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  • Get the character count of a textarea including newlines

    - by styfle
    I tested this code in Chrome and there seems to be a bug involving the newlines. I am reaching the maxlength before I actually use all the characters. <textarea id="myText" maxlength="200" style="width:70%;height:200px"> Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s... Enter something: </textarea> <div> Char Count <span id="count"></span>/<span id="max"></span> </div>? <script> var ta = document.getElementById('myText'); document.getElementById('max').innerHTML = ta.maxLength; setInterval(function() { document.getElementById('count').innerHTML = ta.value.length; }, 250);? </script> How can I accurately get the char count of a textarea? jsFiddle demo: http://jsfiddle.net/Qw6vz/1/

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  • Visual Studio / Blend... how you organize that?

    - by TomTom
    Virst time more complex stuff in WPF. I am a little lost on the split betwen VS and Blend. It seems I am VERY limited with editors in Visual Studio for editing controls - when customizing, for example, it seems I Can enter astyle in XML... but in blend I Can tell it to make a copy of the CURRENT style and use that as a starter, definitely more convenient. I understand the "difference in focus", but it seems to me that i Really need both tools to work, especially if the controls I Do are: More complex Not user controls "on purpose" (to allow more customization by programmes using the application). THis means when I do a control, my approach would be: Work on the backend as good as it gets without front end (i.e. implement all methods needed etc., but can be dummies) Switch over to Blend (closing visual studio - as the projcet must be closed) Put in the initial templating Switch over to VIsual Studio (closing blend) Put logic in and debug. This seems pretty counterintuitively. Am I missing something obvious here?

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  • Linked List push()

    - by JKid314159
    The stack is initialized with a int MaxSize =3. Then I push one int onto the list. " Pushed:" is returned to the console. Program crashes here. I think my logic is flawed but unsure. Maybe an infinite loop or unmet condition? Thanks for your help. I'm trying to traverse the list to the last node in the second part of the full() method. I implemented this stack as array based so must implement this method full() as this method is inside of main class. while(!stacker.full()) { cout << "Enter number = "; cin >> intIn; stacker.push(intIn); cout << "Pushed: " << intIn << endl; }//while Call to LinkListStack.cpp to class LinkList full(). int LinkList::full() { if(head == NULL) { top = 0; } else { LinkNode * tmp1; LinkNode * tmp2; tmp1 = head; while(top != MaxSize) { if(tmp1->next != NULL){ tmp2 = tmp1->next; tmp1 = tmp2; ++top; }//if }//while }//else return (top + 1 == MaxSize); }

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  • Unable to create a breakpoint in Eclipse and Tomcat

    - by Traroth
    Since yesterday, I get a strange error message when I start my Tomcat (6.0.35) under Eclipse Juno (build 20120614-1722): Among the things I tried in order to get rid of the error: Check in Preferences - Java - Compiler if all "Classfile Generation" checkboxes where checked. I did that for both general preferences and project preference Uncheck them, build, check them build again (found on another question) Add org.eclipse.jdt.core.compiler.debug.lineNumber=generate to my .settings/org.eclipse.jdt.core.prefs file Use a new CVS checkout (same symptoms) And now, I don't know what to do anymore. The problem is really stopping me from get anything done. I can't work anymore. Crazy is: the problem doesn't happen on every class, only on some of them. Neither does it happen on my other Eclipse projects. And it didn't happen before yesterday, even if I can't remeber having done anything weird. Actually, I have never seen a problem like this in almost 10 years I'm using Eclipse... If you have any idea, I would be really grateful... Edit: I also tried to ignore the message and go on with my tests: If I create another breakpoint upstream from my problematic class, when I enter this problematic class, it tries to open a $Proxy132 class, which means it actually opens an empty page, with a source not found message

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  • Cheap cloning/local branching in Mercurial

