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  • header location won't work in php

    - by Jayden Kelly
    I am making a login page for my website but the header location won't work. here is the code of login.php: <?php include ( './includes/header.php' ); if (isset($_POST['submit'])) { $username = $_POST['username']; $password = $_POST['password']; $check_username = mysql_query("SELECT username FROM users WHERE username='$username'"); $numrows = mysql_num_rows($check_username); if ($numrows != 1) { echo 'That User doesn\'t exist.'; } else { $check_password = mysql_query("SELECT password FROM users WHERE password='$password' && username='$username'"); while ($row = mysql_fetch_assoc($check_password)) { $password_db = $row['password']; if ($password_db == $password) { $_SESSION['username'] = $username; header("Location: members.php"); } } } } ?> <h2>Login to Your Account</h2> <form action='login.php' method='POST'> <input type='text' name='username' value='Username ...' onclick='value=""'/><p /> <input type='password' name='password' value='Password ...' onclick='value=""'/><p /> <input type='submit' name='submit' value='Login to my Account' /> </form> I would really appreciate it if someone could help me, thanks. P.S. If you need the php part of the header file it is here: <?php session_start(); include ( './includes/functions.php' ); include ( './includes/connect_to_mysql.php' ); ?>

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  • segmentation fault using scanf

    - by agarrow
    noob question here: I'm trying to write a simple menu interface, but I keep getting a segmentation fault error and I can't figure out why. #include <stdlib.h> #include <stdio.h> int flush(); int add(char *name, char *password, char *type); int delete(char *name); int edit(char *name, char *password, char *type, char *newName, char *newPassword, char *newType); int verify(char *name, char *password); int menu(){ int input; char *name, *password, *type, *newName, *newPassword, *newType; printf("MAIN MENU \n ============\n"); printf("1. ADD\n"); printf("2. DELETE\n"); printf("3. EDIT\n"); printf("4. VERIFY\n"); printf("5. Exit\n"); printf("Selection:"); scanf("%d", &input); flush(); switch (input){ case 1: printf("%s\n", "Enter Name:"); scanf("%s", name); flush(); printf("%s\n", "enter password" ); scanf("%s", password); flush(); printf("%s\n","enter type" ); scanf("%s",type); add(name, password, type); menu(); break; case 2: printf("Enter Name:" ); scanf("%s",name); flush(); delete(name); menu(); break; case 3: printf("Enter Name:\n"); scanf("%s",name); flush(); printf("Enter Password\n"); scanf("%s", password); flush(); printf("enter type:\n"); scanf("%s", type); flush(); printf("enter your new username:\n"); scanf("%s",newName); flush(); printf("enter your new password\n"); scanf("%s", newPassword); flush(); printf("enter your new type\n"); scanf("%s",newType); flush(); edit(name, password, type, newName, newPassword, newType); menu(); break; case 4: printf("Enter Name\n"); scanf("%s",name); flush(); printf("Enter Password\n"); scanf("%s",password); flush(); verify(name, password); menu(); break; case 5: return 0; default: printf("invalid input, please select from the following:\n"); menu(); } return 0; } int flush(){ int ch; while ((ch = getchar()) != EOF && ch != '\n') ; return 0; } I get the segmentation fault after entering two fields, in any menu option

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  • Confused on the basics of AJAX

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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  • How can I retrieve "remembered"(stored) wi-fi password from a win. 7 device?

    - by user180880
    I have access to PC, and I am a standard user. Everything(incl. "show charecters" tickbox at wiriless menu) requires admin access. Now, that said machine is actually like a big tv with touch. Type-stuff is handled by virtual keyboard of windows. I can reach to c:\ProgramData\Microsoft\Wlansvc\Profiles\Interfaces and can see-open files there, which is I assume where passwords stored are. Now the problem is that these passwords is encypted. I'm ok with if there is a way with changing/resetting admin password as well. Considering this device has nothing but massive amounts of usb(yep, not even cd-dvd // rw) the only way is from inside or with usb without admin rights.

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  • PHP & MySQL - Undefined variable problem?

    - by TaG
    I keep getting the following error Undefined variable: password on line 33 how do I correct this problem? So this error will stop showing. Here is the php code. $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $password1 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password1']))); $password2 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password2']))); // Check for a password and match against the confirmed password: if ($password1 == $password2) { $sha512 = hash('sha512', $password1); $password = mysqli_real_escape_string($mysqli, $sha512); } else { echo '<p class="error">Your password did not match the confirmed password!</p>'; } //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, password) VALUES ('$user_id', '$first_name', '$password')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; }

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  • Secure Government Series Part 3

