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  • mysql extra columns with same name from two tables

    - by salmane
    Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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  • SELECT DISTINCT multiple field search?

    - by Patrick
    I'm trying to search multiple fields zc_city and zc_zip for when user input and then return row results for zc_city zc_state and zc_zip $q = strtolower($_GET["q"]); if (!$q) return; $sql = "SELECT DISTINCT zc_city AS zcity FROM search_zipcodes WHERE zc_city LIKE '$q%'"; $rsd = mysql_query($sql); while($rs = mysql_fetch_array($rsd)) { $zcity = $rs['zcity']; echo "$zcity\n"; }

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  • Problem with mysql_query() ;Says resource expected .

    - by user364651
    I have this php file. The lines marked as bold are showing up the error :"mysql_query() expecets parameter 2 to be a resources. Well, the similar syntax on the line on which I have commented 'No error??' is working just fine. function checkAnswer($answerEntered,$quesId) { //This functions checks whether answer to question having ques_id = $quesId is satisfied by $answerEntered or not $sql2="SELECT keywords FROM quiz1 WHERE ques_id=$quesId"; **$result2=mysql_query($sql2,$conn);** $keywords=explode(mysql_result($result2,0)); $matches=false; foreach($keywords as $currentKeyword) { if(strcasecmp($currentKeyword,$answerEntered)==0) { $matches=true; } } return $matches; } $sql="SELECT answers FROM user_info WHERE user_id = $_SESSION[user_id]"; $result=mysql_query($sql,$conn); // No error?? $answerText=mysql_result($result,0); //Retrieve answers entered by the user $answerText=str_replace('<','',$answerText); $answerText=str_replace('>',',',$answerText); $answerText=substr($answerText,0,(strlen($answerText)-1)); $answers=explode(",",$answerText); //Get the questions that have been assigned to the user. $sql1="SELECT questions FROM user_info WHERE user_id = $_SESSION[user_id]"; **$result1=mysql_query($sql1,$conn);** $quesIdList=mysql_result($result1,0); $quesIdList=substr($quesIdList,0,(strlen($quesIdList)-1)); $quesIdArray=explode(",",$quesIdList); $reportCard=""; $i=0; foreach($quesIdArray as $currentQuesId) { $answerEnteredByUser=$answers[$i]; if(checkAnswer($answerEnteredByUser,$currentQuesId)) { $reportCard=$reportCard+"1"; } else { $reportCard=$reportCard+"0"; } $i++; } echo $reportCard; ?> Here is the file connect.php. It is working just fine for other PHP documents. <?php $conn= mysql_connect("localhost","root","password"); mysql_select_db("quiz",$conn); ?>

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  • Outer select column value in joined subquery?

    - by Michael DePetrillo
    Is it possible to use a column value from an outer select within a joined subquery? SELECT table1.id, table2.cnt FROM table1 LEFT JOIN (SELECT COUNT(*) as `cnt` FROM table2 where table2.lt > table1.lt and table2.rt < table1.rt) as table2 ON 1; This results in "Unknown column 'table1.lt' in 'where clause'". Here is the db dump. CREATE TABLE IF NOT EXISTS `table1` ( `id` int(1) NOT NULL, `lt` int(1) NOT NULL, `rt` int(4) NOT NULL) ENGINE=MyISAM DEFAULT CHARSET=latin1; CREATE TABLE IF NOT EXISTS `table2` ( `id` int(1) NOT NULL, `lt` int(1) NOT NULL, `rt` int(4) NOT NULL) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `table1` (`id`, `lt`, `rt`) VALUES (1, 1, 4); INSERT INTO `table2` (`id`, `lt`, `rt`) VALUES (2, 2, 3);

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  • Access database Need to prevent from approving overlapping OT.Second Try with modified request Not a programmer [on hold]

    - by user2512764
    Employees Signups on company Website for advance overtime line. Access table already has overtime signups which does not require user to add the time but it requires only to add location as approved. Since this table has field Employee name, Date, start time and End time and location, All the fields has the data except for location. In the data base I have created a form based on this table. Since the table already have most of the information User only has to add location in the form field in order to approve overtime. Once user approves an overtime line for example: User approves overtime for employee name 'John' which starts on 7/1/2013 at 0400-0800, location is successfully added. When user tries to add location for John again which might has the start time for 7/1/2013 at 0600=0900. Again we are not entering Start time, End time and date it is already in the table. we are only entering location as approval. Soon user enters the location for John in the form field, since there is a conflict with previously overtime line which has already been approved. program needs to check employee name, date and time in previously approved (Added location) overtime line and The location in current record needs to be deleted and go to next record. I hope I have explained it in understandable format. Thank You,

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  • How to set up a specific registration on Database

    - by ymorenz
    I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

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  • Which of these queries is more efficient?