    - by Zack
    Hi, Just started working with Mercurial a few days ago and there's something I don't understand. I have an experimental thing I want to do, so the normal thing to do would be to clone my repository, work on the clone and if eventually I want to keep those changes, I'll push them to my main repository. Problem is cloning my repository takes alot of time (we have alot of code) and just compiling the cloned copy would take up to an hour. So I need to somehow work on a different repository but still in my original working copy. Enter local branches. Problem is just creating a local branch takes forever, and working with them isn't all that fun either. Because when moving between local branches doesn't "revert" to the target branch state, I have to issue a hg purge (to remove files that were added in the moved from branch) and then hg update -c (to revert modified files in the moved from branch). (note: I did try PK11 fork of local branch extension, it a simple local branch creation crashes with an exception) At the end of the day, this is just too complex. What are my options?

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  • Submit button on nested form submits the outer form in IE7

    - by Mike Christensen
    I have the following code on my Home.aspx page: <form id="frmJump" method="post" action="Views/ViewsHome.aspx"> <input name="JumpProject" /><input type="submit" value="Go" /> </form> However, when I click the "Go" button, the page posts back to Home.aspx rather than going to ViewsHome.aspx. I even tried adding some script to force the form to submit: <input name="JumpProject" onkeypress="if(event.keyCode == 13) { this.form.submit(); return false; }" /> But still even if I press ENTER, the Home.aspx page is reloaded. The only thing I can see that might be borking things is this form is actually a child form of the main POSTBACK form that ASP.NET injects into the page. I'm sure there's something stupid I'm missing and this post will get 800 downvotes instantly banishing me back into the n00b realm, but perhaps I haven't gotten enough sleep lately and I'm missing something stupid. This is on IE7 and an ASP.NET 4.0 backend. I also have jQuery libraries loaded on the page incase jQuery can improve this somehow. Thanks!

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  • Sequential access to asynchronous sockets

    - by Lars A. Brekken
    I have a server that has several clients C1...Cn to each of which there is a TCP connection established. There are less than 10,000 clients. The message protocol is request/response based, where the server sends a request to a client and then the client sends a response. The server has several threads, T1...Tm, and each of these may send requests to any of the clients. I want to make sure that only one of these threads can send a request to a specific client at any one time, while the other threads wanting to send a request to the same client will have to wait. I do not want to block threads from sending requests to different clients at the same time. E.g. If T1 is sending a request to C3, another thread T2 should not be able to send anything to C3 until T1 has received its response. I was thinking of using a simple lock statement on the socket: lock (c3Socket) { // Send request to C3 // Get response from C3 } I am using asynchronous sockets, so I may have to use Monitor instead: Monitor.Enter(c3Socket); // Before calling .BeginReceive() And Monitor.Exit(c3Socket); // In .EndReceive I am worried about stuff going wrong and not letting go of the monitor and therefore blocking all access to a client. I'm thinking that my heartbeat thread could use Monitor.TryEnter() with a timeout and throw out sockets that it cannot get the monitor for. Would it make sense for me to make the Begin and End calls synchronous in order to be able to use the lock() statement? I know that I would be sacrificing concurrency for simplicity in this case, but it may be worth it. Am I overlooking anything here? Any input appreciated.

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  • Python opening a file and putting list of names on separate lines

    - by Jeremy Borton
    I am trying to write a python program using Python 3 I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list. There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line Instead of printing each name on a separate line, it prints the list all on one line. How can I fix this? def main(): #create control loop keep_going = 'y' #Open name file name_file = open('names.txt', 'r') names = name_file.readlines() name_file.close() #Open outfile outfile = open('sorted_names.txt', 'w') index = 0 while index < len(names): names[index] = names[index].rstrip('\n') index += 1 #sort names print('original order:', names) names.sort() print('sorted order:', names) #write names to outfile for item in names: outfile.write(item + '\n') #close outfile outfile.close() #search names while keep_going == 'y' or keep_going == 'Y': search = input('Enter a name to search: ') if search in names: print(search, 'was found in the list.') keep_going = input('Would you like to do another search Y for yes: ') else: print(search, 'was not found.') keep_going = input('Would you like to do another search Y for yes: ') main()

