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  • Can per-user randomized salts be replaced with iterative hashing?

    - by Chas Emerick
    In the process of building what I'd like to hope is a properly-architected authentication mechanism, I've come across a lot of materials that specify that: user passwords must be salted the salt used should be sufficiently random and generated per-user ...therefore, the salt must be stored with the user record in order to support verification of the user password I wholeheartedly agree with the first and second points, but it seems like there's an easy workaround for the latter. Instead of doing the equivalent of (pseudocode here): salt = random(); hashedPassword = hash(salt . password); storeUserRecord(username, hashedPassword, salt); Why not use the hash of the username as the salt? This yields a domain of salts that is well-distributed, (roughly) random, and each individual salt is as complex as your salt function provides for. Even better, you don't have to store the salt in the database -- just regenerate it at authentication-time. More pseudocode: salt = hash(username); hashedPassword = hash(salt . password); storeUserRecord(username, hashedPassword); (Of course, hash in the examples above should be something reasonable, like SHA-512, or some other strong hash.) This seems reasonable to me given what (little) I know of crypto, but the fact that it's a simplification over widely-recommended practice makes me wonder whether there's some obvious reason I've gone astray that I'm not aware of.

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  • Getting a connection from a Sybase datasource in WAS 6.1 fails with message "User name property miss

    - by Abel Morelos
    I have a standalone application that needs to connect to a Sybase database via a datasource, I'm trying to connect using getConnection() and get the connection from this Sybase datasource which is hosted in WAS 6.1, sadly I'm getting an error JZ004 - Sybase(R) jConnect for JDBC(TM) Programmer's Reference: SQL Exception and Warning Messages JZ004 error message is: User name property missing in DriverManager.getConnection(..., Properties) Action: Provide the required user property. As you can see, this is not a connectivity (so we can discard JNDI or lookup problems), but rather a configuration problem. For my Sybase datasource in WAS 6.1 I have set up the proper authentication alias (Component-managed Authentication Alias), and I know the credentials are alright, "Test Connection" is successful for this datasource. Somebody had a similar problem and was because of the authentication alias- http://forum.springsource.org/showthread.php?t=39915 Next, I tried calling getConnection() but now I provided the credentials like getConnection(user, password)... and this time it worked!!! So I suspect that somehow WAS 6.1 is not picking or taking the authentication info I set in the datasource as mentioned before. If you think that maybe getConnection(user, password) should be OK for my case, well, that's not the case since I have a requirement to keep the credentials in the server, the standalone application only needs to know the JNDI information to lookup the datasource. Please let me know if have faced a similar problem, or what would you suggest me to do. Thanks.

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  • Sanitizing user input that will later be e-mailed - what should I be worried about?

    - by Kevin Burke
    I'm interning for an NGO in India (Seva Mandir, http://sevamandir.org) and trying to fix their broken "subscribe to newsletter" box. Because the staff isn't very sophisticated and our web host isn't great, I decided to send the relevant data to the publications person via mail() instead of storing it in a MySQL database. I know that it's best to treat user input as malicious, and I've searched the SO forums for posts relevant to escaping user data for sending in a mail message. I know the data should be escaped; what should I be worried about and what's the best way to sanitize the input before emailing it? Form flow: 1. User enters email on homepage and clicks Submit 2. User enters name, address, more information on second page (bad usability, I know, but my boss asked me to) and clicks "Submit" 3. Collect the data via $_POST and email it to the publications editor (and possibly send a confirmation to the subscriber). I am going to sanitize the email in step 2 and the other data in step 3. I appreciate your help, Kevin

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  • Setting a profile property in asp.net MVC while creating a user.

    - by twal
    In my application, an authorized user will Register a new customer and set their username and password, etc. The customer will not be registering them self. I have the following code in a class file which creates the new user, and it works just fine. public MembershipCreateStatus CreateUser(string userName, string password, string email, string employeeID) { if (String.IsNullOrEmpty(userName)) throw new ArgumentException("Value cannot be null or empty.", "userName"); if (String.IsNullOrEmpty(password)) throw new ArgumentException("Value cannot be null or empty.", "password"); if (String.IsNullOrEmpty(email)) throw new ArgumentException("Value cannot be null or empty.", "email"); MembershipCreateStatus status; /// _membershipProvider.CreateUser("asdas","ds123BB", email, "asdasd", "asdasdad", true, null, out status); _membershipProvider.CreateUser(userName, password, email, null, null, true, null, out status); string answer = status.ToString(); return status; } However I would also like to set an employeeID property for the profile when creating this user. how would I set the EmployeeID when creating a new user?? Thanks

