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  • utf8 format in xml

    - by hussain
    i want to know how to store this è (this type of symbols) in xml file if i store this symbol in xml file.. the file shows this symbol like ? i was inserted in front of xml file is <?xml version="1.0" encoding="UTF-8"?> but that doest not shows correct thanks and advance

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  • Parsing xml with jQuery in IE6/7 issue

    - by Alexander Corotchi
    Hi, I have some problem with parsing XML in Ie6/7(original 7 no compatible mode). On Another normal browsers it works. Jquery code: $.ajax({ type: "GET", url: "test.xml", dataType: "html", success: function(xml) { $(xml).find('quoteresult').each(function(){ var bid = $(this).find('bid').text(); alert(bid); }); } }); I can't understand what is wrong ! Thanks

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  • passing data to and from server using xml

    - by sapna
    i need to design a web site in which data is passed to and from the server using xml.i got it how to transform data from database to xml and then to html.but i am not able to find how to pass data from client to server using xml.webpages are designed using asp.is it possible to do pass data from client to server using xml.what are the things that are to be studied.help needed immediately.

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  • XSLT 2.0 Header Leaks into Transformed XML

    - by user1303797
    First, a thank you in advance. Second, this is my first post so apologies for any errors or wrongdoings. I am a noob w/ xml and xslt, and can't seem to figure this out. When I transform some xml using xslt 2.0, some of the headers from the xslt leaks into the new xml. It doesn't seem to do it in xslt 1.0 (granted the xslt is a little different). Here is the xml: <?xml version="1.0" encoding="ISO-8859-1" ?> <xml_content> <feed_name>feed</feed_name> <feed_info> <entry_1> <id>1</id> <pub_date>1320814800</pub_date> </entry_1> </feed_info> </xml_content> Here is the xslt: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/TR/xhtml1/strict"> <xsl:output method="xml" indent="yes" /> <xsl:template match="xml_content"> <Records> <xsl:for-each select="feed_info/entry_1"> <Record> <ID><xsl:value-of select="id" /></ID> <PublicationDate><xsl:value-of select='xs:dateTime("1970-01-01T00:00:00") + xs:integer(pub_date) * xs:dayTimeDuration("PT1S")'/></PublicationDate> </Record> </xsl:for-each> </Records> </xsl:template> </xsl:stylesheet> Here is the new xml. Look specifically at the first "Records" element. <?xml version="1.0" encoding="UTF-8"?> <Records xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/TR/xhtml1/strict"> <Record> <ID>1</ID> <PublicationDate>2011-11-09T05:00:00</PublicationDate> </Record> </Records>

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  • SQL Server 2008 2mb Limit for XML??

    - by Nai
    I am trying to output a long XML result from SMSS. When I right click on the results and 'save results as...', I can only get a 2mb file? I have changed the settings in SMSS via Tools - Options - Query Results - SQL Server - Results to Grid, for XML data to be unlimited. Forever, it still seems to be truncating my XML results? So, how can I bypass this problem and output my XML result to a file? Thanks

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  • Url rewriting : prevent to display xml

    - by Frank
    Edit : I've got an aspx file (default.aspx) that loads a flash file (index.swf), but this swf needs a xml file (foo.xml) to load correctly. However, I would like to block any request aiming directly at the xml file. Is it possible, using a rewritting engine (isapi_rewrite for example) to detect if the xml file is being 'hotlinked' or being loaded by the 'index.swf'(inside default.aspx)? Any ideas? Thank you.

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  • What is the best way to modify a few fields in an XML using Java

    - by Kailas J C
    I have a big XML which contains around 300 elements. I need to modify 2 or 3 elements in this xml using Java. I don't want to go for conventional marshalling and unmarshalling as it involves the parsing of the whole XML. How is XPath/XSLT manipulation? I know that I can easily read the data but i need to modify the same and put in back in the same XML. The primary concern here is performance. Kindly advise

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  • Reading embedded XML file c#

    - by Pila
    How can I read from an embedded XML file - an XML file that is part of a c# project? I've added a XML file to my project and I want to read from it. I want the XML file to compile with the project because I don't want that it will be a resource which the user can see. Any idea?

