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  • Probably an easy one - PHP/CodeIgniter 'Undefined Variable'

    - by Jack W-H
    Morning y'all This is probably an easy one but I barely got any sleep last night and am struggling to comprehend anything. I've got a CodeIgniter library I've made called Points.php. Here's the contents of Points: <?php if (!defined('BASEPATH')) exit('No direct script access allowed'); class Points { function __construct() { $this->ci =& get_instance(); $this->ci->load->database(); } function getpoints($params) { echo $userid; } } /* End of file Points.php */ /* Location: ./application/libraries/Points.php */ ?> As you can see, I'm building it up slowly and it's being kept simple. In one of my views, I want it to display the number of 'points' (which for the time being is simply the third segment of the URI). I call it like this: <p>Points: <?php $params['user_id']=$this->uri->segment(3,1); echo $this->points->getpoints($params); ?></p> The warning I get back in the view is this: A PHP Error was encountered Severity: Notice Message: Undefined variable: userid Filename: libraries/Points.php Yes I know it's such a simple problem but I've tried lots of things. Some variations include echoing in Points.php $params['userid']; etc. But I don't see what I'm doing wrong? This is my first CodeIgniter class and I've fallen at the first step, haha...

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  • Zend Framework how to echo value of SUM query

    - by Rick de Graaf
    Hello, I created a query for the zend framework, in which I try to retrieve the sum of a column, in this case the column named 'time'. This is the query I use: $this->timequery = $this->db_tasks->fetchAll($this->db_tasks->select()->from('tasks', 'SUM(time)')->where('projectnumber =' . $this->value_project)); $this->view->sumtime = $this->timequery; Echoing the query tells me this is right. But I can't echo the result properly. Currently I'm using: echo $this->sumtime['SUM(time)']; Returning the following error: Catchable fatal error: Object of class Zend_Db_Table_Row could not be converted to string in C:\xampp\htdocs\BManagement\application\views\scripts\tasks\index.phtml on line 46 Line 46 being the line with the echo in my view. I've been searching now for two days on how to figure this out, or achieve the same result in a different way. Tried to serialize the value, but that didn't work either. Is there somebody who knows how to achieve the total sum of a database column? Any help is greatly appriciated! note: Pretty new to zend framework...

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  • error in implementing static files in django

    - by POOJA GUPTA
    my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

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  • How to perform kCATransitionPush animation without any transparency / fade effects

    - by Anthony
    I'm trying to duplicate the "slide up from the bottom" animation that [UIViewController presentModalViewController:animated:] performs but without calling it because I don't want a modal view. The below core animation code comes very close but appears to be changing transparency values of the views during it. At the start of the animation you can partially see through the view sliding up. By the middle/end of the animation the view we are sliding over is fully transparent so we can see behind it. I'd like both to remain fully opaque during this animation. Any ideas on how to stop transparency changes in this code or to otherwise get the "slide up animation" I am looking for without requiring a modal view? UIViewController *nextViewController = [[UIViewController alloc] autorelease]; nextViewController.view.backgroundColor = [UIColor redColor]; CATransition *animation = [CATransition animation]; animation.duration = 3.5; animation.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut]; animation.type = kCATransitionPush; animation.subtype = kCATransitionFromTop; [self.navigationController pushViewController:nextViewController animated:NO]; [self.navigationController.view.layer addAnimation:animation forKey:nil];

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  • Magento started showing PHP language errors since I downloaded the blank theme using Connect

    - by Aayush
    I used the Magento Connect downloader to install the blank theme extension, but I did not switch to it as I was unable to access any-page anymore. Instead, it started showing php errors for front-end and Magento generated security errors for admin. Frontend Error: Fatal error: Call to a member function toHtml() on a non-object in D:\xampp\htdocs\newpinch\app\code\core\Mage\Core\Model\Layout.php on line 529 Admin error on Log-in: There has been an error processing your request Exception printing is disabled by default for security reasons. Error log record number: 1608724822 Link to the theme extension I installed. I didn't even change the theme from the default, can anyone please tell me what am I doing wrong. I just installed the theme and then clicked on "Return to admin" in Magento Connect but it was unable to go instead started refreshed the Magento Connect page, only this time without any CSS styling. The only page that still appears correctly is the admin log-in page. Please help me, I have already tried the forums at magentocommerce.com and their community sucks. 0 views & 0 replies. please help...