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  • we would like the user to be able to pick a file from native file system and drag & drop it to our a

    - by user261740
    We have an existing java desktop application which starts, when user click on our application icon (placed on desktop) OR double click on executable(.exe). It opens the frame which allows user to select the file from native file system and uploads it to the server. Now we would like to facilitate user, that he can pick a file from windows explorer and drag it to the "shortcut / Application icon" & drop it on the "shortcut / Application icon" on the desktop. This would start the uploading of that file on the server. we need to capture the action of "drop" and launch on shortcut.. which may be completely not related to java, it can be very generic to any application. We are using JSmooth to build an executable from jar and NSIS for installer purpose. I would like to know.. How we can launch the application if user drops local file onto the system icon ? How we get the absolute path of file name which has been dropped onto the executable ?

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  • Why is my user control not instanciated on a postback?

    - by Antoine
    Hi, I'd like to set the trigger of an UpdatePanel to a user control outside the UpdatePanel on the same page . The user control is added at design time, not at runtime. If I statically declare the trigger, I get an error "A control with ID 'xx' cannot be found for the trigger in UpdatePanel". I tried to add the trigger at runtime in Page_Init or Page_Load, but it fails with the user control being null, although it has ViewState enabled. Has someone an idea on how to solve this? Here is the code of the user control: <%@ Control Language="C#" AutoEventWireup="true" CodeFile="ComponentDropDownControl.ascx.cs" Inherits="ComponentDropDownControl" EnableViewState="true" %> <asp:DropDownList ID="ComponentDropDown" runat="server" DataSourceID="ComponentFile" DataTextField="name" DataValueField="name" OnSelectedIndexChanged="ComponentDropDown_SelectedIndexChanged" AutoPostBack="True" EnableTheming="True"> </asp:DropDownList><asp:XmlDataSource ID="ComponentFile" runat="server" DataFile="~/App_Data/Components.xml" XPath="//component"></asp:XmlDataSource> And here it is in the aspx page: <%@ Page Language="C#" MasterPageFile="~/MasterPage.master" AutoEventWireup="true" CodeFile="create.aspx.cs" Inherits="create" Title="Create task" %> <%@ Register Src="ComponentDropDownControl.ascx" TagName="ComponentDropDownControl" TagPrefix="uc1" %> ... <uc1:ComponentDropDownControl ID="CustomComponentDropDown" runat="server" EnableViewState="true" /> In the Page_Load function of the aspx page, the following lines work at first time, but fail on the first PostBack (line 2, CustomComponentDropDown is null). AsyncPostBackTrigger trigger = new AsyncPostBackTrigger(); trigger.ControlID = CustomComponentDropDown.UniqueID.ToString(); UpdatePanel1.Triggers.Add(trigger);

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  • How would a user stay logged in to a REST-based website?

    - by unforgiven3
    A year or so ago I asked this question: Can you help me understand this? “Common REST Mistakes: Sessions are irrelevant”. My question was essentially this: Okay, I get that HTTP authentication is done automatically on every message - but how? Is the username/password sent with every request? Doesn't that just increase attack surface area? I feel like I'm missing part of the puzzle. The answers I received made perfect sense in the context of a mobile (iPhone, Android, WP7) app - when talking to a REST service, the app would just send user credentials along with each request. That worked great for me. But now, I would like to better understand how one would secure a REST-like website, like StackOverflow itself or something like Reddit. How would things work if it was a user logged in via a web browser instead of logged in via an iPhone app? What happens when a user logs in? Are the credentials saved in the browser somehow? How would the browser know what credentials to send with subsequent REST requests? What if it's a JavaScript call to a webservice? How would the JavaScript call include user credentials? I'll be quite frank: my understanding of security when it comes to websites is pretty limited. I enjoyed working with REST services from an app perspective, but now I want to try and build a website that is based on REST principles, and I'm finding myself to be pretty lost. If there is anything in the above question that is unclear that you'd like me to clarify, please leave a comment and I'll address it.

