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  • How do I connect to a remote desktop connection to access files but not graphically

    - by user26453
    Is there any way to connect to a remote Windows server via RDP but not graphically? What options do I have simply to connect to a remote Windows machine and access my files, but not have to do it via a graphic interface. i.e. is there an equivalent of SSH or SCP (file access is really what I'm looking to do) for Windows? I will add the caveat that I do not manage the machine, so installing any services would probably not be kosher, although I do have administrator access to the machine.

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  • Configuring a Genius GW-7200 Access Point

    - by alex
    I came across an access point we had a few years ago. I'm now trying to get it set up to work on our network. here are a couple of pictures: http://twitpic.com/194u06/full http://twitpic.com/194u0v/full I have plugged this into our network via the network port on the back. I set up a DHCP reservation, based on the MAC address on the back of the access point, however I cannot ping it, nor access the web interface. I've held down the reset button for 10 seconds, to see if that would do anything. Google doesn't come up with anything on the matter :-(

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  • Multiple domains, Exchange 2010, mailbox access via OWA

    - by Rob
    We currently run two separate domains where our new implementation of exchange 2010 is currently on a separate domain the users. My problem is: [email protected] cant access his mailbox at joe@domainb via OWA even though full access and sendas has been granted on domainb's mailbox to domaina's account. I keep receiving the error: Access is denied. The Active Directory resource couldn't be accessed. This may be because the Active Directory object doesn't exist or the object has become corrupted, or because you don't have the correct permissions. anyone able to help please? Take care

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  • Windows Server 2012 Essentials - Trying to setup "Anywhere Access" but the "Computer Access" list for users is blank

    - by tetranz
    I have a new installation of Windows Server 2012 Essentials and I'm trying to setup "Anywhere Access" for both VPN and remote desktop. The basic setup is all working. Shared folders is working but remote desktop has no computers available. On the server, if I edit a user with the Essentials Dashboard and go to "Computer access", the list is empty. The desktop computers have been joined to the domain. I can see them in AD under "Computers". I think our mistake was that we didn't use the connector tool to join the domain. We moved from a previous domain and went to Computer / Properties, changed the domain and started with a new profile. Is there something I can do now to make these desktops available for remote desktop? I can access a desktop directly no problem by going directly to it with the RDP client on port 3389. I do that from the outside world through an SSH tunnel.

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  • How to use Ralink RT2501/RT2573 as wifi access point in Debian Linux

    - by user60813
    Hi, I have a fit-PC server with Debian GNU/Linux (Lenny). I would like to use it as a wifi access point since my Linksys WRT54GS has become unstable. I have a USB Ralink wifi NIC. When I insert the card to USB I can see this with lsusb: Bus 001 Device 002: ID 148f:2573 Ralink Technology, Corp. RT2501/RT2573 Wireless Adapter I have tried following various HOWTOs on using wifi card as AP in Linux, however, it seems that the card cannot go into monitor mode. I believe this is because I must use a newer driver or upload non-free firmware or something like that. I have tried installed wicd, but it does not help. I bought this wifi adapter because I was told that it is one of the most common used Linux supported wifi cards that can be used as access point and a lot of other stuff. So my question is: How do I set up this USB wifi card as wireless access point in Debian Lenny?

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  • Can't find a wireless access point's IP address after changing router IP/LAN settings

    - by flagg19
    I have a modem/router, Netgear DG834, and a wireless access point (AP), Netgear WG602. The AP is directly connected to the router. My old working configuration was: Router IP address : 192.168.0.1 Access point IP address: 192.168.0.10 My new configuration is: Router IP address : 192.168.1.1 Access point IP address: ???.???.???.??? I changed my router's IP address/LAN settings to set up a VPN with another Netgear router that had the same LAN configuration. The wireless network is still up and perfectly working, but I can't find the AP's IP address. I've tried broadcast ping but the AP won't respond. I looked at the router "attached devices", but it's not there. I've played around with Nmap and arp request but the AP is totally invisible. I can fix it by resetting it to factory settings, but I'm very interested in learning more about this problem. I'm also interested in network security and this fact of having an invisible AP well, it's something I'd like to understand.