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  • Xml files stop being served by IIS6 after allowing .net to process the .xml extension

    - by Brian Surowiec
    I added a route into my site to allow for a sitemap and everything worked fine in IIS7 but once I deployed the route stopped working. Since the live server is running IIS6 I needed to put a new mapping in for .xml to be processed by .net and then it started to work. My issue though is on every other xml file on the site now. I keep getting a 404 error when trying to view xml files, but the sitemap.xml route works. Is this a routing issue or an IIS setup issue? Here are my routes if it will help routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Gallery-Group-View", "Projects/{groupId}", new { controller = "Gallery", action = "GalleryList", groupId = "" }); routes.MapRoute( "Gallery-List-View", "Projects/{groupId}/{galleryId}", new { controller = "Gallery", action = "GalleryView", groupId = "", galleryId = "" }); routes.MapRoute( "Sitemap", "Sitemap.xml", new { controller = "XML", action = "Sitemap" } ); routes.MapRoute( "Default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" } );

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  • Storing a big xml string in a xml document in java

    - by shyam R
    Hi All, I Have a Java object which I am converting into a xml file. I am getting a big xml file here after converting java object. I am capturing that converted xml file in a string like below String ouputXML = xmlfile; Noe If I pring the ouputXML on the console of IBM RSA in the proper format only it is printing but my requirement is I need to redirect outputXML in to an XML instead of printing in IBm RSA console. I am able to do this but the problem is if I open the craetd XML file the xml structure is not proper , it is showing so many special characters . Please help me !!

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  • Why does JAXB not create a member variable in its generated code when an XML schema base type and subtype have the same element declared in them?

    - by belltower
    I have a question regarding with regard to JAXB generated classes. As you can I see, I have a complex type, DG_PaymentIdentification1, declared in my schema. Its a restriction of PaymentIdentification1. DG_PaymentIdentification1 is also identical to PaymentIdentification1. I also have a type called DG_CreditTransferTransactionInformation10 which has a base type of CreditTransferTransactionInformation10 and is identical to it. I have included the relevant XML schema snippets below. <xs:complexType name="DG_PaymentIdentification1"> <xs:complexContent> <xs:restriction base="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="DG_Max35Text_REF" minOccurs="0"/> <xs:element name="EndToEndId" type="DG_Max35Text_REF" id="DG-41"/> </xs:sequence> </xs:restriction> </xs:complexContent> </xs:complexType> <xs:complexType name="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="Max35Text" minOccurs="0"/> <xs:element name="EndToEndId" type="Max35Text"/> </xs:sequence> </xs:complexType> <xs:complexType name="DG_CreditTransferTransactionInformation10"> <xs:complexContent> <xs:restriction base="CreditTransferTransactionInformation10"> <xs:sequence> <xs:element name="PmtId" type="DG_PaymentIdentification1"/> <xs:simpleType name="DG_Max35Text_REF"> <xs:restriction base="DG_NotEmpty35"> <xs:pattern value="[\-A-Za-z0-9\+/\?:\(\)\.,'&#x20;]*"/> </xs:restriction> </xs:simpleType> <xs:simpleType name="Max35Text"> <xs:restriction base="xs:string"> <xs:minLength value="1"/> <xs:maxLength value="35"/> </xs:restriction> </xs:simpleType> JAXB generates the following java class for DG_PaymentIdentification1: @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "DG_CreditTransferTransactionInformDGion10") public class DGCreditTransferTransactionInformation10 extends CreditTransferTransactionInformation10 { } My question is why doesnt the DGCreditTransferTransactionInformation10 generated class have a variable of type DG_PaymentIdentification1 in the generated code? The base class CreditTransferTransactionInformation10 does have a type PaymentIdentification1 declared in it. Is there any way of ensuring that DGCreditTransferTransactionInformation10 will have a DG_PaymentIdentification1 in it?

