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  • List to CSV in Python

    - by Steve
    Hi, I am creating a CSV from a list of values. CSV File gets created but the csv is formed as a single column. Actually it should be multiple rows with multiple columns, instead it forms as a multiple rows with a single column. I am using the following code from random import choice import csv fileObject = csv.writer(open('Insurance.csv','w'),dialect='excel',delimiter=' ') for i in range(0,175): current_list = list(choice(master_list)) fileObject.writerows(current_list) current_list = [] Thanks

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  • Is method hiding ever a good idea

    - by ScottS
    In C# the new keyword can be used to hide a base class method without overriding the base class method. I've never encountered a situation where hiding a method was the best choice available. Are there any situations where method hiding is the best choice?

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  • WHich Implemtation of JSF 1.1 to USe MyFaces or Sun RI

    - by Macvin
    Hi, We want make a choice between SUN RI 1.1 JSF implementaiton and MyFaces . Appserver we will be using is Weblogic 8.1. Could you please rpovide main points for Comparison between the two Which one is better. Can we USe Facelets in SUN RI 1.1_02 . Which is the better choice if want to move the Application to JSF 1.2 and JDK 1.5 in Future. Thanks Mac

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  • How do I require that an element has either one set of attributes or another in an XSD schema?

    - by Eli Courtwright
    I'm working with an XML document where a tag must either have one set of attributes or another. For example, it needs to either look like <tag foo="hello" bar="kitty" /> or <tag spam="goodbye" eggs="world" /> e.g. <root> <tag foo="hello" bar="kitty" /> <tag spam="goodbye" eggs="world" /> </root> So I have an XSD schema where I use the xs:choice element to choose between two different attribute groups: <xsi:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema" attributeFormDefault="unqualified" elementFormDefault="qualified"> <xs:element name="root"> <xs:complexType> <xs:sequence> <xs:element maxOccurs="unbounded" name="tag"> <xs:choice> <xs:complexType> <xs:attribute name="foo" type="xs:string" use="required" /> <xs:attribute name="bar" type="xs:string" use="required" /> </xs:complexType> <xs:complexType> <xs:attribute name="spam" type="xs:string" use="required" /> <xs:attribute name="eggs" type="xs:string" use="required" /> </xs:complexType> </xs:choice> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xsi:schema> However, when using lxml to attempt to load this schema, I get the following error: >>> from lxml import etree >>> etree.XMLSchema( etree.parse("schema_choice.xsd") ) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "xmlschema.pxi", line 85, in lxml.etree.XMLSchema.__init__ (src/lxml/lxml.etree.c:118685) lxml.etree.XMLSchemaParseError: Element '{http://www.w3.org/2001/XMLSchema}element': The content is not valid. Expected is (annotation?, ((simpleType | complexType)?, (unique | key | keyref)*))., line 7 Since the error is with the placement of my xs:choice element, I've tried putting it in different places, but no matter what I try, I can't seem to use it to define a tag to have either one set of attributes (foo and bar) or another (spam and eggs). Is this even possible? And if so, then what is the correct syntax?

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  • pythonic way of selecing a random value that satisfies a certain predicate

    - by MK
    Suppose I have a list of elements and I want to randomly select an element from the list that satisfies a predicate. What is the pythonic way of doing this? I currently do a comprehension followed by a random.choice() but that is unnecessarily inefficient : intlist = [1,2,3,4,5,6,7,8,9] evenlist = [ i for i in intlist if i % 2 == 0 ] randomeven = random.choice(evenlist) Thanks!

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  • ChoiceField or CharField in django form

    - by Will M.
    I have a CharField in the model that needs to be selected by a ChoiceField. If the user's choice is not in the choice field then they'd select "other" and be able to type in a text input. How can I do this? I don't need the javascript; just the help with the django part.

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  • resizing UITableView to fit content

    - by MiMo81
    I am creating an app which will have a question in a UILabel and a multiple choice answers displayed in UITableView, each row showing a multiple choice. Questions and answers will vary, so I need this UITableView to be dynamic in height. I would like to find a "sizeToFit" work around for the table. Where the table's frame is set to the height of all it's content. Can anyone advise on how I can achieve this? Thank you.

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  • Under what circumstances are linked lists useful?

