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  • Django website on Apache with wsgi failing

    - by notagain
    I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

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  • Webfaction apache + mod_wsgi + django configuration issue

    - by Dmitry Guyvoronsky
    A problem that I stumbled upon recently, and, even though I solved it, I would like to hear your opinion of what correct/simple/adopted solution would be. I'm developing website using Django + python. When I run it on local machine with "python manage.py runserver", local address is http://127.0.0.1:8000/ by default. However, on production server my app has other url, with path - like "http://server.name/myproj/" I need to generate and use permanent urls. If I'm using {% url view params %}, I'm getting paths that are relative to / , since my urls.py contains this urlpatterns = patterns('', (r'^(\d+)?$', 'myproj.myapp.views.index'), (r'^img/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/img' }), (r'^css/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/css' }), ) So far, I see 2 solutions: modify urls.py, include '/myproj/' in case of production run use request.build_absolute_uri() for creating link in views.py or pass some variable with 'hostname:port/path' in templates Are there prettier ways to deal with this problem? Thank you. Update: Well, the problem seems to be not in django, but in webfaction way to configure wsgi. Apache configuration for application with URL "hostname.com/myapp" contains the following line WSGIScriptAlias / /home/dreamiurg/webapps/pinfont/myproject.wsgi So, SCRIPT_NAME is empty, and the only solution I see is to get to mod_python or serve my application from root. Any ideas?

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  • Java - Problem in deploying Web Application

    - by Yatendra Goel
    I have built a Java Web Application and packed it in a .war file and tested it on my local tomcat server and it is running fine. But when I deployed it on my client's server, it is showing an error. According to the remote server (my client's server), it is not finding a tld file packed in a jar file which I had placed in WEB-INF/lib directory. But when I checked the WEB-INF/lib directory for the jar file, i found that it was there. The contents of META-INF/MANIFEST.MF is as follows: Manifest-Version: 1.0 Class-Path: I think that there is no need to explicitly mention the classpath of WEB-INF/lib directory as it is in the classpath of any web application by default. Then, why the server can't find the jar file in the lib directory when I deployed it on a remote server and why it is working when I deployed the same application on my local server. I posted a question for this at http://stackoverflow.com/questions/2441254/struts-1-struts-taglib-jar-is-not-being-found-by-my-web-application but found that the problem is unusual as nobody could answer it. So my questions are as follows: Q1. Is WEB-INF/lib still remains on the classpath if I leave the classpath entry blank as shown above in the MANIFEST.MF file or I should delete the classpath entry completely from the file or I should explicitly enter Class-Path: /WEB-INF/lib as the classpath entry? Q2. I have JSP pages, Servlets and some helper classes in the web application. Jsp pages are located at the root. Servlets and helper classes are located in WEB-INF/classes folder. So Is there any problem if my helper classes are located in the WEB-INF/classes folder? Note: Please note that this question is not same as my previous question. It is a follow-up question of my previous question. Both the servers (local and remote) are tomcat servers.

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  • Sometimes can rename, remove a folder; sometimes cannot

    - by Vy Clarks
    In my website project. I need to rename or remove some folder by code. Sometimes I can do all of that, but sometimes I cannot with error: Access to the path is denied Try to find to solution on Google. May be, there are two reason: The permisstion of that Folder Some subFolder or some file in that Folder that's being held open. Try to check: Right click on Folder- Properties-- Security: if this is the right way to check the permission, the Folder allowes every action (read, write....) There are no file, no subfolder of that Folder is opened. Why? I still dont understant why sometimes I can rename folder but sometimes I cannot. Help!! I need your opinions!!! UPDATE: take a look at my code above: I want to rename the a folder with the new name inputed in a Textbox txtFilenFolderName: protected void btnUpdate_Click(object sender, EventArgs e) { string[] values = EditValue; string oldpath = values[0];// = "D:\\C#Projects\\website\\Lecturer\\giangvien\\New folder" string oldName = values[2]; //= New Folder string newName = txtFilenFolderName.Text; //= New Folder1 string newPath = string.Empty; if (oldName != newName) { newPath = oldpath.Replace(oldName, newName); Directory.Move(oldpath, newPath); } else lblmessage2.Text = "New name must not be the same as the old "; } } Try to debug: oldpath = "D:\\C#Projects\\website\\Lecturer\\giangvien\\New folder" oldName = New Folder newName= New Folder1 newpath = "D:\\C#Projects\\website\\Lecturer\\giangvien\\New folder1" Everything seems right, but I when I click on buton Edit --- rename--- Update--- an error occur: Access to the path is denied D:\\C#Projects\\website\\Lecturer\\giangvien\\New folder Help!

