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  • Full-text indexing? You must read this

    - by Kyle Hatlestad
    For those of you who may have missed it, Peter Flies, Principal Technical Support Engineer for WebCenter Content, gave an excellent webcast on database searching and indexing in WebCenter Content.  It's available for replay along with a download of the slidedeck.  Look for the one titled 'WebCenter Content: Database Searching and Indexing'. One of the items he led with...and concluded with...was a recommendation on optimizing your search collection if you are using full-text searching with the Oracle database.  This can greatly improve your search performance.  And this would apply to both Oracle Text Search and DATABASE.FULLTEXT search methods.  Peter describes how a collection can become fragmented over time as content is added, updated, and deleted.  Just like you should defragment your hard drive from time to time to get your files placed on the disk in the most optimal way, you should do the same for the search collection. And optimizing the collection is just a simple procedure call that can be scheduled to be run automatically.   beginctx_ddl.optimize_index('FT_IDCTEXT1','FULL', parallel_degree =>'1');end; When I checked my own test instance, I found my collection had a row fragmentation of about 80% After running the optimization procedure, it went down to 0% The knowledgebase article On Index Fragmentation and Optimization When Using OracleTextSearch or DATABASE.FULLTEXT [ID 1087777.1] goes into detail on how to check your current index fragmentation, how to run the procedure, and then how to schedule the procedure to run automatically.  While the article mentions scheduling the job weekly, Peter says he now is recommending this be run daily, especially on more active systems. And just as a reminder, be sure to involve your DBA with your WebCenter Content implementation as you go to production and over time.  We recently had a customer complain of slow performance of the application when it was discovered the database was starving for memory.  So it's always helpful to keep a watchful eye on your database.

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  • SEO impact on subdomain for full name and obscure ccTLD

    - by Dan Christian
    There have been a few questions on subdomains and their impact on SEO, mostly in comparison to subfolders. The closest question I've found is this question but it still doesn't completely answer my query. I'm setting up a blog for 'Sam Smith'. It's imperative the SEO is based around his full name as he is a prominent blogger and his name is his value. All ccTLD variations of 'samsmith' (samsmith.com, samsmith.cc etc) are taken. However there has been the opportunity to register an obscure ccTLD for 'smith'. In regards to SEO value purely from the URL... 1) Will there be any negative SEO implications on searches for 'Sam Smith' when setting up the subdomain as 'sam.smith.' compared to a more regular 'samsmith.' domain? Will a search engine recognise the subdomain as the full name as oppose to just 'smith'? 2) Are there any negative SEO implications with an obscure ccTLD. For instance if Sam Smith was a prominent blogger in Canada with most of his audience based there, would there be any negative SEO if he had, for example, a .co ccTLD.

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  • SQL transaction log backups conflicting with full backups?

    - by BradC
    On our SQL servers (2000, 2005, and 2008), we run full backups once a day in the evening, and transaction log backups every 2 hrs. We haven't really worried about these two processes conflicting, but lately we've run into some of the following issues: On one server, the trans log backup occasionally blocks the full backup, and must be manually stopped before the full backup can complete We sometimes end up with a massively-sized trans log backup file (sometimes larger than the full backup!) that seems to occur at the same time the full backup is running. I found a reference that indicate that these are "not allowed" to run at the same time, whatever that means: SQL 2000 Books Online and SQL 2005 Books Online. I'm not sure whether that means that the server will simply prevent them from running simultaneously, or if we ought to be explicitly stopping the log backups while the full backups are running. So are there known conflicts/issues between these? Does the answer differ between SQL versions? Should I have the trans log backup job check to see if the full backup is running before it executes? (and how do I do that...?)

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  • Windows 8 doesn't automatically join Wi-Fi network if Ethernet connection is active

    - by Herb Caudill
    In Windows 7, my laptop would automatically join both an Ethernet network and the Wi-Fi network in my house (both going through the same router). In Windows 8, if the Ethernet connection is present, it doesn't join the Wi-Fi network at all. The reason I noticed this is that if Wi-Fi isn't active, I don't see my AirPlay speakers. My wireless printer is also unavailable until I manually connect to Wi-Fi. To recap: When I turn on my computer and it's connected to Ethernet, this is what my Network Connections control panel looks like: After I manually join my Wi-Fi network, it looks like this: I would prefer for it to join both networks automatically on startup, the way it did in Windows 7. Is there a way to make this happen?

