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  • need to display info for user within active-directory

    - by Brad
    The following code will search for the user within the domain controller, but I want to display the info of each thing noted within the justthese variable: "displayname","mail","samaccountname","sn","givenname","department","telephonenumber" $dn = "dc=xxx,dc=xxx"; $justthese = array("displayname","mail","samaccountname","sn","givenname","department","telephonenumber"); $sr=ldap_search($ldapconn, $dn,'SAMAccountName=username', $justthese); $info = ldap_get_entries($ldapconn, $sr); echo "<h3>".$info["count"]." entries returned</h3>"; foreach($justthese as $key=>$value){ print '<p><strong>'.$value.'</strong></p>'; } It displays each item within the $justthese array, I want to display the info for that user for each thing noted in $justthese array. Right now it outputs it like this: displayname mail samaccountname sn givenname department telephonenumber I want it to have the actual data to the right of it, which I know I am doing something wrong with the foreach loop, any help is appreciated. So it'd look like this displayname Chuck mail [email protected] samaccountname chucknorris sn chuckisthebest givenname Chuck Norris department Security telephonenumber 555-555-5555

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  • Domain migration - 301 Redirect of all contentes of directory)

    - by Trufa
    Hi, I would like to know if it is possible to do the following considering that I would like to migrate domains. I have lets say: one.com/files/one.html one.com/files/two.php one.com/other/three.html one.com/other/four.doc one.com/other/subdirectory/five.doc I am migrating to two.com So I would like to make RESPECTIVE 301 redirects to the following: two.com/old/files/one.html two.com/old/files/two.php two.com/old/other/three.html two.com/old/other/four.doc two.com/old/other/subdirectory/five.doc I've tried with cPanel and although I come "close" with the redirects option I can't seem to make it happen. The folders are not much (10 -12) the file are a lot, and obviously impossible to make it manually. How would you proceed? Can this/ should this be done with regex from the .htaccess?? Can you direct all the elements of a subdirectory in the manner expressed above? I hope the question is clear enough, if not please ask for any clarification needed!! Thanks in advance!!

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  • How to change icon/emblem of a directory from bash

    - by Question Mark
    I'm playing around with get_iplayer (fantastic) it's running every few hours to grab any new episodes of whatever.... After it has finished grabbing anything new i'd like to change the emblem of ~/Videos to add a plus or star (nautilus emblem preferably) Do i go about this via nautilus? Do i need to change something in gnome-config? I'm sure this can't be FS level? Cheers for any links and advice.

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  • Getting the names of all files in a directory with PHP

    - by Greelmo
    For some reason, I keep getting a '1' for the file names with this code: if (is_dir($log_directory)) { if ($handle = opendir($log_directory)) { while($file = readdir($handle) !== FALSE) { $results_array[] = $file; } closedir($handle); } } When I echo each element in $results_array, I get a bunch of '1's, not the name of the file. How do I get the name of the files?

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  • Manipulating Directory Paths in Python

    - by G Ullman
    Basically I've got this current url and this other key that I want to merge into a new url, but there are three different cases. Suppose the current url is localhost:32401/A/B/foo if key is bar then I want to return localhost:32401/A/B/bar if key starts with a slash and is /A/bar then I want to return localhost:32401/A/bar finally if key is its own independent url then I just want to return that key = htt p://foo.com/bar - http://foo.com/bar I assume there is a way to do at least the first two cases without manipulating the strings manually, but nothing jumped out at me immediately in the os.path module.

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  • Get machine name from Active Directory

    - by Stephen Murby
    I have performed an "LDAP://" query to get a list of computers within a specified OU, my issue is not being able to collect just the computer "name" or even "cn". DirectoryEntry toShutdown = new DirectoryEntry("LDAP://" + comboBox1.Text.ToString()); DirectorySearcher machineSearch = new DirectorySearcher(toShutdown); //machineSearch.Filter = "(objectCatergory=computer)"; machineSearch.Filter = "(objectClass=computer)"; machineSearch.SearchScope = SearchScope.Subtree; machineSearch.PropertiesToLoad.Add("name"); SearchResultCollection allMachinesCollected = machineSearch.FindAll(); Methods myMethods = new Methods(); string pcName; foreach (SearchResult oneMachine in allMachinesCollected) { //pcName = oneMachine.Properties.PropertyNames.ToString(); pcName = oneMachine.Properties["name"].ToString(); MessageBox.Show(pcName); } Help much appreciated.

