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• SQL server 2055 remote connection problem, cannot solve it help please thank you

  - by user287745

  note:- if this question does not fit this site please do not just close it but also redirect the question to the fitting sister site, thank you" the steps taken and the error are mentioned please help, i am stuck here! installed sql server 2005 express on both computers installed sql server management studio express on both computers ran each management studio and connect to instance sqlserver using windows authentication ( one computer connection example "A-63A9D4D7E7834\SQLEXPRESS" ) created a database in the databases named as "test1" created a few tables with data saved and exit. did everything what this site says " How to configure SQL Server 2005 to allow remote connections" [add h t t p here as spam prevention] ://support.microsoft.com/kb/914277/en-us" but i have just disable the firewalls completely :turn off connecting to A-63A9D4D7E7834 started "SQL Server Management Studio Express" on computer A-63A9D4D7E7834 sever name: "ALL-E425BE6C41D\SQLEXPRESS" authentication: "windows authentication" and CONNECT I GET THE FOLLOWING ERROR Cannot connect to ALL-E425BE6C41D\SQLEXPRESS. ADDITIONAL INFORMATION: Login failed for user 'ALL-E425BE6C41D\Guest'. (Microsoft SQL Server, Error: 18456) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=18456&LinkId=20476 BUTTONS: OK HELP

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• deprecated readLine() What to change?

  - by user1681751

  I'm trying to get this to work in the eclipse, but the "readLine" is striked through and a notice says it is depreciated, the code works, albeit not the "while ((var2 = var5.readLine()) != null) {" bit.. So I'm wondering how to fix it, a java beginner. String var2 = ""; HttpURLConnection var3 = null; DataOutputStream var4 = null; DataInputStream var5 = null; ...more code here.... try { var5 = new DataInputStream(var3.getInputStream()); while ((var2 = var5.readLine()) != null) { System.out.println("Server Response " + var2); ScreenShotHelper.mc.thePlayer.addChatMessage("\u00a7aSuccessfully uploaded screenshot! Direct link:"); ScreenShotHelper.mc.thePlayer.addChatMessage("\u00a7a" + var2); } var5.close(); }

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• How can I keep gnu screen from becoming unresponsive after losing my SSH connection?

  - by Mikey

  I use a VPN tunnel to connect to my work network and then SSH to connect to my work PC running cygwin. Once logged in I can attach to a screen session and everything works great. Now, after a while, I walk away from my computer and sooner or later, the VPN tunnel times out. The SSH connection on each end eventually times out and then I eventually come back to my computer to do some work. Theoretically, this should be a simple matter of just restarting the VPN, reconnecting via SSH, and then running "screen -r -d". However apparently when the sshd daemon times out on the cygwin PC, it leaves the screen session in some kind of hung state. I can reproduce a similar hung state by clicking the close box on a cygwin bash shell window while it's running a screen session. Is there any way to get the screen session to recover once this has happened, so that I don't lose anything?

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• twitter basic authorisation not working?

  - by Bunny Rabbit

  URL url = new URL("http://twitter.com/statuses/update.xml"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setDoOutput(true); String cridentials = new sun.misc.BASE64Encoder().encode((username + ":" + password).getBytes()); conn.setRequestProperty ("Authorization", "Basic " + cridentials); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(status); wr.flush(); wr.close(); why the above code for updating twitter status is not working ? i am running it on google app engine.

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• Can't figure out how to code my css

  - by JF

  Hi, I'm a new poster in stackoverflow. The community seems really nice so I'll go ahead and post my question. I'm trying to style a asp.net MVC2 form so that instead of having all the fields on a strait line, I would like to have it like so: Label: Text field Label: Text field I know you could do that with a table but I would like to use CSS to accomplish that. I know a little bit about css but not enough to figure out what to do. The only thing I came close to was to but my fields as a unorder list then styling the li item. Thank you for your help!

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• Long running, polling, queueing process for Python. What's the best stuff to use?

  - by Bialecki

  Feel free to close and/or redirect if this has been asked, but here's my situation: I've got an application that will require doing a bunch of small units of work (polling a web service until something is done, then parsing about 1MB worth of XML and putting it in a database). I want to have a simple async queueing mechanism that'll poll for work to do in a queue, execute the units of work that need to be done, and have the flexibility to allow for spawning multiple worker processes so these units of work can be done in parallel. (Bonus if there's some kind of event framework that would also me to listen for when work is complete.) I'm sure there is stuff to do this. Am I describing Twisted? I poked through the documentation, I'm just not sure exactly how my problems maps onto their framework, but I haven't spent much time with it. Should I just look at the multiprocess libraries in Python? Something else?