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  • can bind successfully to the ldap server, but needs to know how to find user w/i AD

    - by Brad
    I create a login form to bind to the ldap server, if successful, it creates a session (which the user's username is stored within), then I go to another page that has session_start(); and it works fine. What I want to do now, is add code to test if that user is a member of a specific group. So in theory, this is what I want to do if(username session is valid) { search ldap for user -> get list of groups user is member of foreach(group they are member of) { switch(group) { case STAFF: print 'they are member of staff group'; $access = true; break; default: print 'not a member of STAFF group'; $access = false; break; } if(group == STAFF) { break; } } if($access == TRUE) { // you have access to the content on this page } else { // you do not have access to this page } } How do I do a ldap_search w/o binding? I don't want to keep asking for their password on each page, and I can't pass their password thru a session. Any help is appreciated.

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  • When do Symfony's user attributes get written to session?

    - by Rob Wilkerson
    I have a Symfony app that populates the "widgets" of a portal application and I'm noticing something (that seems) odd. The portal app has iframes that make calls to the Symfony app. On each of those calls, a random user key is passed on the query string. The Symfony app stores that key its session using myUser->setAttribute(). If the incoming value is different from what it has in session, it overwrites the session value. In pseudo-code (and applying a synchronous nature for clarity even though it may not exist): # Widget request arrives with ?foo=bar if the user attribute 'foo' does not equal 'bar' overwrite the user attribute 'foo' with 'bar' end What I'm noticing is that, on a portal page with multiple widgets (read: multiple requests coming in more or less simultaneously) where the value needs to be overwritten, each request is trying to overwrite. Is this a timing problem? When I look at the log prints, I'd expect the first request that arrives to overwrite and subsequent requests to see that the user attribute they received matches what was just put into cache by the initial request. In this scenario, it could be that subsequent requests begin (and are checked) even before the first one--the one that should overwrite the cached value--has completely finished. Are session values not really available to subsequent requests until one request has completed entirely or could there be something else that I'm missing? Thanks.

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  • Very Urgent :How to start a new session if a user click on the new tab in IE or mozilla on websphere

    - by ha22109
    Hi, I have one "user search" portlet on the home page of one application running on websphere portal server.Which display the matching user records as per the search criteria filled in the search form.I have requirement to have a "back to search input" link on the results page which onclick should show the filled form on the input jsp. The issue which i am facing is if i open the application in two diff tab of same IE browser and start giving some search criteria and submit and same time search for some other input from other IE tab (in the same browser)and then go back to previous tab and click on "back to search input" link then instead of showing me the first input it will show me the imput which i entered in the next IE tab. I am setting and getting the bean(form bean) through portlet session.but in the two diff tab of same IE it will be the sae user session (and may be the same portlet session..) Please tell me solution for this. The one thing to be notice here is i can access this "user search" application even without doing login also.so it must be taking the default portlet session in this case. what wil happen once i login and then search,will it going to overwrite the portlet session and http session or howz is that?

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  • How to get full control of umask/PAM/permissions?