    - by Jerry Coffin
    Most times I see people try to use linked lists, it seems to me like a poor (or very poor) choice. Perhaps it would be useful to explore the circumstances under which a linked list is or is not a good choice of data structure. Ideally, answers would expound on the criteria to use in selecting a data structure, and which data structures are likely to work best under specified circumstances.

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  • How can I fix my program from crashing in C++?

    - by Rachel
    I'm very new to programming and I am trying to write a program that adds and subtracts polynomials. My program sometimes works, but most of the time, it randomly crashes and I have no idea why. It's very buggy and has other problems I'm trying to fix, but I am unable to really get any further coding done since it crashes. I'm completely new here but any help would be greatly appreciated. Here's the code: #include <iostream> #include <cstdlib> using namespace std; int getChoice(void); class Polynomial10 { private: double* coef; int degreePoly; public: Polynomial10(int max); //Constructor for a new Polynomial10 int getDegree(){return degreePoly;}; void print(); //Print the polynomial in standard form void read(); //Read a polynomial from the user void add(const Polynomial10& pol); //Add a polynomial void multc(double factor); //Multiply the poly by scalar void subtract(const Polynomial10& pol); //Subtract polynom }; void Polynomial10::read() { cout << "Enter degree of a polynom between 1 and 10 : "; cin >> degreePoly; cout << "Enter space separated coefficients starting from highest degree" << endl; for (int i = 0; i <= degreePoly; i++) { cin >> coef[i]; } } void Polynomial10::print() { for(int i=0;i<=degreePoly;i++) { if(coef[i] == 0) { cout << ""; } else if(i>=0) { if(coef[i] > 0 && i!=0) { cout<<"+"; } if((coef[i] != 1 && coef[i] != -1) || i == degreePoly) { cout << coef[i]; } if((coef[i] != 1 && coef[i] != -1) && i!=degreePoly ) { cout << "*"; } if (i != degreePoly && coef[i] == -1) { cout << "-"; } if(i != degreePoly) { cout << "x"; } if ((degreePoly - i) != 1 && i != degreePoly) { cout << "^"; cout << degreePoly-i; } } } } void Polynomial10::add(const Polynomial10& pol) { for(int i = 0; i<degreePoly; i++) { int degree = degreePoly; coef[degreePoly-i] += pol.coef[degreePoly-(i+1)]; } } void Polynomial10::subtract(const Polynomial10& pol) { for(int i = 0; i<degreePoly; i++) { coef[degreePoly-i] -= pol.coef[degreePoly-(i+1)]; } } void Polynomial10::multc(double factor) { //int degreePoly=0; //double coef[degreePoly]; cout << "Enter the scalar multiplier : "; cin >> factor; for(int i = 0; i<degreePoly; i++) { coef[i] *= factor; } }; Polynomial10::Polynomial10(int max) { degreePoly=max; coef = new double[degreePoly]; for(int i; i<degreePoly; i++) { coef[i] = 0; } } int main() { int choice; Polynomial10 p1(1),p2(1); cout << endl << "CGS 2421: The Polynomial10 Class" << endl << endl << endl; cout << "0. Quit\n" << "1. Enter polynomial\n" << "2. Print polynomial\n" << "3. Add another polynomial\n" << "4. Subtract another polynomial\n" << "5. Multiply by scalar\n\n"; int choiceFirst = getChoice(); if (choiceFirst != 1) { cout << "Enter a Polynomial first!"; } if (choiceFirst == 1) {choiceFirst = choice;} while(choice != 0) { switch(choice) { case 0: return 0; case 1: p1.read(); break; case 2: p1.print(); break; case 3: p2.read(); p1.add(p2); cout << "Updated Polynomial: "; p1.print(); break; case 4: p2.read(); p1.subtract(p2); cout << "Updated Polynomial: "; p1.print(); break; case 5: p1.multc(10); cout << "Updated Polynomial: "; p1.print(); break; } choice = getChoice(); } return 0; } int getChoice(void) { int c; cout << "\nEnter your choice : "; cin >> c; return c; }

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  • Easymock vs Mockito: Design vs Maintainability?

