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  • Can't get php+sqlite working

    - by facha
    Hi, everyone I'm struggling all morning to make php work with an sqlite database. Here is a piece of php code that I try to execute: #less /var/www/html/test.php <?php $db=new PDO("sqlite:/var/www/test.sql"); $sql = "insert into test (login,pass) values ('login','pass');"; $db->exec($sql); ?> Here is how I've done tests: # sqlite3 /var/www/test.sql sqlite> create table test (login varchar,pass varchar); #chown apache:apache /var/www/test.sql #chmod 644 /var/www/test.sql Here is the stuff that drives me mad: When I execute from command line: #php test.php everything goes well. Sql is being executed and I can see a new row appear in the database. When I execute the same script from a browser - sql is not being executed. I don't get a new row in the database. There are no errors in the apache log file. Please, help

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  • Is there any proper documentation for mod-evasive?

    - by Question Overflow
    mod_evasive20 is one of the loaded modules on my httpd server. I read good things about how it can stop a DOS attack and wanted to try it out on my localhost. A search for mod_evasive turns up a blog post by the author which briefly describes what it does. Other than that, I can't seem to find a reference or a documentation on the apache modules site. I was wondering whether it is a module recognised by Apache since there is no mention of it on its website. I have a mod_evasive.conf file sitting in the /etc/http/conf.d folder that contains the following lines: LoadModule evasive20_module modules/mod_evasive20.so <IfModule mod_evasive20.c> DOSHashTableSize 3097 DOSPageCount 2 DOSSiteCount 50 DOSPageInterval 1 DOSSiteInterval 1 DOSBlockingPeriod 10 </IfModule> My understanding from the setting is that if I were to click refresh or send a form more than two times in a one second interval, apache will issue a 403 error and bar me from the site for 10 seconds. But that is not happening on my localhost. And I would like to know the reason. Thanks.

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  • How to have PHP and mod_wsgi python app on the same domain?

    - by Lazik
    I am using apache with mod_wsgi (python3) on ubuntu 12.04. I have a python app (bottle) which is at www.mysite.com/ In my python app I have routes like www.mysite.com/abbb?q=blab I would like a path www.mysite.com/forum to resolve to a php app (simple machine forums) Ideally I would like to use apache to handle the forum part and pass it to php (instead of coding it in the python app). Don't know if it's possible. I'm new to this, I have read https://code.google.com/p/modwsgi/wiki/ConfigurationGuidelines#The_Apache_Alias_Directive but I don't understand how to use it. Here is my apache conf for the mod_wsgi app, I don't know how to specify the PHP portion. <VirtualHost *:80> ServerName www.ex.com ServerAlias ex.com *.ex.com RewriteEngine On RewriteCond %{HTTP_HOST} !^www\. RewriteRule ^(.*)$ http://www.%{HTTP_HOST}$1 [R=301,L] WSGIDaemonProcess ex user=www-data group=www-data processes=1 threads=5 WSGIScriptAlias / /var/www/vhosts/ex/app.wsgi <Directory /var/www/vhosts/ex> WSGIProcessGroup ex WSGIApplicationGroup %{GLOBAL} Order deny,allow Allow from all </Directory> </VirtualHost>

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  • when to upgrade server to include more cores, versus more processors, versus additional server?

    - by gkdsp
    The server hosting market is separated into single, double, qual, etc., processors, where each processor has several cores, or CPUs. My company will offer a Linux-based web application that relies on an Apache web server and a middle tier for business logic. The middle tier is used to crunch math, and return result to a client. Many clients may access the application simultaneously. The company will start with one processor having 4 cores. I'm trying to understand how the app uses the cores and then how to scale the application as business grows, in terms of servers/processors/cores. For example, I'd assume initially one core would be used for Apache, and the other 3 used to process client's requests for math crunching... Question 1: does that mean, with the 3 cores available, I can handle 3 separate client requests simultaneously (e.g. 1 for each of 3 cores)? I mean, except for the shared RAM, is this effectively like having 3 individual machines (from pt of view or processing client requests simulaneously)? Or, only one client's request may be processed at any one time, but that client's request is divided up into up to 3 cores depending on the type of process running that does the math crunching and whether or not it can take advantage of multi threading (so the # of cores impacts how fast any one client request completes)? I'm confused about what the cores mean to the application here. Question 2: As the business grows and more client requests need to be processed, should the server be upgraded to (A) a new machine with more cores, (B) a new machine with two processors, 4 cores each, or (C) keep the original server and add another server with a single processor? Which route provides the most efficient way to scale the application, in terms of processing more client requests per time interval? Is the choice, for example, limited by RAM (when you need more RAM than box can handle it's time to add another server), or something else? Question 3: Is the total number of client requests processed simultaneously equal to the number of cores times the number of servers (minus the one core for Apache)?

