Search Results

Search found 13437 results on 538 pages for 'trusted root certificates'.

Page 243/538 | < Previous Page | 239 240 241 242 243 244 245 246 247 248 249 250  | Next Page >

  • maven-release-plugin: Perform fails with 'working directory "...workspace\target\checkout\workspace"

    - by Ed
    Hi, I have maven project that fails when release:perform is called, though release;prepare works as expected. I have found the bug report (below) which certainly seems to resemble the issue I have but not entirely sure I understand the problem: MRELEASE516 The last few lines of output I get: [INFO] Executing: cmd.exe /X /C "p4 -d E:\hudson\jobs\myHudsonJob\workspace\target\checkout -p 10.20.0.38:1666 client -d myProjectWorkspace-MavenSCM-E:\hudson\jobs\myHudsonJob\workspace\target\checkout" [INFO] Executing goals 'deploy'... [WARNING] Base directory is a file. Using base directory as POM location. [WARNING] Maven will be executed in interactive mode, but no input stream has been configured for this MavenInvoker instance. [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR [INFO] ------------------------------------------------------------------------ [INFO] Error executing Maven. Working directory "E:\hudson\jobs\myHudsonJob\workspace\target\checkout\workspace" does not exist! From reading the bug report the possible cause of the error is related to my modules' structure, I've tried to outline it below: /workspace | |+ pom.xml (root pom whose parent is the build pom, | calling release:perform on this pom) | [Modules: moduleA and moduleB] | |- moduleA |+ pom.xml (parent is also build pom) |+ build/pom.xml (the build pom - no custom parent) |- moduleB |+ pom.xml (parent is build pom) It seems that the root pom should be in some common directory inside 'workspace' from the error but tried that and doesn't work, nor make sense as to why I need it. What does the warning Base directory is a file want me to do instead?! It then figures that the base directory is workspace which then means the working directory is not found...any ideas? Thanks in advance.

    Read the article

  • How can I write System preferences with Java? Can I invoke UAC?

    - by Jonas
    How can I write system preferences with Java, using Preferences.systemRoot()? I tried with: Preferences preferences = Preferences.systemRoot(); preferences.put("/myapplication/databasepath", pathToDatabase); But I got this error message: 2010-maj-29 19:02:50 java.util.prefs.WindowsPreferences openKey VARNING: Could not open windows registry node Software\JavaSoft\Prefs at root 0x80000002. Windows RegOpenKey(...) returned error code 5. Exception in thread "AWT-EventQueue-0" java.lang.SecurityException: Could not open windows registry node Software\JavaSoft\Prefs at root 0x80000002: Access denied at java.util.prefs.WindowsPreferences.openKey(Unknown Source) at java.util.prefs.WindowsPreferences.openKey(Unknown Source) at java.util.prefs.WindowsPreferences.openKey(Unknown Source) at java.util.prefs.WindowsPreferences.putSpi(Unknown Source) at java.util.prefs.AbstractPreferences.put(Unknown Source) at biz.accountia.pos.install.Setup$2.actionPerformed(Setup.java:43) I would like to do this, because I want to install an embedded JavaDB database, and let multiple users on the computer to use the same database with the application. How to solve this? Can I invoke UAC and do this as Administrator from Java? And if I log in as Administrator when writing, can I read the values with my Java application if I'm logged in as a User?

