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  • Compressing and copying large files on Windows Server?

    - by Aaron
    I've been having a hard time copying large database backups from the database server to a test box at another site. I'm open to any ideas that would help me get this database moved without having to resort to a USB hard drive and the mail. The database server is running Windows Server 2003 R2 Enterprise, 16 GB of RAM and two quad-core 3.0 GHz Xeon X5450s. Files are SQL Server 2005 backup files between 100 GB and 250 GB. The pipe is not the fastest and SQL Server backup files typically compress down to 10-40% of the original, so it made sense to me to compress the files first. I've tried a number of methods, including: gzip 1.2.4 (UnxUtils) and 1.3.12 (GnuWin) bzip2 1.0.1 (UnxUtils) and 1.0.5 (Cygwin) WinRAR 3.90 7-Zip 4.65 (7za.exe) I've attempted to use WinRAR and 7-Zip options for splitting into multiple segments. 7za.exe has worked well for me for database backups on another server, which has ~50 GB backups. I've also tried splitting the .BAK file first with various utilities and compressing the resulting segments. No joy with that approach either- no matter the tool I've tried, it ends up butting against the size of the file. Especially frustrating is that I've transferred files of similar size on Unix boxes without problems using rsync+ssh. Installing an SSH server is not an option for the situation I'm in, unfortunately. For example, this is how 7-Zip dies: H:\dbatmp>7za.exe a -t7z -v250m -mx3 h:\dbatmp\zip\db-20100419_1228.7z h:\dbatmp\db-20100419_1228.bak 7-Zip (A) 4.65 Copyright (c) 1999-2009 Igor Pavlov 2009-02-03 Scanning Creating archive h:\dbatmp\zip\db-20100419_1228.7z Compressing db-20100419_1228.bak System error: Unspecified error

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  • Compressing and copying large files on Windows Server?

    - by Aaron
    I've been having a hard time copying large database backups from the database server to a test box at another site. I'm open to any ideas that would help me get this database moved without having to resort to a USB hard drive and the mail. The database server is running Windows Server 2003 R2 Enterprise, 16 GB of RAM and two quad-core 3.0 GHz Xeon X5450s. Files are SQL Server 2005 backup files between 100 GB and 250 GB. The pipe is not the fastest and SQL Server backup files typically compress down to 10-40% of the original, so it made sense to me to compress the files first. I've tried a number of methods, including: gzip 1.2.4 (UnxUtils) and 1.3.12 (GnuWin) bzip2 1.0.1 (UnxUtils) and 1.0.5 (Cygwin) WinRAR 3.90 7-Zip 4.65 (7za.exe) I've attempted to use WinRAR and 7-Zip options for splitting into multiple segments. 7za.exe has worked well for me for database backups on another server, which has ~50 GB backups. I've also tried splitting the .BAK file first with various utilities and compressing the resulting segments. No joy with that approach either- no matter the tool I've tried, it ends up butting against the size of the file. Especially frustrating is that I've transferred files of similar size on Unix boxes without problems using rsync+ssh. Installing an SSH server is not an option for the situation I'm in, unfortunately. For example, this is how 7-Zip dies: H:\dbatmp>7za.exe a -t7z -v250m -mx3 h:\dbatmp\zip\db-20100419_1228.7z h:\dbatmp\db-20100419_1228.bak 7-Zip (A) 4.65 Copyright (c) 1999-2009 Igor Pavlov 2009-02-03 Scanning Creating archive h:\dbatmp\zip\db-20100419_1228.7z Compressing db-20100419_1228.bak System error: Unspecified error

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  • Postgre varchar field between

    - by Anton
    I have an addresses table with ZIP code field which has type VARCHAR. I need to select all addresses form this table using ZIP codes range. If I used next code: select * from address where cast(zip as bigint) between 90210 and 90220 I get an error on fields where ZIP code cann't be cast as bigint. How I can resolve this issue?