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  • Delete directory by referencing symbolic link

    - by Adam
    To set up the question, imagine this scenario: mkdir ~/temp cd ~/ ln -s temp temporary rm -rf temporary, rm -f temporary, and rm temporary each will remove the symbolic link but leave the directory ~/temp/. I have a script where the name of the symbolic link is easily derived but the name of the linked directory is not. Is there a way to remove the directory by referencing the symbolic link, short of parsing the name of the directory from ls -od ~/temporary?

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  • get the path of moved directory/file (source path and destination path)

    - by Ghanshyam Rathod
    When one directory is moved to other destination path, then i want to log the entry of original source path and entry of the path where it moved. any command is already available ? or any other way of doing this task? Ex: D1 = /home/user/Documents/test D2 = /home/user/Documents/Data/test when i moved D1 directory to the destination path to D2 directory then i want to log, like "test" directory is moved from D1 to D2 path Thanks

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  • Microsoft dévoile Windows Azure Active Directory, le service de gestion d'identité et d'accès dans le Cloud

    Microsoft dévoile Windows Azure Active Directory le service de gestion d'identité et d'accès dans le Cloud Après pratiquement deux années de préparation, Microsoft livre enfin les détails sur l'intégration d'Active Directory dans le Cloud. Le service d'annuaire Active Directory répertorie les éléments d'un réseau comme les comptes utilisateurs, les serveurs, les postes de travail, les dossiers partagés, les imprimantes, les bases de données, etc. Il fournit des services centralisés d'identification et d'authentification à un réseau d'ordinateurs sous Windows. [IMG]http://ftp-developpez.com/gordon-fowler/windowsazurelogo.jpg[/IMG] Windows Azure Active Directory (WAA...

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  • ???????/???30????!Active Directory+Oracle Database

    - by Yusuke.Yamamoto
    ????? ??:2010/09/08 ??:??????/?? Oracle Database 11g ???Active Directory ????????????????????????????????????????????????????????? Active Directory ??Active Directory ? Oracle Database ???Active Directory ? Oracle Database ????????????? ????????? ????????????????? http://otndnld.oracle.co.jp/ondemand/otn-seminar/movie/AD_Oracle_09081500.wmv http://www.oracle.com/technetwork/jp/content/20100908-ad-oracle-244715-ja.pdf

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  • The Active Directory integrated DNS zone _msdcs.COMPANY.LOCAL was not found.

    - by MadBoy
    Recently we renamed our domain from single domain name COMPANY to COMPANY.LOCAL due to multiple problems. However now I get this information from BPA. Issue: The Active Directory integrated DNS zone _msdcs.COMPANY.LOCAL was not found. Impact: DNS queries for the Active Directory integrated zone _msdcs.COMPANY.LOCAL might fail. Resolution: Restore the Active Directory integrated DNS zone _msdcs.COMPANY.LOCAL. Clearly there is no _msdcs.COMPANY.LOCAL as there is only old one _msdcs.COMPANY however when i check under COMPANY there is no _msdsc, but there is one when i check inside COMPANY.LOCAL. So it seems to me that _msdcs.COMPANY.LOCAL should use the one that is inside COMPANY.LOCAL? Should it not? Should I try to recreate it by hand (since it wasn't created on domain rename).

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  • Active Directory password update not recognized on OS X 10.7.3?

    - by eaj
    We have a few Macs in our office which are bound to our Active Directory (Server 2k8R2) domain for login authentication and access to file shares. For the most part this has worked without trouble. I recently changed my AD password (from the Windows box that is my main desktop machine), and my iMac still wants my old password for logins—even after a reboot. It correctly prompts for the new password when I attempt to connect to Windows smb file shares. The last time I changed my password, the iMac was running Snow Leopard and picked up the password change as expected. I'm a little bit of an OS X n00b, so I apologize if this should be obvious. My searching has turned up numerous issues people have had with Lion and Active Directory, but not this particular problem. Possibly related, we do have mobile accounts enabled for AD in the Directory Utility options. I assume this causes credentials to be cached locally, but it's not clear to me how to get them to update.