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  • Writing xml with powershell

    - by alex
    i have a script that get all the info i need about my SharePoint farm : [System.Reflection.Assembly]::LoadWithPartialName("Microsoft.SharePoint") > $null $farm = [Microsoft.SharePoint.Administration.SPFarm]::Local $websvcs = $farm.Services | where -FilterScript {$_.GetType() -eq [Microsoft.SharePoint.Administration.SPWebService]} $webapps = @() foreach ($websvc in $websvcs) { write-output "Web Applications" write-output "" foreach ($webapp in $websvc.WebApplications) { write-output "Webapp Name -->"$webapp.Name write-output "" write-output "Site Collections" write-output "" foreach ($site in $webapp.Sites) { write-output "Site URL --> -->" $site.URL write-output "" write-output "Websites" write-output "" foreach ($web in $site.AllWebs) { write-output "Web URL --> --> -->" $web.URL write-output "" write-output "Lists" write-output "" foreach ($list in $web.Lists) { write-output "List Title --> --> --> -->" $list.Title write-output "" } foreach ($group in $web.Groups) { write-output "Group Name --> --> --> -->" $group.Name write-output "" foreach ($user in $group.Users) { write-output "User Name --> --> --> -->" $user.Name write-output "" } } } } } } i want to make the output to an XML file and then connect the xml file to HTML and make a site of it for manager use how can i do it ? thanks for the help !

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  • Mac - KeyRemap4MacBook - Custom XML

    - by DjRikyx
    I hope someone of you know this powerfull Pref Panel to remap the keyboard.. Since i'm using a PC Keyboard, i wanted to make Screenshot a bit easy to do.. I managed to get working: -Command+Shift+3 to Stamp (full screen screenshot) -Command+Shift+4 to Control+Stamp (Selection Cursor Screenshot) Now i want to remap Shift+Stamp to Command+Shift+4+Space to get Windows Screenshot.. i tried but nothing was working.. Here is my current XML.. i only need to add the last remap! <?xml version="1.0"?> <root> <item> <name>Custom PC Style Screenshot</name> <appendix>Command+Shift_L+4+Space to Shift+F13</appendix> <appendix>Command+Shift_L+4 to Control+F13</appendix> <appendix>Command+Shift_L+3 to F13</appendix> <identifier>private.custom_pc_style_screenshot</identifier> <autogen></autogen> <autogen>--KeyToKey-- KeyCode::F13, VK_CONTROL, KeyCode::KEY_4, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> <autogen>--KeyToKey-- KeyCode::F13, KeyCode::KEY_3, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> Hope someone of you can help me out! Thank you

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  • How could I embed formatted XML source in WORD documents?

    - by eckes
    I'm writing a documentation with WORD that contains XML source code (whole files) as examples. The way I'm embedding the currently XML is quite cumbersome and doesn't seem to me as really maintainable: I'm finishing the editing of the document in WORD and create a PDF from it using Acrobat next, I open my XML files (2x input files, 2x generated output files) with IE and print them with the PDF printer supplied by Acrobat now, I open up Acrobat Pro and attach the four XML-PDF files to my original document The problem with that work flow for me is that it involves too much manual labor in order to get the documentation done. What I've tried up to now is not really satisfying for me: converting each XML to PDF and appending them like described above opening the XML files with SCiTE, copy as RTF and paste into Word playing around with the LaTeX packages minted, pygments and listings (I could write the docs with LaTeX too) but found some unsolvable problems in each of these packages I'm searching for a way that produces my documentation more automatic. For example embedding the XML files including formatting of IE (which I find quite readable). The files should be included by reference so that I don't have to paste the XML sources manually every time the XML changes.

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  • "Content is not allowed in prolog" when parsing perfectly valid XML on GAE

