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  • nested for-each loops in xml

    - by user1748443
    I'm new to XML. I'm trying to create table containing item details and another table to contain customer details for each order on a picklist. It seems like it should be straightforward but I just get a list of all items on all orders repeated by the number of orders. What am I doing wrong? (XSL code below...) <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" doctype-system="about:legacy-compat"/> <xsl:template match="/"> <html xmlns = "http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8"/> <link rel="stylesheet" type="css/text" href="style.css"/> <title>Orders</title> </head> <body> <xsl:for-each select="//order"> <table> <caption><h3>Order Information</h3></caption> <thead> <th align="left">Item Id</th> <th align="left">Item Description</th> <th align="left">Quantity</th> <th align="left">Price</th> </thead> <xsl:for-each select="//item"> <tr> <td align="left"><xsl:value-of select="itemId"/></td> <td align="left"><xsl:value-of select="itemName"/></td> <td align="left"><xsl:value-of select="quantity"/></td> <td align="left"><xsl:value-of select="price"/></td> </tr> </xsl:for-each> </table> <table> <caption><h3>Customer Information</h3></caption> <thead> <th align="left">Customer Name</th> <th align="left">Street</th> <th align="left">City</th> </thead> <xsl:for-each select="//item"> <tr> <td align="left"><xsl:value-of select="customerName"/></td> <td align="left"><xsl:value-of select="street"/></td> <td align="left"><xsl:value-of select="city"/></td> </tr> </xsl:for-each> </table> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> This is the XML: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="Orders.xsl"?> <orders xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Orders.xsd"> <order> <orderId>123</orderId> <items> <item> <itemId>001</itemId> <itemName>Nylon Rope</itemName> <quantity>1</quantity> <price>3.50</price> </item> <item> <itemId>002</itemId> <itemName>Shovel</itemName> <quantity>1</quantity> <price>24.95</price> </item> </items> <customerAddress> <customerName>Larry Murphy</customerName> <street>Shallowgrave Lane</street> <city>Ballymore Eustace, Co. Kildare</city> </customerAddress> </order> <order> <orderId>124</orderId> <items> <item> <itemId>001</itemId> <itemName>Whiskey</itemName> <quantity>1</quantity> <price>18.50</price> </item> <item> <itemId>002</itemId> <itemName>Shotgun</itemName> <quantity>1</quantity> <price>225</price> </item> <item> <itemId>003</itemId> <itemName>Cartridge</itemName> <quantity>1</quantity> <price>1.85</price> </item> </items> <customerAddress> <customerName>Enda Kenny</customerName> <street>A Avenue</street> <city>Castlebar, Co. Mayo</city> </customerAddress> </order> </orders>

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  • Upon doing a XSL Transform to XML how do I remove white space from a Node's attribute or data?

    - by Randy
    I have a part's list built out in XML and each part is labeled as such: <division> <parts> <part number="123456 " drawing="123456 " cad="y"> <attribute> <header>Header</header> <list>2</list> </attribute> </part> And I need to get the data behind the number and drawing attributes without the white space. I tried xsl:strip-space on the specific elements, and across the board, but that only strips the content in between the tags. I unfortunately have no access to the back-end that's producing the XML, so removing the spaces there doesn't look like an option.

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  • Filtering most out of XML with XSL?

    - by Gnudiff
    I need to transform a lot of XML files (Fedora export) into a different kind of XML. Trying to do it with XSL stylesheets and checking with the msxsl transformer. Supposedly I have xml file like this (assuming there are actually other nodes inside AAA, OBJ, amd all other nodes), Source.XML: <DOC> <AAA> <STUFF>example</STUFF> <OBJ> <OBJVERS id="A1" CREATED="2008-02-18T13:28:08.245Z"/> <OBJVERS id="A2" CREATED="2008-02-19T10:42:41.965Z"/> <OBJVERS id="A13" CREATED="2009-03-16T12:43:11.703Z"/> </OBJ> </AAA> <FFF/> <GGG/> <DDD> <FILE /> </DDD> </DOC> Which I need to look something like this (Target.XML): <MYOBJ> <ELEM>contents of OBJVERS with the biggest id OR creation date (whichever is easier to do) go here</ELEM> <IMAGE> contents of <FILE> node go here</IMAGE> </MYOBJ> The main problem that I have is that since I am new to XSL (and for this particular task do not have enough time to learn it properly) is that I can't understand how to tell XSL processor not to process anything else, I keep getting output from , for example. Update: basically, I solved this problem meanwhile. I will post my own answer and close the question. Update2: OK, Andrew's answer works, too, so I am just accepting it. :)

