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  • How to begin writing an Application Server over Apache?

    - by Cracker
    For my college project, I want to create a simple application server in C that runs over Apache. Like .php, .asp, .jsp, the extension of my files would be .sas. I have already written a parser which reads the .sas files and generates the output. For example, consider a file index.sas with the below code: <% echo "Hello"; %> Now, if I execute: sas index.sas The result would be: Hello Now I want to use this program as an application server over Apache just as PHP, Tomcat, etc. work over Apache. I have heard of cgi-bin but I think PHP uses a different approach. I want to learn the approach which PHP uses. Please advice.

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  • links in codeigniter

    - by Patrick
    hi All, I'm experimenting with codeigniter but don't really understand how links work. for example, I have a link like this: localhost/ci/welcome/cat/7 My base url is localhost/ci, so by clicking on this link I would expect the method "cat" of controller "welcome" to be called. This method is very simple: function cat() { echo "just a test."; } Pretty basic - I would expect to see the text on screen, but I just see a 404 -page not found error. What could be the problem?

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  • pass php array to jquery with getJSON

    - by robertdd
    i want to pass a php aray to jQuery: $.getimagesarr = function() { $.getJSON('operations.php', {'operation':'getimglist'}, function(data){ var arr = new Array(); arr = data; return arr; }); } var data = $.getimagesarr(); if (data){ jQuery.each(data, function(i, val) { .... }); } it return undefined in php i have this: function getimglist(){ $results = $_SESSION['files']; echo json_encode($results); } it is possible?

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  • Bash loop command until file contains n duplicate entries (lines)

    - by Andrew
    Hello, I'm writing a script and I need to create a loop that will execute same commands until file does contain a specified number of duplicate entries. For example, with each loop I will echo random string to file results. And I want loop to stop when there are 10 lines of of the same string. I thought of something like while [ `some command here (maybe using uniq)` -lt 10 ] do command1 command2 command3 done Do you have any idea how can this problem be solved? Using grep can't be done since I don't know what string I need to look for. Thank you for your suggestions.

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  • Connect to a MySQL database and count the number of rows.

    - by Hugo
    Hi there! I need to connect to a MySQL database and then show the number of rows. This is what I've got so far; <?php include "connect.php"; db_connect(); $result = mysql_query("SELECT * FROM hacker"); $num_rows = mysql_num_rows($result); echo $num_rows; ?> When I use that code I end up with this error; Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\Documents and Settings\username\Desktop\xammp\htdocs\news2\results.php on line 10 Thanks in advance :D

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  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

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  • JQuery,ajax problem?

    - by user303832
    Hello,I have one table,and when I click on row,it load some content in another table,problem is,when I first time click on row it loads just one time(message 'Some msg' and message 'Some other msg' is showen one time),when I click on other row,it loads twice(messages is shown twice),third time when I click on row it loads three times,ets.Here is my code. $.ajax({ url:'<?php echo $full_path_ajax_php; ?>', data:{'what':'2','mypath':'12345678'}, dataType:'json', type: 'GET', beforeSend:function(){alert('Some msg')}, success: function(){alert('Some other msg')} }); return false; Can someone help me please to understand this.Tnx in advance.

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  • update a column in input file by taking value from Database in perl.

    - by Rahul Singh
    input file: 1,a,USA,, 2,b,UK,, 3,c,USA,, i want to update the 4th column in the input file from taking values from one of the table. my code looks like this: my $customer_dbh = DBI-connect("DBI:Oracle:$INST", $USER, $PASS ) or die "Couldn't connect to datbase $INST"; my $cust_smh; print "connected \n "; open FILE , "+$input_file" or die "can't open the input file"; print "echo \n"; while(my $line=) { my @line_a=split(/\,/,$line); my $customer_id=$line_a[3]; print "$customer_id\n"; $cust_smh = $customer_dbh-prepare("SELECT phone_no from book where number = $line_a[0]"); $cust_smh-execute() or die "Couldn't execute stmt, error : $DBI::errstr"; my $number = $cust_smh-fetchrow_array(); $line_a[3]=$number; }

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  • PHP Array To Class Static Public Values.

    - by what
    I want to make a class that has all the values of an array as a static object in that class. For example: $vars=array(... );//some array with actual values $Class_code='class MyClass{'; for($i=0; $i<count($vars); $i++){ $Class_code.='static public $'.strval($vars[i]).';'; } eval($Class_code.'}'); /* When I echo the line above it says that the vars for MyClass (MyClass::vars) are missing even with strval(). */ So, how can I get $vars[i] to be a string if strval didn't work?

