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  • DFS replication initial step problem

    - by vn
    Heya, I just setup DFS on my network and it's working fine, and now I'm trying to setup DFS-R on a test folder, but then at the end of the procedure (all went fine, selected my 2 folders, primary folder, replication topology and such) I get this error message (roughly translated from french) : Unable to define security on the replicated folder. The shared administration folder doesn't exist. I'm also wondering if there's any required security on the folders to replicate so that DFS-R can access it. I was trying to add SYSTEM in the security, but it won't find it/allow me. The folder has many many files and folders on the primary DFS pointer, but none on the 2nd, just created it with quite the same rights. Note that the primary DFS pointer is on a 2008 server and the DFS service and the secondary DFS pointer are on a 2008r2. Any help is very appreciated, thanks.

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  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

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  • Cluster failover and strange gratuitous arp behavior

    - by lazerpld
    I am experiencing a strange Windows 2008R2 cluster related issue that is bothering me. I feel that I have come close as to what the issue is, but still don't fully understand what is happening. I have a two node exchange 2007 cluster running on two 2008R2 servers. The exchange cluster application works fine when running on the "primary" cluster node. The problem occurs when failing over the cluster ressource to the secondary node. When failing over the cluster to the "secondary" node, which for instance is on the same subnet as the "primary", the failover initially works ok and the cluster ressource continues to work for a couple of minutes on the new node. Which means that the recieving node does send out a gratuitous arp reply packet that updated the arp tables on the network. But after x amount of time (typically within 5 minutes time) something updates the arp-tables again because all of a sudden the cluster service does not answer to pings. So basically I start a ping to the exchange cluster address when its running on the "primary node". It works just great. I failover the cluster ressource group to the "secondary node" and I only have loss of one ping which is acceptable. The cluster ressource still answers for some time after being failed over and all of a sudden the ping starts timing out. This is telling me that the arp table initially is updated by the secondary node, but then something (which I haven't found out yet) wrongfully updates it again, probably with the primary node's MAC. Why does this happen - has anyone experienced the same problem? The cluster is NOT running NLB and the problem stops immidiately after failing over back to the primary node where there are no problems. Each node is using NIC teaming (intel) with ALB. Each node is on the same subnet and has gateway and so on entered correctly as far as I am concerned. Edit: I was wondering if it could be related to network binding order maybe? Because I have noticed that the only difference I can see from node to node is when showing the local arp table. On the "primary" node the arp table is generated on the cluster address as the source. While on the "secondary" its generated from the nodes own network card. Any input on this? Edit: Ok here is the connection layout. Cluster address: A.B.6.208/25 Exchange application address: A.B.6.212/25 Node A: 3 physical nics. Two teamed using intels teaming with the address A.B.6.210/25 called public The last one used for cluster traffic called private with 10.0.0.138/24 Node B: 3 physical nics. Two teamed using intels teaming with the address A.B.6.211/25 called public The last one used for cluster traffic called private with 10.0.0.139/24 Each node sits in a seperate datacenter connected together. End switches being cisco in DC1 and NEXUS 5000/2000 in DC2. Edit: I have been testing a little more. I have now created an empty application on the same cluster, and given it another ip address on the same subnet as the exchange application. After failing this empty application over, I see the exact same problem occuring. After one or two minutes clients on other subnets cannot ping the virtual ip of the application. But while clients on other subnets cannot, another server from another cluster on the same subnet has no trouble pinging. But if i then make another failover to the original state, then the situation is the opposite. So now clients on same subnet cannot, and on other they can. We have another cluster set up the same way and on the same subnet, with the same intel network cards, the same drivers and same teaming settings. Here we are not seeing this. So its somewhat confusing. Edit: OK done some more research. Removed the NIC teaming of the secondary node, since it didnt work anyway. After some standard problems following that, I finally managed to get it up and running again with the old NIC teaming settings on one single physical network card. Now I am not able to reproduce the problem described above. So it is somehow related to the teaming - maybe some kind of bug? Edit: Did some more failing over without being able to make it fail. So removing the NIC team looks like it was a workaround. Now I tried to reestablish the intel NIC teaming with ALB (as it was before) and i still cannot make it fail. This is annoying due to the fact that now i actually cannot pinpoint the root of the problem. Now it just seems to be some kind of MS/intel hick-up - which is hard to accept because what if the problem reoccurs in 14 days? There is a strange thing that happened though. After recreating the NIC team I was not able to rename the team to "PUBLIC" which the old team was called. So something has not been cleaned up in windows - although the server HAS been restarted! Edit: OK after restablishing the ALB teaming the error came back. So I am now going to do some thorough testing and i will get back with my observations. One thing is for sure. It is related to Intel 82575EB NICS, ALB and Gratuitous Arp.

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  • reverse nslookup fails for single machine

    - by matt wilkie
    I have a computer on a windows Active Directory network for which reverse dns lookup fails. It doesn't matter which machine runs the lookup. The problem computer is a debian vm on a windows server 2003 host. >nslookup wiki.dept Server: primary.internal.domain.org Address: 192.111.222.44 Name: wiki.dept.internal.domain.org Address: 192.111.111.185 >nslookup 192.111.111.185 Server: primary.internal.domain.org Address: 192.111.222.44 *** primary.internal.domain.org can't find 192.111.111.185: Non-existent domain Contents of /etc/resolv.conf on the debian guest: nameserver 192.111.111.244 nameserver 192.111.222.44 search internal.domain.org What is wrong? how do I get ip-to-name resolution to work for this machine? Thank you.

