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  • django: can't adapt error when importing data from postgres database

    - by Oleg Tarasenko
    Hi, I'm having strange error with installing fixture from dumped data. I am using psycopg2, and django1.1.1 silver:probsbox oleg$ python manage.py loaddata /Users/oleg/probs.json Installing json fixture '/Users/oleg/probs' from '/Users/oleg/probs'. Problem installing fixture '/Users/oleg/probs.json': Traceback (most recent call last): File "/opt/local/lib/python2.5/site-packages/django/core/management/commands/loaddata.py", line 153, in handle obj.save() File "/opt/local/lib/python2.5/site-packages/django/core/serializers/base.py", line 163, in save models.Model.save_base(self.object, raw=True) File "/opt/local/lib/python2.5/site-packages/django/db/models/base.py", line 495, in save_base result = manager._insert(values, return_id=update_pk) File "/opt/local/lib/python2.5/site-packages/django/db/models/manager.py", line 177, in _insert return insert_query(self.model, values, **kwargs) File "/opt/local/lib/python2.5/site-packages/django/db/models/query.py", line 1087, in insert_query return query.execute_sql(return_id) File "/opt/local/lib/python2.5/site-packages/django/db/models/sql/subqueries.py", line 320, in execute_sql cursor = super(InsertQuery, self).execute_sql(None) File "/opt/local/lib/python2.5/site-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/opt/local/lib/python2.5/site-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) ProgrammingError: can't adapt First I've checked similar issues on internet. This one seemed to be very related: http://code.djangoproject.com/ticket/5996, as my data has many non ASCII symbols But actually I've checked my django installation and it's ok there Could you advice what is wrong

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  • TSQL -- Make it better

    - by user319353
    Hi: -- Very Narrow (all IDs are passed in) IF(@EmpID IS NOT NULL AND @DeptID IS NOT NULL AND @CityID IS NOT NULL) BEGIN SELECT e.EmpName ,d.DeptName ,c.CityName FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE e.EmpID = @EmpID END -- Just 2 IDs passed in ELSE IF(@DeptID IS NOT NULL AND @CityID IS NOT NULL) BEGIN SELECT e.EmpName ,d.DeptName ,NULL AS [CityName] FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE d.deptID = @DeptID END -- Very Broad (just 1 ID passed in) ELSE IF(@CityID IS NOT NULL) BEGIN SELECT e.EmpName ,NULL AS [DeptName] ,NULL AS [CityName] FROM Employee e WITH (NOLOCK) JOIN Department d WITH (NOLOCK) ON e.deptid = d.deptid JOIN City c WITH (NOLOCK) ON e.CityID = c.CityID WHERE c.CityID = @CityID END -- None (Nothing passed in) ELSE BEGIN SELECT NULL AS [EmpName] ,NULL AS [DeptName] ,NULL AS [CityName] END Question: Is there any better way (OR specifically can I do anything without IF...ELSE condition?

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  • Making selectable again a WPF TreeviewITem after the first click

    - by pileggi
    Hi, I have a TreeVIew WPF with 2 Levels of Data. I have deleted the ToogleButton from the TreeViewItemTemplate. Now I'd like to expand / collapse the groups with a single mouse-click (not with a double click as the default behaviour). I have tried in this way: Private Sub tvArt_SelectedItemChanged(ByVal sender As System.Object, _ ByVal e As RoutedPropertyChangedEventArgs(Of System.Object)) Handles tvArt.SelectedItemChanged If e.NewValue Is Nothing = False Then Dim ri As P_RicambiItem = TryCast(e.NewValue, P_RicambiItem) If ri Is Nothing = False Then If ri.isExpanded Then ri.isExpanded = False Else ri.isExpanded = True End If ri.isSelected = False End If End If End Sub Using my properties "isExpanded" and "isSelected" in the collection data source. But it works only halfway: after the first click, infact, I can't click for a second time on the same item, because, even if I've deselected it, the event handler "remembers" that it was the last selected item and it doesn't capture the event "SelectedItemChanged". How can I do? Thanks a lot, Pileggi

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  • Does binarywriter.flush() also flush the underlying filestream object?

    - by jacob sebastian
    I have got a code snippet as follows: Dim fstream = new filestream(some file here) dim bwriter = new binarywriter(fstream) while not end of file read from source file bwriter.write() bwriter.flush() end while The question I have is the following. When I call bwriter.flush() does it also flush the fstream object? Or should I have to explicitly call fstream.flush() such as given in the following example: while not end of file read from source file bwriter.write() bwriter.flush() fstream.flush() end while A few people suggested that I need to call fstream.flush() explicitly to make sure that the data is written to the disk (or the device). However, my testing shows that the data is written to the disk as soon as I call flush() method on the bwriter object. Can some one confirm this?