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  • ASP MVC: Submitting a form with nested user controls

    - by Nigel
    I'm fairly new to ASP MVC so go easy :). I have a form that contains a number of user controls (partial views, as in System.Web.Mvc.ViewUserControl), each with their own view models, and some of those user controls have nested user controls within them. I intended to reuse these user controls so I built up the form using a hierarchy in this way and pass the form a parent view model that contains all the user controls' view models within it. For example: Parent Page (with form and ParentViewModel) -->ChildControl1 (uses ViewModel1 which is passed from ParentViewModel.ViewModel1 property) -->ChildControl2 (uses ViewModel2 which is passed from ParentViewModel.ViewModel2 property) -->ChildControl3 (uses ViewModel3 which is passed from ViewModel2.ViewModel3 property) I hope this makes sense... My question is how do I retrieve the view data when the form is submitted? It seems the view data cannot bind to the ParentViewModel: public string Save(ParentViewModel viewData)... as viewData.ViewModel1 and viewData.ViewModel2 are always null. Is there a way I can perform a custom binding? Ultimately I need the form to be able to cope with a dynamic number of user controls and perform an asynchronous submission without postback. I'll cross those bridges when I come to them but I mention it now so any answer won't preclude this functionality. Many thanks.

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  • How to change identifier quote character in SSIS for connection to ODBC DSN

    - by William Rose
    I'm trying to create an SSIS 2008 Data Source View that reads from an Ingres database via the ODBC driver for Ingres. I've downloaded the Ingres 10 Community Edition to get the ODBC driver, installed it, set up the data access server and a DSN on the server running SSIS. If I connect to the SQL Server 2008 Database Engine on the server running SSIS, I can retrieve data from Ingres over the ODBC DSN by running the following command: SELECT * FROM OPENROWSET( 'MSDASQL' , 'DSN=IngresODBC;UID=testuser;PWD=testpass' , 'SELECT * FROM iitables') So I am quite sure that the ODBC setup is correct. If I try the same query with SQL Server style bracketed identifier quotes, I get an error, as Ingres doesn't support this syntax. SELECT * FROM OPENROWSET( 'MSDASQL' , 'DSN=IngresODBC;UID=testuser;PWD=testpass' , 'SELECT * FROM [iitables]') The error is "[Ingres][Ingres 10.0 ODBC Driver][Ingres 10.0]line 1, Unexpected character '['.". What I am finding is that I get the same error when I try to add tables from Ingres to an SSIS Data Source View. The initial step of selecting the ODBC Provider works fine, and I am shown a list of tables / views to add. I then select any table, and try to add it to the view, and get "ERROR [5000A] [Ingres][Ingres 10.0 ODBC Driver][Ingres 10.0]line 3, Unexpected character '['.". Following Ed Harper's suggestion of creating a named query also seems to be stymied. If I put into my named query the following text: SELECT * FROM "iitables" I still get an error: "ERROR [5000A] [Ingres][Ingres 10.0 ODBC Driver][Ingres 10.0]line 2, Unexpected character '['". According to the error, the query text passed by SSIS to ODBC was: SELECT [iitables].* FROM ( SELECT * FROM "iitables" ) AS [iitables] It seems that SSIS assumes that bracket quote characters are acceptable, when they aren't. How can I persuade it not to use them? Double quotes are acceptable.

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  • C# - Help with LINQ

    - by cmaduro
    I need to check if a certain property exists within a class. Please refer to the LINQ query in question. For the life of me I cannot make the compiler happy. class Program { static void Main(string[] args) { ModuleManager m = new ModuleManager(); IModule module = m.FindModuleForView(typeof(HomeView)); Console.WriteLine(module.GetType().ToString()); Console.ReadLine(); } } public class ModuleManager { [ImportMany] public IEnumerable<Lazy<IModule>> Modules { get; set; } [ImportMany] public IEnumerable<Lazy<View>> Views { get; set; } public ModuleManager() { //An aggregate catalog that combines multiple catalogs var catalog = new AggregateCatalog(); //Adds all the parts found in the same assembly as the Program class catalog.Catalogs.Add(new AssemblyCatalog(typeof(Program).Assembly)); //Create the CompositionContainer with the parts in the catalog _container = new CompositionContainer(catalog); //Fill the imports of this object try { this._container.ComposeParts(this); } catch (CompositionException compositionException) { Console.WriteLine(compositionException.ToString()); } } public IModule FindModuleForView(Type view) { //THIS IS THE PROBLEM var module = from m in Modules where ( from p in m.Value.GetType().GetProperties() where p.GetType().Equals(view) select p ) select m; } public CompositionContainer _container { get; set; } } public interface IModule { } [Export] public class HomeModule : IModule { public HomeModule() { } [Export] public HomeView MyHomeView { get { return new HomeView(); } set { } } } public class HomeView : View { } public class View { }

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  • Need help with creating complex UITableView items (like the Settings app).