    Read the article

  • JPA2 Criteria API creates invalid SQL when using groupBy

    - by Stephan
    JPA2 with the Criteria API seems to generate invalid SQL for PostgreSQL. For this code: Root<DBObjectAccessCounter> from = query.from(DBObjectAccessCounter.class); Path<DBObject> object = from.get(DBObjectAccessCounter_.object); Expression<Long> sum = builder.sumAsLong(from.get(DBObjectAccessCounter_.count)); query.multiselect(object, sum).groupBy(object); I get the following exception: ERROR: column "dbobject1_.id" must appear in the GROUP BY clause or be used in an aggregate function The generated SQL is: select dbobjectac0_.object_id as col_0_0_, sum(dbobjectac0_.count) as col_1_0_, dbobject1_.id as id1001_, dbobject1_.name as name1013_, dbobject1_.lastChanged as lastChan2_1013_, dbobject1_.type_id as type3_1013_ from DBObjectAccessCounter dbobjectac0_ inner join DBObject dbobject1_ on dbobjectac0_.object_id=dbobject1_.id group by dbobjectac0_.object_id Obviously, the first item of the select statement (dbobjectac0_.object_id) does not match the group by clause. Simplified example It does not even work for this simple example: Root<DBObjectAccessCounter> from = query.from(DBObjectAccessCounter.class); Path<DBObject> object = from.get(DBObjectAccessCounter_.object); query.select(object).groupBy(object); which returns select dbobject1_.id as id924_, dbobject1_.name as name933_, dbobject1_.lastChanged as lastChan2_933_, dbobject1_.type_id as type3_933_ from DBObjectAccessCounter dbobjectac0_ inner join DBObject dbobject1_ on dbobjectac0_.object_id=dbobject1_.id group by dbobjectac0_.object_id Does anyone know how to fix this?

    Read the article

  • ASP Menu driving me insane

    - by simplesimon
    Hi there, I am trying to create a menu using ASP (I have never used ASP before, im a PHP man) using values stored in a database. basically the html layout i want is as such: <ul> <li> <ul class="sub-menu"> <li class="sub-menu-li">Test</li> </ul> </li> </ul> I need to loop around the root menu items rs("AD_Level") which is equal to 0 for root objects, then inside that loop, lop around anything that has the same parent id eg if the current record is AD_Level =0 and AD_Parent=5 then loop around all items with AD_Parent 5 and AD_Level != 0 and insert the values into html and so on and so forth. Please help! I am struggling with a new language and cannot see a way to do this without losing sanity Edit (Extracted from Comment by OP) while not rsAdmin.eof sPar = rsAdmin("ad_parent" if rsAdmin("AD_Level")=0 then while not rsAdmin2.eof if rsAdmin2("AD_Level")<>0 and rsAdmin2("ad_parent")=sPar and rsAdmin2("AD_Sec_Level")=>2 then response.write rsAdmin("AD_Menu") end if rsAdmin2.movenext wend end if '' # if not rsAdmin.eof then sPar=rsAdmin("AD_parent") rsAdmin.movenext wend that is my code

    Read the article

  • Classic ASP - Email form with attached file - please help

    - by apg1985
    Hi Guys, Ive got abit of a problem ive got an email web form that send the input to an email address but what I now need is a file input field were the user can also send an image as an attachment. So contact name, logo (attachment). Ive been told in order to send the attachment it needs to be saved in a folder on my hosting before it can be sent. Ive spoken to the hosting company and they dont have anything in place to make this easier such as aspupload. In the form name="contactname" and name="logo" I have a folder in the root directory called logos (this asp page also exists in the root directory) Man I hope someone can help me spent along time looking for answers Dim contactname, logo contactname = request.form("contactname") If request("contactname") <> "" THEN Set myMail=CreateObject("CDO.Message") myMail.Subject="Form" myMail.From="web@email" myMail.To="web@email" myMail.HTMLBody = "" & contactname & "" myMail.Configuration.Fields.Item("http://schemas.microsoft.com/cdo/configuration/sendusing") = 2 myMail.Configuration.Fields.Item("http://schemas.microsoft.com/cdo/configuration/smtpserver") = "relay.host" myMail.Configuration.Fields.Item("http://schemas.microsoft.com/cdo/configuration/smtpserverport") = 25 myMail.Configuration.Fields.Update myMail.Send set myMail=nothing

    Read the article

  • How do I select the shallowest matching elements with XPath?

    - by harpo
    Let's say I have this document. <a:Root> <a:A> <title><a:B/></title> <a:C> <item><a:D/></item> </a:C> </a:A> </a:Root> And I have an XmlNode set to the <a:A> element. If I say A.SelectNodes( "//a:*", namespaceManager ) I get B, C, and D. But I don't want D because it's nested in another "a:" element. If I say A.SelectNodes( "//a:*[not(ancestor::a:*)]", namespaceManager ) of course, I get nothing, since both A and its parent are in the "a" namespace. How can I select just B and C, that is, the shallowest children matching the namespace? Thanks. Note, this is XPath 1.0 (.NET 2), so I can't use in-scope-prefixes (which it appears would help).

