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  • Display loading image while post with ajax

    - by DonJoe
    I know there are thousands of examples on the internet, but I want for the script I already have to display a loading gif image while the data is retrievedd. My java knowledge are poor, therefore I'm asking how to change the following: <script type="text/javascript"> $(document).ready(function(){ function getData(p){ var page=p; $.ajax({ url: "loadData.php?id=<? echo $id; ?>", type: "POST", cache: false, data: "&page="+ page, success : function(html){ $(".content").html(html); } }); } getData(1); $(".page").live("click", function(){ var id = $(this).attr("class"); getData(id.substr(8)); }); }); </script> And my div is here: <div class="content" id="data"></div> Thanks. John

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  • Substring extraction using bash shell scripting and awk

    - by rohanbk
    So, I have a file called 'dummy' which contains the string: "There is 100% packet loss at node 1". I also have a small script that I want to use to grab the percentage from this file. The script is below. result=`grep 'packet loss' dummy` | awk '{ first=match($0,"[0-9]+%") last=match($0," packet loss") s=substr($0,first,last-first) print s}' echo $result I want the value of $result to basically be 100% in this case. But for some reason, it just prints out a blank string. Can anyone help me?

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  • Get only new RSS entries with PHP Script ?

    - by ArneRie
    What im trying to do: Fetch X numbers of RSS Feeds from my Blogs and echo only new entries. My Problem is, how to know wich items are already parsed? Solution so far: Fetch the Feed every 5 hours, store all titles inside an Database table or flat file. Next run check if the title is already in database if not print it and save it inside the database. But iam not sure if this is best practise to do this? If someone knows a fast way, it would be great. Sorry for my poor english.

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • Website including pages/pages to my site

    - by Azzyh
    Hello.. I have my site on index.html made in html+css., at my index.html i have this div id "content", where you put in main content to the page, and there's a link at the menubar that src to page2.php. When you press on the link it goes to the page2.php, but i want it to display inside the < div "content". In page2 i have Hello this is a test, in a echo.. I dont want to use frames.. should i split up my design on index.php, and then on page2.php include top & footer? or is there another way

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  • What is wrong with my SQL syntax here?

    - by CT
    New to SQL. I'm looking to create a IT asset database. Here is one of the tables created with php: mysql_query("CREATE TABLE software( id VARCHAR(30), PRIMARY KEY(id), software VARCHAR(30), key VARCHAR(30))") or die(mysql_error()); echo "Software Table Created.</br />"; This is the output from the browser when I run the script: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VARCHAR(30))' at line 5 I am running a standard LAMP stack on Ubuntu Server 10.04. Thank you.

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  • php - upload script mkdir saying file already exists when same directory even though different filename

    - by neeko
    my upload script says my file already exists when i try upload even though different filename <?php // Start a session for error reporting session_start(); ?> <?php // Check, if username session is NOT set then this page will jump to login page if (!isset($_SESSION['username'])) { header('Location: index.html'); } // Call our connection file include('config.php'); // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/JPG", "image/jpeg", "image/bmp", "image/gif", "image/png"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // Grab the User ID we sent from our form $user_id = $_SESSION['username']; $category = $_POST['category']; // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "img/users/$category/$user_id/"; mkdir($TARGET_PATH, 0755, true); // Get our POSTed variables $fname = $_POST['fname']; $lname = $_POST['lname']; $contact = $_POST['contact']; $price = $_POST['price']; $image = $_FILES['image']; // Build our target path full string. This is where the file will be moved do // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $fname == "" || $lname == "" || $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: error.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: error.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: error.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $imagename = $image['name']; $sql = "insert into people (price, contact, category, username, fname, lname, expire, filename) values (:price, :contact, :category, :user_id, :fname, :lname, now() + INTERVAL 1 MONTH, :imagename)"; $q = $conn->prepare($sql) or die("failed!"); $q->bindParam(':price', $price, PDO::PARAM_STR); $q->bindParam(':contact', $contact, PDO::PARAM_STR); $q->bindParam(':category', $category, PDO::PARAM_STR); $q->bindParam(':user_id', $user_id, PDO::PARAM_STR); $q->bindParam(':fname', $fname, PDO::PARAM_STR); $q->bindParam(':lname', $lname, PDO::PARAM_STR); $q->bindParam(':imagename', $imagename, PDO::PARAM_STR); $q->execute(); $sql1 = "UPDATE people SET firstname = (SELECT firstname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql1) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); $sql2 = "UPDATE people SET surname = (SELECT surname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql2) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); header("Location: search.php"); exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: error.php"); exit; } ?>

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  • Display data requested by an ajax.load() call once complete, not during the call.