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  • Is it possible to disable/bypass the login popup caused by mod_auth_ntlm_winbind (Single Sign On) an

    - by cvack
    I have an intranet on a remote Web server. This will be integrated with Active Directory on our local server. The web server is running Apache / Linux and the AD server is running Windows 2003. This is all done with VPN. Login to the intranet is conducted in two ways: 1. Users who are logged in to AD to be logged in automatically with SSO. 2. Users who are NOT logged in to AD to be logged in using a common login form. In order to auto login (SSO) I use mod_auth_ntlm_winbind. The problem here is that the users not logged in to AD will get a popup box where they must enter their DOMAIN/username + AD password. If I disable this popup, there is no way to get $_SERVER['REMOTE_USER'] Then my question: Is it possible to turn off this popup box and still get the REMOTE_USER? Or: If possible, can I use AJAX to check if http://my-intranet/auth returns 401 error (non-AD users). If so, do not go to the /auth folder.

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  • PHP and MySQL validating problem

    - by IPADvsSLATE
    I'm trying to check if a color is already entered into the database if it is the color should not be entered and stored into the database and the following error code <p>This color has already been entered!</p> should be displayed. But for some reason I cant get this to work, can someone please help me? The color names are entered into $_POST['color'] which is an array entered by the user. Here is the html code that collects the colors. <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> Here is the PHP & MySQL code. for($i=0; $i < count($_POST['color']); $i++) { $color = "'" . $_POST['color'][$i] . "'"; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT * FROM colors WHERE color = '$color' AND user = '$user_id' "); if(mysqli_num_rows($dbc) == TRUE) { echo '<p>This color has already been entered!</p>'; } else if(mysqli_num_rows($dbc) == 0) { // enter the color into the database }

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  • Is it better to use a relational database or document-based database for an app like Wufoo?

    - by mboyle
    I'm working on an application that's similar to Wufoo in that it allows our users to create their own databases and collect/present records with auto generated forms and views. Since every user is creating a different schema (one user might have a database of their baseball card collection, another might have a database of their recipes) our current approach is using MySQL to create separate databases for every user with its own tables. So in other words, the databases our MySQL server contains look like: main-web-app-db (our web app containing tables for users account info, billing, etc) user_1_db (baseball_cards_table) user_2_db (recipes_table) .... And so on. If a user wants to set up a new database to keep track of their DVD collection, we'd do a "create database ..." with "create table ...". If they enter some data in and then decide they want to change a column we'd do an "alter table ....". Now, the further along I get with building this out the more it seems like MySQL is poorly suited to handling this. 1) My first concern is that switching databases every request, first to our main app's database for authentication etc, and then to the user's personal database, is going to be inefficient. 2) The second concern I have is that there's going to be a limit to the number of databases a single MySQL server can host. Pretending for a moment this application had 500,000 user databases, is MySQL designed to operate this way? What if it were a million, or more? 3) Lastly, is this method going to be a nightmare to support and scale? I've never heard of MySQL being used in this way so I do worry about how this affects things like replication and other methods of scaling. To me, it seems like MySQL wasn't built to be used in this way but what do I know. I've been looking at document-based databases like MongoDB, CouchDB, and Redis as alternatives because it seems like a schema-less approach to this particular problem makes a lot of sense. Can anyone offer some advice on this?

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  • How to visually reject user input in a table?

