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  • XML Path needed

    - by user3696029
    I have the following XML file: <?xml version="1.0" encoding="UTF-8"?> <bookstore> <book category="COOKING"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="CHILDREN"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="WEB"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="WEB"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore> I need to write a XML path that returns a book published after 2003, category is children and I just need to display the author and title of the book? What is frustrating is that I have everything in the XPATH that wrote except I am missing the author.

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  • NHibernate and MySql Keywords

    - by jalchr
    Why Nibernate HQL can not handle the following query: from Deal D where (D.ApprovalDate + INTERVAL 1 Year) < current_timestamp() < (D.RenewalDate + INTERVAL -1 Year) knowing that INTERVAL and YEAR are keywords in MySQL, so this is kind of mixing Sql within Hql (unless Hql can handle date functions like so and I don't know) . The dialect is MySQLDialect Its perfectly valid to execute this query SELECT '2005-01-01' + INTERVAL 1 Year;

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  • binary quicksort

    - by davit-datuashvili
    hi i want implement Binary quicksort algorithm from robert sedgewick book it looks like this public class quickb{ public static final int bitsword=32; public static void quicksortB(int a[],int l,int r,int d){ int i=l; int j=r-1; if (r<=l || d>bitsword) return ; while (j!=i) { while (digit(a[i],d)==0 && (i<j)) i++; while (digit(a[j],d)==1 && (j>i)) j++; int t=a[i]; a[i]=a[j]; a[j]=t; } if (digit(a[r-1],d)== 0) j++; quicksortB(a,l,j-1,d+1); quicksortB(a,j,r,d+1); } public static void main(String[]args){ int a[]=new int[]{4,7,3,9,8,2}; quicksortB(a,0,a.length-1,0); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static int digit(int m,int d){ return (m>>d)&1; } } but it show me error: java.lang.ArrayIndexOutOfBoundsException: 6 at quickb.quicksortB(quickb.java:13) at quickb.main(quickb.java:32) what is wrong?

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  • Doubt in stored procedure in asp.net

    - by Surya sasidhar
    hi, i am writing a sotreprocedure displaying month and year it is working but it is not coming in a order descending order can u help me my procedure like below... ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end result will come like this March 2010 January 2010 February 2010 but it is not in a order (desc) can u help me

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  • C++ class is not recognizing string data type

    - by reallythecrash
    I'm working on a program from my C++ textbook, and this this the first time I've really run into trouble. I just can't seem to see what is wrong here. Visual Studio is telling me Error: identifier "string" is undefined. I separated the program into three files. A header file for the class specification, a .cpp file for the class implementation and the main program file. These are the instructions from my book: Write a class named Car that has the following member variables: year. An int that holds the car's model year. make. A string that holds the make of the car. speed. An int that holds the car's current speed. In addition, the class should have the following member functions. Constructor. The constructor should accept the car's year and make as arguments and assign these values to the object's year and make member variables. The constructor should initialize the speed member variable to 0. Accessors. Appropriate accessor functions should be created to allow values to be retrieved from an object's year, make and speed member variables. There are more instructions, but they are not necessary to get this part to work. Here is my source code: // File Car.h -- Car class specification file #ifndef CAR_H #define CAR_H class Car { private: int year; string make; int speed; public: Car(int, string); int getYear(); string getMake(); int getSpeed(); }; #endif // File Car.cpp -- Car class function implementation file #include "Car.h" // Default Constructor Car::Car(int inputYear, string inputMake) { year = inputYear; make = inputMake; speed = 0; } // Accessors int Car::getYear() { return year; } string Car::getMake() { return make; } int Car::getSpeed() { return speed; } // Main program #include <iostream> #include <string> #include "Car.h" using namespace std; int main() { } I haven't written anything in the main program yet, because I can't get the class to compile. I've only linked the header file to the main program. Thanks in advance to all who take the time to investigate this problem for me.

