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  • How to sort NSMutableArray? Code review needed

    - by JAM
    Good evening. This code works. It sorts an array of cards by both Suit and Card Value. It is also very much brute force. Can you recommend a better way? Does Objective-C help dealing with a situation where object being sorted itself has multiple fields, on which sorting depends? -(void) sort: (NSMutableArray *) deck { NSUInteger count = [deck count]; Card *thisCard; Card *nextCard; int this; int next; BOOL stillSwapping = true; while (stillSwapping) { stillSwapping = false; for (NSUInteger i = 0; i < count; ++i) { this = i; next = i+1; if (next < count) { thisCard = [deck objectAtIndex:this]; nextCard = [deck objectAtIndex:next]; if ([thisCard suit] > [nextCard suit]) { [deck exchangeObjectAtIndex:this withObjectAtIndex:next]; stillSwapping = true; } if ([thisCard suit] == [nextCard suit]) { if ([thisCard value] > [nextCard value]) { [deck exchangeObjectAtIndex:this withObjectAtIndex:next]; stillSwapping = true; } } } } } }

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  • Sort List <Rectangle>

    - by user1649498
    How do I sort a rectangle list by their area? Been looking into IComparable at msdn library, but can't figure it out... I wrote this: SortedL= new List<Rectangle>(); int count1 = 0; int count3 = redovi; while (count1 < count3) { int count2 = 0; while (count2 < count3) { int x = Oblici[count1].Width; int y = Oblici[count1].Height; int z = Oblici[count2].Width; int w = Oblici[count2].Height; int area1 = x * y; int area2 = z * w; int a = area1.CompareTo(area2); if (a < 0) { count1 = count2; if (count2 < (count3 - 1)) { count2++; } else break; } else if (a == 0) { if (count2 < (count3 - 1)) { count2++; } else break; } else if (a > 0) { if (count2 < count3 - 1) { count2++; } else break; } } SortedL.Add(Oblici[count1]); Oblici.RemoveAt(count1); count3 = (count3 - 1);}} And it works, but it's pretty ugly, and I know there is an easier way...

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  • Sort wss3.0 view by more than 2 columns

    - by russellGove
    Does anyone know if it's possible to sort a sharepoint list view bymore than 3 columns. It doesn't let me do it in the UI and whwn I added this: > <Query> > <GroupBy Collapse="TRUE" GroupLimit="100"> > <FieldRef Name="Category" /> > <FieldRef Name="SubCategory" /> > <FieldRef Name="Topic" /> > </GroupBy> > <OrderBy> > <FieldRef Name="Category" /> > <FieldRef Name="SubCategory" /> > <FieldRef Name="Topic" /> > </OrderBy> > </Query> I get an error on the page: <!-- #RENDER FAILED -->

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  • bubble sort logic error

    - by Arianule
    I was trying a basic sorting exercise and I was hoping I could receive some help with what is probably a basic logic error. int[] numbers = new int[] { 2, 5, 11, 38, 24, 6, 9, 0, 83, 7 }; for (int loop = 0; loop < numbers.Length; loop++) { Console.WriteLine(numbers[loop]); } Console.WriteLine("Performing a bubble sort"); bool flag = false; do { for (int loop = 0; loop < numbers.Length - 1; loop++) { if (numbers[loop] > numbers[loop + 1]) { int temporary = numbers[loop]; numbers[loop] = numbers[loop + 1]; numbers[loop + 1] = temporary; flag = true; } } } while (flag == false); for (int loop = 0; loop < numbers.Length; loop++) { Console.WriteLine(numbers[loop]); } kind regards arianule