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  • How do I mount a CIFS share via FSTAB and give full RW to Guest

    - by Kendor
    I want to create a Public folder that has full RW access. The problem with my configuration is that Windows users have no issues as guests (they can RW and Delete), my Ubuntu client can't do the same. We can only write and read, but not create or delete. Here is the my smb.conf from my server: [global] workgroup = WORKGROUP netbios name = FILESERVER server string = TurnKey FileServer os level = 20 security = user map to guest = Bad Password passdb backend = tdbsam null passwords = yes admin users = root encrypt passwords = true obey pam restrictions = yes pam password change = yes unix password sync = yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . add user script = /usr/sbin/useradd -m '%u' -g users -G users delete user script = /usr/sbin/userdel -r '%u' add group script = /usr/sbin/groupadd '%g' delete group script = /usr/sbin/groupdel '%g' add user to group script = /usr/sbin/usermod -G '%g' '%u' guest account = nobody syslog = 0 log file = /var/log/samba/samba.log max log size = 1000 wins support = yes dns proxy = no socket options = TCP_NODELAY panic action = /usr/share/samba/panic-action %d [homes] comment = Home Directory browseable = no read only = no valid users = %S [storage] create mask = 0777 directory mask = 0777 browseable = yes comment = Public Share writeable = yes public = yes path = /srv/storage The following FSTAB entry doesn't yield full R/W access to the share. //192.168.0.5/storage /media/myname/TK-Public/ cifs rw 0 0 This doesn't work either //192.168.0.5/storage /media/myname/TK-Public/ cifs rw,guest,iocharset=utf8,file_mode=0777,dir_mode=0777,noperm 0 0 Using the following location in Nemo/Nautilus w/o the Share being mounted does work: smb://192.168.0.5/storage/ Extra info. I just noticed that if I copy a file to the share after mounting, my Ubuntu client immediately make "nobody" be the owner, and the group "no group" has read and write, with everyone else as read-only. What am I doing wrong?

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  • Why is my disk full?

    - by Agmenor
    I installed Ubuntu 12.04 by doing a fresh install where there was previously Ubuntu 11.10. My computer warns me now that my disk is nearly full. After having run apt-get purge, run apt-get autoremove and emptied the Trash can, I still have this problem as shown by this screenshot of Gparted: The disk /dev/sda7 is indeed full. I ran the Disk Usage Analyzer (Baobab) and I am still not sure of what is happening: One of my hypothesis is that when installing Ubuntu 12.04, I didn't configure my disks well and the disk /dev/sda6 is not mounted well as /home. Is this the reason indeed? What should I do to verify this and then to get the things fixed? Here are a few additional details to answer the questions I received (thank you everybody): My home directory is not encrypted. The Backup utility (Déjà Dup) is not set for automatic backups. (I do it myself and manually.) After I mount /dev/sda6, the command df -h gives Filesystem Size Used Avail Use% Mounted on /dev/sda7 244G 221G 12G 96% / udev 3,9G 4,0K 3,9G 1% /dev tmpfs 1,6G 904K 1,6G 1% /run none 5,0M 0 5,0M 0% /run/lock none 3,9G 164K 3,9G 1% /run/shm /dev/sda6 653G 189G 433G 31% /media/8ec2fa69-039b-4c52-ab1b-034d785132a1 (sorry but formatting this into code does not work, for an unknown reason) Thanks to izx's post, I realized /dev/sda6 was not even mounted before. It contains all the documents I used to have when I was running Ubuntu 11.10.

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  • Nhibernate upgraded getting 'Antlr.Runtime.NoViableAltException' on outer join using *=

