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  • A cycle in object graph detected in JPA.

    - by Nitesh Panchal
    Hello, I am trying to figure out this error since 5 hours without any success. SO i finally thought of posting in here. Please help i am really in big trouble. I am stuck on this and see no way of solving this error. This is my database structure tblBlogRegion BlogRegionId (primary key) BlogRegionName tblGadget GadgetId(primary key) GadgetName tblBlogs BlogId(primary key) Blogname BlogTypeId (reference key from tblSiteTerm tblSiteTerms SiteTermsId(primary key) SiteTermsName tblBlogGadgets BlogGadgetsId(primary key) BlogRegionId(foreign key from tblBlogRegion) BlogId(foreign key from tblBlog) GadgetId(foreign key from tblGadget) Is it not normal database structure? Do you see anything that is cyclic? WHen i try to fetch list from tblGadgets i get this error :- [com.sun.istack.SAXException2: A cycle is detected in the object graph. This will cause infinitely deep XML: entity.BlogGadgets[blogGadgetsId=1] -> entity.Blogs[blogId=2] -> entity.BlogGadgets[blogGadgetsId=1]] I am trying to get list from web service using JAS-WS.

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  • Dropdown Menus In Drupal?

    - by Wade D Ouellet
    Hi, I have my Drupal site here so far: selkirk.treethink.net Each Primary Link at the top has a bunch of other primary links under it (sub links) I need to display these sub links when you hover over the parent primary link in a dropdown menu. Everything is in the primary links but there are parents (what you see at the top of the demo) and sub links (what should be in the dropdown). I'm not sure if I set up these menus wrong though...Drupal is a little awkward for me. I did download this module but I am not sure how to get it going to automatically dropdown a primary link's submenu items when rolled over: http://drupal.org/project/jquery_dropdown Thanks, Wade

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  • Doctrine_Table_Exception: Unknown relation alias shoesTable in /home/sadiqsof/public_html/projects/g

    - by Sadiqur Rahman
    I am getting following error message: Doctrine_Table_Exception: Unknown relation alias shoesTable in /home/sadiqsof/public_html/projects/giftshoes/system/database/doctrine/Doctrine/Relation/Parser.php on line 237 My Code is below: ------------BaseShoe------------ <?php // Connection Component Binding Doctrine_Manager::getInstance()->bindComponent('Shoes', 'sadiqsof_giftshoes'); /** * BaseShoes * * This class has been auto-generated by the Doctrine ORM Framework * * @property integer $sku * @property string $name * @property string $keywords * @property string $description * @property string $manufacturer * @property float $sale_price * @property float $price * @property string $url * @property string $image * @property string $category * @property Doctrine_Collection $Viewes * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ abstract class BaseShoes extends Doctrine_Record { public function setTableDefinition() { $this->setTableName('shoes'); $this->hasColumn('sku', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => true, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('name', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('keywords', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('description', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('manufacturer', 'string', 20, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '20', )); $this->hasColumn('sale_price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('url', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('image', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('category', 'string', 50, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '50', )); } public function setUp() { parent::setUp(); $this->hasMany('Viewes', array( 'local' => 'sku', 'foreign' => 'sku')); } } --------------ShoesTable-------- <?php class ShoesTable extends Doctrine_Table { function getAllShoes($from = 0, $total = 15) { $q = Doctrine_Query::create() ->from('Shoes') ->limit($total) ->offset($from); return $q->execute(array(), Doctrine::HYDRATE_ARRAY); } } ---------------Shoes Model----------------- <?php /** * Shoes * * This class has been auto-generated by the Doctrine ORM Framework * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ class Shoes extends BaseShoes { function __construct() { parent::__construct(); $this->shoesTable = Doctrine::getTable('Shoes'); } function getAllShoes() { return $this->shoesTable->getAllShoes(); } }

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  • 12c??? - Active Data Guard Far Sync