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• Where to handle fatal exceptions

  - by Stephen Swensen

  I am considering a design where all fatal exceptions will be handled using a custom UncaughtExceptionHandler in a Swing application. This will include unanticipated RuntimeExceptions but also custom exceptions which are thrown when critical resources are unavailable or otherwise fail (e.g. a settings file not found, or a server communication error). The UncaughtExceptionHandler will do different things depending on the specific custom exception (and one thing for all the unanticipated), but in all cases the application will show the user an error message and exit. The alternative would be to keep the UncaughtExceptionHandler for all unanticipated exceptions, but handle all other fatal scenarios close to their origin. Is the design I'm considering sound, or should I use the alternative?

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• Loop colours from variables for graphics.py [Python 3.2]

  - by user1056548

  I am creating a graphics program that draws 100 x 100 squares next to each other depending on the user-specified grid size. The user also inputs 4 colours for the squares to be coloured (e.g. if they enter red,green,blue,yellow the squares will be coloured in that order, repeating the colours). Is it possible to loop the colours from the variables the user has given? Here is what I have so far: def main(): print ("Please enter four comma seperated colours e.g.: 'red,green,blue,yellow'\n\ Allowed colours are: red, green, blue, yellow and cyan") col1, col2, col3, col4 = input("Enter your four colours: ").split(',') win = GraphWin ("Squares", 500, 500) colours = [col1, col2, col3, col4] drawSquare (win, col1, col2, col3, col4, colours) win.getMouse() win.close() def drawSquare(win, col1, col2, col3, col4, colours): for i in range (4): for j in range (len(colours)): colour = colours[j] x = 50 + (i * 50) circle = Circle (Point (x,50), 20) circle.setFill(colour) circle.draw(win) I think I should be using a list in some way, but can't work out exactly how to do it. Can anybody help?

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• How to remove duplicate line in a file

  - by Abs

  Hi I'm using the below method to write to a file from the Jtextarea and I call this method every 30 second within a Timer but instead to add only new line in file it rewrite the entire lines contained in Jtextarea so then I have duplicate lines. I want to avoid this and update the file just with new lines. Could you help me please. public void loger() { FileWriter writer = null; try { writer = new FileWriter("MBM_Log_"+date()+".txt" , true); textArea.write(writer); } catch (IOException exception) { System.err.println("log error"); exception.printStackTrace(); } finally { if (writer != null) { try { writer.close(); } catch (IOException exception) { System.err.println("Error closing writer"); exception.printStackTrace(); } } } }

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• Drop Down Problems

  - by user351260

  Hello, I am trying to create a drop down list i have it working but not fully, using this code $(document).ready(function(){ $("#zone-bar li em").hover(function() { var hidden = $(this).parents("li").children("ul").is(":hidden"); $("#zone-bar>ul>li>ul").hide() $("#zone-bar>ul>li>a").removeClass(); if (hidden) { $(this) .parents("li").children("ul").toggle() .parents("li").children("a").addClass("zoneCur"); } }); }); I am managed to make it work so on hover the drop down list will appear which is does but when you move to select one of the items from the drop down list the drop down list closes any help to fix this would be great thanks. It works if i put it to onclick but then you have to click the arrow to close it again the website is doctorwhohd.com and it currently on onclick thanks

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• Google App Engine update an object from servlet not working ?

  - by Frank

  I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

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• Learning Python coming from PHP

  - by Coronatus

  Community wiki so don't vote to close, kthxbai. My dynamic language experience is solely PHP. I want to learn Python now to broaden my career opportunities and just because I like programming. :) When learning Java, I used a site (lost the URL/real name now), something like "Java for PHP developers" that had all on one side of the page the PHP code, and on the other side the Java code to do the same thing. Is there a website like that for Python? Any other recommendations/advice? Thanks Edit: I have no votes left today, but I'll up-vote good answers tomorrow :)

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• Disable Task Manager using c# from Limited User Account

  - by srk

  I need to disable and enable the taskmanager from my application. I am doing this for my Kiosk application. I know i can do this by changing the Key in registry using below code. But the problem is my kiosk application will run in limited user account which does not allow the application to change key in registry level. Code working perfectly in Administrator account : RegistryKey regkey; string keyValueInt = "1"; string subKey = "Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\System"; regkey = Registry.CurrentUser.CreateSubKey(subKey); regkey.SetValue("DisableTaskMgr", keyValueInt); regkey.Close(); How can i achieve this in Limited user account ?