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  • onDateSet does not get called from DatePickerDialog on tablet

    - by cit
    I am using a DatePickerDialog to prompt the user for a date. It works fine in the simulator and on my Samsung Galaxy Nexus, but onDateSet does not get called on my Samsung Galaxy Tab 2. I noticed, that the dialog is bigger and shows a calendar besides the normal spin view. Can that be the problem? Here is some code: import java.util.Calendar; import java.util.Date; import android.app.DatePickerDialog; import android.app.Dialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.support.v4.app.DialogFragment; import android.widget.DatePicker; import com.cbit.gtbetapp.R; import com.cbit.gtbetapp.gui.racedata.MeetingDataActivity; import com.cbit.gtbetapp.gui.racedata.MeetingListFragment; import com.cbit.gtbetapp.logic.Utility; public class DatePickerFragment extends DialogFragment implements DatePickerDialog.OnDateSetListener { protected Date date = null; @Override public Dialog onCreateDialog(Bundle savedInstanceState) { // Use the current date as the default date in the picker final Calendar c = Utility.getToday(); int year = c.get(Calendar.YEAR); int month = c.get(Calendar.MONTH); int day = c.get(Calendar.DAY_OF_MONTH); date = c.getTime(); // Create a new instance of DatePickerDialog and return it DatePickerDialog dialog = new DatePickerDialog(getActivity(), this, year, month, day) { @Override public void onDateChanged(DatePicker view, int year, int month, int day) { super.onDateChanged(view, year, month, day); setTitle(getString(R.string.date_picker_title)); } }; dialog.setTitle(getString(R.string.date_picker_title)); dialog.setButton(DatePickerDialog.BUTTON_POSITIVE, getString(android.R.string.ok), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); Intent intent = new Intent(getActivity(), MeetingDataActivity.class); intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); intent.putExtra(MeetingListFragment.EXTRA_DATE, date.getTime()); startActivity(intent); } }); dialog.setButton(DatePickerDialog.BUTTON_NEGATIVE, getString(R.string.button_cancel), new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); } }); return dialog; } public void onDateSet(DatePicker view, int year, int month, int day) { Calendar c = Calendar.getInstance(); c.clear(); c.set(Calendar.YEAR, year); c.set(Calendar.MONTH, month); c.set(Calendar.DAY_OF_MONTH, day); date = c.getTime(); } } What could cause this? A bug in the tablet? Am I missing something? Can anyone think of a workaround? Thanks a lot!

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  • How to convert number(16,10) to date in oracle

    - by Elad
    Hi, I'm trying to read the borland starteam application oracle database and I noticed that they represent their date as a number(16,10) column I think it is not timestamp or epoc. for instance, I have the number: 37137.4347569444, how can I read it as date? I saw that the database has a stored procedure. CONVERT_DATE: CREATE OR REPLACE procedure STARBASE.convert_date ( number_of_days IN integer , nDate OUT number) is nDateOffset number; CurrentDate date; Month integer; Day integer; year number; success boolean := false; bLeapYear boolean:=false; nDaysInMonths number; nLeapDays integer; fDate number (16,10); rgMonthDays number(5,0); begin select sysdate - number_of_days into CurrentDate from dual; nDateOffset := 693959; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 1, 2), '99') - 1 into month from dual; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 4, 2), '99') - 1 into day from dual; select to_number(substr((TO_CHAR (CurrentDate, 'MM-DD-YYYY')) , 7, 4), '9999') into year from dual; if ( mod(year , 4) = 0 ) and ( ( mod(year , 400) = 0) or ( mod(year , 100) < 0 )) then bLeapYear :=true; end if; nLeapDays := 0; if ( bLeapYear = true) and ( Day = 28) and ( Month = 1 ) then nLeapDays := 1; end if; select substr(to_char(last_day(CurrentDate) , 'DD-MM-YYYY') , 1 , 2) into nDaysInMonths from dual; if Month = 0 then rgMonthDays := 0; elsif Month = 1 then rgMonthDays := 31; elsif Month = 2 then rgMonthDays := 59; elsif Month = 3 then rgMonthDays := 90; elsif Month = 4 then rgMonthDays := 120; elsif Month = 5 then rgMonthDays := 151; elsif Month = 6 then rgMonthDays := 181; elsif Month = 7 then rgMonthDays := 212; elsif Month = 8 then rgMonthDays := 243; elsif Month = 9 then rgMonthDays := 273; elsif Month = 10 then rgMonthDays := 304; elsif Month = 11 then rgMonthDays := 334; elsif Month = 12 then rgMonthDays := 365; end if; nDate := Year*365 + Year/4 - Year/100 + Year/400 + rgMonthDays + Day + 1; if( Month < 2 ) and ( bLeapYear = true) then nDate := nDate - 1; end if; nDate := nDate - nDateOffset; exception when others then raise; end convert_date; I don't know how to use it. how can i read it anyway? Please help. thank you

