Search Results

Search found 15376 results on 616 pages for 'mysql triggers'.

Page 240/616 | < Previous Page | 236 237 238 239 240 241 242 243 244 245 246 247  | Next Page >

  • Amazon EC2- micro-instance vs single small/medium instance

    - by shashankaholic
    I have a chat application using stack of Openfire, Tomcat6 and MySQL. Currently, i have installed all these servers on single Linux micro-instance(613 MB memory). Even in low user base 10-20 i am encountering CPU overload which is quite obvious here. As, i am new to Amazon EC2 can somebody suggest me how to scale up my architecture according to traffic use? should i use separate micro instances for every app server(openfire,mysql,tomcat6) should i use single small or medium instance for whole server stack. Some factors in context: high reliance on MYSQL high memory usage due to file transfer web-application interacting with other Amazon service like S3,SES

    Read the article

  • Cannot Login To phpMyAdmin

    - by Zach Dziura
    I'm running a simple LAMP server at home from which I host a personal blog. The server is running Arch Linux, with the latest-and-greatest versions of Apache, MySQL, and PHP. In order to easily maintain the databases, I installed phpMyAdmin. However, I cannot login. If I were to SSH into the server and run mysql -u <user> -p <password>, no errors show up and I'm immediately placed into the MySQL prompt. No problem. However, when I try to log in with phpMyAdmin, using those exact same credentials, nothing happens. No errors, no nothing, I'm just redirected back to the login page. Did I do something wrong? Thanks in advance for any and all answers!

    Read the article

  • Unable to edit/delete/move /etc/my.cnf - Permission denied

    - by FlourishDNA
    I am trying to edit /etc/my.cnf as root user via ssh and I get following error while trying to save it I ma making changes to my.cnf as I want to tweak some values in my.cnf to meet Magento requirement like changing key_buffer_size= to higher value (128M). I assigned the value 128M to key_buffer_size= and tried to save it and then got an error. "Error writing /etc/my.cnf: Permission denied" I cant even restart MySQL successfully. [root@flourish ~]# service mysqld restart Stopping mysqld: [ OK ] MySQL Daemon failed to start. Starting mysqld: [FAILED] I can even delete or replace it with the fresh one. I tried uninstalling MySQL and re-installing but nothing worked. Permission -rw-r--r-- and Owner/Group root/root I hope there is some answer to this problem.

    Read the article

  • Difference between key_buffers and recommendation

    - by Typeoneerror
    I'm looking to add a bit of memory to MySQL on a Linode VPS server on which I've got a small facebook (canvas app) PHP app using MySQL running. I'm not super familiar with MySQL optimization so I'm hoping to find a simple answer. I think I want to increase the key_buffer size (the default is 16M) to something like 32M to start, but I'm not sure if I need to tweak anything else as well. All I've done so far is increase the query_cache_size to 32M from 16M. There's also key_buffer under [mysqld] and key_buffer under [isamchk]. What are the difference between those two? If I have Linode 2048MB (http://www.linode.com) VPS, what would recommend I set the buffers to? I don't expect this site to have tons of visitors, but I'd like it to be as optimized as possible. Definitely way more heavy on the database access than PHP and very few HTTP requests.

    Read the article

  • The good SQL database to process a lot of data?

    - by Dorian
    I have to process like 10-100 millions records. I have to give the data to the client when it's finish. The data is givent as SQL requests to execute in the database. He have a powerful server with MySQL, I think it will be fast enough. The issue is my computer is not as powerful as his server, so I would like to use an other SQL server who is compatible (I export his database and import it in my computer) with MySQL but more powerful. What should I use? Or am I doomed to use MySQL?

    Read the article

  • Web-Server directory permissions

    - by MLS
    Hello All, I would like some help understanding web-server directory permissions. Apache, CentOS, PHP, Mysql Example, I have multiple sites in /var/www/html They are in paths like: /var/www/html/www_domainname_com inside each site I might have a path like /lib/mysql/ like PHP connect stuff, database config, etc. What should me permissions be so that someone cannot just browse to that directory? Should I just .htaccess them? I have apache:apache as the owner of all my web directories. Can I prevent someone from crawling certain directories of my web-server? I have a robots.txt, but what is to say the crawler obeys it? So to sum up: 1. What is the best owner/permission set for my sensitive files that the web-server or php or mysql needs, but I dont want people browsing to? Can I prevent straight out crawling of portions?

