Search Results

Search found 8232 results on 330 pages for 'position'.

Page 239/330 | < Previous Page | 235 236 237 238 239 240 241 242 243 244 245 246  | Next Page >

• Unity has jerky motion when using Vector2.Lerp

  - by Sting Hà

  I made a 2D game with some sprite move to random position. I used Vector2.Lerp and Time.deltaTime to smooth transfer of sprite. When I build this game in iOS ( I used iPhone 4s and iPhone 5 for test ) all sprite made jerky motion and cause my game lagging. But in Android game run very smoothy. I used only 9 sprite and move all in same time. Can someone have any solution to fix this? Thanks. P/s: Sorry about my bad English.

  Read the article

• Bouncing a ball off a surface

  - by Sagekilla

  Hi all, I'm currently in the middle of writing a game like Breakout, and I was wondering how I could properly bounce a ball off a surface. I went with the naive way of rotating the velocity by 180 degrees, which was: [vx, vy] -> [-vy, vx] Which (unsurprisingly) didn't work so well. If I know the position and veocity of the ball, as well as the point the ball would hit (but is going to instead bounce off of) how can I bounce it off that point? I don't need any language specific code. If anyone could provide a small, mathematical formula on how to properly do this that would work fine for me. I also need this to work with integer positions and velocity (I can't use floating point anywhere). Thanks!

  Read the article

• Implementing zoom on a fixed point, javascript/canvas

  - by csiz

  I want to implement zooming on the mouse pointer with the mouse wheel. That is scaling the image while the point under the mouse pointer stays fixed. Here is my code, which doesn't work very well var scala = 1 + event.wheelDelta / 1000; canvas.context.translate(-canvas.mouse.x * ( scala - 1 ) / canvas.scale,-canvas.mouse.y * ( scala - 1 ) / canvas.scale); canvas.context.scale(scala,scala); canvas.scale *= scala; //canvas.scale is my variable that is initially set to 1. //canvas.mouse is my variable that represents the mouse position relative to the canvas

  Read the article

• jQuery FadeTo() bg on rollover, IMG animate().width height

  - by jg462095

  Hello all, I have been reading StackOverflow for a while and now I have a question I cannot find an answer to. i am trying to fade a background and increase on img size on rollover. I have tried animate() and fadeTo(), however, the entire div fades. Do I need to absolute position my images over the div and not within it? img or img? Is that the only way to get items within a div to not fade along with the background? Thanks! Jason

  Read the article

• How do I register a Javascript function to run with every postback?

  - by Kevin

  I have a treeview in a user control. I need to run a javascript function with every synch postback to scroll the div it's in to the right position. I've got it working, but I think there has to be a "cleaner" way to do it. In the Page_Load function of the control, I have the following code. Is there a better way to do it? ScriptManager.RegisterStartupScript(this.UpdatePanel1, this.GetType(), "key" + DateTime.Now.Ticks, "RestorePosition();", true);

  Read the article

• Scrollbar Problem

  - by Hitesh Gupta

  Hi All, There is a datagrid on my page which contains a lot of data. When i click on any row , the user is redirected to a page where he can edit the content of that row. But suppose I am at the bottom of page and then if I click on any row, the scrollbar of browser automatically shifts upwards which causes illusion for the user and make him confused if he has clicked on some other row. Is there any solution to this so that the position of scrollbar does not change after clicking on any data in datagrid. Thanks in advance.

  Read the article

• Finding the heaviest of N objects using M scales

  - by cpprulez

  We have N objects and M scales. It's up to us what the objects are, and we need to position the objects on the scales so that it is undoubtful which is the heaviest object. For example, if we have 3 objects: "a", "b", "c" and 2 scales, one possible solution is "a" "b", "b" = "c" (here "a" is the heaviest). I need an algorithm which generates such solutions given N and M. Also let's assume that "a" is always the heaviest object. I've lost a few hours figuring out how to do it, but no matter what I figure out, there's always cases which I miss. For example, another solution is: "a" + "c" = 2 * "b", "a" "c".

  Read the article

• Why does the right-shift operator produce a zero instead of a one?