    - by plua
    OUR SITUATION Several people from our company log in to a server and upload files. They all need to be able to upload and overwrite the same files. They have different usernames, but are all part of the same group. However, this is an internet server, so the "other" users should have (in general) just read-only access. So what I want to have is these standard permissions: files: 664 directories: 771 My goal is that all users do not need to worry about permissions. The server should be configured in such a way that these permissions apply to all files and directories, newly created, copied, or over-written. Only when we need some special permissions we'd manually change this. We upload files to the server by SFTP-ing in Nautilus, by mounting the server using sshfs and accessing it in Nautilus as if it were a local folder, and by SCP-ing in the command line. That basically covers our situation and what we aim to do. Now, I have read many things about the beautiful umask functionality. From what I understand umask (together with PAM) should allow me to do exactly what I want: set standard permissions for new files and directories. However, after many many hours of reading and trial-and-error, I still do not get this to work. I get many unexpected results. I really like to get a solid grasp of umask and have many question unanswered. I will post these questions below, together with my findings and an explanation of my trials that led to these questions. Given that many things appear to go wrong, I think that I am doing several things wrong. So therefore, there are many questions. NOTE: I am using Ubuntu 9.10 and therefore can not change the sshd_config to set the umask for the SFTP server. Installed SSH OpenSSH_5.1p1 Debian-6ubuntu2 < required OpenSSH 5.4p1. So here go the questions. 1. DO I NEED TO RESTART FOR PAM CHANGS TO TAKE EFFECT? Let's start with this. There were so many files involved and I was unable to figure out what does and what does not affect things, also because I did not know whether or not I have to restart the whole system for PAM changes to take effect. I did do so after not seeing the expected results, but is this really necessary? Or can I just log out from the server and log back in, and should new PAM policies be effective? Or is there some 'PAM' program to reload? 2. IS THERE ONE SINGLE FILE TO CHANGE THAT AFFECTS ALL USERS FOR ALL SESSIONS? So I ended up changing MANY files, as I read MANY different things. I ended up setting the umask in the following files: ~/.profile -> umask=0002 ~/.bashrc -> umask=0002 /etc/profile -> umask=0002 /etc/pam.d/common-session -> umask=0002 /etc/pam.d/sshd -> umask=0002 /etc/pam.d/login -> umask=0002 I want this change to apply to all users, so some sort of system-wide change would be best. Can it be achieved? 3. AFTER ALL, THIS UMASK THING, DOES IT WORK? So after changing umask to 0002 at every possible place, I run tests. ------------SCP----------- TEST 1: scp testfile (which has 777 permissions for testing purposes) server:/home/ testfile 100% 4 0.0KB/s 00:00 Let's check permissions: user@server:/home$ ls -l total 4 -rwx--x--x 1 user uploaders 4 2011-02-05 17:59 testfile (711) ---------SSH------------ TEST 2: ssh server user@server:/home$ touch anotherfile user@server:/home$ ls -l total 4 -rw-rw-r-- 1 user uploaders 0 2011-02-05 18:03 anotherfile (664) --------SFTP----------- Nautilus: sftp://server/home/ Copy and paste newfile from client to server (777 on client) TEST 3: user@server:/home$ ls -l total 4 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 newfile (777) Create a new file through Nautilus. Check file permissions in terminal: TEST 4: user@server:/home$ ls -l total 4 -rw------- 1 user uploaders 0 2011-02-05 18:06 newfile (600) I mean... WHAT just happened here?! We should get 644 every single time. Instead I get 711, 777, 600, and then once 644. And the 644 is only achieved when creating a new, blank file through SSH, which is the least probable scenario. So I am asking, does umask/pam work after all? 4. SO WHAT DOES IT MEAN TO UMASK SSHFS? Sometimes we mount a server locally, using sshfs. Very useful. But again, we have permissions issues. Here is how we mount: sshfs -o idmap=user -o umask=0113 user@server:/home/ /mnt NOTE: we use umask = 113 because apparently, sshfs starts from 777 instead of 666, so with 113 we get 664 which is the desired file permission. But what now happens is that we see all files and directories as if they are 664. We browse in Nautilus to /mnt and: Right click - New File (newfile) --- TEST 5 Right click - New Folder (newfolder) --- TEST 6 Copy and paste a 777 file from our local client --- TEST 7 So let's check on the command line: user@client:/mnt$ ls -l total 8 -rw-rw-r-- 1 user 1007 3 Feb 5 18:05 copyfile (664) -rw-rw-r-- 1 user 1007 0 Feb 5 18:15 newfile (664) drw-rw-r-- 1 user 1007 4096 Feb 5 18:15 newfolder (664) But hey, let's check this same folder on the server-side: user@server:/home$ ls -l total 8 -rwxrwxrwx 1 user uploaders 3 2011-02-05 18:05 copyfile (777) -rw------- 1 user uploaders 0 2011-02-05 18:15 newfile (600) drwx--x--x 2 user uploaders 4096 2011-02-05 18:15 newfolder (711) What?! The REAL file permissions are very different from what we see in Nautilus. So does this umask on sshfs just create a 'filter' that shows unreal file permissions? And I tried to open a file from another user but the same group that had real 600 permissions but 644 'fake' permissions, and I could still not read this, so what good is this filter?? 5. UMASK IS ALL ABOUT FILES. BUT WHAT ABOUT DIRECTORIES? From my tests I can see that the umask that is being applied also somehow influences the directory permissions. However, I want my files to be 664 (002) and my directories to be 771 (006). So is it possible to have a different umask for directories? 6. PERHAPS UMASK/PAM IS REALLY COOL, BUT UBUNTU IS JUST BUGGY? On the one hand, I have read topics of people that have had success with PAM/UMASK and Ubuntu. On the other hand, I have found many older and newer bugs regarding umask/PAM/fuse on Ubuntu: https://bugs.launchpad.net/ubuntu/+source/gdm/+bug/241198 https://bugs.launchpad.net/ubuntu/+source/fuse/+bug/239792 https://bugs.launchpad.net/ubuntu/+source/pam/+bug/253096 https://bugs.launchpad.net/ubuntu/+source/sudo/+bug/549172 http://bugs.debian.org/cgi-bin/bugreport.cgi?bug=314796 So I do not know what to believe anymore. Should I just give up? Would ACL solve all my problems? Or do I have again problems using Ubuntu? One word of caution with backups using tar. Red Hat /Centos distributions support acls in the tar program but Ubuntu does not support acls when backing up. This means that all acls will be lost when you create a backup. I am very willing to upgrade to Ubuntu 10.04 if that would solve my problems too, but first I want to understand what is happening.