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  • Rails XML Builder - Code refactoring

    - by Vijay Dev
    I have written the following code in my Rails app to generate XML. I am using Aptana IDE to do Rails development and the IDE shows a warning that the code structure is identical in both the blocks. What changes can be done to the code to remove the duplicity in structure? Is there any other way to write the same? xml.roles do @rolesList.each do |r| xml.role(:id => r["role_id"], :name => r["role_name"]) end end xml.levels do @levelsList.each do |lvl| xml.level(:id => lvl["level_id"], :name => lvl["level_name"]) end end

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  • How can one setup a version control system on a local network, without a server?

    - by Andrew
    Edit: Ok so I learned that I guess I need an distributed source control, however are there any UI based ones, and do they allow you to merge with other users on the network? This is kind of a two part question, so here it goes. I want to start developing a web application at home (with multiple developers). However, I don't have a dedicated server nor want to pay for on. So first, I don't know which version control system to use for this case, as at work we mostly have TFS setup, so I am not to familiar with whats out there. What are the best free CVS/SVN tools out there? Second, is it possible to somehow setup the CVS/SVN where there is no dedicated server and both clients store up to one week of the source code from the last check-in? Also, it would be helpful if it could integrate with visual studio, again this isn't that important at all. Problem: There are Five users, one is a Server. Server Connected: All Ok Server Disconnected: No one can share. What I am looking for: No Server: Users still have versioning based on version id of last check-in. Users must check all version on network to make sure they aren't outdated based on their last version id. If not check-in, otherwise merge/get latest. If they are update checkin, and set current version id +1.

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  • excel:mysql: rs.Update crashes

    - by every_answer_gets_a_point
    i am connecting to mysql from excel and updating a table. as soon as i get to .update (rs.update) excel crashes. am i doing something wrong? Option Explicit Dim oConn As ADODB.Connection Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=pas;" & _ "Option=3" End Sub Function esc(txt As String) esc = Trim(Replace(txt, "'", "\'")) End Function Private Sub InsertData() Dim dpath, atime, rtime, lcalib, aname, rname, bstate, instrument As String Dim rs As ADODB.Recordset Set rs = New ADODB.Recordset ConnectDB With wsBooks rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable Worksheets.Item("Report 1").Select dpath = Trim(Range("B2").Text) atime = Trim(Range("B3").Text) rtime = Trim(Range("B4").Text) lcalib = Trim(Range("B5").Text) aname = Trim(Range("B6").Text) rname = Trim(Range("B7").Text) bstate = Trim(Range("B8").Text) ' instrument = GetInstrFromXML(wbBook.FullName) With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = bstate ' .Fields("instrument") = "NA" .Update ' stores the new record End With ' get the last id Set rs = oConn.Execute("SELECT @@identity", , adCmdText) 'MsgBox capture_id rs.Close Set rs = Nothing End With End Sub

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  • multicols to respect \nopagebreak

    - by hack.augusto
    I have a list inside multicols, but the list item is being break, how could I suppress this behavior? here is a bit of code: \documentclass{article} \usepackage{multicol} \begin{document} \begin{multicols}{2} \begin{itemize} \item{1} \subitem{2} % i want to break here \item{asdf} % its being break here \subitem{qwerty} % or to break here \item{lorem} \subitem{iptsum} \subitem{dvorak} \end{itemize} \end{multicols} \end{document}

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  • Having problems with sqlDataReader

    - by Anthony
    I am using a sqlDataReader to get data and set it to session variables. The problem is it doesn't want to work with expressions. I can reference any other column in the table, but not the expressions. The SQL does work. The code is below. Thanks in advance, Anthony Using myConnectionCheck As New SqlConnection(myConnectionString) Dim myCommandCheck As New SqlCommand() myCommandCheck.Connection = myConnectionCheck myCommandCheck.CommandText = "SELECT Projects.Pro_Ver, Projects.Pro_Name, Projects.TL_Num, Projects.LP_Num, Projects.Dev_Num, Projects.Val_Num, Projects.Completed, Flow.Initiate_Date, Flow.Requirements, Flow.Req_Date, Flow.Dev_Review, Flow.Dev_Review_Date, Flow.Interface, Flow.Interface_Date, Flow.Approval, Flow.Approval_Date, Flow.Test_Plan, Flow.Test_Plan_Date, Flow.Dev_Start, Flow.Dev_Start_Date, Flow.Val_Start, Flow.Val_Start_Date, Flow.Val_Complete, Flow.Val_Complete_Date, Flow.Stage_Production, Flow.Stage_Production_Date, Flow.MKS, Flow.MKS_Date, Flow.DIET, Flow.DIET_Date, Flow.Closed, Flow.Closed_Date, Flow.Dev_End, Flow.Dev_End_Date, Users_1.Email AS Expr1, Users_2.Email AS Expr2, Users_3.Email AS Expr3, Users_4.Email AS Expr4, Users_4.FNAME, Users_3.FNAME AS Expr5, Users_2.FNAME AS Expr6, Users_1.FNAME AS Expr7 FROM Projects INNER JOIN Users AS Users_1 ON Projects.TL_Num = Users_1.PIN INNER JOIN Users AS Users_2 ON Projects.LP_Num = Users_2.PIN INNER JOIN Users AS Users_3 ON Projects.Dev_Num = Users_3.PIN INNER JOIN Users AS Users_4 ON Projects.Val_Num = Users_4.PIN INNER JOIN Flow ON Projects.id = Flow.Flow_Pro_Num WHERE id = " myCommandCheck.CommandText += QSid myConnectionCheck.Open() myCommandCheck.ExecuteNonQuery() Dim count As Int16 = myCommandCheck.ExecuteScalar If count = 1 Then Dim myDataReader As SqlDataReader myDataReader = myCommandCheck.ExecuteReader() While myDataReader.Read() Session("TL_email") = myDataReader("Expr1").ToString() Session("PE_email") = myDataReader("Expr2").ToString() Session("DEV_email") = myDataReader("Expr3").ToString() Session("VAL_email") = myDataReader("Expr4").ToString() Session("Project_Name") = myDataReader("Pro_Name").ToString() End While myDataReader.Close() End If End Using