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  • Redhat cluster Vs Pacemaker Vs Gluster Vs Sheepdog

    - by chandank
    Changing the entire question as earlier one was very confusing. I have been exploring different clustering system to run Virtual machines on two different machines on LAN with high availability. Currently I am already using DRBD resource on two different machines on Primary/Secondary mode. In case the primary fails I manually promote the secondary to Primary and start the VM. I also explored Gluster and looks good, however, I would rather prefer clustering over Gluster (user space FS). So if anyone has idea which one would be better from ease of use prospective please I would be interested in. Moreover, sheepdog project appears good, however, could not find much documentations/Howtos. I am using Centos 6.

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  • Mouse Icon Distorted on Secondary Display

    - by Nathan Taylor
    I have a strange issue with a dual monitor, extended desktop setup where the mouse is always fine on the primary monitor, but sometimes when I move to the secondary display the icon becomes garbled and distorted (sometimes it just looks like a vertical line, instead of a pointer). If I move the mouse back and forth rapidly between primary and secondary displays the level of "garbledness" of the icon will change and sometimes go away completely. If I switch the display settings and set it to "Duplicate Monitor 1" then I end up with a garbled icon on the primary display and an accurate one on the secondary. Very annoying. Computer is Windows 7 Ultimate with an HD8750 and the newest video drivers. Monitors are two Dell 24" displays connected via DVI cables. I have also tried VGA cables.

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  • Installing Solaris with Window. Disk partitioning problem.

    - by RishiPatel
    I am running windows and want to install the solaris but having hard time while using installer. I have 1 primary partition of 40GB and one extended partition. Extended partition have 4 logical drive. Solaris disk management window show only two partition one is of 40GB(Primary) and second is Extended partition. Can i convert a logical drive into primary partition( I have one free of 25 GB). Please look at the screenshot of disk management utitlity of window. http://img195.imageshack.us/img195/2005/20726948.jpg Is there any way to install solaris without reformatting the and repartitioning whole drive? In case it is not possible how should i partition and using which utility ?

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  • DFS replication initial step problem

    - by vn.
    I just setup DFS on my network and it's working fine, and now I'm trying to setup DFS-R on a test folder, but then at the end of the procedure (all went fine, selected my 2 folders, primary folder, replication topology and such) I get this error message (roughly translated from french) : Unable to define security on the replicated folder. The shared administration folder doesn't exist. I'm also wondering if there's any required security on the folders to replicate so that DFS-R can access it. I was trying to add SYSTEM in the security, but it won't find it/allow me. The folder has many many files and folders on the primary DFS pointer, but none on the 2nd, just created it with quite the same rights. Note that the primary DFS pointer is on a 2008 server and the DFS service and the secondary DFS pointer are on a 2008r2. Any help is very appreciated, thanks.

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  • Dual-WAN router

    - by aix
    I am looking for a router that would fit the following requirements: Two WAN interfaces: the primary is PPPoE, the secondary will link to a GigE port on another router (a 100Mbps link will suffice); Two (ideally four) GigE LAN ports; No requirement for a firewall; No requirement for Wi-Fi; Inexpensive. The plan for the two WAN interfaces is as follows. All outbound traffic will go to the primary, with exceptions based on destination IP/subnet or possibly on src+dest IPs/subnets. Such exceptions should be routed to the secondary. It would be very nice if, should the primary go down, the secondary would automatically take over for all outbound traffic. I am reasonably sure that I can put something together based on dd-wrt. However, I'd like to hear from you what alternatives are out there (especially something easier to set up for my use case, even if it means paying more for the hardware.)

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  • Servers at remote sites vs. centralized servers?

    - by Boden
    Looking for some opinions here. We've got three physical locations and site-to-site VPN between all three. Currently we've got Windows domain controllers at each location, with roughly 50 clients at each. The domains are currently separate, and we're looking at integrating the three sites. Email (Exchange) will be located at the primary site, and RPD is already being used at the secondary branches to hit the app servers also located at the primary site. The bulk of the local user load at the other two sites is just file sharing. What would the main benefits and drawbacks be of replacing the local domain controllers with NAS devices, and only keeping the domain controller(s) at the primary site? (assuming upgrades are coming regardless) Under what circumstances would you choose one setup over the other?

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  • How do I make YouTube videos fill up the entire screen when using dual monitors?

    - by Jephir
    I am using a dual monitor setup on Ubuntu 9.10 using the TwinView configuration in NIVIDA X Server Settings. My total resolution is 2960x1050 pixels, and my individual monitors are 1680x1050 (primary) and 1280x1024 (secondary). When going into fullscreen mode on any video on YouTube, I only see a cropped version of the video on my primary display as seen below. This does not occur on any other video sharing website - they properly make the video to fill the entire screen on my primary monitor. To my knowledge this problem only happens on YouTube.