    - by Naresh Persaud
    Secure Government Training SeriesSafeguarding Government CyberspaceClick here, to register for the live webcast. Cybersecurity threats represent one of the most serious national security, public safety, and economic challenges. While technologies empower government to lead and innovate, they also enable those who seek to disrupt and destroy progress. Cloud computing, mobile devices and social networks help government reduce costs and streamline service delivery, but also introduce heightened security vulnerabilities. How can government organizations keep pace with heightened service delivery demands and advancements in technology without compromising security? Join us November 28th for a webcast as part of the “Secure Government Training Series” to learn about a security portfolio that helps organizations mitigate cyber attacks by providing Full-spectrum cybersecurity capabilities that harden the data tier, lock down sensitive information, and provide access controls and visibility for frequently targeted systems.Gain insights to an integrated security framework and overall strategy for preventing attacks that will help your organization: Deploy resilient IT infrastructure Catalog and classify sensitive and mission-critical data Secure the enterprise data tier and lock down trusted insider privileges at all levels Automate and centralize enterprise auditing Enable automated alerting and situational awareness of security threats and incidents For more information, access the Secure Government Resource Center or to speak with an Oracle representative, please call1.800.ORACLE1. LIVE Webcast Safeguarding Government Cyberspace Date: Wednesday, November 28th, 2012 Time: 2:00 p.m. ET Visit the Secure Government Resource CenterClick here for information on enterprise security solutions that help government safeguard information, resources and networks. ACCESS NOW Copyright © 2012, Oracle. All rights reserved. Contact Us | Legal Notices | Privacy Statement

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  • How to Set Ubuntu 12.04 to it's factory settings like when u first installed it?

    - by Cameron
    Well, this is a simple answered question, from the title, but my real problem is hard af. I have set ubuntu to use root, then it wouldn't let me log into the admin account only root and guest I deleted the admin account, remade another, then attempted to disable root account. This failed - I messed up the password, the original password was "root" I also didn't set a password for my new admin account, so It says it has one, whats the default password for it? I can't moderate my ubuntu system at all now. I have tried to drop to cmd shell thing, it asks for the root password, i type 'root' and any other possible passwords, it doesn't work. To reset ubuntu to factory settings i have found that i could enter the following code: sudo dpkg-reconfigure -phigh -a sudo Requires admin password, that I cant find out without root password and I don;t know. My goal is to try to fix this without remaking a bootable usb for ubuntu, because I lost the one i made for this. so If i can't, please say so. If you can help thanks!

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  • what other bash variables are available during execution such as $USER that can assist on my script?

    - by semi-newbie
    This is related to question 19245, in that one of the responders answered the question in an awesome way, and very VERY clear to any newbie. Now here is a question that i can't seem to figure. i wrote a script for starting the vmware firefox plugin (don't worry. i gave that up and now run vBox VERY happily. i left vmware for my servers :) ) I needed to start the plugin as sudo, but i also needed to pass an argument (password) to it, that happen to be the same. So, if my password was Hello123, the command would be: sudo ./myscript.sh hi other Hello123 running from command line, the script would ask for my sudo password and then run. i wanted to capture THAT password and pass it as well. i also wanted to run graphically, so i tried gksudo, and there is an option -p that returns the password for variable assignment. well, that was a nightmare, because i would still get prompted for the original sudo: see below Find UserName vUser=$USER Find password (and hopefully enable sudo) vP=gksudo -p -D somedescriptiontext echo Execute command gksudo ./myscript.sh hi $vUser $vP and i still get prompted twice. so my question is tri-fold: is there a variable i can use for the password, just like there is one for user, $USER? is there a different way i should be assigning the value resulting of the command i have in $vP? i am wondering if executing the way i have it, does it in an uninitiated session and not the current one, since i am getting some addtl warning type errors on some variables blah blah i tried using Zenity to just capture the text, but then of course, i couldn't pass that value to sudo, so i could only use as a parameter, which puts me back in 2 prompts. Thanksssssssssss!

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  • Securing a Cloud-Based Data Center

    - by Orgad Kimchi
    No doubt, with all the media reports about stolen databases and private information, a major concern when committing to a public or private cloud must be preventing unauthorized access of data and applications. In this article, we discuss the security features of Oracle Solaris 11 that provide a bullet-proof cloud environment. As an example, we show how the Oracle Solaris Remote Lab implementation utilizes these features to provide a high level of security for its users. Note: This is the second article in a series on cloud building with Oracle Solaris 11. See Part 1 here.  When we build a cloud, the following aspects related to the security of the data and applications in the cloud become a concern: • Sensitive data must be protected from unauthorized access while residing on storage devices, during transmission between servers and clients, and when it is used by applications. • When a project is completed, all copies of sensitive data must be securely deleted and the original data must be kept permanently secure. • Communications between users and the cloud must be protected to prevent exposure of sensitive information from “man in a middle attacks.” • Limiting the operating system’s exposure protects against malicious attacks and penetration by unauthorized users or automated “bots” and “rootkits” designed to gain privileged access. • Strong authentication and authorization procedures further protect the operating system from tampering. • Denial of Service attacks, whether they are started intentionally by hackers or accidentally by other cloud users, must be quickly detected and deflected, and the service must be restored. In addition to the security features in the operating system, deep auditing provides a trail of actions that can identify violations,issues, and attempts to penetrate the security of the operating system. Combined, these threats and risks reinforce the need for enterprise-grade security solutions that are specifically designed to protect cloud environments. With Oracle Solaris 11, the security of any cloud is ensured. This article explains how.