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  • Refer to similar associated models with a common name

    - by Horace Loeb
    I have these models: class Bill < ActiveRecord::Base has_many :calls has_many :text_messages end class Call < ActiveRecord::Base belongs_to :bill end class TextMessage < ActiveRecord::Base belongs_to :bill end Now, in my domain calls and text messages are both "the same kind of thing" -- i.e., they're both "bill items". So I'd like some_bill.bill_items to return all calls and text messages associated with that bill. What's the best way to do this?

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  • Tree Node Checked behavior on a TreeView in Compact Framework 3.5 running on Windows Mobile 6.5

    - by Hydroslide
    I have been upgrading an existing .NET Windows Mobile application to use the 3.5 version of the compact framework and to run on Windows Mobile 6.5. I have a form with a TreeView. The TreeView.Checkboxes property is set to true so that each node has a check box. This gives no trouble in all previous versions of Windows Mobile. However, in version 6.5 when you click on a check box it appears to check and then uncheck instantaneously. But it only raises the AfterCheck event once. The only way I can get a check to stick is by double clicking it (which is the wrong behavior). Has anyone seen this behavior? Does anyone know of a workaround for it? I have included a simple test form. Dump this form into a Visual Studio 2008 Smart Device application targeted at Windows Mobile 6 to see what I mean. Public Class frmTree Inherits System.Windows.Forms.Form #Region " Windows Form Designer generated code " Public Sub New() MyBase.new() ' This call is required by the Windows Form Designer. InitializeComponent() ' Add any initialization after the InitializeComponent() call. End Sub 'Form overrides dispose to clean up the component list. <System.Diagnostics.DebuggerNonUserCode()> _ Protected Overrides Sub Dispose(ByVal disposing As Boolean) If disposing AndAlso components IsNot Nothing Then components.Dispose() End If MyBase.Dispose(disposing) End Sub 'Required by the Windows Form Designer Private components As System.ComponentModel.IContainer Friend WithEvents TreeView1 As System.Windows.Forms.TreeView Private mainMenu1 As System.Windows.Forms.MainMenu 'NOTE: The following procedure is required by the Windows Form Designer 'It can be modified using the Windows Form Designer. 'Do not modify it using the code editor. <System.Diagnostics.DebuggerStepThrough()> _ Private Sub InitializeComponent() Dim TreeNode1 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node0") Dim TreeNode2 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node2") Dim TreeNode3 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node3") Dim TreeNode4 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node4") Dim TreeNode5 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node1") Dim TreeNode6 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node5") Dim TreeNode7 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node6") Dim TreeNode8 As System.Windows.Forms.TreeNode = New System.Windows.Forms.TreeNode("Node7") Me.mainMenu1 = New System.Windows.Forms.MainMenu Me.TreeView1 = New System.Windows.Forms.TreeView Me.SuspendLayout() ' 'TreeView1 ' Me.TreeView1.CheckBoxes = True Me.TreeView1.Location = New System.Drawing.Point(37, 41) Me.TreeView1.Name = "TreeView1" TreeNode2.Text = "Node2" TreeNode3.Text = "Node3" TreeNode4.Text = "Node4" TreeNode1.Nodes.AddRange(New System.Windows.Forms.TreeNode() {TreeNode2, TreeNode3, TreeNode4}) TreeNode1.Text = "Node0" TreeNode6.Text = "Node5" TreeNode7.Text = "Node6" TreeNode8.Text = "Node7" TreeNode5.Nodes.AddRange(New System.Windows.Forms.TreeNode() {TreeNode6, TreeNode7, TreeNode8}) TreeNode5.Text = "Node1" Me.TreeView1.Nodes.AddRange(New System.Windows.Forms.TreeNode() {TreeNode1, TreeNode5}) Me.TreeView1.Size = New System.Drawing.Size(171, 179) Me.TreeView1.TabIndex = 0 ' 'frmTree ' Me.AutoScaleDimensions = New System.Drawing.SizeF(96.0!, 96.0!) Me.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Dpi Me.AutoScroll = True Me.ClientSize = New System.Drawing.Size(240, 268) Me.Controls.Add(Me.TreeView1) Me.Menu = Me.mainMenu1 Me.Name = "frmTree" Me.Text = "frmTree" Me.ResumeLayout(False) End Sub #End Region End Class

