Search Results

Search found 18244 results on 730 pages for 'controller action'.

Page 252/730 | < Previous Page | 248 249 250 251 252 253 254 255 256 257 258 259  | Next Page >

  • Play 2.0 javaToDo tutorial doesn't compile

    - by chsn
    I'm trying to follow the Play2.0 JavaToDO tutorial and for some reason it just doesn't want to work. Have looked through stackoverflow and other online resources, but haven't find an answer to this and it's driving me crazy. Attached code of the Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { static Form<Task> taskForm = form(Task.class); public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result newTask() { return TODO; } public static Result deleteTask(Long id) { return TODO; } } Attached code of the Task java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task { public Long id; @Required public String label; // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create task public static void create(Task task) { task.create(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } // create new task public static Result newTask() { Form<Task> filledForm = taskForm.bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.create(filledForm.get()); return redirect(routes.Application.tasks()); } } } I get a compile error on Task.java on the line static Form<Task> taskForm = form(Task.class); As I'm working on eclipse (the project is eclipsified before import), it's telling me that taskForm cannot be resolved and it also underlines every play 2 command e.g. "render(), redirect(), bindFromRequest()" asking me to create a method for it. Any ideas how to solve the compilations error and also how to get Eclipse to recognize the play2 commands? EDIT: updated Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { // create new task public static Result newTask() { Form<Task> filledForm = form(Task.class).bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.newTask(filledForm.get()); return redirect(routes.Application.tasks()); } } public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result deleteTask(Long id) { return TODO; } } Updated task.java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task extends Model { public Long id; @Required public String label; // Define a taskForm static Form<Task> taskForm = form(Task.class); // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create new task public static Result newTask(Task newTask) { save(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } }

    Read the article

  • Make user object available to all Controllers in Zend?

    - by Sled
    Hey guys, I'm using Zend_Auth to identify a user in my application. This creates a session with the userobject. My question is how do I make this object available to every Controller and action, so I don't have to pull it out of the session every time I need data from this object? I'm guessing this should be done in bootstrap.php or index.php but I don't really know how to makte it available to every controller.. so any code examples would be appreciated! Thanks!

    Read the article

  • Are @property's necessary for Interface Builder?

    - by Rits
    In my UIViewController subclass, I have 3 UIView's with each a @property as an IBOutlet. I do not use these properties at all in my code. The views get instantiated as soon as the view controller is created and they are deallocated when the view controller is deallocated. I was thinking; can't I just remove the @property's? I did, and I could still connect my instance variables (with IBOutlet) in Interface Builder. So my question now is; is there any use for properties in combination with Interface Builder, or is it OK to leave them out? Is it required for some memory management or something? Or are they really just for use in your own code? And if I do leave them out, do I still need to release them in dealloc?

    Read the article

  • Widget starting a service also starts main activity

    - by Nick
    Hi, I have a widget that is supposed to start and stop a service (start it when it's not running, stop it when it is). This is working fine, however, each time the service is started, my app's main activity is also launched, which I don't want. If I remove the MAIN-intent-filter ( <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" />) from the app's manifest, it works as I want it to (without launching the main-activity, just the service), but then I obviously don't have a main activity anymore... This is how I start the service (I would assume this is the normal way, and I can't see any reference to what might cause the MAIN intent to fire): Intent svc = new Intent(this, OnOffService.class); startService(svc); Thanks, Nick

    Read the article

  • How to save checkbox checked values in Database

    - by user1298215
    How to save checkbox values in database. Below is my view code. @foreach (var item in Model) { @Html.CheckBox("statecheck", (IEnumerable<SelectListItem>)ViewData["StatesList"]) @Html.DisplayFor(modelItem => item.state_name) </br> } <input class="ASPbutton" type="submit" value="submit"/> Below is My controller. public ActionResult States() { ViewData["StatesList"] = new SelectList(am.FindUpcomingStates().ToList(), "state_id", "state_Name"); return View(); } My model is public IQueryable<state> FindUpcomingStates() { return from state in Adm.states orderby state.state_name select state; } After clicking submit button checked item state_id will be saved into database. I wrote like below in Controller, but i got true or false values, i want state_id [AcceptVerbs(HttpVerbs.Post)] public ActionResult States(string _stateName, char[] statecheck, FormCollection formvalues) { statecheck = Request.Form["statecheck"].ToArray(); ViewData["StatesList"] = new SelectList(am.FindUpcomingStates222().ToList(), "state_id", "state_id", _stateName); }

    Read the article

  • Rails: textfield list to array of strings

    - by poseid
    I want to take input from a textfield and turn it into an array of strings. After having submitted the "post", I want to display again the textfield, but with the array showed below. I have a view that would look like: <% form_tag "/list2array" do -%> <%= text_area_tag "mylist" %> <div><%= submit_tag 'save' %></div> <% end -%> <% @myArray.each do |item| %> <%= item %> <% end %> And as a start for the controller: class List2ArrayController < ApplicationController def index end def save @myArray = params[:mylist].split("\r\n") end end However, after the post, I only get an empty textfield without values in the array from the previous POST. Do I need to use the model layer for my experiment? How? Or do I need to modify my controller?