    - by FX
    In the programming of a table-based application module (i.e. the user mostly enters tabular data in an already laid-out table), how would you reject user input for a given cell? The scenario is: the user edits the cell, enters something (text, picture, ...) and you want them to notice when they finish editing (hitting enter, for example) that their entry is not valid for your given "format" (in the wider meaning: it can be that they entered a string instead of a number, that their entry is too long, too short, they include a picture while it's not acceptable, ...). I can see two different things happening: You can rather easily fit their entry into your format, and you do so, but you want them to notice it so they can change if your guess is not good enough (example: they entered "15.47" in a field that needs to be an integer, so your program makes it "15") You cannot guess what to do with their entry, and want to inform them that it's not valid. My question specifically is: what visual display can you offer to inform the user that his input is invalid? Is it preferable to refuse to leave the editing mode, or not? The two things I can imagine are: using colors (red background if invalid, yellow background for my case 1 above) when you reject an input, do something like Apple does for password entry of user accounts: you make the cell "shaking" (i.e. oscillating left and right) for one second, and keep the focus/editing in their so they don't loose what they've typed. Let's hear your suggestions. PS: This question is, at least in my thought process, somehow a continuation and a specialization of my previous question on getting users to read error messages. PPS: Made this community wiki, was that the right thing to do on this kind of question or not?

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  • PHP/Javascript: Need help removing line break from code

    - by Josh K
    I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

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  • 'C++ object destroyed' in QComboBox descendant editor in delegate

    - by Max
    Hi, all! I have modified combobox to hold colors, using QtColorCombo (http://qt.nokia.com/products/appdev/add-on-products/catalog/4/Widgets/qtcolorcombobox) as howto for the 'more...' button implementation details. It works fine in C++ and in PyQt on linux, but I get 'underlying C++ object was destroyed' when use this control in PyQt on Windows. It seels like the error happens when: ... # in constructor: self.activated.connect(self._emitActivatedColor) ... def _emitActivatedColor(self, index): if self._colorDialogEnabled and index == self.colorCount(): print '!!!!!!!!! QtGui.QColorDialog.getColor()' c = QtGui.QColorDialog.getColor() # <----- :( delegate fires 'closeEditor' print '!!!!!!!!! ' + c.name() if c.isValid(): self._numUserColors += 1 #at the next line currentColor() tries to access C++ layer and fails self.addColor(c, self.currentColor().name()) self.setCurrentIndex(index) ... Maybe console output will help. I've overridden event() in editor and got: ... MouseButtonRelease FocusOut Leave Paint Enter Leave FocusIn !!!!!!!!! QtGui.QColorDialog.getColor() WindowBlocked Paint WindowDeactivate !!!!!!!!! 'CloseEditor' fires! Hide HideToParent FocusOut DeferredDelete !!!!!!!!! #6e6eff ... Can someone explain, why there is such a different behaviour in the different environments, and maybe give a workaround to fix this. Here is minimal example: http://docs.google.com/Doc?docid=0Aa0otNVdbWrrZDdxYnF3NV80Y20yam1nZHM&hl=en

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  • iPhone - Problem with in-app purchases

    - by Satyam svv
    I've created iPhone app with in-app purchase. Now, I'm in testing phase. I created provisioning profile com.satyam.testapp In iTunes connected I created the application and uploaded the images, screen shots, desscription etc. I also created two id's for in-app purchase. One is com.satyam.testapp.book1 and the other one is com.satyam.testapp.book5 I created test account also for verifying my in-app purchases. Using com.stayam.testapp i created developer test profile and using the same in my developed application. I logged out the itunes app store account in my iphone. Now i started running my application on my iphone. Its saying that no items are there to purchase. But its not even asking me for credentials where i've to enter test account username and password..... how to debug it? Here's my delegate: - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response { NSArray *myProduct = [[NSArray alloc] initWithArray:response.products]; for(int i=0;i<[myProduct count];i++) { SKProduct *product = [myProduct objectAtIndex:i]; NSLog(@"Name: %@ - Price: %f",[product localizedTitle],[[product price] doubleValue]); NSLog(@"Product identifier: %@", [product productIdentifier]); } for(NSString *invalidProduct in response.invalidProductIdentifiers) NSLog(@"Problem in iTunes connect configuration for product: %@", invalidProduct); [request autorelease]; [myProduct release]; }

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  • Oracle Forms on-button-pressed trigger to solve three scenarios