    - by Jian Zhang(??)
    ?? ================ Active Data Guard Far Sync?Oracle 12c????(???Far Sync Standby),Far Sync?????????????(Primary Database)?????????Far Sync??,??(Primary Database) ??(synchronous)??redo?Far Sync??,??Far Sync????redo??(asynchronous)???????(Standby Database)???????????????????????Far Sync????????,init?????????,???????? ??redo ????Maximum Availability??,???????????(Primary Database)?????????Far Sync??,??(Primary Database)??(synchronous)??redo?Far Sync??,???????(zero data loss),?????Far Sync????,??????,??????????????Far Sync????redo??(asynchronous)???????(Standby Database)? ??redo ????Maximum Performance??,???????????(Primary Database)?????????Far Sync??,??(Primary Database) ????redo?Far Sync??,??Far Sync???????redo?????????(Standby Database)????????????????(Standby Database)??redo???(offload)? Far Sync????Data Guard ????(role transitions)????,?switchover/failover?????12c????? ???????Data Guard ????,?switchover/failover,???????????????Far Sync??,??Far Sync???????????????????? ???Far Sync???????,??????????????2?Far Sync??,???????? ???????Far Sync????? Far Sync??? ================ ????Far Sync ================ 1. ??Data Guard,???11.2??,??????«Active Database Duplication for A standby database» 2. ????Far Sync??,Far Sync????????,init?????????,???????? ??Far Sync???????,?????: SQL> ALTER DATABASE CREATE FAR SYNC INSTANCE CONTROLFILE AS '/tmp/controlfs01.ctl'; 3. ????redo?????Far Sync??,????LOG_ARCHIVE_DEST_2??: LOG_ARCHIVE_DEST_2='SERVICE=dg12cfs SYNC AFFIRM MAX_FAILURE=1 ALTERNATE=LOG_ARCHIVE_DEST_3 VALID_FOR=(ONLINE_LOGFILES,PRIMARY_ROLE) DB_UNIQUE_NAME=dg12cfs' 4. ??Far Sync??????redo???,??Far Sync??LOG_ARCHIVE_DEST_2??: LOG_ARCHIVE_DEST_2='SERVICE=dg12cs ASYNC VALID_FOR=(STANDBY_LOGFILES,STANDBY_ROLE) DB_UNIQUE_NAME=dg12cs' 5. ????Far Sync???????,??????????????2?Far Sync??? 6. ???????: SQL> select * from  V$DATAGUARD_CONFIG; DB_UNIQUE_NAME       PARENT_DBUN       DEST_ROLE         CURRENT_SCN     CON_ID ------------------------------ ------------------------------     ----------------- ----------- ---------- dg12cfs                        dg12cp          FAR SYNC INSTANCE      682995          0 dg12cs                         dg12cfs         PHYSICAL STANDBY       682995          0 dg12cp                        NONE             PRIMARY DATABASE      683138          0 ????????????????:Oracle_12c_Active_Data_Guard_Far_Sync_v1.pdf

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  • Doctrine_Table_Exception: Unknown relation alias [closed]

    - by Sadiqur Rahman
    I am getting following error message: Doctrine_Table_Exception: Unknown relation alias shoesTable in /home/public_html/projects/giftshoes/system/database/doctrine/Doctrine/Relation/Parser.php on line 237 My Code is below: ------------BaseShoe------------ <?php // Connection Component Binding Doctrine_Manager::getInstance()->bindComponent('Shoes', 'sadiqsof_giftshoes'); /** * BaseShoes * * This class has been auto-generated by the Doctrine ORM Framework * * @property integer $sku * @property string $name * @property string $keywords * @property string $description * @property string $manufacturer * @property float $sale_price * @property float $price * @property string $url * @property string $image * @property string $category * @property Doctrine_Collection $Viewes * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ abstract class BaseShoes extends Doctrine_Record { public function setTableDefinition() { $this->setTableName('shoes'); $this->hasColumn('sku', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => true, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('name', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('keywords', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('description', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('manufacturer', 'string', 20, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '20', )); $this->hasColumn('sale_price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('url', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('image', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('category', 'string', 50, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '50', )); } public function setUp() { parent::setUp(); $this->hasMany('Viewes', array( 'local' => 'sku', 'foreign' => 'sku')); } } --------------ShoesTable-------- <?php class ShoesTable extends Doctrine_Table { function getAllShoes($from = 0, $total = 15) { $q = Doctrine_Query::create() ->from('Shoes') ->limit($total) ->offset($from); return $q->execute(array(), Doctrine::HYDRATE_ARRAY); } } ---------------Shoes Model----------------- <?php /** * Shoes * * This class has been auto-generated by the Doctrine ORM Framework * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ class Shoes extends BaseShoes { function __construct() { parent::__construct(); $this->shoesTable = Doctrine::getTable('Shoes'); } function getAllShoes() { return $this->shoesTable->getAllShoes(); } }

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  • PHP Doctrine - YAML syntax help. Default value for many to many relationship?