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  • Is there a better way to convert SQL datetime from hh:mm:ss to hhmmss?

    - by Johann J.
    I have to write an SQL view that returns the time part of a datetime column as a string in the format hhmmss (apparently SAP BW doesn't understand hh:mm:ss). This code is the SAP recommended way to do this, but I think there must be a better, more elegant way to accomplish this TIME = case len(convert(varchar(2), datepart(hh, timecolumn))) when 1 then /* Hour Part of TIMES */ case convert(varchar(2), datepart(hh, timecolumn)) when '0' then '24' /* Map 00 to 24 ( TIMES ) */ else '0' + convert(varchar(1), datepart(hh, timecolumn)) end else convert(varchar(2), datepart(hh, timecolumn)) end + case len(convert(varchar(2), datepart(mi, timecolumn))) when 1 then '0' + convert(varchar(1), datepart(mi, timecolumn)) else convert(varchar(2), datepart(mi, timecolumn)) end + case len(convert(varchar(2), datepart(ss, timecolumn))) when 1 then '0' + convert(varchar(1), datepart(ss, timecolumn)) else convert(varchar(2), datepart(ss, timecolumn)) end This accomplishes the desired result, 21:10:45 is displayed as 211045. I'd love for something more compact and easily readable but so far I've come up with nothing that works.

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  • Determine whether a canvas has been inserted into each page

    - by Hadi Teo
    Hi, Currently i have a code which will print OMR Mark on each pages. Basically i insert a canvas into each page and subsequently an OMR Mark Line Series are inserted into the canvas. Recently i found an issue that somehow one of the canvas is placed out of a page and it appears at the previous page instead of the current page. Below is the code snippet in how i inserted canvas as well as OMR Marks into each page: ' Start Code Snippet Sub GenerateOMR() Dim ShpCanvas As Shape Dim MaxPages As Integer Dim PNo As Integer ClearOMR MaxPages = Selection.Information(wdNumberOfPagesInDocument) For PNo = 1 To MaxPages Selection.GoTo What:=wdGoToPage, Which:=wdGoToFirst, Count:=PNo, Name:="" Select Case PNo Case 1 Set ShpCanvas = ActiveDocument.Shapes.AddCanvas(0, 0.5, 600, 300) Case Else Set ShpCanvas = ActiveDocument.Shapes.AddCanvas(0, 0, 600, 300) End Select ' Add a canvas on each page With ShpCanvas .Name = "OMR_Canvas_" & CStr(PNo) .RelativeHorizontalPosition = wdRelativeHorizontalPositionPage .RelativeVerticalPosition = wdRelativeVerticalPositionPage End With ' Insert a white background rectange and remove the rectangle border line With ShpCanvas.CanvasItems.AddShape(msoShapeRectangle, 536, 0, 64, 300) .Name = "OMR_WhiteBackground_" & CStr(PNo) .Fill.ForeColor.RGB = RGB(255, 255, 255) .Line.ForeColor.RGB = RGB(255, 255, 255) End With PrintOMRPage ShpCanvas, PNo Next PNo End Sub ' End Code Snippet There is a custom method called PrintOMRPage method which is not relevant here. My question now, how do i know whether a canvas has been inserted into a page ? Basically i will loop in all the pages and check whether a canvas has been inserted into that page. Apparently i cannot find the correct way. I have tried to check using ActiveDocument.Shapes(1).Top and validate whether the Top position is a negative value. But apparently the Top position is always measured from the top of each page. Thanks for the help. hadi teo

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  • ModalPopupExtender + ASP.NET AJAX: Can't page grid

    - by Alex
    I'm trying to page and sort my datagrid wich is inside a modalpopupextender but I can't page it in any way, already tried with , put the updatepanel inside, outside, in the middle (loL) and it does NOT work. modal popup does not get closed but the grid just dissapear. Code: Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load If Not Page.IsPostBack Then BindData() End If End Sub Private Sub btnSearch_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btnSearch.Click SqlServerDS.SelectCommand = "SELECT * FROM emp WHERE name LIKE '%" & txtSearchName.Text & "%'" BindData() End Sub Private Sub BindData() grdSearch.DataSource = SqlServerDS grdSearch.DataBind() End Sub Private Sub grdBuscaPaciente_PageIndexChanging(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewPageEventArgs) Handles grdSearch.PageIndexChanging grdSearch.PageIndex = e.NewPageIndex BindData() End Sub Inside the Designer, this is the code h: <modalpopupextender> </modalpopupextender> <panel> <updatepanel> <gridview> </gridview> </updatepanel> </panel>