  - by mrt181

  Hi, i am teaching myself java and i work through the exercises in Thinking in Java. On page 116, exercise 11, you should right-shift an integer through all its binary positions and display each position with Integer.toBinaryString. public static void main(String[] args) { int i = 8; System.out.println(Integer.toBinaryString(i)); int maxIterations = Integer.toBinaryString(i).length(); int j; for (j = 1; j < maxIterations; j++) { i >>= 1; System.out.println(Integer.toBinaryString(i)); } In the solution guide the output looks like this: 1000 1100 1110 1111 When i run this code i get this: 1000 100 10 1 What is going on here. Are the digits cut off? I am using jdk1.6.0_20 64bit. The book uses jdk1.5 32bit.

  Read the article

• Grid forms in Rails

  - by KandadaBoggu

  I am trying to create a grid form for a survey question. value1 value2 value3 option 1 x option 2 x option 3 x Each cell in the grid is a radio button and the radio buttons in a row belong to one radio button group. My models: class Question # title has_many :answers end class Answer # name, position, atype(row/col) end I am struggling to come up with a Rails approach for creating such a form. To complicate the issue user can save the semi-completed form and complete it at a later time. What is the best approach for this problem?

  Read the article

• memset on array of structures in C++

  - by garry

  I have another memset question. It appears as if the code I am editing may have some issues (or it's not done the same way in different files) A::LRM las[9]; //A and LRM are both structures with BOOLS and INTS memset(&las, 0, sizeof(las)); typedef Sec SecArray[16]; SecArray rad_array; memset(rad_array, 0, sizeof(SecArray)); The second example appears to be correct because rad_array is the same as the first position in the array. Then the sizeof(SecArray)) would make sense. The first one doesn't seem correct to me. All structs are just BOOLs and INTS nothing dynamic in them. My understanding from my other post about memset was that it followed this format. memset("pointer to object", "what to set it to", "size of object") Can anyone tell me what exactly is going on here if I am incorrect with my theory.

  Read the article

• how to set length and postion for repeat-x and scroll background-image?

  - by user550945

  Hi all, I have an to set background image. it is a red line under the input value. background-attachment:scroll; background-color:#FFFFFF; background-image:url("../images/errorLine.gif"); background-position:left bottom; background-repeat:repeat-x; the input value is like "123; 456; 789;". the red line cover all the string, its length is the same as the input width. Is there any way to make the red line only under the "456;"? Is there anyway to do it by CSS? Thanks a lot. Best regards, Ryanivanka

  Read the article

• jquery offset incorrect on floating elements

  - by LordZardeck

  I have a bunch of images each with the float: left property applied to them. They are constrained withing a 400px width area, forcing them into a grid of 4 X 4. If i try to get the position of them, they are always incorrect. What is causing this? You can see what I'm trying to do here: http://dev.redemptionconnect.com/cards/browse. Click one of the images to see what I mean. the dialog that pops up should be over the image you clicked.

  Read the article

• How do you calculate the offset to the client area in WPF?

  - by chris

  I want to position a modal dialog (progress window) at the top right corner of the parent window client area. This code will put it in the corner of the non-client area, but how do I calculate the offset to the client area? this.Owner=owner; this.Left=owner.Left+owner.ActualWidth-Width; this.Top=owner.Top; Edit: I found this 'solution' that works for normal windows: this.Left=owner.Left+owner.ActualWidth-Width-SystemParameters.ResizeFrameVerticalBorderWidth; this.Top=owner.Top+SystemParameters.ResizeFrameHorizontalBorderHeight+SystemParameters.WindowCaptionHeight; This would however fail for windows that have customized borders. EDIT: The code should work regardless of the systems DPI setting (e.g. 120 instead of 96).