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  • PHP array ordering

    - by Melonheadjr44
    Hi, I was wondering how I could sort this array, when I use asort right now it does 14 17 16 15. How would I go to have 14 15 16 17 array(4) { [15]=> array(9) { [2025]=> string(80) "20:25 à 21:15 Spectacle / L'histoire d'un coeur / Auditorium, É.S.P. De La Salle" [2135]=> string(71) "21:35 à 22:25 Spectacle / Transfugue 2 / Auditorium, É.S.P. De La Salle" [1430]=> string(64) "14:30 à 15:30 Mise en lecture/Théâtre la Catapulte / De La Salle" [110]=> string(44) "11:00 à 13:00 Inscription / Pavillon Tabaret" [1330]=> string(49) "13:30 à 14:30 CÉRÉMONIE D'OUVERTURE / De La Salle" [1550]=> string(61) "15:50 à 16:40 Spectacle/Université Laurentienne / De La Salle" [170]=> string(57) "17:00 à 17:50 Spectacle/Université d'Ottawa / De La Salle" [1750]=> string(45) "17:50 à 19:00 REPAS DE L'AMITIÉ / De La Salle" [1915]=> string(76) "19:15 à 20:05 Spectacle / Attendre la pluie / Auditorium, É.S.P. De La Salle" } [16]=> array(8) { [1845]=> string(81) "18:45 à 19:35 Spectacle / Mimes d'horreur / Salle Académique, Université d'Ottawa" [1955]=> string(73) "19:55 à 20:45 Spectacle / Déroute / Salle Académique, Université d'Ottawa" [8]=> string(45) "08:30 à 11:30 Atelier / ABC du jeu dramatique" [13]=> string(41) "13:00 à 16:00 Atelier / Théâtre physique" [1130]=> string(28) "11:30 à 13:00 DÎNER LIBRE / " [1620]=> string(29) "16:20 à 18:20 SOUPER LIBRE / " [220]=> string(58) "22:00 à 23:30 BAL MASQUÉ / l'Agora du centre universitaire" [210]=> string(47) "21:00 à 22:00 Rétroaction / Université d'Ottawa" } [17]=> array(4) { [950]=> string(79) "09:50 à 10:40 Spectacle / Raison d'être / Salle Académique, Université d'Ottawa" [110]=> string(76) "11:00 à 11:50 Spectacle / Potionnée / Salle Académique, Université d'Ottawa" [120]=> string(28) "12:00 à 13:00 DÎNER LIBRE / " [1330]=> string(48) "13:30 à 14:30 CÉRÉMONIE DE CLÔTURE / De La Salle" } [14]=> array(1) { [150]=> string(49) "15:00 à 16:30 Préparation technique / De La Salle" } }

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  • quick java question

    - by j-unit-122
    private static char[] quicksort (char[] array , int left , int right) { if (left < right) { int p = partition(array , left, right); quicksort(array, left, p - 1 ); quicksort(array, p + 1 , right); } for (char i : array) System.out.print(i + ” ”); System.out.println(); return array; } private static int partition(char[] a, int left, int right) { char p = a[left]; int l = left + 1, r = right; while (l < r) { while (l < right && a[l] < p) l++; while (r > left && a[r] >= p) r--; if (l < r) { char temp = a[l]; a[l] = a[r]; a[r] = temp; } } a[left] = a[r]; a[r] = p; return r; } } hi guys just a quick question regarding the above coding, i know that the above coding returns the following B I G C O M P U T E R B C E G I M P U T O R B C E G I M P U T O R B C E G I M P U T O R B C E G I M P U T O R B C E G I M O P T U R B C E G I M O P R T U B C E G I M O P R T U B C E G I M O P R T U B C E G I M O P R T U B C E G I M O P R T U B C E G I M O P R T U B C E G I M O P R T U when the sequence BIGCOMPUTER is used but my question is can someone explain to me what is happening in the code and how? i know abit about the quick-sort algorithm but it doesnt seem to be the same in the above example.

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  • UCA + Natural Sorting

    - by Alix Axel
    I recently learnt that PHP already supports the Unicode Collation Algorithm via the intl extension: $array = array ( 'al', 'be', 'Alpha', 'Beta', 'Álpha', 'Àlpha', 'Älpha', '????', 'img10.png', 'img12.png', 'img1.png', 'img2.png', ); if (extension_loaded('intl') === true) { collator_asort(collator_create('root'), $array); } Array ( [0] => al [2] => Alpha [4] => Álpha [5] => Àlpha [6] => Älpha [1] => be [3] => Beta [11] => img1.png [9] => img10.png [8] => img12.png [10] => img2.png [7] => ???? ) As you can see this seems to work perfectly, even with mixed case strings! The only drawback I've encountered so far is that there is no support for natural sorting and I'm wondering what would be the best way to work around that, so that I can merge the best of the two worlds. I've tried to specify the Collator::SORT_NUMERIC sort flag but the result is way messier: collator_asort(collator_create('root'), $array, Collator::SORT_NUMERIC); Array ( [8] => img12.png [7] => ???? [9] => img10.png [10] => img2.png [11] => img1.png [6] => Älpha [5] => Àlpha [1] => be [2] => Alpha [3] => Beta [4] => Álpha [0] => al ) However, if I run the same test with only the img*.png values I get the ideal output: Array ( [3] => img1.png [2] => img2.png [1] => img10.png [0] => img12.png ) Can anyone think of a way to preserve the Unicode sorting while adding natural sorting capabilities?