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  • Using memorystream and DotNetZip in MVC gives "Cannot access a closed Stream"

    - by Frode Lillerud
    I'm trying to create a zipfile in a MVC method using the DotNetZip components. Here is my code: public FileResult DownloadImagefilesAsZip() { using (var memoryStream = new MemoryStream()) { using (var zip = new ZipFile()) { zip.AddDirectory(Server.MapPath("/Images/")); zip.Save(memoryStream); return File(memoryStream, "gzip", "images.zip"); } } } When I run it I get a "Cannot access a closed Stream" error, and I'm not sure why.

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  • How to remove a node based on contents of a subnode and then convert to CSV with headers intact

    - by Morris Cox
    I'm downloading a 10MB zipped XML file with wget, unzipping it to 40MB, trying to weed out test and expired entries (if the text of a certain node is "This is a test opportunity. Please DO NOT apply!" or if is in the past), and then convert to CSV. However, I get this error: PHP Notice: Array to string conversion in /home/morris/projects/grantsgov/xml2csv.php on line 46 I get Array errors because some entries in the XML file have more than one occurrence of a node (different text contents). The test entries are still present. Contents of grantsgov.sh: #!/bin/bash wget --clobber "http://www.grants.gov/search/downloadXML.do;jsessionid=1n7GNpNF2tKZnRGLyQqf7Tl32hFJ1zndhfQpLrJJD11TTNzWMwDy!368676377?fname=GrantsDBExtract$(date +'%Y%m%d').zip" -O GrantsDBExtract$(date +"%Y%m%d").zip unzip GrantsDBExtract$(date +"%Y%m%d").zip php xml2csv.php zip GrantsDBExtracted$(date +"%Y%m%d").zip GrantsDBExtracted$(date +"%Y%m%d").csv Contents of xml2csv.php: <? $current_date = date("Ymd"); //$getfile=fopen("http://www.grants.gov/search/downloadXML.do;jsessionid=GqJNNmdLyJyMlsQqTzS2KdzgT5NMdhPp0QhG946JTmHzRltNTpMQ!368676377?fname=GrantsDBExtract$current_date.zip", "r"); $zip = zip_open("GrantsDBExtract$current_date.zip"); if(is_resource($zip)) { while ($zip_entry = zip_read($zip)) { $fp = fopen("./".zip_entry_name($zip_entry), "w"); if (zip_entry_open($zip, $zip_entry, "r")) { $buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry)); fwrite($fp,"$buf"); zip_entry_close($zip_entry); fclose($fp); } } zip_close($zip); } // For future potential use $xml = new DOMDocument('1.0', 'ascii'); $xpath = new DOMXpath($xml); $xslFile = "feddata.xsl"; $filexml="GrantsDBExtract$current_date.xml"; if (file_exists($filexml)) { $xml = simplexml_load_file($filexml); echo "Loaded $filexml\n"; $xslt = new XSLTProcessor(); $xsl = new DOMDocument(); //$XSL->load('feddata.xsl', LIBXML_NOCDATA); $xsl->load($xslFile, LIBXML_NOCDATA); $xslt->importStylesheet($xsl); $xslt->transformToXML($xml); $f = fopen("GrantsDBExtracted$current_date.csv", 'w'); // create the CSV header row on the first time here $first = FALSE; $fields = array(); foreach($record as $key => $value) { $fields[] = $key; } fwrite($f,implode(";",$fields)."\n"); foreach ($xml->FundingOppSynopsis as $fos) { fputcsv($f, get_object_vars($fos),',','"'); } } fclose($f); } else { exit('Failed to open file.'); } ?> Contents of feddata.xsl: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml"/> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="FundingOppSynopsis[AgencyMailingAddress = 'This is a test opportunity. Please DO NOT apply!']"> </xsl:template> </xsl:stylesheet><xsl:strip-space elements="*"/> Part of the XML file: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE Grants SYSTEM "http://www.grants.gov/search/dtd/XMLExtract.dtd"> <Grants> <FundingOppSynopsis> <PostDate>08312007</PostDate> <UserID>None</UserID> <Password>None</Password> <FundingInstrumentType>CA</FundingInstrumentType> <FundingActivityCategory>DPR</FundingActivityCategory> <OtherCategoryExplanation>This is a test opportunity. Please DO NOT apply!</OtherCategoryExplanation> <NumberOfAwards>5</NumberOfAwards> <EstimatedFunding>4</EstimatedFunding> <AwardCeiling>2</AwardCeiling> <AwardFloor>1</AwardFloor> <AgencyMailingAddress>This is a test opportunity. Please DO NOT apply!</AgencyMailingAddress> <FundingOppTitle>This is a test opportunity. Please DO NOT apply!</FundingOppTitle> <FundingOppNumber>IVV-08312007-RG-OPP5</FundingOppNumber> <ApplicationsDueDate>09102007</ApplicationsDueDate> <ApplicationsDueDateExplanation>This is a test opportunity. Please DO NOT apply!</ApplicationsDueDateExplanation> <ArchiveDate>10102007</ArchiveDate> <Location>None</Location> <Office>None</Office> <Agency>None</Agency> <FundingOppDescription>This is a test opportunity. Please DO NOT apply!</FundingOppDescription> <CFDANumber>000000</CFDANumber> <EligibilityCategory>21</EligibilityCategory> <AdditionalEligibilityInfo>This is a test opportunity. Please DO NOT apply!</AdditionalEligibilityInfo> <CostSharing>N</CostSharing> <ObtainFundingOppText FundingOppURL="">Not Available</ObtainFundingOppText> <AgencyContact AgencyEmailDescriptor="This is a test opportunity. Please DO NOT apply!" AgencyEmailAddress="This is a test opportunity. Please DO NOT apply!">This is a test opportunity. Please DO NOT apply!</AgencyContact> </FundingOppSynopsis> How can I fix the error and remove expired entries (based on ArchiveDate)? I suspect the second to last line in feddata.xsl needs to be fixed.