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  • Java iteration reading & parsing

    - by Patrick Lorio
    I have a log file that I am reading to a string public static String Read (String path) throws IOException { StringBuilder sb = new StringBuilder(); InputStream in = new BufferedInputStream(new FileInputStream(path)); int r; while ((r = in.read()) != -1) { sb.append(r); } return sb.toString(); } Then I have a parser that iterates over the entire string once void Parse () { String con = Read("log.txt"); for (int i = 0; i < con.length; i++) { /* parsing action */ } } This is hugely a waste of cpu cycles. I loop over all the content in Read. Then I loop over all the content in Parse. I could just place the /* parsing action */ under the while loop in the Read method, which would be find but I don't want to copy the same code all over the place. How can I parse the file in one iteration over the contents and still have separate methods for parsing and reading? In C# I understand there is some sort of yield return thing, but I'm locked with Java. What are my options in Java?

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  • Glob() filesearch, question

    - by Peter
    Hi, a little question. I have this code, which is works perfect for files, but If am trying search on a directory name, the result is blank. How I can fix that? <?php function listdirs($dir,$search) { static $alldirs = array(); $dirs = glob($dir."*"); foreach ($dirs as $d){ if(is_file($d)){ $filename = pathinfo($d); if(eregi($search,$filename['filename'])){ print "<a href=http://someurl.com/" . $d .">". $d . "</a><br/>"; } }else{ listdirs($d."/",$search); } } } $path = "somedir/"; $search= "test"; listdirs($path,$search); ?> somedir/test/ result: blank (I want: /somedir/test/) somedir/test/test.txt result: OK I want to search also in the directory names, how I can do that?

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  • How to define trees with more than one type in ML programing language

    - by user550413
    Well, I am asked to do the next thing: To define a binary tree which can contain 2 different types: ('a,'b) abtree and these are the requirements: Any inner vertex (not a leaf) must be of the type 'a or 'b and the leafs have no value. For every path in the tree all 'a values must appear before the 'b value: examples of paths: 'a->'a->'a-'b (legal) 'a->'b->'b (legal) 'a->'a->'a (legal) 'b->'b->'b (legal) 'a->'b->'a (ILLEGAL) and also I need to define another tree which is like the one described above but now I have got also 'c and in the second requirement it says that for every path I 'a values appear before the 'b values and all the 'b values appear before the 'c values. First, I am not sure how to define binary trees to have more than 1 type in them. I mean the simplest binary tree is: datatype 'a tree = leaf | br of 'a * 'a tree * 'a tree; And also how I can define a tree to have these requirements. Any help will be appreciated. Thanks.

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  • Showing latex commands in text string using mathjax

    - by robezy
    I have a text string, for ex. 'A vehicle travels from A to B, distance {$d} km at constant speed. While returning back to A on same path it {$variation} its speed by {$v} km/hr. The total time of journey is {$t} hours. Find the original speed of vehicle.' The variables in the curly brackets are to be replaced by appropriate latex equation. I'm using php's preg_replace to replace the variables with latex commands. Unfortunately, my latex commands are coming as it is. It is not processed by mathjax. For ex, above text becomes A vehicle travels from A to B, distance 1 km at constant speed. While returning back to A on same path it increased its speed by (\frac{3}{2}) km/hr. The total time of journey is 1 hours. Find the original speed of vehicle. The frac is show as it is. What is wrong here? Please ask me if you need any more info. Thanks

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  • Getting method arguments with Roslyn

