Search Results

Search found 19563 results on 783 pages for 'binary search'.

Page 25/783 | < Previous Page | 21 22 23 24 25 26 27 28 29 30 31 32  | Next Page >

  • Reverse reading WORD from a binary file?

    - by Angel
    Hi, I have a structure: struct JFIF_HEADER { WORD marker[2]; // = 0xFFD8FFE0 WORD length; // = 0x0010 BYTE signature[5]; // = "JFIF\0" BYTE versionhi; // = 1 BYTE versionlo; // = 1 BYTE xyunits; // = 0 WORD xdensity; // = 1 WORD ydensity; // = 1 BYTE thumbnwidth; // = 0 BYTE thumbnheight; // = 0 }; This is how I read it from the file: HANDLE file = CreateFile(filename, GENERIC_READ, FILE_SHARE_READ, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, 0); DWORD tmp = 0; DWORD size = GetFileSize(file, &tmp); BYTE *DATA = new BYTE[size]; ReadFile(file, DATA, size, &tmp, 0); JFIF_HEADER header; memcpy(&header, DATA, sizeof(JFIF_HEADER)); This is how the beginning of my file looks in hex editor: 0xFF 0xD8 0xFF 0xE0 0x00 0x10 0x4A 0x46 0x49 0x46 0x00 0x01 0x01 0x00 0x00 0x01 When I print header.marker, it shows exactly what it should (0xFFD8FFE0). But when I print header.length, it shows 0x1000 instead of 0x0010. The same thing is with xdensity and ydensity. Why do I get wrong data when reading a WORD? Thank you.

    Read the article

  • Return parent of node in Binary Tree

    - by user188995
    I'm writing a code to return the parent of any node, but I'm getting stuck. I don't want to use any predefined ADTs. //Assume that nodes are represented by numbers from 1...n where 1=root and even //nos.=left child and odd nos=right child. public int parent(Node node){ if (node % 2 == 0){ if (root.left==node) return root; else return parent(root.left); } //same case for right } But this program is not working and giving wrong results. My basic algorithm is that the program starts from the root checks if it is on left or on the right. If it's the child or if the node that was queried else, recurses it with the child.

    Read the article

  • Is there a search engine that indexes source code of a web-page?

    - by Dexter
    I need to search the web for sites that are in our industry that use the same Adwords management company, to ensure that the said company is not violating our contract, as they have been accused of doing. They use a tracking code in the template of every page which has a certain domain in the URL, and I'm wondering if it's possible "Google" the source code using some bot that crawls the code rather than the content? For example, I bought an unlimited license for an image gallery, and I was asked to type the license number in a comment just before the script. I thought it was just so a human could look at the source and find out if someone paid, but it turned out that it was actually that they had a crawler looking for their source code and that comment. If it ran across the code on your site, it would look for the comment, and if it found one, it would check to see if it was an existing one. If not, it would first notify you of your noncompliance, and then notify the owner of the script. Edit: I'm looking to index HTML and JavaScript only, not the server-side languages or Java.

    Read the article

  • .NET binary serialization conditionally without ISerializable

    - by SillyWhy
    I got 2 classes, for example: public class A { private B b; ... } public class B { ... } I need to serialize an object A using BinaryFormatter. When remoting it shall include the field b, but not when serialize to file. Here is what I added: [Serializable] public class A : MarshalByRefObject { private B b; [OnSerializing] private void OnSerializing(StreamingContext context) { if (context.State == StreamingContextStates.File) { this.b = null; } } ... } [Serializable] public class B : MarshalByRefObject { ... } I think this is a bad design because if another class C also contains B, in class C we must add the duplicate OnSerializing() logic as in A. Class B should decide what to do, not class A or C. I don't want to use ISerializable interface because there are too many variables in class B have to be added to SerializationInfo. I can create a SerializationSurrogate for class B, which perform nothing in GetObjectData() & SetObjectData(), then use it when serializing to file. However the same maintenance issue because whoever modify class B can't notice what going to happen during serialization & the existence of SerializationSurrogate. Is there a better alternative?