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  • xsl : getting specific node values from a table

    - by prashant rao
    My XML Code <DBE:Attribute name="Test1" type="Table"> <DBE:Table> <DBE:TableHeader> <DBE:TableColumn>t1</DBE:TableColumn> <DBE:TableColumn>t2</DBE:TableColumn> <DBE:TableColumn>t3</DBE:TableColumn> <DBE:TableColumn>t4</DBE:TableColumn> <DBE:TableColumn>t5</DBE:TableColumn> <DBE:TableColumn>t6</DBE:TableColumn> <DBE:TableColumn>t7</DBE:TableColumn> <DBE:TableColumn>t8</DBE:TableColumn> <DBE:TableColumn>t9</DBE:TableColumn> <DBE:TableColumn>t10</DBE:TableColumn> <DBE:TableColumn>t11</DBE:TableColumn> <DBE:TableColumn>t12</DBE:TableColumn> <DBE:TableColumn>t13</DBE:TableColumn> </DBE:TableHeader> <DBE:TableRow> <DBE:TableData>0300 </DBE:TableData> <DBE:TableData/> <DBE:TableData>25</DBE:TableData> <DBE:TableData>25</DBE:TableData> <DBE:TableData>2009/09/03</DBE:TableData> <DBE:TableData/> <DBE:TableData>BAG</DBE:TableData> <DBE:TableData>rrr</DBE:TableData> <DBE:TableData>Yes</DBE:TableData> <DBE:TableData>12</DBE:TableData> <DBE:TableData>2009/03/09</DBE:TableData> <DBE:TableData>GO</DBE:TableData> <DBE:TableData/> </DBE:TableRow> </DBE:Table> </DBE:Attribute> I would like my output to be - t7 t5 t1 t13 --> Header --------------------------------------------------------------- BAG 2009/09/03 0300 GO --> ROW1 .............................................................. --> ROW2 and so on My XSL code -- (for only selected values to be displayed) <xsl:for-each select="DBE:Attribute[@name='Test1']/DBE:Table/DBE:TableRow"> <tr bgcolor="white"> <xsl:for-each select="DBE:TableData"> <td> <xsl:value-of select="node()|*"> </xsl:value-of> </td> </xsl:for-each> </tr> </xsl:for-each>

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  • MOSS ItemStyle.xsl parameter

    - by nav
    Hi, I am trying feed the site URL as a path into HTML rendered by the ItemStyle.xsl. Could anyone please give me some pointers? I need to know how I can extract the site URL from ItemStyle.xsl. Many Thanks, Nav

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  • How do I prevent duplicates, in XSL?

    - by LOlliffe
    How do I prevent duplicate entries into a list, and then ideally, sort that list? What I'm doing, is when information at one level is missing, taking the information from a level below it, to building the missing list, in the level above. Currently, I have XML similar to this: <c03 id="ref6488" level="file"> <did> <unittitle>Clinic Building</unittitle> <unitdate era="ce" calendar="gregorian">1947</unitdate> </did> <c04 id="ref34582" level="file"> <did> <container label="Box" type="Box">156</container> <container label="Folder" type="Folder">3</container> </did> </c04> <c04 id="ref6540" level="file"> <did> <container label="Box" type="Box">156</container> <unittitle>Contact prints</unittitle> </did> </c04> <c04 id="ref6606" level="file"> <did> <container label="Box" type="Box">154</container> <unittitle>Negatives</unittitle> </did> </c04> </c03> I then apply the following XSL: <xsl:template match="c03/did"> <xsl:choose> <xsl:when test="not(container)"> <did> <!-- If no c03 container item is found, look in the c04 level for one --> <xsl:if test="../c04/did/container"> <!-- If a c04 container item is found, use the info to build a c03 version --> <!-- Skip c03 container item, if still no c04 items found --> <container label="Box" type="Box"> <!-- Build container list --> <!-- Test for more than one item, and if so, list them, --> <!-- separated by commas and a space --> <xsl:for-each select="../c04/did"> <xsl:if test="position() &gt; 1">, </xsl:if> <xsl:value-of select="container"/> </xsl:for-each> </container> </did> </xsl:when> <!-- If there is a c03 container item(s), list it normally --> <xsl:otherwise> <xsl:copy-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> But I'm getting the "container" result of <container label="Box" type="Box">156, 156, 154</container> when what I want is <container label="Box" type="Box">154, 156</container> Below is the full result that I'm trying to get: <c03 id="ref6488" level="file"> <did> <container label="Box" type="Box">154, 156</container> <unittitle>Clinic Building</unittitle> <unitdate era="ce" calendar="gregorian">1947</unitdate> </did> <c04 id="ref34582" level="file"> <did> <container label="Box" type="Box">156</container> <container label="Folder" type="Folder">3</container> </did> </c04> <c04 id="ref6540" level="file"> <did> <container label="Box" type="Box">156</container> <unittitle>Contact prints</unittitle> </did> </c04> <c04 id="ref6606" level="file"> <did> <container label="Box" type="Box">154</container> <unittitle>Negatives</unittitle> </did> </c04> </c03> Thanks in advance for any help!