    Read the article

  • my.ini optimization on Windows 2008 R2 VPS

    - by MKphpDev
    I have a vmware VPS running Windows Server 2008 R2 Enterprise that has performance issues with MySQL. Every few minutes, MySQL stall for few seconds then responed to queries. I'm sure that my.ini need to be optimized, but unfortunately, I don't have any idea of my.ini configuration. What's running on the server: 2 small wordpress blogs, 1 vbulletin forums (approx. 1.2 GB database, and increasing), small database for some sort of plug-ins (no more than 4000 records) Server Info: Processor: Intel Xeon X5550 @ 2.67GHz, RAM: 6 GB (memory useage never exceeded 2 GB), MySQL 5.5, PHP 5.3.10, IIS 7 current my.ini: [mysqld] default-storage-engine=INNODB sql-mode="STRICT_TRANS_TABLES,NO_AUTO_CREATE _USER,NO_ENGINE_SUBSTITUTION" max_connections=250 myisam_max_sort_file_size=20G innodb_additional_mem_pool_size=256M innodb_flush_log_at_trx_commit=1 innodb_log_buffer_size=8M innodb_buffer_pool_size=512MB innodb_log_file_size=128M innodb_thread_concurrency=10 key_buffer_size = 512M myisam_sort_buffer_size = 8M join_buffer_size = 256K read_buffer_size = 256K sort_buffer_size = 256K table_cache = 4000 thread_cache_size = 200 wait_timeout = 30 connect_timeout = 10 tmp_table_size = 32M max_allowed_packet = 1M max_connect_errors = 10000 query_cache_size = 16M query_cache_limit = 2M query_cache_type = 1 query_cache_min_res_unit = 1024 query_prealloc_size = 16384 query_alloc_block_size = 16384 skip-external-locking read_rnd_buffer_size=1M max_heap_table_size=16M thread_concurrency=8 [mysqld_safe] open_files_limit = 8192 [mysqldump] quick max_allowed_packet = 16M [myisamchk] key_buffer_size = 128M sort_buffer_size = 128M read_buffer = 2M write_buffer = 2M any help with that, please?

    Read the article

  • New functionality in TFS Build Manager &ndash; Managing Triggers and Build Resources

    - by Jakob Ehn
    Yesterday we pushed out a new release (August 2012) of the Community TFS Build Extension, including a new version of the Community TFS Build Manager (1.0.4.6) The two big new features in the Build Manager in this release are: Set Triggers It is now possible to select one or more build definitions and update the triggers for them in one simple operation: You’ll note that we have started collapsing the context menu a bit, the list of commands are getting long! When selecting the Trigger command, you’ll see a dialog where the options should be self-explanatory: The only thing missing here is the Scheduled trigger option, you’ll have to do that using Team Explorer for now.   Manage Build Resources The other feature is that it is now possible to view the build controllers and agents in your current collection and also perform some actions against them. The new functionality is available by select the Build Resources item in the drop down menu: Selecting this, you’ll see a (sort of) hierarchical view of the build controllers and their agents: In this view you can quickly see all the resources and their status. You can also view the build directory of each build agent and the tags that are associated with them. On the action menu, you can enable and disable both agents and controllers (several at a time), and you can also select to remove them. By selecting Manage, you’ll be presented with the standard Manage Controller dialog from Visual Studio where you can set the rest of the properties. Hopefully we’ll be able to implement most of the existing functionality so that we can remove that menu option Our plan is to add more functionality to this view, such as adding new agents/controllers, restarting build service hosts, maybe view diagnostic information such as disk space and error logs.   Hope you’ll find the new functionality useful. Remember to log any bugs and feature requests on the CodePlex site. Happy building!