    Read the article

  • Write to a binary file?

    - by rick irby
    Here is data structure w/ variables: struct Part_record { char id_no[3]; int qoh; string desc; double price: }; --- (Using "cin" to input data) --- Part_record null_part = {" ", 0," ",0.0}; --- --- file.seekg( -(long)sizeof(Part_record), ios::cur); file.write( ( char *)&part, sizeof(Part_record) ); The three variables, qoh, Id_no & price, write out correctly, but the "desc" variable is not right. Do I need to initialize Part_record some other way? It should be 20 characters in length. If you have enough info here, pls share your advice,thanks.

    Read the article

  • Error inserting data in binary tree

    - by chepe263
    I copied this code (in spanish) http://www.elrincondelc.com/nuevorincon/index.php?pag=codigos&id=4 and wrote a new one. This is my code: #include <cstdlib> #include <conio.h> #include <iostream> using namespace std; struct nodoarbol { int dato; struct nodoarbol *izq; struct nodoarbol *der; }; typedef nodoarbol Nodo; typedef Nodo *Arbol; void insertar(Arbol *, int); void inorden(Arbol); void postorden(Arbol); void preorden(Arbol); void insertar(Arbol *raiz, int nuevo){ if (*raiz==NULL){ *raiz = (Nodo *)malloc(sizeof(Nodo)); if (*raiz != NULL){ (*raiz)->dato=nuevo; (*raiz)->der=NULL; (*raiz)->izq=NULL; } else{ cout<<"No hay memoria suficiente u ocurrio un error"; } } else{ if (nuevo < (*raiz)->dato) insertar( &((*raiz)->izq), nuevo ); else if (nuevo > (*raiz)->dato) insertar(&((*raiz)->der), nuevo); } }//inseertar void inorden(Arbol raiz){ if (raiz != NULL){ inorden(raiz->izq); cout << raiz->dato << " "; inorden(raiz->der); } } void preorden(Arbol raiz){ if (raiz != NULL){ cout<< raiz->dato << " "; preorden(raiz->izq); preorden(raiz->der); } } void postorden(Arbol raiz){ if (raiz!=NULL){ postorden(raiz->izq); postorden(raiz->der); cout<<raiz->dato<<" "; } } int main() { int i; i=0; int val; Arbol raiz = NULL; for (i=0; i<10; i++){ cout<<"Inserte un numero"; cin>>val; insertar( (raiz), val); } cout<<"\nPreorden\n"; preorden(raiz); cout<<"\nIneorden\n"; inorden(raiz); cout<<"\nPostorden\n"; postorden(raiz); return 0; } I'm using netbeans 7.1.1, mingw32 compiler This is the output: make[2]: Leaving directory `/q/netbeans c++/NetBeansProjects/treek' make[1]: Leaving directory `/q/netbeans c++/NetBeansProjects/treek' main.cpp: In function 'int main()': main.cpp:110:30: error: cannot convert 'Arbol {aka nodoarbol*}' to 'Nodo** {aka nodoarbol**}' for argument '1' to 'void insertar(Nodo**, int)' make[2]: *** [build/Release/MinGW-Windows/main.o] Error 1 make[1]: *** [.build-conf] Error 2 make: *** [.build-impl] Error 2 BUILD FAILED (exit value 2, total time: 11s) I don't understand what's wrong since i just copied the code (and rewrite it to my own code). I'm really good in php, asp.net (vb) and other languages but c is a headche for me. I've been struggling with this problem for about an hour. Could somebody tell me what could it be?