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  • How much time roughly it takes to learn ASP.net programming

    - by Mirage
    I am a PHP MYSQL person but now i have got webiste to do it ASP.net. I kow nothing about ASP.NET. INitially i was thinking of ASP.NET as a programming language but now i now its not , i really don't know what it is. Someone told me that i have to do c sharp to build the website. I i have to display simple data from database how much different is c sharp from php. Does it has all function like php to echo stuff etc

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  • Run exe on computer in network through batch file

    - by Peter Kottas
    I have few computers connected to the network and I want to create batch files to automatize the process of working with them. I have already created one used to shutdown computers at once. It is very simple I ll just post it for the sake of argument. @echo off shutdown -s -m \\Slave1-PC shutdown -s -m \\Slave2-PC shutdown -s -m \\Slave3-PC Now I want to execute programs on these machines. So lets say there is "example.exe" file located "\Slave1-PC\d\example.exe" using call \\Slave1-PC\\d\\example.exe runs it on my computer through network and i didn't come up with anything else. I dont want to use any psexec if possible. Help would be much appreciated. Peter

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  • pyramid traversal resource url no attribute __name__

    - by Santana
    So I have: resources.py: def _add(obj, name, parent): obj.__name__ = name obj.__parent__ = parent return obj class Root(object): __parent__ = __name__ = None def __init__(self, request): super(Root, self).__init__() self.request = request self.collection = request.db.post def __getitem__(self, key): if u'profile' in key: return Profile(self.request) class Profile(dict): def __init__(self, request): super(Profile, self).__init__() self.__name__ = u'profile' self.__parent__ = Root self.collection = request.db.posts def __getitem__(self, name): post = Dummy(self.collection.find_one(dict(username=name))) return _add(post, name, self) and I'm using MongoDB and pyramid_mongodb views.py: @view_config(context = Profile, renderer = 'templates/mytemplate.pt') def test_view(request): return {} and in mytemplate.pt: <p tal:repeat='item request.context'> ${item} </p> I can echo what's in the database (I'm using mongodb), but when I provided a URL for each item using resource_url() <p tal:repeat='item request.context'> <a href='${request.resource_url(item)}'>${item}</a> </p> I got an error: 'dict' object has no attribute '__name__', can someone help me?

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  • PHP & MySQL form question.

    - by peakUC
    How do I allow all users to have there username field empty without having them to enter a username when they submit the form using PHP and MySQL? Here is part my PHP and MySQL code. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if(isset($_POST['username'])) { // Make sure the username address is available: $u = "SELECT * FROM users WHERE username = '$username' AND user_id <> '$user_id'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { // Unavailable. echo '<p class="error">Your username is unavailable!</p>'; $username = NULL; } else if(mysqli_num_rows($r) == 0) { // Available. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); } }

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  • Passing an array of data to a private function in CodeIgniter/PHP? [facepalm]

    - by Jack Webb-Heller
    So I thought this should be easy, but, I'm n00bing out here and failing epicly (as they say on teh interwebz). So here's my code: function xy() { $array['var1'] = x; $array['var2'] = y; echo $this->_z; } function _z($array) { $xy = $x.$y; return $xy; } So, why doesn't that seemingly simple code work? I know with views you can pass arrays and the variables are accessible in the views with just their array title, but, why doesn't it work in this case? Jack

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  • PHP & Regular expression: keyword just occurs once

    - by lauthiamkok
    Hi, how can I make sure a certain keyword just occurs once in the input with regular expression? I think there is some mistakes in the expression below as I can repeat the same keywords, if (!preg_match('/\b(.php?){1}\b/', $cfg_path)) { $error = true; echo '<error elementid="cfg_path" message="PATH - make sure you have a \'.php?\' in the path."/>'; } I just want this to be true, form.php?category=something or form.php? but not this, form.php?.php?category=something or form.php?.php? please let me know how to fix it. thanks.

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  • recaptcha image and curl + php

    - by user253530
    $page = $curl->post($baseUrl.'/submit.php', array('url'=>$address,'phase'=>'1','randkey'=>$randKey[0],'id'=>'c_1')); $exp = explode('recaptcha_image',$page); The id recaptcha_image is not found although if i echo $page; the webpage will be displayed and surprisingly even the recpatcha div (with the image itself). Curl shouldn't load the image for recaptcha but somehow it does though when i try to find the div, it is not there. Is there a way to capture the url of the recaptcha image?

