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• Java - binary compatibility of abstract class & subclasses

  - by thSoft

  In Java, I define an abstract class with both concrete and abstract methods in it, and it has to be subclassed independently by third-party developers. Just to be sure: are there any changes I could make to the abstract class that are source compatible with their classes but not binary compatible? In other words: after they have compiled their subclasses, could I change the abstract class - apart from e.g. adding an abstract method to it or removing a protected method from it that is called by subclasses, which are of course source incompatible - in a way that could force them to recompile their subclasses?

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• Binary Search Tree node removal

  - by doc

  I've been trying to implement a delete function for a Binary Search Tree but haven't been able to get it to work in all cases. This is my latest attempt: if(t->get_left() == empty) *t = *t->get_left(); else if(t->get_right() == empty) *t = *t->get_right(); else if((t->get_left() != empty) && (t->get_right() != empty)) { Node* node = new Node(t->get_data(), t->get_parent(), t->get_colour(), t->get_left(), t->get_right()); *t = *node; } t is a node and empty is just a node with nothing in it. I'm just trying to swap the values but I'm getting a runtime error. Any ideas? Thanks

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• Finding the heaviest length-constrained path in a weighted Binary Tree

  - by Hristo

  UPDATE I worked out an algorithm that I think runs in O(n*k) running time. Below is the pseudo-code: routine heaviestKPath( T, k ) // create 2D matrix with n rows and k columns with each element = -8 // we make it size k+1 because the 0th column must be all 0s for a later // function to work properly and simplicity in our algorithm matrix = new array[ T.getVertexCount() ][ k + 1 ] (-8); // set all elements in the first column of this matrix = 0 matrix[ n ][ 0 ] = 0; // fill our matrix by traversing the tree traverseToFillMatrix( T.root, k ); // consider a path that would arc over a node globalMaxWeight = -8; findArcs( T.root, k ); return globalMaxWeight end routine // node = the current node; k = the path length; node.lc = node’s left child; // node.rc = node’s right child; node.idx = node’s index (row) in the matrix; // node.lc.wt/node.rc.wt = weight of the edge to left/right child; routine traverseToFillMatrix( node, k ) if (node == null) return; traverseToFillMatrix(node.lc, k ); // recurse left traverseToFillMatrix(node.rc, k ); // recurse right // in the case that a left/right child doesn’t exist, or both, // let’s assume the code is smart enough to handle these cases matrix[ node.idx ][ 1 ] = max( node.lc.wt, node.rc.wt ); for i = 2 to k { // max returns the heavier of the 2 paths matrix[node.idx][i] = max( matrix[node.lc.idx][i-1] + node.lc.wt, matrix[node.rc.idx][i-1] + node.rc.wt); } end routine // node = the current node, k = the path length routine findArcs( node, k ) if (node == null) return; nodeMax = matrix[node.idx][k]; longPath = path[node.idx][k]; i = 1; j = k-1; while ( i+j == k AND i < k ) { left = node.lc.wt + matrix[node.lc.idx][i-1]; right = node.rc.wt + matrix[node.rc.idx][j-1]; if ( left + right > nodeMax ) { nodeMax = left + right; } i++; j--; } // if this node’s max weight is larger than the global max weight, update if ( globalMaxWeight < nodeMax ) { globalMaxWeight = nodeMax; } findArcs( node.lc, k ); // recurse left findArcs( node.rc, k ); // recurse right end routine Let me know what you think. Feedback is welcome. I think have come up with two naive algorithms that find the heaviest length-constrained path in a weighted Binary Tree. Firstly, the description of the algorithm is as follows: given an n-vertex Binary Tree with weighted edges and some value k, find the heaviest path of length k. For both algorithms, I'll need a reference to all vertices so I'll just do a simple traversal of the Tree to have a reference to all vertices, with each vertex having a reference to its left, right, and parent nodes in the tree. Algorithm 1 For this algorithm, I'm basically planning on running DFS from each node in the Tree, with consideration to the fixed path length. In addition, since the path I'm looking for has the potential of going from left subtree to root to right subtree, I will have to consider 3 choices at each node. But this will result in a O(n*3^k) algorithm and I don't like that. Algorithm 2 I'm essentially thinking about using a modified version of Dijkstra's Algorithm in order to consider a fixed path length. Since I'm looking for heaviest and Dijkstra's Algorithm finds the lightest, I'm planning on negating all edge weights before starting the traversal. Actually... this doesn't make sense since I'd have to run Dijkstra's on each node and that doesn't seem very efficient much better than the above algorithm. So I guess my main questions are several. Firstly, do the algorithms I've described above solve the problem at hand? I'm not totally certain the Dijkstra's version will work as Dijkstra's is meant for positive edge values. Now, I am sure there exist more clever/efficient algorithms for this... what is a better algorithm? I've read about "Using spine decompositions to efficiently solve the length-constrained heaviest path problem for trees" but that is really complicated and I don't understand it at all. Are there other algorithms that tackle this problem, maybe not as efficiently as spine decomposition but easier to understand? Thanks.

