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  • Ruby - Writing Hpricot data to a file

    - by John
    Hey everyone, I am currently doing some XML parsing and I've chosen to use Hpricot because of it's ease of use and syntax, however I am running into some problems. I need to write a piece of XML data that I have found out to another file. However, when I do this the format is not preserved. For example, if the content should look like this: <dict> <key>item1</key><value>12345</value> <key>item2</key><value>67890</value> <key>item3</key><value>23456</value> </dict> And assuming that there are many entries like this in the document. I am iterating through the 'dict' items by using hpricot_element = Hpricot(xml_document_body) f = File.new('some_new_file.xml') (hpricot_element/:dict).each { |dict| f.write( dict.to_original_html ) } After using the above code, I would expect that the output look like the following exactly like the XML shown above. However to my surprise, the output of the file looks more like this: <dict>\n", " <key>item1</key><value>12345</value>\n", " <key>item2</key><value>67890</value>\n", " <key>item3</key><value>23456</value\n", " </dict> I've tried splitting at the "\n" characters and writing to the file one line at a time, but that didn't seem to work either as it did not recognize the "\n" characters. Any help is greatly appreciated. It might be a very simple solution, but I am having troubling finding it. Thanks!

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  • Unable to write to a text file

    - by chrissygormley
    Hello, I am running some tests and need to write to a file. When I run the test's the open = (file, 'r+') does not write to the file. The test script is below: class GetDetailsIP(TestGet): def runTest(self): self.category = ['PTZ'] try: # This run's and return's a value result = self.client.service.Get(self.category) mylogfile = open("test.txt", "r+") print >>mylogfile, result result = ("".join(mylogfile.readlines()[2])) result = str(result.split(':')[1].lstrip("//").split("/")[0]) mylogfile.close() except suds.WebFault, e: assert False except Exception, e: pass finally: if 'result' in locals(): self.assertEquals(result, self.camera_ip) else: assert False When this test run's, no value has been entered into the text file and a value is returned in the variable result. I havw also tried mylogfile.write(result). If the file does not exist is claim's the file does not exist and doesn't create one. Could this be a permission problem where python is not allowed to create a file? I have made sure that all other read's to this file are closed so I the file should not be locked. Can anyone offer any suggestion why this is happening? Thanks

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  • How can I speed up line by line reading of an ASCII file? (C++)

    - by Jon
    Here's a bit of code that is a considerable bottleneck after doing some measuring: //----------------------------------------------------------------------------- // Construct dictionary hash set from dictionary file //----------------------------------------------------------------------------- void constructDictionary(unordered_set<string> &dict) { ifstream wordListFile; wordListFile.open("dictionary.txt"); string word; while( wordListFile >> word ) { if( !word.empty() ) { dict.insert(word); } } wordListFile.close(); } I'm reading in ~200,000 words and this takes about 240 ms on my machine. Is the use of ifstream here efficient? Can I do better? I'm reading about mmap() implementations but I'm not understanding them 100%. The input file is simply text strings with *nix line terminations.

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  • python: how/where to put a simple libary installed in a well-known-place on my computer

    - by Jason S
    I need to put a python script somewhere on my computer so that in another file I can use it. How do I do this and where do I put it? And where in the python documentation do I learn how to do this? I'm a beginner + don't use python much. library file: MyLib.py put in a well-known place def myfunc(): .... other file SourceFile.py located elsewhere, doesn't need to know where MyLib.py is: something = MyLib.myfunc()

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  • write cache and write sequence order

    - by excanoe
    ok, here i have some weird question: let say we have some binary file (.log), and sequence of write operations, for example log1, log2, log3 and each has some block size n (raw data). question: can I be sure that log1,log2 and log3 sequences can be written in the correct order in ONE file, even if i have few cache levels (disk hardware and os level)? update very interested in what will be with records order (not with records) if we have software or hardware failure (reboot or another reason). update there can be some percent of write failures, but main question is: will write order stay correct?

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  • How to get proper alignment when printing to file

    - by user1067334
    I have this Structure the elements of which that I need to write in a text file struct Stage3ADisplay { int nSlot; char *Item; char *Type; int nIndex; unsigned char attributesMD[17]; //the last character is \0 unsigned char contentsMD[17]; //only for regular files - //the last character is \0 }; buffer = malloc(sizeof(Stage3ADisplayVar[nIterator]->nSlot) + sizeof(Stage3ADisplayVar[nIterator]->Item) + sizeof(Stage3ADisplayVar[nIterator]->Type) + sizeof(Stage3ADisplayVar[nIterator]->nIndex) + sizeof(Stage3ADisplayVar[nIterator]->attributesMD) + sizeof(Stage3ADisplayVar[nIterator]->contentsMD) + 1); sprintf (buffer,"%d %s %s %d %x %x",Stage3ADisplayVar[nIterator]->nSlot, Stage3ADisplayVar[nIterator]->Item,Stage3ADisplayVar[nIterator]->Type,Stage3ADisplayVar[nIterator]->nIndex,Stage3ADisplayVar[nIterator]->attributesMD,Stage3ADisplayVar[nIterator]->contentsMD); How do I make sure the rows in the file are properly aligned. Thank you.