    Read the article

  • modx friendly urls nginx FPM php5.3 - friendly url's not working

    - by okdan
    Hi, Im using php5.3 on nginx 0.8.53 with FPM on Modx revolution. Im trying to get "friendly url's" to work, but all I get is 404's. In modx config, friendly url's is set to yes, friendly aliases is set to no (so it drops the suffix) My config file: server { listen 80; server_name .mydomain.net; # index index.php; root /home/mylogin/htdocs; location / { index index.php index.html; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?q=$1 last; } } # serve static files directly location ~* ^.+\.(jpg|jpeg|gif|css|png|js|ico)$ { root /home/mylogin/htdocs; access_log off; expires 30d; break; } } Fast CGI modx file: fastcgi_connect_timeout 60; fastcgi_send_timeout 300; fastcgi_buffers 4 32k; fastcgi_busy_buffers_size 32k; fastcgi_temp_file_write_size 32k; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_ignore_client_abort on; fastcgi_intercept_errors on; fastcgi_read_timeout 300; fastcgi_param QUERY_STRING $query_string; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_param SCRIPT_NAME $fastcgi_script_name; fastcgi_param REQUEST_URI $request_uri; fastcgi_param DOCUMENT_URI $document_uri; fastcgi_param DOCUMENT_ROOT $document_root; fastcgi_param SERVER_PROTOCOL $server_protocol; fastcgi_param GATEWAY_INTERFACE CGI/1.1; fastcgi_param SERVER_SOFTWARE nginx/$nginx_version; fastcgi_param REMOTE_ADDR $remote_addr; fastcgi_param REMOTE_PORT $remote_port; fastcgi_param SERVER_ADDR $server_addr; fastcgi_param SERVER_PORT $server_port; fastcgi_param SERVER_NAME $server_name; fastcgi_param REDIRECT_STATUS 200;

    Read the article

  • jboss Resteasy for java 5

    - by Anand
    Is there a resteasy version that runs on jdk 5 enviroment? I tried to compile my code in java 5 but it didnot work saying version problem. Is there a solution here? type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception javax.servlet.ServletException: Error instantiating servlet class org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:879) org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81) org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689) java.lang.Thread.run(Thread.java:595) root cause java.lang.UnsupportedClassVersionError: Bad version number in .class file (unable to load class javax.ws.rs.core.UriInfo) org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java:1964) org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java:933) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1405) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1284) java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) java.lang.Class.getDeclaredConstructors0(Native Method) java.lang.Class.privateGetDeclaredConstructors(Class.java:2357) java.lang.Class.getConstructor0(Class.java:2671) java.lang.Class.newInstance0(Class.java:321) java.lang.Class.newInstance(Class.java:303) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:879) org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81) org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689) java.lang.Thread.run(Thread.java:595) note The full stack trace of the root cause is available in the Apache Tomcat/5.5.31 logs.

    Read the article

  • Gradle fails injecting dependencies into subprojects using fileTree

    - by Matthias
    Maybe I'm missing something about the way Gradle works. What I have here is a parent project, which only contains configuration, i.e. there won't be any artifact being built when building it, it merely manages and builds all its subprojects. Now the subprojects share some dependency configuration, so I figured what I would do in the root project's build.gradle is: subprojects { dependencies { compile fileTree(dir: 'lib', includes: ['*.jar']) } } that, however, does not work, it fails with a rather obscure error message: A problem occurred evaluating root project 'qype-android' Cause: No signature of method: org.gradle.api.internal.artifacts.dsl.dependencies.DefaultDependencyHandler.compile() is applicable for argument types: (org.gradle.api.internal.file.DefaultConfigurableFileTree) values: [file set 'lib'] Possible solutions: module(java.lang.Object) after some trial and error, I could "fix" this issue by applying the 'java' plugin to the parent project. How come? I don't see anywhere from the Gradle docs that a fileTree dependency requires the Java plugin. Even so, why would I need it on the project that is injecting the configuration, as opposed to on the project that is being configured (note that the subprojects all apply the Java plugin themselves)? Does this mean that if I have N different subprojects that are all of varying natures, and apply different plugins, that the parent projects must always apply the set of all plugins beings used somewhere to itself, too?

    Read the article

  • help('modules') crashing?