    Read the article

  • Binary Search Tree can't delete the root

    - by Ali Zahr
    Everything is working fine in this function, but the problem is that I can't delete the root, I couldn't figure out what's the bug here.I've traced the "else part" it works fine until the return, it returns the old value I don't know why. Plz Help! node *removeNode(node *Root, int key) { node *tmp = new node; if(key > Root->value) Root->right = removeNode(Root->right,key); else if(key < Root->value) Root->left = removeNode(Root->left, key); else if(Root->left != NULL && Root->right != NULL) { node *minNode = findNode(Root->right); Root->value = minNode->value; Root->right = removeNode(Root->right,Root->value); } else { tmp = Root; if(Root->left == NULL) Root = Root->right; else if(Root->right == NULL) Root = Root->left; delete tmp; } return Root; }

    Read the article

  • efficient video format/codec for sparse & binary blob tracking

    - by user391339
    I am working on a blob tracking project and have many high-definition videos that I would like to reduce in size for storage and downstream tracking/shape-analysis. I want to use a lossless method that takes advantage of the black and white nature of the video as well as the fact that not much is moving between individual frames. The videos are quite sparse, with 5 to 10 b&w blobs per frame occupying <30% of the space in total, with each blob moving <5-10% of the field of view between frames and not changing shape too much between 2-3 frames. I will work in Python, Matlab, or LabView for this project, and could use a batch utility if available. It may be worthwhile to export the files as compressed image stacks if a proper video format can't be found. What are the pros and cons of this? A video codec uses correlations between neighboring frames, so it should be more efficient, but not if the wrong one is chosen or if it is improperly configured.

    Read the article

  • How many posibilities on a binary ?

    - by Val
    in hexadecimal "10 10 10 10" system you have 0-255 posibilities right? in total 256 different posibilities as there are 8 1s and 0s. how many different posibilities would i get? if i had 10 digits. instead of 8? or how would i calculate that in php ?

    Read the article

  • Better way to download a binary file?

    - by geoff
    I have a site where a user can download a file. Some files are extremely large (the largest being 323 MB). When I test it to try and download this file I get an out of memory exception. The only way I know to download the file is below. The reason I'm using the code below is because the URL is encoded and I can't let the user link directly to the file. Is there another way to download this file without having to read the whole thing into a byte array? FileStream fs = new FileStream(context.Server.MapPath(url), FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); long numBytes = new FileInfo(context.Server.MapPath(url)).Length; byte[] bytes = br.ReadBytes((int) numBytes); string filename = Path.GetFileName(url); context.Response.Buffer = true; context.Response.Charset = ""; context.Response.Cache.SetCacheability(HttpCacheability.NoCache); context.Response.ContentType = "application/x-rar-compressed"; context.Response.AddHeader("content-disposition", "attachment;filename=" + filename); context.Response.BinaryWrite(bytes); context.Response.Flush(); context.Response.End();