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  • Using nginx to rewrite urls inside outgoing responses

    - by Kev
    We have a customer with a site running on Apache. Recently the site has been seeing increased load and as a stop gap we want to shift all the static content on the site to a cookieless domains, e.g. http://static.thedomain.com. The application is not well understood. So to give the developers time to amend the code to point their links to the static content server (http://static.thedomain.com) I thought about proxying the site through nginx and rewriting the outgoing responses such that links to /images/... are rewritten as http://static.thedomain.com/images/.... So for example, in the response from Apache to nginx there is a blob of Headers + HTML. In the HTML returned from Apache we have <img> tags that look like: <img src="/images/someimage.png" /> I want to transform this to: <img src="http://static.thedomain.com/images/someimage.png" /> So that the browser upon receiving the HTML page then requests the images directly from the static content server. Is this possible with nginx (or HAProxy)? I have had a cursory glance through the docs but nothing jumped out at me except rewriting inbound urls.

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  • Cant get squid proxy to work

    - by danielgratz
    i need squid proxy on my centos server. But i just can't get it to work. I did yum install squid. Here is my squid.conf file (i removed all comments): acl all src 0.0.0.0/0.0.0.0 acl manager proto cache_object acl localhost src 127.0.0.1/255.255.255.255 acl to_localhost dst 127.0.0.0/8 acl SSL_ports port 443 acl Safe_ports port 80 acl Safe_ports port 21 acl Safe_ports port 443 acl Safe_ports port 70 acl Safe_ports port 210 acl Safe_ports port 1025-65535 acl Safe_ports port 280 acl Safe_ports port 488 acl Safe_ports port 591 acl Safe_ports port 777 acl CONNECT method CONNECT acl our_networks src 192.168.1.0/24 192.168.2.0/24 http_access allow our_networks http_access allow manager localhost http_access deny manager http_access deny !Safe_ports http_access deny CONNECT !SSL_ports http_access allow localhost http_access deny all icp_access allow all http_port 3128 hierarchy_stoplist cgi-bin ? access_log /var/log/squid/access.log squid acl QUERY urlpath_regex cgi-bin \? cache deny QUERY refresh_pattern ^ftp: 1440 20% 10080 refresh_pattern ^gopher: 1440 0% 1440 refresh_pattern . 0 20% 4320 acl apache rep_header Server ^Apache broken_vary_encoding allow apache coredump_dir /var/spool/squid Then i just put my server's public ip and port 3128 into my web browsers proxy settings... but it isn't working i can't visit any website. Please help. Thanks.

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  • What can be a reason for phpMyAdmin login to be not working (not at all, no reaction on submit)?

    - by Ivan
    When I open "http://localhost/phpmyadmin/", enter "root" as the user name and my MySQL root password and press go, then if I was using Firefox, I was getting offered to download index.php file (of a zero length), if I was using Opera 11, it said "Connection closed by remote server". Following recommendations I've removed all packages related to phpMyAdmin, PHP, MySQL and Apache and then reinstalled them step-by step (instead of just issuing apt-get install phpmyadmin and relying on the system to install the whole LAMP stack via dependencies as I've done before). The only change I've got was Firefox to stop offering to download index.php - now when I press Ok to submit my password, it just doesn't show any visible reaction at all. What may the reason be and how to fix it? I use up-to-date Xubuntu 11.04. Reinstalling the whole LAMP stack and phpMyAdmin did not help, neither did removing AppArmor. I've tried to use SQLBuddy instead, but there's exactly the same problem. So, I think, the problem is not in phpMyAdmin but in MySQL, Apache or something. MySQL seems to work if I use command line to access it. Apache & PHP seems to work also, as the login page of phpMyAdmin displays correctly.

