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  • Post and get at the same time in php

    - by user225269
    Do you have any suggestions with my problem. I need to use get and post at the same time. Get because I need to output what the user has typed. And post because I need to access the mysql database in relation to that input. It looks something like this: <form name="x" method="get" action="x.php"> <input name="year" type="text"> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> </form> This will output the contents of mysql depending on what the user will check: <form name="y" method="post" action"y.php"> <input name="fname" type="checkbox"> </form> And the form action of those two combined will look something like this: <?php if($_POST['general'] == 'YEAR'){ ?> <?php echo $_GET["year"]; ?> <?php $result2 = mysql_query("SELECT * FROM student WHERE student.YEAR='$syear'"); ?> <table border='1'> <tr> <?php if ( $ShowLastName ) { ?><th>LASTNAME</th><?php } ?> <?php if ( $ShowFirstName ) { ?><th>FIRSTNAME</th><?php } ?> </tr> <?php while ( $row = mysql_fetch_array($result2) ) { if (!$result2) { } ?> <tr> <td><?php echo $row['IDNO']?> </td> <td><?php echo $row['YEAR'] ?> </td> <?php if ( $ShowLastName ) { echo('<td>'.$row['LASTNAME'].'</td>'); } ?></td> <?php if ( $ShowFirstName ) { echo('<td>'.$row['FIRSTNAME'].'</td>'); } ?> I really get lots of undefined errors when I do this. What can you recommend that I should do in order to get the value inputted by the user together with the mysql data.

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  • how to open Gmail View Message Activity?

    - by NickLai
    I want to write an application to List the Gmail message. In the list, if user click one of the message item, it shall link ot Gmail App to see more detial information. Currently I can read the Gmail db with Gmail.java. There are some problems while I want to open Gmail Activity. In general, we can open Activity with Action and parameters. But Gmail App has not release code base. We do not know what Action set to Gmail Activity and what parmeter shall we put the extras. I only know that the Activity of View detial Message is named "HtmlConversationActivity." And the Package is under "com.google.android.gm." please tell me how to open the View detial Message Activity in Gmail APP. thanks a lot.

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  • Pushing View from UITableView Problem

    - by golfromeo
    Basically, what I want is to be able to press a record in a table, and have it push to another view. To do this, I created a nib file and a UIViewController subclass (for the "pushed" view). I set the nib file's "File Owner" to be the controller I created. Then, in the view controller of the table that will push that view, I set the didSelectRowIndexAtPath: method to include the following: SearchTableController *vc = [[SearchTableController alloc] initWithNibName:@"SearchTable" bundle:[NSBundle mainBundle]]; [self.navigationController pushViewController:vc animated:YES]; [vc release]; (where "SearchTableController" is the name of the UIViewController subclass and "SearchTable" is the name of the nib file) However, when I run this code and click on the record, nothing happens- the app doesn't crash, but the view doesn't get pushed. The code is getting run, because it works when I NSLog(), but it doesn't seem to be pushing the view. Thanks for any help in advance.

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  • Best practices for multiple asserts on same result in C#

    - by asdseee
    What do you think is cleanest way of doing multiple asserts on a result? In the past I've put them all the same test but this is starting to feel a little dirty, I've just been playing with another idea using setup. [TestFixture] public class GridControllerTests { protected readonly string RequestedViewId = "A1"; protected GridViewModel Result { get; set;} [TestFixtureSetUp] public void Get_UsingStaticSettings_Assign() { var dataRepository = new XmlRepository("test.xml"); var settingsRepository = new StaticViewSettingsRepository(); var controller = new GridController(dataRepository, settingsRepository); this.Result = controller.Get(RequestedViewId); } [Test] public void Get_UsingStaticSettings_NotNull() { Assert.That(this.Result,Is.Not.Null); } [Test] public void Get_UsingStaticSettings_HasData() { Assert.That(this.Result.Data,Is.Not.Null); Assert.That(this.Result.Data.Count,Is.GreaterThan(0)); } [Test] public void Get_UsingStaticSettings_IdMatches() { Assert.That(this.Result.State.ViewId,Is.EqualTo(RequestedViewId)); } [Test] public void Get_UsingStaticSettings_FirstTimePageIsOne() { Assert.That(this.Result.State.CurrentPage, Is.EqualTo(1)); } }

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  • How to add :format options to a named route in Rails?