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  • PHP matching a string

    - by John Jones
    Hi, I have an Indian company data set and need to extract the City and Zip from the address field: Address Field Example: Gowripuram West, Sengunthapuram Post, Near L.G.B., Karur, Tamilnadu, Karur - 639 002, India As you can see the City is Karur and the zip is followed after the - (hyphen). I need the PHP code to match [city] - [zip] Not sure how to do this I can find the Zip after the Hypen but not sure how to find the City, please note the City can be 2 words. Cheers for your time./ J

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  • Regular expression to retrieve everything before first slash

    - by alex
    I need a regular expression to basically get the first part of a string, before the first slash (). For example in the following: C:\MyFolder\MyFile.zip The part I need is "C:" Another example: somebucketname\MyFolder\MyFile.zip I would need "somebucketname" I also need a regular expression to retrieve the "right hand" part of it, so everything after the first slash (excluding the slash.) For example somebucketname\MyFolder\MyFile.zip would return MyFolder\MyFile.zip.

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  • How can I email someone a git repository?

    - by Zubair
    I have tried: git archive HEAD --format=zip > archive.zip :and then I email archive.zip and at the other end they unzip archive.zip into a folder. But when they try any git commands they find out that this does not produce a valid git repository

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  • Project Nashorn Slides & Talks

    - by $utils.escapeXML($entry.author)
    At the Eclipse Demo Camp in Hamburg last week I got asked about resources on Project Nashorn. So, I compiled a quick list:slides from Jim Laskey's JavaOne 2011 talk titled "The Future of JavaScript in the JDK".slides from Bernard Traversat's JavaOne 2011 talk titled "HTLM5 and Java: The Facts and the Myths".slides and video from Jim Laskey's JVM Language Simmit talk titled "Adventures in JSR 292 (Nashorn)".

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  • Squid not caching files (Randomly)