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  • Unrecognized file format .mdb in Microsoft Access -- repair doesn't fix it

    - by user1282159
    So what I have is a file from a staff computer that I believe is an access file b/c its called .mdb, however it does not open! I even tried to follow the repair steps (create a new file and use the "compact and repair" tool. and all I keep getting is "unrecognized file format *.mdb" (replace the * with the filename). I am not even sure it is an access file. I have tried using Office 2007 and office 2010 but neither work. Is there a way to fix this that is not on the Microsoft website? Or to determine whether this is actually an access file and not some other file with the extension renamed? Any help would be appricated, thanks.

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  • VPN provider for remote access to servers from a known IP address

    - by brentkeller
    My organization has a few servers that are being hosted by a provider and we limit remote access to a whitelist and deny access to any IPs not on the whitelist. We would like to find a hosted VPN service that we can connect to that would give us a known IP that we could add to our whitelist and gain access to the servers while on the road. Does anyone know of any such services? I don't think we can just setup the VPN built in to Windows Server since the servers are hosted. Any suggestions would be appreciated.

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  • Apache deny access to images folder, but still able to display via <img> on site

    - by jeffery_the_wind
    I have an images folder on my site, let's call it /images/ where I keep a lot of images. I don't want anyone to have direct access to the images via the web, so I put a new directive in my Apache config that achieves this: <Directory "/var/www/images/"> Options Includes AllowOverride All Order allow,deny Deny from All </Directory> This is working, but it is blocking out ALL ACCESS, and I can't show the images anymore through my web pages. I guess this makes sense. So how do I selectively control access to these images? Basically I only want to display certain images through certain webpages and to certain users. What is best way to do this? Do I need to save the images to the database? Tim

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  • Access Control issue

    - by user160605
    Ok this is stumping me mainly because of the lack of experience I have with access control. I have two folders I need to keep away from users. Payroll and Banking. I went into security and took away all the users. I made a new group called access granted and added it to both folders. I then gave full control to the group. I then added a few days to this group. I tested with partial success. I can only get into some folders and subfolders/files. I made sure I clicked on the option for all subfolders. This is my layout C:(folder) -- permissions granted to admin,access (full control) when I look at the problem files/folders no one has any permissions I don't even see the group or admin. what am I doing wrong. Thanks

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  • SSH into Ubuntu Linux on a box without a static IP address

    - by Steven Xu
    Basically, how do I do it? I'd like to connect to my home computer from work, but my internet is routed through my apartment building's network, so I don't have the static IP address I'm accustomed to having. How do I go about accessing my home computer through SSH (I'll be using Putty at work if it matters) if my home computer doesn't have a static IP address?

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  • Give Access to a Subdirectory Without Giving Access to Parent Directories

    - by allquixotic
    I have a scenario involving a Windows file server where the "owner" wants to dole out permissions to a group of users of the following sort: \\server\dir1\dir2\dir3: Read & Execute and Write \\server\dir1\dir2: No permissions. \\server\dir1: No permissions. \\server: Read & Execute To my understanding, it is not possible to do this because Read & Execute permission must be granted to all the parent directories in a directory chain in order for the operating system to be able to "see" the child directories and get to them. Without this permission, you can't even obtain the security context token when trying to access the nested directory, even if you have full access to the subdirectory. We are looking for ways to get around this, without moving the data from \\server\dir1\dir2\dir3 to \\server\dir4. One workaround I thought of, but which I am not sure if it will work, is creating some sort of link or junction \\server\dir4 which is a reference to \\server\dir1\dir2\dir3. I am not sure which of the available options (if any) would work for this purpose if the user does not have Read & Execute permission on \\server\dir1\dir2 or \\server\dir1, but as far as I know, the options are these: NTFS Symbolic Link, Junction, Hard Link. So the questions: Are any of these methods suitable to accomplish my goal? Are there any other methods of linking or indirectly referencing a directory, which I haven't listed above, which might be suitable? Are there any direct solutions that don't involve granting Read & Execute to \\server\dir1 or \\server\dir2 but still allowing access to \\server\dir1\dir2\dir3?