    - by Kevin Burton
    I can get a list from the solution of all calls to a particuliar method using the following code: var createCommandList = new List<MethodSymbol>(); INamedTypeSymbol interfaceSymbol = (from p in solution.Projects select p.GetCompilation().GetTypeByMetadataName("BuySeasons.BsiServices.DataResource.IBsiDataConnection")).FirstOrDefault(); foreach (ISymbol symbol in interfaceSymbol.GetMembers("CreateCommand")) { if (symbol.Kind == CommonSymbolKind.Method && symbol is MethodSymbol) { createCommandList.Add(symbol as MethodSymbol); } } foreach (MethodSymbol methodSymbol in createCommandList) { foreach (ReferencedSymbol referenceSymbol in methodSymbol.FindReferences(solution)) { foreach (ReferenceLocation referenceLocation in from l in referenceSymbol.Locations orderby l.Document.FilePath select l) { if (referenceLocation.Location.GetLineSpan(false).StartLinePosition.Line == referenceLocation.Location.GetLineSpan(false).EndLinePosition.Line) { Debug.WriteLine(string.Format("{0} {1} at {2} {3}/{4} - {5}", methodSymbol.Name, "(" + string.Join(",", (from p in methodSymbol.Parameters select p.Type.Name + " " + p.Name).ToArray()) + ")", Path.GetFileName(referenceLocation.Location.GetLineSpan(false).Path), referenceLocation.Location.GetLineSpan(false).StartLinePosition.Line, referenceLocation.Location.GetLineSpan(false).StartLinePosition.Character, referenceLocation.Location.GetLineSpan(false).EndLinePosition.Character)); } else { throw new ApplicationException("Call spans multiple lines"); } } } } But this gives me a list of ReferencedSymbol's. Although this gives me the file and line number that the method is called from I would also like to get the specific arguments that the method is called with. How can I either convert what I have or get the same information with Roslyn? (notice the I first load the solution with the Solution.Load method and then loop through to find out where the method is defined/declared (createCommandList)). Thank you.

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  • Enumerating pixel formats for adaptors and modes with OpenGL

    - by Robinson
    I'm trying to code an OpenGL path for my 3D engine. The D3D path enumerates all device adaptors, all modes (by mode I mean bit depth, dimensions, available windowed, and refresh rate) for each adaptor and then all pixel formats available for the given mode and adaptor, along side certain useful caps (shader version, filter types, etc.). So, I have broadly got the following protected functions in the class: // Enumerate all back/front buffer combinations. virtual void EnumerateBackFrontBufferCombinations(CComPtr<IDirect3D9>& d3d9); // Enumerate all depth/stencil formats. virtual void EnumerateDepthStencilFormats(CComPtr<IDirect3D9>& d3d9); // Enumerate all multi-sample formats. virtual void EnumerateMultiSampleTypes(CComPtr<IDirect3D9>& d3d9); // Enumerate all device formats, i.e. dynamic, static, render target, etc. virtual void EnumerateMapFormats(CComPtr<IDirect3D9>& d3d9); // Enumerate all capabilities. virtual void EnumerateCapabilities(CComPtr<IDirect3D9>& d3d9); The adaptors are enumerated with EnumDisplayDevices, the modes (resolutions and refresh rates) are enumerated with EnumDisplaySettings, so this can be done for either GL or D3D. The other functions I'm not so sure about with OpenGL. What are the equivalents to the IDirect3D9's CheckDeviceType, CheckDeviceFormat, CheckDeviceMultiSampleType, CheckDepthStencilMatch? I know I can use DescribePixelFormat, given a DC, but you kind-of need to have created the window before you can use a DC with it, but you can't create the window correctly until you know what formats you're going to use. Any tips you can give me? Thanks.

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  • Static files in (Java) App Engine not accessible.

    - by fiXedd
    The example documentation says that you simply need to place your files in war/ (or a subdirectory) and they should be accessible from the host (as long as they aren't JSPs or in WEB-INF). For example, if you place foo.css in war/ then you should be able to access it at http://localhost:8080/foo.css. However, this isn't working for me at all. NONE of my static files are accessible. The docs on appengine-web.xml say that you can also specifically denote certain types as static. I've tried this as well and it makes no difference. Am I missing something obvious? UPDATE: Turns out one of the mappings in my web.xml was a little too aggressive. The following was the culprit: <servlet> <servlet-name>Main</servlet-name> <servlet-class>MainServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Main</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> It seems that it was grabbing everything that wasn't grabbed be one of the other rules, which I don't understand because there was no * on the end of the url-pattern. It also seems to be directly contradictory to the documentation that says: Note: Static files, files that are served verbatim to users such as images, CSS or JavaScript, are handled separately from paths mentioned in the deployment descriptor. A request for a URL path that matches a path to a file in the WAR that's considered a static file will serve the file, regardless of servlet and filter mappings in the deployment descriptor. You can exclude files from those treated as static files using the appengine-web.xml file. So, how can I have a rule that matches the base of my domain (eg. http://www.example.com/) and still allows the static files to filter through?