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  • Constructor ambiguous quesiton

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • Ambiguous constructor call

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • Problem sub-total Matrix with rdlc report in vb.NET

    - by Keven
    Hi everyone, I have a matrix and I need to add the money earned this year and past years. However, I must remove the money spent in past years. I must have the separate amount per year and the total of these amounts. This is what gives my matrix: Year = Fields!Year.value =formatnumber((sum(Fields!Results.Value))-(sum(iif( Fields!Year.value & Parameters!choosedYear.Value, Fields!Moneyspent.value,0))), 2) & "$" However, the subtotal gives me an error. What should I do? P.S.: I already found that the subtotal gives me an error because it's not in the scope of the rowgroup1, but is there a way to get the scope in the subtotal? or can anybody find another way to do it?

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  • Display empty textbox using Html.TextBoxFor on a not-null property in an EF entity.

    - by hungster
    I am using Entity Framework (v4) entities. I have an entity called Car with a Year property of type integer. The Year property does not allow NULL. I have the following in my Create view: <%= Html.TextBoxFor(model => model.Year) %> I am required to return a new Car object (due to other requirements) in my HttpGet Create action in the CarController. Currently, a zero is displayed in the Year textbox because the Year property does not allow NULL. I would like to display an empty textbox in the Create view. How do I do this?

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  • Just quick: How do you call a mutator from within a constructor in the same class?

    - by Blockhead
    For a homework assignment the instructions state (within Undergrad class): You do NOT need to include a default constructor, but you must write a full parameterized constructor (it takes 4 arguments) -- this constructor calls the parent class parameterized constructor and the mutator for year level. Because Undergrad extends Student, then Student is my parent class, right? I just can't quite figure out how I'm to use my year level mutator (which is just the simplest of methods) to assign my "year" attribute. public void setYear(int inYear) { year = inYear; } public Student(String inName, String inID, int inCredits) { name = inName; id = inID; credits = inCredits; } public Undergrad(String inName, String inID, int inCredits,int inYear) { super(inName, inID, inCredits); year = inYear; } I keep missing assignments because I spend too much time on these small specific points of the homework so just asking for a little help. I swear it's the wording that throws me off on these assignments almost as often as just learning the material itself.

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  • Oracle Linux and Oracle VM pricing guide