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  • ASP.NET MVC 3: Layouts and Sections with Razor

    - by ScottGu
    This is another in a series of posts I’m doing that cover some of the new ASP.NET MVC 3 features: Introducing Razor (July 2nd) New @model keyword in Razor (Oct 19th) Layouts with Razor (Oct 22nd) Server-Side Comments with Razor (Nov 12th) Razor’s @: and <text> syntax (Dec 15th) Implicit and Explicit code nuggets with Razor (Dec 16th) Layouts and Sections with Razor (Today) In today’s post I’m going to go into more details about how Layout pages work with Razor.  In particular, I’m going to cover how you can have multiple, non-contiguous, replaceable “sections” within a layout file – and enable views based on layouts to optionally “fill in” these different sections at runtime.  The Razor syntax for doing this is clean and concise. I’ll also show how you can dynamically check at runtime whether a particular layout section has been defined, and how you can provide alternate content (or even an alternate layout) in the event that a section isn’t specified within a view template.  This provides a powerful and easy way to customize the UI of your site and make it clean and DRY from an implementation perspective. What are Layouts? You typically want to maintain a consistent look and feel across all of the pages within your web-site/application.  ASP.NET 2.0 introduced the concept of “master pages” which helps enable this when using .aspx based pages or templates.  Razor also supports this concept with a feature called “layouts” – which allow you to define a common site template, and then inherit its look and feel across all the views/pages on your site. I previously discussed the basics of how layout files work with Razor in my ASP.NET MVC 3: Layouts with Razor blog post.  Today’s post will go deeper and discuss how you can define multiple, non-contiguous, replaceable regions within a layout file that you can then optionally “fill in” at runtime. Site Layout Scenario Let’s look at how we can implement a common site layout scenario with ASP.NET MVC 3 and Razor.  Specifically, we’ll implement some site UI where we have a common header and footer on all of our pages.  We’ll also add a “sidebar” section to the right of our common site layout.  On some pages we’ll customize the SideBar to contain content specific to the page it is included on: And on other pages (that do not have custom sidebar content) we will fall back and provide some “default content” to the sidebar: We’ll use ASP.NET MVC 3 and Razor to enable this customization in a nice, clean way.  Below are some step-by-step tutorial instructions on how to build the above site with ASP.NET MVC 3 and Razor. Part 1: Create a New Project with a Layout for the “Body” section We’ll begin by using the “File->New Project” menu command within Visual Studio to create a new ASP.NET MVC 3 Project.  We’ll create the new project using the “Empty” template option: This will create a new project that has no default controllers in it: Creating a HomeController We will then right-click on the “Controllers” folder of our newly created project and choose the “Add->Controller” context menu command.  This will bring up the “Add Controller” dialog: We’ll name the new controller we create “HomeController”.  When we click the “Add” button Visual Studio will add a HomeController class to our project with a default “Index” action method that returns a view: We won’t need to write any Controller logic to implement this sample – so we’ll leave the default code as-is.  Creating a View Template Our next step will be to implement the view template associated with the HomeController’s Index action method.  To implement the view template, we will right-click within the “HomeController.Index()” method and select the “Add View” command to create a view template for our home page: This will bring up the “Add View” dialog within Visual Studio.  We do not need to change any of the default settings within the above dialog (the name of the template was auto-populated to Index because we invoked the “Add View” context menu command within the Index method).  When we click the “Add” Button within the dialog, a Razor-based “Index.cshtml” view template will be added to the \Views\Home\ folder within our project.  Let’s add some simple default static content to it: Notice above how we don’t have an <html> or <body> section defined within our view template.  This is because we are going to rely on a layout template to supply these elements and use it to define the common site layout and structure for our site (ensuring that it is consistent across all pages and URLs within the site).  Customizing our Layout File Let’s open and customize the default “_Layout.cshtml” file that was automatically added to the \Views\Shared folder when we created our new project: The default layout file (shown above) is pretty basic and simply outputs a title (if specified in either the Controller or the View template) and adds links to a stylesheet and jQuery.  The call to “RenderBody()” indicates where the main body content of our Index.cshtml file will merged into the output sent back to the browser. Let’s modify the Layout template to add a common header, footer and sidebar to the site: We’ll then edit the “Site.css” file within the \Content folder of our project and add 4 CSS rules to it: And now when we run the project and browse to the home “/” URL of our project we’ll see a page like below: Notice how the content of the HomeController’s Index view template and the site’s Shared Layout template have been merged together into a single HTML response.  Below is what the HTML sent back from the server looks like: Part 2: Adding a “SideBar” Section Our site so far has a layout template that has only one “section” in it – what we call the main “body” section of the response.  Razor also supports the ability to add additional "named sections” to layout templates as well.  These sections can be defined anywhere in the layout file (including within the <head> section of the HTML), and allow you to output dynamic content to multiple, non-contiguous, regions of the final response. Defining the “SideBar” section in our Layout Let’s update our Layout template to define an additional “SideBar” section of content that will be rendered within the <div id=”sidebar”> region of our HTML.  