    - by RAbraham
    One way of thinking about this is: if we care about the Design of the code then Easymock is the better choice as it gives feedback to you by its concept of expectations If we care about the maintainability of tests( easier to read,write and having less brittle tests which are not affected much by change), then Mockito seems a better choice. My question is: - If you have used Easymock in large scale projects, do you find that your tests are harder to maintain? - What are the limitations of Mockito( other than endo testing)

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  • Increase efficiency for an R simulator of the Monty Hall Puzzle

    - by jahan_m
    The Monty Hall Problem is a simple puzzle involving probability that even stumps professionals in careers dealing with some heavy-duty math. Here's the basic problem: Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice? You can find numerous explanations of the solution here: http://en.wikipedia.org/wiki/Monty_Hall_problem Goal of my simulation: Prove that a switching strategy will win you the car 2/3 of the time. I got curious and wanted to write a little function that simulates the problem many times and returns the proportion of wins if you switched and the proportion of wins if you stayed with your first choice. The function then plots the cumulative wins. First and foremost, I'm interested in hearing if my simulation is indeed replicating the Monty Problem, or if some aspect of the code got it wrong. Secondly, this function takes a long time to run once I get to about 10,000 simulations. I know I don't need this many simulations to prove this but I'd love to hear some ideas on how to make it more efficient. Thanks for your feedback! Monty_Hall=function(repetitions){ doors=c('A','B','C') stay_wins=0 switch_wins=0 series=data.frame(sim_num=seq(repetitions),cum_sum_stay=replicate(repetitions,0),cum_sum_switch=replicate(repetitions,0)) for(i in seq(repetitions)){ winning_door=sample(doors,1) contestant_chooses=sample(doors,1) if(contestant_chooses==winning_door) stay_wins=stay_wins+1 else switch_wins=switch_wins+1 series[i,'cum_sum_stay']=stay_wins series[i,'cum_sum_switch']=switch_wins } plot(series$sim_num,series$cum_sum_switch,col=2,ylab='Cumulative # of wins', xlab='Simulation #',main=sprintf('%d Simulations of the Monty Hall Paradox',repetitions),type='l') lines(series$sim_num,series$cum_sum_stay,col=4) legend('topleft',legend=c('Cumulative wins from switching', 'Cumulative wins from staying'),col=c(2,4),lty=1) result=list(series=series,stay_wins=stay_wins,switch_wins=switch_wins, proportion_stay_wins=stay_wins/repetitions, proportion_switch_wins=switch_wins/repetitions) return(result) } #Theory predicts that it is to the contestant's advantage if he #switches his choice to the other door. This function simulates the game #many times, and shows you the proportion of games in which staying or #switching would win the car. It also plots the cumulative wins for each strategy. Monty_Hall(100)

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  • Programming Language Choices for High Integrity Systems

    - by Finbarr
    What programming languages are a good choice for High Integrity Systems? An example of a bad choice is Java as there is a considerable amount of code that is inaccessible to the programmer. I am looking for examples of strongly typed, block structured languages where the programmer is responsible for 100% of the code, and there is as little interference from things like a JVM as possible. Compilers will obviously be an issue. Language must have a complete and unambiguous definition.

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  • Custom rendering a radioselect in django form / accessing single element?

    - by Oli
    I have a form like this: CHOICES = [ ('a', 'a_value'), ('b', 'b_value'), ('c', 'c_value') ] self.fields["choice"] = forms.ChoiceField( widget=RadioSelect(), choices=CHOICES, ) How can I select a single element of this form field in my template? I want to be able to do something like: <tr><td>{{form.choice.a}}</td><td>some custom extra field</td></tr> Or is there another way to change how the RadioSelect is rendered?

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  • How do I randomly select from a list in Python?

    - by Liam Block
    Basically, I've got a homework task of programming a text based battle simulator in Python. Obviously I've gone with pokémon... I would like the enemy to be randomly selected, however I don't know how to randomly select from a list... foo = ['a', 'b', 'c', 'd', 'e'] from random import choice print choice(foo) This is what I've been told to try but I've got no modules or anything imported... How can I make this work, appreciated.

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  • how to go back to first if statement if no choices are valid - python

    - by wondergoat77
    how can i have python move to the top of an if statement if nothing is satisfied correctly i have a basic if/else statement like this: print "pick a number, 1 or 2" a = int(raw_input("> ") if a == 1: print "this" if a == 2: print "that" else: print "you have made an invalid choice, try again." what i want is to prompt the user to make another choice for 'a' this if statement without them having to restart the entire program, but am very new to python and am having trouble finding the answer online anywhere.