    - by Chris
    I was trying to install a module for opencv and added an opencv.pth file to the folder beyond my sites.py file. I have since deleted it and no change. When I try to run help('modules'), I get the following error: Please wait a moment while I gather a list of all available modules... /System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/twisted/words/im/init.py:8: UserWarning: twisted.im will be undergoing a rewrite at some point in the future. warnings.warn("twisted.im will be undergoing a rewrite at some point in the future.") /System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py:110: DeprecationWarning: The wxPython compatibility package is no longer automatically generated or actively maintained. Please switch to the wx package as soon as possible. import(name) Traceback (most recent call last): File "", line 1, in File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site.py", line 348, in call return pydoc.help(*args, **kwds) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1644, in call self.help(request) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1681, in help elif request == 'modules': self.listmodules() File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1802, in listmodules ModuleScanner().run(callback) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1853, in run for importer, modname, ispkg in pkgutil.walk_packages(): File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py", line 110, in walk_packages import(name) File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/init.py", line 19, in from ctypes_opencv.cv import * File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/cv.py", line 2567, in ('desc', CvMat_r, 1), # CvMat* desc File "/Library/Python/2.5/site-packages/ctypes_opencv/cxcore.py", line 114, in cfunc return CFUNCTYPE(result, *atypes)((name, dll), tuple(aflags)) AttributeError: dlsym(0x2674d10, cvCreateFeatureTree): symbol not found What gives?!

    Read the article

  • TFS Folders - Getting them to work like Subversion "Trunk/Tags/Branches"

    - by Sam Schutte
    I recently started using Team Foundation Server, and am having some trouble getting it to work the way I want it to. I've used Subversion for a couple years now, and love the way it works. I always set up three folders under each project, Trunk, Tags, and Branches. When I'm working on a project, all my code lives under a folder called "C:\dev\projectname". This "projectname" folder can be made to point to either trunk, or any of the branches or tags using Subversion (with the switch command). Now that I'm using TFS (my client's system), I'd like things to work the same way. I created a "Trunk" folder with my project in it, and mapped "Project/Trunk/Website" to "c:\dev\Website". Now, I want to make a release under the "tags" folder (located in "Project/Tags/Version 1.0/Website", and TFS is giving me the following error when I execute the branch command: "No appropriate mapping exists for $Project/tags/Version 1.0/Website" From what I can find on the internet, TFS expects you to have a mapping to your hard drive at the root of the project (the "Project" folder in my case), and then have all the source code that lives in trunk, tags and branches all pulled down to your hard drive. This sucks because it requires way too much stuff on your hard drive, and even worse, when you are working in a solution in Visual Studio, you won't be able to pull down "Version 2.0" and have all your project references to other projects work, because they'll all be pointing to "trunk" folders under the main folder, not just the main folder itself. What I want to do is have the root "Project/Website" folder on my hard drive, and be able to have it point to (mapped to) either tags, branches, or trunk, depending on what i'm doing, without having to screw around with fixing Visual Studio project references. Ideas?

    Read the article

  • How can display gif on a subview in iPhone using glgif?

    - by iPhoney
    I want to display a gif image on a subview in iPhone. The sample code glgif shows the gif image on the controller's root view, but when I make the following modifications, the application just crashes: IBOutlet UIView *gifView; // gifView is added as a subview of controller's root view //PlayerView *plView = (PlayerView *)self.view; PlayerView *plView = (PlayerView *)gifView; // Load test.gif VideoSource NSString *str = [[NSBundle mainBundle] pathForResource:@"test" ofType:@"gif"]; FILE *fp = fopen([str UTF8String], "r"); VideoSource *src = VideoSource_init(fp, VIDEOSOURCE_FILE); src->writeable = false; // Init video using VideoSource Video *vid = [[GifVideo alloc] initWithSource:src inContext:[plView context]]; VideoSource_release(src); // Start if loaded if (vid) { [plView startAnimation:vid]; [vid release]; return; } // Cleanup if failed fclose(fp); Now the app crashes in this line: Video *vid = [[GifVideo alloc] initWithSource:src inContext:[plView context]]; with the error message:-[UIView context]: unrecognized selector sent to instance. Any ideas about how to add the plView to the subview properly?