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  • CentOS - Yum doesn't update anymore?

    - by Xanathos
    I've been trying to use yum now, but for some reason, not even the search work anymore. I even tried putting packages I already downloaded in the search criteria and is the same. [root@AMDFX03 Downloads]# yum search glibc Loaded plugins: fastestmirror, refresh-packagekit, security Loading mirror speeds from cached hostfile epel/metalink | 22 kB 00:00 * base: centos.secrel.com.br * epel: archive.linux.duke.edu * extras: centos.secrel.com.br * rpmforge: apt.sw.be * updates: centos.secrel.com.br adobe-linux-x86_64/primary | 1.2 kB 00:00 http://linuxdownload.adobe.com/linux/x86_64/repodata/primary.xml.gz: [Errno -1] Metadata file does not match checksum Trying other mirror. Error: failure: repodata/primary.xml.gz from adobe-linux-x86_64: [Errno 256] No more mirrors to try. This error always appear no matter what I do. Please, can you tell me how to fix this, or at least how to reset yum's configuration?

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  • Will my RAID0 stay intact when I move it to a new computer?

    - by Jeremy H
    My primary drive is a 250GB WD SATA drive. So, I added 2x 500GB 7,200 RPM WD SATA drives into my Windows Vista box and created a 1TB RAID0. I then formatted the the primary drive and installed Windows 7. To my pleasant surprise when I booted into Windows 7 my RAID0 was still intact and I kept trotting along the same as I did before. Now I am replacing my motherboard, processor, and RAM and plan on formatting the primary 250GB drive again and using it to boot for a new clean install of Windows 7. My question is: if I move these two SATA drives which are setup for RAID0 into the new system, install Windows 7 again, will the RAID0 remain? Edit: Software RAID. I created it within Windows. The RAID0 does NOT contain the system boot partition.

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  • How do I make YouTube videos fill up an entire screen when using dual monitors?

    - by Jephir
    I am using a dual monitor setup on Ubuntu 9.10 using the TwinView configuration in NIVIDA X Server Settings. My total resolution is 2960x1050 pixels, and my individual monitors are 1680x1050 (primary) and 1280x1024 (secondary). When going into fullscreen mode on any video on YouTube, I only see a cropped version of the video on my primary display as seen below. This does not occur on any other video sharing website - they properly make the video to fill the entire screen on my primary monitor. To my knowledge this problem only happens on YouTube.

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  • Dialogs appear on wrong monitor with SQL Server Management Studio 2008

    - by David
    I am running SSMS 2008 on Windows 7 with a dual monitor setup (one large, one small). SSMS is running on the secondary monitor, but everytime a dialog is opened, the dialog is placed on the primary monitor instead. I've tried moving the dialog over, closing it, and then re-opening it, but it doesn't remember and goes back to the primary monitor. This is really annoying for some of the designer dialogs, is there any way to fix this other than switching SSMS to the primary monitor? Is this a known bug with SSMS, or is it a problem with my particular setup?

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  • Devices menu - project to second screen with only one monitor

    - by Jacob Palmer
    So I made a huge blunder. In the devices menu on Windows 8, I selected to project to a second screen only on accident. I had two monitors connected but only the primary one was actually displaying anything. So I projected it and now I can't access anything. The primary screen will show the windows icon when it loads, but then it disappears and I can't login or anything. Surely there's a way to get it back on the primary screen? Thanks a bunch. I'm really lost..

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  • Freenas & LDAP Multiple User Groups Not Taking Affect

    - by Daniel Baker
    we are using, Freenas 9.2.1.7 which communicates with LDAP to control file permission. We have Windows users in multiple groups. Some belong to Finance as their primary group and Admin as another group they belong to. They can only access files from their Primary group. We use LDAP Account Manager - 4.4 to control which group the users belong to. We have also been trying to control access from the command line. We hae tried using this : setfacl -m group@:rwWxpaRc::allow DIR / Or File Name The problem is only the primary group is being seen / used. I am trying to determine why only on group is being used. Can someone please help me diagnose where the problem is. Thanks for the help, Dan

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  • Partition and mount my secondary hard drive on CentOS 5.5 64bit?

    - by Andrew Fashion
    I am trying to prepare my second hard drive for user image uploads. Here is the current layout: # sudo parted /dev/sda print Model: ATA WDC WD2500KS-00M (scsi) Disk /dev/sda: 250GB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 32.3kB 107MB 107MB primary ext3 boot 2 107MB 8595MB 8488MB primary linux-swap 3 8595MB 10.7GB 2147MB primary ext3 4 10.7GB 250GB 239GB extended 5 10.7GB 250GB 239GB logical ext3 Information: Don't forget to update /etc/fstab, if necessary. I am assuming #4 is my secondary drive? How do I partition and mount it so I can begin using it? And how do I add to fstab? I understand if it's to many questions in one, just help me with whatever you can I guess :) Thank you for any help!

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  • How to install Windows 8 boot manager in a different partition?