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• print integer and array from file android

  - by vik

  i want to open a file and then calculate the integer and array value from file and print on the screen. i tried this but not working @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); TextView av = new TextView(this); setContentView(av); try { String i = "abc.xyz"; InputStream in = assets.open(i); try { DataInputStream din = new DataInputStream(in); int value = din.readInt(); // print value on screen int[] arry = new int[1]; // print arry on screen how to do it int arry[1] = din.readInt(); } } finally { in.close(); } } catch (IOException e) { throw new PuzzleIOException(e); } av.setText(size); }

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• Reading in 4 bytes at a time

  - by alphomega

  I have a big file full of integers that I'm loading in. I've just started using C++, and I'm trying out the filestream stuff. From everything I've read, it appears I can only read in bytes, So I've had to set up a char array, and then cast it as a int pointer. Is there a way I can read in 4 bytes at a time, and eliminate the need for the char array? const int HRSIZE = 129951336; //The size of the table char bhr[HRSIZE]; //The table int *dwhr; int main() { ifstream fstr; /* load the handranks.dat file */ std::cout << "Loading table.dat...\n"; fstr.open("table.dat"); fstr.read(bhr, HRSIZE); fstr.close(); dwhr = (int *) bhr; }

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• How to execute commands in Command Prompt using c#

  - by karthik

  I want to execute these steps in CMD using c# 1 - CD C:\MySQL\MySQL Server 5.0\bin 2 - mysqldump -uroot -ppassword sample d:\Test\222.sql On manually doing this, i will get file named "222.sql" I am using the below code to do it, but missing something.. Nothing Happens public void CreateScript_AAR() { string commandLine = @"CD C:\MySQL\MySQL Server 5.0\bin\mysqldump -uroot -ppassword sample> d:\Test\222.sql"""; System.Diagnostics.ProcessStartInfo PSI = new System.Diagnostics.ProcessStartInfo("cmd.exe"); PSI.RedirectStandardInput = true; PSI.RedirectStandardOutput = true; PSI.RedirectStandardError = true; PSI.UseShellExecute = false; System.Diagnostics.Process p = System.Diagnostics.Process.Start(PSI); System.IO.StreamWriter SW = p.StandardInput; System.IO.StreamReader SR = p.StandardOutput; SW.WriteLine(commandLine); SW.Close(); }

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• Best method to cleanly shut down an application launched via another.

  - by JYelton

  I couldn't find any close answers to this, so I'm consulting the experience of SO users: Scenario: I have two small C# winforms applications where one behaves as a server or host, the other as a client. They share data via SQL Server, in terms of configuration settings. I am currently launching the client application (which only needs to run periodically) from the server application via Process.Start() and terminating it via Process.CloseMainWindow() (after finding it in the process list). While it seems clean enough, I wondered if there's a better way. Question: Which way would be best to instruct the client application to shut down: Continue using Process.CloseMainWindow()? Implement WCF between the applications? (I would need help on how to do this.) Set a variable in SQL that the client application checks for? Some other way?

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• C# database file directory

  - by Simon

  I'm using the windows forms aplication with an ms access database. And i would like to know if there is a way to show the directory of the database file (to save data in it)excpet like this: string connectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=save.mdb"; or this: "Data Source=D:\Simonova aktovka na namizju\matura\test5\save.mdb"; couse if i use the first one the aplication undos the changes i've made when i close it(the aplication) the second one makes me have to change the path everytime i bring the aplication to another computer(cous the direktory is different of coars) So... is there another way?

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• How to stop LocationManager to broadcast the location to BroadcastManager.