We can do this by calling the RenderSection(string sectionName, bool required) helper method within our Layout.cshtml file like below:   The first parameter to the “RenderSection()” helper method specifies the name of the section we want to render at that location in the layout template.  The second parameter is optional, and allows us to define whether the section we are rendering is required or not.  If a section is “required”, then Razor will throw an error at runtime if that section is not implemented within a view template that is based on the layout file (which can make it easier to track down content errors).  If a section is not required, then its presence within a view template is optional, and the above RenderSection() code will render nothing at runtime if it isn’t defined. Now that we’ve made the above change to our layout file, let’s hit refresh in our browser and see what our Home page now looks like: Notice how we currently have no content within our SideBar <div> – that is because the Index.cshtml view template doesn’t implement our new “SideBar” section yet. Implementing the “SideBar” Section in our View Template Let’s change our home-page so that it has a SideBar section that outputs some custom content.  We can do that by opening up the Index.cshtml view template, and by adding a new “SiderBar” section to it.  We’ll do this using Razor’s @section SectionName { } syntax: We could have put our SideBar @section declaration anywhere within the view template.  I think it looks cleaner when defined at the top or bottom of the file – but that is simply personal preference.  You can include any content or code you want within @section declarations.  Notice above how I have a C# code nugget that outputs the current time at the bottom of the SideBar section.  I could have also written code that used ASP.NET MVC’s HTML/AJAX helper methods and/or accessed any strongly-typed model objects passed to the Index.cshtml view template. Now that we’ve made the above template changes, when we hit refresh in our browser again we’ll see that our SideBar content – that is specific to the Home Page of our site – is now included in the page response sent back from the server: The SideBar section content has been merged into the proper location of the HTML response : Part 3: Conditionally Detecting if a Layout Section Has Been Implemented Razor provides the ability for you to conditionally check (from within a layout file) whether a section has been defined within a view template, and enables you to output an alternative response in the event that the section has not been defined.  This provides a convenient way to specify default UI for optional layout sections.  Let’s modify our Layout file to take advantage of this capability.  Below we are conditionally checking whether the “SideBar” section has been defined without the view template being rendered (using the IsSectionDefined() method), and if so we render the section.  If the section has not been defined, then we now instead render some default content for the SideBar:  Note: You want to make sure you prefix calls to the RenderSection() helper method with a @ character – which will tell Razor to execute the HelperResult it returns and merge in the section content in the appropriate place of the output.  Notice how we wrote @RenderSection(“SideBar”) above instead of just RenderSection(“SideBar”).  Otherwise you’ll get an error. Above we are simply rendering an inline static string (<p>Default SideBar Content</p>) if the section is not defined.  A real-world site would more likely refactor this default content to be stored within a separate partial template (which we’d render using the Html.RenderPartial() helper method within the else block) or alternatively use the Html.Action() helper method within the else block to encapsulate both the logic and rendering of the default sidebar. When we hit refresh on our home-page, we will still see the same custom SideBar content we had before.  This is because we implemented the SideBar section within our Index.cshtml view template (and so our Layout rendered it): Let’s now implement a “/Home/About” URL for our site by adding a new “About” action method to our HomeController: The About() action method above simply renders a view back to the client when invoked.  We can implement the corresponding view template for this action by right-clicking within the “About()” method and using the “Add View” menu command (like before) to create a new About.cshtml view template.  We’ll implement the About.cshtml view template like below. Notice that we are not defining a “SideBar” section within it: When we browse the /Home/About URL we’ll see the content we supplied above in the main body section of our response, and the default SideBar content will rendered: The layout file determined at runtime that a custom SideBar section wasn’t present in the About.cshtml view template, and instead rendered the default sidebar content. One Last Tweak… Let’s suppose that at a later point we decide that instead of rendering default side-bar content, we just want to hide the side-bar entirely from pages that don’t have any custom sidebar content defined.  We could implement this change simply by making a small modification to our layout so that the sidebar content (and its surrounding HTML chrome) is only rendered if the SideBar section is defined.  The code to do this is below: Razor is flexible enough so that we can make changes like this and not have to modify any of our view templates (nor make change any Controller logic changes) to accommodate this.  We can instead make just this one modification to our Layout file and the rest happens cleanly.  This type of flexibility makes Razor incredibly powerful and productive. Summary Razor’s layout capability enables you to define a common site template, and then inherit its look and feel across all the views/pages on your site. Razor enables you to define multiple, non-contiguous, “sections” within layout templates that can be “filled-in” by view templates.  The @section {} syntax for doing this is clean and concise.  Razor also supports the ability to dynamically check at runtime whether a particular section has been defined, and to provide alternate content (or even an alternate layout) in the event that it isn’t specified.  This provides a powerful and easy way to customize the UI of your site - and make it clean and DRY from an implementation perspective. Hope this helps, Scott P.S. In addition to blogging, I am also now using Twitter for quick updates and to share links. Follow me at: twitter.com/scottgu