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  • move xsl sibling node inside parent?

    - by user288929
    How can I get from this: <Include xmlns="http://schemas.microsoft.com/wix/2006/wi"> <Component Feature="toplevel"> <File Id="fil8A88F8B155E29670FCA1B83F0E99E635" /> <TypeLib Id="{DC88F377-25DD-49C8-99D9-1FD8AE484362}" > <Interface Id="{5D12ED70-0B5A-49C4-A8A3-FC4C209295BA}" /> <Interface Id="{73E8EDB7-4293-496D-8ABD-F973F002A033}" /> </TypeLib> <TypeLib Id="{F3C9A192-17C2-4E25-ADB9-89FFEEC0403E}"> <Interface Id="{89FF44C6-979D-49B6-AF56-EC9509001DE4}" /> </TypeLib> </Component> </Include> to this: <Include xmlns="http://schemas.microsoft.com/wix/2006/wi"> <Component Feature="toplevel"> <File Id="fil8A88F8B155E29670FCA1B83F0E99E635" > <TypeLib Id="{DC88F377-25DD-49C8-99D9-1FD8AE484362}" > <Interface Id="{5D12ED70-0B5A-49C4-A8A3-FC4C209295BA}" /> <Interface Id="{73E8EDB7-4293-496D-8ABD-F973F002A033}" /> </TypeLib> <TypeLib Id="{F3C9A192-17C2-4E25-ADB9-89FFEEC0403E}"> <Interface Id="{89FF44C6-979D-49B6-AF56-EC9509001DE4}" /> </TypeLib> </File> </Component> </Include> (move <TypeLib>s inside <File>...) Thanks,

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  • XSL: Dead or not dead

    - by Seattle Leonard
    I'm currently taking on a new project at home. In this project I'm going to be generating HTML emails. For this purpose, I believe XSL to be a good candidate. However, I have heard people say that XSL is a dead language, and if it's not that it is on it's way out. In fact, MS has been very leary to support XSL 2.0. Personally I feel that any time you are going from text to text, it is a great tool. Such as: Generating HTML e-mails Creating Open Office Docs Generating another XML doc What are your thoughts? Is it dead, or is it still a viable, usefull tool?

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  • In xpath why can I use greater-than symbol > but not less-than <

    - by runrunraygun
    Using c#3 compiled transforms the following seems to work just fine... <xsl:choose> <xsl:when test="$valA > $valB"> <xsl:value-of select="$maxUnder" /> </xsl:when> <xsl:when test="$valA &lt; $valC"> <xsl:value-of select="$maxOver" /> </xsl:when> </xsl:choose> However if i dare use a < in place of &lt; it gives an error... <xsl:choose> <xsl:when test="$valA > $valB"> <xsl:value-of select="$maxUnder" /> </xsl:when> <xsl:when test="$valA < $valC"> <xsl:value-of select="$maxOver" /> </xsl:when> </xsl:choose> System.Xml.XmlException: '<', hexadecimal value 0x3C, is an invalid attribute character. So why is > ok and not < ?