    Read the article

  • Problems in Binary Search Tree

    - by user2782324
    This is my first ever trial at implementing the BST, and I am unable to get it done. Please help The problem is that When I delete the node if the node is in the right subtree from the root or if its a right child in the left subtree, then it works fine. But if the node is in the left subtree from root and its any left child, then it does not get deleted. Can someone show me what mistake am I doing?? the markedNode here gets allocated to the parent node of the node to be deleted. the minValueNode here gets allocated to a node whose left value child is the smallest value and it will be used to replace the value to be deleted. package DataStructures; class Node { int value; Node rightNode; Node leftNode; } class BST { Node rootOfTree = null; public void insertintoBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { Node newNode = new Node(); newNode.value = value; rootOfTree = newNode; newNode.rightNode = null; newNode.leftNode = null; } else { while (true) { if (value >= markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.rightNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.leftNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } } } } public void searchBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { System.out.println("Element Not Found"); } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { System.out.println("Element Not Found"); break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { System.out.println("Element Not Found"); break; } } if (value == markedNode.value) { System.out.println("Element Found"); break; } } } } public void deleteFromBST(int value) { Node markedNode = rootOfTree; Node minValueNode = null; if (rootOfTree == null) { System.out.println("Element Not Found"); return; } if (rootOfTree.value == value) { if (rootOfTree.leftNode == null && rootOfTree.rightNode == null) { rootOfTree = null; return; } else if (rootOfTree.leftNode == null ^ rootOfTree.rightNode == null) { if (rootOfTree.rightNode != null) { rootOfTree = rootOfTree.rightNode; return; } else { rootOfTree = rootOfTree.leftNode; return; } } else { minValueNode = rootOfTree.rightNode; if (minValueNode.leftNode == null) { rootOfTree.rightNode.leftNode = rootOfTree.leftNode; rootOfTree = rootOfTree.rightNode; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node rootOfTree.value = minValueNode.leftNode.value; // The value has been swapped if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { break; } else { markedNode = markedNode.rightNode; } } else { System.out.println("Element Not Found"); return; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { break; } else { markedNode = markedNode.leftNode; } } else { System.out.println("Element Not Found"); return; } } } // Parent of the required element found // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { if (markedNode.rightNode.rightNode == null && markedNode.rightNode.leftNode == null) { markedNode.rightNode = null; return; } else if (markedNode.rightNode.rightNode == null ^ markedNode.rightNode.leftNode == null) { if (markedNode.rightNode.rightNode != null) { markedNode.rightNode = markedNode.rightNode.rightNode; return; } else { markedNode.rightNode = markedNode.rightNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.rightNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { if (markedNode.leftNode.rightNode == null && markedNode.leftNode.leftNode == null) { markedNode.leftNode = null; return; } else if (markedNode.leftNode.rightNode == null ^ markedNode.leftNode.leftNode == null) { if (markedNode.leftNode.rightNode != null) { markedNode.leftNode = markedNode.leftNode.rightNode; return; } else { markedNode.leftNode = markedNode.leftNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.leftNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// } } } } } } public class BSTImplementation { public static void main(String[] args) { BST newBst = new BST(); newBst.insertintoBST(19); newBst.insertintoBST(13); newBst.insertintoBST(10); newBst.insertintoBST(20); newBst.insertintoBST(5); newBst.insertintoBST(23); newBst.insertintoBST(28); newBst.insertintoBST(16); newBst.insertintoBST(27); newBst.insertintoBST(9); newBst.insertintoBST(4); newBst.insertintoBST(22); newBst.insertintoBST(17); newBst.insertintoBST(30); newBst.insertintoBST(40); newBst.deleteFromBST(5); newBst.deleteFromBST(4); newBst.deleteFromBST(9); newBst.deleteFromBST(10); newBst.deleteFromBST(13); newBst.deleteFromBST(16); newBst.deleteFromBST(17); newBst.searchBST(5); newBst.searchBST(4); newBst.searchBST(9); newBst.searchBST(10); newBst.searchBST(13); newBst.searchBST(16); newBst.searchBST(17); System.out.println(); newBst.deleteFromBST(20); newBst.deleteFromBST(23); newBst.deleteFromBST(27); newBst.deleteFromBST(28); newBst.deleteFromBST(30); newBst.deleteFromBST(40); newBst.searchBST(20); newBst.searchBST(23); newBst.searchBST(27); newBst.searchBST(28); newBst.searchBST(30); newBst.searchBST(40); } }

    Read the article

  • Dlink search is hijacking my browser

    - by James
    For months now "DLink search" has been hijacking my search engines. I use google chrome, and I have organized my search engines in the handy dandy "manage search engines" tool about a TRILLION times. It never even says D-link is hacking my search engines. It does not show up! I have read many posts on this forum and others saying that to fix this problem from internet explorer: Setup, internet options, yadayada, magical fairies, and you are solved, but my browser is google chrome! How am I supposed to do this from there! I do not know how to re-setup my Dlink router, which is the cause of the problem! HOW? In those posts with the magical fairies fixing it, HUNDREDS responded saying, "yep, those fairies definitely fixed it right. :)" These people were so satisfied. IT WORKED FOR THEM, WHY NOT ME. I look at it and go ":(" because it does not help me. There are no options for anything to do with this in GOOGLE chrome. PLEASE EXPLAIN and HELP. I see no "SETUP" option, no "Internet Options" button, no anything. BTW the exact posts are these: "Uncheck Advanced DNS in the router internet setup. This will take care of it. I had this problem with my DLink router before." "I had this issue with my DIR-655 and unchecking the Advanced DNS setting in Setup - Internet - Manual Internet Connection Setup fixed it." "If this is just internet explorer, you can go to Tools Internet Options or Internet Options in Control Panel. From here, go to the advanced tab and click the Reset button." "I would set the router's DNS to a site like OpenDNS, and I would ensure the machines are set to get their DNS settings via DHCP or set the machine's DNS setting to OpenDNS. If the router's DNS looks like it was messed with, some bad software know the default passwords for routers and could have changed it. If you don't already I would make sure the password to the router is not default or easy to guess. I've had spyware change a machine's DNS, but the fact it is happening on all machines makes me wonder if it is the router." "Something got into your router and changed the dns server most likely, do a hard reset of the router and then change the password to something strong. Also check for a firmware update for the router and apply it as soon as possible."