    - by arnab321
    the last time i installed Windows 7, the boot manager automatically got installed in a small hidden partition, and the main os into another partition. So, formatting the c: won't affect the boot manager. yesterday i wiped and repartitioned my hdd like this: 50mb primary ntfs (meant for boot manager) 100gb primary ntfs (for win 8) 50gb primary ntfs (for win 7) some logical partitions to install ubuntu and other os i installed win 7 and then win 8, and now there is no os choosing menu. system directly boots win 8 and the 50 mb partition is empty. There is a way to boot Windows 7 and even Ubuntu directly from the Windows boot manager with EasyBCD. But How do i put the boot manager in the 50mb partition ?

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  • Is there a software in windows that enables you to boot from a specific partition?

    - by Tono Nam
    I use acronis true image to mount images to my primary partition and it works great. lets say I have 3 partitions on my hard disk and all of them each is 600 GB. In the 3rd partition I keep files (documents, pictures etc), on the first partition is my primary partition where the operating system runs (windows 7). And in the 2nd partition is empty. I have an image of my primary partition and I save that image in my 3rd partition (50 GB is the size of the image so it fits in the partition number 3) and in an external hard drive. I know it is possible to install a new operating system in partition 2 such as windows xp but the only problem is that once I install that how could I tell the computer to boot from partition 1? is there a way to switch back and forth just like it's possible in the mac?

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  • How can I create a bootable CD-ROM/USB Drive? (With NTFS + USB Drive support)

    - by RonK
    My motherboard got fried and I was forced to get a new hardware set (MB+CPU+RAM) so in most likelyhood I'll need to reinstall my Windows 7. I usually follow procedure and put the OS on the primary partition and my data on a logical partition - so I can format the primary without concern - but this time I made a mistakte and left some crucial items on the primary partition. I want to create a bootable CD-ROM/USB Drive which can read NTFS so I can access this data. If booting via a CD-ROM, I would prefer being able to connect a disk-on-key/My Passport to the computer and be able to access it to transfer the data to it. How can I do it? (free 3rd party applications are most welcome)

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  • Gnome 3 freezes on logon on samsung RV 509

    - by Noufal
    I have a Samsung NP-RV509 A0FIN and I tried to install GNU/Linux with gnome 3.2 on it. I tried Fedora 16, Ubuntu 11.10 and Linux Mint 12 RC, but with no success. All of these freezes upon login into gnome shell. I think it is the problem with graphics driver, so I tried xorg-edgers ppa on my last installation, ie., Linux Mint. I also tried various intel graphics packages listed on Synaptic package manager, but no success again. My device configuration is as follows(obtained from windows 7): More details about my computer Component Details Subscore Base score Processor Intel(R) Pentium(R) CPU P6200 @ 2.13GHz 5.6 4.6 Memory (RAM) 4.00 GB 7.2 Graphics Intel(R) HD Graphics 4.6 Gaming graphics 1562 MB Total available graphics memory 5.2 Primary hard disk 12GB Free (50GB Total) 5.9 Windows 7 Ultimate System -------------------------------------------------------------------------------- Manufacturer SAMSUNG ELECTRONICS CO., LTD. Model RV409/RV509/RV709 Total amount of system memory 4.00 GB RAM System type 32-bit operating system Number of processor cores 2 64-bit capable Yes Storage -------------------------------------------------------------------------------- Total size of hard disk(s) 418 GB Disk partition (C:) 12 GB Free (50 GB Total) Media drive (D:) CD/DVD Disk partition (E:) 526 MB Free (191 GB Total) Disk partition (F:) 101 GB Free (177 GB Total) Graphics -------------------------------------------------------------------------------- Display adapter type Intel(R) HD Graphics Total available graphics memory 1562 MB Dedicated graphics memory 64 MB Dedicated system memory 0 MB Shared system memory 1498 MB Display adapter driver version 8.15.10.2202 Primary monitor resolution 1366x768 DirectX version DirectX 10 Network -------------------------------------------------------------------------------- Network Adapter Realtek PCIe GBE Family Controller Network Adapter Broadcom 802.11n Network Adapter Network Adapter Microsoft Virtual WiFi Miniport Adapter Notes -------------------------------------------------------------------------------- The gaming graphics score is based on the primary graphics adapter. If this system has linked or multiple graphics adapters, some software applications may see additional performance benefits. Any help is appreciated, and thanks in advance.

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  • So…is it a Seek or a Scan?