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  • Using Excel as front end to Access database (with VBA)

    - by Alex
    I am building a small application for a friend and they'd like to be able to use Excel as the front end. (the UI will basically be userforms in Excel). They have a bunch of data in Excel that they would like to be able to query but I do not want to use excel as a database as I don't think it is fit for that purpose and am considering using Access. [BTW, I know Access has its shortcomings but there is zero budget available and Access already on friend's PC] To summarise, I am considering dumping a bunch of data into Access and then using Excel as a front end to query the database and display results in a userform style environment. Questions: How easy is it to link to Access from Excel using ADO / DAO? Is it quite limited in terms of functionality or can I get creative? Do I pay a performance penalty (vs.using forms in Access as the UI)? Assuming that the database will always be updated using ADO / DAO commands from within Excel VBA, does that mean I can have multiple Excel users using that one single Access database and not run into any concurrency issues etc.? Any other things I should be aware of? I have strong Excel VBA skills and think I can overcome Access VBA quite quickly but never really done Excel / Access link before. I could shoehorn the data into Excel and use as a quasi-database but that just seems more pain than it is worth (and not a robust long term solution) Any advice appreciated. Alex

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  • MS Access: Permission problems with views

    - by Keith Williams
    "I'll use an Access ADP" I said, "it's only a tiny project and I've got better things to do", I said, "I can build an interface really quickly in Access" I said. </sarcasm> Sorry for the rant, but it's Friday, I have a date in just under two hours, and I'm here late because this just isn't working - so, in despair, I turn to SO for help. Access ADP front-end, linked to a SQL Server 2008 database Using a SQL Server account to log into the database (for testing); this account is a member of the role, "Api"; this role has SELECT, EXECUTE, INSERT, UPDATE, DELETE access to the "Api" schema The "Api" schema is owned by "dbo" All tables have a corresponding view in the Api schema: e.g. dbo.Customer -- Api.Customers The rationale is that users don't have direct table access, but can deal with views as if they were tables I can log into SQL using my test login, and it works fine: no access to the tables, but I can select, insert, update and delete from the Api views. In Access, I see the views, I can open them, but whenever I try to insert or update, I get the following error: The SELECT permission was denied on the object '[Table name which the view is using]', database '[database name]', schema 'dbo' Crazy as it sounds, Access seems to be trying to access the underlying table rather than the view. Any ideas?

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  • Creating an Objective-C++ Static Library in Xcode

    - by helixed
    So I've developed an engine for the iPhone with which I'd like to build a couple different games. Rather than copy and paste the files for the engine inside of each game's project directory, I'd a way to link to the engine from each game, so if I need to make a change to it I only have to do so once. After reeding around a little bit, it seems like static libraries are the best way to do this on the iPhone. I created a new project called Skeleton and copied all of my engine files over to it. I used this guide to create a static library, and I imported the library into a project called Chooser. However, when I tried to compile the project, Xcode started complaining about some C++ data structures I included in a file called ControlScene.mm. Here's my build errors: "operator delete(void*)", referenced from: -[ControlScene dealloc] in libSkeleton.a(ControlScene.o) -[ControlScene init] in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::deallocate(operation_t*, unsigned long)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t*>::deallocate(operation_t**, unsigned long)in libSkeleton.a(ControlScene.o) "operator new(unsigned long)", referenced from: -[ControlScene init] in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t*>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) "std::__throw_bad_alloc()", referenced from: __gnu_cxx::new_allocator<operation_t*>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) __gnu_cxx::new_allocator<operation_t>::allocate(unsigned long, void const*)in libSkeleton.a(ControlScene.o) "___cxa_rethrow", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) "___cxa_end_catch", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) "___gxx_personality_v0", referenced from: ___gxx_personality_v0$non_lazy_ptr in libSkeleton.a(ControlScene.o) ___gxx_personality_v0$non_lazy_ptr in libSkeleton.a(MenuLayer.o) "___cxa_begin_catch", referenced from: std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_create_nodes(operation_t**, operation_t**)in libSkeleton.a(ControlScene.o) std::_Deque_base<operation_t, std::allocator<operation_t> >::_M_initialize_map(unsigned long)in libSkeleton.a(ControlScene.o) ld: symbol(s) not found collect2: ld returned 1 exit status If anybody could offer some insight as to why these problems are occuring, I'd appreciate it. Thanks, helixed