    - by Adrian Petrescu
    Hey guys, I've been beating my head against this absolutely infuriating bug for the last 48 hours, so I thought I'd finally throw in the towel and try asking here before I throw my laptop out the window. I'm trying to parse the response XML from a call I made to AWS SimpleDB. The response is coming back on the wire just fine; for example, it may look like: <?xml version="1.0" encoding="utf-8"?> <ListDomainsResponse xmlns="http://sdb.amazonaws.com/doc/2009-04-15/"> <ListDomainsResult> <DomainName>Audio</DomainName> <DomainName>Course</DomainName> <DomainName>DocumentContents</DomainName> <DomainName>LectureSet</DomainName> <DomainName>MetaData</DomainName> <DomainName>Professors</DomainName> <DomainName>Tag</DomainName> </ListDomainsResult> <ResponseMetadata> <RequestId>42330b4a-e134-6aec-e62a-5869ac2b4575</RequestId> <BoxUsage>0.0000071759</BoxUsage> </ResponseMetadata> </ListDomainsResponse> I pass in this XML to a parser with XMLEventReader eventReader = xmlInputFactory.createXMLEventReader(response.getContent()); and call eventReader.nextEvent(); a bunch of times to get the data I want. Here's the bizarre part -- it works great inside the local server. The response comes in, I parse it, everyone's happy. The problem is that when I deploy the code to Google App Engine, the outgoing request still works, and the response XML seems 100% identical and correct to me, but the response fails to parse with the following exception: com.amazonaws.http.HttpClient handleResponse: Unable to unmarshall response (ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog.): <?xml version="1.0" encoding="utf-8"?> <ListDomainsResponse xmlns="http://sdb.amazonaws.com/doc/2009-04-15/"><ListDomainsResult><DomainName>Audio</DomainName><DomainName>Course</DomainName><DomainName>DocumentContents</DomainName><DomainName>LectureSet</DomainName><DomainName>MetaData</DomainName><DomainName>Professors</DomainName><DomainName>Tag</DomainName></ListDomainsResult><ResponseMetadata><RequestId>42330b4a-e134-6aec-e62a-5869ac2b4575</RequestId><BoxUsage>0.0000071759</BoxUsage></ResponseMetadata></ListDomainsResponse> javax.xml.stream.XMLStreamException: ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog. at com.sun.org.apache.xerces.internal.impl.XMLStreamReaderImpl.next(Unknown Source) at com.sun.xml.internal.stream.XMLEventReaderImpl.nextEvent(Unknown Source) at com.amazonaws.transform.StaxUnmarshallerContext.nextEvent(StaxUnmarshallerContext.java:153) ... (rest of lines omitted) I have double, triple, quadruple checked this XML for 'invisible characters' or non-UTF8 encoded characters, etc. I looked at it byte-by-byte in an array for byte-order-marks or something of that nature. Nothing; it passes every validation test I could throw at it. Even stranger, it happens if I use a Saxon-based parser as well -- but ONLY on GAE, it always works fine in my local environment. It makes it very hard to trace the code for problems when I can only run the debugger on an environment that works perfectly (I haven't found any good way to remotely debug on GAE). Nevertheless, using the primitive means I have, I've tried a million approaches including: XML with and without the prolog With and without newlines With and without the "encoding=" attribute in the prolog Both newline styles With and without the chunking information present in the HTTP stream And I've tried most of these in multiple combinations where it made sense they would interact -- nothing! I'm at my wit's end. Has anyone seen an issue like this before that can hopefully shed some light on it? Thanks!

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  • utf8 problem with Perl and XML::Parser

    - by René Nyffenegger
    I encountered a problem dealing with utf8, XML and Perl. The following is the smallest piece of code and data in order to reproduce the problem. Here's an XML file that needs to be parsed: <?xml version="1.0" encoding="utf-8"?> <test> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> [<words> .... </words> 148 times repeated] <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> </test> The parsing is done with this perl script: use warnings; use strict; use XML::Parser; use Data::Dump; my $in_words = 0; my $xml_parser=new XML::Parser(Style=>'Stream'); $xml_parser->setHandlers ( Start => \&start_element, End => \&end_element, Char => \&character_data, Default => \&default); open OUT, '>out.txt'; binmode (OUT, ":utf8"); open XML, 'xml_test.xml' or die; $xml_parser->parse(*XML); close XML; close OUT; sub start_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 1; } else { $in_words = 0; } } sub end_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 0; } } sub default { # nothing to see here; } sub character_data { my($parseinst, $data) = @_; if ($in_words) { if ($in_words) { print OUT "$data\n"; } } } When the script is run, it produces the out.txt file. The problem is in this file on line 147. The 22th character (which in utf-8 consists of \xd6 \xb8) is split between the d6 and b8 with a new line. This should not happen. Now, I am interested if someone else has this problem or can reproduce it. And why I am getting this problem. I am running this script on Windows: C:\temp>perl -v This is perl, v5.10.0 built for MSWin32-x86-multi-thread (with 5 registered patches, see perl -V for more detail) Copyright 1987-2007, Larry Wall Binary build 1003 [285500] provided by ActiveState http://www.ActiveState.com Built May 13 2008 16:52:49

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  • Parsing google feed with linq to xml