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  • Design-time failure: WPF, Usercontrols and Namespaces

    - by Simon Woods
    Hi I have a very simple WPF project comprising a Window and Usercontrol. I'm very much in a learning phase. It works fine when I run it. However, I am unable to see the form in design time. The problem, I believe is something to do with namespaces, but I don't understand where. It may well be a simple error Main Window XML <Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:views="clr-namespace:UserLogin" x:Class="UserLogin.MainView" x:Name="MainViewWindow" mc:Ignorable="d" Title="Login" Height="141" Width="347" > <Grid> <views:LoginView /> </Grid> </Window> Main Window CodeBehind Imports Microsoft.VisualBasic Imports System Imports System.Windows Imports UserLogin Namespace UserLogin Partial Public Class MainView Inherits System.Windows.Window Public Sub New() InitializeComponent() End Sub End Class End Namespace Usercontrol XAML <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" x:Class="UserLogin.LoginView" x:Name="LoginViewControl" mc:Ignorable="d" d:DesignHeight="96" d:DesignWidth="298"> <Grid Height="96" Width="298"> <Button Command="{Binding OKCommand}" Height="21" Margin="0,0,90,16" Name="btnOK" VerticalAlignment="Bottom" HorizontalAlignment="Right" Width="76">OK</Button> <Button Command="{Binding CancelCommand}" Height="21" HorizontalAlignment="Right" Margin="0,0,9,16" Name="btnCancel" VerticalAlignment="Bottom" Width="75">Cancel</Button> <Label Height="23" HorizontalAlignment="Left" Margin="10,5,0,0" Name="Label1" VerticalAlignment="Top" Width="85">Name:</Label> <Label HorizontalAlignment="Left" Margin="10,32,0,0" Name="Label2" Width="85" Height="29" VerticalAlignment="Top">Password:</Label> <TextBox Margin="0,31,6,0" Name="txtPassword" Height="22" VerticalAlignment="Top" HorizontalAlignment="Right" Width="182" /> <ComboBox Height="22" Margin="110,6,6,0" Name="cboNames" VerticalAlignment="Top" /> </Grid> </UserControl> Usercontrol CodeBehind Imports Microsoft.VisualBasic Imports System Imports UserLogin Namespace UserLogin Partial Public Class LoginView Inherits System.Windows.Controls.UserControl Public Sub New() InitializeComponent() End Sub End Class End Namespace I think I'm missing something this namespace xmlns:views="clr-namespace:UserLogin" since intellisense doesn't give me the usercontrol declared within it in the XAML designer but rather reports the error "Unable to load the metadata for the assembly ... etc etc" Thx for any suggestions Simon

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  • Cucumber could not find table; but its there. What is going on?

    - by JZ
    I'm working with cucumber and I'm running into difficulties. When I run "cucumber features", I am met with errors, cucumber is unable to find my requests table. What obvious mistake am I making? Thank you in advance! Bash: justin-zollarss-mac-pro:conversion justinz$ cucumber features Using the default profile... /Users/justinz/.gem/ruby/1.8/gems/rails-2.3.5/lib/rails/gem_dependency.rb:119:Warning: Gem::Dependency#version_requirements is deprecated and will be removed on or after August 2010. Use #requirement F-- (::) failed steps (::) Could not find table 'requests' (ActiveRecord::StatementInvalid) ./features/article_steps.rb:3 ./features/article_steps.rb:2:in `each' ./features/article_steps.rb:2:in `/^I have requests named (.+)$/' features/manage_articles.feature:7:in `Given I have requests named Foo, Bar' Failing Scenarios: cucumber features/manage_articles.feature:6 # Scenario: Conversion 1 scenario (1 failed) 3 steps (1 failed, 2 skipped) 0m0.154s justin-zollarss-mac-pro:conversion justinz$ Manage_articles.feature: Feature: Manage Articles In order to make sales As a customer I want to make conversions Scenario: Conversion Given I have requests named Foo, Bar When I go to the list of customers Then I should see a new "customer" Article_steps.rb: Given /^I have requests named (.+)$/ do |firsts| firsts.split(', ').each do |first| Request.create!(:first => first) pending # express the regexp above with the code you wish you had end end Then /^I should see a new "([^"]*)"$/ do |arg1| pending # express the regexp above with the code you wish you had end DB schema: ActiveRecord::Schema.define(:version => 20100528011731) do create_table "requests", :force => true do |t| t.string "institution" t.string "website" t.string "type" t.string "users" t.string "first" t.string "last" t.string "jobtitle" t.string "phone" t.string "email" t.datetime "created_at" t.datetime "updated_at" end end