  Read the article

• Help with WinAPI scroll bars

  - by user146780

  Right now I have a window with horizontal ad vertical scrollbars. I use these parameters to initialize it. //Set OGL Frame scroll bar SCROLLINFO inf; inf.cbSize = sizeof(SCROLLINFO); inf.fMask = SIF_PAGE | SIF_POS; inf.nPage = 20; inf.nPos = 30; It creates them in the center and I like their size, but when I scroll I multiply by 50 which creates chopiness. How could I add more resolution to the bars and still keep the same thumb size. Is there a way I can calculate the size and position of the bar based on the above parameters? Thanks

  Read the article

• How to get the url of the page which is currently loading i the iframe

  - by Gayathri

  Hi, I have an requirement that, in my application on clicking an button i have to laod one more application with the same template which i was using for my application. So, on clicking the button in my application i have used one intermediate page in that using iframe i passed that URL of an external application. Its working fine. But the problem is in the external applicatio which is not in my control on clicking an button it is moving to next page. In that page i want to hide an button. I did that also using div tag color as white and set the positions. But the problem is in all the pages in the same position that is affecting. So i want to get the url of the page which is loading in the iframe on the second or third click of an external application, so that i can using some conditions i can hide the control. So please any one help me to get the solution for this problem

  Read the article

• Why does the Scala compiler disallow overloaded methods with default arguments?

  - by soc

  While there might be valid cases where such method overloadings could become ambiguous, why does the compiler disallow code which is neither ambiguous at compile time nor at run time? Example: // This fails: def foo(a: String)(b: Int = 42) = a + b def foo(a: Int) (b: Int = 42) = a + b // This fails, too. Even if there is no position in the argument list, // where the types are the same. def foo(a: Int) (b: Int = 42) = a + b def foo(a: String)(b: String = "Foo") = a + b // This is OK: def foo(a: String)(b: Int) = a + b def foo(a: Int) (b: Int = 42) = a + b // Even this is OK. def foo(a: Int)(b: Int) = a + b def foo(a: Int)(b: String = "Foo") = a + b val bar = foo(42)_ // This complains obviously ... Are there any reasons why these restrictions can't be loosened a bit? Especially when converting heavily overloaded Java code to Scala default arguments are a very important and it isn't nice to find out after replacing plenty of Java methods by one Scala methods that the spec/compiler imposes arbitrary restrictions.

  Read the article

• MATLAB: Can axes tick labels be accesed as text objects?

  - by yuk

  I'm curious is it possible to change text properties of tick labels independently of axes properties. Do they have handles? I'd like to control their position better, alignment, color, fonts, etc. I know I can substitute them with text labels, but it has some drawbacks. Any alternative solutions? Particularly, is it possible to put xticklabels between ticks, that are irregular? plot(1:100) set(gca,'xtick',[30 45 53 70 95]) grid on I need to put xticklabels in the middle between grids.

  Read the article

• [Android] Pass variable/intent to an activity when launched from a Widget

  - by Pelly

  Hi, Currently within an activity in my application I can call another activity and pass a variable to it in the following manner: Intent myIntent = new Intent(parentView.getContext(), ShowStations.class); myIntent.putExtra("stationName", stations[position].StationName); startActivity(myIntent); This works fine, but now I want to be able to do the same from my Widget. Currently this code works fine for launching a specific activity from my widget: Intent WidgetIntent = new Intent(Intent.ACTION_MAIN).addCategory(Intent.CATEGORY_LAUNCHER).setComponent(new ComponentName("grell.com", "grell.com.FavStations")); PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, WidgetIntent, 0); updateViews.setOnClickPendingIntent(R.id.widget_main, pendingIntent); So now I am wondering how can I launch the same activity as shown in the first example but also pass through the 'stationName' variable. Any help would be greatly appreciated. Cheers

  Read the article

• Extending a view to the left side, animated

  - by Heinrich

  Hi, I have a view that I want to extend on the left side using an animation. All borders but the left one should remain the same, so the x position and the width of the view are changing. I use this code: [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:5.0]; self.frame = CGRectMake(self.frame.origin.x-100, self.frame.origin.y, self.frame.size.width+100, self.frame.size.height); [UIView commitAnimations]; If I run this code, the width of the view is set to the new value immediately and then the view is moved to the new x point, but why? How can I change this behaviour? Thanks for your ideas!

  Read the article

• How to find the number of inversions in an array ?

  - by Michael

  This is an phone interview question: "Find the number of inversions in an array". I guess they mean O(N*log N) solution since O(N^2) is trivial. I guess it cannot be better than O(N*log N) since sorting is O(N*log N) I have checked a similar question from SO and can summarize the answers as follows: Calculate half the distance the elements should be moved to sort the array : copy the array and sort the copy. For each element of the original array a[i] find it's position j in the sorted copy (binary search) and sum abs(i - j)/2. Modify merge sort : modify merge to count inversions between two sorted arrays (it takes O(N)) and run merge sort with the modified merge. Does it make sense ? Are there other (maybe simpler) solution ? Isn't it too hard for a phone interview ?