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  • PHP form validation submit problem

    - by TaG
    Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

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  • Windows environment variables change when opening command line?

    - by Jakobud
    Sometimes when I change my environment variables in Windows, and then use software the depends on those variables, they are not properly updated. And good example is to change a variable, then open up Windows Command Line and echo the variable and see that it hasn't been changed, even though you properly changed it in the Environment Variables window. Another example I'm dealing with right now: I've been using Python 2.4.x for a while for a project, which uses the env var PYTHONPATH who's value has been: C:\Python24;C:\Python24\lib Today I installed Python 2.5.x for the project. I changed my PYTHONPATH to be: C:\Python25;C:\Python25\lib When I use Python 2.5 to run a script and do this: import sys print sys.path It prints: 'C:\\PYTHON24', 'C:\\PYTHON24\\lib' (and some other Python 2.5 related default installation paths) So clearly, the old PYTHONPATH environment variable changes aren't really sticking.... Does anyone know why this happens and how to fix it?

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  • PHP reads 1.10 value as 1.1 (0 at end of variable not honored)

    - by adbox
    Hello, This is hard for me to word, but easier for me to demonstrate: I have a select option: <option <?php if($frequency[$key]=='1.10'){echo "selected";}?> value='1.10'>1 every 10 days</option> Really, $frequency[$key]=1.1; , but the above still shows up selected. I've never seen this before, and didnt know it could happen. Any ideas on how to prevent this? Working with php5. Thank you, Hudson

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  • mysql_connect()

    - by Jacksta
    I am trying to connect to mysql and am getting an error. I put my servers ip address in and used port 3306 whihch post should be used? <?php $connection = mysql_connect("serer.ip:port", "user", "pass") or die(mysql_error()); if ($connection) {$msg = "success";} ?> <html> <head> </head> <body> <? echo "$msg"; ?> </body> </html> Here is the error its producing Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'admin'@'server1.myserver.com' (using password: YES) in /home/admin/domains/mydomain.com.au/public_html/db_connect.php on line 3 Access denied for user 'admin'@'server1.myserver.com' (using password: YES)

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  • Jquery mobile email form with php script

    - by Pablo Marino
    i'm working in a mobile website and i'm having problems with my email form The problem is that when I receive the mail sent through the form, it contains no data. All the data entered by the user is missing. Here is the form code <form action="correo.php" method="post" data-ajax="false"> <div> <p><strong>You can contact us by filling the following form</strong></p> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="first_name">First Name</label> <input id="first_name" placeholder="" type="text" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="last_name">Last name</label> <input id="last_name" placeholder="" type="text" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="email">Email</label> <input id="email" placeholder="" type="email" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="telephone">Phone</label> <input id="telephone" placeholder="" type="tel" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="age">Age</label> <input id="age" placeholder="" type="number" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup" data-mini="true"> <label for="country">Country</label> <input id="country" placeholder="" type="text" /> </fieldset> </div> <div data-role="fieldcontain"> <fieldset data-role="controlgroup"> <label for="message">Your message</label> <textarea id="message" placeholder="" data-mini="true"></textarea> </fieldset> </div> <input data-inline="true" data-theme="e" value="Submit" data-mini="true" type="submit" /> </form> Here is the PHP code <? /* aqui se incializan variables de PHP */ if (phpversion() >= "4.2.0") { if ( ini_get('register_globals') != 1 ) { $supers = array('_REQUEST', '_ENV', '_SERVER', '_POST', '_GET', '_COOKIE', '_SESSION', '_FILES', '_GLOBALS' ); foreach( $supers as $__s) { if ( (isset($$__s) == true) && (is_array( $$__s ) == true) ) extract( $$__s, EXTR_OVERWRITE ); } unset($supers); } } else { if ( ini_get('register_globals') != 1 ) { $supers = array('HTTP_POST_VARS', 'HTTP_GET_VARS', 'HTTP_COOKIE_VARS', 'GLOBALS', 'HTTP_SESSION_VARS', 'HTTP_SERVER_VARS', 'HTTP_ENV_VARS' ); foreach( $supers as $__s) { if ( (isset($$__s) == true) && (is_array( $$__s ) == true) ) extract( $$__s, EXTR_OVERWRITE ); } unset($supers); } } /* DE AQUI EN ADELANTE PUEDES EDITAR EL ARCHIVO */ /* reclama si no se ha rellenado el campo email en el formulario */ /* aquí se especifica la pagina de respuesta en caso de envío exitoso */ $respuesta="index.html#respuesta"; // la respuesta puede ser otro archivo, en incluso estar en otro servidor /* AQUÍ ESPECIFICAS EL CORREO AL CUAL QUEIRES QUE SE ENVÍEN LOS DATOS DEL FORMULARIO, SI QUIERES ENVIAR LOS DATOS A MÁS DE UN CORREO, LOS PUEDES SEPARAR POR COMAS */ $para ="[email protected];" /* this is not my real email, of course */ /* AQUI ESPECIFICAS EL SUJETO (Asunto) DEL EMAIL */ $sujeto = "Mail de la página - Movil"; /* aquí se construye el encabezado del correo, en futuras versiones del script explicaré mejor esta parte */ $encabezado = "From: $first_name $last_name <$email>"; $encabezado .= "\nReply-To: $email"; $encabezado .= "\nX-Mailer: PHP/" . phpversion(); /* con esto se captura la IP del que envío el mensaje */ $ip=$REMOTE_ADDR; /* las siguientes líneas arman el mensaje */ $mensaje .= "NOMBRE: $first_name\n"; $mensaje .= "APELLIDO: $last_name\n"; $mensaje .= "EMAIL: $email\n"; $mensaje .= "TELEFONO: $telephone\n"; $mensaje .= "EDAD: $age\n"; $mensaje .= "PAIS: $country\n"; $mensaje .= "MENSAJE: $message\n"; /* aqui se intenta enviar el correo, si no se tiene éxito se da un mensaje de error */ if(!mail($para, $sujeto, $mensaje, $encabezado)) { echo "<h1>No se pudo enviar el Mensaje</h1>"; exit(); } else { /* aqui redireccionamos a la pagina de respuesta */ echo "<meta HTTP-EQUIV='refresh' content='1;url=$respuesta'>"; } ?> Any help please? Thanks in advance Pablo