    - by Craig
    I hoping to create a custom Settings view, similar to the Settings application, but with more control over the UI and access to some settings (i need to lock some of the settings). Obvously, there are a variety of UI elements mixed in each row of application's UITableView. For example, the 'Airplane Mode' setting shows a UISwitch, while the 'Wi-Fi' setting has a text value adjacent to the disclosure symbol (''). Further complicating matters, is the grouping of these settings. I have some general questions about the approach I should take: Seems like i need to save the name of the setting, its current value, its grouping, and the type of UI element(s) needed to modify its value. i would like to make use [NSUserDefault standardUserDefaults], but not have these settings appear in the Settings application. I'm guessing that I will need to create my own settings-persistence class. is it better to build each one of these complex UI-element combinations in code or to create a series of custom views based on the UITableViewCell and load the appropriate one? i'm guessing the latter. some of the setting require that i load another view to select its value. assuming that the application is based on the Utility pattern, should the SettingsView manage the navigation stack, rather than having the app delegate do so? Thanks for your time and comments. Craig Buchanan

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  • undefined method `user_sessions_path' for #<ActionView::Base:0xdb3158>

    - by mrbernz
    I'm getting this error that's driving me up the wall. I don't see what's going on... I've followed instructions to the T and it's still complaining - help please!! I've got extracts of the error message, controller file, login page and routes file. Error message NoMethodError in User_sessions#new Showing app/views/user_sessions/new.html.erb where line #4 raised: undefined method `user_sessions_path' for # Extracted source (around line #4): 1: 2: User Login 3: 4: <% form_for @user_session do |f| % 5: <%= f.error_messages % 6: 7: controller/user_sessions_controller.rb class UserSessionsController < ApplicationController before_filter :require_no_user, :only = [:new, :create] before_filter :require_user, :only = :destroy def new @user_session = UserSession.new end def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_to root_url #redirect_back_or_default account_url else render :action = :new end end def destroy current_user_session.destroy flash[:notice] = "Logout successful!" redirect_to root_url #redirect_back_or_default account_url end end user_sessions/new.html.erb User Login <% form_for @user_session do |f| % <%= f.error_messages % <%= f.label :Email % <%= f.text_field :email % <%= f.label :Password % <%= f.password_field :password % <%= f.submit "Submit" % <% end % routes.rb file ActionController::Routing::Routes.draw do |map| map.login "login", :controller = "user_sessions", :action = "new" Am I look in in the wrong place??

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  • ASP.Net MVC 3 Full Name In DropDownList

    - by tgriffiths
    I am getting a bit confused with this and need a little help please. I am developing a ASP.Net MVC 3 Web application using Entity Framework 4.1. I have a DropDownList on one of my Razor Views, and I wish to display a list of Full Names, for example Tom Jones Michael Jackson James Brown In my Controller I retrieve a List of User Objects, then select the FirstName and LastName of each User, and pass the data to a SelectList. List<User> Requesters = _userService.GetAllUsersByTypeIDOrgID(46, user.organisationID.Value).ToList(); var RequesterNames = from r in Requesters let person = new { UserID = r.userID, FullName = new { r.firstName, r.lastName } } orderby person.FullName ascending select person; viewModel.RequestersList = new SelectList(RequesterNames, "UserID", "FullName"); return View(viewModel); In my Razor View I have the following @Html.DropDownListFor(model => model.requesterID, Model.RequestersList, "Select", new { @class = "inpt_a"}) @Html.ValidationMessageFor(model => model.requesterID) However, when I run the code I get the following error At least one object must implement IComparable. I feel as if I am going about this the wrong way, so could someone please help with this? Thanks.

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  • Subsonic - How to use SQL Schema / Owner name as part of the namespace?

