Search Results

Search found 2027 results on 82 pages for 'php5 gd'.

Page 24/82 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

  • php edit database entery script not working.

    - by Jacksta
    I have two files which show all contats in a database, then edits them. The second script keeps directing the browser back due to this part. I cant work out how to make it work! :) <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin_cantsayno", "cantsayno") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '$_POST[id]'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="id" value="<? echo "$_POST[id]"; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name" ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1" ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2" ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3" ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode" ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country" ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday" ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html>

    Read the article

  • Zend DB MYSQL Wrapper

    - by Vincent
    All, I have a PHP application written in Zend Framework with MVC style. I plan to use Zend_DB to connect to the MySQL database and process queries. I am looking for a wrapper class which makes it easy to use Zend_DB class. This wrapper class will have a constructor that connects to the Mysql db using Zend_DB. It will also have a method to return a singleton instance for each and every db connection made. Something like: $pptDB = PPTDB::getInstance(); $pptDB->setFetchMode(PPTDB::FETCH_OBJ); $result = $pptDB->fetchRow('SELECT * FROM bugs WHERE bug_id = 2'); echo $result->bug_description; Where class PPTDB extends Zend_DB Is this something feasible to have? If not, how ls would you use Zend_DB in a major application? Thanks,

    Read the article

  • CURL - https - solaris

    - by Vincent
    All, I am receiving the following error when I use PHP to curl to a https site. Both PHP and the https site are hosted on Solaris. This error seems to occur occassionally but frequently. error:80089077:lib(128):func(137):reason(119) This is the curl code I am using: $ch = curl_init(); $devnull = fopen('/tmp/cookie.txt', 'w'); curl_setopt($ch, CURLOPT_STDERR, $devnull); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_URL, $desturl); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT,800); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_ENCODING, 'gzip,deflate'); curl_setopt($ch, CURLOPT_POSTFIELDS, $postdata); $retVal = curl_exec($ch); print_r(curl_error($ch)); curl_close($ch); if ($devnull) { fclose($devnull); } How can I fix this error? If not, is there an alternative to curl?

    Read the article

  • SWIG generated code fails to run on PHP 5.3.2 undefined symbol: zend_error_noreturn

    - by wookiebreath
    I have a library that I have been using successfully with PHP 5.1.6 with the help of some wrapper code generated by SWIG (v1.3.40). I have just upgraded to PHP 5.3.2 and I am seeing the following error: PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/modules/myLib_php.so' - /usr/lib/php/modules/myLib_php.so: undefined symbol: zend_error_noreturn in Unknown on line 0 On investigation it appears that the wrapper code produced by SWIG (myLib_wrap.c) includes calls to the PHP function: zend_error_noreturn and that this function isn't available in PHP 5.3.2? Has anyone seen this issue before? Things seem to work if I manually update the generated code so that instead of calling zend_error_noreturn it just calls zend_error. Is this approach safe?

    Read the article

  • why this sql not working?

    - by user295189
    I have a query public static function TestQuery( $start=0, $limit=0){ $sql = " SELECT count(*) AS total FROM db.table1 JOIN db.table2 ON table1.fieldID = {$fieldID} AND table2.assigned = 'N'"; $qry = new SQLQuery; $qry-query($sql); if($row = $qry-fetchRow()){ $total = intval($row-total); } return $total; } which works fine but when I add the limit as below, then it doesnt work and gives me errors public static function TestQuery( $start=0, $limit=0){ $sql = " SELECT count(*) AS total FROM db.table1 JOIN db.table2 ON table1.fieldID = {$fieldID} AND table2.assigned = 'N'"; //this fails if($recordlimit 0) $sql .= "LIMIT {$startRecord}, {$recordLimit} "; // $qry = new SQLQuery; $qry-query($sql); if($row = $qry-fetchRow()){ $total = intval($row-total); } return $total; } Any help will be appreciated

    Read the article

  • how to use gettext in php?

    - by NeoNmaN
    i have a file dk.po and dk.mo ind folder lang in my webdir. how can i use this file? i have try all, but i can't relly get it to work. pls help me. // Lang putenv('LC_ALL=dk'); setlocale(LC_ALL, 'dk'); // Specify location of translation tables bindtextdomain("dk", ROOT .'lang'); // Choose domain textdomain("dk"); Tanks a lot.