    - by Dan
    Hi, I have the following YAML schema for organising users in Doctrine: Person: tableName: people columns: id: type: integer primary: true autoincrement: true firstname: type: string notnull: true lastname: type: string notnull: true User: inheritance: extends: Person type: column_aggregation keyField: type keyValue: 1 Userdetails: columns: person_id: type: integer primary: true password: type: string notnull: true relations: User: foreignType: one local: person_id onDelete: CASCADE onUpdate: CASCADE Group: tableName: groups columns: id: type: integer primary: true autoincrement: true name: type: string notnull: true UserGroup: columns: group_id: type: integer primary: true person_id: type: integer primary: true relations: User: foreignType: many local: person_id Group: foreignType: many Basically, any people who are users will belong to one or more groups. Is there any way to add new users to a particular group by default? Any advice appreciated. Thanks

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  • Doctrine_Table_Exception: Unknown relation alias shoesTable [closed]

    - by Sadiqur Rahman
    I am getting following error message: Doctrine_Table_Exception: Unknown relation alias shoesTable in /home/public_html/projects/giftshoes/system/database/doctrine/Doctrine/Relation/Parser.php on line 237 My Code is below: ------------BaseShoe------------ <?php // Connection Component Binding Doctrine_Manager::getInstance()->bindComponent('Shoes', 'sadiqsof_giftshoes'); /** * BaseShoes * * This class has been auto-generated by the Doctrine ORM Framework * * @property integer $sku * @property string $name * @property string $keywords * @property string $description * @property string $manufacturer * @property float $sale_price * @property float $price * @property string $url * @property string $image * @property string $category * @property Doctrine_Collection $Viewes * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ abstract class BaseShoes extends Doctrine_Record { public function setTableDefinition() { $this->setTableName('shoes'); $this->hasColumn('sku', 'integer', 4, array( 'type' => 'integer', 'fixed' => 0, 'unsigned' => false, 'primary' => true, 'autoincrement' => false, 'length' => '4', )); $this->hasColumn('name', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('keywords', 'string', 255, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '255', )); $this->hasColumn('description', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('manufacturer', 'string', 20, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '20', )); $this->hasColumn('sale_price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('price', 'float', null, array( 'type' => 'float', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('url', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('image', 'string', null, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '', )); $this->hasColumn('category', 'string', 50, array( 'type' => 'string', 'fixed' => 0, 'unsigned' => false, 'primary' => false, 'notnull' => true, 'autoincrement' => false, 'length' => '50', )); } public function setUp() { parent::setUp(); $this->hasMany('Viewes', array( 'local' => 'sku', 'foreign' => 'sku')); } } --------------ShoesTable-------- <?php class ShoesTable extends Doctrine_Table { function getAllShoes($from = 0, $total = 15) { $q = Doctrine_Query::create() ->from('Shoes') ->limit($total) ->offset($from); return $q->execute(array(), Doctrine::HYDRATE_ARRAY); } } ---------------Shoes Model----------------- <?php /** * Shoes * * This class has been auto-generated by the Doctrine ORM Framework * * @package ##PACKAGE## * @subpackage ##SUBPACKAGE## * @author ##NAME## <##EMAIL##> * @version SVN: $Id: Builder.php 6820 2009-11-30 17:27:49Z jwage $ */ class Shoes extends BaseShoes { function __construct() { parent::__construct(); $this->shoesTable = Doctrine::getTable('Shoes'); } function getAllShoes() { return $this->shoesTable->getAllShoes(); } }

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  • Oracle Unique Indexes

    - by Melvin
    I was creating a new table today in 10g when I noticed an interesting behavior. Here is an example of what I did: CREATE TABLE test_table ( field_1 INTEGER PRIMARY KEY ); Oracle will by default, create a non-null unique index for the primary key. I double checked this. After a quick check, I find a unique index name SYS_C0065645. Everything is working as expected so far. Now I did this: CREATE TABLE test_table ( field_1 INTEGER, CONSTRAINT pk_test_table PRIMARY KEY (field_1) USING INDEX (CREATE INDEX idx_test_table_00 ON test_table (field_1))); After describing my newly created index idx_test_table_00, I see that it is non-unique. I tried to insert duplicate data into the table and was stopped by the primary key constraint, proving that the functionality has not been affected. It seems strange to me that Oracle would allow a non-unique index to be used for a primary key constraint. Why is this allowed?

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  • Database design for a Fantasy league

    - by Samidh T
    Here's the basic schema for my database Table user{ userid numeber primary key, count number } Table player{ pid number primary key, } Table user-player{ userid number primary key foreign key(user), pid number primary key foreign key(player) } Table temp{ pid number primary key, points number } Here's what I intend to do... After every match the temp table is updated which holds the id of players that played the last match and the points they earned. Next run a procedure that will match the pid from temp table with every uid of user-player table having the same pid. add the points from temp table to the count of user table for every matching uid. empty temp table. My questions is considering 200 players and 10000 users,Will this method be efficient? I am going to be using mysql for this.