    - by wcoekaer
    A few days ago someone showed me a pricing guide from a Linux vendor and I was a bit surprised at the complexity of it. Especially when you look at larger servers (4 or 8 sockets) and when adding virtual machine use into the mix. I think we have a very compelling and simple pricing model for both Oracle Linux and Oracle VM. Let me see if I can explain it in 1 page, not 10 pages. This pricing information is publicly available on the Oracle store, I am using the current public list prices. Also keep in mind that this is for customers using non-oracle x86 servers. When a customer purchases an Oracle x86 server, the annual systems support includes full use (all you can eat) of Oracle Linux, Oracle VM and Oracle Solaris (no matter how many VMs you run on that server, in case you deploy guests on a hypervisor). This support level is the equivalent of premier support in the list below. Let's start with Oracle VM (x86) : Oracle VM support subscriptions are per physical server on which you deploy the Oracle VM Server product. (1) Oracle VM Premier Limited - 1- or 2 socket server : $599 per server per year (2) Oracle VM Premier - more than 2 socket server (4, or 8 or whatever more) : $1199 per server per year The above includes the use of Oracle VM Manager and Oracle Enterprise Manager Cloud Control's Virtualization management pack (including self service cloud portal, etc..) 24x7 support, access to bugfixes, updates and new releases. It also includes all options, live migrate, dynamic resource scheduling, high availability, dynamic power management, etc If you want to play with the product, or even use the product without access to support services, the product is freely downloadable from edelivery. Next, Oracle Linux : Oracle Linux support subscriptions are per physical server. If you plan to run Oracle Linux as a guest on Oracle VM, VMWare or Hyper-v, you only have to pay for a single subscription per system, we do not charge per guest or per number of guests. In other words, you can run any number of Oracle Linux guests per physical server and count it as just a single subscription. (1) Oracle Linux Network Support - any number of sockets per server : $119 per server per year Network support does not offer support services. It provides access to the Unbreakable Linux Network and also offers full indemnification for Oracle Linux. (2) Oracle Linux Basic Limited Support - 1- or 2 socket servers : $499 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem. (3) Oracle Linux Basic Support - more than 2 socket server (4, or 8 or more) : $1199 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management. It includes ocfs2 as a clustered filesystem (4) Oracle Linux Premier Limited Support - 1- or 2 socket servers : $1399 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (5) Oracle Linux Premier Support - more than 2 socket servers : $2299 per server per year This subscription provides 24x7 support services, access to the Unbreakable Linux Network and the Oracle Support portal, indemnification, use of Oracle Clusterware for Linux HA and use of Oracle Enterprise Manager Cloud control for Linux OS management, XFS filesystem support. It also offers Oracle Lifetime support, backporting of patches for critical customers in previous versions of package and ksplice zero-downtime updates. (6) Freely available Oracle Linux - any number of sockets You can freely download Oracle Linux, install it on any number of servers and use it for any reason, without support, without right to use of these extra features like Oracle Clusterware or ksplice, without indemnification. However, you do have full access to all errata as well. Need support? then use options (1)..(5) So that's it. Count number of 2 socket boxes, more than 2 socket boxes, decide on basic or premier support level and you are done. You don't have to worry about different levels based on how many virtual instance you deploy or want to deploy. A very simple menu of choices. We offer, inclusive, Linux OS clusterware, Linux OS Management, provisioning and monitoring, cluster filesystem (ocfs), high performance filesystem (xfs), dtrace, ksplice, ofed (infiniband stack for high performance networking). No separate add-on menus. NOTE : socket/cpu can have any number of cores. So whether you have a 4,6,8,10 or 12 core CPU doesn't matter, we count the number of physical CPUs.

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  • Help with SQL query (add 5% to users with conditions)

    - by Mestika
    Hi everyone, I’m having some difficulties with a query which purpose is to give users with more than one thread (called CS) in current year a 5% point “raise”. My relational schema looks like this: Thread = (threadid, threadname, threadLocation) threadoffering = (threadid, season, year, user) user = (name, points) Then, what I need is to check: WHERE thread.threadid = threadoffering.threadid AND where threadoffering.year AND threadoffering.season = currentDate AND where threadoffering.User 1 GIVE 5 % raise TO user.points I hope it is explained thoroughly but otherwise here it is in short text: Give a 5 % “point raise” to all users who has more than 1 thread in threadLocation CS in the current year and season (always dynamic, so for example now is year = 2010 and season is = spring). I am looking forward to your answer Sincerely, Emil

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  • How do I get date form week, working also with 53-week years? c#

    - by Oskar Kjellin
    Hey, I have made a function to cound the weeks in a year, and that works fine. The problem is that I need a method to get the mondaydate of the week. This is a swedish calendar. The code below works well for years that have 52 weeks, but some years(like 2009) has 53 weeks. Then I got a date from januari as the mondaydate(cant be right). So please help me to get it to work for all years. What I probably could do is check if the year has 53 weeks and then do some checks but I'd like it to go smooth without special checks. Here's what I've come up with: public static DateTime GetDateFromWeek(int year, int week) { //First day of the year DateTime d = new DateTime(year, 1, 1); GregorianCalendar calendar = new GregorianCalendar(GregorianCalendarTypes.MiddleEastFrench); d = calendar.AddWeeks(d, week); d = d.AddDays(1 - (double)d.DayOfWeek); return d; }