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• Finding height in Binary Search Tree

  - by mike

  Hey I was wondering if anybody could help me rework this method to find the height of a binary search tree. So far my code looks like this however the answer im getting is larger than the actual height by 1, but when I remove the +1 from my return statements its less than the actual height by 1? I'm still trying to wrap my head around recursion with these BST any help would be much appreciated. public int findHeight(){ if(this.isEmpty()){ return 0; } else{ TreeNode<T> node = root; return findHeight(node); } } private int findHeight(TreeNode<T> aNode){ int heightLeft = 0; int heightRight = 0; if(aNode.left!=null) heightLeft = findHeight(aNode.left); if(aNode.right!=null) heightRight = findHeight(aNode.right); if(heightLeft > heightRight){ return heightLeft+1; } else{ return heightRight+1; } }

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• WCF - (Custom) binary serialisation.

  - by Barguast

  I want to be able to query my database over the web, and I am wanting to use a WCF service to handle the requests and results. The problem is that due to the amount of data that can potentially be returned from these queries, I'm worried about how these results will be serialised over the network. For example, I can imagine the XML serialisation looking like: <Results> <Person Name="Adam" DateOfBirth="01/02/1985" /> <Person Name="Bob" DateOfBirth="04/07/1986" /> </Results> And the binary serialisation containing types names and other (unnecessary) metadata. Perhaps even the type name for each element in a collection? o_o Ideally, I'd like to perform the serialisation of certain 'DataContract'-s myself so I can make it super-compact. Does anyone know if this is possible, or of any articles which explain how to do custom serialisation with WCF? Thanks in advance

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• Perl, treat string as binary byte array

  - by Mike

  In Perl, is it appropriate to use a string as a byte array containing 8-bit data? All the documentation I can find on this subject focuses on 7-bit strings. For instance, if I read some data from a binary file into $data my $data; open FILE, "<", $filepath; binmode FILE; read FILE $data 1024; and I want to get the first byte out, is substr($data,1,1) appropriate? (again, assuming it is 8-bit data) I come from a mostly C background, and I am used to passing a char pointer to a read() function. My problem might be that I don't understand what the underlying representation of a string is in Perl.

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• Read VB binary file with c# (knowing the structure)

  - by Kai

  I'd like to read a file that has been binary saved by a vb prog. the file should be read line by line, 'cause every single line represents an object with many attributes. a link looks the following: 999011011/10/1 ELW the structure of data types is: Public Type FahrzeugDAT Kennung As String * 8 Name As String * 30 Info As String * 50 StatusFzg As Integer DatumFzg As Date StatusLst As Integer DatumLst As Date TKI As Integer Folgetlg As Integer LstKurztext As String * 100 FME1 As String * 5 FME2 As String * 5 FME3 As String * 5 DME1 As String * 8 DME2 As String * 8 DME3 As String * 8 Bemerkung As String * 256 Art As Long Standort As Long End Type

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• How to parse a binary file using Javascript and Ajax

  - by Alex Jeffery

  I am trying to use JQuery to pull a binary file from a webserver, parse it in Javascript and display the contents. I can get the file ok and parse some of the file correctly. How ever I am running into trouble with one byte not coming out as expected. I am parsing the file a byte at a time, it is correct until I get to the hex value B6 where I am getting FD instead of B6. Function to read a byte data.charCodeAt(0) & 0xff; File As Hex: 02 00 00 00 55 4C 04 00 B6 00 00 00 The format I want to parse the file out into. short: 0002 short: 0000 string: UL short: 0004 long: 0000B6 Any hints as to why the last value is incorrect?