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  • What are the steps needed to set up and use security for AWS command line tools?

    - by chris
    I've been trying to set up the AWS command-line tools following Eric's most useful guide at http://alestic.com/2012/09/aws-command-line-tools. I can't seem to find a good how-to for how to generate the x509 certificate and private key, and how that relates to the various security files the guide creates. Update: I have found a couple of links that describe the some steps. These steps seem to work, however I'm not sure if this is secure & the best way to do it: 1) Create a private key openssl genrsa -out my-private-key.pem 2048 2) Create x.509 cert openssl req -new -x509 -key my-private-key.pem -out my-x509-cert.pem -days 365 Hit enter to accept all of the defaults. Then, from the IAM Dashboard, User, select a user & click on the "Security Credentials" tab. Click on "Manage Signing Certificates", then "Upload Signing Certificate", paste in the contents of my-x509-cert.pem, click OK and it should be accepted. One step that is discussed, but not required for me, was the addition and subsequent removal of a pass phrase on the private key. Should I have been prompted for one, and is my cert potentially unsafe because of this?

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  • College Courses through distance learning

    - by Matt
    I realize this isn't really a programming question, but didn't really know where to post this in the stackexchange and because I am a computer science major i thought id ask here. This is pretty unique to the programmer community since my degree is about 95% programming. I have 1 semester left, but i work full time. I would like to finish up in December, but to make things easier i like to take online classes whenever I can. So, my question is does anyone know of any colleges that offer distance learning courses for computer science? I have been searching around and found a few potential classes, but not sure yet. I would like to gather some classes and see what i can get approval for. Class I need: Only need one C SC 437 Geometric Algorithms C SC 445 Algorithms C SC 473 Automata Only need one C SC 452 Operating Systems C SC 453 Compilers/Systems Software While i only need of each of the above courses i still need to take two more electives. These also have to be upper 400 level classes. So i can take multiple in each category. Some other classes I can take are: CSC 447 - Green Computing CSC 425 - Computer Networking CSC 460 - Database Design CSC 466 - Computer Security I hoping to take one or two of these courses over the summer. If not, then online over the regular semester would be ok too. Any help in helping find these classes would be awesome. Maybe you went to a college that offered distance learning. Some of these classes may be considered to be graduate courses too. Descriptions are listed below if you need. Thanks! Descriptions Computer Security This is an introductory course covering the fundamentals of computer security. In particular, the course will cover basic concepts of computer security such as threat models and security policies, and will show how these concepts apply to specific areas such as communication security, software security, operating systems security, network security, web security, and hardware-based security. Computer Networking Theory and practice of computer networks, emphasizing the principles underlying the design of network software and the role of the communications system in distributed computing. Topics include routing, flow and congestion control, end-to-end protocols, and multicast. Database Design Functions of a database system. Data modeling and logical database design. Query languages and query optimization. Efficient data storage and access. Database access through standalone and web applications. Green Computing This course covers fundamental principles of energy management faced by designers of hardware, operating systems, and data centers. We will explore basic energy management option in individual components such as CPUs, network interfaces, hard drives, memory. We will further present the energy management policies at the operating system level that consider performance vs. energy saving tradeoffs. Finally we will consider large scale data centers where energy management is done at multiple layers from individual components in the system to shutting down entries subset of machines. We will also discuss energy generation and delivery and well as cooling issues in large data centers. Compilers/Systems Software Basic concepts of compilation and related systems software. Topics include lexical analysis, parsing, semantic analysis, code generation; assemblers, loaders, linkers; debuggers. Operating Systems Concepts of modern operating systems; concurrent processes; process synchronization and communication; resource allocation; kernels; deadlock; memory management; file systems. Algorithms Introduction to the design and analysis of algorithms: basic analysis techniques (asymptotics, sums, recurrences); basic design techniques (divide and conquer, dynamic programming, greedy, amortization); acquiring an algorithm repertoire (sorting, median finding, strong components, spanning trees, shortest paths, maximum flow, string matching); and handling intractability (approximation algorithms, branch and bound). Automata Introduction to models of computation (finite automata, pushdown automata, Turing machines), representations of languages (regular expressions, context-free grammars), and the basic hierarchy of languages (regular, context-free, decidable, and undecidable languages). Geometric Algorithms The study of algorithms for geometric objects, using a computational geometry approach, with an emphasis on applications for graphics, VLSI, GIS, robotics, and sensor networks. Topics may include the representation and overlaying of maps, finding nearest neighbors, solving linear programming problems, and searching geometric databases.