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  • IndyTechFest Recap

    - by Johnm
    The sun had yet to raise above the horizon on Saturday, May 22nd and I was traveling toward the location of the 2010 IndyTechFest. In my freshly awaken, and pre-coffee, state I reflected on the months that preceded this day and how quickly they slipped away. The big day had finally come and the morning dew glistened with a unique brightness that morning. What is this all about? For those who are unfamiliar with IndyTechFest, it is a regional conference held in Indianapolis and hosted by the Indianapolis .NET Developers Association (IndyNDA) and the Indianapolis Professional Association for SQL Server (IndyPASS).  The event presents multiple tracks and sessions covering subjects such as Business Intelligence,  Database Administration, .NET Development, SharePoint Development, Windows Mobile Development as well as non-Microsoft topics such as Lean and MongoDB. This year's event was the third hosting of IndyTechFest. No man is an island No event such as IndyTechFest is executed by a single person. My fellow co-founders, with their highly complementary skill sets and philanthropy make the process very enjoyable. Our amazing volunteers and their aid were indispensible. The generous financial support of our sponsors that made the event and fabulous prizes possible. The spectacular line up of speakers who came from near and far to donate their time and knowledge. Our beloved attendees who sacrificed the first sunny Saturday in weeks to expand their skill sets and network with their peers. We are deeply appreciative. Challenges in preparation With the preparation of any event comes challenges. It is these challenges that makes the process of planning an event so interesting. This year's largest challenge was the location of the event. In the past two years IndyTechFest was held at the Gene B. Glick Junior Achievement Center in Indianapolis. This facility has been the hub of the Indy technical community for many years. As the big day drew near, the facility's availability came into question due to some recent changes that had occurred with those who operated the facility. We began our search for an alternative option. Thankfully, the Marriott Indianapolis East was available, was very spacious and willing to work within the range of our budget. Within days of our event, the decision to move proved to be wise since the prior location had begun renovations to the interior. Whew! Always trust your gut. Every day it's getting better At the ending of each year, we huddle together, review the evaluations and identify an area in which the event could improve. This year's big opportunity for improvement resided in the prize give-away portion at the end of the day. In the 2008 event, admittedly, this portion was rather chaotic, rushed and disorganized. This year, we broke the drawing into two sections, of which each attendee received two tickets. The first ticket was a drawing for the mountain of books that were given away. The second ticket was a drawing for the big prizes, the 2 Xboxes, 3 laptops and iPad. We peppered the ticket drawings with gift card raffles and tossing t-shirts into the audience. If at first you don't succeed, try and try again Each year of IndyTechFest, we have offered a means for ad-hoc sessions or discussion groups to pop-up. To our disappointment it was something that never quite took off. We have always believed that this unique type of session was valuable and wanted to figure out a way to make it work for this year. A special thanks to Alan Stevens, who took on and facilitated the "open space" track and made it an official success. Share with your tweety When the attendee badges were designed we decided to place an emphasis on the attendee's Twitter account as well as the events hash-tag (#IndyTechFest) to encourage some real-time buzz during the day. At the host table we displayed a Twitter feed for all to enjoy. It was quite successful and encouraging use of social media. My badge was missing my Twitter account since it was recently changed. For those who care to follow my rather sparse tweets, my address is @johnnydata. Man, this is one long blog post! All in all it was a very successful event. It is always great to see new faces and meet old friends. The planning for the 2011 IndyTechFest will kick off very soon. We have more capacity for future growth and a truck full of great ideas. Stay tuned!