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  • Reading log files from web application

    - by Egorinsk
    Hi! I want to write a small PHP application for monitoring logs on a Debian server, including syslog logs and Apache/PHP messages. The problem here is that Apache user (www-data) has no access to /var/log directory. What would be the best way to grant an access to logs for PHP application? Let's assume that log files can be really large, like hundreds of megabytes. I have some ideas: Write a shell script that would be run via sudo and tail last 512 Kb of log into a separate file that can be read by application - that's ineffective, because of forking a new process and having to read data twice Add www-data to adm group (that can read logs) - that's insecure Start a PHP process via cron every minute to read logs — that's not very good, because it doesn't allow real-time monitoring. Also, this script will be started even when I don't read logs, and consume CPU time (server is in the cloud, and I'll have to pay for it) Create a hardlink for all log files with lowered permissions - I guess, that won't work because logrotate could recreate log files and they'll change inode number. Start a separate nginx/Apache server under privileged user that may read logs. Maybe anyone got a better solution?

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  • How do I set up Tomcat 7's server.xml to access a network share with an different url?

    - by jneff
    I have Apache Tomcat 7.0 installed on a Windows 2008 R2 Server. Tomcat has access to a share '\server\share' that has a documents folder that I want to access using '/foo/Documents' in my web application. My application is able to access the documents when I set the file path to '//server/share/documents/doc1.doc'. I don't want the file server's path to be exposed on my link to the file in my application. I want to be able to set the path to '/foo/Documents/doc1.doc'. In http://www3.ntu.edu.sg/home/ehchua/programming/howto/Tomcat_More.html under 'Setting the Context Root Directory and Request URL of a Webapp' item number two says that I can rename the path by putting in a context to the server.xml file. So I put <Host name="localhost" appBase="webapps" unpackWARs="true" autoDeploy="true"> <!-- SingleSignOn valve, share authentication between web applications Documentation at: /docs/config/valve.html --> <!-- <Valve className="org.apache.catalina.authenticator.SingleSignOn" /> --> <!-- Access log processes all example. Documentation at: /docs/config/valve.html Note: The pattern used is equivalent to using pattern="common" --> <Valve className="org.apache.catalina.valves.AccessLogValve" directory="logs" prefix="localhost_access_log." suffix=".txt" pattern="%h %l %u %t &quot;%r&quot; %s %b" /> <Context path="/foo" docBase="//server/share" reloadable="false"></Context> </Host> The context at the bottum was added. Then I tried to pull the file using '/foo/Documents/doc1.doc' and it didn't work. What do I need to do to get it to work correctly? Should I be using an alias instead? Are there other security issues that this may cause?

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  • Working with different PHP version at the same time, php_value extension_dir not working?

    - by Gremo
    I need both PHP 5.4.7 and 5.3.17 running on Windows 7 x64 with Apache 2.2.23. This is my virtual host configuration: <VirtualHost *:80> DocumentRoot "C:/WAMP/Apache/htdocs/php54" ServerName php54.local PHPIniDir "C:/WAMP/PHP54" LoadModule php5_module "C:/WAMP/PHP54/php5apache2_2.dll" php_value extension_dir "C:/WAMP/PHP54/ext" <Directory "C:/WAMP/Apache/htdocs/php54"> Order allow,deny Allow from all </Directory> </VirtualHost> The PHPIniDir and LoadModule directives work fine and using phpinfo() inside my script prints the right PHP version. But I need to load extensions, and this is where it fails. php_value extension_dir should be C:/WAMP/PHP54/ext but it's (default one) C:/php. What I'm missing here? EDIT: Of course I can set this value directly in C:/WAMP/PHP54/php.ini, but I prefer passing it using vhost configuration: ; Directory in which the loadable extensions (modules) reside. ; http://php.net/extension-dir ; extension_dir = "./" ; On windows: extension_dir = "C:/WAMP/PHP54/ext"

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  • Amazon EC2 - Free memory