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  • How to troubleshoot problem with OpenVpn Appliance Server not able to connect

    - by Peter
    1) I have a Windows Server 2008 Standard SP2 2) I am running Hyper-V and have the OpenSvn Appliance Server virtual running 3) I have configured it as it said, only issue was that the legacy network adapter does not have a setting the instructions mention "Enable spoofing of MAC Addresses". My understand is that before R2, this was on by default. 4) Server is running, web interfaces look good 5) I am trying to connect from a Vista 64 box and cannot 5a) If I set to UPD I am stuck at Authorizing and client log looks like: 10/11/09 15:00:42: INFO: OvpnConfig: connect... 10/11/09 15:00:42: INFO: Gui listen socket at 34567 10/11/09 15:00:42: INFO: sending start command to instantiator... 10/11/09 15:00:42: INFO: start 34567 ?C:\Users\Peter\AppData\Roaming\OpenVPNTech\config?02369512D0C82A04B88093022DA0226202218022A902264022AE022B? 10/11/09 15:00:42: INFO: Got line from MI->>INFO:OpenVPN Management Interface Version 1 -- type 'help' for more info 10/11/09 15:00:42: INFO: Got line from MI->>HOLD:Waiting for hold release 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: real-time state notification set to ON 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: bytecount interval changed 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold flag set to OFF 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold release succeeded 10/11/09 15:00:43: INFO: Got line from MI->>PASSWORD:Need 'Auth' username/password 10/11/09 15:00:43: INFO: Processing PASSWORD. 10/11/09 15:00:43: INFO: OvpnClient: setting need auth to true. 10/11/09 15:00:43: INFO: OvpnConfig: Setting need auth to true. 10/11/09 15:00:43: INFO: Got auth request from active_config from 0 10/11/09 15:00:47: INFO: Sending Credentials.... 10/11/09 15:00:47: INFO: Sending 25 bytes for username. 10/11/09 15:00:47: INFO: Sent 25 bytes for username. 10/11/09 15:00:47: INFO: Sending 30 bytes for password. 10/11/09 15:00:47: INFO: Sent 30 bytes for password. 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' username entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' password entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287647,WAIT,,, 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:0,42 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:54,42 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287648,AUTH,,, 10/11/09 15:00:50: INFO: Got line from MI->>BYTECOUNT:2560,2868 10/11/09 15:00:52: INFO: Got line from MI->>BYTECOUNT:2560,3378 5b) I setup server for tcp and try to connect, I get a loop of authorizing and reconnecting. Log looks like: 10/11/09 15:00:42: INFO: Got line from MI->>HOLD:Waiting for hold release 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: real-time state notification set to ON 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: bytecount interval changed 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold flag set to OFF 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold release succeeded 10/11/09 15:00:43: INFO: Got line from MI->>PASSWORD:Need 'Auth' username/password 10/11/09 15:00:43: INFO: Processing PASSWORD. 10/11/09 15:00:43: INFO: OvpnClient: setting need auth to true. 10/11/09 15:00:43: INFO: OvpnConfig: Setting need auth to true. 10/11/09 15:00:43: INFO: Got auth request from active_config from 0 10/11/09 15:00:47: INFO: Sending Credentials.... 10/11/09 15:00:47: INFO: Sending 25 bytes for username. 10/11/09 15:00:47: INFO: Sent 25 bytes for username. 10/11/09 15:00:47: INFO: Sending 30 bytes for password. 10/11/09 15:00:47: INFO: Sent 30 bytes for password. 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' username entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' password entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287647,WAIT,,, 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:0,42 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:54,42 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287648,AUTH,,, 10/11/09 15:00:50: INFO: Got line from MI->>BYTECOUNT:2560,2868 10/11/09 15:00:52: INFO: Got line from MI->>BYTECOUNT:2560,3378 10/11/09 15:00:54: INFO: Got line from MI->>BYTECOUNT:2560,3888 ... Is there anyway to turn on robust logging on the server to understand what is happening? Any ideas on how to hunt this down?

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  • Attempting Unauthorized operation - SQL 2008 R2 install