    - by DBase486
    Hello, I'm writing a when-button-pressed trigger on a save button for an Oracle Forms 6i form, and it has to fulfill a couple of scenarios. Here's some background information: the fields we're primarily concerned with are: n_number, alert_id, end_date For all three scenarios we are comparing candidate records against the following records in the database (for the sake of argument, let's assume they're the only records in the database so far): alert_id|| n_number|| end_date ------------------------------------- 1|| 5|| _______ 2|| 6|| 10/25/2009 Scenario 1: The user enters a new record: alert_id 1 n_number 5 end_date NULL Objective: prevent the user from committing duplicate rows Scenario 2: The user enters a new record: alert_id 1 n_number 10 end_date NULL Objective: Notify the user that this alert_id already exists, but allow the user the ability to commit the row, if desired. Scenario 3: The user enters a new record: alert_id 2 n_number 6 end_date NULL Objective: Notify the user that this alert_id has occurred in the past (i.e. it has a not-null end_date), but allow the user to commit the row, if desired. I've written the code, which seems to comply with the first two scenarios, but prevents me from fulfilling the third. Issues: When I enter the third scenario case, I am prompted to commit the record, but when I attempt this, the "duplicate_stop" alert pops up, preventing me. Issues: I'm getting the following error: ORA-01843: not a valid month. While testing the code for the third scenario in Toad (hard-coding the values, etc) things seemed to be fine. Why would I encounter these problems at run-time? Help is very much appreciated. Thank you

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  • How to build a simulation of a login hardware token in .Net

    - by Michel
    Hi, i have a hardware token for remote login to some citrix environment. When i click the button on the device, i get an id and i can use that to login to the citrix farm. I can click the button as much as i like, and every time a new code gets generated, and they all work. Now i want to secure my private website likewise, but not with the hardware token, but with a 'token app' on my phone. So i run an app on my phone, generate a key, and use that to (partly) authenticate myself on the server. But here's the point: i don't know how it works! How can i generate 1, 2 or 100 keys at one time which i can see (on the server) are all valid, but without the server and the phone app having contact (the hardware token also is an 'offline' solution). Can you help me with a hint how i would do this? This is what i thought of so far: the phone app and the server app know (hardcoded) the same encryption key. The phone app encrypts the current time. The server app decrypts the string to the current time and if the diff between that time and the actual server time is less than 10 minutes it's an ok. Difficult for other users to fake a key, but encryption gives such nasty strings to enter, and the hardware token gives me nice things like 'H554TU8' And this is probably not how the real hardware token works, because the server and the phone app must 'know' the same encryption key. Michel

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  • XForms relation of 'constraint' and 'required' properties

    - by Danny
    As a reference, the most similar question already asked is: http://stackoverflow.com/questions/8667849/making-xforms-enforce-the-constraint-and-type-model-item-properties-only-when-fi The difference is that I cannot use the relevant properties since I do want the field to be visible and accessible. I'm attempting to make a XForms form that has the following properties: It displays a text field named 'information'. (for the example) This field must not be required, since it may not be necessary to enter data. (Or this data will be entered at a later time.) However, if data is entered in this field, it must adhere to the specified constraint. I cannot mark the field as not relevant since this would hide the field and some data may need to be entered in it. The trouble now is that even though the field has no data in it, the constraint is still enforced (i.e. even though it is not marked as 'required'). I have taken a look at the XForms 1.1 specification, however it does not seem to describe how the properties 'required' and 'constraint' should interact. The only option I see, is to add a part to the constraint such that an empty value is allowed. e.g.: . = '' or <actual-constraint However, I don't like this. It feels like a workaround to add this to every such field. Is there any other way to express that non-required fields should not need to match the constraint for that field? (Am I missing something?)

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  • im unable to validate a login of users ,since if im entering the wrong values my datareader is not getting executed y ?