    - by Alfred Nerstu
    I've got a named route called profile and I would like to be able to access it as json. But when I look at my rake routes output I see that the (.:format) is missing. How do I add it to a named route? user GET /users/:id(.:format) {:action=>"show", :controller=>"users"} profile /:username {:action=>"show", :controller=>"users"} Thanks in advance!

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  • Conditional value for ActiveRecord create method only

    - by Steve Wright
    I have a form where I have an administrator creating new users. The form uses the User model I created (login, password, first_name, etc...). For the last field on the form, I want to have a checkbox that doesn't need to be stored as part of the User record, but it is needed for the controller. This will control whether or not the newly created user will receive a welcome email or not. def create @user = User.new(params[:user]) if @user.save if @user.send_welcome_email UserMailer.welcome_email(@user).deliver end redirect_to(admin_users_url, :notice => "User #{@user.name} was successfully created.") else render :action => "new" end end In my view (haml) I am trying to access it like this: %p Send Welcome Email? = f.check_box :send_welcome_email I tried to make this an attr_accessible: :send_welcome_email but the controller does not recognize it. I get an undefined method 'send_welcome_email' for #&lt;User:0x00000100d080a8&gt; I would like it to look like this: What is the best way to get this working:

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  • Why doesn't jquery validation plugin's remote attribute work for me?

    - by Pandiya Chendur
    I use jquery validation plugin and the remote attribute works with emailId but not with mobileNo? var validator = $("#addform").validate({ rules: { Name: "required", MobileNo: { required: true, minlength: 10, remote: '<%=Url.Action("getClientMobNo", "Clients") %>' }, Address: "required" }, messages: { Name: "please provide a client name", MobileNo: { required: "Please provide a mobile phone no", rangelength: jQuery.format("Enter at least {0} characters"), remote: jQuery.format("This MobileNo is already in use") }, Address: "please provide client address" }, A null value is passed to my controller action.. Any suggestion... public JsonResult getClientMobNo(string mobno) { JsonResult result = new JsonResult(); string status = clirep.getClientMobNo(Convert.ToInt64(mobno)); if (status == "Mobile No already exists") { result.Data = false; } else { result.Data = true; } return result; }

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  • Additional parameters for FileSystemEventHandler

    - by peku
    I'm trying to write a program that could monitor multiple folders for file creations and launch the same action but with different settings for each folder. My problem is in specifying an extra parameter for the FileSystemEventHandler. I create a new FileWatcher for each directory to monitor and add the handler for the Created-action: foreach (String config in configs) { ... FileWatcher.Created += new System.IO.FileSystemEventHandler(FileSystemWatcherCreated) ... } void FileSystemWatcherCreated(object sender, System.IO.FileSystemEventArgs e, MySettings mSettings) { DoSomething(e.FullPath, mSettings); } How could I get the 'mSettings' variable passed to FileSystemWatcherCreated()?

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  • Property Scope (Iphone)

    - by Hank
    Hello All. I am having trouble accessing a declared property and I think I am missing something fundamental about the nature of properties and perhaps view controllers. Here's what I'm doing so far: declaring a property "myPhone" in a root view controller called RootViewController. grabbing a phone number from a modally presented people picker setting "myPhone" to the value from the people picker (from within shouldContinueAfterSelectingPerson of ABPeoplePickerNavigationController) trying to access "myPhone" from another modally presented view controller "myPhone" continues to NSLog to null despite trying every permutation of self.myPhone, super, RootViewController, etc. to try and access the value I set. What am I missing?

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  • Jquery Click in li

    - by cKendrick
    I have my html set up like this: <li> Header <button>Edit</button> </li> And I was wondering if there is a way so that you can click on the li and have one action happen and click on the button and have another action happen. Right now if I have a jquery click element on the li it gets fired when you hit the button to. Is there a way to make this separate without changing the html structure?

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  • image is not getting loaded in view.

    - by anurag
    I have created 2 views named "FirstView" and "SecondView".SecondView's nib file has an UIImage view object as its IBOtlet.Now I am getting an UIImage object from some FirstViewController's method.Now I am setting the SecondViewController's imageView property with that image and then I am pushing my SecondView Controller's object in Navigation Controller.The SecondView gets loaded but that image is not shown in that view. The code is as follows:..... (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo { [[picker parentViewController] dismissModalViewControllerAnimated:YES]; SecondViewController *secondView=[[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]]; secondView.imageView.image=img; [self.navigationController pushViewController:secondView animated:YES]; }

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  • image is not getting loaded in view.