    - by Fred L
    I've been banging against this for a few days. Keep getting this unauthorized error when trying to install SQL 2008 R2 on a Windows 7 machine. I've changed permissions on the key, does not fix... Created an admin user, gave specific permissions on that key, does not fix... Disabled all firewalls, installed from a local admin, does not fix... I'm out of patience and ideas! :) Help? 2012-07-06 13:09:11 Slp: Sco: Attempting to set value AppName 2012-07-06 13:09:11 Slp: SetValue: HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\VSTAHostConfig\SSIS_ScriptComponent\2.0, Name = AppName 2012-07-06 13:09:11 Slp: Sco: Attempting to create base registry key HKEY_LOCAL_MACHINE, machine 2012-07-06 13:09:11 SSIS: Processing Registry ACLs for SID 'S-1-5-21-2383144575-3599344511-819193542-1074' 2012-07-06 13:09:11 Slp: Sco: Attempting to open registry subkey SOFTWARE\Microsoft\Microsoft SQL Server\100 2012-07-06 13:09:11 SSIS: Setting permision on registry key HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Microsoft SQL Server\100. 2012-07-06 13:09:11 Slp: Sco: Attempting to replace account with sid in security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be processed: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be returned: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Sco: Attempting to set security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Sco: Attempting to normalize security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Sco: Attempting to replace account with sid in security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be processed: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be returned: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Sco: Attempting to normalize security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Sco: Attempting to replace account with sid in security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be processed: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: ReplaceAccountWithSidInSddl -- SDDL to be returned: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:11 Slp: Prompting user if they want to retry this action due to the following failure: 2012-07-06 13:09:11 Slp: ---------------------------------------- 2012-07-06 13:09:11 Slp: The following is an exception stack listing the exceptions in outermost to innermost order 2012-07-06 13:09:11 Slp: Inner exceptions are being indented 2012-07-06 13:09:11 Slp: 2012-07-06 13:09:11 Slp: Exception type: Microsoft.SqlServer.Configuration.Sco.ScoException 2012-07-06 13:09:11 Slp: Message: 2012-07-06 13:09:11 Slp: Attempted to perform an unauthorized operation. 2012-07-06 13:09:11 Slp: Data: 2012-07-06 13:09:11 Slp: WatsonData = 100 2012-07-06 13:09:11 Slp: DisableRetry = true 2012-07-06 13:09:11 Slp: Inner exception type: System.UnauthorizedAccessException 2012-07-06 13:09:11 Slp: Message: 2012-07-06 13:09:11 Slp: Attempted to perform an unauthorized operation. 2012-07-06 13:09:11 Slp: Stack: 2012-07-06 13:09:11 Slp: at System.Security.AccessControl.Win32.GetSecurityInfo(ResourceType resourceType, String name, SafeHandle handle, AccessControlSections accessControlSections, RawSecurityDescriptor& resultSd) 2012-07-06 13:09:11 Slp: at System.Security.AccessControl.NativeObjectSecurity.CreateInternal(ResourceType resourceType, Boolean isContainer, String name, SafeHandle handle, AccessControlSections includeSections, Boolean createByName, ExceptionFromErrorCode exceptionFromErrorCode, Object exceptionContext) 2012-07-06 13:09:11 Slp: at Microsoft.SqlServer.Configuration.Sco.SqlRegistrySecurity..ctor(ResourceType resourceType, SafeRegistryHandle handle, AccessControlSections includeSections) 2012-07-06 13:09:11 Slp: at Microsoft.SqlServer.Configuration.Sco.SqlRegistrySecurity.Create(InternalRegistryKey key) 2012-07-06 13:09:11 Slp: at Microsoft.SqlServer.Configuration.Sco.InternalRegistryKey.GetAccessControl() 2012-07-06 13:09:11 Slp: at Microsoft.SqlServer.Configuration.Sco.InternalRegistryKey.SetSecurityDescriptor(String sddl, Boolean overwrite) 2012-07-06 13:09:11 Slp: ---------------------------------------- 2012-07-06 13:09:24 Slp: User has chosen to retry this action 2012-07-06 13:09:24 Slp: Sco: Attempting to normalize security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: Sco: Attempting to replace account with sid in security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: ReplaceAccountWithSidInSddl -- SDDL to be processed: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: ReplaceAccountWithSidInSddl -- SDDL to be returned: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: Sco: Attempting to normalize security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: Sco: Attempting to replace account with sid in security descriptor D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: ReplaceAccountWithSidInSddl -- SDDL to be processed: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: ReplaceAccountWithSidInSddl -- SDDL to be returned: D:(A;OICI;KR;;;S-1-5-21-2383144575-3599344511-819193542-1074) 2012-07-06 13:09:24 Slp: Prompting user if they want to retry this action due to the following failure: 2012-07-06 13:09:24 Slp: ----------------------------------------

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  • How to troubleshoot problem with OpenVPN Appliance Server not able to connect