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  • download large files using servlet

    - by niks
    I am using Apache Tomcat Server 6 and Java 1.6 and am trying to write large mp3 files to the ServletOutputStream for a user to download. Files are ranging from a 50-750MB at the moment. The smaller files aren't causing too much of a problem but with the larger files it and getting socket exception broken pipe. File fileMp3 = new File(objDownloadSong.getStrSongFolder() + "/" + strSongIdName); FileInputStream fis = new FileInputStream(fileMp3); response.setContentType("audio/mpeg"); response.setHeader("Content-Disposition", "attachment; filename=\"" + strSongName + ".mp3\";"); response.setContentLength((int) fileMp3.length()); OutputStream os = response.getOutputStream(); try { int byteRead = 0; while ((byteRead = fis.read()) != -1) { os.write(byteRead); } os.flush(); } catch (Exception excp) { downloadComplete = "-1"; excp.printStackTrace(); } finally { os.close(); fis.close(); }

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  • File mode for creating+reading+appending+binary

    - by MihaiD
    I need to open a file for reading and writing. If the file is not found, it should be created. It should also be treated as a binary for Windows. Can you tell me the file mode sequence I need to use for this? I tried 'r+ab' but that doesn't create the files if they are not found. Thanks

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  • Fastest Way To Format a Plain Text Using Javascript

    - by Nathan Campos
    I have a huge plain text document, about 700kb which is very big for plain texts and I need to format it on cloud converting it to HTML, but the only things that I need to replace, format to HTML so it can be displayed by the browser, are bold and italic. For bold at the plain text they are like this: Not on bold... **bold text here** not bold here And italic like this: Not italic... *italic text* no italic Just like StackOverflow does for their formatting, but the problem is that I need to make it a lot faster, since the text is so big... One of my ideas was to add a page slide, so I the script just need to format some part of the text, not it all, then after the user changes the page the script would be called again, but the problem is how I can make the code for this all?

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  • Create whole path automatically when writing to a new file

    - by Bernhard V
    Hi, I want to write a new file with the Java FileWriter. I use it like this: FileWriter newJsp = new FileWriter("C:\\user\Desktop\dir1\dir2\filename.txt"); Now the dir1 and dir2 currently don't exist. I want Java to create them automatically if they aren't already there. Actually Java should set up the whole file path if not already existing. How can I achieve this?

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  • Reading and writing in parallel

    - by Malfist
    I want to be able to read and write a large file in parallel, or if not in parallel, at least in blocks so that I don't use up so much memory. This is my current code: // Define memory stream which will be used to hold encrypted data. MemoryStream memoryStream = new MemoryStream(); // Define cryptographic stream (always use Write mode for encryption). CryptoStream cryptoStream = new CryptoStream(memoryStream, encryptor, CryptoStreamMode.Write); //start encrypting using (BinaryReader reader = new BinaryReader(File.Open(fileIn, FileMode.Open))) { byte[] buffer = new byte[1024 * 1024]; int read = 0; do { read = reader.Read(buffer, 0, buffer.Length); cryptoStream.Write(buffer, 0, read); } while (read == buffer.Length); } // Finish encrypting. cryptoStream.FlushFinalBlock(); // Convert our encrypted data from a memory stream into a byte array. //byte[] cipherTextBytes = memoryStream.ToArray(); //write our memory stream to a file memoryStream.Position = 0; using (BinaryWriter writer = new BinaryWriter(File.Open(fileOut, FileMode.Create))) { byte[] buffer = new byte[1024 * 1024]; int read = 0; do { read = memoryStream.Read(buffer, 0, buffer.Length); writer.Write(buffer, 0, read); } while (read == buffer.Length); } // Close both streams. memoryStream.Close(); cryptoStream.Close(); As you can see, it reads the entire file into memory, encrypts it, then writes it out. If I happen to be encrypting files that are very large (2GB+) it tends not to work, or at the very least, consumes ~97% of my memory. How could I do it in a more effective manner?

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  • How can chunks be allocated in a node.js stream in object mode all at once?

    - by Quentin Engles
    I can see how buffers, and strings can be sent as chunks, but I'm having a problem thinking about how streams can be dealt when working in object mode. Say I have a byte stream from an http request message. I want to take that message, parse, and then transform it into one big object. I already know how to parse the message. What I'm wondering is if the message is big so it has many chunks, but I want to make one object for the output how can I make sure the data event waits for the whole thing? Is this just a matter of not using the push method until the chunked data has finished being sent? That would then restrict the stream data output to a smaller object which I think I'm fine with for now. As an added condition the larger data will be reduced in size after the the transform.