    - by Heinrich
    I want to use an intercepting squid server to cache specific large zip files that users in my network download frequently. I have configured squid on a gateway machine and caching is working for "static" zip files that are served from an Apache web server outside our network. The files that I want to have cached by squid are zip files 100MB which are served from a heroku-hosted Rails application. I set an ETag header (SHA hash of the zip file on the server) and Cache-Control: public header. However, these files are not cached by squid. This, for example, is a request that is not cached: $ curl --no-keepalive -v -o test.zip --header "X-Access-Key: 20767ed397afdea90601fda4513ceb042fe6ab4e51578da63d3bc9b024ed538a" --header "X-Customer: 5" "http://MY_APP.herokuapp.com/api/device/v1/media/download?version=latest" * Adding handle: conn: 0x7ffd4a804400 * Adding handle: send: 0 * Adding handle: recv: 0 ... > GET /api/device/v1/media/download?version=latest HTTP/1.1 > User-Agent: curl/7.30.0 > Host: MY_APP.herokuapp.com > Accept: */* > X-Access-Key: 20767ed397afdea90601fda4513ceb042fe6ab4e51578da63d3bc9b024ed538a > X-Customer: 5 > 0 0 0 0 0 0 0 0 --:--:-- 0:00:09 --:--:-- 0< HTTP/1.1 200 OK * Server Cowboy is not blacklisted < Server: Cowboy < Date: Mon, 18 Aug 2014 14:13:27 GMT < Status: 200 OK < X-Frame-Options: SAMEORIGIN < X-Xss-Protection: 1; mode=block < X-Content-Type-Options: nosniff < ETag: "95e888938c0d539b8dd74139beace67f" < Content-Disposition: attachment; filename="e7cce850ae728b81fe3f315d21a560af.zip" < Content-Transfer-Encoding: binary < Content-Length: 125727431 < Content-Type: application/zip < Cache-Control: public < X-Request-Id: 7ce6edb0-013a-4003-a331-94d2b8fae8ad < X-Runtime: 1.244251 < X-Cache: MISS from AAA.fritz.box < Via: 1.1 vegur, 1.1 AAA.fritz.box (squid/3.3.11) < Connection: keep-alive In the logs squid is reporting a TCP_MISS. This is the relevant excerpt from my squid file: # Squid normally listens to port 3128 http_port 3128 http_port 3129 intercept # Uncomment and adjust the following to add a disk cache directory. maximum_object_size 1000 MB maximum_object_size_in_memory 1000 MB cache_dir ufs /usr/local/var/cache/squid 10000 16 256 cache_mem 2000 MB # Leave coredumps in the first cache dir coredump_dir /usr/local/var/cache/squid cache_store_log daemon:/usr/local/var/logs/cache_store.log #refresh_pattern -i (/cgi-bin/|\?) 0 0% 0 refresh_pattern -i .(zip) 525600 100% 525600 override-expire ignore-no-cache ignore-no-store refresh_pattern . 0 20% 4320 ## DNS Configuration dns_nameservers 8.8.8.8 8.8.4.4 After trying around for some time I realized that squid is sometimes deciding that my file is cacheable, sometimes not, depending on whether and when I enable/disable the dns_nameservers directive. What could be wrong here?

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  • Security: Unable to display current owner

    - by Jim McKeeth
    I have a user with local administrative rights on their Windows 7 64-bit box. They extracted a file from a zip file they downloaded with the Zip shell extension to their desktop on a non-encrypted or compressed NTFS volume. Unfortunately they cannot open it. I tried to take ownership of it and it just reports "Access is Denied" and for the current owner it reports "Unable to display current owner." At this point the file cannot be deleted, executed or modified. I have actually seen this exact same happen in Vista before, but I can't for the life of me remember how to fix it. Any ideas how it happened or how to fix it? I'd be happy just to delete it without a format at this point.

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  • Friends Don’t Let Friends Play with Portal Guns [Video]

    - by Jason Fitzpatrick
    Many Portal fan films are sci-fi stories in their own right; this humorous video is simply focused on what happens when three guys get their hands on a portal gun. Jason Craft, the video’s director, explains: My interpretation of what a real POrtal gun would be like if one existed. Based on the video game, POrtal. I tried to match the game as close as possible. This was the most challenging project I have ever undertaken, consisting of 3D tracking, seamless camera cuts and 3D camera projection. ENJOY! We certainly wish our goofing around with friends videos came off this polished. For those of you wondering how he got such an awesome Portal Gun prop, it’s all CGI (you can check out his model here). [via Boing Boing] HTG Explains: What Is Windows RT & What Does It Mean To Me? HTG Explains: How Windows 8′s Secure Boot Feature Works & What It Means for Linux Hack Your Kindle for Easy Font Customization