    - by niczoom
    My jQuery code (using ajax) request's data from a php script (pgiproxy.php) using the following function: function grabPage($pageURL) { $homepage = file_get_contents($pageURL); echo $homepage; } I then extract the html code i need from the returned data using jQuery and insert it into a div called #BFX, as follows: $("#btnNewLoadMethod1").click(function(){ $('#temp1').load('pgiproxy.php', { data : $("#formdata").serialize(), mode : "graph"} , function() { $('#temp').html( $('#temp1').find('center').html() ); $('#BFX').html( $('#temp').html() ); }); }); This works fine. I get the html data (which is a gif image) i need displayed on screen in the correct div. The problem is i can see the html data loading into the div (dependant on network speed), but what I want is to insert the extracted html code into #BFX ONLY when the ajax request has fully completed.

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  • Wordpress: Not able to retrieve css for new plugin in admin mode

    - by Steven
    I'm creating a new plugin which will have it's own css file. The css file resides in the root folder of the plugin. In the plugin section of the admin interface, I have added a few text fields fields. But the CSS is not applied. I'm adding the CSS file using this code: // Register styling add_action('admin_init', 'event_styles'); function event_styles() { wp_register_style('event_cal', plugins_url('eventcall.css',__FILE__)); wp_enqueue_style('event_cal'); } The following code gives me the CSS path: echo plugins_url('eventcall.css',__FILE__); and outputs http://mysite.com/wp-content/plugins/wp-eventcal/eventcall.css If I try to enter this URL directly in the browser, it only shows me the front page. And if I look in the source code using Firebug, where the link to the CSS should be, I only find the entire HTML code for the front page. Am I using wrong code to use backend in admin interface? In my HOST file, I have added ``

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  • Unable to open a file for writing

    - by asdasdas
    I am trying to write to a file. I do a file_exists check on it before I do fopen and it returns true (the file does exist). However, the file fails this code and gives me the error every time: $handle = fopen($filename, 'w'); if($handle) { flock($handle, LOCK_EX); fwrite($handle, $contents); } else { echo 'ERROR: Unable to open the file for writing.',PHP_EOL; exit(); } flock($handle, LOCK_UN); fclose($handle); Is there a way I can get more specific error details as to why this file does not let me open it for writing? I know that the filename is legit, but for some reason it just wont let me write to it. I do have write permissions, I was able to write and write over another file.

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  • How to substr html entities properly?

    - by Emily
    Hi everyone. I have like this : $mytext="that&#039;s really &quot;confusing&quot; and &lt;absolutly&gt; silly"; echo substr($mytext,0,6); The output in this case will be : that&# instead of that's What i want is to count html entities as 1 character then substr, because i always end up with breaked html or some obscure characters at the end of text. Please don't suggest me to html decode it then substr then encode it, i want a clean method :) Thanks

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  • Getting the number of feedburner subscribers?

    - by iMaster
    I'm currently using this code to get the number of subscribers to my blog: $whaturl="http://api.feedburner.com/awareness/1.0/GetFeedData?uri=http://feeds.feedburner.com/DesignDeluge"; $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_URL, $whaturl); $data = curl_exec($ch); curl_close($ch); $xml = new SimpleXMLElement($data); $fb = $xml->feed->entry['circulation']; but when I echo $fb it doesn't work (the whole file that $fb is being echoed on doesn't appear). Any ideas on why this isn't working?

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  • Korn Shell - Test with variable that may be not set

    - by C. Ross
    I have the following code in KornShell FAILURE=1 SUCCESS=0 isNumeric(){ if [ -n "$1" ]; then case $1 in *[!0-9]* | "") return $FAILURE; * ) return $SUCCESS; esac; else return $FAILURE; fi; } #... FILE_EXT=${FILE#*.} if [ isNumeric ${FILE_EXT} ]; then echo "Numbered file." fi #... In some cases the file name not have an extension, and this causes the FILE_EXT variable to be empty, which causes the following error: ./script[37]: test: 0403-004 Specify a parameter with this command. How should I be calling this function so that I do not get this error?