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  • Sort array by two specifics values in PHP

    - by Roger
    The folks have already showed me how to sort an array by a specific value using usort and a fallback function in PHP. What if this specifc value doesn't exist and we have to use two values? in the example bellow the values [4] and [5]... In other words, I want to do this: order all objects numericaly by the fith value of each object from the highest to the lowest, and addicionally, for those objects that have the fifht value is empty (in the examplem '-'), order them by the fourth value. Array( [0] => Array( [0] => links-patrocinados [1] => adwords [2] => 0,5 [3] => R$92,34 [4] => 823000 [5] => 49500 ) [1] => Array( [0] => adwords [1] => google adwords como funciona [2] => 0,38 [3] => R$0,20 [4] => 480 [5] => 480 ) [2] => Array( [0] => links-patrocinados [1] => adword [2] => 0,39 [3] => R$58,77 [4] => 49500 [5] => 2900 ) [3] => Array( [0] => agencia [1] => agencias viagens espanholas [2] => - [3] => R$0,20 [4] => 58 [5] => - ) [4] => Array( [0] => agencia [1] => era agencia imobiliaria [2] => - [3] => R$0,20 [4] => 73 [5] => - ) )

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  • Double Linked List Insertion Sorting Bug

    - by house
    Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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  • How do I display a Wicket Datatable, sorted by a specific column by default?

    - by David
    Hello everyone! I have a question regarding Wicket's Datatable. I am currently using DataTable to display a few columns of data. My table is set up as follows: DataTable<Column> dataTable = new DataTable<Column>("columnsTable", columns, provider, maxRowsPerPage) { @Override protected Item<Column> newRowItem(String id, int index, IModel<Column> model) { return new OddEvenItem<Column>(id, index, model); } }; The columns look like so: columns[0] = new PropertyColumn<Column>(new Model<String>("Description"), "description", "description"); columns[1] = new PropertyColumn<Column>(new Model<String>("Logic"), "columnLogic"); columns[2] = new PropertyColumn<Column>(new Model<String>("Type"), "dataType", "dataType"); Here is my column data provider: public class ColumnSortableDataProvider extends SortableDataProvider<Column> { private static final long serialVersionUID = 1L; private List<Column> list = null; public ColumnSortableDataProvider(Table table) { this.list = Arrays.asList(table.getColumns().toArray(new Column[0])); } public ColumnSortableDataProvider(List<Column> list) { this.list = list; } @Override public Iterator<? extends Column> iterator(int first, int count) { /* first - first row of data count - minimum number of elements to retrieve So this method returns an iterator capable of iterating over {first, first+count} items */ Iterator<Column> iterator = null; try { if(getSort() != null) { Collections.sort(list, new Comparator<Column>() { private static final long serialVersionUID = 1L; @Override public int compare(Column c1, Column c2) { int result=1; PropertyModel<Comparable> model1= new PropertyModel<Comparable>(c1, getSort().getProperty()); PropertyModel<Comparable> model2= new PropertyModel<Comparable>(c2, getSort().getProperty()); if(model1.getObject() == null && model2.getObject() == null) result = 0; else if(model1.getObject() == null) result = 1; else if(model2.getObject() == null) result = -1; else result = ((Comparable)model1.getObject()).compareTo(model2.getObject()); result = getSort().isAscending() ? result : -result; return result; } }); } if (list.size() > (first+count)) iterator = list.subList(first, first+count).iterator(); else iterator = list.iterator(); } catch (Exception e) { e.printStackTrace(); } return iterator; } Sorting by clicking a column works perfectly, but I would like the table to initially be sorted, by default, by the Description column. I am at a loss to do this. If you need to see some other code, please let me know. Thank you in advance!!! - D

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  • Flex XMLListCollection sort on nested tags