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  • Cross platform GUI Programming with D

    - by Adam Hawes
    I want to start programming with D. I have a simple application in mind that needs a GUI but I want to make sure it's portable to Linux/Windows/Mac equally well and with minimal (no) change for each platform. wxD is looking like the contender of choice because I know the wx toolkit already. I see fltk4d as a contender and a (unfinished) wrapper around Qt. Are there any other truly cross platform GUI toolkits for D that will go where I want with little effort and what would the the toolkit of choice for people here?

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  • What am I encrypting wrong here?

    - by Katie Krueger
    So I have a wordplay project to do and I have to encrypt some characters. I am at the point where I am stuck, and when I run it and type 1 for encrypt it doesn't shift that many letters. It just prints the work over again. I am wondering what I could do to fix it where if I say "hello" it will print 1 character over and say "ifmmp" Thank you! import java.util.Scanner; public class WordPlayTester{ public static void main(String [] args){ String word, reverse=""; String original; int key= 0; String Menu= "1-Encrypt \n2-Decrypt \n3-Is Palindrome \n0-Quit \n-Select an option-"; Scanner in = new Scanner(System.in); System.out.println("-Type any word-"); word = in.nextLine(); System.out.println(Menu); int choice=in.nextInt(); if(choice==1) { System.out.println("Insert a Key number"); int select= in.nextInt(); for (int i=0; i < word.length(); i++) { char c = word.charAt(i); if (c >= 'A' && c <= 'Z') { c = (char)(c - 64); int n = c+1; n = n % 26; if (n < 0) { n = n + 26; } c = (char)(n + 65); } System.out.println(c); } } else if(choice==3) { int length = word.length(); for ( int i = length - 1 ; i >= 0 ; i-- ) reverse = reverse + word.charAt(i); if (word.equals(reverse)) System.out.println("Your word is a palindrome."); else System.out.println("Your word is not a palindrome."); } else if(choice==0) { System.exit(0); } else { System.out.println(Menu); } } }

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  • combobox in j2me

    - by learn
    how can i keep the combobox on the form in j2me with out using frameworks? i have tried this but it is not showing any drop down for selection. ChoiceGroup CoursePOP = new ChoiceGroup ("Pop Up choice", Choice.EXCLUSIVE, new String[] {"Python", "J2ME","Symbian"}, null);

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  • c++ setting string attribute value in class is throwing "Access violation reading location"

    - by user259789
    I am having some trouble getting this simple code to work: class CreateUserView { public: CreateUserView(void); ~CreateUserView(void); UserController* controller; void showView(); string name; string lastname; string address; string email; string dateOfBirth; }; All i need is to set these attributes in the implementation with getline(). CreateUserView::CreateUserView(void) { } void CreateUserView::showView() { cout << endl << " New User" << endl; cout << "--------------------------" << endl; cout << " Name\t\t: "; getline(cin, name); cout << " Lastname\t: "; getline(cin, lastname); cout << " Email\t\t: "; getline(cin, email); cout << " ===============================" << endl; cout << " 1. SAVE 2.CHANGE 3.CANCEL" << endl; cout << " ===============================" << endl; cout << " choice: "; int choice; cin >> choice; cin.ignore(); controller->createUser_choice(choice); } I keep getting this "Access violation reading location" error at this line: getline(cin, name); what's the best way of assigning a value to an std::string attribute of a class? even name = "whatever" is throwing that error!! thanks

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  • Regarding data storage in ecommerce applications

    - by geeth
    Why is MainFrame better choice to stores data related to customer, orders etc? I work with a online retail store, they use .net technologies for applications and MainFrames for storing product, customer, order etc related data. Is SQL DB server not a good option for these type of applications? How is MainFrames better choice than SQL DB? Please provide your insight.

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  • Reading input from a text file, omits the first and adds a nonsense value to the end?