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  • Passing get values mangles my urls

    - by SibLiant
    Just upgraded from 1.3 to 2.0.3 and I'm trying to migrate all the changes. I'm noticing that the following line echo $this->Html->link('Quote', array('controller'=>'crm_quotes', 'action'=>'index', $lead['id'].'/'.$crmContact['CrmContact']['id']), null); builds the url "/crm_quotes/index/15/21". When I click the link I'm taken to url: "/crm_quotes/index/15%2F212 so it's replacing the characters with the html # but it's ultimately breaking the link. When I manually edit the URL to the correct one: "/crm_quotes/index/15/21" the page loads. Can someone enlighten me? Should I be using the url function rather than link? I have a lot of pages that need multiple parameters passed in the url. I was using named parameters but after reading some comments by Mark Story I decided to stop the named parameters as he hinted at their possible removal from future versions.

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  • Using md5_file(); doesn't return the md5 sometimes?

    - by Rob
    <?php include_once('booter/login/includes/db.php'); $query="SELECT * FROM shells"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $hash = @md5_file($row['url']); echo $hash . "<br>"; } ?> The above is my code. Usually it works flawlessly on most urls, but every now and then it will just skip the md5 on a line, as if it doesn't retrieve it, even though the file is there. I can't figure out why. Any ideas?

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  • PHP Connect to 4D Database

    - by Matt Reid
    Trying to connect to 4D Database. PHPINFO says PDO is installed etc etc... Testing on localhost MAMP system. However when I run my code I get: Fatal error: Uncaught exception 'PDOException' with message 'could not find driver' in /Applications/MAMP/htdocs/4d/index.php:12 Stack trace: #0 /Applications/MAMP/htdocs/4d/index.php(12): PDO->__construct('4D:host=127.0.0...', 'test', 'test') #1 {main} thrown in /Applications/MAMP/htdocs/4d/index.php on line 12 My code is: $dsn = '4D:host=127.0.0.1;charset=UTF-8'; $user = 'test'; $pass = 'test'; // Connection to the 4D SQL server $db = new PDO($dsn, $user, $pass); try { echo "OK"; } catch (PDOException $e) { die("Error 4D : " . $e->getMessage()); } Can't put my finger on the error, i'm using the settings under the PHP tab... Thank you.

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  • php array to jquery array to qTip plugin.

    - by jp577
    Hi I'm trying to get a PHP array to use in some jquery script using the qTip plugin. This is my array: $descqtip[ ] = array('name' => ''.$name.'', 'description' => ''.$description.''); Here is my jquery code: <script type="text/javascript"> $(document).ready(function() { var description = <?php echo json_encode($descqtip)?>; $('#homepage_catgames h2').each(function(i){ $(this).qtip({ content: description }) }); }); </script> I know the above doesn't work, but i'm stuck on trying to get the description variable in each part of the array to their own individual tooltip. Can anyone help me? Thanks

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  • Compare output of program to correct program using bash script, without using text files

    - by Doug
    I've been trying to compare the output of a program to known correct output by using a bash script without piping the output of the program to a file and then using diff on the output file and a correct output file. I've tried setting the variables to the output and correct output and I believe it's been successful but I can't get the string comparison to work correctly. I may be wrong about the variable setting so it could be that. What I've been writing: TEST=`./convert testdata.txt < somesampledata.txt` CORRECT="some correct output" if [ "$TEST"!="$CORRECT" ]; then echo "failed" fi

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  • Outputting an HTML entity character from a helper function

    - by morpheous
    I am using Symfony 1.3.2 on Ubuntu. I have written a little helper function (statsfoo) that prints out summary statistics about an item. I am using the helper function in my template like this: // In StatsHelper.php <?php function statsfoo($some_param) { return "<div class=\"sfoo\">&9830; the stats number for item is 42</div>" } //In showStatsSuccess.php <?php use_helper(Stats); <?php echo statsfoo($foobar, ESC_ENTITIES); I tried both ESC_ENTITIES and ESC_RAW. In both instances, the raw number (&9830) was displayed in the page. I want to display the diamond instead. What am I doing wrong and how can I fix this?

