Search Results

Search found 5589 results on 224 pages for 'materialized views'.

Page 26/224 | < Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >

  • SQL Syntax for testing objects before creating views & functions

    - by Scott Weinstein
    I'm trying to figure out the syntax for creating a view (or function) but only if a dependent CLR assembly exits. I've tried both IF EXISTS (SELECT name FROM sys.assemblies WHERE name = 'MyCLRAssembly') begin create view dbo.MyView as select GETDATE() as C1 end and IF EXISTS (SELECT name FROM sys.assemblies WHERE name = 'MyCLRAssembly') create view dbo.MyView as select GETDATE() as C1 go Neither work. I get Msg 156, Level 15, State 1, Line 2 Incorrect syntax near the keyword 'view'. How can this be done?

    Read the article

  • perforce implementation of clearcase like "views"

    - by Pradyot
    I have read through the documentation on perforce and the "branching strategy" advice as well. One thing thats left me baffled, is how a simple concern is does not seem to adequtely adressed. When I am working on a project that touches many parts of our code base , I cannot checkin my code at the end of the day without checking into the trunk. So do I need to branch in this situation? I want to be able to have the ability to have a history of my changes in a long and hard project, so I can go back when I I make a wrong turn.. The problem with branching I see is that I will be creating copies of almost the entire codebase .. Am I missing an obvious solution here? thanks

    Read the article

  • Easily reuse views, controller, layout in a command line interface

    - by Alex
    My Zend application is going to get an command line php script that should email reports. There generation depends on Zend_View, Zend_Layout and is currently already working fine in the web interface. How can I reuse this whole MVC functionality in the command line? Should I add a new controller CommandLineController and call this somehow from the commandline? How can I kick of such a Controller manually, without having a HTTP request?

    Read the article

  • Display different iphone views depending on logged in status

    - by user330936
    I want to display a login view to my users if they are not logged in and the main view if they are. In my header file I define a variable to hold the logged in status #define loggedIn 0 I figure I should then reference this in the initWithNibName method and then decide which nib to load. Is the right way of doing it? If so can someone help me out with the exact code? Thanks for any help

    Read the article

  • Tracking image views - PHP

    - by RS7
    I'd like for my app to be able to tell if an image hasn't been viewed in the last 30 days and remove it (along with data in the DB associated with it). I know you can have PHP read and output the image dynamically but I've heard its quite taxing on the system. Is there a way to for me to track these hits even when the image is viewed directly? (would htaccess be able to do this?) Thanks in advance.

    Read the article

  • dependent: :destroy is not deleting dependencies from views

    - by jxdx
    Projects have many rooms. When I delete a project from the view, the associated rooms are not deleted. Rooms also have many products which should also be deleted when a project is deleted. Project class class Project < ActiveRecord::Base belongs_to :user has_many :rooms, dependent: :destroy has_many :products, through: :rooms end Projects Controller class ProjectsController < ApplicationController def destroy @project = current_user.projects.find(params[:id]) if @project.delete redirect_to user_projects_path(@project.user) end end end Rooms Controller class RoomsController < ApplicationController def destroy @room = Room.find(params[:id]) if @room.delete redirect_to root_path end end The delete link in the projects show view. = link_to "Delete", project_room_path(room.project, room), method: :delete, data: { confirm: "Are you sure?" }, title: room.title, class: "btn btn-danger"

    Read the article

  • how to create 2 controllers with same actionresult 2 views but one implementation

    - by amalatsliit
    I got a controller in my mvc application like below. public class BaseController: Controller { protected void LogInfo() { logger.InfoFormat("[SessionID: {0}, RemoteIP: {1}]", Session.SessionID, Request.UserHostAddress); } } public class FirstController : BaseController { public ActionResult Index(string name) { LogInfo(); getQueryString(); if(IsValidRec()) { if(Errors())) { return View("Error"); } var viewname = getViewName(name); return view(viewname); } else return view("NotFound"); } } I need to create another controller(SecondController ) with same ActionResult method that FirstController has but without any implementation. Because I dont wont to repeat same code in 2 ActionResult methods. what is the best way to do that. I tried in following way but I m getting error when I initialize my protected method 'LogInfo()' public class SecondController : BaseController { public ActionResult Index(string name) { var firstcontroller = new FirstController(); return firstcontroller.Index(name); } }

    Read the article

  • Pass database data to multiples views-Laravel

    - by user3696018
    I have a database with details of daily sales. To query a database, I have a form in a view with parameters that will query as date of admission, client and others. The result is shown in another view with the daily details of income, and below is a summary of the article do all entered. The summary I wish to transfer to another view, try to view :: composer but only transfer the empty query (I saw it with debug bar). Just appeared an empty view. How I can transfer data from the database without the latter view is empty? The second html view is totaly diferent , only the data is the same.