    Read the article

  • Java appending XML data

    - by Travis
    I've already read through a few of the answers on this site but none of them worked for me. I have an XML file like this: <root> <character> <name>Volstvok</name> <charID>(omitted)</charID> <userID>(omitted)</userID> <apiKey>(omitted)</apiKey> </character> </root> I need to add another <character> somehow. I'm trying this but it does not work: public void addCharacter(String name, int id, int userID, String apiKey){ Element newCharacter = doc.createElement("character"); Element newName = doc.createElement("name"); newName.setTextContent(name); Element newID = doc.createElement("charID"); newID.setTextContent(Integer.toString(id)); Element newUserID = doc.createElement("userID"); newUserID.setTextContent(Integer.toString(userID)); Element newApiKey = doc.createElement("apiKey"); newApiKey.setTextContent(apiKey); //Setup and write newCharacter.appendChild(newName); newCharacter.appendChild(newID); newCharacter.appendChild(newUserID); newCharacter.appendChild(newApiKey); doc.getDocumentElement().appendChild(newCharacter); }

    Read the article

  • svnsync loses revision properties although hook installed

    - by roesslerj
    Hello all! I have a pretty weird problem. We have setup an SVN-Mirror via cronjob (because it needs to go from inside to outside of a firewall, so no post-commit-hook possible) and svnsync. We installed a pre-revprop-hook just as told. Everything seems to work fine, except that it doesn't. E.g. when manually executing the script. # svnsync --non-interactive sync file://<path-to-mirror> --source-username <usr> --source-password <pwd> Committed revision 19817. Copied properties for revision 19817. No error, no complaints. But if checking for the revision properties it says: # svnlook info <path-to-mirror> 0 # svn info -r HEAD file://<path-to-mirror> 2>&1 Path: <root-of-mirror> URL: file://<path-to-mirror> Repository Root: file://<path-to-mirror> Repository UUID: <uid> Revision: 19817 Node Kind: directory Last Changed Rev: 19817 So somehow the author and timestamp information gets lost. But we need that information for our internal processes. Since no error or warning is produced I have absolutely no idea even where to start to look. Everything is local (except for the remote master), so there are no server-logs to look at. I also tried to manually recopy via svnsync copy-revprops (http://chestofbooks.com/computers/revision-control/subversion-svn/svnsync-Copy-revprops-Ref-svnsync-C-Copy-revprops.html). It says Copied properties for revision 19885. But when I query them, it's just the same. Any ideas how I could approach that problem, or even better -- how to solve it? Any ideas appreciated.

    Read the article

  • Why does XPath.selectNodes(context) always use the whole document in JDOM

    - by Simeon
    Hi, I'm trying to run the same query on several different contexts, but I always get the same result. This is an example xml: <root> <p> <r> <t>text</t> </r> </p> <t>text2</t> </root> So this is what I'm doing: final XPath xpath = XPath.newInstance("//t"); List<Element> result = xpath.selectNodes(thisIsThePelement); // and I've debuged it, it really is the <p> element And I always get both <t> elements in the result list. I need just the <t> inside the <p> I'm passing to the XPath object. Any ideas would be of great help, thanks.

    Read the article

  • Force Download Files Broken Headers wrong?

    - by Sinan
    if($_POST['mode']=="save") { $root = $_SERVER['DOCUMENT_ROOT']; $path = "/mcboeking/"; $path = $root.$path; $file_path = $_POST['path']; $file = $path.$file_path; if(!file_exists($file)) { die('file not found'); } else { header("Cache-Control: public"); header("Content-Description: File Transfer"); header('Content-Type: application/force-download'); header("Content-Disposition: attachment; filename=\"".basename($file)."\";" ); header("Content-Length: ".filesize($file)); readfile($file);}} As soon as i download the file and open it i get an error message. When i try to open a .doc i get the message : file structure is invalid. And when i try to open a jpg : This file can not be opened. It may be corrupt or a file format that Preview does not recognize. But when i download PDF files, they open without any problem. Can someone help me? P.s. i tried different headers including : header('Content-Type: application/octet-stream');

    Read the article

  • Counting elements and reading attributes with .net2.0 ?