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  • Problem with linking in gcc

    - by chitra
    I am compiling a program in which a header file is defined in multiple places. Contents of each of the header file is different, though the variable names are the same internal members within the structures are different . Now at the linking time it is picking up from a library file which belongs to a different header not the one which is used during compilation. Due to this I get an error at link time. Since there are so many libraries with the same name I don't know which library is being picked up. I have lot of oems and other customized libraries which are part of this build. I checked out the options in gcc which talks about selecting different library files to be included. But no where I am able to see an option which talks about which libraries are being picked up the linker. If the linker is able to find more than one library file name, then which does the linker pick up is something which I am not able to understand. I don't want to specify any path, rather I want to understand how the linker is resolving the multiple libraries that it is able to locate. I tried putting -v option, but that doesn't list out the path from which the gcc picks up the library. I am using gcc on linux. Any help in this regard is highly appreciated. Regards, Chitra

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  • How to increase PermGen memory for eclipselink StaticWeaveAntTask

    - by rayd09
    We are using Eclipselink and need to weave the code in order for lazy fetching to work property. During the weave process I'm getting the following error: weave: BUILD FAILED java.lang.OutOfMemoryError: PermGen space I have the following tasks within my ant build file: <target name="define_weave_task" description="task definition for EclipseLink static weaving"> <taskdef name="eclipse_weave" classname="org.eclipse.persistence.tools.weaving.jpa.StaticWeaveAntTask"/> </target> <target name="weave" depends="compile,define_weave_task" description="weave eclipselink code into compiled classes"> <eclipse_weave source="${path.classes}" target="${path.classes}"> <classpath refid="compile.classpath"/> </eclipse_weave> </target> It has been working great for a long time. Now that the amount of code to be woven has increased I'm getting the PermGen error. I would like to be able to up the amount of perm space. If I was doing a compile I would be able to up the perm space via a compiler argument such as <compilerarg value="-XX:MaxPermSize=256M"/> but this does not appear to be a valid argument for eclipselink weaving. How can I up the perm space for the weave?

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  • Jquery Find an XML element based on the value of one of it's children

    - by NateD
    I'm working on a simple XML phonebook app to learn JQuery, and I can't figure out how to do something like this: When the user enters the first name of a contact in a textbox I want to find the entire record of that person. The XML looks like this: <phonebook> <person> <number> 555-5555</number> <first_name>Evelyn</first_name> <last_name>Remington</last_name> <address>Edge of the Abyss</address> <image>path/to/image</image> </person> <person> <number>+34 1 6444 333 2223230</number> <first_name>Max</first_name> <last_name>Muscle</last_name> <address>Mining Belt</address> <image>path/to/image</image> </person> </phonebook> and the best I've been able to do with the jQuery is something like this: var myXML; function searchXML(){ $.ajax({ type:"GET", url: "phonebook.xml", dataType: "xml", success: function(xml){myXML = $("xml").find("#firstNameBox").val())} }); } What I want it to do is return the entire <person> element so I can iterate through and display all that person's information. Any help would be appreciated.

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  • Python: Most efficient way to concatenate and rearrange files

    - by user300890
    Hi, I am reading from several files, each file is divided into 2 pieces, first a header section of a few thousand lines followed by a body of a few thousand. My problem is I need to concatenate these files into one file where all the headers are on the top followed by the body. Currently I am using two loops; one to pull out all the headers and write them, and the second to write the body of each file (I also include a tmp_count variable to limit the number of lines to be loading into memory before dumping to file). This is pretty slow - about 6min for 13gb file. Can anyone tell me how to optimize this or if there is a faster way to do this in python ? Thanks! Here is my code: def cat_files_sam(final_file_name,work_directory_master,file_count): final_file = open(final_file_name,"w") if len(file_count) > 1: file_count=sort_output_files(file_count) # only for @ headers for bowtie_file in file_count: #print bowtie_file tmp_list = [] tmp_count = 0 for line in open(os.path.join(work_directory_master,bowtie_file)): if line.startswith("@"): if tmp_count == 1000000: final_file.writelines(tmp_list) tmp_list = [] tmp_count = 0 tmp_list.append(line) tmp_count += 1 else: final_file.writelines(tmp_list) break for bowtie_file in file_count: #print bowtie_file tmp_list = [] tmp_count = 0 for line in open(os.path.join(work_directory_master,bowtie_file)): if line.startswith("@"): continue if tmp_count == 1000000: final_file.writelines(tmp_list) tmp_list = [] tmp_count = 0 tmp_list.append(line) tmp_count += 1 final_file.writelines(tmp_list) final_file.close()