    Read the article

  • php random array

    - by user295189
    I am trying to get a random array like this srand((float) microtime() * 10000000); $input = array("Neo", "Morpheus", "Trinity", "Cypher", "Tank"); $rand_keys = array_rand($input, 2); echo $input[$rand_keys[0]] . "\n"; echo $input[$rand_keys[1]] . "\n"; it shows 2 numbers randomly if I have $rand_keys = array_rand($input, 2);$rand_keys = array_rand($input, 5); but since I want all 5 to show it doesnt work. whats causing that. I need to use array_rand. thanks

    Read the article

  • Install PHP 5 without libxml2

    - by Mike Trpcic
    I am trying to install a copy of PHP 5 to my home directory on the school computer. The problem is that whenever I try, it complains that my copy of libxml2 is too outdated to work. Is there any way I can install this without upgrading libxml2, since I don't have permission to upgrade. Any suggestions?

    Read the article

  • Some instruction needed for PHP OOPS concepts.

    - by Avinash
    Hi, I need to clear some OOPS concepts in PHP. 1) Which is faster $this-method(); or self:method(); 2) I know the concept of static keyword but can you please post the actual Use of it. Since it can not be accessed by the instance, but is there ant benefit for that? 3) what is factory? How can i use it? 4) What is singleton? How can i use that? 5) What is late static binding? http://www.php.net/manual/en/oop5.intro.php I have gone through below link but I am not getting clear with it. Thanks Avinash

    Read the article

  • mysql query the latest date

    - by user295189
    I am running this query SEL ECT sh.*, u.initials AS initals FROM database1.table1 AS sh JOIN database2.user AS u ON u.userID = sh.userid WHERE id = 123456 AND dts = ( SELECT MAX(dts) from database1.table1 ) ORDER BY sort_by, category In the table1 I have records like this dts status category sort_by 2010-04-29 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:27 Civil Engineers Occupation 1 2010-04-28 12:20:54 Married Marital Status 2 2010-04-28 12:21:15 Smoker Tobbaco 3 2010-04-27 12:20:27 Civil Engineers Occupation 1 2010-04-27 12:20:54 Married Marital Status 2 2010-04-27 12:21:15 Smoker Tobbaco 3 2010-04-26 12:20:27 Civil Engineers Occupation 1 2010-04-26 12:20:54 Married Marital Status 2 2010-04-26 12:21:15 Smoker Tobbaco 3 so if you look at my data, I am choosing the latest entry by category and sort_id. however in some case such as on 29th (2010-04-29 12:20:27) I have only one record. So in this case I want to show occupation for latest and then the rest of them (latest). But currently it displays only one row. Thanks

    Read the article

  • PHP script works fine until I send a parameter from HTTPService in Flash Builder 4?

    - by ben
    I'm using a PHP script to read an RSS feed in my Flex 4 app. The script works when I put the url of the feed in the actual script, but I can't get it to work when I try to send the URL as a parameter from a HTTPService in Flex. Can anyone tell me what I'm doing wrong? Here is the HTTPService from Flex 4 that I'm using: <mx:HTTPService url="http://talk.6te.net/proxy.php" id="proxyService" method="POST" result="rssResult()" fault="rssFault()"> <mx:request> <url> http://feeds.feedburner.com/nah_right </url> </mx:request> </mx:HTTPService> This is the script that works: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, "http://feeds.feedburner.com/nah_right"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> But this is what I actually want to use, but it doesn't work: <?php $ch = curl_init(); $timeout = 30; $userAgent = $_SERVER['HTTP_USER_AGENT']; curl_setopt($ch, CURLOPT_URL, $_REQUEST['url']); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); $response = curl_exec($ch); if (curl_errno($ch)) { echo curl_error($ch); } else { curl_close($ch); echo $response; } ?> Here is the request and response output of the HTTPService from the network monitor in Flash Builder 4 (using the PHP script that doesn't work): Request: POST /proxy.php HTTP/1.1 Host: talk.6te.net User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Content-type: application/x-www-form-urlencoded Content-length: 97 url=%0A%09%09%09%09%09http%3A%2F%2Ffeeds%2Efeedburner%2Ecom%2Fnah%5Fright%0A%20%20%20%20%09%09%09 Response: HTTP/1.1 200 OK Date: Mon, 10 May 2010 03:23:27 GMT Server: Apache X-Powered-By: PHP/5.2.13 Content-Length: 15 Content-Type: text/html <url> malformed I've tried putting the URL in " " in the HTTPService, but that didn't do anything. Any help would be greatly appreciated!