    - by Peter
    1) I have a Windows Server 2008 Standard SP2 2) I am running Hyper-V and have the OpenVPN Appliance Server virtual running 3) I have configured it as it said, only issue was that the legacy network adapter does not have a setting the instructions mention "Enable spoofing of MAC Addresses". My understand is that before R2, this was on by default. 4) Server is running, web interfaces look good 5) I am trying to connect from a Vista 64 box and cannot 5a) If I set to UPD I am stuck at Authorizing and client log looks like: 10/11/09 15:00:42: INFO: OvpnConfig: connect... 10/11/09 15:00:42: INFO: Gui listen socket at 34567 10/11/09 15:00:42: INFO: sending start command to instantiator... 10/11/09 15:00:42: INFO: start 34567 ?C:\Users\Peter\AppData\Roaming\OpenVPNTech\config?02369512D0C82A04B88093022DA0226202218022A902264022AE022B? 10/11/09 15:00:42: INFO: Got line from MI->>INFO:OpenVPN Management Interface Version 1 -- type 'help' for more info 10/11/09 15:00:42: INFO: Got line from MI->>HOLD:Waiting for hold release 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: real-time state notification set to ON 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: bytecount interval changed 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold flag set to OFF 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold release succeeded 10/11/09 15:00:43: INFO: Got line from MI->>PASSWORD:Need 'Auth' username/password 10/11/09 15:00:43: INFO: Processing PASSWORD. 10/11/09 15:00:43: INFO: OvpnClient: setting need auth to true. 10/11/09 15:00:43: INFO: OvpnConfig: Setting need auth to true. 10/11/09 15:00:43: INFO: Got auth request from active_config from 0 10/11/09 15:00:47: INFO: Sending Credentials.... 10/11/09 15:00:47: INFO: Sending 25 bytes for username. 10/11/09 15:00:47: INFO: Sent 25 bytes for username. 10/11/09 15:00:47: INFO: Sending 30 bytes for password. 10/11/09 15:00:47: INFO: Sent 30 bytes for password. 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' username entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' password entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287647,WAIT,,, 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:0,42 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:54,42 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287648,AUTH,,, 10/11/09 15:00:50: INFO: Got line from MI->>BYTECOUNT:2560,2868 10/11/09 15:00:52: INFO: Got line from MI->>BYTECOUNT:2560,3378 5b) I setup server for tcp and try to connect, I get a loop of authorizing and reconnecting. Log looks like: 10/11/09 15:00:42: INFO: Got line from MI->>HOLD:Waiting for hold release 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: real-time state notification set to ON 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: bytecount interval changed 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold flag set to OFF 10/11/09 15:00:43: INFO: Got line from MI->SUCCESS: hold release succeeded 10/11/09 15:00:43: INFO: Got line from MI->>PASSWORD:Need 'Auth' username/password 10/11/09 15:00:43: INFO: Processing PASSWORD. 10/11/09 15:00:43: INFO: OvpnClient: setting need auth to true. 10/11/09 15:00:43: INFO: OvpnConfig: Setting need auth to true. 10/11/09 15:00:43: INFO: Got auth request from active_config from 0 10/11/09 15:00:47: INFO: Sending Credentials.... 10/11/09 15:00:47: INFO: Sending 25 bytes for username. 10/11/09 15:00:47: INFO: Sent 25 bytes for username. 10/11/09 15:00:47: INFO: Sending 30 bytes for password. 10/11/09 15:00:47: INFO: Sent 30 bytes for password. 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' username entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->SUCCESS: 'Auth' password entered, but not yet verified 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287647,WAIT,,, 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:0,42 10/11/09 15:00:48: INFO: Got line from MI->>BYTECOUNT:54,42 10/11/09 15:00:48: INFO: Got line from MI->>STATE:1255287648,AUTH,,, 10/11/09 15:00:50: INFO: Got line from MI->>BYTECOUNT:2560,2868 10/11/09 15:00:52: INFO: Got line from MI->>BYTECOUNT:2560,3378 10/11/09 15:00:54: INFO: Got line from MI->>BYTECOUNT:2560,3888 ... Is there anyway to turn on robust logging on the server to understand what is happening? Any ideas on how to hunt this down?

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  • Every month, scheduled task fails and password must be reset - why?

    - by Ducain
    [NOTE: I posted this originally at StackOverflow but it got no traction there - reposting here.] We have a bit of software installed at a few client locations that runs (via Windows task scheduler) a few times each day. In ONLY ONE of the client locations, we have a unique problem: each month, the task will stop working, after running every day for weeks. Twice now it's failed on the 2nd of the month. When I walk the client through troubleshooting it, we've found that it can't start - access denied. To fix it, we simply re-enter the same exact password, and then off it goes happy as a clam. I've never heard of this issue, and their IT people say they don't have anything running once a month that might cause that. I'm at a complete loss here. Any ideas as to why this might be happening? Further details: Windows XP pro machine. Task is being fired with credentials from a local admin account. Computer is always on, and connected to the net.

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  • If I ssh to a domain provided by dyndns, does my password go through them?

    - by D Connors
    I'm running Ubuntu on my work PC, and my work place provides me with a static IP address but not with a domain. It's sometimes useful for me to connect to that PC through ssh, but it's not common enough for me to instantly remember the IP number. So I set um a dyndns account, and associated a short and intuitive domain name to that IP. Here's my question, when I try to ssh to the domain, it asks me $ ssh [email protected] The authenticity of host 'something.there.foo (xx.xx.xx.xx)' can't be established. RSA key fingerprint is 'ALPHANUMERIC STRING' Are you sure you want to continue connecting (yes/no)? That surprised me a little bit. I have already registered the RSA fingerprint by connecting directly to the IP address. I thought the domain name was simply a convenient way of pointing me in the right direction (i. e. the ip address), but that message makes me think my data is actually going through their servers or something. Which one is it? Am I sending my password through someone else's server? Or is ssh just really really careful, thus warning me even if the final destination is a know host? The ssh server I'm using is the openssh-server package.