    - by gauravgr8
    Hi all, I have a requirement of sorting the <ename> in the XML with in the branch. The XML goes like this: <company> <branch> <name>finance</name> <emp> <ename>rahul</ename> <phno>123456</phno> </emp> <emp> <ename>sunil</ename> <phno>123456</phno> </emp> <emp> <ename>akash</ename> <phno>123456</phno> </emp> <emp> <ename>alok</ename> <phno>123456</phno> </emp> </branch> <branch> <name>finance</name> <emp> <ename>sameer</ename> <phno>123456</phno> </emp> <emp> <ename>rahul</ename> <phno>123456</phno> </emp> <emp> <ename>anand</ename> <phno>123456</phno> </emp> <emp> <ename>sandeep</ename> <phno>123456</phno> </emp> </branch> </company> I tried it with taking XML in XMLList: var xl:XMLList = new XMLList(branch.ename) var xlc:XMLListCollection = new XMLListCollection(xl); then applied sort to the <ename>. I am able to get the sorted but XMLListCollection but the problem is I got the <ename> collection sorted but I need the sorted <ename> in the XML. I tried with deleting the the item in Collection then adding the sorted list but in that case the <name> is lost. Please help me out in sorting <ename> or is there any way to specify nested tags in SortField name? Thanks in advance.

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  • php sorting a seriously multidimensional array...

    - by BigDogsBarking
    I'm trying to sort a multidimensional object, and, after looking on php.net and around here, I get that I should write a function that I can then call via usort. I'm having some trouble with the syntax. I haven't ever written something this complicated before, and trying to figure it out feels like a mindbender... I'm working with the array posted at the end of this post. I want to filter out duplicate [n] values. But, and this is the tricky part for me, I want to keep the [n] value that has the smallest [d] value. So, if I have (and this example is simplified, the real array is at the end of this post): Array ( [7777] => Array ( [0] => Array ( [n] => '12345' [d] => 1 ) [1] => Array ( [n] => '67890' [d] => 4 ) ) [8888] => Array ( [2] => Array ( [n] => '12345' [d] => 10 ) [3] => Array ( [n] => '67890' [d] => 2 ) ) ) I want to filter out duplicate [n] values based on the [d] value, so that I wind up with this: Array ( [7777] => Array ( [0] => Array ( [n] => '12345' [d] => 1 ) ) [8888] => Array [3] => Array ( [n] => '67890' [d] => 2 ) ) ) I've tried writing different variations of the function cmp example posted on php.net, but I haven't been able to get any to work, and I think it's because I'm not altogether clear on how to traverse it using their example... I tried: function cmp($a, $b) { if($a['n'] == $b['n']) { if($a['d'] == $b['d']) { return 0; } } return ($a['n'] < $b['n']) ? -1 : 1; } But, that really did not work at all... Anyway, here's the real array I'm trying to work with... Help is greatly appreciated! Array ( [32112] => Array ( [0] => Array ( [n] => '02124' [d] => '0' ) [1] => Array ( [n] => '02124' [d] => '0.240101905123744' ) [2] => Array ( [n] => '11050' [d] => '0.441758632682761' ) [3] => Array ( [n] => '02186' [d] => '0.317514080260304' ) ) [43434] => Array ( [4] => Array ( [n] => '02124' [d] => '5.89936971664429e-05' ) [5] => Array ( [n] => '02124' [d] => '0.145859264792549' ) [6] => Array ( [n] => '11050' [d] => '0.327864593457739' ) [7] => Array ( [n] => '11050' [d] => '0.312135345168295' ) ) )

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  • sort surname in alphabet from file to file JAVA

    - by user577939
    hello all. I need some help. I have wrote this code and dont now how to sort surnames in alphabet from my file to other file. import java.io.; import java.util.; class Asmuo { String pavarde; String vardas; long buvLaikas; int atv1; int atv2; int atv3; } class Irasas { Asmuo duom; Irasas kitas; } class Sarasas { private Irasas p; Sarasas() { p = null; } Irasas itrauktiElementa(String pv, String v, long laikas, int d0, int d1, int d2) { String pvrd, vrd; int data0; int data1; int data2; long lks; lks = laikas; pvrd = pv; vrd = v; data0 = d0; data1 = d1; data2 = d2; Irasas r = new Irasas(); r.duom = new Asmuo(); uzpildymasDuomenimis(r, pvrd, vrd, lks, d0, d1, d2); r.kitas = p; p = r; return r; } void uzpildymasDuomenimis(Irasas r, String pv, String v, long laik, int d0, int d1, int d2) { r.duom.pavarde = pv; r.duom.vardas = v; r.duom.atv1 = d0; r.duom.buvLaikas = laik; r.duom.atv2 = d1; r.duom.atv3 = d2; } void spausdinti() { Irasas d = p; int i = 0; try { FileWriter fstream = new FileWriter("rez.txt"); BufferedWriter rez = new BufferedWriter(fstream); while (d != null) { System.out.println(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3); rez.write(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3 + "\n"); d = d.kitas; i++; } rez.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } } } public class Gyventojai { public static void main(String args[]) { Sarasas sar = new Sarasas(); Calendar atv = Calendar.getInstance(); Calendar isv = Calendar.getInstance(); try { FileInputStream fstream = new FileInputStream("duom.txt"); DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String eil; while ((eil = br.readLine()) != null) { String[] cells = eil.split(" "); String pvrd = cells[0]; String vrd = cells[1]; atv.set(Integer.parseInt(cells[2]), Integer.parseInt(cells[3]), Integer.parseInt(cells[4])); isv.set(Integer.parseInt(cells[5]), Integer.parseInt(cells[6]), Integer.parseInt(cells[7])); long laik = (isv.getTimeInMillis() - atv.getTimeInMillis()) / (24 * 60 * 60 * 1000); int d0 = Integer.parseInt(cells[2]); int d1 = Integer.parseInt(cells[3]); int d2 = Integer.parseInt(cells[4]); sar.itrauktiElementa(pvrd, vrd, laik, d0, d1, d2); } in.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } sar.spausdinti(); } }