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  • CakePHP - radio button not showing error message

    - by teepusink
    Hi, I'm unable to get the error message to show up when creating a radio form using the CakePHP form helper. This is what I have now. $options=array('active'=>'Active','inactive'=>'Inactive'); echo $form->input('Status', array( 'type' => 'radio', 'id' => 'EntryStatus', 'name' => 'data[Entry][status]', 'options' => $options )); What am I missing? I'm using CakePHP 1.2.7 and this is what I have in the validation 'status' = array( 'notempty' = array( 'rule' = 'notempty', 'required' = true, 'message' = 'yo' ) ) Tried the answer from http://stackoverflow.com/questions/1388823/form-helper-for-creating-radio-button-in-cakephp and it's giving me a select option form instead. Thanks, Tee

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  • What's the best way to format long strings of HTML in PHP?

    - by dclowd9901
    I know it's really a subjective question, but for best-practices (and readability), I can't seem to get a fix on the best way to format long strings of HTML. I typically do it like this: echo ' <div> <p>Content Inside</p> <div class="subbox"> <ul> <li>etc.</li> <li>etc.</li> <li>etc.</li> <li>etc.</li> </ul> </div> </div> '; But I still don't like the outcome, especially if this appears in the middle of a large block of code. It just feels messy.

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  • Why I am getting type error undefined from my jquery from my php json?

    - by Brained Washed
    I don't know what is wrong is am I just missing something, all my expected data is successfully receive based on firebug' console tab the problem is displaying the data. Here's my jquery code: success: function(data){ var toAppend = ''; if(typeof data === "object"){ for(var i=0;i<data.length;i++){ toAppend += '<tr><td colspan="2">'+data[i]['main-asin'][0]+'</td></tr>'; toAppend += '<tr><td>'+data[i]['sub-asin'][0]+'</td><td></td></tr>'; } $('.data-results').append(toAppend); } } Here's my php code: foreach($xml->Items->Item as $item){ $items_from_amazon[] = array('main-asin'=>$item->ASIN); foreach($xml->Items->Item->Variations->Item as $item){ $items_from_amazon[] = array('sub-asin'=>$item->ASIN); } } echo json_encode($items_from_amazon); //return amazon products And here's the result from my firebug:

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  • Bash script function return value problem

    - by Eedoh
    Hi to all. Can anyone help me return the correct value from a bash script function? Here's my function that should return first (and only) line of the file passed as an argument: LOG_FILE_CREATION_TIME() { return_value=`awk 'NR==1' $1` return return_value } And here's my call of that function in the other script: LOG_FILE_CREATION_TIME "logfile" timestamp=$? echo "Timestamp = $timestamp" I always get some random values with this code. If, for example, there's a value of 62772031 in the "logfile", I get Timestamp = 255 as an output. For some other values in the file, I get other random values as a return value, never the correct one. Any ideas?

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  • different explanation

    - by Delirium tremens
    The following code echoes 5, not 10: $global_obj = null; class my_class { var $value; function my_class() { global $global_obj; $global_obj = &$this; } } $a = new my_class; $a->my_value = 5; $global_obj->my_value = 10; echo $a->my_value; "Upon first examination, it would seem that the constructor of my_class stores a reference to itself inside the $global_obj variable. Therefore, one would expect that, when we later change the value of $global_obj-my_value to 10, the corresponding value in $a would change as well. Unfortunately, the new operator does not return a reference, but a copy of the newly created object." Please, give me a different explanation.

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  • PHP is not returning me a number type

    - by Tristan
    Hello, i tryed to follow that great tutorial (STAR rating with css : http://stackoverflow.com/questions/1987524/turn-a-number-into-star-rating-display-using-jquery-and-css) but i've just a big problem : When i do <span class="stars">1.75</span> or $foo='1.75'; echo '<span class="stars">'.$foo.'</span> the stars is correctly shown, but as soon as i do : while($val = mysql_fetch_array($result)) { $average = ($val['services'] + $val['serviceCli'] + $val['interface'] + $val['qualite'] + $val['rapport'] ) / 5 ; <span class="stars">.$average.</span> } the stars stops working i double checked the data type in mysql : they're all TINYINT(2) and i tryed that : $average = intval($average); but it's still not working, Thank you

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