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• MATLAB - Delete elements of binary files without loading entire file

  - by Doresoom

  This may be a stupid question, but Google and MATLAB documentation have failed me. I have a rather large binary file (10 GB) that I need to open and delete the last forty million bytes or so. Is there a way to do this without reading the entire file to memory in chunks and printing it out to a new file? It took 6 hours to generate the file, so I'm cringing at the thought of re-reading the whole thing. EDIT: The file is 14,440,000,000 bytes in size. I need to chop it to 14,400,000,000.

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• Pointer-based binary heap implementation

  - by Derek Chiang

  Is it even possible to implement a binary heap using pointers rather than an array? I have searched around the internet (including SO) and no answer can be found. The main problem here is that, how do you keep track of the last pointer? When you insert X into the heap, you place X at the last pointer and then bubble it up. Now, where does the last pointer point to? And also, what happens when you want to remove the root? You exchange the root with the last element, and then bubble the new root down. Now, how do you know what's the new "last element" that you need when you remove root again?

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• Uniform distribution of binary values in Matlab

  - by JohnIdol

  I have a requirement for the generation of a given number N of vectors of given size each consistent of a uniform distribution of 0s and 1s. This is what I am doing at the moment, but I noticed that the distribution is strongly peaked at half 1s and half 0s, which is no good for what I am doing: a = randint(1, sizeOfVector, [0 1]); The unifrnd function looks promising for what I need, but I can't manage to understand how to output a binary vector of that size. Is it the case that I can use the unifrnd function (and if so how would be appreciated!) or can is there any other more convenient way to obtain such a set of vectors? Any help appreciated!

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• Optimize Binary Search Algorithm

  - by Ganesh M

  In a binary search, we have two comparisons one for greater than and other for less than, otherwise its the mid value. How would you optimize so that we need to check only once? bool binSearch(int array[], int key, int left, int right) { mid = left + (right-left)/2; if (key < array[mid]) return binSearch(array, key, left, mid-1); else if (key > array[mid]) return binSearch(array, key, mid+1, right); else if (key == array[mid]) return TRUE; // Found return FALSE; // Not Found }

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• printing double in binary

  - by Happy Mittal

  In Thinking in C++ by Bruce eckel, there is a program given to print a double value in binary.(Chapter 3, page no. 189) int main(int argc, char* argv[]) { if(argc != 2) { cout << "Must provide a number" << endl; exit(1); } double d = atof(argv[1]); unsigned char* cp = reinterpret_cast<unsigned char*>(&d); for(int i = sizeof(double); i > 0 ; i -= 2) { printBinary(cp[i-1]); printBinary(cp[i]); } } Here while printing cp[i] when i=8(assuming double is of 8 bytes), wouldn't it be undefined behaviour? I mean this code doesn't work as it doesn't print cp[0].

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• Dynamic binary from file

  - by Aurel300

  This is a little bit of weird problem here. Say I have a C++ code, running on a specific platform. The only purpose of this code is to run files containing binary, NATIVE to that platform. Now - my question is - HOW would I get the data from these files (could even be by bits, like 1024 bits a cycle) to the memory of machine running my code so that this data would be in the execution part? In other words, can I get the data to somewhere where I can point the instruction pointer? If yes, how? I don't mind if I have to use assembler for this - just so it would work.

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• JavaScript pack("d") - binary strings

  - by Tim Whitlock

  I'm trying to replicate the Perl and PHP style pack and unpack functions in JavaScript. Unsigned integers were easy enough, so my pack('n') and pack('N') are ok. But my lack of a computer science background is a hurdle now and I don't know where to start with pack('d') for packing JavaScript's standard floating point. Is there a JavaScript library for this out there? If not, is there a good resource where I can learn how to do this? I am fine with bitwise and binary level operations in JS, I just don't know where to start with the logic. Thanks.