    - by Damo
    We have an amazon ec2 small instance running and over the past few days we noticed that the memory is going down and down. On the small instance, we are running apache and tomcat6 Tomcat is started with the following JVM parameters -Xms32m -Xmx128m -XX:PermSize=128m -XX:MaxPermSize=256m We use nagios to monitor stuff like updates to apply, free disk space and memory. Everything else is behaving as expected but our memory is going down all the time. Our app receives approx half a million hits a day When I shutdown apache and tomcat, and ran free -m, we had only 594mb of memory free out out of the 1.7gb of memory. Not much else is running on the small instance and when running the top command I cannot see where the memory is going. The app we run on tomcat is a grails webapp. Could there be a possibility that there is a memory leak within our application? I read online and folks say that a small amazon instance is perfect for running apach and tomcat. I found a few posts online that showed how to setup apache and tomcat to limit the memory usage and I have already performed those steps. The memory is not being used up as quick but the memory is still decreasing over time. We have other amazone ec2 small instances running grails apps and the memory is fairly standard on those nodes. But they would not be receiving as much traffic Just to add, when I run the top command on the problem server, I cannot see where all the memory is being used Any help with this is greatly appreciated The output of free -m when run on my server is as follows total used free shared buffers cached Mem: 1657 1380 277 0 158 773 -/+ buffers/cache: 447 1209 Swap: 895 0 895 In your opinion, does this look ok? At what stage would the OS give back memory, would it wait to the memory reaches 0% or is this OS dependent?

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  • different user group can not upload file in the server

    - by Dallal
    I have a CentOS server running in Thailand, and I'm in Canada. The guy at the computer center who set up the server for me doesn't really understand much about linux and left me off an issue to solve myself. I just moved from Mac Server to Linux server, and the first thing I'm facing a problem now is `file name` has failed to upload due to an error The uploaded file could not be moved to `location name` So what happen is that I knew from my experiences of these problem is all about permissions. So I go ahead and checked on my whole folder and found that everything in the folder permission is like myusername mygroupname then I checked the httpd file in the server and it is default to apache apache. My question is that how can I make my user to be in the same group with apache group so that I don't have to have any problem about uploading, changing data in my file....? But without having to affect other user in the same server. I'm holding Administrator account, but not root account, but I can change stuff on the server root no problem. When I was with godaddy.com there never been any problem about the permission and I wish I know how they configure that :(

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  • please take a look at my server's ram usage

    - by user66779
    Hi, i am a noob with servers. I have a centos5.5 vps with 512mb ram. My goal is to have it host just one magento store. I've installed Magento on the server without any control panel, by just installing lamp myself and whatever php extensions were necessary to get Magento to install. As soon as i visit my magento store, suddenly the ram on the vps is almost completely used, with only about 100mb left. Please see this screenshot of htop taken after just myself visited the website. http://img714.imageshack.us/img714/1944/screenouv.png As you can see there's only around 100mb left. Is that normal? I'm wondering if i might have done something stupid with the server that makes it very resource hungry. I installed apache from the centos base repo, php version 5.3 from the ius repository and mysql 5.1 also from ius repo. I haven't changed any of the default config files for any of these except to make memory_minimum 256 in php.ini. Is there anything i can do to make more ram free? I'm clueless but i see each Apache daemon is using 8% of available ram, and AFAIK each visitor needs one Apache daemon. So i would run out of ram with just a handful of visitors. Thanks for your advice.

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  • Connection pooling options with JDBC: DBCP vs C3P0

    - by Dema
    What is the best connection pooling library available for Java/JDBC? I'm considering the 2 main candidates (free / open-source): Apache DBCB - http://commons.apache.org/dbcp/ C3P0 - http://sourceforge.net/projects/c3p0 I've read a lot about them in blogs and other forums but could not reach a decision. Is there any relevant alternatives to this two?