    - by CResults
    Hi there, I've just started using Subsonic 2.2 and so far very impressed - think it'll save me some serious coding time. Before I dive into using it full time though there is something bugging me that I'd like to sort out. In my current database (a SQL2008 db) I have split the tables, views, sps etc. up into separate chunks by schema/owner name, so all the customer tables are in the customer. schema, products in the product. schema etc., so a to select from the customers address table i'd do a select * from customer.address Unfortunately, Subsonic ignores the schema/owner name and just gives me the base table name. This is fine as I've no duplicates between schemas (e.g Customer.Address and Supplier.Address don't both exist) but I just feel the code could be clearer if I could split by schema. Ideally I'd like to be able to alter the namespace by schema/owner - I think this would have least impact on SubSonic yet make the resulting code easier to read. Problem is, I've crawled all over the Subsonic source and don't have a clue how to do this (doesn't help that I code in VB not C# = yes I know, blame the ZX Spectrum!!) If anyone has tackled this before or has an idea on how to solve it, I'd be really grateful, Thanks in advance. Ed

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  • Django deployment - can't import app.urls

    - by hora
    I just moved a django project to a deployment server from my dev server, and I'm having some issues deploying it. My apache config is as follows: <Location "/"> Order allow,deny Allow from all SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE project.settings PythonDebug On PythonPath "['/home/django/'] + sys.path" </Location> Django does work, since it renders the Django debug views, but I get the following error: ImportError at / No module named app.urls And here is all the information Django gives me: Request Method: GET Request URL: http://myserver.com/ Django Version: 1.1.1 Python Version: 2.6.5 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'django.contrib.admindocs', 'project.app'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/usr/lib64/python2.6/site-packages/django/core/handlers/base.py" in get_response 83. request.path_info) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 218. sub_match = pattern.resolve(new_path) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 216. for pattern in self.url_patterns: File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_url_patterns 245. patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_urlconf_module 240. self._urlconf_module = import_module(self.urlconf_name) File "/usr/lib64/python2.6/site-packages/django/utils/importlib.py" in import_module 35. __import__(name) Exception Type: ImportError at / Exception Value: No module named app.urls Any ideas as to why I get an import error?

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  • Setting article properties for a publication using RMO in C# .NET

    - by Pavan Kumar
    I am using transaction replication with push subscription. I am developing a UI for replication using RMO in C#.NET between different instances of the same database within same machine holding similar schema and structure. I am using Single subscriber and multiple publisher topology. During creation of publication i want to set a few article properties such as Keep the existing object unchanged ,allow schema changes at subscriber to false a,copy foriegn key constarint and copy check constraints to true. How do i set the article properties using RMO in C# .NET. I am using Visual Studio 2008 SP1.I also want to know as how we can select all the objects including Tables,Views,Stored Procedures for publishing at one stretch. I could do it for one table but i want to select all the tables at one stretch. This is the code snippet i used for selecting single table for publishing. TransArticle ta = new TransArticle(); ta.Name = "Article_1"; ta.PublicationName = "TransReplication_DB2"; ta.DatabaseName = "DB2"; ta.SourceObjectName = "person"; ta.SourceObjectOwner = "dbo"; ta.ConnectionContext = conn; ta.Create();

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  • Render label for a field inside ASP.NET MVC 2 editor templates

    - by artvolk
    I'm starting to use DataAnnotations in ASP.NET MVC and strongly typed template helpers. Now I have this in my views (Snippet is my custom type, Created is DateTime): <tr> <td><%= Html.LabelFor(f => Model.Snippet.Created) %>:</td> <td><%= Html.EditorFor(f => Model.Snippet.Created)%></td> </tr> The editor template for DateTime is like this: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.DateTime>" %> <%=Html.TextBox("", Model.ToString("g"))%> But now I want to put inside editor template the whole <tr>, so I'd like to have just this in my view: <%= Html.EditorFor(f => Model.Snippet.Created)%> And something like this in editor template, but I don't know how to render for for label attribute, it should be Snippet_Created for my example, the same as id\name for textbox, so pseudo code: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.DateTime>" %> <tr> <td><label for="<What to place here???>"><%=ViewData.ModelMetadata.DisplayName %></label></td> <td><%=Html.TextBox("", Model.ToString("g"))%></td> </tr> The Html.TextBox() have the first parameter empty and id\name for textbox is generated corectly. Thanks in advance!