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• C++ print out a binary search tree

  - by starcorn

  Hello, Got nothing better to do this Christmas holiday, so I decided to try out making a binary search tree. I'm stuck with the print function. How should the logic behind it work? Since the tree is already inserting it in a somewhat sorted order, and I want to print the tree from smallest values to the biggest. So I need to travel to the furthest left branch of the tree to print the first value. Right, so after that how do I remember the way back up, do I need to save the previous node? A search in wikipedia gave me an solution which they used stack. And other solutions I couldn't quite understand how they've made it, so I'm asking here instead hoping someone can enlight me. I also wonder my insert function is OK. I've seen other's solution being smaller. void treenode::insert(int i) { if(root == 0) { cout << "root" << endl; root = new node(i,root); } else { node* travel = root; node* prev; while(travel) { if(travel->value > i) { cout << "travel left" << endl; prev = travel; travel = travel->left; } else { cout << "travel right" << endl; prev = travel; travel = travel->right; } } //insert if(prev->value > i) { cout << "left" << endl; prev->left = new node(i); } else { cout << "right" << endl; prev->right = new node(i); } } } void treenode::print() { node* travel = root; while(travel) { cout << travel->value << endl; travel = travel->left; } }

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• Search filenames in MySQL database table restricted by filetype?

  - by ju

  Hello I have a MySQL database that I replicate from another server. The database contains a table with this columns ID, FileName and FileSize In the table there are more than 4'000'000 records. I want to make fast a search in FileName (varchar) column I found that I can use for this Sphinx search engine. The problem is that I want to restrict searches by filetype. Do I have to and how (trigers?) to extract file extensions for all rows? May be I have to create another table (because this one is replicated) and join them in 1:1 relation? Can you give me some advices please :)

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• Python: fetching SVG file using urllib is returning binary when I need ASCII

  - by Drew Dara-Abrams

  I'm using urllib (in Python) to fetch an SVG file: import urllib urllib.urlopen('http://alpha.vectors.cloudmade.com/BC9A493B41014CAABB98F0471D759707/-122.2487,37.87588,-122.265823,37.868054?styleid=1&viewport=400x231').read() which produces output of the sort: xb6\xf6\x00\xb3\xfb2\xff\xda\xc5\xf2\xc2\x14\xef\xcd\x82\x0b\xdbU\xb0\x81\xcaF\xd8\x1a\xf6\xdf[i)\xba\xcf\x80\xab\xd6\x8c\xe3l_\xe7\n\xed2,\xbdm\xa0_|\xbb\x12\xff\xb6\xf8\xda\xd9\xc3\xd9\t\xde\x9a\xf8\xae\xb3T\xa3\r`\x8a\x08!T\xfb8\x92\x95\x0c\xdd\x8b!\x02P\xea@\x98\x1c^\xc7\xda\\\xec\xe3\xe1\xbe,0\xcd\xbeZ~\x92\xb3\xfa\xdd\xfcbyu\xb8\x83\xbb\xbdS\x0f\x82\x0b\xfe\xf5_\xdawn\xff\xef_\xff\xe5\xfa\x1f?\xbf\xffoZ\x0f\x8b\xbfV\xf4\x04\x00' when I was expecting more like this: <?xml version='1.0' encoding='UTF-8'?> <svg xmlns="http://www.w3.org/2000/svg" xmlns:cm="http://cloudmade.com/" width="400" height="231"> <rect width="100%" height="100%" fill="#eae8dd" opacity="1"/> <g transform="scale(0.209849975856)"> <g transform="translate(13610569, 4561906)" flood-opacity="0.1" flood-color="grey"> <path d="M -13610027.720000000670552 -4562403.660000000149012 I guess this is an issue of binary vs. ASCII. Can anyone help me (a Python newbie) with the appropriate conversion so that I can get on with parsing and manipulating the SVG code?

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• Binary file email attachment problem