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  • how to get child nodes in xsl

    - by ppp
    here my code- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="ArrayOfLinkEntity" name="bindLink"> <ul> <xsl:for-each select="LinkEntity[ParentLinkId=0]"> <li> <xsl:variable name="linkId" select="LinkId"/> <xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/> <xsl:value-of select="$child"/> <xsl:choose> <xsl:when test="($child &gt; 0)"> <a href="#" data-flexmenu="flexmenu1" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> <img src="../images/down.gif" border="0"/> </a> </xsl:when> <xsl:otherwise > <a href="#" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> </a> </xsl:otherwise> </xsl:choose> </li> </xsl:for-each> </ul> </xsl:template> </xsl:stylesheet> but I am getting $child=0 always.but there exists children. my xml structure- <ArrayOfLinkEntity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <LinkEntity> <EntityId>00000000-0000-0000-0000-000000000000</EntityId> <LinkId>1</LinkId> <SequenceNo>1</SequenceNo> <ParentLinkId>0</ParentLinkId> <LinkTitle>Home</LinkTitle> <SubLink /> </LinkEntity> ... </ArrayOfLinkEntity> What should I do? Please suggest.

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  • How to sort an XML file by date in XLST

    - by AdRock
    I am trying to sort by date and get an error message about the stylesheet can't be loaded I found an answer on how others have suggested but it doesn't work for me Here is where it is supposed to sort. The commented out line is where the sort should occur <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template name="hoo" match="/"> <html> <head> <title>Registered Festival Organisers and Festivals</title> <link rel="stylesheet" type="text/css" href="userfestival.css" /> </head> <body> <h1>Registered Festival Organisers and Festivals</h1> <xsl:for-each select="folktask/member"> <xsl:if test="user/account/userlevel='3'"> <!--<xsl:sort select="concat(substring(festival/event/datefrom,1,4),substring(festival/event/datefrom, 6,2),substring(festival/event/datefrom, 9,2))" data-type="number" order="ascending"/>--> Sample node from XML <festival id="1"> <event> <eventname>Oxford Folk Festival</eventname> <url>http://www.oxfordfolkfestival.com/</url> <datefrom>2010-04-07</datefrom> <dateto>2010-04-09</dateto> <location>Oxford</location> <eventpostcode>OX1 9BE</eventpostcode> <coords> <lat>51.735640</lat> <lng>-1.276136</lng> </coords> </event> </festival>

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  • Generate dynamic xmlns

    - by alexbf
    Hello, I would like to dynamically generate xmlns attributes. I want to generate this in XSL : <Common:MainPageBase xmlns:Common="clr-namespace:ThisPartIsDynamic;assembly=ThisPartIsDynamic" </Common:MainPageBase How can I do that in XSL? Thanks, Alex

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  • need help transforming an XML file, whose part of it is with escape sequences, into html

    - by shlomi
    hello, i need help transforming the following XML <?xml-stylesheet type=text/xsl href=XSL_17.xsl?> <Root> <Book> <Author>John smith</Author> <Genre>Novel</Genre> <Details>&lt;?xml version="1.0" encoding="utf-16"?&gt;&lt;Dets&gt;&lt;Ds&gt;&lt;D DN="Pages" DV="381" /&gt;&lt;D DN="Binding" DV="Hardcover" /&gt;&lt;D DN="Rate" DV="7.8" /&gt;&lt;/Ds&gt;&lt;/Dets&gt;</Details> </Book> <Car> <Year>2010</Year> <Name>Charger</Name> <Manufacturer>Dodge</Manufacturer> </Car> </Root> to the following HTML <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> </head> <body> <table> <tr> <td><strong>Book</strong></td> </tr> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Author</td> <td>John smith</td> </tr> <tr> <td>Genre</td> <td>Novel</td> </tr> <tr> <td>Details</td> <td> <table> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Pages</td> <td>381</td> </tr> <tr> <td>Binding</td> <td>Hardcover</td> </tr> <tr> <td>Rate</td> <td>7.8</td> </tr> </table> </td> </tr> </table> <table> <tr> <td><strong>Car</strong></td> </tr> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Year</td> <td>2010</td> </tr> <tr> <td>Name</td> <td>Charger</td> </tr> <tr> <td>Manufacturer</td> <td>Dodge</td> </tr> </table> </body> </html> i.e. i need to represent both normal XML and escaped XML in HTML tables.