  Read the article

• ListView created programmatically - emptyView doesn't show

  - by Yorick

  I've created custom ListView programmatically, and set view to show when ListAdapter is empty but nothing shows on the screen in that case, what can be wrong? public PlayerList(Context context, Activity activity) { super(context); mParent = activity; setOnItemClickListener( new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { ... } }; List<PlayerInfo> players; players = getPlayerList(); // here size of players == 0 setAdapter(new PlayersAdapter(this.getContext(), R.id.player_name, players)); LayoutInflater vi = (LayoutInflater)mParent.getSystemService(Context.LAYOUT_INFLATER_SERVICE); emptyView = vi.inflate(R.layout.empty_view, null); // emptyView is View, and member of PlayerList this.setEmptyView(emptyView); }

  Read the article

• how to close layer that showed in other layer in cocos2d-iphone

  - by yegomo

  I have one layer called alayer, and there is a button called abutton, when click the button, another layer called blayer will show in alayer, not replaceScene, please look at the following code, alayer.m -(void)abuttonclicked:(id)sender { blayer *blayer = [blayer node]; blayer.position = ccp(1,1); [self addChild:blayer]; } blayer.m has a button called bbutton and string value called bstring, I want to click the b button, it will close blayer (remove blayer from alayer), and pass the string value bstring to alayer, please look at following code, -(void)bbuttonclicked:(id)sender { // how can do here to close its self(remove its self from alayer), and pass the bstring to alayer? } thanks. ps. I can use NSUserDefault to pass the string value, but I think it's a bad way to do this, is there another way to pass value?

  Read the article

• Text indent is not working in ie7

  - by saorabh

  I am working on a website and on the top navigation bar there is a search box, I applied the following css on the search submit button #submit{background:url("img/new-search-icon.png") no-repeat scroll -1px 0 #FFFFFF; border:0 none; cursor:pointer; display:block; height:21px; padding:0; position:absolute; right:0; text-indent:-9999px; top:0; width:20px; z-index:2;} My Problem is in IE7 the text indent is not working please help me if you want to see the demo you can view it by clicking here Click here. Please help me.

  Read the article

• jquery background image fade

  - by Nick

  I am using jQuery to load ina background image that fills the page width / height. I have the following in the Head: $(document).ready(function() { $('body').css({ 'background-image' : 'url({HTML_BASE}images/backgrounds/randoms/{BACK_IMG})', 'background-repeat' : 'no-repeat', 'background-position' : 'center top', 'background-attachment': 'fixed', 'background-size': '100% 100%', }); $('#home-promo').innerfade({ speed: 'slow', timeout: 5000, type: 'sequence', containerheight: 'auto' }); $('.model-search').innerfade({ speed: 'slow', timeout: 5000, type: 'sequence', containerheight: '393' }); }); This works fine and can be seen at http://projects.snowshtechnologies.com/golden_dragon/home/ I want the BG image to fade in from the black background colour. I have looked at a few other threads on Stack that suggest its not possible as a body element defined in css, but in this scenario the BG image is being loaded in by jQuery. How would I go about adding a fade in to this code to bring the image in with a nice fadein?

  Read the article

• getting code in new line

  - by Man Behind

  I have several divs one of which is as below <div id="drawarea"> <img class="draggable ui-droppable ui-draggable ui-draggable-dragging" id="image1" src="user_2/1323384165.jpg" style="height: 40%; width: 50%; position: absolute; left: 0%; top: 0%;"> <label id="first">This is content of the div</label> <input type="button" value="GO"/> </div> I am using jquerys below function to get the html inside the div and put in a text area html = $('#drawarea').html(); $('#codearea').text(html); the problem is that i am getting all the tags in same line i want to get one element code in one then others on other line so thats its easy to read.

  Read the article

< Previous Page | 235 236 237 238 239 240 241 242 243 244 245 246  | Next Page >