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  • window services works after local account used before this account

    - by Gauls
    Hi All of a sudden my window services app after installation does not start(Some services stop automatically if they have no work to do) uses custom user, if i change the logon setting to use local system account and click start works fine, then when i go back and change to use this account (local user- custom user under user group) and then click start it works fine, why didn't work in the first place???????????? Thanks

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  • How to make a custom Windows 8 installation

    - by Nison Maël
    What is the step-by-step way to make a custom Windows 8 installation ? For example, with a minimal example, I would like an image which : Has a single user named "User" This user has Chrome and Firefox installed Has no link in the start screen except the desktop link Has no buttons on the task bar I have tried to use sysprep but I lose user settings. The CopyProfile seems to apply Administrator's settings on programmaticaly created accounts, but does not preserve local users settings accross installations.

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  • Rsync --backup-dir seems to be ignored

    - by Patrik
    I want to use rsync to backup a directory from a local location to a remote location, and store changed files in another remote location. I did use: rsync -rcvhL --progress --backup [email protected]:/home/user/Changes/`date +%Y.%m.%d` . [email protected]:/home/user/Files/ The --backup-dir stays empty, while it should be filled. Is it possible what I try to accomplish, and am I doing something wrong? Thanks

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  • Make windows XP ask for password

    - by daramarak
    We have software that have some features that are so sensitive that we want to verify the identity of the user. Instead of using a own user/password scheme we would really like to either test the password against the user password in XP, or even make Windows self reauthenticate the user so we can make sure that it is an authorized person that accesses the function. Or software is only running on windows XP embedded. I do not know if this is possible at all, does windows have any such features?

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  • dynamically allocating space for variable in ksh

    - by Govind Rajan
    I am new to ksh unix shell scripting.I need my ksh script to get inputs from the user. and the number of inputs is unkown. I need to get the inputs and process again further .The sample run could be : Enter the input values : Hello how are you Select two values from the above : how you Here the italized text are the inputs from the user.The inputs number given by the user is unknown .I down know how to handle the values given by user. Thanks in advance

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  • share git rep access on unix machine with ssh

    - by Daniel
    at my school we have a student unix server with our accounts. i have installed git on my account, created a repository, and created the acl permissions on the folder repository so other users can access the repository # file: tp1 # owner: my_account # group: groupxxx user::rwx user:friend_account:rwx group::--- mask::rwx other::--- default:user::rwx default:user:friend_account:rwx default:group::--- default:mask::rwx default:other::--- but friend_account cant even cd to my tp1 directory (permission denied), so i think the problem should be in unix acl permissions..