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  • Multiple database with Spring+Hibernate+JPA

    - by ziftech
    Hi everybody! I'm trying to configure Spring+Hibernate+JPA for work with two databases (MySQL and MSSQL) my datasource-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"> <!-- Data Source config --> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${local.jdbc.driver}" p:url="${local.jdbc.url}" p:username="${local.jdbc.username}" p:password="${local.jdbc.password}"> </bean> <bean id="dataSourceRemote" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${remote.jdbc.driver}" p:url="${remote.jdbc.url}" p:username="${remote.jdbc.username}" p:password="${remote.jdbc.password}" /> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactory" /> <!-- JPA config --> <tx:annotation-driven transaction-manager="transactionManager" /> <bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager"> <property name="persistenceXmlLocations"> <list value-type="java.lang.String"> <value>classpath*:config/persistence.local.xml</value> <value>classpath*:config/persistence.remote.xml</value> </list> </property> <property name="dataSources"> <map> <entry key="localDataSource" value-ref="dataSource" /> <entry key="remoteDataSource" value-ref="dataSourceRemote" /> </map> </property> <property name="defaultDataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="localjpa"/> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> </beans> each persistence.xml contains one unit, like this: <persistence-unit name="remote" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${remote.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${remote.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> PersistenceUnitManager cause following exception: Cannot resolve reference to bean 'persistenceUnitManager' while setting bean property 'persistenceUnitManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'persistenceUnitManager' defined in class path resource [config/datasource-context.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type [java.util.ArrayList] to required type [java.lang.String] for property 'persistenceXmlLocation'; nested exception is java.lang.IllegalArgumentException: Cannot convert value of type [java.util.ArrayList] to required type [java.lang.String] for property 'persistenceXmlLocation': no matching editors or conversion strategy found If left only one persistence.xml without list, every works fine but I need 2 units... I also try to find alternative solution for work with two databases in Spring+Hibernate context, so I would appreciate any solution new error after changing to persistenceXmlLocations No single default persistence unit defined in {classpath:config/persistence.local.xml, classpath:config/persistence.remote.xml} UPDATE: I add persistenceUnitName, it works, but only with one unit, still need help UPDATE: thanks, ChssPly76 I changed config files: datasource-context.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${local.jdbc.driver}" p:url="${local.jdbc.url}" p:username="${local.jdbc.username}" p:password="${local.jdbc.password}"> </bean> <bean id="dataSourceRemote" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${remote.jdbc.driver}" p:url="${remote.jdbc.url}" p:username="${remote.jdbc.username}" p:password="${remote.jdbc.password}"> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor"> <property name="defaultPersistenceUnitName" value="pu1" /> </bean> <bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager"> <property name="persistenceXmlLocation" value="${persistence.xml.location}" /> <property name="defaultDataSource" ref="dataSource" /> <!-- problem --> <property name="dataSources"> <map> <entry key="local" value-ref="dataSource" /> <entry key="remote" value-ref="dataSourceRemote" /> </map> </property> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="pu1" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactoryRemote" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="pu2" /> <property name="dataSource" ref="dataSourceRemote" /> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactory" /> <bean id="transactionManagerRemote" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactoryRemote" /> </beans> persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="pu1" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${local.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${local.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> <persistence-unit name="pu2" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${remote.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${remote.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> </persistence> Now it builds two entityManagerFactory, but both are for Microsoft SQL Server [main] INFO org.hibernate.ejb.Ejb3Configuration - Processing PersistenceUnitInfo [ name: pu1 ...] [main] INFO org.hibernate.cfg.SettingsFactory - RDBMS: Microsoft SQL Server [main] INFO org.hibernate.ejb.Ejb3Configuration - Processing PersistenceUnitInfo [ name: pu2 ...] [main] INFO org.hibernate.cfg.SettingsFactory - RDBMS: Microsoft SQL Server (but must MySQL) I suggest, that use only dataSource, dataSourceRemote (no substitution) is not worked. That's my last problem

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  • log4j prints all levels

    - by Florian
    Hello, I've got log4j configured on my Java project with the following log4j.properties: log4j.rootLogger=WARNING, X log4j.appender.X=org.apache.log4j.ConsoleAppender log4j.appender.X.layout=org.apache.log4j.PatternLayout log4j.appender.X.layout.ConversionPattern=%p %m %n log4j.logger.org.hibernate.SQL=WARNING log4j.logger.com.****.services.clarity.dao.impl=WARNING log4j.logger.com.****.services.clarity.controller=WARNING log4j.logger.com.****.services.clarity.services.impl=WARNING log4j.logger.com.****.services.clarity.feeds.impl=WARNING As configured, it should only print WARNING messages, however it prints all levels to DEBUG. any ideas where this can come from ? Thanks !