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  • FREE Online Azure Workshop includes a **FREE Azure Account**

    - by Jim Duffy
    My friend and all around good guy, Microsoft Developer Evangelist for the Carolinas, Brian Hitney, along with fellow Microsofties Jim O’Neil and John McClelland will be presenting a FREE Windows Azure online workshop tomorrow, Tuesday, May 4th from 7pm-9pm. What? You can’t make it Tuesday evening? Not to worry. This webcast will be repeated again a number of times over the next month or so. Taken from Brian’s blog post about it: “Elevate your skills with Windows Azure in this hands-on workshop! In this event we’ll guide you through the process of building and deploying a large scale Azure application. Forget about “hello world”! In less than two hours we’ll build and deploy a real cloud app that leverages the Azure data center and helps make a difference in the world. Yes, in addition to building an application that will leave you with a rock-solid understanding of the Azure platform, the solution you deploy will contribute back to Stanford’s Folding@home distributed computing project. There’s no cost to you to participate in this session; each attendee will receive a temporary, self-expiring, full-access account to work with Azure for a period of 2-weeks.” Did you catch that last sentence??  “each attendee will receive a temporary, self-expiring, full-access account to work with Azure for a period of 2-weeks.” A FREE, full-access, Windows Azure account to experiment and learn with? Now we’re talking. For more information check out Brian’s blog post or head here. Have a day. :-|

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  • hdmi AC-3 audio broke after upgrading from 11.10 to 12.04.3

    - by Jim LastName
    I just updated my MythBuntu 11.10 to 12.04.3. Now, when I try to play 5.1 content (ripped DVD), my TV (and receiver) plays a "chattering" sound. I check my receiver and the digital dolby light isn't on--it's in PCM mode. So, either the audio is getting sent as AC-3, but the TV and receiver think it's PCM or the AC-3 audio got converted to multichannel PCM and they can't handle it. My setup: hdmi cable from htpc to TV. TV has an s/pdif output to my receiver. I know TV sends AC-3 audio out correctly because I see digital dolby light come on when I view a digital TV channel and PCM come on when I view an old analog channel. I can connect s/pdif from my htpc to my receiver and the digital dolby light comes on and it can decode the audio just fine. It's just not sending it right over hdmi. Now for some hints to the issue: I noticed in MythTV audio setup when I select alsa:hdmi.... the description only lists 2 channel PCM audio capability. speaker-test -Dhdmi:PCH -c6 errors about a bad channel count (only -c2 works). Finally, I tried vlc and it does the same chattering sound. These all make me think this isn't a MythTV issue, it's something lower than that. I think the best way to troubleshoot this is to start at the drivers and check each layer, one at a time all the way to alsa. I just don't know what the layers are and how to do it. So, I need to find some audio troubleshooting guide to assist me. Or, if one doesn't exist, I'd appreciate some steps. Thanks much, Jim

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  • How to do a multishot in xna?

    - by DeVonte
    I am trying to simulate a gun in which shoots multiple bullets at the same time(similar to a spread out shot). I am thinking I have to create another bullet array then do the same as I have below but in a different direction. Here is what I have so far: foreach (GameObject bullet in bullets) { // Find a bullet that isn't alive if (!bullet.alive) { //And set it to alive bullet.alive = true; if (flip == SpriteEffects.FlipHorizontally) //Facing right { float armCos = (float)Math.Cos(arm.rotation - MathHelper.PiOver2); float armSin = (float)Math.Sin(arm.rotation - MathHelper.PiOver2); // Set the initial position of our bullets at the end of our gun arm // 42 is obtained by taking the width of the Arm_Gun texture / 2 // and subtracting the width of the Bullet texture / 2. ((96/2)=(12/2)) bullet.position = new Vector2( arm.position.X + 42 * armCos, arm.position.Y + 42 * armSin); // And give it a velocity of the direction we're aiming. // Increae/decrease speed by changeing 15.0f bullet.Velocity = new Vector2( (float)Math.Cos(arm.rotation - MathHelper.PiOver4 + MathHelper.Pi + MathHelper.PiOver2), (float)Math.Sin(arm.rotation - MathHelper.PiOver4 + MathHelper.Pi + MathHelper.PiOver2)) * 15.0f; } else //Facing left { float armCos = (float)Math.Cos(arm.rotation + MathHelper.PiOver2); float armSin = (float)Math.Sin(arm.rotation + MathHelper.PiOver2); //Set the initial position of our bullet at the end of our gun arm //42 is obtained be taking the width of the Arm_Gun texture / 2 //and subtracting the width of the Bullet texture / 2. ((96/2)-(12/2)) bullet.position = new Vector2( arm.position.X - 42 * armCos, arm.position.Y - 42 * armSin); //And give it a velocity of the direction we're aiming. //Increase/decrease speed by changing 15.0f bullet.Velocity = new Vector2( -armCos, -armSin) * 15.0f; } return; }// End if }// End foreach