    Read the article

  • Numerology with Python And Django

    - by Asinox
    Hi guys, i have a function that give me the result that im expecting in console mode, but if i try to use the function with Django, the page never load and just have a loop calculating and never end. Any idea ? *sorry with my english Console function (WORK GREAT): def sum_digitos(n): sum = 0; while n != 0: sum += n % 10 n /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) return sum print sum_digitos(2461978) Django views: def Calcular(request): if request.method == 'POST': form = NumerologiaForm(request.POST) if form.is_valid(): sum = 0; ano = str(request.POST['fecha_year']) mes = str(request.POST['fecha_month']) dia = str(request.POST['fecha_day']) data = dia + mes + ano fecha = int(data) while fecha != 0: f = fecha sum += f % 10 f /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) resultado = get_object_or_404(Numero,numero = sum) return HttpResponseRedirect(resultado.get_absolute_url()) else: form = NumerologiaForm() return render_to_response('numerologiaForm.html',{'form':form})

    Read the article

  • Problem showing modelstate errors while using RenderPartialToString

    - by Martin
    Im using the following code: public string RenderPartialToString(ControllerContext context, string partialViewName, ViewDataDictionary viewData, TempDataDictionary tempData) { ViewEngineResult result = ViewEngines.Engines.FindPartialView(context, partialViewName); if (result.View != null) { StringBuilder sb = new StringBuilder(); using (StringWriter sw = new StringWriter(sb)) { using (HtmlTextWriter output = new HtmlTextWriter(sw)) { ViewContext viewContext = new ViewContext(context, result.View, viewData, tempData, output); result.View.Render(viewContext, output); } } return sb.ToString(); } return String.Empty; } To return a partial view and a form through JSON. It works as it should, but as soon as I get modelstate errors my ValidationSummary does not show. The JSON only return the default form but it does not highlight the validation errors or show the validation summary. Am I missing something? This is how I call the RenderPartialToString: string partialView = RenderPartialToString(this.ControllerContext, "~/Areas/User/Views/Account/ChangeAccountDetails.ascx", new ViewDataDictionary(avd), new TempDataDictionary());

    Read the article

  • Error about 'invalid JSON' with couchDB view but the json's fine...

    - by Chris Huang-Leaver
    I am trying to setup the following view on CouchDB { "_id":"_design/id", "_rev":"1-9be2e55e05ac368da3047841f301203d", "language":"javascript", "views":{ "by_id":{ "map" : "function(doc) { emit(doc.id, doc)}" },"from_user_id":{ "map" : "function(doc) { if (doc.from_user_id) {emit(doc.from_user_id, doc)}}"}, "from_user":{ "map" : "function(doc) { if (doc.from_user) {emit(doc.from_user, doc)}}"}, "to_user_id":{ "map" : "function(doc) {if (doc.to_user_id){ emit(doc.to_user_id, doc)}}"}, "to_user":{ "map" : "function(doc) {if (doc.to_user){ emit(doc.to_user, doc)}}" }, "max_id":{ "map" : "function(doc) { if (doc.id) {emit(doc._id, eval(doc.id))}}", "reduce" :"function(key,value) { a = value[0]; for (i=1; i <value.length; ++i){a = Math.max(a,value[i])} return a}" } } } when I try to 'PUT' this using curl: curl -X PUT -d keys.json $CDB/_design/id {"error":"bad_request","reason":"invalid UTF-8 JSON"} I know it's not invalid JSON, because I tested it using the 'json' library built into Python 2.6, it loads fine. JS screw ups give me the error 'must evaluate to a function' What else might be wrong with it?

    Read the article

  • How do I put a custom version of node/add form in a view using customfield in drupal 6?

    - by niedakh
    Hi, I'm trying to add a pre-filled 'add reply' form to a view of nodes. Reply is a content-type (reply) with certain fields that need to be prefilled based on what is in the view. This way a user can see only the selected fields from the node/add/reply. At the moment I'm building the forms manually - copy the form from node/add, do some modifications using php & views customfield, but I would like to be able to just push default values to some fields and hide some others and then make drupal render it with all the javascript glory like date select etc. Can this be done?

    Read the article

  • Update {node_counter} table programatically in drupal

    - by wiifm69
    I currently use the statistics module (core) on my Drupal 6 install. This increments a count in the {node_counter} table every time the node is viewed, and this works. My question is - can I programmatically increment this counter as well? I am looking to achieve this when users interact with content created from views (say click a lightbox), so being able to update the table with AJAX would be ideal. I have done a quick search on d.o and there doesn't appear to be any modules that stick out straight away. Does anyone have any experience with this?

    Read the article

  • Django foreign key question

    - by Hulk
    All, i have the following model defined, class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() AND IN MY VIEWS I HAVE p= header(title=name,created_by=id) p.save() Now the data will be saved to header table .My question is that for this id generated in header table how will save the data to criteria and options table..Please let me know.. Thanks..