    - by user86431
    so we upgraded to newer Nhibernate and Fluent Nhibernate. now I' getting this exception: FailedNHibernate.Hql.Ast.ANTLR.QuerySyntaxException: Exception of type 'Antlr.Runtime.NoViableAltException' was thrown. near line 1, column 459 On this hql, which worked fine before the upgrade. SELECT s.StudId, s.StudLname, s.StudFname, s.StudMi, s.Ssn, s.Sex, s.Dob, et.EnrtypeId, et.Active, et.EnrId, sss.StaffLname, sss.StaffFname, sss.StaffMi,vas.CurrentAge FROM CIS3G.Jcdc.EO.StudentEO s , CIS3G.Jcdc.EO.EnrollmentEO e , CIS3G.Jcdc.EO.EnrollmentTypeEO et , CIS3G.Jcdc.EO.VwStaffStudentStaffEO sss, CIS3G.Jcdc.EO.VwAgeStudentEO vas WHERE ( e.EnrId = et.EnrId ) AND ( s.StudId = vas.StudId ) AND ( s.StudId = e.StudId ) AND ( et.EnrtypeId *= sss.EnrtypeId ) AND ( Isnull ( sss.StudStaffRoleCd , 1044 ) = 1044 ) AND ( s.StudId = 4000 ) Clearly it does nto like the *= syntax, I tried rewritign is as ansi sql outer join and no joy. Can anyone tell me what ineed to change the sql to so I can get the outer join to work correctly? Thanks, Eric-

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  • Multiple many-to-many JOINs in a single mysql query without Cartesian Product

    - by VWD
    At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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  • Referencing outer query's tables in a subquery

    - by soulmerge
    Is it possible to reference an outer query in a subquery with MySQL? I know there are some cases where this is possible: SELECT * FROM table t1 WHERE t1.date = ( SELECT MAX(date) FROM table t2 WHERE t2.id = t1.id)` ); But I'm wondering if something like this could work: SELECT u.username, c._postCount FROM User u INNER JOIN ( SELECT p.user, COUNT(*) AS _postCount FROM Posting p --# This is the reference I would need: WHERE p.user = u.id ) c ON c.user = u.id WHERE u.joinDate < '2009-10-10'; I know I could achieve the same using a GROUP BY or by pulling the outer WHERE clause into the sub-query, but I need this for automatic SQL generation and cannot use either alternative for various other reasons.

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  • SUM of column with Left Outer Join

    - by Matt
    I am trying to get the Count of all records that have at least on person who is authorized on the record. Basically, a Record can have more than one person associated with it. I want to return the count of Total Records, a count of total Authorized Records where at least 1 person is authorized, and a count of total NotAuthorized records where no person associated with record is authorized. It doesn't matter if one person is authorized per Record or if 3 people are authorized for that record, that should add 1 to the Authorized counter. The current query is incrementing Auth and Non auth for each person added per record rather, than one per record. If no people are assigned to the record that should also count towards Not Auth. SELECT Count(DISTINCT Record.RecordID) AS TotalRecords, SUM(CASE WHEN People.PersonLevel = 1 THEN 1 ELSE 0 END) AS Authorized, SUM(CASE WHEN People.PersonLevel <> 1 THEN 1 ELSE 0 END) AS NotAuthorized FROM Record LEFT OUTER JOIN RecordPeople ON Record.RecordID = RecordPeople.RecordID LEFT OUTER JOIN People ON RecordPeople.PersonID = People.PersonID

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  • SQL SELECT multiple INNER JOINs

    - by Noam Smadja
    The SELECT statement includes a reserved word or an argument name that is misspelled or missing, or the punctuation is incorrect its Access database.. i have a Library table, where Autnm Topic Size Cover Lang are foreign Keys each record is actually a book which has its properties such as author and stuff. i am not quite sure i am even using the correct JOIN.. quite new with "complex" SQL :) SELECT Library.Bknm_Hebrew, Library.Bknm_English, Library.Bknm_Russian, Library.Note, Library.ISBN, Library.Pages, Library.PUSD, Author.ID AS [AuthorID], Author.Author_hebrew AS [AuthorHebrew], Author.Author_English AS [AuthorEnglish], Author.Author_Russian AS [AuthorRussian], Topic.ID AS [TopicID], Topic.Topic_Hebrew AS [TopicHebrew], Topic.Topic_English AS [TopicEnglish], Topic.Topic_Russian AS [TopicRussian], Size.Size AS [Size], Cover.ID AS [TopicID], Cover.Cvrtyp_Hebrew AS [CoverHebrew], Cover.Cvrtyp_English AS [TopicEnglish], Cover.Cvrtyp_Russian AS [CoverRussian], Lang.ID AS [LangID], Lang.Lang_Hebrew AS [LangHebrew], Lang.Lang_English AS [LangEnglish], FROM Library INNER JOIN Author ON Library.Autnm = Author.ID INNER JOIN Topic ON Library.Topic = Topic.ID INNER JOIN Size ON Library.Size = Size.ID INNER JOIN Cover ON Library.Cover = Cover.ID INNER JOIN Lang ON Library.Lang = Lang.ID Thx in advance

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  • How to join this table?