    - by Salman_Khan
    //code private void glassButton1_Click(object sender, EventArgs e) { if (textBox1.Text == "" || textBox1.Text == "" || comboBox1.SelectedIndex == 0) { Message m = new Message(); m.ShowDialog(); } else { try { con.ConnectionString = "Data source=BLACK-PEARL;Initial Catalog=LIFELINE ;User id =sa; password=143"; con.Open(); SqlCommand cmd = new SqlCommand("Select LoginID,Password,Department from Login where LoginID=@loginID and Password=@Password and Department=@Department", con); cmd.Parameters.Add(new SqlParameter("@loginID", textBox1.Text)); cmd.Parameters.Add(new SqlParameter("@Password", textBox2.Text)); cmd.Parameters.Add(new SqlParameter("@Department", comboBox1.Text)); SqlDataReader dr = cmd.ExecuteReader(); if (dr.Read()) { string Strname = dr[0].ToString(); string StrPass = dr[1].ToString(); string StrDept = dr[2].ToString(); if(dr[2].ToString().Equals(comboBox1.Text)&&dr[0].ToString().Equals(textBox1.Text)&&dr[1].ToString().Equals(textBox2.Text)) { MessageBox.Show("Welcome"); } else { MessageBox.Show("Please Enter correct details"); } } dr.Close(); } catch (Exception ex) { MessageBox.Show("Exception" + ex); } finally { con.Close(); } } }

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  • Lost Array After Validation Error

    - by Georges Kmeid
    I'm working on a CakePHP project and I have User, Post and Location models among others. User hasMany Location and Post belongsTo User so Location is not directly related to Post. This is my code in the Post controller: public function add() { if ($this->request->is('get')) { $this->loadModel('Location'); $this->set('locations', $this->Location->find('all', array('conditions' => array('user_id' => $this->Auth->user('id'))))); } ... } And this is my code in the posts/add view: <?php $i = 0; $j = 0; foreach ($locations as $location): $location_names[$i] = $location['Location']['name']; $i++; endforeach; echo "<select name=\"location\" onchange=\"select(this.value)\">"; echo "<option value=\"\">Select a saved location</option>"; foreach ($locations as $location): echo "<option value=\"" . $location['Location']['latitude'] . "," . $location['Location']['longitude'] . "\">" . $location_names[$j] . "</option>"; $j++; endforeach; ?> </select> If I enter a wrong value in one of the post inputs that has a validation rule in Post model, it redirects to the current add view, shows what is the validation error, but then the $locations array passed from controller to view disappears and can't use it in view and I get this error: Notice (8): Undefined variable: locations [APP\View\Posts\add.ctp, line 68]

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  • Pop-up and font colour based problems in a form which is designed in Share Point.

    - by ephieste
    I am designing a system in Share Point via Share Point Designer. We have a form in my Share Point site. Users have to fill some fields in the form and send it to the approval committee. We cannot upload anything to the servers. The design is site based. Our problems are: 1- I want to add small (?) icons for the descriptions of that field. When the user click on the (?) icon for "brief description" field a pop-up or another window will be opened and perhaps it will say: Enter a description of the requested thing. Be as specific as possible. 2- I want to change the font colors of the fields in the form. The share point brings them black as default. Such as I want to see the "Brief description:" and "Status:" as purple instead of black. Brief description: ..... Status: ..... 3- I want to add an agreement pop-up to the new form which will be open just after clicking "send" button in the form. The pop up will say: "Are you sure that you read the procedure" . The user has to click "Yes" to continue sending the form. Otherwise It will return to previous screen again. I would be glad if you kindly help me.

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  • How to debug an external library (OpenCV) in Visual C++?