    Read the article

  • Using a join with three tables when a field might be null

    - by John
    Hello, The code below works great. It combines data from two MySQL tables. I would like to modify it by pulling in some data from a third MySQL table called "comment." In the HTML table below, "title" is a field in the MySQL table "submission." Every "title" has a corresponding "submissionid" field. The field "submissionid" is also found in the "comment" MySQL table. In the HTML table below, I would like "countComments" to equal the number of times a field called "commentid" appears in the MySQL table "comment" for any given "submissionid," where the "submissionid" is the same in both the "submission" and "comment" tables, and where the "submissionid" corresponds to the "title" being used. Here's the catch: if there is no row in the MySQL table "comment" that corresponds with the "submissionid" being used for "table", I would like "countComments" to equal to zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

    Read the article

  • Multiplayer card game using PHP/Ajax and mysql

    - by Alireza Seifi
    I am designing a map game, using PHP and MYSQL. I don't know how to make the players who sign-in to the website to see other players who are also connected to the site and be able to chat with one another. I want to design the game in such a way that 2 players can play with each other and be able to send messages during the game while others groups are playing at the same time. I have designed the map game successfully, but the problem is making the player 1 who log-in to site to see the player 2 who will also log-in and both can get connected to play each other. http://i.stack.imgur.com/YyCPG.png I will appreciate your responses.

    Read the article

  • Ubuntu 13.10 gives "Package 'libapache2-mod-auth-mysql' has no installation candidate" error

    - by John Crawford
    I'm trying to install my LAMP environment on Ubuntu 13.10 using my script file that can be found here. That script worked for Ubuntu 12.04, Ubuntu 13.04 but when I try it on Ubuntu 13.10 it gives the following error: E: Package 'libapache2-mod-auth-mysql' has no installation candidate Any idea on how to fix this? Note, I do want this package to be installed. EDIT: I've found out now that the reason this could not be installed was because it needed the following two packages that were missing: libmysqlclient16 and apache2.2-common. Do I just need to install these packages or were they removed for a reason?

    Read the article

  • OpenID implementation - PHP, Javascript, MySQL

    - by Marc A.
    Hello, I've started doing some research on the technologies that I will need for my website. I'm trying to implement a really simple website with OpenID user registration. The website will store a block of text for each user. I imagine this means that I will need a database with: User ID Open ID url Data Having said that, I'm still having trouble deciding what I really need to do this. I know that I will need the following for the actual site: Javascript JQuery CSS But on the back end, I'm kind of lost at the moment. I've been looking at the OpenID-Selector, which is coded in Javascript. It seems like it's exactly what is used on this site. Will I actually need PHP? MySQL for the data and user registration? Thanks for the kickstart!

    Read the article

  • MySQL in ASP.NET: Mono using VB.NET

    In a previous tutorial titled ASP.NET Web Development and Hosting published October 25th you learned how to develop ASP.NET websites using Mono Project and deploy them in your existing Linux-Apache hosting account. The example ASP.NET mono website http www.dotnetdevelopment.net did not use a database at the time the tutorial was written. In this part you will learn how to connect and use a MySQL database with your ASP.NET mono project website.... Microsoft Exchange - IT peace of mind Big time solution. Small-stakes price. Get the White Paper now.

    Read the article

  • Ikoula : 500 serveurs virtuels dédiés offerts, disponibles sur deux configurations et incluent MySQL et SQLServer

    Ikoula : 500 serveurs virtuels dédiés offerts Disponibles sur deux configurations et incluent MySQL et SQLServer Ikoula, leader du Cloud Computing en France propose une promotion limitée sur son offre de serveurs virtuels dédiés. 500 Flex'Servers sont en effet offerts aux premiers inscrits à cette promotion valable jusqu'au 31 janvier prochain, et ce durant 3 mois et sans engagement de durée. [IMG]http://idelways.developpez.com/news/images/flex_image.gif[/IMG] Construits sur une architecture haut de gamme (Dell, Cisco, ...) robuste et performante, les Flex'Servers de iKoula s'adaptent potentiellement à tous les besoins. Le nombre de pro...

    Read the article

  • Learning MySQL Query optimization

    - by recluze
    I've been doing web/desktop/server development for a while and have worked with many databases (mysql mostly). I've come to the point in my career when I need to have someone look at my queries because they're 'kind of slow'. I believe it's now time to start learning query optimization. While I know the basics of index and joins etc., I'm not familiar with how to use, say, the EXPLAIN output to improve performance of my queries. I have not been able to find any online material that starts with the basics and takes me to application. Getting a book is not an option right now so I'm looking for tips about how to proceed with this. I hope this question is general enough not to get closed.

    Read the article

  • PHP MYSQL FPDF retrieving pdf string stored as blob.