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  • Oracle sort Solaris 11 pour les architectures SPARC et x86 et l'annonce comme le "premier OS Cloud"

    Oracle sort Solaris 11 pour les architectures SPARC et x86 Et l'annonce comme le "premier OS Cloud" Mise à jour du 10 novembre 2011 par Idelways Le grand chantier de Sun, puis d'Oracle Solaris 11 est enfin achevé. L'implémentation Unix au nom de code « Nevada » sort pour les architectures Sparc et x86 et s'annonce par ses créateurs comme « le premier OS Cloud ». Cette communication d'Oracle autour de Solaris 11 s'inscrit dans le sillage de son ado...

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  • Random sort list with LINQ and Entity Framework in vb.net

    - by Sander Versluys
    I've seen many examples in LINQ but i'm not able to reproduce the same result in vb.net. I have following code: Dim context As New MyModel.Entities() Dim rnd As New System.Random() Dim gardens As List(Of Tuin) = (From t In context.Gardens Where _ t.Approved = True And _ Not t.Famous = True _ Order By rnd.Next() _ Select t).ToList() But i receive an error when binding this list to a control. LINQ to Entities does not recognize the method 'Int32 Next()' method, and this method cannot be translated into a store expression. Any suggestion on how to get this to work?

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  • sort mysql query by filtered query

    - by kalpaitch
    I have two mysql queries: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc"; and $sql = "SELECT * FROM content ORDER BY lastUpdated desc"; The end result is to have all rows returned from a particular table 'content' but have those that match the variable $filter at the top. Is there either a single query that could combine these two or should I be using a JOIN?

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  • Sort list of items in Django

    - by mridang
    Hi Guys, I have a Django view called change_priority. I'm posting a request to this view with a commas separated list of values which is basically the order of the items in my model. The data looks like this: 1,4,11,31,2,4,7 I have a model called Items which has two values - id and priority. Upon getting this post request, how can I set the priority of the Item depending upon the list order. So my data in the db would look like. 1,1 4,2 11,3 31,4 2,5 4,6 7,7 Thanks guys.

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  • sort associative array in awk - help?

    - by Richard
    Hi all, I have an associative array in awk that gets populated like this... chr_count[$3]++ When I try to print my chr_counts I use this: for (i in chr_count) { print i,":",chr_count[i]; } But not surprisingly, the order of i is not sorted in any way. Is there an easy way to iterate over the sorted "keys" of chr_count?

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  • Sort data using DataView

    - by Kristina Fiedalan
    I have a DataGridView with column Remarks (Passed, Failed). For example, I want to show all the records Failed in the column Remarks using DataView, how do I do that? Thank you. Here's the code I'm working on: ds.Tables["Grades"].PrimaryKey = new DataColumn[] { ds.Tables["Grades"].Columns["StudentID"] }; DataRow dRow = ds.Tables["Students"].Rows.Find(txtSearch.Text); DataView dataView = new DataView(dt); dataView.RowFilter = "Remarks = " + txtSearch.Text; dgvReport.DataSource = dataView;

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  • Searchlogic cannot sort search result

    - by jaycode
    Imagine a code: search = Project.search( :title_or_description_or_child_name_or_child_age_or_inspiration_or_decorating_style_or_favorite_item_or_others_like_any => keys, :galleries_id_like_any => @g, :styles_id_like_any => @st, :tags_like_any => @t ) search.all returns the rows correctly. But search.descend_by_views returns nil. Is this gem buggy? What else should I use then?