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  • How to share data between SSRS Security and Data Processing extension?

    - by user2904681
    I've spent a lot of time trying to solve the issue pointed in title and have no found a solution yet. I use MS SSRS 2012 with custom Security (based on Form Authentication and ClaimsPrincipal) and Data Processing extensions. In Data extension level I need to apply filter programmatically based on one of the claim which I have access in Security extension level only. Here is the problem: I do know how to pass the claim from Security to Data Processing extension code... What I've tried: IAuthenticationExtension.LogonUser(string userName, string password, string authority) { ... ClaimsPrincipal claimsPrincipal = CreateClaimsPrincipal(...); Thread.CurrentPrincipal = claimsPrincipal; HttpContext.Current.User = claimsPrincipal; ... }; But it doesn't work. It seems SSRS overrides it within either GenericPrincipal or FormsIdentity internally. The possible workaround I'm thinking about (but haven't checked it yet): 1. Create HttpModule which will create HttpContext with all required information (minus: will be invoke getting claims each time - huge operation) 2. Write to custom SQL table to store logged users information which is required for Data extension and then read it 3. try somehow to append to cookies due to LogOn and then read each time on IAuthenticationExtension.GetUserInfo and fill HttpContext None of them seems to be a good solution. I would be grateful for any help/advise/comments.

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  • April 2010 Critical Patch Update Released

    - by eric.maurice
    Hi, this is Eric Maurice. Today Oracle released the April 2010 Critical Patch Update (CPUApr2010),the first one to include security fixes for Oracle Solaris. Today's Critical Patch Update (CPU) provides 47 new security fixes across the following product families: Oracle Database Server, Oracle Fusion Middleware, Oracle Collaboration Suite, Oracle E-Business Suite, Oracle PeopleSoft Enterprise, Oracle Life Sciences, Retail, and Communications Industry Suites, and Oracle Solaris. 28 of these 47 new vulnerabilities are remotely exploitable without authentication, but the criticality of the affected components and the severity of these vulnerabilities vary greatly. Customers should, as usual, refer to the Risk Matrices in the CPU Advisory to assess the relevance of these fixes for their environment (and the urgency with which to apply the fixes). 7 of the 47 new vulnerabilities affect various versions of Oracle Database Server. None of these 7 vulnerabilities are remotely exploitable without authentication. Furthermore, none of these fixes are applicable to client-only deployments. The most severe CVSS Base Score for the Database Server vulnerabilities is 7.1. As a reminder, information about Oracle's use of the CVSS 2.0 standard can be found in Note 394487.1 (My Oracle Support subscription required). Note that this Critical Patch Update includes fixes for vulnerabilities that were publicly disclosed by David Litchfield at the BlackHat DC Conference in early February (CVE-2010-0866 and CVE-2010-0867). 5 of the 47 new vulnerabilities affect various components of the Oracle Fusion Middleware product family. The highest CVSS Base Score for these vulnerabilities is 7.5. Note that the patches for Oracle WebLogic Server are cumulative and this Critical Patch Update therefore also includes a fix for a vulnerability (CVE-2010-0073) that was the subject of a Security Alert issued by Oracle on February 4, 2010. Customers, who have not applied the previously-released patch, should apply today's Critical Patch Update as soon as possible. As stated at the beginning of this blog, it is also noteworthy to highlight that this Critical Patch Update provides 16 new fixes for the Sun product line. With the recent close of the Sun acquisition both security organizations have worked diligently to align Sun's previous security practices with Oracle's. Java users know that Oracle released a Critical Patch Update for Java SE and Java For Business earlier this month (in accordance with the Java patching schedule previously published by Sun Microsystems). Please note that for the first time, the Java advisories included CVSS Scores to help assess the severity of the new vulnerabilities fixed with the advisory. The rapid inclusion of the Solaris product lines in the Critical Patch Update and the extension of Oracle Software Security Assurance to Sun technologies are evidence of the flexibility of Oracle's security assurance programs. These should also result in tangible security benefits for the users of the Oracle hardware and software stack (such as a predictable patching schedule for all Oracle products).