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  • Discrete mathematics problem - Probability theory and counting

    - by Mohammad
    Hello All, I'm taking a discrete mathematics course, and I encountered a question and I need your help. I don't know if this is the right place for that though :) It says: Each user on a computer system has a password, which is six to eight characters long, where each character is an uppercase letter or a digit. Each password must contain at least one digit. How many possible passwords are there? The book solves this by adding the probabilities of having six,seven and eight characters long password. However, when he solves for probability of six characters he does this P6 = 36^6 - 26^6 and does P7 = 36^7 - 26^7 and P8 = 36^8 - 26^8 and then add them all I understand the solution, but my question is why doesn't calculating, P6 = 10*36^5 and the same for P7 and P8, work? 10 for the digit and 36 for the alphanumeric? Also, if anyone could give me another solution, other than the one in the book. Thank you very much :)

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  • How is schoolbook long division an O(n^2) algorithm?

    - by eSKay
    Premise: This Wikipedia page suggests that the computational complexity of Schoolbook long division is O(n^2). Deduction: Instead of taking "Two n-digit numbers", if I take one n-digit number and one m-digit number, then the complexity would be O(n*m). Contradiction: Suppose you divide 100000000 (n digits) by 1000 (m digits), you get 100000, which takes six steps to arrive at. Now, if you divide 100000000 (n digits) by 10000 (m digits), you get 10000 . Now this takes only five steps. Conclusion: So, it seems that the order of computation should be something like O(n/m). Question: Who is wrong, me or Wikipedia, and where?

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  • XSLT adding elements on the same path

    - by Stefan
    Consider the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> </catalog> I want to add elements to this XML using XSLT, to get the following result: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> <!-- NEW --> <middlename>???</middlename> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> <!-- NEW --> <comment>great one</comment> </cd> <!-- NEW --> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </catalog> To achieve that, I wrote the following XSLT: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="injectXml"> <xsl:param name="whatToInject"/> <xsl:copy> <xsl:copy-of select="node() | @*"/> <xsl:copy-of select="$whatToInject"/> </xsl:copy> </xsl:template> <xsl:template match="//catalog"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <comment>great one</comment> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]/artist"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <middlename>???</middlename> </xsl:with-param> </xsl:call-template> </xsl:template> </xsl:stylesheet> Why it's not working? How to do it?

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  • JavaOne 2012 Sunday Strategy Keynote