    Read the article

  • converting compressed Rich text (C#)

    - by Code Smack
    Hello, I have a string with CompressedRichText in it. I want to uncompressed it to standard RTF and then to plain Text. I am using VS 2008 C# Windows Application. I found references to C++ code to do it, but nothing directly in C#. here is a sample of what I am thinking... not much code though... private string _CompressedRichText = "5A46751234E1234A3214C12D34213412346F4"; private void button1_Click(object sender, EventArgs e) { //Convert to Uncompressed RTF richTextBox1.Text = //Some action //Convert to text textBox1.Text = //some action } This will at least give you an example of what I am thinking.

    Read the article

  • Design advices for quick navigation between view

    - by Thomas Joulin
    Usually, when a View requires a lot of bindings, or some UI Elements like a Bing Map, it takes a "while" to load (like between half a second and a second). I don't want a delay between a "tap" action (like tapping an element on a ListBox) and the navigation action (displaying a new page). I don't mind displaying the page progressively. For example, for a Bing Map, I don't mind displaying a black page with only a title, and a second later, having the Map appear. What are the best practices ? It could post a sample if i'm not clear enough

    Read the article

  • Rails routing issue

    - by Brob
    Hi I've just started learning rails and been going through some tutorials from learning rails (http://www.buildingwebapps.com/podcasts/79335-putting-the-page-contents-into-the) The tutorials appear to be Rails v2 and I'm on Rails v3 There is a line in the routes file which appears to be causing a problem map.view_page ':name', :controller => 'viewer', :action => 'show' The line works for the front end view i.e. my viewer controller but not for the back end I get the error NoMethodError in Viewer#show I think this has something to do with the view I am using and the line <%= @page.body %> I know it's difficult without the full code but if anyone can help that would be awesome

    Read the article

  • Perl: How do I extract certain bits from a byte and then covert these bits to a hex value?

    - by Siegfried Hepp
    I need to extract certain bits of a byte and covert the extract bits back to a hex value. Example (the value of the byte is 0xD2) : 76543210 bit position 11010010 is 0xD2 Bit 0-3 defines the channel which is 0010b is 0x2 Bit 4-5 defines the controller which is 01b is 0x1 Bit 6-7 defines the port which is 11b is 0x3 I somehow need to get from the byte is 0xD2 to channel is 0x2, controller is 0x1, port is 0x3 I googled allot and found the functions pack/unpack, vec and sprintf. But I'm scratching by head how to use the functions to achieve this. Any idea how to achieve this in Perl ?

    Read the article

  • jquery $.ajax not working in firefox against rails (406 response) (works in chrome & IE)

    - by phil swenson
    I have a rails backend and am testing the following jquery code against it: var content = $("#notification_content").val(); var data = new Object(); data.content = content; $.ajax({ url: "/notifications/detect_type.json", type:"POST", data: data, success: function(result ){updateTypeDropDown(result)}}); This code works fine in Chrome and IE. However in Firefox (using Firebug), I see this: http://localhost:3000/notifications/detect_type.json 406 Not Acceptable here is a chrome request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:05:59) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson denver co 80209", "controller"="notifications"} User Columns (2.0ms) SHOW FIELDS FROM users User Load (37.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 58ms (View: 1, DB: 40) | 406 Not Acceptable [http://localhost/notifications/detect_type.json] here is a firefox request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:06:41) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson 80209", "controller"="notifications"} User Columns (2.1ms) SHOW FIELDS FROM users User Load (30.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 100ms (View: 1, DB: 33) | 200 OK [http://localhost/notifications/detect_type.json] I'm stumped. Ideas?

    Read the article

  • A question related to UIButton

    - by vikas Savardekar
    I have taken customview in my code for UIButton. UIButton *button= [[UIButton buttonWithType:UIButtonTypeRoundedRect] retain]; //(UIButton *)newCell.accessoryView; [button addTarget:self action:@selector(checkedimage:) forControlEvents:UIControlEventTouchUpInside]; -(IBAction)checkedimage:(id)sender { NSLog(@"checkedimage"); if(checkImage == NO) { newImage = [UIImage imageNamed:@"a.png"]; checkImage=YES; } else if(checkImage==YES) { newImage = [UIImage imageNamed:@"b.png"]; checkImage=NO; } } but when i click on UIButton it is not going to action checkedimage why?

    Read the article

  • Passing values across pages ASP.net

    - by GigaPr
    Hi i need to pass a long list of Ids from one page to another, i was thinking of using querystring but taking in consideration that the number of ids to be passed may reach 300 i think is not a good idea. an option from my understanding may be the use of session, this seems to me an optimal solution in my case but on the other hand I can certainly clear the session when the user performs a certain action and the list of ids is not longer needed, but if the user leaves the page without performing any action i want to clear the session, how can i do it? If multiple users are using the same functionality do i need the session's items to be confused or the session is for a single user? I am working in asp.net c# Thanks

    Read the article

  • iPhone - Landscape Only App

    - by Robert
    Hello all! I am trying to make an app that will only be viewed in Landscape. I have looked up some tutorials (albeit older ones) and have done the following: -set up the info.plist to include a key for uiinterfaceorientation -in the main view controller I have set the frame to be 480 x 320 Now, the first screen loads up ok. Everything is where it should be and whatnot. However, if I click a button that is set to present a modal view controller nothing happens. Everything is linked and coded correctly but nothing happens when I press the button. Am I doing something wrong with trying to force landscape? At it's basic, this question is a how do you effectively make an app that will only be in landscape mode? Thanks for any help.