    - by pamella
    ads table img90.imageshack.us/img90/6295/adsvo.png phones table img194.imageshack.us/img194/3713/phones.png cars table img35.imageshack.us/img35/1035/carsm.png i have 3 tables ads,cars and phones. i want to join tables is based on category in ads table. and i tried this query but no luck,any helps? SELECT * FROM `ads` JOIN `ads.category` ON `ads.id` = `ads.category.id` ** i cant add comment any of your post,but i want it to be automatic based on category in ads table. for example :- if in table have phones category,i will automatic join phones table then SELECT * FROM `ads` JOIN `phone` ON `ads.id` = `phone.id` if in table have cars category,i will automatic join cars table SELECT * FROM `ads` JOIN `cars` ON `ads.id` = `cars.id`

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  • How do I create a self referential association (self join) in a single class using ActiveRecord in Rails?

    - by Daniel Chang
    I am trying to create a self join table that represents a list of customers who can refer each other (perhaps to a product or a program). I am trying to limit my model to just one class, "Customer". The schema is: create_table "customers", force: true do |t| t.string "name" t.integer "referring_customer_id" t.datetime "created_at" t.datetime "updated_at" end add_index "customers", ["referring_customer_id"], name: "index_customers_on_referring_customer_id" My model is: class Customer < ActiveRecord::Base has_many :referrals, class_name: "Customer", foreign_key: "referring_customer_id", conditions: {:referring_customer_id => :id} belongs_to :referring_customer, class_name: "Customer", foreign_key: "referring_customer_id" end I have no problem accessing a customer's referring_customer: @customer.referring_customer.name ... returns the name of the customer that referred @customer. However, I keep getting an empty array when accessing referrals: @customer.referrals ... returns []. I ran binding.pry to see what SQL was being run, given a customer who has a "referer" and should have several referrals. This is the SQL being executed. Customer Load (0.3ms) SELECT "customers".* FROM "customers" WHERE "customers"."id" = ? ORDER BY "customers"."id" ASC LIMIT 1 [["id", 2]] Customer Exists (0.2ms) SELECT 1 AS one FROM "customers" WHERE "customers"."referring_customer_id" = ? AND "customers"."referring_customer_id" = 'id' LIMIT 1 [["referring_customer_id", 3]] I'm a bit lost and am unsure where my problem lies. I don't think my query is correct -- @customer.referrals should return an array of all the referrals, which are the customers who have @customer.id as their referring_customer_id.

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  • Slow queries in Rails- not sure if my indexes are being used.