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  • Enabling EUS support in OUD 11gR2 using command line interface

    - by Sylvain Duloutre
    Enterprise User Security (EUS) allows Oracle Database to use users & roles stored in LDAP for authentication and authorization.Since the 11gR2 release, OUD natively supports EUS. EUS can be easily configured during OUD setup. ODSM (the graphical admin console) can also be used to enable EUS for a new suffix. However, enabling EUS for a new suffix using command line interface is currently not documented, so here is the procedure: Let's assume that EUS support was enabled during initial setup.Let's o=example be the new suffix I want to use to store Enterprise users. The following sequence of command must be applied for each new suffix: // Create a local database holding EUS context infodsconfig create-workflow-element --set base-dn:cn=OracleContext,o=example --set enabled:true --type db-local-backend --element-name exampleContext -n // Add a workflow element in the call path to generate on the fly attributes required by EUSdsconfig create-workflow-element --set enabled:true --type eus-context --element-name eusContext --set next-workflow-element:exampleContext -n // Add the context to a workflow for routingdsconfig create-workflow --set base-dn:cn=OracleContext,o=example --set enabled:true --set workflow-element:eusContext --workflow-name exampleContext_workflow -n //Add the new workflow to the appropriate network groupdsconfig set-network-group-prop --group-name network-group --add workflow:exampleContext_workflow -n // Create the local database for o=exampledsconfig create-workflow-element --set base-dn:o=example --set enabled:true --type db-local-backend --element-name example -n // Create a workflow element in the call path to the user data to generate on the fly attributes expected by EUS dsconfig create-workflow-element --set enabled:true --set eus-realm:o=example --set next-workflow-element:example --type eus --element-name eusWfe// Add the db to a workflow for routingdsconfig create-workflow --set base-dn:o=example --set enabled:true --set workflow-element:eusWfe --workflow-name example_workflow -n //Add the new workflow to the appropriate network groupdsconfig set-network-group-prop --group-name network-group --add workflow:example_workflow -n  // Add the appropriate acis for EUSdsconfig set-access-control-handler-prop \           --add global-aci:'(target="ldap:///o=example")(targetattr="authpassword")(version 3.0; acl "EUS reads authpassword"; allow (read,search,compare) userdn="ldap:///??sub?(&(objectclass=orclservice)(objectclass=orcldbserver))";)' dsconfig set-access-control-handler-prop \       --add global-aci:'(target="ldap:///o=example")(targetattr="orclaccountstatusevent")(version 3.0; acl "EUS writes orclaccountstatusenabled"; allow (write) userdn="ldap:///??sub?(&(objectclass=orclservice)(objectclass=orcldbserver))";)' Last but not least you must adapt the content of the ${OUD}/config/EUS/eusData.ldif  file with your suffix value then inport it into OUD.

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  • Programmatically create static arrays at compile time in C++

    - by Hippicoder
    One can define a static array at compile time as follows: const std::size_t size = 5; unsigned int list[size] = { 1, 2, 3, 4, 5 }; Question 1 - Is it possible by using various kinds of metaprogramming techniques to assign these values "programmatically" at compile time? Question 2 - Assuming all the values in the array are to be the same barr a few, is it possible to selectively assign values at compile time in a programmatic manner? eg: const std::size_t size = 7; unsigned int list[size] = { 0, 0, 2, 3, 0, 0, 0 }; Solutions using C++0x are welcome The array may be quite large, few hundred elements long The array for now will only consist of POD types It can also be assumed the size of the array will be known beforehand, in a static compile-time compliant manner. Solutions must be in C++ (no script or codegen based solutions)

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  • Why do Java source files go into a directory structure?

    - by bdhar
    Suppose that I am creating a Java project with the following classes com.bharani.ClassOne com.bharani.ClassTwo com.bharani.helper.HelperOne com.bharani.helper.support.HelperTwo with files put immediately under the folder 'src' src/ClassOne.java src/ClassTwo.java src/HelperOne.java src/HelperTwo.java and compile them using the command $ javac src/*.java -d classes (assuming that classes directory exists) The compiler compiles these files and put the class files in appropriate sub-directories inside the 'classes' directory like this classes/com/bharani/ClassOne.class classes/com/bharani/ClassTwo.class classes/com/bharani/helper/HelperOne.class classes/com/bharani/helper/support/HelperTwo.class Because the spec mandates that the classes should go inside appropriate directory structure. Fine. My question is this: When I use an IDE such as Eclipse or NetBeans, they create the directory structure for the source code directory ('src' directory here) also. Why is that? Is it mandatory? Or, is it just a convention? Thanks.

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  • Create whole path automatically when writing to a new file

    - by Bernhard V
    Hi, I want to write a new file with the Java FileWriter. I use it like this: FileWriter newJsp = new FileWriter("C:\\user\Desktop\dir1\dir2\filename.txt"); Now the dir1 and dir2 currently don't exist. I want Java to create them automatically if they aren't already there. Actually Java should set up the whole file path if not already existing. How can I achieve this?

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