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  • PHP - CodeIgniter

    - by nXqd
    I try to write a site with CodeIgniter but I've a problem with PHP. I'm sure that it's so simple and can't be wrong. But I don't know bugs from , just a newbie of CodeIgniter :) <html> <head> <title><?=$page_title?></title> </head> <body> <?php foreach($result as $row):?> <h3><? echo $row->title; ?></h3> <p><? echo $row->text; ?></p> <?php endforeach;?> </body> </html> I've a bug from this file : A PHP Error was encountered Severity: Warning Message: Invalid argument supplied for foreach() Filename: views/helloworld_view.php Line Number: 6 thanks in advance for reading this :)

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  • Java errors on Lotus Domino Designer Client 8.5.1

    - by ajcooper
    I have a clean install of Lotus Notes 8.5.1 (now with FP3) and I'm getting the following errors in Designer. This is with a new database with a couple of forms and views. I'm finding this is typical across all databases. Is there something I need to install/configure etc.? I'm not new to Notes, but I'm new to 8.5 Thanks Aidan Description Resource Path Location Type Cannot resolve plug-in: org.eclipse.core.runtime plugin.xml TestAgent.nsf line 9 Plug-in Problem Cannot resolve plug-in: org.eclipse.ui plugin.xml TestAgent.nsf line 8 Plug-in Problem Cannot resolve plug-in: com.ibm.commons plugin.xml TestAgent.nsf line 10 Plug-in Problem Cannot resolve plug-in: com.ibm.commons.vfs plugin.xml TestAgent.nsf line 12 Plug-in Problem Cannot resolve plug-in: com.ibm.commons.xml plugin.xml TestAgent.nsf line 11 Plug-in Problem Cannot resolve plug-in: com.ibm.designer.runtime plugin.xml TestAgent.nsf line 15 Plug-in Problem Cannot resolve plug-in: com.ibm.designer.runtime.directory plugin.xml TestAgent.nsf line 14 Plug-in Problem Cannot resolve plug-in: com.ibm.jscript plugin.xml TestAgent.nsf line 13 Plug-in Problem Cannot resolve plug-in: com.ibm.notes.java.api plugin.xml TestAgent.nsf line 20 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.core plugin.xml TestAgent.nsf line 16 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.core plugin.xml TestAgent.nsf line 21 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.designer plugin.xml TestAgent.nsf line 18 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.designer plugin.xml TestAgent.nsf line 22 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.domino plugin.xml TestAgent.nsf line 19 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.domino plugin.xml TestAgent.nsf line 23 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.extsn plugin.xml TestAgent.nsf line 17 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.extsn plugin.xml TestAgent.nsf line 24 Plug-in Problem Cannot resolve plug-in: com.ibm.xsp.rcp plugin.xml TestAgent.nsf line 25 Plug-in Problem

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  • Templates vs. coded HTML

    - by Alan Harris-Reid
    I have a web-app consisting of some html forms for maintaining some tables (SQlite, with CherryPy for web-server stuff). First I did it entirely 'the Python way', and generated html strings via. code, with common headers, footers, etc. defined as functions in a separate module. I also like the idea of templates, so I tried Jinja2, which I find quite developer-friendly. In the beginning I thought templates were the way to go, but that was when pages were simple. Once .css and .js files were introduced (not necessarily in the same folder as the .html files), and an ever-increasing number of {{...}} variables and {%...%} commands were introduced, things started getting messy at design-time, even though they looked great at run-time. Things got even more difficult when I needed additional javascript in the or sections. As far as I can see, the main advantages of using templates are: Non-dynamic elements of page can easily be viewed in browser during design. Except for {} placeholders, html is kept separate from python code. If your company has a web-page designer, they can still design without knowing Python. while some disadvantages are: {{}} delimiters visible when viewed at design-time in browser Associated .css and .js files have to be in same folder to see effects in browser at design-time. Data, variables, lists, etc., must be prepared in advanced and either declared globally or passed as parameters to render() function. So - when to use 'hard-coded' HTML, and when to use templates? I am not sure of the best way to go, so I would be interested to hear other developers' views. TIA, Alan

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  • RedirectToAction and validate MVC 2