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  • Titanium Appcelerator - After enabling cloud services I get UnicodeDecodeError when compiling for Android

    - by Shahar Zrihen
    I've got an app that has a UTF8 name (hebrew). I use the platform/android/AndroidManifest.xml file for this. I've managed to narrow it down to the Ti.cloudpush module. only when I enable this module I get the error. I used to be able to compile it to android without any issues but as soon as I enable cloud services I get this error - [ERROR] Exception occured while building Android project: [ERROR] Traceback (most recent call last): [ERROR] File "/Users/Shahar/Library/Application Support/Titanium/mobilesdk/osx/2.1.0.GA/android/builder.py", line 2218, in <module> [ERROR] s.build_and_run(True, None, key, password, alias, output_dir) [ERROR] File "/Users/Shahar/Library/Application Support/Titanium/mobilesdk/osx/2.1.0.GA/android/builder.py", line 1970, in build_and_run [ERROR] self.manifest_changed = self.generate_android_manifest(compiler) [ERROR] File "/Users/Shahar/Library/Application Support/Titanium/mobilesdk/osx/2.1.0.GA/android/builder.py", line 1195, in generate_android_manifest [ERROR] custom_manifest_contents = fill_manifest(custom_manifest_contents) [ERROR] File "/Users/Shahar/Library/Application Support/Titanium/mobilesdk/osx/2.1.0.GA/android/builder.py", line 1122, in fill_manifest [ERROR] manifest_source = manifest_source.replace(ti_permissions,permissions_required_xml) [ERROR] UnicodeDecodeError: 'ascii' codec can't decode byte 0xd7 in position 501: ordinal not in range(128) and this is my manifest file with the part that causes the issues. If I remove the hebrew name, it compiles without any issues <application android:icon="@drawable/appicon" android:label="??????" android:name="QuestionnaireApplication" android:debuggable="false" > <activity android:name=".QuestionnaireActivity" android:label="??????" android:theme="@style/Theme.Titanium" android:screenOrientation="portrait" android:configChanges="keyboardHidden" > Any suggestions?

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  • Getting SSL to work with Apache/Passenger on OSX

    - by jonnii
    I use apache/passenger on my development machine, but need to add SSL support (something which isn't exposed through the control panel). I've done this before in production, but for some reason I can't seem to get it work on OSX. The steps I've followed so far are from a default apache osx install: Install passenger and passenger preference pane. Add my rails app (this works) Create my ca.key, server.crt and server.key as detailed on the apple website. At this point I need to start editing the apache configs, so I added: # Apache knows to listen on port 443 for ssl requests. Listen 443 Listen 80 I thought I'd try editing the passenger pref pane generated config first to get everything working, when I add: It starts off looking like this <VirtualHost *:80> ServerName myapp.local DocumentRoot "/Users/jonnii/programming/ruby/myapp/public" RailsEnv development <Directory "/Users/jonnii/programming/ruby/myapp/public"> Order allow,deny Allow from all </Directory> </VirtualHost> I then append this: <VirtualHost *:443> ServerName myapp.local DocumentRoot "/Users/jonnii/programming/ruby/myapp/public" RailsEnv development <directory "/Users/jonnii/programming/ruby/myapp/public"> Order allow,deny Allow from all </directory> # SSL Configuration SSLEngine on SSLCipherSuite ALL:!ADH:!EXPORT56:RC4+RSA:+HIGH:+MEDIUM:+LOW:+SSLv2:+EXP SSLOptions +FakeBasicAuth +ExportCertData +StdEnvVars +StrictRequire #Self Signed certificates SSLCertificateFile /private/etc/apache2/ssl.key/server.crt SSLCertificateKeyFile /private/etc/apache2/ssl.key/server.key SSLCertificateChainFile /private/etc/apache2/ssl.key/ca.crt SetEnvIf User-Agent ".*MSIE.*" nokeepalive ssl-unclean-shutdown downgrade-1.0 force-response-1.0 </VirtualHost> The files referenced all exist (I doubled checked that), but now when I restart my apache I can't even get to myapp.local. However apache can still server the default page when I click on it in the sharing preference panel. Any help would be greatly appreciated.