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  • foreign key and index issue

    - by George2
    Hello everyone, I am using SQL Server 2008 Enterprise. I have a table and one of its column is referring to another column in another table (in the same database) as foreign key, here is the related SQL statement, in more details, column [AnotherID] in table [Foo] refers to another table [Goo]'s column [GID] as foreign key. [GID] is primary key and clustered index on table [Goo]. My question is, in this way, if I do not create index on [AnotherID] column on [Foo] explicitly, will there be an index created automatically for [AnotherID] column on [Foo] -- because its foreign key reference column [GID] on table [Goo] already has primary clustered key index? CREATE TABLE [dbo].[Foo]( [ID] [bigint] IDENTITY(1,1) NOT NULL, [AnotherID] [int] NULL, [InsertTime] [datetime] NULL CONSTRAINT DEFAULT (getdate()), CONSTRAINT [PK_Foo] PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] ALTER TABLE [dbo].[Foo] WITH CHECK ADD CONSTRAINT [FK_Foo] FOREIGN KEY([Goo]) REFERENCES [dbo].[Goo] ([GID]) ALTER TABLE [dbo].[Foo] CHECK CONSTRAINT [FK_Foo] thanks in advance, George

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  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

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  • In Android, does _id have to be present in any table created?

    - by Andy
    I am trying to create a table to only has a foreign key, not a primary key. I am getting this error: java.lang.IllegalArgumentException: column '_id' does not exist I read a tutorial that the primary key must be _id, with no explanation. And that is fine. But what if I do not want a primary key! What if I only want a foreign key. I am assuming this is where my problem lies. The schemas below are what I have. But the third one is where I assume this is coming from. database.execSQL("CREATE TABLE events (" + "_id INTEGER PRIMARY KEY, event_name TEXT" + ")"); database.execSQL("CREATE TABLE reminders(_id INTEGER PRIMARY KEY, event_name TEXT" + ")"); database.execSQL("CREATE TABLE events_info (_id INTEGER, event_name TEXT, all_day INTEGER, " + "start_date INTEGER, start_time INTEGER, end_date INTEGER, end_time INTEGER," + " location TEXT, reminder_id INTEGER, notes TEXT, repeat TEXT," + "FOREIGN KEY(_id) REFERENCES events(_id), FOREIGN KEY(reminder_id) REFERENCES reminders(_id))" );

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  • BizTalk Business Rules Engine - Repeating Elements Question

    - by Andrew Cripps
    Hello I'm trying to create what I think should be a relatively simple business rule to operate over repeating elements in an XML schema. Consider the following XML snippet (this is simplified with namespaces removed, for readability): <Root> <AllAccounts> <Account id="1" currentPayment="10.00" arrearsAmount="25.00"> <AllCustomers> <Customer id="20" primary="true" canSelfServe="false" /> <Customer id="21" primary="false" canSelfServe="false" /> </AllCustomers> </Account> <Account id="2" currentPayment="10.00" arrearsAmount="15.00"> <AllCustomers> <Customer id="30" primary="true" canSelfServe="false" /> <Customer id="31" primary="false" canSelfServe="false" /> </AllCustomers> </AllAccounts> </Root> What I want to do is to have two rules: Set /Root/AllAccounts/Account[x]/AllCustomers/Customer[primary='true']/canSelfServe = true IF arrearsAmount < currentPayment Set /Root/AllAccounts/Account[x]/AllCustoemrs/Customer[primary='true']/canSelfServer = false IF arrearsAmount = currentPayment Where [x] is 0...number of /Root/AllAccounts/Account records present in the XML. I've tried two simple rules for this, and each rule seems to fire x * x times, where x is the number of Account records in the XML. I only want each rule to fire once for each Account record. Any help greatly appreciated! Thanks Andrew

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  • python sqlite3 won't execute a join, but sqlite3 alone will

    - by Francis Davey
    Using the sqlite3 standard library in python 2.6.4, the following query works fine on sqlite3 command line: select segmentid, node_t, start, number,title from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) left outer join numbers using (start, legid, version); But If I execute it via the sqlite3 library in python I get an error: >>> conn=sqlite3.connect('data/test.db') >>> conn.execute('''select segmentid, node_t, start, number,title from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) left outer join numbers using (start, legid, version)''') Traceback (most recent call last): File "<stdin>", line 1, in <module> sqlite3.OperationalError: cannot join using column start - column not present in both tables The (computed) table on the left hand side of the join appears to have the relevant column because if I check it by itself I get: >>> conn.execute('''select * from ((segments inner join position using (segmentid)) left outer join titles using (legid, segmentid)) limit 20''').description (('segmentid', None, None, None, None, None, None), ('html', None, None, None, None, None, None), ('node_t', None, None, None, None, None, None), ('legid', None, None, None, None, None, None), ('version', None, None, None, None, None, None), ('start', None, None, None, None, None, None), ('title', None, None, None, None, None, None)) My schema is: CREATE TABLE leg (legid integer primary key, t char(16), year char(16), no char(16)); CREATE TABLE numbers ( number char(16), legid integer, version integer, start integer, end integer, prev integer, prev_number char(16), next integer, next_number char(16), primary key (number, legid, version)); CREATE TABLE position ( segmentid integer, legid integer, version integer, start integer, primary key (segmentid, legid, version)); CREATE TABLE 'segments' (segmentid integer primary key, html text, node_t integer); CREATE TABLE titles (legid integer, segmentid integer, title text, primary key (legid, segmentid)); CREATE TABLE versions (legid integer, version integer, primary key (legid, version)); CREATE INDEX idx_numbers_start on numbers (legid, version, start); I am baffled as to what I am doing wrong. I have tried quitting/restarting both the python and sqlite command lines and can't see what I'm doing wrong. It may be completely obvious.