    - by Janice J. Heiss
    At the Sunday Strategy Keynote, held at the Masonic Auditorium, Hasan Rizvi, EVP, Middleware and Java Development, stated that the theme for this year's JavaOne is: “Make the future Java”-- meaning that Java continues in its role as the most popular, complete, productive, secure, and innovative development platform. But it also means, he qualified, the process by which we make the future Java -- an open, transparent, collaborative, and community-driven evolution. "Many of you have bet your businesses and your careers on Java, and we have bet our business on Java," he said.Rizvi detailed the three factors they consider critical to the success of Java--technology innovation, community participation, and Oracle's leadership/stewardship. He offered a scorecard in these three realms over the past year--with OS X and Linux ARM support on Java SE, open sourcing of JavaFX by the end of the year, the release of Java Embedded Suite 7.0 middleware platform, and multiple releases on the Java EE side. The JCP process continues, with new JSR activity, and JUGs show a 25% increase in participation since last year. Oracle, meanwhile, continues its commitment to both technology and community development/outreach--with four regional JavaOne conferences last year in various part of the world, as well as the release of Java Magazine, with over 120,000 current subscribers. Georges Saab, VP Development, Java SE, next reviewed features of Java SE 7--the first major revision to the platform under Oracle's stewardship, which has included near-monthly update releases offering hundreds of fixes, performance enhancements, and new features. Saab indicated that developers, ISVs, and hosting providers have all been rapid adopters of the platform. He also noted that Oracle's entire Fusion middleware stack is supported on SE 7. The supported platforms for SE 7 has also increased--from Windows, Linux, and Solaris, to OS X, Linux ARM, and the emerging ARM micro-server market. "In the last year, we've added as many new platforms for Java, as were added in the previous decade," said Saab.Saab also explored the upcoming JDK 8 release--including Project Lambda, Project Nashorn (a modern implementation of JavaScript running on the JVM), and others. He noted that Nashorn functionality had already been used internally in NetBeans 7.3, and announced that they were planning to contribute the implementation to OpenJDK. Nandini Ramani, VP Development, Java Client, ME and Card, discussed the latest news pertaining to JavaFX 2.0--releases on Windows, OS X, and Linux, release of the FX Scene Builder tool, the JavaFX WebView component in NetBeans 7.3, and an OpenJFX project in OpenJDK. Nandini announced, as of Sunday, the availability for download of JavaFX on Linux ARM (developer preview), as well as Scene Builder on Linux. She noted that for next year's JDK 8 release, JavaFX will offer 3D, as well as third-party component integration. Avinder Brar, Senior Software Engineer, Navis, and Dierk König, Canoo Fellow, next took the stage and demonstrated all that JavaFX offers, with a feature-rich, animation-rich, real-time cargo management application that employs Canoo's just open-sourced Dolphin technology.Saab also explored Java SE 9 and beyond--Jigsaw modularity, Penrose Project for interoperability with OSGi, improved multi-tenancy for Java in the cloud, and Project Sumatra. Phil Rogers, HSA Foundation President and AMD Corporate Fellow, explored heterogeneous computing platforms that combine the CPU and the parallel processor of the GPU into a single piece of silicon and shared memory—a hardware technology driven by such advanced functionalities as HD video, face recognition, and cloud workloads. Project Sumatra is an OpenJDK project targeted at bringing Java to such heterogeneous platforms--with hardware and software experts working together to modify the JVM for these advanced applications and platforms.Ramani next discussed the latest with Java in the embedded space--"the Internet of things" and M2M--declaring this to be "the next IT revolution," with Java as the ideal technology for the ecosystem. Last week, Oracle released Java ME Embedded 3.2 (for micro-contollers and low-power devices), and Java Embedded Suite 7.0 (a middleware stack based on Java SE 7). Axel Hansmann, VP Strategy and Marketing, Cinterion, explored his company's use of Java in M2M, and their new release of EHS5, the world's smallest 3G-capable M2M module, running Java ME Embedded. Hansmaan explained that Java offers them the ability to create a "simple to use, scalable, coherent, end-to-end layer" for such diverse edge devices.Marc Brule, Chief Financial Office, Royal Canadian Mint, also explored the fascinating use-case of JavaCard in his country's MintChip e-cash technology--deployable on smartphones, USB device, computer, tablet, or cloud. In parting, Ramani encouraged developers to download the latest releases of Java Embedded, and try them out.Cameron Purdy, VP, Fusion Middleware Development and Java EE, summarized the latest developments and announcements in the Enterprise space--greater developer productivity in Java EE6 (with more on the way in EE 7), portability between platforms, vendors, and even cloud-to-cloud portability. The earliest version of the Java EE 7 SDK is now available for download--in GlassFish 4--with WebSocket support, better JSON support, and more. The final release is scheduled for April of 2013. Nicole Otto, Senior Director, Consumer Digital Technology, Nike, explored her company's Java technology driven enterprise ecosystem for all things sports, including the NikeFuel accelerometer wrist band. Looking beyond Java EE 7, Purdy mentioned NoSQL database functionality for EE 8, the concurrency utilities (possibly in EE 7), some of the Avatar projects in EE 7, some in EE 8, multi-tenancy for the cloud, supporting SaaS applications, and more.Rizvi ended by introducing Dr. Robert Ballard, oceanographer and National Geographic Explorer in Residence--part of Oracle's philanthropic relationship with the National Geographic Society to fund K-12 education around ocean science and conservation. Ballard is best known for having discovered the wreckage of the Titanic. He offered a fascinating video and overview of the cutting edge technology used in such deep-sea explorations, noting that in his early days, high-bandwidth exploration meant that you’d go down in a submarine and "stick your face up against the window." Now, it's a remotely operated, technology telepresence--"I think of my Hercules vehicle as my equivalent of a Na'vi. When I go beneath the sea, I actually send my spirit." Using high bandwidth satellite links, such amazing explorations can now occur via smartphone, laptop, or whatever platform. Ballard’s team regularly offers live feeds and programming out to schools and the world, spanning 188 countries--with embedding educators as part of the expeditions. It's technology at its finest, inspiring the next-generation of scientists and explorers!