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  • htmlunit eofexception

    - by ihtram
    hi, i am using htmlunit to parse a page. but when i tried to get page from url i got an exception, lets have a look on my code: WebClient wc = new WebClient(BrowserVersion.FIREFOX_3); HtmlPage page = wc.getPage(strUrl); when compilet goes to wc.getPage(strUrl) it throws an exception i.e. java.io.EOFException at java.util.zip.GZIPInputStream.readUByte(Unknown Source) at java.util.zip.GZIPInputStream.readUShort(Unknown Source) at java.util.zip.GZIPInputStream.readHeader(Unknown Source) at java.util.zip.GZIPInputStream.(Unknown Source) at java.util.zip.GZIPInputStream.(Unknown Source) at com.gargoylesoftware.htmlunit.WebResponseData.getBody(WebResponseData.java:129) at com.gargoylesoftware.htmlunit.WebResponseData.(WebResponseData.java:87) at com.gargoylesoftware.htmlunit.HttpWebConnection.newWebResponseDataInstance(HttpWebConnection.java:452) at com.gargoylesoftware.htmlunit.HttpWebConnection.makeWebResponse(HttpWebConnection.java:432) at com.gargoylesoftware.htmlunit.HttpWebConnection.getResponse(HttpWebConnection.java:104) at com.gargoylesoftware.htmlunit.WebClient.loadWebResponseFromWebConnection(WebClient.java:1407) at com.gargoylesoftware.htmlunit.WebClient.loadWebResponse(WebClient.java:1340) at com.gargoylesoftware.htmlunit.WebClient.getPage(WebClient.java:299) at com.gargoylesoftware.htmlunit.WebClient.getPage(WebClient.java:360) at com.gargoylesoftware.htmlunit.WebClient.getPage(WebClient.java:345) at com.htmlunit.test.IHGHotelTest.main(IHGHotelTest.java:39) any one have an idea about it

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  • VS2010 - Add template to New Project window

    - by gbogumil
    I am trying to add a new project template for an often used pattern. Starting from the class library template I have done the following (it still does not show up in the new project window): opened the .vstemplate file changed name and description to 'hard coded' values (my template). The values in there pulled from the csharpui.dll resources. changed the TemplateID, DefaultName, and ProjectItems included. saved these to the ProjectemplatesCache folder and as a zip in the ProjectTemplates folder. restarted VS2010 and checked the new project location which should have shown my new template. specifically, the folders I saved to were.. C:\program files\Microsoft Visual Studio 10.0\Common7\IDE\ProjectTemplatesCache\CSharp\Windows\1033\HostComm.zip (the zip is the folder name, not a zip file) and C:\program files\Microsoft Visual Studio 10.0\Common7\IDE\ProjectTemplates\CSharp\Windows\1033 (this folder has a HostComm.zip file in it) Has anyone else done this? Can it be done? If it can then what did I miss?