  - by Alan Harris-Reid

  Hi there, Using Python 3.1.2 I am having a problem sending binary attachment files (jpeg, pdf, etc.) - MIMEText attachments work fine. The code in question is as follows... for file in self.attachments: part = MIMEBase('application', "octet-stream") part.set_payload(open(file,"rb").read()) encoders.encode_base64(part) part.add_header('Content-Disposition', 'attachment; filename="%s"' % file) msg.attach(part) # msg is an instance of MIMEMultipart() server = smtplib.SMTP(host, port) server.login(username, password) server.sendmail(from_addr, all_recipients, msg.as_string()) However, way down in the calling-stack (see traceback below), it looks as though msg.as_string() has received an attachment which creates a payload of 'bytes' type instead of string. Has anyone any idea what might be causing the problem? Any help would be appreciated. Alan builtins.TypeError: string payload expected: File "c:\Dev\CommonPY\Scripts\email_send.py", line 147, in send server.sendmail(self.from_addr, all_recipients, msg.as_string()) File "c:\Program Files\Python31\Lib\email\message.py", line 136, in as_string g.flatten(self, unixfrom=unixfrom) File "c:\Program Files\Python31\Lib\email\generator.py", line 76, in flatten self._write(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 101, in _write self._dispatch(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 127, in _dispatch meth(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 181, in _handle_multipart g.flatten(part, unixfrom=False) File "c:\Program Files\Python31\Lib\email\generator.py", line 76, in flatten self._write(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 101, in _write self._dispatch(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 127, in _dispatch meth(msg) File "c:\Program Files\Python31\Lib\email\generator.py", line 155, in _handle_text raise TypeError('string payload expected: %s' % type(payload))

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• C# - parse content away from structure in a binary file

  - by Jeff Godfrey

  Using C#, I need to read a packed binary file created using FORTRAN. The file is stored in an "Unformatted Sequential" format as described here (about half-way down the page in the "Unformatted Sequential Files" section): http://www.tacc.utexas.edu/services/userguides/intel8/fc/f_ug1/pggfmsp.htm As you can see from the URL, the file is organized into "chunks" of 130 bytes or less and includes 2 length bytes (inserted by the FORTRAN compiler) surrounding each chunk. So, I need to find an efficient way to parse the actual file payload away from the compiler-inserted formatting. Once I've extracted the actual payload from the file, I'll then need to parse it up into its varying data types. That'll be the next exercise. My first thoughts are to slurp up the entire file into a byte array using File.ReadAllBytes. Then, just iterate through the bytes, skipping the formatting and transferring the actual data to a second byte array. In the end, that second byte array should contain the actual file contents minus all the formatting, which I'd then need to go back through to get what I need. As I'm fairly new to C#, I thought there might be a better, more accepted way of tackling this. Also, in case it's helpful, these files could be fairly large (say 30MB), though most will be much smaller...

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• compile Boost as static Universal binary lib

  - by Albert

  I want to have a static Universal binary lib of Boost. (Preferable the latest stable version, that is 1.43.0, or newer.) I found many Google hits with similar problems and possible solutions. However, most of them seems outdated. Also none of them really worked. Right now, I am trying sudo ./bjam --toolset=darwin --link=static --threading=multi \ --architecture=combined --address-model=32_64 \ --macosx-version=10.4 --macosx-version-min=10.4 \ install That compiles and install fine. However, the produced binaries seems broken. az@ip245 47 (openlierox) %file /usr/local/lib/libboost_signals.a /usr/local/lib/libboost_signals.a: current ar archive random library az@ip245 49 (openlierox) %lipo -info /usr/local/lib/libboost_signals.a input file /usr/local/lib/libboost_signals.a is not a fat file Non-fat file: /usr/local/lib/libboost_signals.a is architecture: x86_64 az@ip245 48 (openlierox) %otool -hv /usr/local/lib/libboost_signals.a Archive : /usr/local/lib/libboost_signals.a /usr/local/lib/libboost_signals.a(trackable.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1536 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(connection.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1776 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(named_slot_map.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1856 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(signal_base.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1776 SUBSECTIONS_VIA_SYMBOLS /usr/local/lib/libboost_signals.a(slot.o): Mach header magic cputype cpusubtype caps filetype ncmds sizeofcmds flags MH_MAGIC_64 X86_64 ALL 0x00 OBJECT 3 1616 SUBSECTIONS_VIA_SYMBOLS Any suggestion how to get that correct?