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  • wsgi django not working

    - by MaKo
    im installing django, the test for wsgi is ok, but when i point my default file to the django test, it doesnt work, this is the test that works fine: default: /etc/apache2/sites-available/default <VirtualHost *:80> ServerName www.example.com ServerAlias example.com ServerAdmin [email protected] DocumentRoot /var/www <Directory /var/www/documents> Order allow,deny Allow from all </Directory> WSGIScriptAlias / /home/ubuntu/djangoProj/micopiloto/application.wsgi <Directory /home/ubuntu/djangoProj/mysitio/wsgi_handler.py> Order allow,deny Allow from all </Directory> </VirtualHost> application.wsgi:: ~/djangoProj/micopiloto import os import sys sys.path.append('/srv/www/cucus/application') os.environ['PYTHON_EGG_CACHE'] = '/srv/www/cucus/.python-egg' def application(environ, start_response): status = '200 OK' output = 'Hello World!MK SS9 tkt kkk' response_headers = [('Content-type', 'text/plain'), ('Content-Length', str(len(output)))] start_response(status, response_headers) return [output] but if I change the default to point to application_sa.wsgi the django test, it doesnt work :( application_sa.wsgi import os, sys sys.path.append('/home/ubuntu/djangoProj/micopiloto') os.environ['DJANGO_SETTINGS_MODULE'] = 'micopiloto.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I restart the apache server every time i change the wsgi to test, so what im i missing? thanks a lot!

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  • I have a WPF/Silverlight ListView whose height is unpredictable and too high. How do I control it be

    - by Rob Perkins
    I have a ListView element with a DataTemplate for each ListViewItem defined as follows. When run, the ListView's height is not collapsed onto the items in the view, which is undesirable behavior: <DataTemplate x:Key="LicenseItemTemplate"> <Grid> <Grid.RowDefinitions> <RowDefinition Height="Auto" /> <RowDefinition Height="Auto" /> </Grid.RowDefinitions> <TextBlock Grid.Row="0" Text="{Binding company}"></TextBlock> <Grid Grid.Row="1" Style="{StaticResource HiddenWhenNotSelectedStyle}"> <Grid.RowDefinitions> <RowDefinition /> </Grid.RowDefinitions> <Button Grid.Row="0">ClickIt</Button> </Grid> </Grid> </DataTemplate> The second row of the outer grid has a style applied which looks like this. The purpose of the style is to : <Style TargetType="{x:Type Grid}" x:Key="HiddenWhenNotSelectedStyle" > <Style.Triggers> <DataTrigger Binding="{Binding Path=IsSelected, RelativeSource={ RelativeSource Mode=FindAncestor, AncestorType={x:Type ListViewItem} } }" Value="False"> <Setter Property="Grid.Visibility" Value="Collapsed" /> </DataTrigger> <DataTrigger Binding="{Binding Path=IsSelected, RelativeSource={ RelativeSource Mode=FindAncestor, AncestorType={x:Type ListViewItem} } }" Value="True"> <Setter Property="Grid.Visibility" Value="Visible" /> </DataTrigger> </Style.Triggers> </Style> The ListView renders like this: The desired appearance is this, when none of the elements are selected: ...with, of course, the ListView's height adjusting to accommodate the additional content when the second grid is made visible by selection. What can I do to get the desired behavior?

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  • Rails runner command not saving to cache

    - by mark
    Hi I'm having a bit of a problem with a cron task generated by rails whenever plugin that should store remote data in the rails cache for display. What I have is this: schedule.rb set :path, '/var/www/apps/tuexplore/current' every 1.hour do runner "Weather.cache_remote", :environment => :production end calls this model class Weather def self.cache_remote Rails.cache.write('weather_data', Net::HTTP.get_response(URI.parse(WEATHER_URL)).body) end end Calling whenever returns this PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/home/deploy/.gem/ruby/1.8/bin 0 * * * * /var/www/apps/tuexplore/current/script/runner -e production "Weather.cache_remote" This doesn't work. Calling the weather model method from a controller works fine, but I need to schedule it hourly. The cron task causes a "Cache write: weather_data" entry to appear in the production log but data isn't stored nor output into the page. Additional information, I can log into production console and run Weather.cache_remote, then read the data from the rails cache. I'd be really appreciative if someone could point out the error of my ways. If further explanation is needed please ask. Thanks in advance for any pointers.