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  • Read char from txt file in C++

    - by Jack in the Box
    I have a program that will read the number of rows and columns from a txt file. Also, the program has to read the contents of a 2D array from the same file. Here is the txt file 8 20 * * *** *** 8 and 20 are the number of rows and columns respectively. The spaces and asterisks are the contents of the array, Array[8][20] For example, Array[0][1] = '*' I did make the program reading 8 and 20 as follow: ifstream myFile; myFile.open("life.txt"); if(!myFile) { cout << endl << "Failed to open file"; return 1; } myFile >> rows >> cols; myFile.close(); grid = new char*[rows]; for (int i = 0; i < rows; i++) { grid[i] = new char[cols]; } Now, how to assign the spaces and the asterisks to to the fields in the array? I hope you got the point.

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  • FileNotFound exception

    - by Pratik
    I am trying to read a file in a servlet. I am using eclipse IDE. I get a FileNotFoundException if I provide relative file name. List<String> ls=new ArrayList<String>(); Scanner input = new Scanner(new File("Input.txt")); while(input.hasNextLine()) { ls.add(input.nextLine()); } The same code works if I put the absolute path like this: Scanner input = new Scanner(new File("F:/Spring and other stuff/AjaxDemo/src/com/pdd/ajax/Input.txt")); The Java file and text file are there in the same folder. Does it searches text file in some other folder ?

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  • Python text file processing speed issues

    - by Anonymouslemming
    Hi all, I'm having a problem with processing a largeish file in Python. All I'm doing is f = gzip.open(pathToLog, 'r') for line in f: counter = counter + 1 if (counter % 1000000 == 0): print counter f.close This takes around 10m25s just to open the file, read the lines and increment this counter. In perl, dealing with the same file and doing quite a bit more (some regular expression stuff), the whole process takes around 1m17s. Perl Code: open(LOG, "/bin/zcat $logfile |") or die "Cannot read $logfile: $!\n"; while (<LOG>) { if (m/.*\[svc-\w+\].*login result: Successful\.$/) { $_ =~ s/some regex here/$1,$2,$3,$4/; push @an_array, $_ } } close LOG; Can anyone advise what I can do to make the Python solution run at a similar speed to the Perl solution? I've tried just uncompressing the file and dealing with it using open instead of gzip.open, but that made a very small difference to the overall time.

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  • How to create custom filenames in C?

    - by eSKay
    Please see this piece of code: #include<stdio.h> #include<string.h> #include<stdlib.h> int main() { int i = 0; FILE *fp; for(i = 0; i < 100; i++) { fp = fopen("/*what should go here??*/","w"); //I need to create files with names: file0.txt, file1.txt, file2.txt etc //i.e. file{i}.txt } }

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  • How do I open a file in such a way that if the file doesn't exist it will be created and opened automatically?

    - by snakile
    Here's how I open a file for writing+ : if( fopen_s( &f, fileName, "w+" ) !=0 ) { printf("Open file failed\n"); return; } fprintf_s(f, "content"); If the file doesn't exist the open operation fails. What's the right way to fopen if I want to create the file automatically if the file doesn't already exist? EDIT: If the file does exist, I would like fprintf to overwrite the file, not to append to it.

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  • File.Exists() returns false, but not in debug

    - by Tor Haugen
    I'm being completely confused here folks, My code throws an exception because File.Exists() returns false public override sealed TCargo ReadFile(string fileName) { if (!File.Exists(fileName)) { throw new ArgumentException("Provided file name does not exist", "fileName"); } Visual studio breaks at the throw statement, and I immediately check the value of File.Exists(fileName) in the immediate window. It returns true. When I drag the breakpoint back up to the if statement and execute it again, it throws again. fileName is an absolute path to a file. I'm not creating the file, nor writing to it (it's there all along). If I paste the path into the open dialog in Notepad, it reads the file without problems. The code is executing in a background worker. It's the only complicating factor I can think of. I am positive the file has not been opened already, either in the worker thread or elsewhere. What's going on here?

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  • Exciting new Evented I/O technologies

    - by Saif Bechan
    Lately I have been having my eye on evented I/O to tackle some of my web application problems. I have been looking at things as Python's Twisted, Ruby's Eventmachine, and Node.js. Are there any other alternatives to these three, maybe in other languages as PHP ?

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  • Seeking to a line in a file in g++

    - by Phenom
    Is there a way that I can seek to a certain line in a file to read or write data? Let's say I want to write some data starting on the 10th line in a text file. There might be some data already in the first few lines, or the file could even be empty. Is there a way I can seek directly to the line I want without having to worry about what's already in the file?

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  • [c++] How to create a std::ofstream to a temp file?

    - by dehmann
    Okay, mkstemp is the preferred way to create a temp file in POSIX. But it opens the file and returns an int, which is a file descriptor. From that I can only create a FILE*, but not an std::ofstream, which I would prefer in C++. (Apparently, on AIX and some other systems, you can create an std::ofstream from a file descriptor, but my compiler complains when I try that.) I know I could get a temp file name with tmpnam and then open my own ofstream with it, but that's apparently unsafe due to race conditions, and results in a compiler warning (g++ v3.4. on Linux): warning: the use of `tmpnam' is dangerous, better use `mkstemp' So, is there any portable way to create an std::ofstream to a temp file?

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