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  • MySQL Connection Timeout Issue - Grails Application on Tomcat using Hibernate and ORM

    - by gav
    Hi Guys I have a small grails application running on Tomcat in Ubuntu on a VPS. I use MySql as my datastore and everything works fine unless I leave the application for more than half a day (8 hours?). I did some searching and apparently this is the default wait_timeout in mysql.cnf so after 8 hours the connection will die but Tomcat won't know so when the next user tries to view the site they will see the connection failure error. Refreshing the page will fix this but I want to get rid of the error altogether. For my version of MySql (5.0.75) I have only my.cnf and it doesn't contain such a parameter, In any case changing this parameter doesn't solve the problem. This Blog Post seems to be reporting a similar error but I still don't fully understand what I need to configure to get this fixed and also I am hoping that there is a simpler solution than another third party library. The machine I'm running on has 256MB ram and I'm trying to keep the number of programs/services running to a minimum. Is there something I can configure in Grails / Tomcat / MySql to get this to go away? Thanks in advance, Gav From my Catalina.out; 2010-04-29 21:26:25,946 [http-8080-2] ERROR util.JDBCExceptionReporter - The last packet successfully received from the server was 102,906,722 milliseconds$ 2010-04-29 21:26:25,994 [http-8080-2] ERROR errors.GrailsExceptionResolver - Broken pipe java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) ... 2010-04-29 21:26:26,016 [http-8080-2] ERROR util.JDBCExceptionReporter - Already closed. 2010-04-29 21:26:26,016 [http-8080-2] ERROR util.JDBCExceptionReporter - Already closed. 2010-04-29 21:26:26,017 [http-8080-2] ERROR servlet.GrailsDispatcherServlet - HandlerInterceptor.afterCompletion threw exception org.hibernate.exception.GenericJDBCException: Cannot release connection at java.lang.Thread.run(Thread.java:619) Caused by: java.sql.SQLException: Already closed. at org.apache.commons.dbcp.PoolableConnection.close(PoolableConnection.java:84) at org.apache.commons.dbcp.PoolingDataSource$PoolGuardConnectionWrapper.close(PoolingDataSource.java:181) ... 1 more

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  • Android Source Code Tree Structure

    - by Walidix
    I have downloaded Android source code but I don't find the "Kernel Directory" in the top level directory of the source code tree. Is it normal ???? or is it missing ??? /mydroid$ find . -name kernel ./bionic/libc/kernel ./vendor/htc/sapphire-open/kernel ./vendor/htc/dream-open/kernel ./dalvik/libcore/luni-kernel/src/test/java/tests/api/org/apache/harmony/kernel ./dalvik/libcore/luni-kernel/src/main/java/org/apache/harmony/kernel ./prebuilt/android-arm/kernel ./prebuilt/android-x86/kernel ./device/htc/passion/kernel

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  • XStream JavaBeanConverter not serializing properties

    - by Steve Foster
    Hello All, Attempting to use XStream's JavaBeanConverter and running into an issue. Most likely I'm missng something simple, or not understanding XStream's converter handling well enough. @XStreamAlias("test") public class TestObject { private String foo; public String getFoo() { return foo; } public void setFoo(String foo) { this.foo = foo; } } public void test() throws Exception { XStream x = new XStream(new XppDriver()); x.autodetectAnnotations(true); x.processAnnotations(TestObject.class); x.registerConverter(new JavaBeanConverter(x.getMapper())); TestObject o = new TestObject(); o.setFoo("bar"); String xml = x.toXML(o); System.out.println(xml); /* Expecting... <test> <foo>bar</foo> </test> But instead getting... <test> <foo/> </test> */ } I tried adding a trace on the TestObject.getFoo() method and it appears it is being called by XStream, but the data isn't being written to the output stream. After looking at the source for JavaBeanConverter, it looks like my implementation should work, which leads me to believe I haven't configured something correctly during the XStream setup. Am I just missing something simple? Thanks! Edit Also, if it helps, I'm using the following Maven deps for this... <dependency> <groupId>org.apache.servicemix.bundles</groupId> <artifactId>org.apache.servicemix.bundles.xstream</artifactId> <version>1.3_3</version> </dependency> <dependency> <groupId>org.apache.servicemix.bundles</groupId> <artifactId>org.apache.servicemix.bundles.xpp3</artifactId> <version>1.1.4c_3</version> </dependency>