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  • What I like about WIF&rsquo;s Claims-based Authorization

    - by Your DisplayName here!
    In “traditional” .NET with its IPrincipal interface and IsInRole method, developers were encouraged to write code like this: public void AddCustomer(Customer customer) {     if (Thread.CurrentPrincipal.IsInRole("Sales"))     {         // add customer     } } In code reviews I’ve seen tons of code like this. What I don’t like about this is, that two concerns in your application get tightly coupled: business and security logic. But what happens when the security requirements change – and they will (e.g. members of the sales role and some other people from different roles need to create customers)? Well – since your security logic is sprinkled across your project you need to change the security checks in all relevant places (and make sure you don’t forget one) and you need to re-test, re-stage and re-deploy the complete app. This is clearly not what we want. WIF’s claims-based authorization encourages developers to separate business code and authorization policy evaluation. This is a good thing. So the same security check with WIF’s out-of-the box APIs would look like this: public void AddCustomer(Customer customer) {     try     {         ClaimsPrincipalPermission.CheckAccess("Customer", "Add");           // add customer     }     catch (SecurityException ex)     {         // access denied     } } You notice the fundamental difference? The security check only describes what the code is doing (represented by a resource/action pair) – and does not state who is allowed to invoke the code. As I mentioned earlier – the who is most probably changing over time – the what most probably not. The call to ClaimsPrincipalPermission hands off to another class called the ClaimsAuthorizationManager. This class handles the evaluation of your security policy and is ideally in a separate assembly to allow updating the security logic independently from the application logic (and vice versa). The claims authorization manager features a method called CheckAccess that retrieves three values (wrapped inside an AuthorizationContext instance) – action (“add”), resource (“customer”) and the principal (including its claims) in question. CheckAccess then evaluates those three values and returns true/false. I really like the separation of concerns part here. Unfortunately there is not much support from Microsoft beyond that point. And without further tooling and abstractions the CheckAccess method quickly becomes *very* complex. But still I think that is the way to go. In the next post I will tell you what I don’t like about it (and how to fix it).

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  • Gawker Passwords

    - by Nick Harrison
    There has been much news about the hack of the Gawker web sites. There has even been an analysis of the common passwords found. This list is embarrassing in many ways. The most common password was "123456". The second most common password was "password". Much has also been written providing advice on how to create good passwords. This article provides some interesting advice, none of which should be taken. Anyone reading my blog, probably already knows the importance of strong passwords, so I am not going to reiterate the reasons here. My target audience is more the folks defining password complexity requirements. A user cannot come up with a strong password, if we have complexity requirements that don't make sense. With that in mind, here are a few guidelines:  Long Passwords Insist on long passwords. In some cases, you may need to change to allow a long password. I have seen many places that cap passwords at 8 characters. Passwords need to be at least 8 characters minimal. Consider how much stronger the passwords would be if you double the length. Passwords that are 15-20 characters will be that much harder to crack. There is no need to have limit passwords to 8 characters. Don't Require Special Characters Many complexity rules will require that your password include a capital letter, a lower case letter, a number, and one of the "special" characters, the shits above the number keys. The problem with such rules is that the resulting passwords are harder to remember. It also means that you will have a smaller set of characters in the resulting passwords. If you must include one of the 9 digits and one of the 9 "special" characters, then you have dramatically reduced the character set that will make up the final password. Two characters will be one of 10 possible values instead of one of 70. Two additional characters will be one of 26 possible characters instead of a 70 character potential character set. If you limit passwords to 8 characters, you are left with only 7 characters having the full set of 70 potential values. With these character restrictions in place, there are 1.6 x1012 possible passwords. Without these special character restrictions, but allowing numbers and special characters, you get a total of 5.76x1014 possible passwords. Even if you only allowed upper and lower case characters, you will still have 2.18X1014 passwords. You can do the math any number of ways, requiring special characters will always weaken passwords. Now imagine the number of passwords when you require more than 8 characters.  If you are responsible for defining complexity rules, I urge you to take these guidelines into account. What other guidelines do you follow?

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  • Root users and mysql: `sudo mysql` vs `/root/.my.cnf`

    - by user67641
    I have a /root/.my.cnf file which stores the mysql root user's password: [client] password = "my password" When I log in as system root and enter mysql, I get a passwordless login: myuser@local:$ sudo su root@local:$ mysql mysql> But when I try to do the same just using sudo, I get access denied: myuser@local:$ sudo mysql ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) How can I get sudo mysql to log me in as the mysql root user, without entering a password?

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  • Why are all logins disabled in the virtual terminal after enabling root account from desktop?

    - by Mitch
    Just for testing purposes, I went a head and enabled the root account, by using the commands below: sudo passwd root [sudo] password for abed: Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully Once that happened, I went ahead and did Ctrl+Alt+F1, to get to the first virtual console, and at the login prompt I try logging in as abed, su, root, all comeback with login incorrect. Why is that happening, and how can I fix it.

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  • Deploy EAR with Websphere Application Server wsadmin.bat without losing security role-mapping?

    - by Tommy
    We're running CI towards our WAS with wsadmin.bat The applications are updated with this command $AdminApp update ${projectName}EAR app {-operation update -update.ignore.new -contents {${artifactsDir}/${projectName}-${buildVersion}.ear}} This causes all the "Security role to user/group mapping"-settings to reset, even though all the other settings are preserved with the -update.ignore.new Anyone know how to fix this?

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