    - by Greenhouse Gases
    Hi there When I input locations from a txt file I am getting a peculiar error where it seems to miss off the first entry, yet add a garbage entry to the end of the link list (it is designed to take the name, latitude and longitude for each location you will notice). I imagine this to be an issue with where it starts collecting the inputs and where it stops but I cant find the error!! It reads the first line correctly but then skips to the next before adding it because during testing for the bug it had no record of the first location Lisbon though whilst stepping into the method call it was reading it. Very bizarre but hopefully someone knows the issue. Here is firstly my header file: #include <string> struct locationNode { char nodeCityName [35]; double nodeLati; double nodeLongi; locationNode* Next; void CorrectCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(n <= MAX_SIZE - 1) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } n++; } //cityNameInput = this->nodeCityName; } }; class Locations { private: int size; public: Locations(){ }; // constructor for the class locationNode* Head; //int Add(locationNode* Item); }; And here is the file containing main: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations.h" #include <iostream> #include <string> #include <fstream> using namespace std; int n = 0,x, locationCount = 0, MAX_SIZE = 35; string cityNameInput; char targetCity[35]; bool acceptedInput = false, userInputReq = true, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *start_ptr = NULL; // pointer to first entry in the list locationNode *temp, *temp2; // Part is a pointer to a new locationNode we can assign changing value followed by a call to Add locationNode *seek, *bridge; void setElementsNull(char cityParam[]) { int y=0, count =0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void addLocation() { temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it if(!userInputReq) // bool that determines whether user input is required in adding the node to the list { cout << endl << "Enter the name of the location: "; cin >> temp->nodeCityName; temp->CorrectCase(); setElementsNull(temp->nodeCityName); cout << endl << "Please enter the latitude value for this location: "; cin >> temp->nodeLati; cout << endl << "Please enter the longitude value for this location: "; cin >> temp->nodeLongi; cout << endl; } temp->Next = NULL; //set to NULL as when one is added it is currently the last in the list and so can not point to the next if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list if(!userInputReq){ cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } } void populateList(){ ifstream inputFile; inputFile.open ("locations.txt", ios::in); userInputReq = true; temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it do { inputFile.get(temp->nodeCityName, 35, ' '); setElementsNull(temp->nodeCityName); inputFile >> temp->nodeLati; inputFile >> temp->nodeLongi; setElementsNull(temp->nodeCityName); if(temp->nodeCityName[0] == 10) //remove linefeed from input { for(int i = 0; temp->nodeCityName[i] != NULL; i++) { temp->nodeCityName[i] = temp->nodeCityName[i + 1]; } } addLocation(); } while(!inputFile.eof()); userInputReq = false; cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; cout << endl; inputFile.close(); } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } void deleteRecord() // complete this { int junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek != start_ptr && seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } } else { cout << targetCity << "That entry does not currently exist" << endl << endl << endl; } } void searchDatabase() { char choice; cout << "Enter search term..." << endl; cin >> targetCity; if(nodeExistTest(targetCity)) { cout << "Entry: " << endl << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': addLocation(); break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } } void printDatabase() { temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] >= 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] >=91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin >> name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin >> name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array<System::String ^> ^args) { //main contains test calls to functions at present cout << "Populating list..."; populateList(); printDatabase(); deleteRecord(); printDatabase(); cin >> cityNameInput; } The text file contains this (ignore the names, they are just for testing!!): Lisbon 45 47 Fattah 45 47 Darius 42 49 Peter 45 27 Sarah 85 97 Michelle 45 47 John 25 67 Colin 35 87 Shiron 40 57 George 34 45 Sean 22 33 The output omits Lisbon, but adds on a garbage entry with nonsense values. Any ideas why? Thank you in advance.

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  • What's the best/most efficent way to create a semi-intelligent AI for a tic tac toe game?