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  • XSL: Get variable data without exslt:node-set

    - by Louis W
    Using native XSL lib in PHP. Is it possible to get a node value inside a variable without having to call it through exslt:node-set every time.... it long and ugly. <xsl:variable name="mydata"> <foo>1</foo> <bar>2</bar> </xsl:variable> <!-- How currently being done --> <xsl:value-of select="exslt:node-set($mydata)/foo" /> <!-- I want to be able to do this --> <xsl:value-of select="$mydata/foo" />

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  • DotNetNuke + XPath = Custom navigation menu DNNMenu HTML render

    - by Rui Santos
    I'm developing a skin for DotNetNuke 5 using the Component DNN Done Right menu by Mark Alan which uses XSL-T to convert the XML sitemap into an HTML navigation. The XML sitemap outputs the following structure: <Root > <root > <node id="40" text="Home" url="http://localhost/dnn/Home.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="0" > <node id="58" text="Child1" url="http://localhost/dnn/Home/Child1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="1" > <keywords >Child1</keywords> <description >Child1</description> <node id="59" text="Child1 SubItem1" url="http://localhost/dnn/Home/Child1/Child1SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child1 SubItem1</keywords> <description >Child1 SubItem1</description> </node> <node id="60" text="Child1 SubItem2" url="http://localhost/dnn/Home/Child1/Child1SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="0" only="0" depth="2" > <keywords >Child1 SubItem2</keywords> <description >Child1 SubItem2</description> </node> <node id="61" text="Child1 SubItem3" url="http://localhost/dnn/Home/Child1/Child1SubItem3.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child1 SubItem3</keywords> <description >Child1 SubItem3</description> </node> </node> <node id="65" text="Child2" url="http://localhost/dnn/Home/Child2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="1" > <keywords >Child2</keywords> <description >Child2</description> <node id="66" text="Child2 SubItem1" url="http://localhost/dnn/Home/Child2/Child2SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child2 SubItem1</keywords> <description >Child2 SubItem1</description> </node> <node id="67" text="Child2 SubItem2" url="http://localhost/dnn/Home/Child2/Child2SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child2 SubItem2</keywords> <description >Child2 SubItem2</description> </node> </node> </node> </root> </Root> My Goal is to render this XML block into this HTML Navigation structure only using UL's LI's, etc.. <ul id="topnav"> <li> <a href="#" class="home">Home</a> <!-- Parent Node - Depth0 --> <div class="sub"> <ul> <li><h2><a href="#">Child1</a></h2></li> <!-- Parent Node 1 - Depth1 --> <li><a href="#">Child1 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem2</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem3</a></li ><!-- ChildNode - Depth2 --> </ul> <ul> <li><h2><a href="#">Child2</a></h2></li> <!-- Parent Node 2 - Depth1 --> <li><a href="#">Child2 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child2 SubItem2</a></li> <!-- ChildNode - Depth2 --> </ul> </div> </li> </ul> Can anyone help with the XSL coding? I'm just starting now with XSL..

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  • DOCTYPE declaration getting lost when using XSL

    - by Rachel
    The input to my XSL is an XHTML. After applying the XSL the DOCTYPE declaration that was present in the input XHTML gets lost in the output. Do i have an option to copy/retain the DOCTYPE declaration in the output using XSL. The XSL processor that i am using is SAXON.

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  • Iteration, or copying in XSL, based on a count. How do I do it?

    - by LOlliffe
    I'm trying to create an inventory list (tab-delimited text, for the output) from XML data. The catch is, I need to take the line that I created, and list it multiple times (iterate ???), based on a number found in the XML. So, from the XML below: <?xml version="1.0" encoding="UTF-8"?> <library> <aisle label="AA"> <row>bb</row> <shelf>a</shelf> <books>4</books> </aisle> <aisle label="BB"> <row>cc</row> <shelf>d</shelf> <books>3</books> </aisle> </library> I need to take the value found in "books", and then copy the text line that number of times. The result looking like this: Aisle Row Shelf Titles AA bb a AA bb a AA bb a AA bb a BB cc d BB cc d BB cc d So that the inventory taker, can then write in the titles found on each shelf. I have the basic structure of my XSL, but I'm not sure how to do the "iteration" portion. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" xmlns:xd="http://www.oxygenxml.com/ns/doc/xsl" version="2.0"> <xsl:output omit-xml-declaration="yes"/> <xsl:variable name="tab" select="'&#09;'"/> <xsl:variable name="newline" select="'&#10;'"/> <xsl:template match="/"> <!-- Start Spreadsheet header --> <xsl:text>Aisle</xsl:text> <xsl:value-of select="$tab"/> <xsl:text>Row</xsl:text> <xsl:value-of select="$tab"/> <xsl:text>Shelf</xsl:text> <xsl:value-of select="$tab"/> <xsl:text>Titles</xsl:text> <xsl:value-of select="$newline"/> <!-- End spreadsheet header --> <!-- Start entering values from XML --> <xsl:for-each select="library/aisle"> <xsl:value-of select="@label"/> <xsl:value-of select="$tab"/> <xsl:value-of select="row"/> <xsl:value-of select="$tab"/> <xsl:value-of select="shelf"/> <xsl:value-of select="$tab"/> <xsl:value-of select="$tab"/> <xsl:value-of select="$newline"/> </xsl:for-each> <!-- End of values from XML --> <!-- Iteration of the above needed, based on count value in "books" --> </xsl:template> </xsl:stylesheet> Any help would be greatly appreciated. For starters, is "iteration" the right term to be using for this? Thanks!