    - by Brian
    Which of these queries are more efficient? select 1 as newAndClosed from sysibm.sysdummy1 where exists ( select 1 from items where new = 1 ) and not exists ( select 1 from status where open = 1 ) select 1 as newAndClosed from items where new = 1 and not exists ( select 1 from status where open = 1 )

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  • SQL - Query to display average as either "longer than" or "shorter than"

    - by user1840801
    Here are the tables I've created: CREATE TABLE Plane_new (Pnum char(3), Feature varchar2(20), Ptype varchar2(15), primary key (Pnum)); CREATE TABLE Employee_new (eid char(3), ename varchar(10), salary number(7,2), mid char(3), PRIMARY KEY (eid), FOREIGN KEY (mid) REFERENCES Employee_new); CREATE TABLE Pilot_new (eid char(3), Licence char(9), primary key (eid), foreign key (eid) references Employee_new on delete cascade); CREATE TABLE FlightI_new (Fnum char(4), Fdate date, Duration number(2), Pid char(3), Pnum char(3), primary key (Fnum), foreign key (Pid) references Pilot_new (eid), foreign key (Pnum) references Plane_new); And here is the query I must complete: For each flight, display its number, the name of the pilot who implemented the flight and the words ‘Longer than average’ if the flight duration was longer than average or the words ‘Shorter than average’ if the flight duration was shorter than or equal to the average. For the column holding the words ‘Longer than average’ or ‘Shorter than average’ make a header Length. Here is what I've come up with - with no luck! SELECT F.Fnum, E.ename, CASE Length WHEN F.Duration>(SELECT AVG(F.Duration) FROM FlightI_new F) THEN "Longer than average" WHEN F.Duration<=(SELECT AVG(F.Duration) FROM FlightI_new F) THEN 'Shorter than average' END FROM FlightI_new F LEFT OUTER JOIN Employee_new E ON F.Pid=E.eid GROUP BY F.Fnum, E.ename; Where am I going wrong?

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  • MySQLi - Should every statement be prepared?

    - by Kerry
    I know its supposed to improve performance and clean strings, but lets say there are no variables? Might just be a SELECT COUNT( `column` ) AS count FROM `table` Should that be prepared? Is there any case that a SELECT statement should not be prepared?

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  • PHP - Get value of imput box, without a form?

    - by Dodi300
    Hello. Does anyone know how I can get the value of an imput box, without having a form? I want a sumbit button, but instead of submiting a form, I want it to change data in a MySQL database. Something like this maybe? $img1="WHAT DO I PUT HERE?" $idx=1 $sql="INSERT INTO games SET img1='$img1' WHERE id=$idx"; $result=mysql_query($sql); Could I use that code on a "onclick" event? The imput box is named "img1". Thanks for the help!

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  • Docmd.TransferText to update data

    - by every_answer_gets_a_point
    i am using Docmd.TransferText to import data from a text file into my access table. i would like it to do the following: if the record already exists, then update it if the record does not exist then add it how do i accomplish this? currently i have this line: DoCmd.TransferText acImportDelim, yesyes, "table3", "C:\requisition_data_dump.txt", True

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  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

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  • LOAD DATA LOCAL INFILE custom value

    - by NR03
    How to add a custom value using LOAD DATA LOCAL INFILE? The column time_added is the 7th column and the file has only 2 values for the first and the second column. For the 7th column, time_added I want to use the unix timestamp when loading from file. This code isn't working: $result = mysql_query("LOAD DATA LOCAL INFILE '{$myFile}' INTO TABLE {$table} FIELDS TERMINATED BY ':' LINES TERMINATED BY '\n' SET `time_added`=unix_timestamp()");

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  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

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  • treating paramater as literal

    - by I__
    DoCmd.TransferText acImportDelim, Import-Accounts, "tableImport", _ "C:\Documents and Settings\accounts.txt", True The second parameter: Import-Accounts is the actual name of the saved import specifications. supposedly it does NOT need to be in quotes; however in this case since there is a - there it is treating it as if i were doing an operation. is there a way i can force it to treat it literally instead of as an operation?

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  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

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  • Android-SQLite: How to Count specific value from Column?

    - by sanpatil
    I have two table (TABLE_EXAM,TABLE_RESULT). Here is value of my TABLE_RESULT. result_id exam_id question_id correct_answer 1 2 4 y 2 2 5 y 3 2 6 n 4 2 7 y I need to count how many correct_answer='y' where exam_id=2. I try following code but it return 0. public int calculateResult(int examId,String confirmAnswer) { int correctAnswer=0; try { SQLiteDatabase db=this.getWritableDatabase(); String selectQuery=("select count(correctAnswer) from result where exam_id ='" + examId + "' and correctAnswer ='" + 'y' +"'" ); // String selectQuery=("SELECT COUNT(*)FROM result WHERE exam_id ='" + examId + "' and correctAnswer ='" + confirmAnswer +"'" ); Cursor cursor = db.rawQuery(selectQuery, null); if(cursor.moveToLast()) { correctAnswer=cursor.getInt(3); } } catch(Exception e) { e.printStackTrace(); } return correctAnswer; } In variable confirm_answer i pass "y". Give me some hint or reference. Any help is appreciated. Thanks in Advance

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  • Show the specific field on mysql table based on active date

    - by mrjimoy_05
    Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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