    - by Paul White
    You’re probably most familiar with the terms ‘Seek’ and ‘Scan’ from the graphical plans produced by SQL Server Management Studio (SSMS).  The image to the left shows the most common ones, with the three types of scan at the top, followed by four types of seek.  You might look to the SSMS tool-tip descriptions to explain the differences between them: Not hugely helpful are they?  Both mention scans and ranges (nothing about seeks) and the Index Seek description implies that it will not scan the index entirely (which isn’t necessarily true). Recall also yesterday’s post where we saw two Clustered Index Seek operations doing very different things.  The first Seek performed 63 single-row seeking operations; and the second performed a ‘Range Scan’ (more on those later in this post).  I hope you agree that those were two very different operations, and perhaps you are wondering why there aren’t different graphical plan icons for Range Scans and Seeks?  I have often wondered about that, and the first person to mention it after yesterday’s post was Erin Stellato (twitter | blog): Before we go on to make sense of all this, let’s look at another example of how SQL Server confusingly mixes the terms ‘Scan’ and ‘Seek’ in different contexts.  The diagram below shows a very simple heap table with two columns, one of which is the non-clustered Primary Key, and the other has a non-unique non-clustered index defined on it.  The right hand side of the diagram shows a simple query, it’s associated query plan, and a couple of extracts from the SSMS tool-tip and Properties windows. Notice the ‘scan direction’ entry in the Properties window snippet.  Is this a seek or a scan?  The different references to Scans and Seeks are even more pronounced in the XML plan output that the graphical plan is based on.  This fragment is what lies behind the single Index Seek icon shown above: You’ll find the same confusing references to Seeks and Scans throughout the product and its documentation. Making Sense of Seeks Let’s forget all about scans for a moment, and think purely about seeks.  Loosely speaking, a seek is the process of navigating an index B-tree to find a particular index record, most often at the leaf level.  A seek starts at the root and navigates down through the levels of the index to find the point of interest: Singleton Lookups The simplest sort of seek predicate performs this traversal to find (at most) a single record.  This is the case when we search for a single value using a unique index and an equality predicate.  It should be readily apparent that this type of search will either find one record, or none at all.  This operation is known as a singleton lookup.  Given the example table from before, the following query is an example of a singleton lookup seek: Sadly, there’s nothing in the graphical plan or XML output to show that this is a singleton lookup – you have to infer it from the fact that this is a single-value equality seek on a unique index.  The other common examples of a singleton lookup are bookmark lookups – both the RID and Key Lookup forms are singleton lookups (an RID lookup finds a single record in a heap from the unique row locator, and a Key Lookup does much the same thing on a clustered table).  If you happen to run your query with STATISTICS IO ON, you will notice that ‘Scan Count’ is always zero for a singleton lookup. Range Scans The other type of seek predicate is a ‘seek plus range scan’, which I will refer to simply as a range scan.  The seek operation makes an initial descent into the index structure to find the first leaf row that qualifies, and then performs a range scan (either backwards or forwards in the index) until it reaches the end of the scan range. The ability of a range scan to proceed in either direction comes about because index pages at the same level are connected by a doubly-linked list – each page has a pointer to the previous page (in logical key order) as well as a pointer to the following page.  The doubly-linked list is represented by the green and red dotted arrows in the index diagram presented earlier.  One subtle (but important) point is that the notion of a ‘forward’ or ‘backward’ scan applies to the logical key order defined when the index was built.  In the present case, the non-clustered primary key index was created as follows: CREATE TABLE dbo.Example ( key_col INTEGER NOT NULL, data INTEGER NOT NULL, CONSTRAINT [PK dbo.Example key_col] PRIMARY KEY NONCLUSTERED (key_col ASC) ) ; Notice that the primary key index specifies an ascending sort order for the single key column.  This means that a forward scan of the index will retrieve keys in ascending order, while a backward scan would retrieve keys in descending key order.  If the index had been created instead on key_col DESC, a forward scan would retrieve keys in descending order, and a backward scan would return keys in ascending order. A range scan seek predicate may have a Start condition, an End condition, or both.  Where one is missing, the scan starts (or ends) at one extreme end of the index, depending on the scan direction.  Some examples might help clarify that: the following diagram shows four queries, each of which performs a single seek against a column holding every integer from 1 to 100 inclusive.  