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  • mysql complex key or + auto increment key (guid)

    - by darko
    Hi, I have not very big db. I am using auto increment primary keys and in my case there is no problem with that. GUID is not necessary. I have a table containing this fields: from_destination to_testination shipper quantity Where the fields 1,2,3 needs to be unique. Also I have second table that for the fields 1,2,3 stores bought quantities per day One to many. from_destination to_destination shipper date reserved_quantity case 1 Is it better to make fields 1,2,3 as primary complex key in the first table and the same fields in the second table to be foreign key First table from_destination | to_destination | primary shipper | quaitity Second table second_id - autoincrement primary from_destination | to_destination | foreign key shipper | date reserved_quantity Case 2 or just to add auto increment filed in the first table and make fields 1,2,3 unique. In the second table there will be one ingeger foreign key pointing to the first table, and one auto increment key for the table. First table first_id - autoincrement primary from_destination | to_destination | unique shipper | quaitity Second table second_id - autoincrement primary first_id - forein date reserved_quantity If so why we need complex keys, when we can have one field auto increment or GUID and all other fields that are candidates for complex key to be unique. Regards

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  • Which non-clustered index should I use?

    - by Junior Mayhé
    Here I am studying nonclustered indexes on SQL Server Management Studio. I've created a table with more than 1 million records. This table has a primary key. CREATE TABLE [dbo].[Customers]( [CustomerId] [int] IDENTITY(1,1) NOT NULL, [CustomerName] [varchar](100) NOT NULL, [Deleted] [bit] NOT NULL, [Active] [bit] NOT NULL, CONSTRAINT [PK_Customers] PRIMARY KEY CLUSTERED ( [CustomerId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] This is the query I'll be using to see what execution plan is showing: SELECT CustomerName FROM Customers Well, executing this command with no additional non-clustered index, it leads the execution plan to show me: I/O cost = 3.45646 Operator cost = 4.57715 Now I'm trying to see if it's possible to improve performance, so I've created a non-clustered index for this table: 1) First non-clustered index CREATE NONCLUSTERED INDEX [IX_CustomerID_CustomerName] ON [dbo].[Customers] ( [CustomerId] ASC, [CustomerName] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] GO Executing again the select against Customers table, the execution plan shows me: I/O cost = 2.79942 Operator cost = 3.92001 It seems better. Now I've deleted this just created non-clustered index, in order to create a new one: 2) First non-clustered index CREATE NONCLUSTERED INDEX [IX_CustomerIDIncludeCustomerName] ON [dbo].[Customers] ( [CustomerId] ASC ) INCLUDE ( [CustomerName]) WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] GO With this new non-clustered index, I've executed the select statement again and the execution plan shows me the same result: I/O cost = 2.79942 Operator cost = 3.92001 So, which non-clustered index should I use? Why the costs are the same on execution plan for I/O and Operator? Am I doing something wrong or this is expected? thank you

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  • How do I write this MySQL query?

    - by CT
    I am working on an Asset DB using a lamp stack. In this example consider the following 5 tables: asset, server, laptop, desktop, software All tables have a primary key of id, which is a unique asset id. Every object has all asset attributes and then depending on type of asset has additional attributes in the corresponding table. If the type is a server, desktop or laptop it also has items in the software table. Here are the table create statements: // connect to mysql server and database "asset_db" mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); // create asset table mysql_query("CREATE TABLE asset( id VARCHAR(50) PRIMARY KEY, company VARCHAR(50), location VARCHAR(50), purchase_date VARCHAR(50), purchase_order VARCHAR(50), value VARCHAR(50), type VARCHAR(50), notes VARCHAR(200))") or die(mysql_error()); echo "Asset Table Created.</br />"; // create software table mysql_query("CREATE TABLE software( id VARCHAR(50) PRIMARY KEY, software VARCHAR(50), license VARCHAR(50))") or die(mysql_error()); echo "Software Table Created.</br />"; // create laptop table mysql_query("CREATE TABLE laptop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Laptop Table Created.</br />"; // create desktop table mysql_query("CREATE TABLE desktop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Desktop Table Created.</br />"; // create server table mysql_query("CREATE TABLE server( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Server Table Created.</br />"; ?> How do I query the database so that if I search by id, I receive all related fields to that asset id? Thank you.