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  • Which is more efficient/faster when calling a cached image?

    - by andufo
    Hi, i made an image resizer in php. When an image is resized, it caches a new jpg file with the new dimensions. Next time you call the exact img.php?file=hello.jpg&size=400 it checks if the new jpg has already been created. If it has NOT been created yet, it creates the file and then prints the output (cool). If it ALREADY exists, no new file needs to be generated and instead, it just calls the already cached file. My question is regarding the second scenario. Which of these is faster? redirecting: header('Location: cache/hello_400.jpg');die(); grabbing data and printing the cached file: $data = file_get_contents('cache/hello_400.jpg'); header('Content-type: '.$mime); header('Content-Length: '.strlen($data)); echo $data; Any other ways to improve this?

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  • How can I run a package created with Simple Build Tool?

    - by Lukasz Lew
    I run: $ echo 'object Hi { def main(args: Array[String]) { println("Hi!") } }' > hw.scala $ sbt > warn Set log level to warn > run Hi! > package $ java -jar target/scala_2.7.7/test_2.7.7-1.0.jar Exception in thread "main" java.lang.NoClassDefFoundError: scala/ScalaObject at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:621) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:124) at java.net.URLClassLoader.defineClass(URLClassLoader.java:260) Why can't I run this jar package this way?

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  • php - track down premature headers leak

    - by user151841
    I'm using set_cookie() on a site. After adding some functionality, I'm getting Warning: Cannot modify header information - headers already sent by... error. The line number it references as to where the headers initiated from is the very line where set_cookie() is! And I checked, it's not being called twice. How can I track down these premature headers? I looked at the source code and didn't see any stray characters or anything before the error message starts ( I'm using xdebug, so the first thing is a , which I thought was me, but is actually the beginning of the xdebug message ). I've grepped my code for extra echo and so forth -- nothing. Can PHP tell me when and where the headers are starting? Or are they really starting on the set_cookie line, and if so, how have I gotten myself into this situation, and how do I get out?

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  • node_load in drupal gets incorrect node when you are NOT logged in

    - by Alaa
    Hi All, i have a module and i am using node_load(array('nid' = arg(1))); now the problem is that this function keep getting its data for node_load from DB cache. how can i force this function to not use DB cache or static value? Example my link is http://mydomain.com/node/344983 now: $node=node_load(array('nid'=arg(1)),null,true); echo $node-nid; output: 435632 which is a randomly node id (available in the database) and everytime i ctrl+F5 my browser, i get new nid!! Note: if i am logged in, it gives the result correctly, but this problem happens only when i am browsing the website as an anonymous user i really appreciate any idea!! Thanks

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