The results from each query are shown in the blue columns, and relevant attributes from the Properties window appear on the right: Query 1 specifies that all key_col values less than 5 should be returned in ascending order.  The query plan achieves this by seeking to the start of the index leaf (there is no explicit starting value) and scanning forward until the End condition (key_col < 5) is no longer satisfied (SQL Server knows it can stop looking as soon as it finds a key_col value that isn’t less than 5 because all later index entries are guaranteed to sort higher). Query 2 asks for key_col values greater than 95, in descending order.  SQL Server returns these results by seeking to the end of the index, and scanning backwards (in descending key order) until it comes across a row that isn’t greater than 95.  Sharp-eyed readers may notice that the end-of-scan condition is shown as a Start range value.  This is a bug in the XML show plan which bubbles up to the Properties window – when a backward scan is performed, the roles of the Start and End values are reversed, but the plan does not reflect that.  Oh well. Query 3 looks for key_col values that are greater than or equal to 10, and less than 15, in ascending order.  This time, SQL Server seeks to the first index record that matches the Start condition (key_col >= 10) and then scans forward through the leaf pages until the End condition (key_col < 15) is no longer met. Query 4 performs much the same sort of operation as Query 3, but requests the output in descending order.  Again, we have to mentally reverse the Start and End conditions because of the bug, but otherwise the process is the same as always: SQL Server finds the highest-sorting record that meets the condition ‘key_col < 25’ and scans backward until ‘key_col >= 20’ is no longer true. One final point to note: seek operations always have the Ordered: True attribute.  This means that the operator always produces rows in a sorted order, either ascending or descending depending on how the index was defined, and whether the scan part of the operation is forward or backward.  You cannot rely on this sort order in your queries of course (you must always specify an ORDER BY clause if order is important) but SQL Server can make use of the sort order internally.  In the four queries above, the query optimizer was able to avoid an explicit Sort operator to honour the ORDER BY clause, for example. Multiple Seek Predicates As we saw yesterday, a single index seek plan operator can contain one or more seek predicates.  These seek predicates can either be all singleton seeks or all range scans – SQL Server does not mix them.  For example, you might expect the following query to contain two seek predicates, a singleton seek to find the single record in the unique index where key_col = 10, and a range scan to find the key_col values between 15 and 20: SELECT key_col FROM dbo.Example WHERE key_col = 10 OR key_col BETWEEN 15 AND 20 ORDER BY key_col ASC ; In fact, SQL Server transforms the singleton seek (key_col = 10) to the equivalent range scan, Start:[key_col >= 10], End:[key_col <= 10].  This allows both range scans to be evaluated by a single seek operator.  To be clear, this query results in two range scans: one from 10 to 10, and one from 15 to 20. Final Thoughts That’s it for today – tomorrow we’ll look at monitoring singleton lookups and range scans, and I’ll show you a seek on a heap table. Yes, a seek.  On a heap.  Not an index! If you would like to run the queries in this post for yourself, there’s a script below.  Thanks for reading! IF OBJECT_ID(N'dbo.Example', N'U') IS NOT NULL BEGIN DROP TABLE dbo.Example; END ; -- Test table is a heap -- Non-clustered primary key on 'key_col' CREATE TABLE dbo.Example ( key_col INTEGER NOT NULL, data INTEGER NOT NULL, CONSTRAINT [PK dbo.Example key_col] PRIMARY KEY NONCLUSTERED (key_col) ) ; -- Non-unique non-clustered index on the 'data' column CREATE NONCLUSTERED INDEX [IX dbo.Example data] ON dbo.Example (data) ; -- Add 100 rows INSERT dbo.Example WITH (TABLOCKX) ( key_col, data ) SELECT key_col = V.number, data = V.number FROM master.dbo.spt_values AS V WHERE V.[type] = N'P' AND V.number BETWEEN 1 AND 100 ; -- ================ -- Singleton lookup -- ================ ; -- Single value equality seek in a unique index -- Scan count = 0 when STATISTIS IO is ON -- Check the XML SHOWPLAN SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col = 32 ; -- =========== -- Range Scans -- =========== ; -- Query 1 SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col <= 5 ORDER BY E.key_col ASC ; -- Query 2 SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col > 95 ORDER BY E.key_col DESC ; -- Query 3 SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col >= 10 AND E.key_col < 15 ORDER BY E.key_col ASC ; -- Query 4 SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col >= 20 AND E.key_col < 25 ORDER BY E.key_col DESC ; -- Final query (singleton + range = 2 range scans) SELECT E.key_col FROM dbo.Example AS E WHERE E.key_col = 10 OR E.key_col BETWEEN 15 AND 20 ORDER BY E.key_col ASC ; -- === TIDY UP === DROP TABLE dbo.Example; © 2011 Paul White email: [email protected] twitter: @SQL_Kiwi