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  • Unable to persist objects in GAE JDO

    - by Basil Dsouza
    Hello Guys, I am completely fresh to both JDO and GAE, and have been struggling to get my data layer to persist any code at all! The issues I am facing may be very simple, but I just cant seem to find any a way no matter what solution I try. Firstly the problem: (Slightly simplified, but still contains all the info necessary) My data model is as such: User: (primary key) String emailID String firstName Car: (primary key) User user (primary key) String registration String model This was the initial datamodel. I implemented a CarPK object to get a composite primary key of the User and the registration. However that ran into a variety of issues. (Which i will save for another time/question) I then changed the design as such: User: (Unchanged) Car: (primary key) String fauxPK (here fauxPK = user.getEmailID() + SEP + registration) User user String registration String model This works fine for the user, and it can insert and retrieve user objects. However when i try to insert a Car Object, i get the following error: "Cannot have a java.lang.String primary key and be a child object" Found the following helpful link about it: http://stackoverflow.com/questions/2063467/persist-list-of-objects Went to the link suggested there, that explains how to create Keys, however they keep talking about "Entity Groups" and "Entity Group Parents". But I cant seem to find any articles or sites that explain what are "Entity Group"s or an "Entity Group Parents" I could try fiddling around some more to figure out if i can store an object somehow, But I am running sort on patience and also would rather understand and implement than vice versa. So i would appreciate any docs (even if its huge) that covers all these points, and preferably has some examples that go beyond the very basic data modeling. And thanks for reading such a long post :)

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  • How to reference using Entity Framework and Asp.Net Mvc 2

    - by Picflight
    Tables CREATE TABLE [dbo].[Users]( [UserId] [int] IDENTITY(1,1) NOT NULL, [UserName] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, [Email] [varchar](255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, [BirthDate] [smalldatetime] NULL, [CountryId] [int] NULL, CONSTRAINT [PK_Users] PRIMARY KEY CLUSTERED ([UserId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] CREATE TABLE [dbo].[TeamMember]( [UserId] [int] NOT NULL, [TeamMemberUserId] [int] NOT NULL, [CreateDate] [smalldatetime] NOT NULL CONSTRAINT [DF_TeamMember_CreateDate] DEFAULT (getdate()), CONSTRAINT [PK_TeamMember] PRIMARY KEY CLUSTERED ([UserId] ASC, [TeamMemberUserId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] dbo.TeamMember has both UserId and TeamMemberUserId as the index key. My goal is to show a list of Users on my View. In the list I want to flag, or highlight the Users that are Team Members of the LoggedIn user. My ViewModel public class UserViewModel { public int UserId { get; private set; } public string UserName { get; private set; } public bool HighLight { get; private set; } public UserViewModel(Users users, bool highlight) { this.UserId = users.UserId; this.UserName = users.UserName; this.HighLight = highlight; } } View <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcPaging.IPagedList<MyProject.Mvc.Models.UserViewModel>>" %> <% foreach (var item in Model) { %> <%= item.UserId %> <%= item.UserName %> <%if (item.HighLight) { %> Team Member <% } else { %> Not Team Member <% } %> How do I toggle the TeamMember or Not If I add dbo.TeamMember to the EDM, there are no relationships on this table, how will I wire it to Users object? So I am comparing the LoggedIn UserId with this list(SELECT TeamMemberUserId FROM TeamMember WHERE UserId = @LoggedInUserId)

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  • Symfony generating database from model