  - by SKuamr

  Hi i added one Broadcast listener for LocationManager [GPS_PROVIDER] with a pending intent. so now when i close my application on phone location manager is updating the broadcast listener perfectly... so this is working fine. Now issue is, i want to stop the LocationManager to update the Broadcast listener... but i am not able to do so... i am again running the application and using locationManager.removeUpdates function to stop it but it still updating the location to Broadcast Manager. Please help me out... its very urgent... Thanks in advance.. Started the Location Manager. Intent intent = new Intent("com.test.geoL.RECEIVE"); //Broadcast Receiver Action PendingIntent pendingIntent = PendingIntent.getBroadcast(getApplicationContext(),0, intent, 0); locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, pendingIntent);

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• Closing a dialog form closes the application

  - by user361633

  bool CheckAnswer() { DialogForm dialogForm = new DialogForm(); if (dialogForm.showDialog() == System.Windows.Forms.DialogResult.OK) return true; } The dialog form is invoked by a form created in the main form. When i close the dialog form the application is closed, not just the dialog form! If i invoke the dialog form in other form it works normally. The form from which i invoke the dialog form is top level, but even if i change that i'm getting the same result. Does anyone know what's wrong?

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• Why is Window.open()'s return type void ?

  - by Salvin Francis

  Doing something like this is perfectly permissible in javascript: var newWindow = window.open(...) However, this does not work in the senario of GWT (I am using 1.5 I dont know about later versions), Window window = Window.open("", "", ""); Throws me a compile time error that the open is a method with a return type as void. Why should it be void ? What if i want to close my popup from the main Window ? how do I get its handle ? I will have to resort to native javascript no doubt but i was just curious so as to why this is so...

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• SQL Server Cursor data as result of stored procedure

  - by Dmitry Borovsky

  Hello, I have a stored procedure DECLARE cursor FOR SELECT [FooData] From [FooTable]; OPEN cursor ; FETCH NEXT FROM cursor INTO @CurrFooData; WHILE @@FETCH_STATUS = 0 BEGIN SELECT @CurrFooData AS FooData; INSERT INTO Bar (BarData) VALUES(@CurrFooData); FETCH NEXT FROM cursor INTO @CurrFooData; END; CLOSE cursor DEALLOCATE cursor But in result I have a lot of tables, not one. How can I return one table with 'FooData' column and all '@CurrFooData' rows?

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• Magento connect stuck while installing

  - by itsandy

  Hi Everyone, I am facing this problem while installing extensions, themes basically anything from magento connect. When I enter the extension key and click install It just gets stuck and even when it says done and I try and go back on admin page it says "There are PEAR processes running. If you will close the window or navigate away from the page, installation will be interrupted. " Has anyone faced this problem. I am working on ubuntu 9.1 and having magento 1.4. Any help would be highly appreciated. Cheers

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• getAssetFileDescriptor from ZipResourceFile merges all mp3 in mediaplayer SOLVED

  - by Jordi

  I've a program with an Expansion file that stores 4 mp3 in a obb file (zip without compression). I can retrieve the data, but instead of taking the audio file i asked for, it merges ALL audio files in the same AssetFileDescriptor. ---SOLVED--- with the fixes Support class public AssetFileDescriptor getaudio(){ ZipResourceFile expansionFile = APKExpansionSupport.getAPKExpansionZipFile(c,21,21); AssetFileDescriptor afd=null; if(take==1) { afd = expansionFile.getAssetFileDescriptor("file01.mp3"); }else if(take==2 { afd = expansionFile.getAssetFileDescriptor("file02.mp3"); } //more els eif ............ return afd; } In the MediaPlayer class AssetFileDescriptor fd = Llistat.getInstance().getAudio(); mPlayer.setDataSource(fd.getFileDescriptor(), fd.getStartOffset(),fd.getLength()); mPlayer.prepare(); fd.close(); My problem was that i directly was returning and using a FileDescriptor, while i was needing the AssetFileDescriptor to take its StartOffset and Length.

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• Write problem - lossing the original data

  - by John

  Every time I write to the text file I will lose the original data, how can I read the file and enter the data in the empty line or the next line which is empty? public void writeToFile() { try { output = new Formatter(myFile); } catch(SecurityException securityException) { System.err.println("Error creating file"); System.exit(1); } catch(FileNotFoundException fileNotFoundException) { System.err.println("Error creating file"); System.exit(1); } Scanner scanner = new Scanner (System.in); String number = ""; String name = ""; System.out.println("Please enter number:"); number = scanner.next(); System.out.println("Please enter name:"); name = scanner.next(); output.format("%s,%s \r\n", number, name); output.close(); }

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