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  • windows 2000 domain controller

    - by Chris
    in active directory 2000 server i have 5 groups of users and every user has different policies. The problem is that a different desktop loads for only one specific user no matter what changes i make in administrative templates. If i copy this user profile and paste it to another group with a different name windows workaround loads as it should but some policies are not applied. Does anybody know a way to solve this problem instead of creating a new group and user from scratch?

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  • The best terminal emulator for a heavy terminal user?

    - by Noah Goodrich
    I spend a lot of time at the command-line during the workday and at home too since I run Ubuntu exclusively. I've been using the default gnome terminal but I've reached a point where I'd really like to get my terminal tricked out so that my common tasks are as easy as possible. Specifically, I find that I spend of lot of time browsing code in the terminal and working in config files. On my wish list would be: Ability to have multiple screens, tabs, windows (I don't have a preference at this point) that I can easily switch between. Color coding for everything Easy to modify the aesthetics of the terminal (is it vain to want my terminal to look nice?) such as transparency, borders, etc.

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  • How get an Android ListPreference defined in Xml whose values are integers?

    - by Rob Kent
    Is it possible to define a ListPreference in Xml and retrieve the value from SharedPreferences using getInt? Here is my Xml: <ListPreference android:key="@string/prefGestureAccuracyKey" android:title="@string/prefGestureAccuracyTitle" android:summary="@string/prefGestureAccuracyDesc" android:entries="@array/prefNumberAccuracyLabels" android:entryValues="@array/prefNumberAccuracyValues" android:dialogTitle="@string/prefGestureAccuracyDialog" android:persistent="true" android:defaultValue="2" android:shouldDisableView="false" /> And I want to get the value with something like: int val = sharedPrefs.getInt(key, defaultValue). At the moment I have to use getString and parse the result.

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  • How to make a file load in my program when a user double clicks an associated file.

    - by Edward Boyle
    I assume in this article that file extension association has been setup by the installer. I may address file extension association at a later date, but for the purpose of this article, I address what sometimes eludes new C# programmers. This is sometimes confusing because you just don’t think about it — you have to access a file that you rarely access when making Windows forms applications, “Program.cs” static class Program { /// /// The main entry point for the application. /// [STAThread] static void Main() { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Application.Run(new Form1()); } } There are so many ways to skin this cat, so you get to see how I skinned my last cat. static class Program { /// /// The main entry point for the application. /// [STAThread] static void Main(string[] args) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Form1 mainf = new Form1(); if (args.Length > 0) { try { if (System.IO.File.Exists(args[0])) { mainf.LoadFile= args[0]; } } catch { MessageBox.Show("Could not open file.", "Could not open file.", MessageBoxButtons.OK, MessageBoxIcon.Information); } } Application.Run(mainf); } } It may be easy to miss, but don’t forget to add the string array for the command line arguments: static void Main(string[] args) this is not a part of the default program.cs You will notice the mainf.LoadFile property. In the main form of my program I have a property for public string LoadFile ... and the field private string loadFile = String.Empty; in the forms load event I check the value of this field. private void Form1_Load(object sender, EventArgs e) { if(loadFile != String.Empty){ // The only way this field is NOT String.empty is if we set it in // static void Main() of program.cs // LOAD it however it is needed OpenFile, SetDatabase, whatever you use. } }

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  • Django - model.save(commit=False - Is there a way to replicate this?

    - by orokusaki
    I'm wanting to do this: from django.contrib.auth.models import User class PetFrog(models.Model): user = models.OnetoOneField(User) color = models.CharField(max_length=20) def clean(self): if self.color == 'Green': user = User(username='prince') user.save(commit=False) # No commit argument in models.Model.save() like there is in ModelForm.save() user.set_password(self.password) user.save() self.user = user Is there a way to do this creation of a model instance without filling in all the required fields, and then setting them manually before trying to save() for real (which would obviously raise a "Must choose a Password" error)? I need to do this in my model, vs using a ModelForm. If there is another way to do it (while still in clean()), I'm completely open to any suggestions.

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