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  • Create signed urls for CloudFront with Ruby

    - by wiseleyb
    History: I created a key and pem file on Amazon. I created a private bucket I created a public distribution and used origin id to connect to the private bucket: works I created a private distribution and connected it the same as #3 - now I get access denied: expected I'm having a really hard time generating a url that will work. I've been trying to follow the directions described here: http://docs.amazonwebservices.com/AmazonCloudFront/latest/DeveloperGuide/index.html?PrivateContent.html This is what I've got so far... doesn't work though - still getting access denied: def url_safe(s) s.gsub('+','-').gsub('=','_').gsub('/','~').gsub(/\n/,'').gsub(' ','') end def policy_for_resource(resource, expires = Time.now + 1.hour) %({"Statement":[{"Resource":"#{resource}","Condition":{"DateLessThan":{"AWS:EpochTime":#{expires.to_i}}}}]}) end def signature_for_resource(resource, key_id, private_key_file_name, expires = Time.now + 1.hour) policy = url_safe(policy_for_resource(resource, expires)) key = OpenSSL::PKey::RSA.new(File.readlines(private_key_file_name).join("")) url_safe(Base64.encode64(key.sign(OpenSSL::Digest::SHA1.new, (policy)))) end def expiring_url_for_private_resource(resource, key_id, private_key_file_name, expires = Time.now + 1.hour) sig = signature_for_resource(resource, key_id, private_key_file_name, expires) "#{resource}?Expires=#{expires.to_i}&Signature=#{sig}&Key-Pair-Id=#{key_id}" end resource = "http://d27ss180g8tp83.cloudfront.net/iwantu.jpeg" key_id = "APKAIS6OBYQ253QOURZA" pk_file = "doc/pk-APKAIS6OBYQ253QOURZA.pem" puts expiring_url_for_private_resource(resource, key_id, pk_file) Can anyone tell me what I'm doing wrong here?

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  • Latex renewcommand not working properly

    - by Nazgulled
    Why is this not working: \documentclass[a4paper,10pt]{article} \usepackage{a4wide} \usepackage[T1]{fontenc} \usepackage[portuguese]{babel} \usepackage[latin1]{inputenc} \usepackage{indentfirst} \usepackage{listings} \usepackage{fancyhdr} \usepackage{url} \usepackage[compat2,a4paper,left=25mm,right=25mm,bottom=15mm,top=20mm]{geometry} \usepackage{color} \usepackage[colorlinks]{hyperref} \usepackage[pdftex]{graphicx} \renewcommand{\headrulewidth}{0.4pt} \renewcommand{\footrulewidth}{0.4pt} \pagestyle{fancy} \fancyhead[L]{\small Laboratórios de Informática III} \fancyhead[R]{\small Projecto 1 (Linguagem \textsf{C})} \lstset{ basicstyle=\ttfamily\footnotesize, showstringspaces=false, frame=single, tabsize=4, breaklines=true, } \definecolor{Section1}{rgb}{0.09,0.21,0.36} \definecolor{Section2}{rgb}{0.21,0.37,0.56} \definecolor{Section3}{rgb}{0.30,0.50,0.74} \hypersetup{ bookmarks=false, linkcolor=red, urlcolor=cyan, } \renewcommand{\section}[1]{\texorpdfstring{\color{green}#1}{#1}} \parskip=6pt \begin{document} \begin{titlepage} \begin{center} \includegraphics[width=5cm]{./logo.jpg}\\[1cm] \textsc{\LARGE Universidade do Minho}\\[1cm] \textsc{\large Licenciatura em Engenharia Informática\\Laboratórios de Informática III}\\[1.5cm] \rule{\linewidth}{0.5mm}\\[0.4cm] \huge{\textbf{\textsc{Relatório do Projecto 1 (Linguagem C)}}} \rule{\linewidth}{0.5mm} \vfill \begin{tabular}{c c} \includegraphics[width=3.5cm]{./nuno.jpg} & \includegraphics[width=3.5cm]{./ricardo.jpg} \\ \textsc{\large{Nuno Mendes (51161)}} & \textsc{\large{Ricardo Amaral (48404)}} \\ \end{tabular} \vfill \large{\today} \end{center} \end{titlepage} \tableofcontents \newpage \section{Introdução} Lorem ipsum... \newpage \appendix \section{\color{Section1}Diagrama das Estruturas de Dados} \begin{center} \includegraphics[width=16cm]{./Diagrama.pdf} \end{center} \end{document} ! LaTeX Error: Something's wrong--perhaps a missing \item. See the LaTeX manual or LaTeX Companion for explanation. Type H for immediate help. ... l.2 ...rline {1}\color {green}Teste}{3}{section.1} How can I make it work properly?

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  • How do I grant anonymous access to a url using FormsAuthentication?