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  • Logical python question - handling directories and files in them

    - by Konstantin
    Hello! I'm using this function to extract files from .zip archive and store it on the server: def unzip_file_into_dir(file, dir): import sys, zipfile, os, os.path os.makedirs(dir, 0777) zfobj = zipfile.ZipFile(file) for name in zfobj.namelist(): if name.endswith('/'): os.mkdir(os.path.join(dir, name)) else: outfile = open(os.path.join(dir, name), 'wb') outfile.write(zfobj.read(name)) outfile.close() And the usage: unzip_file_into_dir('/var/zips/somearchive.zip', '/var/www/extracted_zip') somearchive.zip have this structure: somearchive.zip 1.jpeg 2.jpeg another.jpeg or, somethimes, this one: somearchive.zip somedir/ 1.jpeg 2.jpeg another.jpeg Question is: how do I modify my function, so that my extracted_zip catalog would always contain just images, not images in another subdirectory, even if images are stored in somedir inside an archive.

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  • downloading archives response corrupts files

    - by panchicore
    wrapper = FileWrapper(file("C:/pics.zip")) content_type = mimetypes.guess_type(result.files)[0] response = HttpResponse(wrapper, content_type=content_type) response['Content-Length'] = os.path.getsize("C:/pics.zip") response['Content-Disposition'] = "attachment; filename=pics.zip" return response pics.zip is a valid file with 3 pictures inside. server response the download, but when I am going to open the zip, winrar says This archive is either in unknown format or damaged! If I change the file path and the file name to a valid image C:/pic.jpg is downloaded damaged too. What Im missing in this download view?

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  • Read a remote zipped xml with just XSL

    - by Emaguel
    Hello there I want to know if it's possible for an XSLT file to read data from an XML located within folders of a remote zip(from the server at work), without any external processors (saxon and so forth) and without downloading it. Failing that, I'll resort to just reading the information from the zip... which brings me to my other (newb)issue. I currently have an XSLT that accesses and gets the data from the downloaded and extracted XML file, but I can't do this without extracting it. I've read that with Altova and xslt 2.0 it is possible to read from within a zip file using the document() function, though, as of yet I have not been able achieve this. this is how I'm trying to do it: document('name.zip|zip/folder/folder2/iwantthis.xml') It just doesn't seem to find the file. I'd be almost eternally grateful if you show me the error of my ways and guide me into XSLThood. Thank you kindly

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  • Logical python question - handeling directories and files in them

    - by Konstantin
    Hello! I'm using this function to extract files from .zip archive and store it on the server: def unzip_file_into_dir(file, dir): import sys, zipfile, os, os.path os.makedirs(dir, 0777) zfobj = zipfile.ZipFile(file) for name in zfobj.namelist(): if name.endswith('/'): os.mkdir(os.path.join(dir, name)) else: outfile = open(os.path.join(dir, name), 'wb') outfile.write(zfobj.read(name)) outfile.close() And the usage: unzip_file_into_dir('/var/zips/somearchive.zip', '/var/www/extracted_zip') somearchive.zip have this structure: somearchive.zip 1.jpeg 2.jpeg another.jpeg or, somethimes, this one: somearchive.zip somedir/ 1.jpeg 2.jpeg another.jpeg Question is: how do I modify my function, so that my extracted_zip catalog would always contain just images, not images in another subdirectory, even if images are stored in somedir inside an archive.

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  • Checking contents of Uploaded file

    - by kapil
    Hi all, I am using ASP.NEt MVC . I want to upload .zip files for which I am using html input file upload control on my view. I want only .zip files to be uploaded. I want to check that my .zip contains only two files - both having extensions .txt and one of them having name "start". Can anyone please suggest me about how to check this? How can we assure that the uploaded .zip is really a zipped folder and not any other file having just .zip extension. can we use HttpPostedFileBase.ContentType? thanks in advance, kaps

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  • In html <a href> tag, how to call servlet before opening file dialog for download (save as)?

    - by deepthinker121
    Hi All, I am developing a web-app where I want to provide a download link to users - so they can download a zip file from my server. Now, my requirement is that I want to execute some processing logic contained in a servlet before displaying the file dialog to the user for 'zip' files. So If I write <a href="abc.zip".......> then it opens a file dialog asking the user to select the location where this file can be saved But if I want a servlet's doGet method to do some preprocessing - say like building the zip file , then how can I first call the servlet and then open the file dialog. Will the following snippet work? <a href="MyHandlerServlet;abc.zip".......> Thanks for your help !!

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