    - by Link
    basically I am attempting to make a a efficient/smallish C game of Tic-Tac-Toe. I have implemented everything other then the AI for the computer so far. my squares are basically structs in an array with an assigned value based on the square. For example s[1].value = 1; therefore it's a x, and then a value of 3 would be a o. My question is whats the best way to create a semi-decent game playing AI for my tic-tac-toe game? I don't really want to use minimax, since It's not what I need. So how do I avoid a a lot of if statments and make it more efficient. Here is the rest of my code: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <time.h> struct state{ // defined int state; // 0 is tie, 1 is user loss, 2 is user win, 3 is ongoing game int moves; }; struct square{ // one square of the board int value; // 1 is x, 3 is o char sign; // no space used }; struct square s[9]; //set up the struct struct state gamestate = {0,0}; //nothing void setUpGame(){ // setup the game int i = 0; for(i = 0; i < 9; i++){ s[i].value = 0; s[i].sign = ' '; } gamestate.moves=0; printf("\nHi user! You're \"x\"! I'm \"o\"! Good Luck :)\n"); } void displayBoard(){// displays the game board printf("\n %c | %c | %c\n", s[6].sign, s[7].sign, s[8].sign); printf("-----------\n"); printf(" %c | %c | %c\n", s[3].sign, s[4].sign, s[5].sign); printf("-----------\n"); printf(" %c | %c | %c\n\n", s[0].sign, s[1].sign, s[2].sign); } void getHumanMove(){ // get move from human int i; while(1){ printf(">>:"); char line[255]; // input the move to play fgets(line, sizeof(line), stdin); while(sscanf(line, "%d", &i) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid move!\n"); fgets(line, sizeof(line), stdin); } if(s[i-1].value != 0){printf("Sorry, That moves already been taken!\n\n");continue;} break; } s[i-1].value = 1; s[i-1].sign = 'x'; gamestate.moves++; } int sum(int x, int y, int z){return(x*y*z);} void getCompMove(){ // get the move from the computer } void checkWinner(){ // check the winner int i; for(i = 6; i < 9; i++){ // check cols if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } for(i = 0; i < 7; i+=3){ // check rows if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } if((sum(s[0].value,s[4].value,s[8].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[0].value,s[4].value,s[8].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} if((sum(s[2].value,s[4].value,s[6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[2].value,s[4].value,s[6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } void playGame(){ // start playing the game gamestate.state = 3; //set-up the gamestate srand(time(NULL)); int temp = (rand()%2) + 1; if(temp == 2){ // if two comp goes first temp = (rand()%2) + 1; if(temp == 2){ s[4].value = 2; s[4].sign = 'o'; gamestate.moves++; }else{ s[2].value = 2; s[2].sign = 'o'; gamestate.moves++; } } displayBoard(); while(gamestate.state == 3){ if(gamestate.moves<10); getHumanMove(); if(gamestate.moves<10); getCompMove(); checkWinner(); if(gamestate.state == 3 && gamestate.moves==9){ printf("The game is a tie :p\n"); break; } displayBoard(); } } int main(int argc, const char *argv[]){ printf("Welcome to Tic Tac Toe\nby The Elite Noob\nEnter 1-9 To play a move, standard numpad\n1 is bottom-left, 9 is top-right\n"); while(1){ // while game is being played printf("\nPress 1 to play a new game, or any other number to exit;\n>>:"); char line[255]; // input whether or not to play the game fgets(line, sizeof(line), stdin); int choice; // user's choice about playing or not while(sscanf(line, "%d", &choice) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid option!\n"); fgets(line, sizeof(line), stdin); } if(choice == 1){ setUpGame(); // set's up the game playGame(); // Play a Game }else {break;} // exit the application } printf("\nThank's For playing!\nHave a good Day!\n"); return 0; }

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  • Countdown of Top 10 Reasons to Never Ever Use a Pie Chart

    - by Tony Wolfram
      Pie charts are evil. They represent much of what is wrong with the poor design of many websites and software applications. They're also innefective, misleading, and innacurate. Using a pie chart as your graph of choice to visually display important statistics and information demonstrates either a lack of knowledge, laziness, or poor design skills. Figure 1: A floating, tilted, 3D pie chart with shadow trying (poorly)to show usage statistics within a graphics application.   Of course, pie charts in and of themselves are not evil. This blog is really about designers making poor decisions for all the wrong reasons. In order for a pie chart to appear on a web page, somebody chose it over the other alternatives, and probably thought they were doing the right thing. They weren't. Using a pie chart is almost always a bad design decision. Figure 2: Pie Chart from an Oracle Reports User Guide   A pie chart does not do the job of effectively displaying information in an elegant visual form.  Being circular, they use up too much space while not allowing their labels to line up. Bar charts, line charts, and tables do a much better job. Expert designers, statisticians, and business analysts have documented their many failings, and strongly urge software and report designers not to use them. It's obvious to them that the pie chart has too many inherent defects to ever be used effectively. Figure 3: Demonstration of how comparing data between multiple pie charts is difficult.   Yet pie charts are still used frequently in today's software applications, financial reports, and websites, often on the opening page as a symbol of how the data inside is represented. In an attempt to get a flashy colorful graphic to break up boring text, designers will often settle for a pie chart that looks like pac man, a colored spinning wheel, or a 3D floating alien space ship.     Figure 4: Best use of a pie chart I've found yet.   Why is the pie chart so popular? Through its constant use and iconic representation as the classic chart, the idea persists that it must be a good choice, since everyone else is still using it. Like a virus or an urban legend, no amount of vaccine or debunking will slow down the use of pie charts, which seem to be resistant to logic and common sense. Even the new iPad from Apple showcases the pie chart as one of its options.     Figure 5: Screen shot of new iPad showcasing pie charts. Regardless of the futility in trying to rid the planet of this often used poor design choice, I now present to you my top 10 reasons why you should never, ever user a pie chart again.    Number 10 - Pie Charts Just Don't Work When Comparing Data Number 9 - You Have A Better Option: The Sorted Horizontal Bar Chart Number 8 - The Pie Chart is Always Round Number 7 - Some Genius Will Make It 3D Number 6 - Legends and Labels are Hard to Align and Read Number 5 - Nobody Has Ever Made a Critical Decision Using a Pie Chart Number 4 - It Doesn't Scale Well to More Than 2 Items Number 3 - A Pie Chart Causes Distortions and Errors Number 2 - Everyone Else Uses Them: Debunking the "Urban Legend" of Pie Charts Number 1 - Pie Charts Make You Look Stupid and Lazy  