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  • XSL transformation and special XML entities escaping

    - by Tomas R
    I have an XML file which is transformed with XSL. Some elements have to be changed, some have to be left as is - specifically, text with entities &quot;, &amp;, &apos;, &lt;, &gt; should be left as is, and in my case &quot; and &apos; are changed to " and ' accordingly. Test XML: <?xml version="1.0" encoding="UTF-8" ?> <root> <element> &quot; &amp; &apos; &lt; &gt; </element> </root> transformation file: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="UTF-8" omit-xml-declaration="no" indent="no" /> <xsl:template match="element"> <xsl:copy> <xsl:value-of disable-output-escaping="no" select="." /> </xsl:copy> </xsl:template> </xsl:stylesheet> result: <?xml version="1.0" encoding="UTF-8"?> <element> " &amp; ' &lt; &gt; </element> desired result: <?xml version="1.0" encoding="UTF-8"?> <element> &quot; &amp; &apos; &lt; &gt; </element> I have 2 questions: why does some of those entities are transformed and other not? how can I get a desired result?

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  • XSL Reuse? YES! But: Element must not contain an xsl:import element! :-(

    - by Fedor Steeman
    I am using a heavy stylesheet with a lot of recurring transformations, so I thought it would be smart to reuse the same chunks of code, so I would not need to make the same changes at a bunch of different places. So I discovered , but -alas- it won't allow me to do it. When trying to run it in Sonic Workbench I get the following error: An xsl:for-each element must not contain an xsl:import element This is my stylesheet code: <xsl:template match="/"> <InboundFargoMessage> <EdiSender> <xsl:value-of select="TransportInformationMessage/SenderId"/> </EdiSender> <EdiReceiver> <xsl:value-of select="TransportInformationMessage/RecipientId"/> </EdiReceiver> <EdiSource>PORLOGIS</EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <xsl:for-each select="TransportInformationMessage/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> <xsl:for-each select="TransportInformationMessage/Waybill/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> </Transportations> </InboundFargoMessage> </xsl:template> </xsl:stylesheet> I will leave out the child xsl-sheets for now, as the problem appears to be happening at the base. If I cannot use xsl:import, is there any option of reuse?

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  • Why does this XSL fails to retrieve value from xml ?

    - by Pavitar
    Following is an extract of the XSL stylesheet that I have written. It says my '.xsl' is well formed but it somehow does not retrieve values from the xml,instead jus pastes the header and table headings. EDIT <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:template match="/" > <html> <head> <title>GlenMark Pharma</title> </head> <h1 align="center"><font face="Monotype Corsiva" color="red">GlenMarkPharma</font></h1> <body> <table> <tbody> <tr> <th>ID</th> <th>ENAME</th> <th>Mobile</th> <th>EMAIL</th> <th>PWD</th> </tr> <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="name" /></td> <td><xsl:value-of select="mobile" /></td> <td><xsl:value-of select="email" /></td> <td><xsl:value-of select="pwd" /></td> </tr> </xsl:for-each> </tbody> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="MyfirstXsl.xsl"?> <!DOCTYPE employees SYSTEM "Mydtd.dtd"> <me:employees xmlns:me="[email protected]" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="[email protected] Mycomplex.xsd"> <me:employee empID="EMP101"> <me:name>Vicky</me:name> <me:mobile>9870582356</me:mobile> <me:email>[email protected]</me:email> <me:pwd>&defPWD;</me:pwd> </me:employee> </me:employees> I have also tried writing: <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="me:name" /></td> in the XSL since I have an alias to the namespace in my XML Doc.But it gives me an error of Invalid Pre-fix.I don't know what I'm doing wrong.

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