    - by Sergej Jevsejev
    Hello, I am having troubles generating a simple database form model. I am using: Doctrine on Symfony 1.4.4 MySQL Workbench 5.2.16 with Doctrine Export 0.4.2dev So my ERL Model is: http://img708.imageshack.us/img708/1716/tmg.png Genereted YAML file: --- detect_relations: true options: collate: utf8_unicode_ci charset: utf8 type: InnoDB Course: columns: id: type: integer(4) primary: true notnull: true autoincrement: true name: type: string(255) notnull: true keywords: type: string(255) notnull: true summary: type: clob(65535) notnull: true Lecture: columns: id: type: integer(4) primary: true notnull: true autoincrement: true course_id: type: integer(4) primary: true notnull: true name: type: string(255) notnull: true description: type: string(255) notnull: true url: type: string(255) relations: Course: class: Course local: course_id foreign: id foreignAlias: Lectures foreignType: many owningSide: true User: columns: id: type: integer(4) primary: true unique: true notnull: true autoincrement: true firstName: type: string(255) notnull: true lastName: type: string(255) notnull: true email: type: string(255) unique: true notnull: true designation: type: string(1024) personalHeadline: type: string(1024) shortBio: type: clob(65535) UserCourse: tableName: user_has_course columns: user_id: type: integer(4) primary: true notnull: true course_id: type: integer(4) primary: true notnull: true relations: User: class: User local: user_id foreign: id foreignAlias: UserCourses foreignType: many owningSide: true Course: class: Course local: course_id foreign: id foreignAlias: UserCourses foreignType: many owningSide: true And no matter what I try this error occurs after: symfony doctrine:build --all --no-confirmation SQLSTATE[42000]: Syntax error or access violation: 1072 Key column 'user_userid' doesn't exist in table. Failing Query: "ALTER TABLE user_has_course ADD CONSTRAINT user_has_course_user_userid_user_id FOREIGN KEY (user_userid) REFERENCES user(id)". Failing Query: ALTER TABLE user_has_course ADD CONSTRAINT user_has_cou rse_user_userid_user_id FOREIGN KEY (user_userid) REFERENCES user(id) Currently I am studying Symfony, and stuck with this error. Please help.

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  • symfony + doctrine + inheritance, how to make them work?

    - by imac
    I am beginning to work with Symfony, I've found some documentation about inheritance. But also found this discouraging article, which make me doubt if Doctrine handles inheritance any good at all... Has anyone find a smart solution for inheritance in Symfony+Doctrine? As an example, I have already structured the database something like this: CREATE TABLE `poster` ( `poster_id` int(11) NOT NULL AUTO_INCREMENT, `user_name` varchar(50) NOT NULL, PRIMARY KEY (`poster_id`), UNIQUE KEY `id` (`poster_id`), ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; CREATE TABLE `user` ( `user_id` int(11) NOT NULL, `real_name` varchar(50) DEFAULT NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`), CONSTRAINT `user_fk` FOREIGN KEY (`user_id`) REFERENCES `poster` (`poster_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; From that, Doctrine generated this "schema.yml": Poster: connection: doctrine tableName: poster columns: poster_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true user_name: type: string(50) fixed: false unsigned: false primary: false notnull: true autoincrement: false relations: Post: local: poster_id foreign: poster_id type: many User: local: poster_id foreign: user_id type: many Version: local: poster_id foreign: poster_id type: many User: connection: doctrine tableName: user columns: user_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: false real_name: type: string(50) fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Poster: local: user_id foreign: poster_id type: one User creation for this structure with Doctrine auto-generated forms does not work. Any clue will be appreciated.

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  • Question on SQL Grouping

    - by Lijo
    Hi Team, I am trying to achieve the following without using sub query. For a funding, I would like to select the latest Letter created date and the ‘earliest worklist created since letter created’ date for a funding. FundingId Leter (1, 1/1/2009 )(1, 5/5/2009) (1, 8/8/2009) (2, 3/3/2009) FundingId WorkList (1, 5/5/2009 ) (1, 9/9/2009) (1, 10/10/2009) (2, 2/2/2009) Expected Result - FundingId Leter WorkList (1, 8/8/2009, 9/9/2009) I wrote a query as follows. It has a bug. It will omit those FundingId for which the minimum WorkList date is less than latest Letter date (even though it has another worklist with greater than letter created date). CREATE TABLE #Funding( [Funding_ID] [int] IDENTITY(1,1) NOT NULL, [Funding_No] [int] NOT NULL, CONSTRAINT [PK_Center_Center_ID] PRIMARY KEY NONCLUSTERED ([Funding_ID] ASC) ) ON [PRIMARY] CREATE TABLE #Letter( [Letter_ID] [int] IDENTITY(1,1) NOT NULL, [Funding_ID] [int] NOT NULL, [CreatedDt] [SMALLDATETIME], CONSTRAINT [PK_Letter_Letter_ID] PRIMARY KEY NONCLUSTERED ([Letter_ID] ASC) ) ON [PRIMARY] CREATE TABLE #WorkList( [WorkList_ID] [int] IDENTITY(1,1) NOT NULL, [Funding_ID] [int] NOT NULL, [CreatedDt] [SMALLDATETIME], CONSTRAINT [PK_WorkList_WorkList_ID] PRIMARY KEY NONCLUSTERED ([WorkList_ID] ASC) ) ON [PRIMARY] SELECT F.Funding_ID, Funding_No, MAX (L.CreatedDt), MIN(W.CreatedDt) FROM #Funding F INNER JOIN #Letter L ON L.Funding_ID = F.Funding_ID LEFT OUTER JOIN #WorkList W ON W.Funding_ID = F.Funding_ID GROUP BY F.Funding_ID,Funding_No HAVING MIN(W.CreatedDt) MAX (L.CreatedDt) How can I write a correct query without using subquery? Please help Thanks Lijo