    - by neuviemeporte
    I am developing a project in VC++2008. The project uses the OpenCV library (but I guess this applies to any other library). I am working with the Debug configuration, the linker properties include the debug versions of the library .lib's as additional dependencies. In VC++ Directories under Tools|Options i set up the include directory, the .lib directory, the source directories for the library as well. I get an error while calling one of the functions from the library and I'd like to see exactly what that function is doing. The line that produces the error is: double error = cvStereoCalibrate(&calObjPointsM, &img1PointsM, &img2PointsM, &pointCountsM, &cam1M, &dist1M, &cam2M, &dist2M, imgSize, &rotM, &transM, NULL, NULL, cvTermCriteria(CV_TERMCRIT_ITER + CV_TERMCRIT_EPS, 100, 1e-5)); I set up a breakpoint at this line to see how the cvStereoCalibrate() function fails. Unfortunately the debugger won't show the source code for this function when I hit "Step into". It skips immediately to the cvTermCriteria() (which is a simple inline, macro-kinda function) and show its contents. Is there anything else I need to do to be able to enter the external library functions in the debugger? EDIT: I think the cvTermCriteria() function shows in the debugger, because it's defined in a header file, therefore immediately accesible to the project.

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  • CGGradient Not Displaying Correctly on iPad 1 and 2

    - by daveMac
    I have been experimenting with creating my own gradients for the UI in my iOS app. I first used a CAGradientLayer but I was disappointed with the "stepped" look so I have been trying out CGGradient. enter code here I am having an issue with the Gradient displaying correctly. I have three iPads—one for each generation. The gradient looks right on the iPad 3 but not on the iPad 1 or 2. This is really strange. I was going to take a screenshot and post the two differences but even more strange, the screenshot look the same (and yes, the brightness is the same on both). The colors seem really washed out on the older iPads. I know the iPad 3 is a retina display, but I think it must be something more than that. Here is the code I am using: - (void)drawRect:(CGRect)rect { CGContextRef currentContext = UIGraphicsGetCurrentContext(); CGGradientRef skyGradient; CGColorSpaceRef rgbColorspace; size_t num_locations = 3; CGFloat locations[3] = { 0.0, .5, 1.0 }; CGFloat components[12] = { .106, .73, .93333, 1., 0.0, 0.0 , 1.0, 1., .106, .73, .93333, 1. }; rgbColorspace = CGColorSpaceCreateDeviceRGB(); skyGradient = CGGradientCreateWithColorComponents(rgbColorspace, components, locations, num_locations); CGRect currentBounds = self.bounds; CGPoint topLeft = CGPointMake(0.0f, 0.0f); CGPoint bottomRight = CGPointMake(CGRectGetMaxX(currentBounds), CGRectGetMaxY(currentBounds)); CGContextDrawLinearGradient(currentContext, skyGradient, topLeft, bottomRight, 0); CGGradientRelease(skyGradient); CGColorSpaceRelease(rgbColorspace); }

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  • How Session out trigger on browser close?

    - by Hemant Kothiyal
    Hi, Yesterday morning i open gmail account in Internet Exlorer second tab. I checked my mail and closed that tab (not browser). Then at the time of evining i again open second tab of browser and enetr gmail.com, it automatically redirect me at my email account without asking login. I shocked and i thought i should remain browser open for whole night and today open gmail in second tab , it behave similar means without login screen it redirect in my gmail account. Then i closed that tab and open another browser session and enter gmail i again surprised that i redirect me login page. At the same time i open second tab of first browser and it automatically redirect me at mail account page. What i councluded by this behaviour is that might be gmail server keep my browser id at their server so that whenever i eneter gmail.com on second tab of first browser, it automatically redirect me at gmail account. I don't know i am right or not? Please clear me this concept? What happens with my session at gmail server when i closed my browser tab? As per my opinion it should automatically logout me but why this doesn't happened?

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  • Using Loops for prompts with If/Else/Esif

    - by Dante
    I started with: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 puts "Hey! I said GREATER than 10! Try again buddy." else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end That worked fine, but if the user entered a number less than 10 the program ended. I want the user to be prompted to try again until they enter a number greater than 10. Am I supposed to do that with a loop? Here's what I took a swing at, but clearly it's wrong: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 loop.do puts "Hey! I said GREATER than 10! Try again buddy." favnumOverTen = gets.to_i until favnumOverTen > 10 else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end

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