    - by the_V
    Hi I'm trying to parse XML feed that I get via Google Contacts API with LINQ 2 XML. That's what feed looks like: <feed xmlns="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:gContact="http://schemas.google.com/contact/2008" xmlns:batch="http://schemas.google.com/gdata/batch" xmlns:gd="http://schemas.google.com/g/2005"> <id>[email protected]</id> <updated>2010-06-11T17:37:06.561Z</updated> <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact" /> <title type="text">My Contacts</title> <link rel="alternate" type="text/html" href="http://www.google.com/" /> <link rel="http://schemas.google.com/g/2005#feed" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full" /> <link rel="http://schemas.google.com/g/2005#post" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full" /> <link rel="http://schemas.google.com/g/2005#batch" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full/batch" /> <link rel="self" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full?max-results=25" /> <author> <name>My NAme</name> <email>[email protected]</email> </author> <generator version="1.0" uri="http://www.google.com/m8/feeds">Contacts</generator> <openSearch:totalResults>19</openSearch:totalResults> <openSearch:startIndex>1</openSearch:startIndex> <openSearch:itemsPerPage>25</openSearch:itemsPerPage> <entry> <id>http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/base/0</id> <updated>2010-01-26T20:34:03.802Z</updated> <category scheme="http://schemas.google.com/g/2005#kind" term="http://schemas.google.com/contact/2008#contact" /> <title type="text">Contact name</title> <link rel="http://schemas.google.com/contacts/2008/rel#edit-photo" type="image/*" href="http://www.google.com/m8/feeds/photos/media/myemailaddress%40gmail.com/0/O-ydnzWMJcfZWqT-6gGetw" /> <link rel="http://schemas.google.com/contacts/2008/rel#photo" type="image/*" href="http://www.google.com/m8/feeds/photos/media/myemailaddress%40gmail.com/0" /> <link rel="self" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full/0" /> <link rel="edit" type="application/atom+xml" href="http://www.google.com/m8/feeds/contacts/myemailaddress%40gmail.com/full/0/1264538043802000" /> <gd:email rel="http://schemas.google.com/g/2005#other" address="[email protected]" primary="true" /> </entry> </feed> I've tried a number of things with linq 2 sql, but they didn't work. Even this simple code snipped doesn't work: using (FileStream stream = File.OpenRead("response.xml")) { XmlReader reader = XmlReader.Create(stream); XDocument doc = XDocument.Load(reader); XElement feed = doc.Element("feed"); if (feed == null) { Console.WriteLine("feed not found"); } XElement id = doc.Element("id"); if (id == null) { Console.WriteLine("id is null"); } } Problem is that both id and feed are null here. What wrong am I doing?

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  • Blackberry XML Parsing Application not working

    - by Nirmal
    Hello All... I found one sample application from the Blackberry knowledgebase. From that application I have put that sample application on my eclipse plugin, and the code is as follows : import javax.microedition.io.*; import net.rim.device.api.ui.*; import net.rim.device.api.ui.component.*; import net.rim.device.api.ui.container.*; import net.rim.device.api.system.*; import net.rim.device.api.xml.parsers.*; import org.w3c.dom.*; import org.xml.sax.*; class XML_Parsing_Sample extends UiApplication { // creating a member variable for the MainScreen MainScreen _screen = new MainScreen(); // string variables to store the values of the XML document String _node, _element; Connection _connectionthread; public static void main(String arg[]) { XML_Parsing_Sample application = new XML_Parsing_Sample(); // create a new instance of the application // and start the application on the event thread application.enterEventDispatcher(); } public XML_Parsing_Sample() { _screen.setTitle("XML Parsing");// setting title _screen.add(new RichTextField("Requesting.....")); _screen.add(new SeparatorField()); pushScreen(_screen); // creating a screen // creating a connection thread to run in the background _connectionthread = new Connection(); _connectionthread.start();// starting the thread operation } public void updateField(String node, String element) { // receiving the parsed node and its value from the thread // and updating it here // so it can be displayed on the screen String title = "My App"; _screen.add(new RichTextField(node + " : " + element)); if (node.equals(title)) { _screen.add(new SeparatorField()); } } private class Connection extends Thread { public Connection() { super(); } public void run() { // define variables later used for parsing Document doc; StreamConnection conn; try { // providing the location of the XML file, // your address might be different conn = (StreamConnection) Connector .open("http://www.sufalamtech.com/demo/moviewebservice/Test.xml"); // next few lines creates variables to open a // stream, parse it, collect XML data and // extract the data which is required. // In this case they are elements, // node and the values of an element DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory .newInstance(); DocumentBuilder docBuilder = docBuilderFactory .newDocumentBuilder(); docBuilder.isValidating(); doc = docBuilder.parse(conn.openInputStream()); doc.getDocumentElement().normalize(); NodeList list = doc.getElementsByTagName("*"); _node = new String(); _element = new String(); // this "for" loop is used to parse through the // XML document and extract all elements and their // value, so they can be displayed on the device for (int i = 0; i < list.getLength(); i++) { Node value = list.item(i).getChildNodes().item(0); _node = list.item(i).getNodeName(); _element = value.getNodeValue(); updateField(_node, _element); }// end for }// end try // will catch any exception thrown by the XML parser catch (Exception e) { Dialog.alert("exception = " + e); } }// end connection function }// end connection class }// end XML_Parsing_Sample But when I am running this application, the simulator just showing me a Blank screen with label Requesting... Anybody help me out for this ? Thanks in advance...