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  • Log shipping and shrinking transaction logs

    - by DavidWimbush
    I just solved a problem that had me worried for a bit. I'm log shipping from three primary servers to a single secondary server, and the transaction log disk on the secondary server was getting very full. I established that several primary databases had unused space that resulted from big, one-off updates so I could shrink their logs. But would this action be log shipped and applied to the secondary database too? I thought probably not. And, more importantly, would it break log shipping? My secondary databases are in a Standby / Read Only state so I didn't think I could shrink their logs. I RTFMd, Googled, and asked on a Q&A site (not the evil one) but was none the wiser. So I was facing a monumental round of shrink, full backup, full secondary restore and re-start log shipping (which would leave us without a disaster recovery facility for the duration). Then I thought it might be worthwhile to take a non-essential database and just make absolutely sure a log shrink on the primary wouldn't ship over and occur on the secondary as well. So I did a DBCC SHRINKFILE and kept an eye on the secondary. Bingo! Log shipping didn't blink and the log on the secondary shrank too. I just love it when something turns out even better than I dared to hope. (And I guess this highlights something I need to learn about what activities are logged.)

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  • Hello Operator, My Switch Is Bored

    - by Paul White
    This is a post for T-SQL Tuesday #43 hosted by my good friend Rob Farley. The topic this month is Plan Operators. I haven’t taken part in T-SQL Tuesday before, but I do like to write about execution plans, so this seemed like a good time to start. This post is in two parts. The first part is primarily an excuse to use a pretty bad play on words in the title of this blog post (if you’re too young to know what a telephone operator or a switchboard is, I hate you). The second part of the post looks at an invisible query plan operator (so to speak). 1. My Switch Is Bored Allow me to present the rare and interesting execution plan operator, Switch: Books Online has this to say about Switch: Following that description, I had a go at producing a Fast Forward Cursor plan that used the TOP operator, but had no luck. That may be due to my lack of skill with cursors, I’m not too sure. The only application of Switch in SQL Server 2012 that I am familiar with requires a local partitioned view: CREATE TABLE dbo.T1 (c1 int NOT NULL CHECK (c1 BETWEEN 00 AND 24)); CREATE TABLE dbo.T2 (c1 int NOT NULL CHECK (c1 BETWEEN 25 AND 49)); CREATE TABLE dbo.T3 (c1 int NOT NULL CHECK (c1 BETWEEN 50 AND 74)); CREATE TABLE dbo.T4 (c1 int NOT NULL CHECK (c1 BETWEEN 75 AND 99)); GO CREATE VIEW V1 AS SELECT c1 FROM dbo.T1 UNION ALL SELECT c1 FROM dbo.T2 UNION ALL SELECT c1 FROM dbo.T3 UNION ALL SELECT c1 FROM dbo.T4; Not only that, but it needs an updatable local partitioned view. We’ll need some primary keys to meet that requirement: ALTER TABLE dbo.T1 ADD CONSTRAINT PK_T1 PRIMARY KEY (c1);   ALTER TABLE dbo.T2 ADD CONSTRAINT PK_T2 PRIMARY KEY (c1);   ALTER TABLE dbo.T3 ADD CONSTRAINT PK_T3 PRIMARY KEY (c1);   ALTER TABLE dbo.T4 ADD CONSTRAINT PK_T4 PRIMARY KEY (c1); We also need an INSERT statement that references the view. Even more specifically, to see a Switch operator, we need to perform a single-row insert (multi-row inserts use a different plan shape): INSERT dbo.V1 (c1) VALUES (1); And now…the execution plan: The Constant Scan manufactures a single row with no columns. The Compute Scalar works out which partition of the view the new value should go in. The Assert checks that the computed partition number is not null (if it is, an error is returned). The Nested Loops Join executes exactly once, with the partition id as an outer reference (correlated parameter). The Switch operator checks the value of the parameter and executes the corresponding input only. If the partition id is 0, the uppermost Clustered Index Insert is executed, adding a row to table T1. If the partition id is 1, the next lower Clustered Index Insert is executed, adding a row to table T2…and so on. In case you were wondering, here’s a query and execution plan for a multi-row insert to the view: INSERT dbo.V1 (c1) VALUES (1), (2); Yuck! An Eager Table Spool and four Filters! I prefer the Switch plan. My guess is that almost all the old strategies that used a Switch operator have been replaced over time, using things like a regular Concatenation Union All combined with Start-Up Filters on its inputs. Other new (relative to the Switch operator) features like table partitioning have specific execution plan support that doesn’t need the Switch operator either. This feels like a bit of a shame, but perhaps it is just nostalgia on my part, it’s hard to know. Please do let me know if you encounter a query that can still use the Switch operator in 2012 – it must be very bored if this is the only possible modern usage! 2. Invisible Plan Operators The second part of this post uses an example based on a question Dave Ballantyne asked using the SQL Sentry Plan Explorer plan upload facility. If you haven’t tried that yet, make sure you’re on the latest version of the (free) Plan Explorer software, and then click the Post to SQLPerformance.com button. That will create a site question with the query plan attached (which can be anonymized if the plan contains sensitive information). Aaron Bertrand and I keep a close eye on questions there, so if you have ever wanted to ask a query plan question of either of us, that’s a good way to do it. The problem The issue I want to talk about revolves around a query issued against a calendar table. The script below creates a simplified version and adds 100 years of per-day information to it: USE tempdb; GO CREATE TABLE dbo.Calendar ( dt date NOT NULL, isWeekday bit NOT NULL, theYear smallint NOT NULL,   CONSTRAINT PK__dbo_Calendar_dt PRIMARY KEY CLUSTERED (dt) ); GO -- Monday is the first day of the week for me SET DATEFIRST 1;   -- Add 100 years of data INSERT dbo.Calendar WITH (TABLOCKX) (dt, isWeekday, theYear) SELECT CA.dt, isWeekday = CASE WHEN DATEPART(WEEKDAY, CA.dt) IN (6, 7) THEN 0 ELSE 1 END, theYear = YEAR(CA.dt) FROM Sandpit.dbo.Numbers AS N CROSS APPLY ( VALUES (DATEADD(DAY, N.n - 1, CONVERT(date, '01 Jan 2000', 113))) ) AS CA (dt) WHERE N.n BETWEEN 1 AND 36525; The following query counts the number of weekend days in 2013: SELECT Days = COUNT_BIG(*) FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; It returns the correct result (104) using the following execution plan: The query optimizer has managed to estimate the number of rows returned from the table exactly, based purely on the default statistics created separately on the two columns