    Read the article

  • Can I use this technique to provide free email service for my users?

    - by Naughty.Coder
    I'll let users register their [email protected] ,,, they enter their members area where they can : 1- send emails ( easy to do) 2- receive emails .. for receiving emails , I'll use a catch all email account , read the email and figure to whom it's sent (username), and then I save it on the database with userid of the username who has registerd ! Do I miss something here ... is it really this simple (if I don't have an email server) ?

    Read the article

  • Zend_Soap_Client - Ignore HTTPS verification

    - by Vincent
    All, I want to use Zend_Soap_Client class to load WSDL from an HTTPS url. Currently, if I call like this, it gives me an error even if the WSDL is perfectly valid: $wsdlUrl = "https://abc.xyz.com/webservices/WeatherService.php?wsdl"; $soapClient = new Zend_Soap_Client($wsdlUrl); The error I receive is: SOAP-ERROR: Parsing WSDL: Couldn't load from 'https://abc.xyz.com/webservices /WeatherService.php?wsdl' : Start tag expected, '<' not found If I browse to the WSDL url in the browser, it loads up the WSDL just fine. I think Zend_Soap_Client is trying to validate the certificate and failing. Is there a way to set the SOAP option to ignore the HTTPS verification and just load the WSDL? Thanks

    Read the article

  • Can I refresh a Yii CGridView from js?

    - by Brian Dunn
    When a "Create" modal dialog is submitted via XHR Then the rows in a Yii CGridView should be refreshed. I've tried to achieve this by rendering the new gridview in the XHR "create" action and then inserting it into the page via $("#list").html(response), but rendering a CGridView causes jQuery <script> include tags to be registered for inclusion, and so when I introduce those tags into the page they reload jQuery, which wipes out my live event handlers, so a bunch of stuff breaks. Which has me thinking, "the GridView knows how to refresh itself. heck, it does all the time on sort or page." So I can click a sort button in the GridView from js, but thats less than Ideal. I'd prefer to say $("#list").gridview('reload') or $.fn.gridview.reload("#list") or some such sense. Or do the way cool thing that is soo much simpler that you thought of just now.

    Read the article

  • Wordpress nav not visible in pages like articles, blog & search

    - by kwek-kwek
    My wordpress*(a custom template)* nav is all working on all of the pages but now I found out that the Main nav doesn't show on this pages All pages e.g. search.php, single.php, index.php, page.php all has <?php get_header(); ?> I really don't know whats wrong. Here is the code for my header.php <?php /** * @package WordPress * @subpackage Default_Theme */ ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" <?php language_attributes() ?>> <head> <meta http-equiv="Content-Type" content="<?php bloginfo('html_type'); ?>; charset=<?php bloginfo('charset'); ?>" /> <title><?php bloginfo('name'); ?> <?php wp_title(); ?></title> <link rel="stylesheet" href="<?php bloginfo('stylesheet_url'); ?>" type="text/css" media="screen,projection" /> <link rel="stylesheet" href="<?php bloginfo('template_url'); ?>/css/sifr.css" type="text/css" /> <script src="<?php bloginfo('template_url'); ?>/js/sifr.js" type="text/javascript"></script> <script src="<?php bloginfo('template_url'); ?>/js/sifr-config.js" type="text/javascript"></script> <script src="http://cdn.jquerytools.org/1.1.2/jquery.tools.min.js"></script> <?php wp_head(); ?> </head> <?php $current_page = $post->ID; $parent = 1; while($parent) { $page_query = $wpdb->get_row("SELECT post_name, post_parent FROM $wpdb->posts WHERE ID = '$current_page'"); $parent = $current_page = $page_query->post_parent; if(!$parent) $parent_name = $page_query->post_name; } ?> <body id="<?php echo (is_page()) ? "$parent_name" : ((is_home()) ? "blog" : ((is_search()) ? "other" : ((is_single()) ? "blog" : "blog"))); ?>"> <div id="BGtie"> <!--HEAD WRAPPER--> <div id="headwrapper"> <!--HEADER--> <div id="headContainer"> <div id="nameTag"> <a href="<?php echo get_option('home'); ?>/"><?php bloginfo('name'); ?></a> </div> <!--TOP NAV--> <div id="topNav"> <ul> <li><a href="<?php bloginfo('url'); ?>home">Home</a></li> <li><a href="#">Request info</a></li> <li><a href="#">Contact us</a></li> <?php do_action('icl_language_selector'); ?> </ul> </div> <!--END TOP NAV--> <!--MAIN NAV--> <?php if ( is_page() AND (strtolower(ICL_LANGUAGE_CODE) == 'fr') ) {include("main-nav-fr.php");} ?> <?php if (is_page() AND (strtolower(ICL_LANGUAGE_CODE) == 'en')) include("main-nav-en.php") ?> <!--END MAIN NAV--> </div> <!--END HEADER--> </div> <!--END HEAD WRAPPER--> </div>