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• Passing Binary Data to a Stored Procedure in SQL Server 2008

  - by Joe Majewski

  I'm trying to figure out a way to store files in a database. I know it's recommended to store files on the file system rather than the database, but the job I'm working on would highly prefer using the database to store these images (files). There are also some constraints. I'm not an admin user, and I have to make stored procedures to execute all the commands. This hasn't been of much difficulty so far, but I cannot for the life of me establish a way to store a file (image) in the database. When I try to use the BULK command, I get an error saying "You do not have permission to use the bulk load statement." The bulk utility seemed like the easy way to upload files to the database, but without permissions I have to figure a work-a-round. I decided to use an HTML form with a file upload input type and handle it with PHP. The PHP calls the stored procedure and passes in the contents of the file. The problem is that now it's saying that the max length of a parameter can only be 128 characters. Now I'm completely stuck. I don't have permissions to use the bulk command and it appears that the max length of a parameter that I can pass to the SP is 128 characters. I expected to run into problems because binary characters and ascii characters don't mix well together, but I'm at a dead end... Thanks

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• Ruby GraphViz Binary Tree Record

  - by Jason M

  I'm using the ruby-graphviz gem and I'm trying to draw binary trees. I'd like to use the record shape so that each node can have a left, middle, and right field and, thus, if there are two edges leaving a node, the left and right edges can be distinguished. I tried specifying the field by concatenating the field name like this: @node1.name + ":left" But that did not work. What is the correct way of specifying the field? require 'rubygems' require 'graphviz' @graph = GraphViz.new( :G, :type => :digraph ) @node1 = @graph.add_node("1", "shape" => "record", "label" => "<left>|<f1> 1|<right>" ) @node2 = @graph.add_node("2", "shape" => "record", "label" => "<left>|<f1> 2|<right>" ) @graph.add_edge(@node1.name + ":left", @node2) # generate a random filename filename = "/tmp/#{(0...8).map{65.+(rand(25)).chr}.join}.png" @graph.output( :png => filename ) exec "open #{filename}"

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• parse content away from structure in a binary file

  - by Jeff Godfrey

  Using C#, I need to read a packed binary file created using FORTRAN. The file is stored in an "Unformatted Sequential" format as described here (about half-way down the page in the "Unformatted Sequential Files" section): http://www.tacc.utexas.edu/services/userguides/intel8/fc/f_ug1/pggfmsp.htm As you can see from the URL, the file is organized into "chunks" of 130 bytes or less and includes 2 length bytes (inserted by the FORTRAN compiler) surrounding each chunk. So, I need to find an efficient way to parse the actual file payload away from the compiler-inserted formatting. Once I've extracted the actual payload from the file, I'll then need to parse it up into its varying data types. That'll be the next exercise. My first thoughts are to slurp up the entire file into a byte array using File.ReadAllBytes. Then, just iterate through the bytes, skipping the formatting and transferring the actual data to a second byte array. In the end, that second byte array should contain the actual file contents minus all the formatting, which I'd then need to go back through to get what I need. As I'm fairly new to C#, I thought there might be a better, more accepted way of tackling this. Also, in case it's helpful, these files could be fairly large (say 30MB), though most will be much smaller...

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• Using recursion to to trim a binary tree based on a given min and max value

  - by Justin

  As the title says, I have to trim a binary tree based on a given min and max value. Each node stores a value, and a left/right node. I may define private helper methods to solve this problem, but otherwise I may not call any other methods of the class nor create any data structures such as arrays, lists, etc. An example would look like this: overallRoot _____[50]____________________ / \ __________[38] _______________[90] / \ / _[14] [42] [54]_____ / \ \ [8] [20] [72] \ / \ [26] [61] [83] trim(52, 65); should return: overallRoot [54] \ [61] My attempted solution has three methods: public void trim(int min, int max) { rootFinder(overallRoot, min, max); } First recursive method finds the new root perfectly. private void rootFinder(IntTreeNode node, int min, int max) { if (node == null) return; if (overallRoot.data < min) { node = overallRoot = node.right; rootFinder(node, min, max); } else if (overallRoot.data > max) { node = overallRoot = node.left; rootFinder(node, min, max); } else cutter(overallRoot, min, max); } This second method should eliminate any further nodes not within the min/max, but it doesn't work as I would hope. private void cutter(IntTreeNode node, int min, int max) { if (node == null) return; if (node.data <= min) { node.left = null; } if (node.data >= max) { node.right = null; } if (node.data < min) { node = node.right; } if (node.data > max) { node = node.left; } cutter(node.left, min, max); cutter(node.right, min, max); } This returns: overallRoot [54]_____ \ [72] / [61] Any help is appreciated. Feel free to ask for further explanation as needed.

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