    - by Brian Bolton
    For the most part, my webapp requires authentication to do anything. There are a few pages, namely the homepage, that I'd like people to be able to access without authenticating. Specifically, I'd like to allow anonymous access to these urls: /home /default.aspx I'm using asp.net MVC and FormsAuthentication. Both urls point to the same view: /home/index.aspx Here is my current configuration in web.config. <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" timeout="2880" /> </authentication> <authorization> <deny users="?" /> </authorization> Reading the documentation for the authorization tag, it says "Configures the authorization for a Web application, controlling client access to URL resources." It seems like I should be able to use the authorization tag to specify a url and allow access. Something like: <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" timeout="2880" /> </authentication> <authorization> <deny users="?" /> </authorization> <authorization url="/default.aspx"> <allow users="?" /> </authorization> <authorization url="/home"> <allow users="?" /> </authorization>

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  • implicit argument passing of super from method defined by define_method() is not supported. Specify

    - by jaycode
    Most of you should already know Pragmatic book's "Agile web dev with rails" (third edition). On page 537 - 541 it has "Custom Form Builders" code as follows: class TaggedBuilder < ActionView::Helpers::FormBuilder # <p> # <label for="product_description">Description</label><br/> # <%= form.text_area 'description' %> #</p> def self.create_tagged_field(method_name) define_method(method_name) do |label, *args| @template.content_tag("p" , @template.content_tag("label" , label.to_s.humanize, :for => "#{@object_name}_#{label}") + "<br/>" + super) end end field_helpers.each do |name| create_tagged_field(name) end end This code doesn't work with Ruby 1.9.1. It returns error as follows: implicit argument passing of super from method defined by define_method() is not supported. Specify all arguments explicitly. (ActionView::TemplateError) My question is: What should I change in the code to fix this? Thank you

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  • best way to parse plain text file with a nested information structure

    - by Beffa
    The text file has hundreds of these entries (format is MT940 bank statement) {1:F01AHHBCH110XXX0000000000}{2:I940X N2}{3:{108:XBS/091502}}{4: :20:XBS/091202/0001 :25:5887/507004-50 :28C:140/1 :60F:C0914CHF7789, :61:0912021202D36,80NTRFNONREF//0887-1202-29-941 04392579-0 LUTHY + xxx, ZUR :86:6034?60LUTHY + xxxx, ZUR vom 01.12.09 um 16:28 Karten-Nr. 2232 2579-0 :62F:C091202CHF52,2 :64:C091302CHF52,2 -} This should go into an Array of Hashes like [{"1"=>"F01AHHBCH110XXX0000000000"}, "2"=>"I940X N2", 3 => {108=>"XBS/091502"} etc. } ] I tried it with tree top, but it seemed not to be the right way, because it's more for something you want to do calculations on, and I just want the information. grammar Mt940 rule document part1:string spaces [:|/] spaces part2:document { def eval(env={}) return part1.eval, part2.eval end } / string / '{' spaces document spaces '}' spaces { def eval(env={}) return [document.eval] end } end end I also tried with a regular expression matches = str.scan(/\A[{]?([0-9]+)[:]?([^}]*)[}]?\Z/i) but it's difficult with recursion ... How can I solve this problem?

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  • Rails: unable to set any attribute of child model

    - by Bryan Roth
    I'm having a problem instantiating a ListItem object with specified attributes. For some reason all attributes are set to nil even if I specify values. However, if I specify attributes for a List, they retain their values. Attributes for a List retain their values: >> list = List.new(:id => 20, :name => "Test List") => #<List id: 20, name: "Test List"> Attributes for a ListItem don't retain their values: >> list_item = ListItem.new(:id => 17, :list_id => 20, :name => "Test Item") => #<ListItem id: nil, list_id: nil, name: nil> UPDATE #1: I thought the id was the only attribute not retaining its value but realized that setting any attribute for a ListItem gets set to nil. list.rb: class List < ActiveRecord::Base has_many :list_items, :dependent => :destroy accepts_nested_attributes_for :list_items, :reject_if => lambda { |a| a[:name].blank? }, :allow_destroy => true end list_item.rb: class ListItem < ActiveRecord::Base belongs_to :list validates_presence_of :name end schema.rb ActiveRecord::Schema.define(:version => 20100506144717) do create_table "list_items", :force => true do |t| t.integer "list_id" t.string "name" t.datetime "created_at" t.datetime "updated_at" end create_table "lists", :force => true do |t| t.string "name" t.datetime "created_at" t.datetime "updated_at" end end

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  • Sequel Migration not running up?

    - by Sleepycat
    Having some trouble with the Migrations in Sequel and could use another set of eyes. I am running a migration that looks ok but no table is created. It is definitely connecting because I can see the schema_info table has been created. -M 0/1 changes the version as you would expect but still no table. The command: sequel -m . -M 1 ~/Desktop/dbtest/testdb.yml 001_testdb.rb: class TestDb < Sequel::Migration def up create_table( "terminals") do primary_key :id Integer :location_id Integer :merchant_id BigDecimal :terminal_id, :size=>[11, 0] String :reference, :size=>255 DateTime :created_at DateTime :updated_at String :image, :default=>"default.jpg", :size=>255 end end def down drop_table :terminals end end The output in Postgres: test_db=# \dt List of relations Schema | Name | Type | Owner --------+-------------+-------+---------- public | schema_info | table | postgres (1 row) test_db=# select * from schema_info; version --------- 1 (1 row)

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