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  • JPA @OneToMany and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @OneToMany mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • Character encoding issues when generating MD5 hash cross-platform

    - by rogueprocess
    This is a general question about character encoding when using MD5 libraries in various languages. My concern is: suppose I generate an MD5 hash using a native Python string object, like this: message = "hello world" m = md5() m.update(message) Then I take a hex version of that MD5 hash using: m.hexdigest() and send the message & MD5 hash via a network, let's say, a JMS message or a HTTP request. Now I get this message in a Java program in the form of a native Java string, along with the checksum. Then I generate an MD5 hash using Java, like this (using the Commons Codec library): String md5 = org.apache.commons.codec.digest.DigestUtils.DigestUtils.md5Hex(s) My feeling is that this is wrong because I have not specified character encodng at either end. So the original hash will be based on the bytes of the Python version of the string; the Java one will be based on the bytes of the Java version of the string , these two byte sequences will often not be the same - is that right? So really I need to specify "UTF-8" or whatever at both ends right? (I am actually getting an intermittent error in my code where the MD5 checksum fails, and I suspect this is the reason - but because it's intermittent, it's difficult to say if changing this fixes it or not. ) Thank you!

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  • JPA @ManyToOne and composite PK

    - by Fleuri F
    Good Morning, I am working on project using JPA. I need to use a @ManyToOne mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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  • How to start with NOSQL using .net programming languages?

    - by Amr ElGarhy
    just was reading this article http://highscalability.com/blog/2010/3/23/digg-4000-performance-increase-by-sorting-in-php-rather-than.html And found this nice article http://wiki.apache.org/cassandra/DataModel I just want to know as a .net developer how to deal with NOSQL, and somethings like cassandra. I found that cassandra is apache product, is there something like this in microsoft world? or articles to know how to deal with cassandra using .net?

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  • evaluation of a java thread dump

    - by raticulin
    I got a thread dump of one of my processes. It has a bunch of these threads. I guess they are keeping a bunch of memory so I am getting OOM. "Thread-8264" prio=6 tid=0x4c94ac00 nid=0xf3c runnable [0x4fe7f000] java.lang.Thread.State: RUNNABLE at java.util.zip.Inflater.inflateBytes(Native Method) at java.util.zip.Inflater.inflate(Inflater.java:223) - locked <0x0c9bc640 (a java.util.zip.Inflater) at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.read(ZipArchiveInputStream.java:235) at com.my.ZipExtractorCommonsCompress.extract(ZipExtractorCommonsCompress.java:48) at com.my.CustomThreadedExtractorWrapper$ExtractionThread.run(CustomThreadedExtractorWrapper.java:151) Locked ownable synchronizers: - None "Thread-8241" prio=6 tid=0x4c94a400 nid=0xb8c runnable [0x4faef000] java.lang.Thread.State: RUNNABLE at java.util.zip.Inflater.inflateBytes(Native Method) at java.util.zip.Inflater.inflate(Inflater.java:223) - locked <0x0c36b808 (a java.util.zip.Inflater) at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.read(ZipArchiveInputStream.java:235) at com.my.ZipExtractorCommonsCompress.extract(ZipExtractorCommonsCompress.java:48) at com.my.CustomThreadedExtractorWrapper$ExtractionThread.run(CustomThreadedExtractorWrapper.java:151) Locked ownable synchronizers: - None I am trying to find out how it arrived to this situation. CustomThreadedExtractorWrapper is a wrapper class that fires a thread to do some work (ExtractionThread, which uses ZipExtractorCommonsCompress to extract zip contents from a compressed stream). If the task is taking too long, ExtractionThread.interrupt(); is called to cancel the operation. I can see in my logs that the cancellation happened 25 times. And I see 21 of these threads in my dump. My questions: What is the status of these threads? Alive and running? Blocked somehow? They did not die with .interrupt() apparently? Is there a sure way to really kill a thread? What does really mean 'locked ' in the stack trace? Line 223 in Inflater.java is: public synchronized int inflate(byte[] b, int off, int len) { ... //return is line 223 return inflateBytes(b, off, len); }

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