    Read the article

  • Rails, search item in different model?

    - by Danny McClelland
    Hi Everyone, I have a kase model which I am using a simple search form in. The problem I am having is some kases are linked to companies through a company model, and people through a people model. At the moment my search (in Kase model) looks like this: # SEARCH FACILITY def self.search(search) search_condition = "%" + search + "%" find(:all, :conditions => ['jobno LIKE ? OR casesubject LIKE ? OR transport LIKE ? OR goods LIKE ? OR comments LIKE ? OR invoicenumber LIKE ? OR netamount LIKE ? OR clientref LIKE ? OR kase_status LIKE ? OR lyingatlocationaddresscity LIKE ?', search_condition, search_condition, search_condition, search_condition, search_condition, search_condition, search_condition, search_condition, search_condition, search_condition]) end What I am trying to work out, is what condition can I add to allow a search by Company or Person to show the cases they are linked to. @kase.company.companyname and company.companyname don't work :( Is this possible? Thanks, Danny

    Read the article

  • Advanced search functionality

    - by Chris
    I have a website with a jQuery based autocomplete search functionality which works great. Currently though I have just one search box for all categories, what I want is for someone to be able to type in, say for example, dorian gray dvd (in any order) which will search for dorian gray within the dvd category. What this will require then is a bit of magic on the server side to figure out if any of the words are category keywords, and then limit the search by that. What is the best (and quickest) way to do this in PHP / MySQL? I currently have a few trains of thought Search the category table for matches and perhaps order the results by that. Or split up the search terms into an array and separately search the categories for that for a match. Another thought I just had is to concat the category title to the dvd title in the database and match against that, or something similar... but this sounds computationally expensive? Any advice?

    Read the article

  • SharePoint Search: processing filenames containing underscores

    - by Todd Owen
    We use SharePoint Server 2007 to allow employees to search network file shares, but it seems that underscores in filenames are not treated as word separators when indexing the files. As a result, a search for chocolate will: match "chocolate milkshake.doc" but not match "chocolate_cake.doc" (Of course, this is a simplified example; in practice the content of the second file might include the word "chocolate" and match on that instead of the filename. But the problem itself is real enough, because a common scenario in a corporate environment is that a user knows the the partial name of the file they are looking for and expects to see matching filenames at the top of the search results. And using underscores in filenames is a widely used convention within our company). Underscores are not treated as word separators in the file content either, although this is less of a concern for us. The root cause of this problem is possibly related to the behaviour of the word breakers that SharePoint uses (i.e. the language-specific DLLs that implement the IWorkBreaker interface), although I haven't confirmed this yet. Does anyone know of a workaround for this issue? I have tested with Search Server 2008 Express too (which is based on the same technology), and it is also affected. I do not know whether the problem is fixed in SharePoint 2010 or not.

    Read the article

  • "OR" clause in Outlook 2007 Search Folders - Folder Composition

    - by Thomas L Holaday
    Is it possible to specify a Search Folder in Outlook 2007 that will use an OR rule ("any") instead of an AND rule ("and")? In particular, I have a search folder named A and another named B; I want a search folder named AB that will have all the messages that are in either A or B, or both. When I specify AB with the rules "In Folder is A exactly" and "In Folder is B exactly", I get an empty folder, possibly because at the moment no messages are in both. Is the workaround to rename "A" to "A workaround" and "B" to "B workaround" and then specify "AB" with the rule "In Folder contains workaround"? Urggh.