    Read the article

  • Django javascript escape characters

    - by Hulk
    There is a text area in which the data is entered as, 122 //Enter button pushed Address Name //Enter button pushed 1 And the same is tored in the db.And the data is fetched in views and returned it to template as, <script> {% for i in dict.row_arr %} var ii= ('{{ i }}'); row_arr.push( ii ); {% endfor %} </script> Here there is an error as Error: unterminated string literal Line: 40, Column: 12 Source Code: var ii= ('1212 And when the html source shows up as, var ii= ('1212 1 21 11212121212'); row_arr.push( ii ); How should the escape function be applied here. Thanks..

    Read the article

  • Drupal: Sorting a view programmatically

    - by Ace
    Hey there. I'm trying to take the results of a view - using the function views_get_view_result() - and sort the array in a way I couldn't do from within the Views interface. So far so good. I've got a $rows variable with all of the stuff I need. Now... How do I put it back? :) Before I needed this sort, I used views_embed_view(), but I can't do that anymore. Grateful for any help on this, feels like I'm so close to cracking it!

    Read the article

  • Drupal: How can one use Context to trigger a reaction for a Taxonomy Term condition caused by a Vie

    - by jschrab
    What I would like to do is use the Context module to insert $body_classes of my choosing based on a Taxonomy Term condition. Fine, that's what the Context module is for. Seems simple enough IF your content/page source is a node that is involved with the appropriate Terms. However, I have a page generated by Views that has the appropriate Taxonomy Term id that SHOULD trigger the condition but it doesn't. Now I could set my $body_classes in a "preprocess" in template.php but I'd rather avoid that. Is this even possible in Context? Or am I just doing something wrong?

    Read the article

  • How do you separate the template of a blog block in Drupal?

    - by Ralph
    Hi, In Drupal, I created a block using views. This block contains the latest blog entries. I've placed this on a specific page to display it as an archive. Now, as for the blog itself (for example when one of them is clicked), A blog template for it depends on node-blog.tpl.php. My problem is, when I style node-blog.tpl.php, the block I created for the archives (as it displays on the page) gets affected. For example if I add TEST on node-blog.tpl.php, I will also get that on the block for every entry. I think it's because it is associated to a blog entry? What I want is to have node-blog styled "alone" when blog entries are viewed individually and not get the other entries on the blocks on the archive page be affected. How should I do this?

    Read the article

  • Django models avaoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

    Read the article

  • Django models avoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

    Read the article

  • ASP.NET MVC: Is it "wrong" to use HTTP 500 via an AJAX request to return invalid form content?

    - by Daniel Schaffer
    Here's the situation: I've got two partial views. One has a form. What needs to happen is when the form is posted via an AJAX request, if the operation succeeds, the area with the second partial is repopulated with the content. However, if the posted data was invalid, the original partial is repopulated with an error message. I'm using jQuery and the ajaxForm plugin to handle the form posts and responses. Would it be "wrong"/bad coding/wtf-worthy to conditionally use $.html() to replace the content in one area when it's a 200, and a different area if it's a 500? To me, this idea smells, but I'm not sure how else to accomplish the goal.

    Read the article

  • Drupal 5: CCK fields in custom content type

    - by Kuroki Kaze
    I have module that implements custom content type via NodeAPI hooks (hook_insert, hook_update etc). I want to add CCK field to this content type and populate it via hook_nodeapi calls like create or update (to show content nodes in Views). Problem is, I cannot access CCK fields for this content type. Sure, it's enabled on "Manage Fields" page, but when I load any node of this type with Devel module, I cannot see field attribute (field_flag) in node object. I can see it under "Dev Render" tab as part of "content" attribute, like $node-content['field_flag']['#value'], but if I assign value to $node-field_flag or $node-content['field_flag']['#value'] and call node_save, CCK fields are not saved. Maybe I must call some other function to save CCK fields? Or what may be wrong with this setup?

    Read the article

  • Drupal 6 - Including a module form in a view

    - by espais
    I'm making use of the Favorites module, in order to allow my users to favorite nodes they like. Currently, I know that there is a block available for listing out the favorites, along with the 'Add to favorites' button at the top of this list. What I'd like to do is generate the form which includes the button, and include it within each node that I generate. I'd gotten it hacked up and quickly working by copying the generated form and placing it in my views-view--fields-.tpl.php template, however I believe that doing it this way goes against the thought behind Drupal, and probably introduces security issues with the form_id and form_token being hand-written. I've attempted to call the get_form function, and have passed it the form_id that I found in the generated form code, however I can't get Drupal to recognize it. From some Googling I've noticed that generating module forms programmatically may require a hook, but I haven't been able to find any good examples of this. What is the best way to go about creating this form?

    Read the article

< Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >