials were rejected"); // Set FTP Passive Mode = True ftp_pasv ($conn, true); // Build the file list $ftp_nlist = ftp_nlist($conn, "."); // Alphabetical sorting sort($ftp_nlist); // Display Output foreach ($ftp_nlist as $raw_file) { // Get the last modified time $mod = ftp_mdtm($conn, $raw_file); // Get the file size $size = ftp_size($conn, $raw_file); // Size is not '-1' => file if (!(ftp_size($conn, $raw_file) == -1)) { //output as file echo "Filename: $raw_file<br />"; echo "FileSize: ".number_format($size, '')."Kb</br>"; echo "Last Modified: ".date("d/m/Y H:i", $mod)."</br>"; } } ?>

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  • Cannot redeploy to remote tomcat 7 with using cargo-maven-plugin

    - by rottmanj
    I am attempting to build and redeploy to a remote tomcat 7 server using the cargo-maven plugin. I have been able to successfully deploy to the remote server, but all other actions fail. Here is the pluging settings in my pom.xml <plugin> <groupId>org.codehaus.cargo</groupId> <artifactId>cargo-maven2-plugin</artifactId> <version>1.1.1</version> <configuration> <!-- Container configuration --> <container> <containerId>tomcat7x</containerId> <type>remote</type> </container> <configuration> <type>runtime</type> <properties> <cargo.remote.username>tomcat</cargo.remote.username> <cargo.remote.password>tomcat</cargo.remote.password> <cargo.remote.uri>http://devserver:8080/manager/html</cargo.remote.uri> </properties> </configuration> </configuration> </plugin> This is the error I am seeing within eclipse, when I attempt to deploy. I posted it to pastebin so it is easier to read. Error link. Any help with this is greatly appreciated.

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • Putting together CSV Cells in Excel with a macro

    - by Eric Kinch
    So, I have a macro to export data into CSV format and it's working great (Code at the bottom). The problem is the data I am putting into it. When I put the data in question in it comes out Firstname,Lastname,username,password,description I'd like to change it so I get Firstname Lastname,Firstname,Lastname,username,password,description What I'd like to do is manipulate my existing macro so to accomplish this. I'm not so good at VBS so any input or a shove in the right direction would be fantastic. Thanks! Sub Make_CSV() Dim sFile As String Dim sPath As String Dim sLine As String Dim r As Integer Dim c As Integer r = 1 'Starting row of data sPath = "C:\CSVout\" sFile = "MyText_" & Format(Now, "YYYYMMDD_HHMMSS") & ".CSV" Close #1 Open sPath & sFile For Output As #1 Do Until IsEmpty(Range("A" & r)) 'You can also Do Until r = 17 (get the first 16 cells) sLine = "" c = 1 Do Until IsEmpty(Cells(1, c)) 'Number of Columns - You could use a FOR / NEXT loop instead sLine = sLine & """" & Replace(Cells(r, c), ";", ":") & """" & "," c = c + 1 Loop Print #1, Left(sLine, Len(sLine) - 1) 'Remove the trailing comma r = r + 1 Loop Close #1 End Sub

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  • DWR and Spring Security - User is deauthenticated in few seconds

    - by Vojtech
    I am trying to implement user authentication via DWR as follows: public class PublicRemote { @Autowired @Qualifier("authenticationManager") private AuthenticationManager authenticationManager; public Map<String, Object> userLogin(String username, String password, boolean stay) { Map<String, Object> map = new HashMap<>(); UsernamePasswordAuthenticationToken authRequest = new UsernamePasswordAuthenticationToken(username, password); try { Authentication authentication = authenticationManager.authenticate(authRequest); SecurityContextHolder.getContext().setAuthentication(authentication); map.put("success", "true"); } catch (Exception e) { map.put("success", "false"); } return map; } public Map<String, Object> getUserState() { Map<String, Object> map = new HashMap<>(); Authentication authentication = SecurityContextHolder.getContext().getAuthentication(); boolean authenticated = authentication != null && authentication.isAuthenticated(); map.put("authenticated", authenticated); if (authenticated) { map.put("authorities", authentication.getAuthorities()); } return map; } } The authentication works correctly and by calling getUserState() I can see that the user is successfully logged in. The problem is that this state will stay only for few seconds. In probably 5 seconds, the getAuthentication() starts returning null. Is there some problem with session in DWR or is it some misconfiguration of Spring Security?

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • How to get Tkinter to input text and submit with button

    - by Rob
    Hi I was wondering if anybody could help me submit code from the test fields to the login fields from Tkinter import * import tkMessageBox if ( __name__ == "__main__" ): import resources.lib.mechanize as mechanize mechanize # Start Browser br = mechanize.Browser(factory=mechanize.RobustFactory()) # User-Agent (Firefox) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://razetheworld.com/wp-login.php?redirect_to=http%3A%2F%2Frazetheworld.com') br.select_form(name="loginform") br['log'] = 'entryWidget_U must enter here' br['pwd'] = 'entryWidget_P must enter here' br.submit(name="wp-submit") print br.geturl() def displayText(): """ Display the Entry text value. """ global entryWidget_U global entryWidget_P if entryWidget_U.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Username") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_U.get().strip()) if entryWidget_P.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Password") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_P.get().strip()) if __name__ == "__main__": root = Tk() root.title("Tkinter Entry Widget") root["padx"] = 40 root["pady"] = 20 # Create a text frame to hold the text Label and the Entry widget textFrame_U = Frame(root) textFrame_P = Frame(root) #Create a Label in textFrame entryLabel = Label(textFrame_U) entryLabel["text"] = "Enter Username:" entryLabel.pack(side=LEFT) entryLabel = Label(textFrame_P) entryLabel["text"] = "Enter Password:" entryLabel.pack(side=LEFT) # Create an Entry Widget in textFrame entryWidget_U = Entry(textFrame_U) entryWidget_U["width"] = 50 entryWidget_U.pack(side=LEFT) entryWidget_P = Entry(textFrame_P) entryWidget_P["width"] = 50 entryWidget_P.pack(side=LEFT) textFrame_U.pack() textFrame_P.pack() button = Button(root, text="Login", command=#Run br.submit(name="wp-submit")) button.pack() root.mainloop()

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  • Remove this URL string when login fails and simply show div error

    - by Anagio
    My developer built our registration page to display a div when logins failed based on a string in the URL. When logins fail this is added to the URL /login?msg=invalid The PHP in my login.phtml which displays the error messages based on the msg= parameter is <?php $msg = ""; $msg = $_GET['msg']; if($msg==""){ $showMsg = ""; } elseif($msg=="invalid"){ $showMsg = ' <div class="alert alert-error"> <a class="close" data-dismiss="alert">×</a> <strong>Error!</strong> Login or password is incorrect! </div>'; } elseif($msg=="disabled"){ $showMsg = "Your account has been disabled."; } elseif($msg==2){ $showMsg = "Your account is not activated. Please check your email."; } ?> In the controller the redirect to that URL is else //email id does not exist in our database { //redirecting back with invalid email(invalid) msg=invalid. $this->_redirect($url."?msg=invalid"); } I know there are a few other validation types for disabled accounts etc. I'm in the process of redesigning the entire interface and would like to get rid of this kind of validation so that the div tags display when logins fail but not show the URL strings. If it matters the new div I want to display is <div class="alert alert-error alert-login"> Email or password incorrect </div> I'd like to replace the php my self in my login.phtml and controller but not a good programmer. What can I replace $this->_redirect($url."?msg=invalid"); with so that no strings are added to the URL and display the appropriate div tags? Thanks

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  • Get Mail with PHP and IMAP in Gmail just loading

    - by Oscar Godson
    I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = '[email protected]'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

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  • CakePHP: Need help using saveField to update a fields in a belongsTo model

    - by afrisch
    I am trying to update a password into two different models/tables in CakePHP. I can update it fine in the parent model, but not the second model. Models: Users (hasOne GameProfile) PK=id Gameprofiles (belongsTo User) FK=user_id Here is a stripped down version of my function in the Users_controller.php: function updatepass() { if (!empty($this->data)) { $this->User->id = $this->Auth->user('id'); $this->User->saveField('sha1password', $this->Auth->password($this->data['User']['newpass'])); $this->User->Gameprofile->saveField('plainpassword', $this->data['User']['newpass']); } } When I execute the function, the users table is updated fine. But the gameprofile table is not updated, rather Cake does an insert. SQL Query Log: 1195 Query UPDATE `users` SET `sha1password` = 'e9443e9f5e1a07832aad1b2f84de1a666daf89b5' WHERE `users`.`id` = 30 1195 Query INSERT INTO `gameprofiles` (`plainpassword`) VALUES ('abc') Is there a way to get CakePHP to do an update using saveField on a model with a belongsTo attribute? I've tried various ways to refer to user_id before executing the second saveField, but just can't seem to find the winning combination. Any help is greatly appreciated!

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  • Output problem in mysql query in MFC program

    - by D.Gaughan
    Im currently working on a small MFC program that outputs data from a mysql database. I can get output when im using an sql statement that does not contain any variable eg. select album from Artists; but when i try to use a variable the program compiles but i get no output eg. mysql_perform_query(conn,select album from Artists where artists = '"+m_search_edit"'") Here is the function for mysql_perform_query: MYSQL_RES* mysql_perform_query(MYSQL *conn, const char* query) { // send the query to the database if (mysql_query(conn, query)) { // printf("MySQL query error : %s\n", mysql_error(conn)); // exit(1); } return mysql_use_result(conn); } And here is the code block for outputting the data: struct connection_details mysqlD; mysqlD.server = "www.freesqldatabase.com"; // where the mysql database is mysqlD.user = "**********"; // the root user of mysql mysqlD.password = "***********"; // the password of the root user in mysql mysqlD.database = "***************"; // the databse to pick // connect to the mysql database conn = mysql_connection_setup(mysqlD); CStringA query; query.Format("select album from Artists where artist = '%s'", CT2CA(m_search_edit)); res = mysql_perform_query(conn, query); //res = mysql_perform_query (conn, "select distinct artist from Artists"); while((row = mysql_fetch_row(res)) != NULL){ CString str; UpdateData(); str = ("%s\n", row[0]); UpdateData(FALSE); m_list_control.AddString(str); } The m_search_edit variable is the variable for an edit box. I am using Visual Studio 2008 with one copy of this program unicode and one nonunicode, I also have a version built with VC++ 6. Any tips on how I can get output from the databse using the m_search_edit variable??

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  • Can i change the identity of the logged in user in ASP.net?

    - by Rising Star
    I have an ASP.net application I'm developing authentication for. I am using an existing cookie-based log on system to log users in to the system. The application runs as an anonymous account and then checks the cookie when the user wants to do something restricted. This is working fine. However, there is one caveat: I've been told that for each page that connects to our SQL server, I need to make it so that the user connects using an Active Directory account. because the system I'm using is cookie based, the user isn't logged in to Active Directory. Therefore, I use impersonation to connect to the server as a specific account. However, the powers that be here don't like impersonation; they say that it clutters up the code. I agree, but I've found no way around this. It seems that the only way that a user can be logged in to an ASP.net application is by either connecting with Internet Explorer from a machine where the user is logged in with their Active Directory account or by typing an Active Directory username and password. Neither of these two are workable in my application. I think it would be nice if I could make it so that when a user logs in and receives the cookie (which actually comes from a separate log on application, by the way), there could be some code run which tells the application to perform all network operations as the user's Active Directory account, just as if they had typed an Active Directory username and password. It seems like this ought to be possible somehow, but the solution evades me. How can I make this work?

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  • cannot modify header information puzzler

    - by outofmyleague_lucy
    hi im out of my league i have written what has now become identical code for two sites hosted on different servers. the first worked perfectly and i have therefore used it to compare the second to.from a login for i am directing to a loginaction.php when i include the db_connect.php ie <?php session_start(); include 'db_connect.php'; $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? i am returning cannot modify header information header info already sent, but when i include the content of the db_connect ie <?php session_start(); $connect = mysql_connect("localhost", "user", "pass"); mysql_select_db(db_name, $connection); $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? it works. any ideas? edit - requested error message Warning: Cannot modify header information - headers already sent by (output started at /home/avenncou/public_html/include/db_connect.php:4) in /home/avenncou/public_html/include/loginaction.php on line 14 at line 14 the is a header("Location: {$_SERVER["HTTP_REFERER"]}"); edit - requested db_connect.php <?php $connection = mysql_connect("localhost", "user", "pass");// or die ("Unable to connect!"); mysql_select_db("db", $connection);// or die ("Unable to select database!"); ?> that is all of it (dies commented out in case thats where the error was)!!!

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  • The post->success->data variable is empty..

    - by Asaf
    Hello, I tried sending some data like so: <form action="http://www.someurl.com/something.php" id="login"> <input type="textbox" id="UserName" value="user"> <input type="textbox" id="Password" value="password"> <input type="submit" value="submit"> </form> <div id="result"></div> <script type="text/javascript"> $('form#login').submit(function() { $.post($('form#login').attr('action'), $('form#login').serialize(), function(data) { $('#result').html(data+'222') }); return false; }); </script> Now, the value of #result div change to 222... that is: the post was successful but for some reason there is no data, and when I go directly to something.php and post manually, it does bring back data (am I mistaken or does the post(success(data)) variable returns the whole page returned after you post something? if so, how could it be?) Thank you very much for your help

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  • Kohana Auth Library Deployment

    - by Steve
    My Kohana app runs perfectly on my local machine. When I deployed my app to a server (and adjust the config files appropriately), I can no longer log into the app. I've traced through the app login routine on both my local version and the server version and they both agree with each other all the way through until you get to the auth.php controller logged_in() routine where suddenly, at line 140 - the is_object($this-user) test - the $user object no longer exists!?!?!? The login() function call that calls the logged_in() function successfully passes the following test, which causes a redirect to the logged_in() function. if(Auth::instance()->login($user, $post['password'])) Yes, the password and hash, etc all work perfectly. Here is the offending code: public function logged_in() { if ( ! is_object($this->user)) { // No user is currently logged in url::redirect('auth/login'); } etc... } As the code is the same between my local installation and the server, I reckon it must be some server setting that is messing with me. FYI: All the rest of the code works because I have a temporary backdoor available that allows me to use the application (view pages of tables, etc) without being logged in. Any ideas?

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