    Read the article

  • Removing New line character in Fields PHP

    - by Aruna
    Hi, i am trying to upload an excel file and to store its contents in the Mysql database. i am having a problem in saving the contents.. like My csv file is in the form of "1","aruna","IEEE paper" "2","nisha","JOurnal magazine" actually i am having 2 records and i am using the code <?php $string = file_get_contents( $_FILES["file"]["tmp_name"] ); //echo $string; foreach ( explode( "\n", $string ) as $userString ) { echo $userString; } ? since in the Csv record there is a new line inserted in between IEEE and paper it is dispaying me as 3 records.. How to remove this new line code wise and to modify the code so that only the new line between the records 1 and 2 is considered... Pls help me....

    Read the article

  • foreach loop corrupting my array?

    - by WmasterJ
    Explanation I have a multidimensional array that is iterated over to created a categorized view of people with different research interests. The main array look something like this: Array ( ... ['Cell Biology'] => Array(4 elements) ['Molecular'] => Array(6 elements) ['Biology Education'] => Array(14 elements) ['Plant Biology'] => Array(19 elements) <--- Last element in array ) I know that the entire array is intact and correctly structured. The only information that is inside these array is an user id, like so: Array ('Plant Biology') 19 elements ( [0] => 737 [1] => 742 [2] => 748 ... ) My problem is that after i run the main array through a foreach loop the last 'sub-array' gets messed up. By messed up I mean that what you see about instead look like: String (13 characters) 'Plant Biology' This is without doing at all anything inside the loop with to the array that gets corrupted. Any tips to what it might be? PHP Code // ---> Array is OK here echo "<h2>Research divided</h2>"; // Loop areas and list them in 2 columns foreach($research['areas'] as $area => $areaArray) { // ---> Here it is already corrupted $count = count($areaArray); if($count > 0) { echo "<h3>$area</h3><hr/>"; echo "<table class='area_list'><tr>"; // Loop users within areas, divided up in 2 columns for($i=0 ; $i<$count ; $i++) { $uid = $areaArray[$i]; echo "<li>$uid</li>"; } echo "</tr></table>"; } }

    Read the article

  • HTML and PHP simple contact form.