referenced in the query’s WHERE clause. (Well, almost exactly, the unrounded estimate is 104.289 rows.) There is already an invisible operator in this query plan – a Filter operator used to apply the WHERE clause predicates. We can see it by re-running the query with the enormously useful (but undocumented) trace flag 9130 enabled: Now we can see the full picture. The whole table is scanned, returning all 36,525 rows, before the Filter narrows that down to just the 104 we want. Without the trace flag, the Filter is incorporated in the Clustered Index Scan as a residual predicate. It is a little bit more efficient than using a separate operator, but residual predicates are still something you will want to avoid where possible. The estimates are still spot on though: Anyway, looking to improve the performance of this query, Dave added the following filtered index to the Calendar table: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear) WHERE isWeekday = 0; The original query now produces a much more efficient plan: Unfortunately, the estimated number of rows produced by the seek is now wrong (365 instead of 104): What’s going on? The estimate was spot on before we added the index! Explanation You might want to grab a coffee for this bit. Using another trace flag or two (8606 and 8612) we can see that the cardinality estimates were exactly right initially: The highlighted information shows the initial cardinality estimates for the base table (36,525 rows), the result of applying the two relational selects in our WHERE clause (104 rows), and after performing the COUNT_BIG(*) group by aggregate (1 row). All of these are correct, but that was before cost-based optimization got involved :) Cost-based optimization When cost-based optimization starts up, the logical tree above is copied into a structure (the ‘memo’) that has one group per logical operation (roughly speaking). The logical read of the base table (LogOp_Get) ends up in group 7; the two predicates (LogOp_Select) end up in group 8 (with the details of the selections in subgroups 0-6). These two groups still have the correct cardinalities as trace flag 8608 output (initial memo contents) shows: During cost-based optimization, a rule called SelToIdxStrategy runs on group 8. It’s job is to match logical selections to indexable expressions (SARGs). It successfully matches the selections (theYear = 2013, is Weekday = 0) to the filtered index, and writes a new alternative into the memo structure. The new alternative is entered into group 8 as option 1 (option 0 was the original LogOp_Select): The new alternative is to do nothing (PhyOp_NOP = no operation), but to instead follow the new logical instructions listed below the NOP. The LogOp_GetIdx (full read of an index) goes into group 21, and the LogOp_SelectIdx (selection on an index) is placed in group 22, operating on the result of group 21. The definition of the comparison ‘the Year = 2013’ (ScaOp_Comp downwards) was already present in the memo starting at group 2, so no new memo groups are created for that. New Cardinality Estimates The new memo groups require two new cardinality estimates to be derived. First, LogOp_Idx (full read of the index) gets a predicted cardinality of 10,436. This number comes from the filtered index statistics: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH STAT_HEADER; The second new cardinality derivation is for the LogOp_SelectIdx applying the predicate (theYear = 2013). To get a number for this, the cardinality estimator uses statistics for the column ‘theYear’, producing an estimate of 365 rows (there are 365 days in 2013!): DBCC SHOW_STATISTICS (Calendar, theYear) WITH HISTOGRAM; This is where the mistake happens. Cardinality estimation should have used the filtered index statistics here, to get an estimate of 104 rows: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH HISTOGRAM; Unfortunately, the logic has lost sight of the link between the read of the filtered index (LogOp_GetIdx) in group 22, and the selection on that index (LogOp_SelectIdx) that it is deriving a cardinality estimate for, in group 21. The correct cardinality estimate (104 rows) is still present in the memo, attached to group 8, but that group now has a PhyOp_NOP implementation. Skipping over the rest of cost-based optimization (in a belated attempt at brevity) we can see the optimizer’s final output using trace flag 8607: This output shows the (incorrect, but understandable) 365 row estimate for the index range operation, and the correct 104 estimate still attached to its PhyOp_NOP. This tree still has to go through a few post-optimizer rewrites and ‘copy out’ from the memo structure into a tree suitable for the execution engine. One step in this process removes PhyOp_NOP, discarding its 104-row cardinality estimate as it does so. To finish this section on a more positive note, consider what happens if we add an OVER clause to the query aggregate. This isn’t intended to be a ‘fix’ of any sort, I just want to show you that the 104 estimate can survive and be used if later cardinality estimation needs it: SELECT Days = COUNT_BIG(*) OVER () FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; The estimated execution plan is: Note the 365 estimate at the Index Seek, but the 104 lives again at the Segment! We can imagine the lost predicate ‘isWeekday = 0’ as sitting between the seek and the segment in an invisible Filter operator that drops the estimate from 365 to 104. Even though the NOP group is removed after optimization (so we don’t see it in the execution plan) bear in mind that all cost-based choices were made with the 104-row memo group present, so although things look a bit odd, it shouldn’t affect the optimizer’s plan selection. I should also mention that we can work around the estimation issue by including the index’s filtering columns in the index key: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear, isWeekday) WHERE isWeekday = 0 WITH (DROP_EXISTING = ON); There are some downsides to doing this, including that changes to the isWeekday column may now require Halloween Protection, but that is unlikely to be a big problem for a static calendar table ;)  With the updated index in place, the original query produces an execution plan with the correct cardinality estimation showing at the Index Seek: That’s all for today, remember to let me know about any Switch plans you come across on a modern instance of SQL Server! Finally, here are some other posts of mine that cover other plan operators: Segment and Sequence Project Common Subexpression Spools Why Plan Operators Run Backwards Row Goals and the Top Operator Hash Match Flow Distinct Top N Sort Index Spools and Page Splits Singleton and Range Seeks Bitmaps Hash Join Performance Compute Scalar © 2013 Paul White – All Rights Reserved Twitter: @SQL_Kiwi

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