    - by Max Williams
    I'm doing a quite complicated find with lots of includes, which rails is splitting into a sequence of discrete queries rather than do a single big join. The queries are really slow - my dataset isn't massive, with none of the tables having more than a few thousand records. I have indexed all of the fields which are examined in the queries but i'm worried that the indexes aren't helping for some reason: i installed a plugin called "query_reviewer" which looks at the queries used to build a page, and lists problems with them. This states that indexes AREN'T being used, and it features the results of calling 'explain' on the query, which lists various problems. Here's an example find call: Question.paginate(:all, {:page=>1, :include=>[:answers, :quizzes, :subject, {:taggings=>:tag}, {:gradings=>[:age_group, :difficulty]}], :conditions=>["((questions.subject_id = ?) or (questions.subject_id = ? and tags.name = ?))", "1", 19, "English"], :order=>"subjects.name, (gradings.difficulty_id is null), gradings.age_group_id, gradings.difficulty_id", :per_page=>30}) And here are the generated sql queries: SELECT DISTINCT `questions`.id FROM `questions` LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id AND `taggings`.taggable_type = 'Question' LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id LEFT OUTER JOIN `subjects` ON `subjects`.id = `questions`.subject_id LEFT OUTER JOIN `gradings` ON gradings.question_id = questions.id WHERE (((questions.subject_id = '1') or (questions.subject_id = 19 and tags.name = 'English'))) ORDER BY subjects.name, (gradings.difficulty_id is null), gradings.age_group_id, gradings.difficulty_id LIMIT 0, 30 SELECT `questions`.`id` AS t0_r0 <..etc...> FROM `questions` LEFT OUTER JOIN `answers` ON answers.question_id = questions.id LEFT OUTER JOIN `quiz_questions` ON (`questions`.`id` = `quiz_questions`.`question_id`) LEFT OUTER JOIN `quizzes` ON (`quizzes`.`id` = `quiz_questions`.`quiz_id`) LEFT OUTER JOIN `subjects` ON `subjects`.id = `questions`.subject_id LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id AND `taggings`.taggable_type = 'Question' LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id LEFT OUTER JOIN `gradings` ON gradings.question_id = questions.id LEFT OUTER JOIN `age_groups` ON `age_groups`.id = `gradings`.age_group_id LEFT OUTER JOIN `difficulties` ON `difficulties`.id = `gradings`.difficulty_id WHERE (((questions.subject_id = '1') or (questions.subject_id = 19 and tags.name = 'English'))) AND `questions`.id IN (602, 634, 666, 698, 730, 762, 613, 645, 677, 709, 741, 592, 624, 656, 688, 720, 752, 603, 635, 667, 699, 731, 763, 614, 646, 678, 710, 742, 593, 625) ORDER BY subjects.name, (gradings.difficulty_id is null), gradings.age_group_id, gradings.difficulty_id SELECT count(DISTINCT `questions`.id) AS count_all FROM `questions` LEFT OUTER JOIN `answers` ON answers.question_id = questions.id LEFT OUTER JOIN `quiz_questions` ON (`questions`.`id` = `quiz_questions`.`question_id`) LEFT OUTER JOIN `quizzes` ON (`quizzes`.`id` = `quiz_questions`.`quiz_id`) LEFT OUTER JOIN `subjects` ON `subjects`.id = `questions`.subject_id LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id AND `taggings`.taggable_type = 'Question' LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id LEFT OUTER JOIN `gradings` ON gradings.question_id = questions.id LEFT OUTER JOIN `age_groups` ON `age_groups`.id = `gradings`.age_group_id LEFT OUTER JOIN `difficulties` ON `difficulties`.id = `gradings`.difficulty_id WHERE (((questions.subject_id = '1') or (questions.subject_id = 19 and tags.name = 'English'))) Actually, looking at these all nicely formatted here, there's a crazy amount of joining going on here. This can't be optimal surely. Anyway, it looks like i have two questions. 1) I have an index on each of the ids and foreign key fields referred to here. The second of the above queries is the slowest, and calling explain on it (doing it directly in mysql) gives me the following: +----+-------------+----------------+--------+---------------------------------------------------------------------------------+-------------------------------------------------+---------+------------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+--------+---------------------------------------------------------------------------------+-------------------------------------------------+---------+------------------------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | questions | range | PRIMARY,index_questions_on_subject_id | PRIMARY | 4 | NULL | 30 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | answers | ref | index_answers_on_question_id | index_answers_on_question_id | 5 | millionaire_development.questions.id | 2 | | | 1 | SIMPLE | quiz_questions | ref | index_quiz_questions_on_question_id | index_quiz_questions_on_question_id | 5 | millionaire_development.questions.id | 1 | | | 1 | SIMPLE | quizzes | eq_ref | PRIMARY | PRIMARY | 4 | millionaire_development.quiz_questions.quiz_id | 1 | | | 1 | SIMPLE | subjects | eq_ref | PRIMARY | PRIMARY | 4 | millionaire_development.questions.subject_id | 1 | | | 1 | SIMPLE | taggings | ref | index_taggings_on_taggable_id_and_taggable_type,index_taggings_on_taggable_type | index_taggings_on_taggable_id_and_taggable_type | 263 | millionaire_development.questions.id,const | 1 | | | 1 | SIMPLE | tags | eq_ref | PRIMARY | PRIMARY | 4 | millionaire_development.taggings.tag_id | 1 | Using where | | 1 | SIMPLE | gradings | ref | index_gradings_on_question_id | index_gradings_on_question_id | 5 | millionaire_development.questions.id | 2 | | | 1 | SIMPLE | age_groups | eq_ref | PRIMARY | PRIMARY | 4 | millionaire_development.gradings.age_group_id | 1 | | | 1 | SIMPLE | difficulties | eq_ref | PRIMARY | PRIMARY | 4 | millionaire_development.gradings.difficulty_id | 1 | | +----+-------------+----------------+--------+---------------------------------------------------------------------------------+-------------------------------------------------+---------+------------------------------------------------+------+----------------------------------------------+ The query_reviewer plugin has this to say about it - it lists several problems: Table questions: Using temporary table, Long key length (263), Using filesort MySQL must do an extra pass to find out how to retrieve the rows in sorted order. To resolve the query, MySQL needs to create a temporary table to hold the result. The key used for the index was rather long, potentially affecting indices in memory 2) It looks like rails isn't splitting this find up in a very optimal way. Is it, do you think? Am i better off doing several find queries manually rather than one big combined one? Grateful for any advice, max