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  • SQL: ATER COLUMN to shorter CHAR(n) type

    - by Rising Star
    I'm working with MS SQL SERVER 2003. I want to change a column in one of my tables to have fewer characters in the entries. This is identical to this question: http://stackoverflow.com/questions/2281336/altering-a-table-column-to-accept-more-characters except for the fact that I want fewer characters instead of more. I have a column in one of my tables that holds nine-digit entries. A developer previously working on the table mistakenly set the column to hold ten-digit entries. I need to change the type from CHAR(10) to CHAR(9). Following the instructions from the discussion linked above, I wrote the statement ALTER TABLE [MY_TABLE] ALTER COLUMN [MY_COLUMN] CHAR(9); This returns the error message "String or binary data would be truncated". I see that my nine-digit strings have a space appended to make them ten digits. How do I tell SQL Server to discard the extra space and convert my column to a CHAR(9) type?

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  • recursive program

    - by wilson88
    I am trying to make a recursive program that calculates interest per year.It prompts the user for the startup amount (1000), the interest rate (10%)and number of years(1).(in brackets are samples) Manually I realised that the interest comes from the formula YT(1 + R)----- interest for the first year which is 1100. 2nd year YT(1 + R/2 + R2/2) //R squared 2nd year YT(1 + R/3 + R2/3 + 3R3/) // R cubed How do I write a recursive program that will calculate the interest? Below is the function which I tried double calculateInterest(double startUp, double rate, double duration) { double cpdInterest = (duration*startUp)*(1 + rate); if (duration == 0) { return cpdInterest; } else if (duration < 0) { cout << "Please enter a valid year"; } else { calculateInterest(cpdInterest,rate,duration); } return cpdInterest; }

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  • When does a query/subquery return a NULL and when no value at all?

    - by AspOnMyNet
    a) If a query/subquery doesn’t find any matching rows, then it either returns NULL or no value at all, thus not even a NULL value. Based on what criteria does a query/subquery return a NULL and when doesn’t it return any results, not even a NULL value? b) I assume a scalar subquery will always return NULL, when no matching rows are found? I assume most-outer scalar query also returns NULL if no rows are found? c) SELECT FirstName, LastName, YEAR(BirthDate) FROM Persons WHERE YEAR(BirthDate) IN (SELECT YearReleased FROM Albums); If subquery finds no results, is then a WHERE clause of an outer query translated into WHERE YEAR(BirthDate) IN (null); ? If instead WHERE clause is translated into WHERE YEAR(BirthDate) IN(); then shouldn’t that be an error condition, since how can YEAR(BirthDate) value be compared to nothing? thanx

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  • Why my print current date time (C language) gives different answer

    - by vodkhang
    I want to get the current date (day, mon and year). I found out there are some functions in C to do that like ctime (get the string of time), localtime and gmtime. I tried with following code but the output are different. I get this output: The date and time is Tue Apr 20 2010 (which is correct) The year is : 110 The year is : 110. Does anybody know why? int main(int argc, char** argv) { time_t now; if((now = time(NULL)) == (time_t)-1) { puts("Failure in getting time"); } else { printf("The date and time is: %s\n", ctime(&now)); printf("The year is: %ld\n", localtime(&now)->tm_year); printf("The year is: %ld\n", gmtime(&now)->tm_year); } getchar(); }

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  • how to take Value From java Scrpit File and send it to php File?:(

    - by Nina
    Hi ! Can U tell me how to take Value From java Scrpit File and send it to php File . code : var year = (year != null) ? year : '".$this->arrToday["year"]."'; var month = (month != null) ? month : '".$this->ConvertToDecimal($this>arrToday["mon"])."'; var day = (day != null) ? day : '".$this->arrToday["mday"]."'; my_window= window.open ('Event.php','mywindow1','status=1,width=350,height=150'); \\ and I wont to send these varible (year,Month,day) to Event.php . can U tell me How ?

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