    - by Prix
    I have an application that is on .net 2.0 and I am having some difficult with it as I am more use to linq. The xml file look like this: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <updates> <files> <file url="files/filename.ext" checksum="06B9EEA618EEFF53D0E9B97C33C4D3DE3492E086" folder="bin" system="0" size="40448" /> <file url="files/filename.ext" checksum="CA8078D1FDCBD589D3769D293014154B8854D6A9" folder="" system="0" size="216" /> <file url="files/filename.ext" checksum="CA8078D1FDCBD589D3769D293014154B8854D6A9" folder="" system="0" size="216" /> </files> </updates> The file is downloaded and readed on the fly: XmlDocument readXML = new XmlDocument(); readXML.LoadXml(xmlData); Initially i was thinking it would go with something like this: XmlElement root = doc.DocumentElement; XmlNodeList nodes = root.SelectNodes("//files"); foreach (XmlNode node in nodes) { ... im reading it ... } But before reading them I need to know how many they are to use on my progress bar and I am also clueless on how to grab the attribute of the file element in this case. How could I count how many "file" ELEMENTS I have (count them before entering the foreach ofc) and read their attributes ? I need the count because it will be used to update the progress bar. Overall it is not reading my xml very well.

    Read the article

  • split line of text

    - by plys
    Hi all, I was wondering if there is an algorithm to split a line into multiple lines, so that the resulting set of multiple lines fit into a square shape rather than a rectangle. Let me give some examples, Input: Hi this is a really long line. Output: Hi this is a really long line Input: a b c d e f Output: a b c d e f Input: This is really such looooooooooooooooooooong line.This is the end. Output: This is really such looooooooooooooooooooong line This is the end. If you see in the above examples, input line fits into a wide rectangle. But the output more or less fits into a square shape. Essentially what needs to be done here is simply count the number of characters in the line, take the square root of that number. Then put square root number of characters in each line. But in the above example, the splitting needs to be done by respecting word wraps instead of characters. Is there any standard algorithm for this? Any code examples/ pointers would be appreciated!

    Read the article

  • Log4net RollingFileAppender doesn't roll over anymore after a couple of weeks

    - by Rocko
    Hello, I'm using log4net (v1.2.9.0) in a web project. Everything works like a charm, but after a couple of weeks the RollingFileAppender stops to roll over. Instead every log message is appended to the same file which therefore has a giant size by now. Here is my log4net configuration: <?xml version="1.0" encoding="utf-8"?> <log4net> <appender name="RollingLogFileAppender" type="log4net.Appender.RollingFileAppender"> <param name="File" value="C:\\Documents and Settings\\All Users\\Application Data\\CAPServer\\log\\CWSServer.log"/> <param name="AppendToFile" value="true"/> <param name="MaxSizeRollBackups" value="50"/> <param name="RollingStyle" value="Date"/> <param name="DatePattern" value="yyyyMMdd"/> <param name="StaticLogFileName" value="true"/> <layout type="log4net.Layout.PatternLayout"> <param name="ConversionPattern" value="%d{dd.MM.yyyy HH:mm:ss} [%t] %-5p %c{1} - %m%n"/> </layout> </appender> <root> <level value="ALL"/> <appender-ref ref="RollingLogFileAppender"/> </root> </log4net> Can you help? Thanks in advance, Rocko

    Read the article

  • How do I search a NTEXT column for XML attributes and update the values? MS SQL 2005

    - by Alan
    Duplicate: this exact question was asked by the same author in http://stackoverflow.com/questions/1221583/how-do-i-update-a-xml-string-in-an-ntext-column-in-sql-server. Please close this one and answer in the original question. I have a SQL table with 2 columns. ID(int) and Value(ntext) The value rows have all sorts of xml strings in them. ID Value -- ------------------ 1 <ROOT><Type current="TypeA"/></ROOT> 2 <XML><Name current="MyName"/><XML> 3 <TYPE><Colour current="Yellow"/><TYPE> 4 <TYPE><Colour current="Yellow" Size="Large"/><TYPE> 5 <TYPE><Colour current="Blue" Size="Large"/><TYPE> 6 <XML><Name current="Yellow"/><XML> How do I: A. List the rows where <TYPE><Colour current="Yellow", bearing in mind that there is an entry <XML><Name current="Yellow"/><XML> B. Modify the rows that contain <TYPE><Colour current="Yellow" to be <TYPE><Colour current="Purple" Thanks! 4 your help