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  • How to define a default tooltip style for all Controls

    - by skjagini
    I would like to define a style with a template when there are validation errors and would display the first error message as a tooltip. It works fine when targeting specific control like DatePicker in the following xaml. <Style TargetType="{x:Type ToolKit:DatePicker}"> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}"/> </Trigger> </Style.Triggers> </Style> I cannot get it to work for Control though, i.e. the following doesn't give any tooltip <Style TargetType="{x:Type ToolKit:Control}"> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}"/> </Trigger> </Style.Triggers> </Style> Any idea?

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  • Tagging in Subversion - how do I make the decision about continuing to work on my trunk vs. the new

    - by Howiecamp
    I'm running Tortoise SVN to manage a project. Obviously the principles around tagging apply to any implementation of SVN but in this question I'll be referring to some TortoiseSVN-specific dialog boxes and messages. My working directory and the subversion repository structure both have a Source root directory and the Trunk, Tags and Branches directories underneath. (I couldn't figure out how to do a multilevel indented hierarchy in markdown without using bullets, so if someone could edit and fix this I'd appreciate it.) I'm working out of the Trunk directory in my working copy and it's pointing at the Trunk directory in the repo. I want to apply a Tag "Release1" so I click the "Branch/tag..." menu option and set the repo path as my [repo_path/bla/Source/Tags/Release1" tag. This dialog box gives me the option to "Switch my working copy to new branch/tag". I understand that if this option is left unchecked, the new "Release1" branch under /Tags" will be created but my working copy will remain on the previous "Trunk" path. If I do check this option (or use the Switch command) I understand that my working copy will switch to the new "Release1" branch under "/Tags". Where I'm missing a concept is how to make this decision. It doesn't seem like I want to switch my working directory to the recently created tag since by definition (?) I want that tag to be a snapshot of my code as of a point in time. If I don't switch the working directory, I'll continue working off Trunk and when I'm ready to take another snapshot I'll make another tag. And so on... Am I understanding this right or am I stating something incorrectly in the previous paragraph (e.g. the statement about not wanting to switch to the tag since the tag should represent a point in time snapshot) or otherwise missing something regarding how to make this decision?

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  • Using mod-rewrite to conditionally select existing file in a subdirectory based on Host header?

    - by Kevin Hakanson
    I'm working through a problem where I want to select a different static content file based on the incoming Host header. The simple example is a mapping from URLs to files like this: www.example.com/images/logo.gif - \images\logo.gif skin2.example.com/images/logo.gif - \images\skin2\logo.gif skin3.example.com/images/logo.gif - \images\skin3logo.gif I have this working with the following RewriteRules, but I don't like how I have to repeat myself so much. Each host has the same set of rules, and each RewriteCond and RewriteRule has the same path. I'd like to use the RewriteMap, but I don't know how to use it to map the %{HTTP_HOST} to the path. <VirtualHost *:80> DocumentRoot "C:/Program Files/Apache Software Foundation/Apache2.2/htdocs" ServerName www.example.com ServerAlias skin2.example.com ServerAlias skin3.example.com RewriteEngine On RewriteCond %{HTTP_HOST} skin2.example.com RewriteCond %{DOCUMENT_ROOT}$1/skin2/$2 -f RewriteRule ^(.*)/(.*) $1/skin2/$2 [L] RewriteCond %{HTTP_HOST} skin3.example.com RewriteCond %{DOCUMENT_ROOT}$1/skin3/$2 -f RewriteRule ^(.*)/(.*) $1/skin3/$2 [L] </VirtualHost> The concept behind the rules is if the same filename exists in a subdirectory for that host, use it instead of the direct targeted file. This uses host based subdirectories at the lowest level, and not a top level subdirectory to separate content.

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  • Django: How can I identify the calling view from a template?