    Read the article

  • Tool for Search in Outlook

    - by LeeRob
    Hey guys, I am in search of a tool, with which I can organize my e-mail inbox!! It should search of course for e-mails, but it would be nice if I can also search for and in attachments, appointments, adresses etc. Beside this it also should be small and of course fast! ;) I heard and read of several tool (xobni, copernic, WDS, Lookeen), but now wanted to know your opinions which would be the best...I am interested in all, no matter if freeware or not! Thank you!

    Read the article

  • Combine the Address & Search Bars in Firefox

    - by Asian Angel
    The Search Bar in Firefox is very useful for finding additional information or images while browsing but the UI space it takes up can be frustrating at times. Now you can reclaim that UI space and still have access to all that searching goodness with the Foobar extension. Note: This is about the Foobar Firefox extension and not to be confused with Foobar2000 the open source music player. Before If you have the “Search Bar” displayed there is no doubt that it is taking up valuable space in your browser’s UI. What you need is the ability to reclaim that UI space and still have the same access to your search capability as before…no more sacrificing one for a gain with the other. After As soon as you have installed the extension you can see that the top part of your browser will look much sleeker without the “Search Bar” to clutter it up. The “Search Engine Icon” will now be visible inside of your “Address Bar” as seen here. You will be able to access the same “Search Engine Menu” as before by clicking on the “Search Engine Icon”. There are two display modes for search results (setting available in the “Options”). The first one shown here is “Simple Mode” where all results are in a condensed format. Notice that not only are there search suggestions but also “Bookmarks & History” listings as well. You can literally get the best of both when conducting a search. Note: The number of entries for search suggestions and bookmark/history listings can be adjusted higher or lower in the “Options”. The second one is “Rich Mode” where the results are shown with more details. Choose the “mode” that best suits your personal style. For our first example you can see the results when we conducted a quick search on “Windows 7” (using the first of the three offerings shown from Bing). Our second example was a search for “Flowers” using our Photobucket search engine. Once again nice results opened in a new tab for us. Options The options are easy to go through. It is really nice to be able to choose the number of results that you want displayed and the format that you want them shown in. Note: Changing the “Suggestion popup style” will require a browser restart to take effect. Conclusion If you love using the “Search Bar” in Firefox but want to reclaim the UI space then you will definitely want to add this extension to your browser. The ability to customize the number of results and choose the formatting make this extension even better. Links Download the Foobar extension (Mozilla Add-ons) Similar Articles Productive Geek Tips Combine the Address Bar and Progress Bar Together in FirefoxHide Some or All of the GUI Bars in FirefoxEnable Partial Match AutoComplete in the Firefox Address BarQuick Firefox UI TweaksAdd Search Forms to the Firefox Search Bar TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Scan your PC for nasties with Panda ActiveScan CleanMem – Memory Cleaner AceStock – The Personal Stock Monitor Add Multiple Tabs to Office Programs The Wearing of the Green – St. Patrick’s Day Theme (Firefox) Perform a Background Check on Yourself

    Read the article

  • Security issue when returning local filesystem results in a custom Windows Federated Search Provider

    - by user561922
    hi- i'm following the instructions on how to build a custom search provider for windows federated search: http://msdn.microsoft.com/en-us/library/dd742956(v=VS.85) i'm returning local results of the form: File://C:\Users\user\file.txt however, when i perform a search, i get results that say: "This item was blocked because of your Internet security settings". how can i change my security settings so that federated search will allow my customer search provider to return local filesystem results? thanks.

    Read the article

  • Implementing long running search in ASP.NET

    - by Gursharn Singh
    I am building a search page in asp.net 3.5. Search takes a bit of time (few seconds to few minutes). Current I use AsyncMethodCaller to call Search method. AsyncMethodCaller method stores search results in Session. I user Ajax timer to check if Search method finished and then display results. What would be the best way to implement this scenario?

    Read the article

< Previous Page | 21 22 23 24 25 26 27 28 29 30 31 32  | Next Page >