    Read the article

  • Devise routes to only use custom sign in page

    - by eblume
    I am trying to learn Devise and seem to have hit a problem that is nearly the same as many, many questions here on SO but just slightly different enough that I am not getting much traction following those questions' threads. I have a very simple application. Users can sign in and sign out (and also the devise 'forgot password' stuff is enabled - I am not concerned about it at this time) and that is it. They can't register, they can't edit their profile other than to change their password, they can't do anything except sign in and sign out. (Account creation will, for now, be handled manually at the command line.) I would vastly prefer that the only page that users can log in from was "/" (root_path). I already have it working where you can log in from "/", and that is great. The problem I am having is that if you type in your user/password combination incorrectly from the root_path login page, it automatically sends you to the Devise sign-in page to continue trying to sign in. How can I make Devise redirect to root_path on sign-in failure? Here are my routes - they are probably not optimal or correctly configured and I would appreciate pointers on fixing them: root to: "core_pages#splash" devise_for :users, skip: [:sessions] as :user do # get 'signin' => 'devise/sessions#new', as: :new_user_session post 'signin' => 'devise/sessions#create', as: :user_session delete 'signout' => 'devise/sessions#destroy', as: :destroy_user_session, via: Devise.mappings[:user].sign_out_via end match '/home' => 'core_pages#home' Note the commented-out 'get signin' line. The system works without this line but, surprisingly (to me), "GET /signin" results in a HTTP 400 (OK) response and renders the Devise login template. I would prefer it return some sort of 'invalid request' or just silently redirect the user to root_path. Running rake routes on these routes gives: root / core_pages#splash user_password POST /users/password(.:format) devise/passwords#create new_user_password GET /users/password/new(.:format) devise/passwords#new edit_user_password GET /users/password/edit(.:format) devise/passwords#edit PUT /users/password(.:format) devise/passwords#update user_session POST /signin(.:format) devise/sessions#create destroy_user_session DELETE /signout(.:format) devise/sessions#destroy home /home(.:format) core_pages#home Thanks!

    Read the article

  • PHP error problem.

    - by TaG
    I get the following error on line 8: Undefined index: real_name which is $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); I was wondering how can I fix this problem? Here is the PHP. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $privacy_policy = mysqli_real_escape_string($mysqli, $_POST['privacy_policy']); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, privacy_policy) VALUES ('$user_id', '$privacy_policy')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET privacy_policy = '$privacy_policy' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the HTML. <form method="post" action="index.php"> <fieldset> <ul> <li><input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" <?php if (isset($_POST['privacy_policy'])) { echo 'checked="checked"'; } else if($privacy_policy == "yes") { echo 'checked="checked"'; } ?> /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

    Read the article

  • Rails - strip xml import from whitespace and line break

    - by val_to_many
    Hey folks, I am stuck with something quite simple but really annoying: I have an xml file with one node, where the content includes line breaks and whitspaces. Sadly I can't change the xml. <?xml version="1.0" encoding="utf-8" ?> <ProductFeed> ACME Ltd. Fooproduct Foo Root :: Bar Category I get to the node and can read from it without trouble: url = "http://feeds.somefeed/feed.xml.gz" @source = open((url), :http_basic_authentication=>["USER", "PW"]) @gz = Zlib::GzipReader.new(@source) @result = @gz.read @doc = Nokogiri::XML(@result) @doc.xpath("/ProductFeed/Vendors/Vendor").each do |manuf| vendor = manuf.css("Name").first.text manuf.xpath("//child::Product").each do |product| product_name = product.css("Name").text foocat = product.css("Category").text puts "#{vendor} ---- #{product_name} ---- #{foocat} " end end This results in: ACME Ltd. ---- Fooproduct ---- Foo Root :: Bar Category Obviously there are line breaks and tab stops or spaces in the string returned by product.css("Category").text. Does anyone know how to strip the result from linebreaks and taps or spaces right here? Alternatively I could do that in the next step, where I do a find on 'foocat' like barcat = Category.find_by_foocat(foocat) Thanks for helping! Val

    Read the article

  • Tell me SQL Server Full-Text searcher is crazy, not me.