    - by jj.amonit
    Using the above technologies, I want to create a PDF, store it in my db, and email it. All with the click of one button. I also want to call it up and have it be able to display with a hyperlink. I am very new to FPDF. Therefore, I am trying to start off very slowly. I began with this link stackoverflow Q I put both parts of his code into the same page and tried with separate pages. I made the suggested changes/additions and even did a line by line comparison. I still get the message, "format error: not a PDF or corrupted" If I just $pdf-Output(); I get the pdf to display. It's either the way the string is being Output, or it's the header() function. It's not the storage method, unless my column setup is incorrect. BUt a blob is a blob, right? If you want, I can upload the sanitized code. Just let me know what would help answer this. Thanks JJ

    Read the article

  • Is it possible to group rows twice in MySQL?

    - by DisgruntledGoat
    I have a table like this: someid somestring 1 Hello 1 World 1 Blah 2 World 2 TestA 2 TestB ... Currently I'm grouping by the id and concatenating the strings, so I end up with this: 1 Hello,World,Blah 2 World,TestA,TestB ... Is it possible to do a second grouping so that if there are multiple entries that end up with the same string, I can group those too?

    Read the article

  • How do I INSERT INTO from one mysql table into another table and set the value of one column?

    - by Laxmidi
    Hi, I need to insert data from table1 into table2. However, I would like to set the myYear column in table2 to 2010. But, there isn't a myYear Column in table1. So, my basic insert looks like: INSERT INTO `table2` ( place, event ) SELECT place, event FROM table1 Roughly, I'd like to do something like the following: INSERT INTO `table2` ( place, event, SET myYear='2010' ) ... Is there a way to set the column value in the insert statement? THANK YOU! -Laxmidi

    Read the article

  • Is this so bad when using MySQL queries in PHP?

    - by alex
    I need to update a lot of rows, per a user request. It is a site with products. I could... Delete all old rows for that product, then loop through string building a new INSERT query. This however will lose all data if the INSERT fails. Perform an UPDATE through each loop. This loop currently iterates over 8 items, but in the future it may get up to 15. This many UPDATEs doesn't sound like too good an idea. Change DB Schema, and add an auto_increment Id to the rows. Then first do a SELECT, get all old rows ids in a variable, perform one INSERT, and then a DELETE WHERE IN SET. What is the usual practice here? Thanks

    Read the article

  • Very simply, how can check if a user exists against my MySQL database?

    - by Sergio Tapia
    Here's what I have but nothing is output to the screen. :\ <html> <head> </head> <body> <? mysql_connect(localhost, "sergio", "123"); @mysql_select_db("multas") or die( "Unable to select database"); $query="SELECT * FROM usuario"; $result=mysql_query($query); $num=mysql_numrows($result); $i=0; $username=GET["u"]; $password=GET["p"]; while ($i < $num) { $dbusername=mysql_result($result,$i,"username"); $dbpassword=mysql_result($result,$i,"password"); if(($username == $dbusername) && ($password == $dbpassword)){ echo "si"; } $i++; } ?> </body> </html> I'm iterating through all users and seeing if there is a match for user && password. Any guidance?

    Read the article

  • After writing SQL statements in MySQL, how to measure the speed / performance of them?

    - by Jian Lin
    I saw something from an "execution plan" article: 10 rows fetched in 0.0003s (0.7344s) How come there are 2 durations shown? What if I don't have large data set yet. For example, if I have only 20, 50, or even just 100 records, I can't really measure how faster 2 different SQL statements compare in term of speed in real life situation? In other words, there needs to be at least hundreds of thousands of records, or even a million records to accurately compares the performance of 2 different SQL statements?