    - by anurag
    I have created 2 views named "FirstView" and "SecondView".SecondView's nib file has an UIImage view object as its IBOtlet.Now I am getting an UIImage object from some FirstViewController's method.Now I am setting the SecondViewController's imageView property with that image and then I am pushing my SecondView Controller's object in Navigation Controller.The SecondView gets loaded but that image is not shown in that view. The code is as follows:..... - (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo { [[picker parentViewController] dismissModalViewControllerAnimated:YES]; SecondViewController *secondView=[[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]]; secondView.imageView.image=img; [self.navigationController pushViewController:secondView animated:YES]; }

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  • Working with nested models in ROR

    - by user487429
    Hi there, I'm trying to create an application where users can freely create shops and associated shop item for a specific shop is displayed when a show action is called but I seem to be doing something wrong. Any help here will be appreciated. I have attached shots of my code below. class ShopItem < ActiveRecord::Base belongs_to :shop def self.find_shop_items_for_sale find(:all, :order => "title", :conditions => ["shop_id = ?", @shop.id]) end end class Shop < ActiveRecord::Base has_many :shop_items end #Controllers class ShopsController < ApplicationController def new @shop = Shop.new end def create @shop = Shop.new(params[:shop]) @shop.user_id = current_user.id respond_to do |format| if @shop.save flash[:notice] = "Successfully created shop." format.html {redirect_to(all_shops_shops_url)} format.xml {render :xml => @shop, :status => :created, :location => @shop } else format.html {render :action => 'new'} format.xml { render :xml => @shop.errors, :status => :unprocessable_entity } end end end def show @shop = Shop.find(params[:id]) @shop_items = ShopItem.find_shop_items_for_sale @shop_cart = find_shop_cart end class ShopItemsController < ApplicationController def user @per_page ||= 5 @user = User.find(params[:id]) @shop_items = ShopItem.find(:all, :conditions=>["user_id = ?", @user.id], :order=>"id desc") end def show @shop_item = ShopItem.find(params[:id]) @shop = @shop_item.shop respond_to do |format| format.html # show.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/new # GET /shop_items/new.xml def new @shop_item = ShopItem.new @shop = Shop.find(params[:id]) #@shop_items = ShopItem.paginate(:all, :condition=>["shop_id] = ?", @shop.id], :order=> "id desc", :page => params[:page],:per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions=>["shop_id = ?", @shop.id], :order=> "id desc") @shop_item.shop_id = params[:id] respond_to do |format| format.html # new.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/1/edit def edit @shop_item = ShopItem.find(params[:id]) end # POST /shop_items # POST /shop_items.xml def create @shop_item = ShopItem.new(params[:shop_item]) @shop_item.user_id = current_user.id respond_to do |format| if @shop_item.save flash[:notice] = 'Shop item was successfully created.' format.html { redirect_to(@shop_item) } format.xml { render :xml => @shop_item, :status => :created, :location => @shop_item } else @shop = Shop.find(@shop_item.shop_id) #@shop_items = ShopItem.paginate(:all, :condition =>["shop_id = ?", @shop.id], :order=> "id desc" , :page => params[:page], :per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions =>["shop_id = ?", @shop.id], :order=> "id desc") format.html { render :action => "new" } format.xml { render :xml => @shop_item.errors, :status => :unprocessable_entity } end end end

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  • AJAX form sections - how to pass url of next stage of form

    - by dan727
    Hi, I've got a multi-part form (in a PHP MVC setup) which I have working correctly without javascript enhancement. I'm starting to add the AJAX form handling code which will handle each stage of a form submission, validating/saving data etc, before using AJAX to load the next stage of the form. I'm wondering how best to pass the URL of the next stage to the current form being processed, so that my jQuery form handling code can process the current form, then load the next part via AJAX. The form "action" is different from what the url of the next stage of the form is - what do you think would be good practice here? I was thinking about either appending the url of the next stage to the form action url, via a query string - then just use javascript to extract this url when the form is successfully processed. The other option is via a hidden form element. Not sure what other client side options I have here Any thoughts?

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  • cocoa - referencing a method on the parent

    - by Mike
    I had a method on my main view controller named "calculateThis". This method was run, obviously, as int newValue = [self calculateThis:myVariable]; when I run it from inside the view controller. Then I created a static class and I need to run this method from there. How do I reference this method from that class using just relative references, as super, superview, delegate, etc. I cannot use the class name defined on the delegate because this static class is used in several apps of mine.

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  • iPhone screen rotates at random !