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  • How to sort a list so that managers are always ahead of their subordinates

    - by James Black
    I am working on a project using Groovy, and I would like to take an array of employees, so that no manager follows their subordinates in the array. The reason being that I need to add people to a database and I would prefer not to do it in two passes. So, I basically have: <employees> <employee> <employeeid>12</employeeid> <manager>3</manager> </employee> <employee> <employeeid>1</employeeid> <manager></manager> </employee> <employee> <employeeid>3</employeeid> <manager>1</manager> </employee> </employees> So, it should be sorted as such: employeeid = 1 employeeid = 3 employeeid = 12 The first person should have a null for managers. I am thinking about a binary tree representation, but I expect it will be very unbalanced, and I am not certain the best way to do this using Groovy properly. Is there a way to do this that isn't going to involve using nested loops?

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  • PHP Sort Array based on values in another.....

    - by Fearghal
    Need some help regarding array sorting.... I have two arrays. The main one (where the key is the user id) : $user[31] = 'Tom' $user[43] = 'Jane' and another array with the order they should be displayed (where key is the order and value is the user id) : $order[1] = 43 $order[2] = 31 How can I apply the ordering to the main array using the ordering one? Thanks guys!

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  • Array Problem, need to sort via Keys

    - by sologhost
    Ok, not really sure how to do this. I have values that are being outputted from a SQL query like so: $row[0] = array('lid' => 1, 'llayout' => 1, 'lposition' => 1, 'mid' => 1, 'mlayout' => 1, 'mposition' => 0); $row[1] = array('lid' => 2, 'llayout' => 1, 'lposition' => 0, 'mid' => 2, 'mlayout' => 1, 'mposition' => 0); $row[2] = array('lid' => 2, 'llayout' => 1, 'lposition' => 0, 'mid' => 3, 'mlayout' => 1, 'mposition' => 1); $row[3] = array('lid' => 3, 'llayout' => 1, 'lposition' => 1, 'mid' => 4, 'mlayout' => 1, 'mposition' => 1); $row[4] = array('lid' => 4, 'llayout' => 1, 'lposition' => 2, 'mid' => 5, 'mlayout' => 1, 'mposition' => 0); etc. etc. Ok, so the best thing I can think of for this is to give lid and mid array keys and have it equal the mposition into an array within the while loop of query like so... $old[$row['lid']][$row['mid']] = $mposition; Now if I do this, I need to compare this array's keys with another array that I'll need to build based on a $_POST array[]. $new = array(); foreach($_POST as $id => $data) { // $id = column, but we still need to get each rows position... $id = str_replace('col_', '', $id); // now get the inner array... foreach($data as $pos => $idpos) $new[$id][$idpos] = $pos; } Ok, so now I have 2 arrays of info, 1 from the database, and another from the $_POST positions, I hope I got the array keys correct. Now I need to figure out which one's changed, comparing from the old to the new. And also, need to update the database with all of the new positions where new lid = the old lid, and the new mid = the old mid from each array. I'm sure I'll have to use array_key or array_key_intersect somehow, but not sure exactly how...??? Also, I don't think an UPDATE would be useful in a foreach loop, perhaps there's a way to do a CASE statement in the UPDATE query? Also, Am I going about this the right way? OR should I do it another way instead of using a muli-dimensional array for this.

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  • How to merge two tables based on common column and sort the results by date

    - by techiepark
    Hello friends, I have two mysql tables and i want to merge the results of these two tables based on the common column rev_id. The merged results should be sorted by the date of two tables. Please help me. CREATE TABLE `reply` ( `id` int(3) NOT NULL auto_increment, `name` varchar(25) NOT NULL default '', `member_id` varchar(45) NOT NULL, `rev_id` int(3) NOT NULL default '0', `description` text, `post_date` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `flag` char(2) NOT NULL default 'N', PRIMARY KEY (`id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM; CREATE TABLE `comment` ( `com_id` int(8) NOT NULL auto_increment, `rev_id` int(5) NOT NULL default '0', `member_id` varchar(50) NOT NULL, `comm_desc` text NOT NULL, `date_created` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, PRIMARY KEY (`com_id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM;

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