    - by Ian Boyd
    i have some customers with a particular address that the user is searching for: 123 generic way There are 5 rows in the database that match: ResidentialAddress1 ============================= 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY i run a FT query to look for these rows. i'll show you each step as i add more criteria to the search: SELECT ResidentialAddress1 FROM Patrons WHERE CONTAINS(Patrons.ResidentialAddress1, '"123*"') ResidentialAddress1 ========================= 123 MAPLE STREET 12345 TEST 123 MINE STREET 123 GENERIC WAY 123 FAKE STREET ... (30 row(s) affected) Okay, so far so good, now adding the word "generic": SELECT ResidentialAddress1 FROM Patrons WHERE CONTAINS(Patrons.ResidentialAddress1, '"123*"') AND CONTAINS(Patrons.ResidentialAddress1, '"generic*"') ResidentialAddress1 ============================= 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY 123 GENERIC WAY (5 row(s) affected) Excellent. And now i'l add the final keyword that the user wants to make sure exists: SELECT ResidentialAddress1 FROM Patrons WHERE CONTAINS(Patrons.ResidentialAddress1, '"123*"') AND CONTAINS(Patrons.ResidentialAddress1, '"generic*"') AND CONTAINS(Patrons.ResidentialAddress1, '"way*"') ResidentialAddress1 ------------------------------ (0 row(s) affected) Huh? No rows? What if i query for just "way*": SELECT ResidentialAddress1 FROM Patrons WHERE CONTAINS(Patrons.ResidentialAddress1, '"way*"') ResidentialAddress1 ------------------------------ (0 row(s) affected) At first i thought that perhaps it's because of the *, and it's requiring that the root way have more characters after it. But that's not true: Searching for "123*" matches "123" Searching for "generic*" matches "generic" Books online says, The asterisk matches zero, one, or more characters What if i remove the * just for s&g: SELECT ResidentialAddress1 FROM Patrons WHERE CONTAINS(Patrons.ResidentialAddress1, '"way"') Server: Msg 7619, Level 16, State 1, Line 1 A clause of the query contained only ignored words. So one might think that you are just not allowed to even search for way, either alone, or as a root. But this isn't true either: SELECT * FROM Patrons WHERE CONTAINS(Patrons.*, '"way*"') AccountNumber FirstName Lastname ------------- --------- -------- 33589 JOHN WAYNE So sum up, the user is searching for rows that contain all the words: 123 generic way Which i, correctly, translate into the WHERE clauses: SELECT * FROM Patrons WHERE CONTAINS(Patrons.*, '"123*"') AND CONTAINS(Patrons.*, '"generic*"') AND CONTAINS(Patrons.*, '"way*"') which returns no rows. Tell me this just isn't going to work, that it's not my fault, and SQL Server is crazy. Note: i've emptied the FT index and rebuilt it.

    Read the article

  • JTree - Issues with adding of nodes

    - by John
    Hi. Im developing a system that stores courses that participants can apply to. I'm presenting the enrollments in a JTree in the courseadministratorGUI. My problem is that, for every enrollment it's adding a new courseNode. Been trying for many hours, and hope I can now get some advice that will point me in the correct direction. Thank you. private void updateJTree() { for (Category cat : catcontrol.getAllCategoriesList()) { category = new DefaultMutableTreeNode(cat); for (Course c : ccontrol.getAllCourses()) { if (cat.getIdCategory() == c.getIdCategory()) { for (Enrollment e : econtrol.getAllEnrollments()) { if (e.getIdCourse() == c.getIdCourse()) { if (cat.getIdCategory() == c.getIdCategory() && e.getCourse().equals(c)) { root.add(category); } if (c.getIdCourse() == e.getIdCourse()) { course = new DefaultMutableTreeNode(c); category.add(course); enrollment = new DefaultMutableTreeNode(e.getParticipant().getFirstNames()); course.add(enrollment); } } } } } } jTree1.setModel(new DefaultTreeModel(root)); jTree1.addTreeSelectionListener(this); jTree1.getSelectionModel().setSelectionMode(TreeSelectionModel.SINGLE_TREE_SELECTION); }

    Read the article

< Previous Page | 239 240 241 242 243 244 245 246 247 248 249 250  | Next Page >