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  • Save a binary file in SQL Server as BLOB and text (or get the text from Full-Text index)

    - by Glennular
    Currently we are saving files (PDF, DOC) into the database as BLOB fields. I would like to be able to retrieve the raw text of the file to be able to manipulate it for hit-highlighting and other functions. Does anyone know of a simple way to either parse out the files and save the raw text on save, either via SQL or .net code. I have found that Adobe has a filtdump utility that will convert the PDF to text. Filtdump seems to be a command line tool, and i don't see a way to use a file stream. And what would the extractor be for Office documents and other file types? -or- Is there a way to pull out the raw text from the Full text index? Note i am trying to build a .net & MSSql solution without having to use a third party tool such as Lucene

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  • Is 'second' a keyword in mysql full-text searches?

    - by Larry
    I have a simple MySQL table that is setup for full text search. | id | title | ---------------------- | 1 | test event | | 2 | Second test | | 3 | Larry's event | | 4 | this second | When I use the query: SELECT * FROM EVENTS WHERE MATCH (title) AGAINST ('test event' IN BOOLEAN MODE); I get back 3 rows; the ones containing 'test event', 'Second test', and 'Larry's Event'. Now If I run the following query: SELECT * FROM EVENTS WHERE MATCH (title) AGAINST ('second' IN BOOLEAN MODE); Nothing is returned... strange? Lastly, if I run the query: SELECT * FROM EVENTS WHERE MATCH (title) AGAINST ('second test' IN BOOLEAN MODE); I get back 2 rows; the ones containing 'test event' and 'Second test'. I appears that the word 'second' cannot be searched or needs to be escaped somehow. Am I missing something?

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  • Unlock the Full Value of Oracle CRM On Demand

    - by charles.knapp
    Register for this live Oracle CRM On Demand Virtual Community Session! Oracle CRM On Demand delivers the most complete On Demand CRM available anywhere. But how can you ensure you are getting maximum value from the many powerful features that Oracle CRM On Demand offers? Join our interactive Oracle CRM On Demand Virtual Community Session on Tuesday, January 11, 2011 from 10.00-11 a.m. PT / 1 p.m.-2 p.m. ET to get expert advice and discuss the best ways to unlock the full potential of Oracle CRM Demand with Mike Lairson, author of 'Oracle CRM On Demand Reporting'. Book OfferSend your Oracle CRM On Demand configuration ideas before the Webcast to [email protected] and you could win a free copy of 'Oracle CRM On Demand Reporting' by Mike Lairson. Learn more and register now!

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  • Unlock the Full Value of Oracle CRM On Demand

    - by ruth.donohue
    Register for this live Oracle CRM On Demand Virtual Community Session! Oracle CRM On Demand delivers the most complete On Demand CRM solution on the market. But how can you ensure you are getting maximum value from the many powerful features that Oracle CRM On Demand offers? Join our interactive Oracle CRM On Demand Virtual Community Session on Tuesday, January 11, 2011 from 10.00-11 a.m. PT / 1 p.m.-2 p.m. ET to get expert advice and discuss the best ways to unlock the full potential of Oracle CRM Demand with Mike Lairson, author of 'Oracle CRM On Demand Reporting'. Book Offer Send your Oracle CRM On Demand configuration ideas before the Webcast to [email protected] and you could win a free copy of 'Oracle CRM On Demand Reporting' by Mike Lairson. Learn more and register now!