    Read the article

  • java.sql.SQLException: Parameter number X is not an OUT parameter

    - by Frederik
    Hi guys, I'm struggling with getting the result OUT variable from a MySQL stored procedure. I get the following error: java.sql.SQLException: Parameter number 3 is not an OUT parameter The stored procedure looks like this: CREATE DEFINER=`cv_admin`@`localhost` PROCEDURE `CheckGameEligibility`( IN gID INT(10), IN uID INT(10), OUT result TINYINT(1) ) BEGIN # Do lots of stuff, then eventually: SET result = 1; END My java function takes an array of strings* and creates the CallableStatement object dynamically: public static int callAndReturnResult( String sql , String[] values ) { int out = 0 ; try { // construct the SQL. Creates: CheckGameEligibility(?, ?, ?) sql += "(" ; for( int i = 0 ; i < values.length ; i++ ) { sql += "?, " ; } sql += "?)" ; System.out.println( "callAndReturnResult("+sql+"): constructed SQL: " + sql ); // Then the statement CallableStatement cstmt = DB.prepareCall( sql ); for( int i = 0 ; i < values.length ; i++ ) { System.out.println( " " + (i+1) + ": " + values[ i ] ) ; cstmt.setString(i+1, values[ i ] ); } System.out.println( " " + (values.length+1) + ": ? (OUT)" ) ; cstmt.registerOutParameter( values.length + 1 , Types.TINYINT ); cstmt.execute(); out = cstmt.getInt( values.length ); cstmt.close(); } catch( Exception e ) { System.out.println( "*** db trouble: callAndReturnResult(" + sql + " failed: " + e ); e.printStackTrace() ; } return out ; } *) I suppose I should be using an int array instead of a string array, but it doesn't seem to be what the error message was about. Anyway, here's the output it generates: callAndReturnResult(CheckGameEligibility(?, ?, ?)): constructed SQL: CheckGameEligibility(?, ?, ?) 1: 57 2: 29 3: ? (OUT) *** db trouble: callAndReturnResult(CheckGameEligibility(?, ?, ?) failed: java.sql.SQLException: Parameter number 3 is not an OUT parameter at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1075) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:989) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:984) at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:929) at com.mysql.jdbc.CallableStatement.checkIsOutputParam(CallableStatement.java:692) at com.mysql.jdbc.CallableStatement.registerOutParameter(CallableStatement.java:1847) at org.apache.commons.dbcp.DelegatingCallableStatement.registerOutParameter(DelegatingCallabl>eStatement.java:92) at Tools.callAndReturnResult(Tools.java:156) Any ideas what might be the problem? :) Thanks in advance!

    Read the article

  • Best way to sort MySql results based on two columns and show results using pagination?

    - by understack
    I want to sort results set first based on one column and then based on second column. I know how to do it on server side. And then I want to show these results with pagination feature. Question: would it be better to do it on client side via ajax in jQuery? I'm using Zend Framework. Would Zend_Paginator module be useful in this scenario? Basically I want to evaluate all the possible ways? Which one would be best and/or simplest option given I'm using jQuery and Zend Framework?

    Read the article

  • MySQL & PHP - select/option lists and showing data to users that still allows me to generate queries

    - by Andrew Heath
    Sorry for the unclear title, an example will clear things up: TABLE: Scenario_victories ID scenid timestamp userid side playdate 1 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 2 RtBr001 2010-03-15 17:13:36 7 1 2010-03-10 3 RtBr001 2010-03-15 17:13:51 7 2 2010-03-10 ID and timestamp are auto-insertions by the database when the other 4 fields are added. The first thing to note is that a user can record multiple playings of the same scenario (scenid) on the same date (playdate) possibly with the same outcome (side = winner). Hence the need for the unique ID and timestamps for good measure. Now, on their user page, I'm displaying their recorded play history in a <select><option>... list form with 2 buttons at the end - Delete Record and Go to Scenario My script takes the scenid and after hitting a few other tables returns with something more user-friendly like: (playdate) (from scenid) (from side) ######################################################### # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Germany, Hungary won # # 2010-03-10 Road to Berlin #1 -- Soviet Union won # ######################################################### [Delete Record] [Go To Scenario] in HTML: <select name="history" size=3> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Germany, Hungary won</option> <option>2010-03-10 Road to Berlin #1 -- Soviet Union won</option> </select> Now, if you were to highlight the first record and click Go to Scenario there is enough information there for me to parse it and produce the exact scenario you want to see. However, if you were to select Delete Record there is not - I have the playdate and I can parse the scenid and side from what's listed, but in this example all three records would have the same result. I appear to have painted myself into a corner. Does anyone have a suggestion as to how I can get some unique identifying data (ID and/or timestamp) to ride along on this form without showing it to the user? PHP-only please, I must be NoScript compliant!

    Read the article

< Previous Page | 236 237 238 239 240 241 242 243 244 245 246 247  | Next Page >