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  • Ask the Readers: Would You Be Willing to Give Windows Up and Use a Different O.S.?

    - by Asian Angel
    When it comes to computers, Windows definitely rules the desktop in comparison to other operating systems. What we would like to know this week is if you would actually be willing to give up using Windows altogether and move to a different operating system on your computers. Note: This week’s Ask the Readers post is posing a hypothetical situation, so please refrain from starting arguments or a flame war in the comments. Good reasoned discussion is always welcome. There is no doubt that Windows is the dominant operating system in use today. Everywhere you go or look it is easy to find computers with Windows installed such as at work, home, the library, government offices, and more. For many people it is the operating system that they know and are comfortable with, which makes changing to a different operating system less appealing. Adding to the preference for Windows (or dependency based on your view) is the custom software that many businesses use on a daily basis. Throw in the high volume of people who depend on and use Microsoft Office as a standard for their business documents and it is little wonder that Windows is so dominant. So what would you use if you did decide to take a break from or permanently move away from Windows? If your choice is Linux then you have a large and wonderful variety of distributions to choose from based on what you want out of your system. Want a distribution that is easy to work with? You could choose Ubuntu, Linux Mint, or others that are engineered to be ready to go “out of the box”. Like a challenge? Perhaps Arch Linux is more your style. One of the most attractive features of all about Linux is the price…it is very hard to beat free! Maybe Mac OS X sounds like the perfect choice. It has a certain mystique and elegance associated with it and many OS X fans refuse to use anything else if given a choice. Then there is the soon to be released Chrome OS with its’ emphasis on cloud computing. This is a system that is definitely focused on being as low-maintenance and hassle-free as possible. Quick on, quick off, minimalist, and made to be portable. All of the system’s updates will occur automatically leaving you free to work and play in the cloud. But it does have its’ limitations…no installing all of those custom apps that you love using on Windows or other systems…it is literally all about the browsing window and web apps. So there you have it. If the opportunity presented itself would you, could you give Windows up and use a different operating system? Would it be easy or hard for you to do? Perhaps it would not really matter so long as you could do what you needed or wanted to do on a computer. And maybe this is the perfect time to try something new and find out…that new favorite operating system could be just an install disc away. Let us know your thoughts in the comments! How-To Geek Polls require Javascript. Please Click Here to View the Poll. Latest Features How-To Geek ETC The Complete List of iPad Tips, Tricks, and Tutorials The 50 Best Registry Hacks that Make Windows Better The How-To Geek Holiday Gift Guide (Geeky Stuff We Like) LCD? LED? Plasma? The How-To Geek Guide to HDTV Technology The How-To Geek Guide to Learning Photoshop, Part 8: Filters Improve Digital Photography by Calibrating Your Monitor The Brothers Mario – Epic Gangland Style Mario Brothers Movie Trailer [Video] Score Awesome Games on the Cheap with the Humble Indie Bundle Add a Colorful Christmas Theme to Your Windows 7 Desktop This Windows Hack Changes the Blue Screen of Death to Red Edit Images Quickly in Firefox with Pixlr Grabber Zoho Writer, Sheet, and Show Now Available in Chrome Web Store

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