    - by Baldoph
    I use a tabBar Controller as root controller. It has 4 tabs and each of its ViewControllers has - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation { return YES; } as long as the tabBarController itself. But when I rotate the device (real or simulator), the screen turns at random! If it doesn't turn when I open the application it would have the same behavior until I quit the app. I tried to add the 4 viewControllers one by one in IB to see if one was problematic, but I obtained the same issue. It only always works when there is no tabs at all! Please tell me if you have any ideas. Thanks!

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  • Stubborn UIButton

    - by Mike
    I have a UIButton that is supposed to be disabled during certain phases. So, when this happens I do [myButton setEnabled:NO]; This is perfect because the button stays grayed and if clicked will not trigger its action, but... when the button is clicked even grayed, it enables again and a second click will trigger its actions (???????!!!!!!!!!!). How can that be? If the button is disabled it is supposed to be "part of the background", i.e., an image without any action. I have tried to make the button vanish using alpha but even if you click on the empty spot, it reappears after the first click and then can trigger actions after the second click... (????) Am I missing something?

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  • How to set per-script upload_max_filesize limit?

    - by Ilya Muromets
    I have the following issue: How to set per-script upload_max_filesize limit? I want to set a larger upload max filesize limit for a particular script (action). I know I could use .htaccess, but the problem is that all actions are being dispatched via single index.php file, which likely means for all actions .htaccess rules are the same. So is it possible to set a per-script max_upload_size for a single php script (action)? Hope, you will be able to help me. Thanks in advance.

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  • What are the differences between MVP, Presentation Model, MVVM and MVC?

    - by Nicholas
    I have a pretty good idea how each of these patterns work some of the minor differences between them, but are they really all that different from each other? It seems to me that the Presenter, Presentation Model, ViewModel and Controller are essentially the same concept. Why couldn't I classify all of these concepts as controllers? I feel like it might simplify the entire idea a great deal. Can anyone give a clear description of their differences? I want to clarify that I do understand how the patterns work, and have implemented most of them in one technology or another. What I am really looking for is someone's experience with one of these patterns, and why they would not consider their ViewModel a controller for instance.

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • What is your prefered way to return XML from an ActionMethod in Asp.net MVC?

    - by serbrech
    I am displaying charts that load the data asynchronously because the searches are the work to fetch the data is quite heavy. The data has to be return as XML to make the chart library happy. My ActionMethods return a ContentResult with the type set as text/xml. I build my Xml using Linq to XML and call ToString. This works fine but it's not ideal to test. I have another idea to achieve this which would be to return a view that builds my XML using the XSLT View engine. I am curious and I always try to do the things "the right way". So how are you guys handling such scenarios? Do you implement a different ViewEngine (like xslt) to build your XML or do you Build your XML inside your controller (Or the service that serves your controller)?

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  • How do I set up my @product=Product.find(params[:id]) to have a product_url?

    - by montooner
    Trying to recreate { script/generate scaffold }, and I've gotten thru a number of Rails basics. I suspect that I need to configure default product url somewhere. But where do I do this? Setup: Have: def edit { @product=Product.find(params[:id]) } Have edit.html.erb, with an edit form posting to action = :create Have def create { ... }, with the code redirect_to(@product, ...) Getting error: undefined method `product_url' for #< ProductsController:0x56102b0 My def update: def update @product = Product.find(params[:id]) respond_to do |format| if @product.update_attributes(params[:product]) format.html { redirect_to(@product, :notice => 'Product was successfully updated.') } format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @product.errors, :status => :unprocessable_entity } end end end

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  • How to set UITableView to Grouped?

    - by 4thSpace
    In an iPhone navigation based app, I want to add a second tableview but have its design available in IB. I've added a new empty XIB and dragged a UITableView onto it. I want to setup the layout through IB. I've created a controller for this tableview and set the File's Owner class in IB to this controller. I linked the tableview to File's Owner as well. I set the tableview to grouped in IB. However, that does not translate at runtime. I still have a plain tableview. In fact, none of the Inspector settings work at runtime. What have I missed?

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  • Devise role based routing

    - by teknull
    I have an app with multiple users. Each user as a theoretical role (user, client, etc). I've designed a view/controller for each user type. I want to be able to login each type of user do a different root url and lock them to it. Originally I was going to add a column to Users in Devise called role and so I can differentiate the users. The problem I'm having is how to say in routes.rb if current_user.role == "client" root :to = 'controller#index' Once they are logged in to the page I also want to keep them from being able to visit any of my other paths ie: domain.com/calls domain.com/units I've been looking into cancan to run alongside Devise but I'm not sure if this is the answer.

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