    Read the article

  • back button wont work.. Iphone

    - by lotuseater
    Hi, I have 2 page controls in my app, one for category and when i click details button of that category other page control comes. I have pushed the first view controller and used present modal view controller. Now a need to go back to the home page from the category page control but the view did load and view will appear wont work. That is where i have added my navigation bar programmatically. is there any way i can call them? i am new to iphone programming. Please help me if you can.... Thankyou

    Read the article

  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

    Read the article

  • Deserialising Json to derived types in Asp.Net Web API

    - by IoChaos
    I'm calling a method of my WebAPI sending a json that I would like to match (or bind) with a model. In the controller I have a method like: public Result Post([ModelBinder(typeof(CustomModelBinder))]MyClass model); 'MyClass', wich is given as a parameter is an abstract class. I would like that at, depending of the type of json passed, the correct inherited class is instantiated. To achieve it, I'm trying to implement a custom binder. The problem is that (I don't know if it's very basic but I can't find anything) I don't know how to retrieve the raw Json (or better, some kind of serialization) that comes in the request. I see: actionContext.Request.Content But all methods are exposed as async. I don't know who this fits with passing the generate model to the controller method... Thanks a lot!

    Read the article

  • How to record when user follows external links without slowing user down

    - by taw
    I want to track when user clicks external links for analytics purposes. The simplest solution is to replace all external links with links to special record-and-redirect controller, but that would slow the user unnecessarily. The second idea would be to override click event and within in $.post a message to record controller, then let the main event handler happen, which will usually be either click (open link in same tab) or middle click (open in new tab) - good either way, and the user won't have to wait for wait for my server to record it, it's fire-and-forget. (I don't care if users without Javascript don't get tracked) Is that a reasonable way to go? Or what else would be the best way to track all external link clicks?

    Read the article

  • WiX - How do I prevent ComPlusAssembly being unregistered during uninstall?

    - by Duncan Watts
    As part of my Installer, I am adding files to an existing COM+ package. I have defined a ComPlusApplication underneath my Product element, which has the name set to a property - I then have a custom action which looks up that property - all good so far. When the installer adds the files, within the same component I have added a ComPlusAssembly which adds the assembly to the ComPlusApplication I defined above - this is also working correctly. When uninstalled however, I am receiving an error related to being unable to find the COM+ application, this is because I am not running my custom action to look up the name of the COM+ package. Basically I do not want to remove my files or unregister the component package as part of the uninstallation process - How do I achieve this? I am using WiX 3.0 with VS2008. Thanks

    Read the article

  • Where to put a recursive function when following MVC?

    - by Glibly
    Hello, I have a recursive function being used to generate a menu on my site. The function is calling a database for each level of children in the menu, and generating html for them. I've currently put this function in a Model part of the code, however, I feel that generating html in the model goes against the MVC. I didn't put it in a Controller because I didn't want to have database calls or HTML generation there. I didn't put it in a View because I didn't want database calls there either. Is the 'correct' way of tackling this problem to have a Controller call a recursive function in a Model that returns a 2d array representing the menu. Then pass the array to a view which has it's own recursive function for generating html from the array?

    Read the article

  • jQuery - getting the id of the item selected

    - by John Leonard
    I have a basic jQuery selector question. Let's say I'm parsing JSON and generating a row of data for each item in my result set. On each item row, I want an action button. What is the best practice to script that button so its click action can reference the data specific to that row? Starting with the block below, how do I generate a 'Click Me' button that when clicked will alert with its json data? $.getJSON(url,params,function(json){ if(json.items){ $.each(json.items, function(i, n){ var item = json.items[i];

    Read the article

  • Subprocess with variables & Command from different class

    - by Pastelinux
    source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

    Read the article

  • Global search box extension - how to make browser to start when suggestion picked.

    - by Ramps
    Hi, I'm implementing global search box extension (sth like SearchableDictionary sample in android sdk). Everything works fine - suggestions are displayed properly. Problem is that I want browser to start when user picks a suggestion. (each suggestion is a link) Columns of my cursor contain SearchManager.SUGGEST_COLUMN_INTENT_DATA, and I use that to pass http link. My searchable xml contains default intent action set to: android:searchSuggestIntentAction="android.intent.action.VIEW". But when user hits the suggestion, my application is started instead of browser. What am I missing? Regards!

    Read the article

  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

    Read the article

< Previous Page | 248 249 250 251 252 253 254 255 256 257 258 259  | Next Page >