    - by bryan
    Short version: Is there a simple, built-in way to identify the calling view in a Django template, without passing extra context variables? Long (original) version: One of my Django apps has several different views, each with its own named URL pattern, that all render the same template. There's a very small amount of template code that needs to change depending on the called view, too small to be worth the overhead of setting up separate templates for each view, so ideally I need to find a way to identify the calling view in the template. I've tried setting up the views to pass in extra context variables (e.g. "view_name") to identify the calling view, and I've also tried using {% ifequal request.path "/some/path/" %} comparisons, but neither of these solutions seems particularly elegant. Is there a better way to identify the calling view from the template? Is there a way to access to the view's name, or the name of the URL pattern? Update 1: Regarding the comment that this is simply a case of me misunderstanding MVC, I understand MVC, but Django's not really an MVC framework. I believe the way my app is set up is consistent with Django's take on MVC: the views describe which data is presented, and the templates describe how the data is presented. It just happens that I have a number of views that prepare different data, but that all use the same template because the data is presented the same way for all the views. I'm just looking for a simple way to identify the calling view from the template, if this exists. Update 2: Thanks for all the answers. I think the question is being overthought -- as mentioned in my original question, I've already considered and tried all of the suggested solutions -- so I've distilled it down to a "short version" now at the top of the question. And right now it seems that if someone were to simply post "No", it'd be the most correct answer :) Update 3: Carl Meyer posted "No" :) Thanks again, everyone.

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  • Check if TIFF file is complete

    - by Davi
    I have a FileSystemWatcher monitoring a directory that receives TIF files from a scanning device. Its necessary to check if the scanning process is done and then read a multipage TIF file, otherwise, the FileSystemWatcher will raise the event before the file be fully scanned. I have something like: private void OnFileCreated(...) { while(IsFileLocked(path)) Thread.Sleep(time); // OK to read } This is what is happening: - Scanner creates the file - FileSystemWatcher detects the file, but its in use - Scanner reads the first page to the file - Scanner releases the file - My code leaves the while(FileInUse(path)) - My code reads the incomplete file (problem) - Scanner adds more pages to the file Let's say the scanner is scanning 100 pages, then, when "OK to read", the file will be incomplete (99 pages left). So, its necessary to know if the file is complete or not. Maybe waiting some time to see if the file is modified, but this time span can be up to hours, because the scanner can get idle scanning the same TIF. Other solution would be checking some flag in the TIF file that indicates that the file is not complete(I've looked for this but don't found anything).

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  • How to use dirent.h correctly.

    - by Nick
    Hello, I am new to C++ and I am experimenting with the dirent.h header to manipulate directory entries. The following little app compiles but pukes after you supple a directory name. Can someone give me a hint? The int quit is there to provide a while loop. I removed the loop in an attempt to isolate my problem. thanks! #include <iostream> #include <dirent.h> using namespace std; int main() { char *dirname = 0; DIR *pd = 0; struct dirent *pdirent = 0; int quit = 1; cout<< "Enter a directory path to open (leave blank to quit):\n"; cin >> dirname; if(dirname == NULL) { quit = 0; } pd = opendir(dirname); if(pd == NULL) { cout << "ERROR: Please provide a valid directory path.\n"; } return 0; }

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  • EXC_BAD_ACCESS with NSUserdefaults on iphone.

    - by Andreas Johannessen
    I have the following code in my ApplicationDelegate. My deployment target is 3.0 and upwards, however I get a EXC_BAD_ACCESS when I launch the app with the following code on my iPhone with 3.1.3, however on the simulator which has 4.2 it runs fine. I would really appriciate help on this one, thanks in advance. When I comment this block when I deploy to 3.1.3 device it runs without bad access. + (void)initialize { NSString *path = [[NSBundle mainBundle] bundlePath]; NSString *pListPath = [path stringByAppendingPathComponent:@"Settings.bundle/Root.plist"]; NSDictionary *pList = [NSDictionary dictionaryWithContentsOfFile:pListPath]; NSMutableArray *prefsArray = [pList objectForKey:@"PreferenceSpecifiers"]; NSMutableDictionary *regDictionary = [NSMutableDictionary dictionary]; for (NSDictionary *dict in prefsArray) { NSString *key = [dict objectForKey:@"Key"]; if(key) { id value = [dict objectForKey:@"DefaultValue"]; [regDictionary setObject:value forKey:key]; } } [[NSUserDefaults standardUserDefaults] registerDefaults:regDictionary]; } UPDATE: I traced the error to happen on this line: [[NSUserDefaults standardUserDefaults] registerDefaults:regDictionary]; So there is probaly another syntax on earlier iOS, or am I wrong?

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