    - by Dan
    Hi, my problem is the View where the user typed, the validation. I have to take RedirectToAction on the site because on the site upload a file. Thats my code. My model class public class Person { [Required(ErrorMessage= "Please enter name")] public string name { get; set; } } My View <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcWebRole1.Models.Person>" %> Name <h2>Information Data</h2> <%= Html.ValidationSummary() %> <%using (Html.BeginForm ("upload","Home", FormMethod.Post, new{ enctype ="multipart/form-data" })) {%> <fieldset> <legend>Fields</legend> <p> <label for="name">name:</label> <%= Html.TextBox("name") %> <%= Html.ValidationMessage("name", "*") %> </p> </fieldset> <% } %> and the Controller [AcceptVerbs(HttpVerbs.Post)] public ActionResult upload(FormCollection form) { Person lastname = new Person(); lastname.name = form["name"]; return RedirectToAction("Index"); } Thx for answer my question In advance

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  • Ordering view by highest group count question - Ruby on Rails

    - by bgadoci
    I've read the couple of questions about this on stack overflow but can't seem to find the answer. I am trying to display the tags in my blog by the ones with the highest count in the tags table. Thanks to KandadaBoggu for helping me get the tags feature of the blog I am designing working. Here is the basics and my question. Tag belongs_to :post and Post has_many :tags. The tags table is simple really, consisting of the normal scaffolded fields plus post_id and tag_name (I actually called the column 'tag_name' instead of just 'name'). in my /views/posts/index.html/erb file I correctly am displaying the tags by group and the amount of times they are being used (appearing in the tags table). I just want to know how to order them by the highest count. Here is the code, and I currently have it set to updated_at: PostsController def index @tag_counts = Tag.count(:group => :tag_name, :order => 'updated_at DESC', :limit => 10) conditions, joins = {}, nil unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = :tags end @posts=Post.all(:joins => joins, :conditions=> conditions, :order => 'created_at DESC').paginate :page => params[:page], :per_page => 5 respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end

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  • iPhone Landscape FAQ and Solutions

    - by Johannes Rudolph
    There has been a lot of confusion and a set of corresponding set of questions here on SO how iPhone applications with proper handling for Landscape/Portrait mode autorotation can be implemented. It is especially difficult to implement such an application when starting in landscape mode is desired. The most common observed effect are scrambled layouts and areas of the screen where touches are no longer recognized. A simple search for questions tagged iphone and landscape reveals these issues, which occur under certain scenarios: Landscape only iPhone app with multiple nibs: App started in Landscape mode, view from first nib is rendered fine, everything view loaded from a different nib is not displayed correctly. Iphone Landscape mode switching to Portraite mode on loading new controller: Self explanatory iPhone: In landscape-only, after first addSubview, UITableViewController doesn’t rotate properly: Same issue as above. iPhone Landscape-Only Utility-Template Application: Layout errors, controller does not seem to recognize the view should be rotated but displays a clipped portrait view in landscape mode, causing half of the screen to stay blank. presentModalViewController in landscape after portrait viewController: Modal views are not correctly rendered either. A set of different solutions have been presented, some of them including completely custom animation via CoreGraphics, while others build on the observation that the first view controller loaded from the main nib is always displayed correct. I have spent a significant amount of time investigating this issue and finally found a solution that is not only a partial solution but should work under all these circumstances. It is my intend with this CW post to provide sort of a FAQ for others having issues with UIViewControllers in Landscape mode. Please provide feedback and help improve the quality of this Post by incorporating any related observations. Feel free to edit and post other/better answers if you know of any.

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  • Duplicate method 'ProcessRequest' in ASPX

    - by Mauricio Scheffer
    I'm trying to code ASP.NET MVC views (WebForms view engine) in F#. I can already write regular ASP.NET WebForms ASPX and it works ok, e.g. <%@ Page Language="F#" %> <% for i in 1..2 do %> <%=sprintf "%d" i %> so I assume I have everything in my web.config correctly set up. However, when I make the page inherit from ViewPage: <%@ Page Language="F#" Inherits="System.Web.Mvc.ViewPage" %> I get this error: Compiler Error Message: FS0442: Duplicate method. The abstract method 'ProcessRequest' has the same name and signature as an abstract method in an inherited type. The problem seems to be this piece of code generated by the F# CodeDom provider: [<System.Diagnostics.DebuggerNonUserCodeAttribute>] abstract ProcessRequest : System.Web.HttpContext -> unit [<System.Diagnostics.DebuggerNonUserCodeAttribute>] default this.ProcessRequest (context:System.Web.HttpContext) = let mutable context = context base.ProcessRequest(context) |> ignore when I change the Page directive to use C# instead, the generated code is: [System.Diagnostics.DebuggerNonUserCodeAttribute()] public new virtual void ProcessRequest(System.Web.HttpContext context) { base.ProcessRequest(context); } which of course works fine and AFAIK is not semantically the same as the generated F# code. I'm using .NET 4.0.30319.1 (RTM) and MVC 2 RTM