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  • iOS static Framework crash when animating view

    - by user1439216
    I'm encountering a difficult to debug issue with a static library project when attempting to animate a view. It works fine when debugging (and even when debugging in the release configuration), but throws an error archived as a release: Exception Type: EXC_CRASH (SIGSYS) Exception Codes: 0x00000000, 0x00000000 Crashed Thread: 0 Thread 0 name: Dispatch queue: com.apple.main-thread Thread 0 Crashed: 0 TestApp 0x000d04fc 0x91000 + 259324 1 UIKit 0x336d777e +[UIView(UIViewAnimationWithBlocks) animateWithDuration:animations:] + 42 2 TestApp 0x000d04de 0x91000 + 259294 3 TestApp 0x000d0678 0x91000 + 259704 4 Foundation 0x355f04f8 __57-[NSNotificationCenter addObserver:selector:name:object:]_block_invoke_0 + 12 5 CoreFoundation 0x35aae540 ___CFXNotificationPost_block_invoke_0 + 64 6 CoreFoundation 0x35a3a090 _CFXNotificationPost + 1400 7 Foundation 0x355643e4 -[NSNotificationCenter postNotificationName:object:userInfo:] + 60 8 UIKit 0x33599112 -[UIInputViewTransition postNotificationsForTransitionStart] + 846 9 UIKit 0x335988cc -[UIPeripheralHost(UIKitInternal) executeTransition:] + 880 10 UIKit 0x3351bb8c -[UIPeripheralHost(UIKitInternal) setInputViews:animationStyle:] + 304 11 UIKit 0x3351b260 -[UIPeripheralHost(UIKitInternal) _reloadInputViewsForResponder:] + 952 12 UIKit 0x3351ae54 -[UIResponder(UIResponderInputViewAdditions) reloadInputViews] + 160 13 UIKit 0x3351a990 -[UIResponder becomeFirstResponder] + 452 14 UIKit 0x336194a0 -[UITextInteractionAssistant setFirstResponderIfNecessary] + 168 15 UIKit 0x33618d6a -[UITextInteractionAssistant oneFingerTap:] + 1602 16 UIKit 0x33618630 _UIGestureRecognizerSendActions + 100 17 UIKit 0x335a8d5e -[UIGestureRecognizer _updateGestureWithEvent:] + 298 18 UIKit 0x337d9472 ___UIGestureRecognizerUpdate_block_invoke_0541 + 42 19 UIKit 0x33524f4e _UIGestureRecognizerApplyBlocksToArray + 170 20 UIKit 0x33523a9c _UIGestureRecognizerUpdate + 892 21 UIKit 0x335307e2 _UIGestureRecognizerUpdateGesturesFromSendEvent + 22 22 UIKit 0x33530620 -[UIWindow _sendGesturesForEvent:] + 768 23 UIKit 0x335301ee -[UIWindow sendEvent:] + 82 24 UIKit 0x3351668e -[UIApplication sendEvent:] + 350 25 UIKit 0x33515f34 _UIApplicationHandleEvent + 5820 26 GraphicsServices 0x376d5224 PurpleEventCallback + 876 27 CoreFoundation 0x35ab651c __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE1_PERFORM_FUNCTION__ + 32 28 CoreFoundation 0x35ab64be __CFRunLoopDoSource1 + 134 29 CoreFoundation 0x35ab530c __CFRunLoopRun + 1364 30 CoreFoundation 0x35a3849e CFRunLoopRunSpecific + 294 31 CoreFoundation 0x35a38366 CFRunLoopRunInMode + 98 32 GraphicsServices 0x376d4432 GSEventRunModal + 130 33 UIKit 0x33544cce UIApplicationMain + 1074 Thread 0 crashed with ARM Thread State: r0: 0x0000004e r1: 0x000d04f8 r2: 0x338fed47 r3: 0x3f523340 r4: 0x00000000 r5: 0x2fe8da00 r6: 0x00000001 r7: 0x2fe8d9d0 r8: 0x3f54cad0 r9: 0x00000000 r10: 0x3fd00000 r11: 0x3f523310 ip: 0x3f497048 sp: 0x2fe8d988 lr: 0x33539a41 pc: 0x000d04fc cpsr: 0x60000010 To give some background info: The static library is part of an 'iOS fake-framework', built using the templates from here: https://github.com/kstenerud/iOS-Universal-Framework The framework presents a registration UI as a modal view on top of whatever the client application is doing at the time. It pushes these views using a handle to a UIViewController provided by the client application. It doesn't do anything special, but here's the animation code: -(void)keyboardWillShowNotification:(NSNotification *)notification { double animationDuration = [[[notification userInfo] objectForKey:UIKeyboardAnimationDurationUserInfoKey] doubleValue]; dispatch_async(dispatch_get_main_queue(), ^(void) { [self animateViewsToState:kUMAnimationStateKeyboardVisible forIdiom:[UIDevice currentDevice].userInterfaceIdiom forDuration:animationDuration]; }); } -(void)animateViewsToState:(kUMAnimationState)state forIdiom:(UIUserInterfaceIdiom)idiom forDuration:(double)duration { float fieldOffset; if (idiom == UIUserInterfaceIdiomPhone) { if (state == kUMAnimationStateKeyboardVisible) { fieldOffset = -KEYBOARD_HEIGHT_IPHONE_PORTRAIT; } else { fieldOffset = KEYBOARD_HEIGHT_IPHONE_PORTRAIT; } } else { if (state == kUMAnimationStateKeyboardVisible) { fieldOffset = -IPAD_FIELD_OFFSET; } else { fieldOffset = IPAD_FIELD_OFFSET; } } [UIView animateWithDuration:duration animations:^(void) { mUserNameField.frame = CGRectOffset(mUserNameField.frame, 0, fieldOffset); mUserPasswordField.frame = CGRectOffset(mUserPasswordField.frame, 0, fieldOffset); }]; } Further printf-style debugging shows that it crashes whenever I do anything much with UIKit - specifically, it crashes when I replace -animateViewsToState with: if (0 == UIUserInterfaceIdiomPhone) { NSLog(@""); } and [[[[UIAlertView alloc] initWithTitle:@"test" message:@"123" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] autorelease] show]; To me, this sounds like a linker problem, but I don't understand how such problems would only manifest here, and not beforehand. Any help would be greatly appreciated.