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  • How can I Add newer Data to the start of the xml file (Example inside)

    - by Ofear
    Hi All! After alot of work i finish to make a xml reader and writer... but my problem is that i want the newer data that i insert using my form will be added to the top of the xml file. and not in the bottom.. let me show you an example: this is the XML file: <?xml version="1.0" encoding="utf-8"?> <events> <record> <event>old event</event> <eventDate>1/1/2009</eventDate> <desc>old desc</desc> </record> <record> <event>newer event</event> <eventDate>12/12/2011</eventDate> <desc>newer desc</desc> </record> </events> now.. I want the XML file to be like this: newer data and then old data <?xml version="1.0" encoding="utf-8"?> <events> <record> <event>newer event</event> <eventDate>12/12/2011</eventDate> <desc>newer desc</desc> </record> <record> <event>old event</event> <eventDate>1/1/2009</eventDate> <desc>old desc</desc> </record> </events> This is my add.php (the file that get the POST information from the Form in the main.html : <?php $record = array( 'event' => $_POST['event'], 'eventDate' => $_POST['eventDate'], 'desc' => $_POST['desc'], ); $doc = new DOMDocument(); $doc->load( 'events.xml' ); $doc->formatOutput = true; $r = $doc->getElementsByTagName("events")->item(0); $b = $doc->createElement("record"); $event = $doc->createElement("event"); $event->appendChild( $doc->createTextNode( $record["event"] ) ); $b->appendChild( $event ); $eventDate = $doc->createElement("eventDate"); $eventDate->appendChild( $doc->createTextNode( $record["eventDate"] ) ); $b->appendChild( $eventDate ); $desc = $doc->createElement("desc"); $desc->appendChild( $doc->createTextNode( $record["desc"] ) ); $b->appendChild( $desc ); $r->appendChild( $b ); $doc->save("events.xml"); header("Location: {$_SERVER['HTTP_REFERER']}"); ?> Where do i need to edit to be able to make the *xml as i want?*

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  • Importing an XML file into excel

    - by Sudhee
    I have a multilevel XML file. When I import the XML into excel, it creates multiple columns for the multilevel data. However, I need the multilevel data as additional rows. Is there any way I can achieve this ? Thanks a lot for your help. My XML File: <L1> <L1dataId>07320</L1dataId> <DateDetail>13-Oct-2013</DateDetail> <TypeDetail> <TypeId>1</TypeId> <Rate1> <Current> <onsite>100</onsite> <net>100</net> <gross>100</gross> </Current> <Past> <onsite>100</onsite> <net>100</net> <gross>100</gross> </Past> </Rate1> <Rate2> <Current> <onsite>2100</onsite> <net>2100</net> <gross>2100</gross> </Current> <Past> <onsite>2100</onsite> <net>2200</net> <gross>1200</gross> </Past> </Rate2> <Rate3> <Current> <onsite>300</onsite> <net>300</net> <gross>300</gross> </Current> <Past> <onsite>400</onsite> <net>400</net> <gross>400</gross> </Past> </Rate3> </TypeDetail> <TypeDetail> <TypeId>2</TypeId> <Rate1> <Current> <onsite>100</onsite> <net>100</net> <gross>100</gross> </Current> <Past> <onsite>100</onsite> <net>100</net> <gross>100</gross> </Past> </Rate1> <Rate2> <Current> <onsite>2100</onsite> <net>2100</net> <gross>2100</gross> </Current> <Past> <onsite>2100</onsite> <net>2200</net> <gross>1200</gross> </Past> </Rate2> <Rate3> <Current> <onsite>300</onsite> <net>300</net> <gross>300</gross> </Current> <Past> <onsite>400</onsite> <net>400</net> <gross>400</gross> </Past> </Rate3> </TypeDetail> </L1> How Excel converts it and how I need it:

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  • Removing the XML Formatter from ASP.NET Web API Applications

    - by Rick Strahl
    ASP.NET Web API's default output format is supposed to be JSON, but when I access my Web APIs using the browser address bar I'm always seeing an XML result instead. When working on AJAX application I like to test many of my AJAX APIs with the browser while working on them. While I can't debug all requests this way, GET requests are easy to test in the browser especially if you have JSON viewing options set up in your various browsers. If I preview a Web API request in most browsers I get an XML response like this: Why is that? Web API checks the HTTP Accept headers of a request to determine what type of output it should return by looking for content typed that it has formatters registered for. This automatic negotiation is one of the great features of Web API because it makes it easy and transparent to request different kinds of output from the server. In the case of browsers it turns out that most send Accept headers that look like this (Chrome in this case): Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Web API inspects the entire list of headers from left to right (plus the quality/priority flag q=) and tries to find a media type that matches its list of supported media types in the list of formatters registered. In this case it matches application/xml to the Xml formatter and so that's what gets returned and displayed. To verify that Web API indeed defaults to JSON output by default you can open the request in Fiddler and pop it into the Request Composer, remove the application/xml header and see that the output returned comes back in JSON instead. An accept header like this: Accept: text/html,application/xhtml+xml,*/*;q=0.9 or leaving the Accept header out altogether should give you a JSON response. Interestingly enough Internet Explorer 9 also displays JSON because it doesn't include an application/xml Accept header: Accept: text/html, application/xhtml+xml, */* which for once actually seems more sensible. Removing the XML Formatter We can't easily change the browser Accept headers (actually you can by delving into the config but it's a bit of a hassle), so can we change the behavior on the server? When working on AJAX applications I tend to not be interested in XML results and I always want to see JSON results at least during development. Web API uses a collection of formatters and you can go through this list and remove the ones you don't want to use - in this case the XmlMediaTypeFormatter. To do this you can work with the HttpConfiguration object and the static GlobalConfiguration object used to configure it: protected void Application_Start(object sender, EventArgs e) { // Action based routing (used for RPC calls) RouteTable.Routes.MapHttpRoute( name: "StockApi", routeTemplate: "stocks/{action}/{symbol}", defaults: new { symbol = RouteParameter.Optional, controller = "StockApi" } ); // WebApi Configuration to hook up formatters and message handlers RegisterApis(GlobalConfiguration.Configuration); } public static void RegisterApis(HttpConfiguration config) { // remove default Xml handler var matches = config.Formatters .Where(f = f.SupportedMediaTypes .Where(m = m.MediaType.ToString() == "application/xml" || m.MediaType.ToString() == "text/xml") .Count() 0) .ToList() ; foreach (var match in matches) config.Formatters.Remove(match); } } That LINQ code is quite a mouthful of nested collections, but it does the trick to remove the formatter based on the content type. You can also look for the specific formatter (XmlMediatTypeFormatter) by its type name which is simpler, but it's better to search for the supported types as this will work even if there are other custom formatters added. Once removed, now the browser request results in a JSON response: It's a simple solution to a small debugging task that's made my life easier. Maybe you find it useful too…© Rick Strahl, West Wind Technologies, 2005-2012Posted in Web Api  ASP.NET   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • Don’t string together XML