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  • Join us for Live Oracle Linux and Oracle VM Cloud Events in Europe

    - by Monica Kumar
    Join us for a series of live events and discover how Oracle VM and Oracle Linux offer an integrated and optimized infrastructure for quickly deploying a private cloud environment at lower cost. As one of the most widely deployed operating systems today, Oracle Linux delivers higher performance, better reliability, and stability, at a lower cost for your cloud environments. Oracle VM is an application-driven server virtualization solution fully integrated and certified with Oracle applications to deliver rapid application deployment and simplified management. With Oracle VM, you have peace of mind that the entire Oracle stack deployed is fully certified by Oracle. Register now for any of the upcoming events, and meet with Oracle experts to discuss how we can help in enabling your private cloud. Nov 20: Foundation for the Cloud: Oracle Linux and Oracle VM (Belgium) Nov 21: Oracle Linux & Oracle VM Enabling Private Cloud (Germany) Nov 28: Realize Substantial Savings and Increased Efficiency with Oracle Linux and Oracle VM (Luxembourg) Nov 29: Foundation for the Cloud: Oracle Linux and Oracle VM (Netherlands) Dec 5: MySQL Tech Tour, including Oracle Linux and Oracle VM (France) Hope to see you at one of these events!

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  • Join the Dark Side of Visual Studio 2010

    - by InfinitiesLoop
    Hard to believe it’s been so long, but it was almost 4 years ago when I published Join the Dark Side of Visual Studio . That was when a lot of people were still using VS2003, and importing and exporting environment settings required a custom add-in, VSStyler, which has since fallen off the planet and is hard to find (link, anyone? Let me know). Three versions of VS later, and I’m still using and loving the dark side. Pleased, I am (haha). In fact, that article for one reason or another is still one...(read more)

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by user797911
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more: Event Date: 24-JUN-11 Event Time: 08:00 am PST/PDT/4pm UK time Web Registration and Access: http://oukc.oracle.com/static09/opn/login/?t=livewebcast|c=1031672594 Access for Mobile Devices: http://my.oracle.com/content/web/cnt636926 Call Provider: Intercall International Participant Dial-In Number: 706-634-8508 Additional International Dial-In Numbers Link: http://www.intercall.com/national/oracleuniversity/gdnam.html Dial-In Passcode: 96395

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by mseika
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an ! entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more:24. Jun 2011 08:00 am PST/PDT/4pm UK timeWeb Registration and AccessAccess for Mobile DevicesInternational Participant Dial-In Number: 706-634-8508Additional International Dial-In Numbers LinkDial-In Passcode: 6395

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  • mysql join with multiple values in one column

    - by CYREX
    I need to make a query that creates 3 columns that come from 2 tables which have the following relations: TABLE 1 has Column ID that relates to TABLE 2 with column ID2 In TABLE 1 there is a column called user In TABLE 2 there is a column called names There can be 1 unique user but there can be many names associated to that user. If i do the following i get all data BUT the user column repeats itself for each name it has associated. What i want is for use to appear unique but the names columns appear with all the names associated to the user column but separated by commas, like the following: select user,names from TABLE1 left join TABLE2 on TABLE1.id = TABLE2.id This will show the users repeated everytime a name appears for that user. what i want is to appear like this: USER - NAMES cyrex - pedrox, rambo, zelda homeboy - carmen, carlos, tom, sandra jerry - seinfeld, christine ninja - soloboy etc....

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming January 19 & 20, 2010. In this webcast we'll bring you up to speed on the latest updates and changes made available these past few months. Additionally, we'll cover the new features and certifications in the latest ODC & ODDC 10.1.3.5.1 release, as well as the upcoming Enterprise Content Management Suite 11gR1 PS3 (patch set 3) release. Register Today! Americas / EMEA time zones: Customer Update January 19, 2010 9:00am US PT / 12:00pm US ET / 17:00 London Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) January 20, 2010 1:00pm Sydney AET, 10:00am Singapore (Jan 19, 2010 @ 6:00pm US PT) Length: 1 hour *Please use your corporate email address to register Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming June 30 / July 1 2010. Don't miss this chance to get an overview on the latest updates to Oracle Content Management. We'll be covering the latest ECM Suite 11g release - highlighting the Universal Content Management (UCM) and Universal Records Management releases. Register Today! Americas / EMEA time zones: Customer Update June 30, 2010 9:00am US PDT / 12:00pm US EDT / 16:00 GMT Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) July 1, 2010 12:00pm Sydney AEST, 10:00am Singapore (June 30, 2010 @ 7:00pm US PDT) Length: 1 hour *Please use your corporate email address to register Please Note: If you have attended previous Quarterly Customer Update Webcasts, we are now using a new web conference system, WebEx, to host the meeting. Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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