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  • Clang Static Analyzer for xcode for dummies

    - by dubbeat
    Hi, Could somebody please help me get Clang up and running? (I don't have 3.2) I've followed numerous tutorials (basically every link off of this page http://stackoverflow.com/questions/961844/using-clang-static-analyzer-from-within-xcode) but I just cant get it to work! The only thing I've managed to do successfully so far is download clang! Grrrr .... dubbeat smash! Bear in mind I've never written an apple script before. I have clang on my desktop

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  • Static code analysis for VB6 and classic ASP

    - by Ryan
    I'm looking for a static code analysis tool that will determine if I have orphaned functions in my VB6 code. The problem I'm running into is we make calls to the VB6 code from classic asp. Is there a tool that will look at both the classic asp and VB6 and determine if there are any orphaned functions?

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  • How do I call a static bool method in main.m

    - by AaronG
    This is Objective-C, in Xcode for the iPhone. I have a method in main.m: int main(int argc, char *argv[]) { NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; //I want to call the method here// int retVal = UIApplicationMain(argc, argv, nil, nil); [pool release]; return retVal; } static BOOL do_it_all () { //code here// } How do I call the do_it_all method from main.m?

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  • Howto compile a static library in linux

    - by Summer_More_More_Tea
    Hi folks: I have a question: How to compile a static library in linux with gcc, i.e. I need to compile my source code into a file named out.a. Is it sufficient to simply compile with the command gcc -o out.a out.c? I'm not quite familiar with gcc, hope anyone can give me a hand. Thanks Regards.

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