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  • UpdateModelFromDatabaseException when trying to add a table to Entity Framework model

    - by Agent_9191
    I'm running into a weird issue with Entity Framework in .NET 3.5 SP1 within Visual Studio 2008. I created a database with a few tables in SQL Server and then created the associated .edmx Entity Framework model and had no issues. I then created a new table in the database that has a foreign key to an existing table and needed to be added to the .edmx. So I opened the .edmx in Visual Studio and in the models right-clicked and chose "Update Model From Database...". I saw the new table in the "add" tab, so I checked it and clicked finish. However I get an error message with the following text: --------------------------- Microsoft Visual Studio --------------------------- An exception of type 'Microsoft.Data.Entity.Design.Model.Commands.UpdateModelFromDatabaseException' occurred while attempting to update from the database. The exception message is: 'Cannot update from the database. Cannot resolve the Name Target for ScalarProperty 'ID <==> CustomerID'.'. --------------------------- OK --------------------------- For reference, here's the tables seem to be the most pertinent to the error. CustomerPreferences already exists in the .edmx. Diets is the table that was added afterwards and trying to add to the .edmx. CREATE TABLE [dbo].[CustomerPreferences]( [ID] [uniqueidentifier] NOT NULL, [LastUpdatedTime] [datetime] NOT NULL, [LastUpdatedBy] [uniqueidentifier] NOT NULL, PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] CREATE TABLE [dbo].[Diets]( [ID] [uniqueidentifier] NOT NULL, [CustomerID] [uniqueidentifier] NOT NULL, [Description] [nvarchar](50) NOT NULL, [LastUpdatedTime] [datetime] NOT NULL, [LastUpdatedBy] [uniqueidentifier] NOT NULL, PRIMARY KEY CLUSTERED ( [ID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[Diets] WITH CHECK ADD CONSTRAINT [FK_Diets_CustomerPreferences] FOREIGN KEY([CustomerID]) REFERENCES [dbo].[CustomerPreferences] ([ID]) GO ALTER TABLE [dbo].[Diets] CHECK CONSTRAINT [FK_Diets_CustomerPreferences] GO This seems like a fairly common use case, so I'm not sure where I'm going wrong.

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  • MySQL Query Where Column Like Column

    - by shmeeps
    I'm working on a small project that involves grabbing a list of contacts which are stored for each group. Essentially, the database is set up so that each group has a primary and secondary contact stored as, unsurprisingly, Group.Primary and Group.Secondary. The objective is to pull every Primary and Secondary contact for each Group and display them in a sortable table. I have the sortable table all worked out, but I have come across a small problem. Each primary and secondary field can have more than one contact separated by a comma. For instance, if Primary contained 123,256 , it would need to pull both Contacts with IDs 123 and 256. I had intended to use a query formatted like this: SELECT * FROM Group G, Contacts C WHERE G.Primary LIKE %C.ID% OR G.Secondary LIKE %C.ID% so that I could just skip the comma part, but I can't seem to find a working query for this. My question to you is, am I just overlooking something here? Is there a simple query that would let me do this? Or am I better off getting the groups and contacts separately, and combine the two later. I think the former is a little easier to understand when read, which is a plus as this is a shared project, but if that is not possible I will do the latter. This code is simplified, but it gets the point across.

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  • odd behavior when checking if radio button selected in jQuery

    - by RememberME
    I had the following check in my jQuery which I thought was working fine to see if a radio button was checked. if ($("input[@name='companyType']:checked").attr('id') == "primary") { ... } Here's the radiobuttons: <p> <label>Company Type:</label> <label for="primary"><input onclick="javascript: $('#sec').hide('slow');$('#primary_company').find('option:first').attr('selected','selected');" type="radio" name="companyType" id="primary" checked />Primary</label> <label for="secondary"><input onclick="javascript: $('#sec').show('slow');" type="radio" name="companyType" id="secondary" />Subsidiary</label> </p> Then, it suddenly stopped working (or so I thought). I did some debugging and finally realized that it was returning an id of "approved_status". Elsewhere on my form I have a checkbox called "approved_status". I realized that when I originally tested this, I must have testing it on records where approved_status is false. And, now most of my approved_statuses are true/checked. I changed the code to this: var id = $("input:radio[@name='companyType']:checked").attr('id'); alert(id); if (id == "primary") { And it's now properly returning "primary" or "secondary" as the id. So, it is working, but it seems that it's not checking the name at all and now just checking radio buttons. I just want to know for future use, what's wrong with the original code b/c I can see possibly having 2 different radio sets on a page and then my new fix probably wouldn't work. Thanks!

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