    - by KyleBurns
    XML has been a pervasive tool in software development for over a decade.  It provides a way to communicate data in a manner that is simple to understand and free of platform dependencies.  Also pervasive in software development is what I consider to be the anti-pattern of using string manipulation to create XML.  This usually starts with a “quick and dirty” approach because you need an XML document and looks like (for all of the examples here, we’ll assume we’re writing the body of a method intended to take a Contact object and return an XML string): return string.Format("<Contact><BusinessName>{0}</BusinessName></Contact>", contact.BusinessName);   In the code example, I created (or at least believe I created) an XML document representing a simple contact object in one line of code with very little overhead.  Work’s done, right?  No it’s not.  You see, what I didn’t realize was that this code would be used in the real world instead of my fantasy world where I own all the data and can prevent any of it containing problematic values.  If I use this code to create a contact record for the business “Sanford & Son”, any XML parser will be incapable of processing the data because the ampersand is special in XML and should have been encoded as &amp;. Following the pattern that I have seen many times over, my next step as a developer is going to be to do what any developer in his right mind would do – instruct the user that ampersands are “bad” and they cannot be used without breaking computers.  This may work in many cases and is often accompanied by logic at the UI layer of applications to block these “bad” characters, but sooner or later someone is going to figure out that other applications allow for them and will want the same.  This often leads to the creation of “cleaner” functions that perform a replace on the strings for every special character that the person writing the function can think of.  The cleaner function will usually grow over time as support requests reveal characters that were missed in the initial cut.  Sooner or later you end up writing your own somewhat functional XML engine. I have never been told by anyone paying me to write code that they would like to buy a somewhat functional XML engine.  My employer/customer’s needs have always been for something that may use XML, but ultimately is functionality that drives business value. I’m not going to build an XML engine. So how can I generate XML that is always well-formed without writing my own engine?  Easy – use one of the ones provided to you for free!  If you’re in a shop that still supports VB6 applications, you can use the DomDocument or MXXMLWriter object (of the two I prefer MXXMLWriter, but I’m not going to fully describe either here).  For .Net Framework applications prior to the 3.5 framework, the code is a little more verbose than I would like, but easy once you understand what pieces are required:             using (StringWriter sw = new StringWriter())             {                 using (XmlTextWriter writer = new XmlTextWriter(sw))                 {                     writer.WriteStartDocument();                     writer.WriteStartElement("Contact");                     writer.WriteElementString("BusinessName", contact.BusinessName);                     writer.WriteEndElement(); // end Contact element                     writer.WriteEndDocument();                     writer.Flush();                     return sw.ToString();                 }             }   Looking at that code, it’s easy to understand why people are drawn to the initial one-liner.  Lucky for us, the 3.5 .Net Framework added the System.Xml.Linq.XElement object.  This object takes away a lot of the complexity present in the XmlTextWriter approach and allows us to generate the document as follows: return new XElement("Contact", new XElement("BusinessName", contact.BusinessName)).ToString();   While it is very common for people to use string manipulation to create XML, I’ve discussed here reasons not to use this method and introduced powerful APIs that are built into the .Net Framework as an alternative.  I’ve given a very simplistic example here to highlight the most basic XML generation task.  For more information on the XmlTextWriter and XElement APIs, check out the MSDN library.

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  • jqGrid adding new row with XML Data

    - by mahr.g.mohyuddin
    Hi Everyone, I am using jQGrid in my ASP.NET MVC application with add row feature. My problem is I have to save XML data in some of the row fields. But while posting the new row with some fields having plain xml, to server I get Internal server error. By default jqGrid perhaps expects json or text data to be posted on server while adding a new row. I used beforeSubmit method for workaround to convert xml first to json and then send to server, but while converting json back to xml I lose the orginal structure of the xml. FYI: I used JsonReaderWriterFactory on server to convert it back. Your help will be highly appreciated. Thanks.

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  • use jsonp to get xml cross domain

    - by lmkk
    I am trying to read xml into a webpage from another server, and I assume that my problem is Same-Origin Policy, and therefore a cross domain problem. I have a bit of googling and it seems that jsonp is the way forward. Based on some examples I found here on stackoverflow and another sites, this is what I have, and it does not "hit" the server with the xml. I can view the xml in a browser. $(document).ready(function(){ $.ajax({ type: 'GET', dataType: 'jsonp', url: 'http://192.168.0.106:8111/getconfiguration?', success: function (xml) { //do stuff with received xml }}); Any suggestions? please keep in mind that I am a newbie with regards to JS / JQuery ;o)

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