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  • Django - Override admin site's login form

    - by TrojanCentaur
    I'm currently trying to override the default form used in Django 1.4 when logging in to the admin site (my site uses an additional 'token' field required for users who opt in to Two Factor Authentication, and is mandatory for site staff). Django's default form does not support what I need. Currently, I've got a file in my templates/ directory called templates/admin/login.html, which seems to be correctly overriding the template used with the one I use throughout the rest of my site. The contents of the file are simply as below: # admin/login.html: {% extends "login.html" %} The actual login form is as below: # login.html: {% load url from future %}<!DOCTYPE html> <html> <head> <title>Please log in</title> </head> <body> <div id="loginform"> <form method="post" action="{% url 'id.views.auth' %}"> {% csrf_token %} <input type="hidden" name="next" value="{{ next }}" /> {{ form.username.label_tag }}<br/> {{ form.username }}<br/> {{ form.password.label_tag }}<br/> {{ form.password }}<br/> {{ form.token.label_tag }}<br/> {{ form.token }}<br/> <input type="submit" value="Log In" /> </form> </div> </body> </html> My issue is that the form provided works perfectly fine when accessed using my normal login URLs because I supply my own AuthenticationForm as the form to display, but through the Django Admin login route, Django likes to supply it's own form to this template and thus only the username and password fields render. Is there any way I can make this work, or is this something I am just better off 'hard coding' the HTML fields into the form for?

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  • DropDownListFor and relating my lambda to my ViewModel

    - by Daniel Harvey
    After googling for a while I'm still drawing a blank here. I'm trying to use a ViewModel to pull and provide a dictionary to a drop down list inside a strongly typed View: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="Notebook.ViewModels.CorporationJoinViewModel" %> ... <%: Html.DropDownListFor(c => c.CorpDictionary.Keys, new SelectList(Model.CorpDictionary, "Value", "Key"))%> I'm getting the error CS1061: 'object' does not contain a definition for 'CorpDictionary' and no extension method 'CorpDictionary' accepting a first argument of type 'object' could be found and the relevant bit of my ViewModel public class CorporationJoinViewModel { DB _db = new DB(); // data context public Dictionary<int, string> CorpDictionary { get { Dictionary<int, string> corporations = new Dictionary<int, string>(); int x = 0; foreach (Corporation corp in _db.Corporations) { corporations.Add(x, corp.name); } return corporations; } } I'll admit i have a pretty magical understanding of how linq is finding my ViewModel object from that lambda, and the error message is making me think it's not. Is my problem the method I'm using to pass the data? What am I missing here?

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  • SQL Server, how to join a table in a "rotated" format (returning columns instead of rows)?

    - by Joshua Carmody
    Sorry for the lame title, my descriptive skills are poor today. In a nutshell, I have a query similar to the following: SELECT P.LAST_NAME, P.FIRST_NAME, D.DEMO_GROUP FROM PERSON P JOIN PERSON_DEMOGRAPHIC PD ON PD.PERSON_ID = P.PERSON_ID JOIN DEMOGRAPHIC D ON D.DEMOGRAPHIC_ID = PD.DEMOGRAPHIC_ID This returns output like this: LAST_NAME FIRST_NAME DEMO_GROUP --------------------------------------------- Johnson Bob Male Smith Jane Female Smith Jane Teacher Beeblebrox Zaphod Male Beeblebrox Zaphod Alien Beeblebrox Zaphid Politician I would prefer the output be similar to the following: LAST_NAME FIRST_NAME Male Female Teacher Alien Politician --------------------------------------------------------------------------------------------------------- Johnson Bob 1 0 0 0 0 Smith Jane 0 1 1 0 0 Beeblebrox Zaphod 1 0 0 1 1 The number of rows in the DEMOGRAPHIC table varies, so I can't say with certainty how many columns I need. The query needs to be flexible. Yes, it would be trivial to do this in code. But this query is one piece of a complicated set of stored procedures, views, and reporting services, many of which are outside my sphere of influence. I need to produce this output inside the database to avoid breaking the system. Any ideas? This is MS SQL Server 2005, by the way. Thanks.

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