    - by user317128
    I tried to make a simple contact form via HTML and PHP but the form doesnt seem to submit. it stays on the HTML page and doesnt post to the php form. would love someone to look over the code, thanks in advanced. simple_form.html cdoe <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form</title> </head> <body> <form action="send_simpleform.php" method="post"> <p>Your name<br /> <input name="sender_name" type="text" size="30" /></p> <p>Email<br /> <input name="sender_email" type="text" size="30" /></p> <p>Message<br /> <textarea name="message" cols="30" rows="5"></textarea></p> <input name="submit" type="button" value="Send This Form" /> </form> </body> </html> send_simpleform.php code <? if (($_POST[sender_name] == "") || ($_POST[sender_email] == "") || ($_POST[message] == "") { header("Location: simple_form.php"); exit; } $msg = "Email sent from wwwsite\n"; $msg .= "Sender's Name:\t $_POST[senders_name]\n"; $msg .= "Sender's E-mail:\t $_POST[senders_email]\n"; $msg .= "Sender's Message:\t $_POST[message]\n"; $to = "[email protected]"; $subject = "Website feedback message"; $mailheaders = "From: My web site <www.testwebsite.com>\n"; $mailherders .= "Reply to: $_POST[sender_email]\n"; $mail($to, $subject, $msg, $mailheaders); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form Sent</title> </head> <body> <h1>The following email has been sent</h1> <p>Your Name:<br /> <? echo "$_POST[sender_name]"; ?> <p>Your Email Adress:<br /> <? echo "$_POST[sender_email]"; ?> <p>Message:<br /> <? echo "$_POST[message]"; ?> </p> </body> </html>

    Read the article

  • MySQL & PHP Parameter 1 as Resource

    - by Nik
    Alright, PHP is throwing this error at me (in the log) when I run the code mentioned below: Error mysql_num_rows() expects parameter 1 to be resource, string given in (place) on line 10 Line 9-11 $queryFP = ("SELECT * FROM db"); $countFP = mysql_num_rows($queryFP); $aID = rand(1, $countFP); I think it has something to do with the $queryFP's syntax, but I'm not completely sure how to fix it since $queryFP's syntax is the simplest query I've ever seen.

    Read the article

  • Unable to login magento administration

    - by SIA
    Hi Everybody, I have just installed Magento on Windows using WAMP. Installation was successfull without any errors or warnings. When i browse administration page, i can see login screen. After entering the correct credentials it is not displaying me the Dashboard/Control Panel. Its displaying the same login page. If i enter wrong credentials, its authenticating and displaying a message as "invalid username or password" I am unable to determine the issue. If anybody has been through this issue and solved it please help me. How can i login Magento administration. Note: While installation i have selected session=Database. Will that be a issue? Kindly Advice, SIA

    Read the article

  • Create combined client side and server side validation in Symfony2

    - by ausi
    I think it would be very useful to create client side form validation up on the symfony2 Form and Validator components. The best way to do this would be to pass the validation constraints to the form view. With that information it would be possible to make a template that renders a form field to something like this: <div> <label for="form_email">E-Mail</label> <input id="form_email" type="text" name="form[email]" value="" data-validation-constraints='["NotBlank":{},"MinLength":{"limit":6}]' /> </div> The JavaScript part then would be to find all <input> elements that have the data-validation-constraints attribute and create the correct validation for them. To pass the validation constraints to the form view i thought the best way would be to create a form type extension. That's the point of my Question: Is this the correct way? And how is this possible? At the Moment my form type extension looks like this: use Symfony\Component\Form\FormInterface; use Symfony\Component\Form\FormView; use Symfony\Component\Form\FormBuilder; class FieldTypeExtension extends \Symfony\Component\Form\AbstractTypeExtension{ public function getExtendedType(){ return 'field'; } public function buildView(FormView $view, FormInterface $form) { // at this point i didn't find a way to get the // validation constraints out of the $form // the `getAllValidationConstraints` here is just an example $view->set('validation_constraints', $form->getAllValidationConstraints()); } } How can i get all validation constraints applied to one form field out of the FormInterface object?

    Read the article

  • How do I write a custom validator for a zend form element with customized error messages?

    - by Mallika Iyer
    I have a question field with a list of allowed characters : A-Z,0-9,colon (:), question mark (?), comma(,), hyphen(-), apostrophe ('). I have the regex which works fine, in the fashion : $question->addValidator('regex', true, array(<regular expresstion>)) The default error message is something like ''' does not match against pattern '' I want to write a custom error message that says ' is not allowed in this field' Is there a simple way to do it using the existing zend components that I'm missing? Is writing a custom validator the only way to achieve what I'm trying to achieve? If yes, how do I write a custom validator (I looked at the documentation and didn't quite understand how I can customize the error messages) If there is any other way, I'd most appreciate that input too. Thanks for taking the time to answer this!

    Read the article

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >