Search Results

Search found 5589 results on 224 pages for 'materialized views'.

Page 27/224 | < Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >

  • counter variable not working?

    - by jaycode
    Just like many things in rails, sometimes it works, sometimes it doesn't... Showing app/views/admin/products/_variant.html.erb where line #8 raised: undefined local variable or method `variant_counter' for #<ActionView::Base:0x107f7ae10> I only want to display variant_counter from partial _variant. This was the render caller code: <%= render :partial => '/admin/products/variant', :collection => product.variants %> The funny thing is, I have been using partial counter heaps number of times, somehow now I encountered this issue. Could anybody point me out what are there to find out what may went wrong?

    Read the article

  • Switch from a View (Login) to another View with a TabBarController

    - by Raphael
    Hi, i'm new at Iphone SDK Developing and now i need some help. I have a LoginView where the User have to authentificate his legitimacy. After he enter his Username and Passwort he click on the "Sign In" Button. Then i want to load my "Real-App". Here is the Problem because i can't switch from the LoginScreen to the TabBarController. I found many solutions but only for switching to other views. Is there a way to do it ?

    Read the article

  • Drupal 6 / Views2 Grid style: whole cells link to nodes

    - by jackocnr
    I have a Users page, which is simply a nicely styled grid (HTML table) of users. I'm displaying a few fields for each one, and both the name and the profile picture have been set to link to the user node. What is the best way to change it so that the whole cell (HTML td) links to the user node? Would you have to use javascript? I've looked into modifying the theme of the view (over-riding the Style output e.g. views-view-grid--users.tpl.php), but cant see an elegant way to get the URL of the user node. And I think you would have to use javascript anyway to turn a whole block element into a link.

    Read the article

  • Add image gallery to node in Drupal

    - by vian
    I'm using Image module for Drupal 6 and the submodule of Image Gallery. Image gallery is identified by taxonomy term of certain vocabulary. What I need is to attach Image Gallery View supplied with Image Gallery to certain node. I am now trying to use Views Attach to do this. But how can I pass an argument of taxonomy term for gallery to the view? Also I added the taxonomy term for gallery to be defined for both images and my node type. Is it ok?

    Read the article

  • How do I do a grouping by year?

    - by kibyegn
    I have a books model with a date type column named publish_date. On my views I'm iterating through the books and I want to group the books by year such that I have a heading for every year and books that were published on that year to be listed below the year heading. So by starting with "2010" all books published on 2010 would be listed, then another heading "2009" with all books published in 2009 listed below it and so forth. <% @all_books.each do |book| %> <%=link_to book.title + ", (PDF, " + get_file_size(book.size) + ")" %> <% end %> By doing a book.publish_date.strftime("%Y") I am able to get the year but I do not know how to group the entries by year. Any help on this would be appreciated.

    Read the article

  • How do I get selected background color from SecondView to pass to FirstView?

    - by rob
    I am going insane! This is a simple app with two Views. FirstView is a text field with info button to flip to SecondView. In SecondView I have 6 buttons for background color choice. When button is pushed the color of background changes perfectly but cannot make it also change background color for FirstView. Any help would be GREAT! Thanks! I am using Objective C class working on a iPhone app. Sorry new at this. The SecondView acts almost like a settings page in the fact that when a button is pushed the background color changes to the button color. I need it so when I push the "back" button to go back to FirstView the background color has also changed to that color choice. Been thru sooooooooo many tutorials and codes that now I am totally lost......... Thanks again!

    Read the article

  • How do I use master page container in partial view

    - by user200295
    I have several partial views with Javascript that I am trying to move to the bottom of the page. To do this I am trying to use a container in the master page Master Page - <asp:ContentPlaceHolder ID="Foot" runat="server"></asp:ContentPlaceHolder> Partial view(ascx) <asp:Content ID="header" ContentPlaceHolderID="head" runat="server"> ... </asp:Content> But I get this error Parser Error Message: Content controls have to be top-level controls in a content page or a nested master page that references a master page. So how do I ensure that the Javascript for the partial view is at the bottom of the page? Especially in cases where the html layout needs to be at the top of the page?

    Read the article

  • Best way to manage a header navigation menu from within a template?

    - by Stefan Kendall
    I'm looking to put navigation in my GSP template, and I would like to set the active class on the navigation elements for each respective page. What's the best way to do this? I have several .gsp views merging with a single template that looks like this: <div id="bd" role="main"> <div role="navigation" class="yui-g"> <ul id="nav"><a href="index.gsp"><li class="active">Home</li></a><a href = "products.gsp"><li>Products</li></a><a href = "contacts.gsp"><li>Contact</li></a></ul> </div> <g:layoutBody/> </div>

    Read the article

  • Drupal - Getting node id from view to customise link in block

    - by hfidgen
    I got a little problem with Drupal (again) in that I'm trying to work out how I can build a block which is able to show the node ID of the view page the block is currently sitting on. I'm using views to build a large chunk of my site, but I need to be able to make "intelligent" blocks in PHP mode which will have dynamic content depending on what the view is displaying. So.. how can I go about finding the $nid which a view is currently displaying?! Any ideas?

    Read the article

  • Dynamically render partial templates using mustache

    - by btakita
    Is there a way to dynamically inject partial templates (and have it work the same way in both Ruby & Javascript)? Basically, I'm trying to render different types of objects in a list. The best I can come up with is this: <div class="items"> {{#items}} <div class="item"> {{#is_message}} {{< message}} {{/is_message}} {{^is_message}} {{#is_picture}} {{< picture}} {{/is_picture}} {{^is_picture}} {{/is_picture}} {{/is_message}} </div> {{/items}} </div> For obvious reasons, I'm not super-psyched about this approach. Is there a better way? Also note that the different types of models for the views can have non-similar fields. I suppose I could always go to the lowest common denominator and have the data hash contain the html, however I would rather use the mustache templates.

    Read the article

  • using jquery to parse XML export in drupal

    - by gables20
    I need to use jquery to parse a drupal xml export that was created with views datasource module. The format of the xml export is shown below and on the browser, its access by entering, say for example, http://mydomain/test.xml, where test.xml represents the path of the xml export. <node> <node> <nothing> Lorem ipsum </nothing> </node> <node> The jquery to parse xml is shown below. But, it does nothing, which is kind of the main problem. $(document).ready(function(){ $.ajax({ type: "GET", url: "http://mydomain/test.xml", dataType: "xml", success: function(xml){ $(xml).find('node').each(function(){ var title = $(this).find('nothing').text(); $('#output').append($(this).find('nothing').text()); }); } }); });

    Read the article

  • Drupal: create a node with employee working hours

    - by JMarshall
    I have a bit complicated task. 1. I need to create a node with employee working hours (it's gonna be created for all users with role "employee"), which looks like this: Monday: From __ : __ To __ : __ Tuesday: From __ : __ To __ : __ Wednesday: From __ : __ To __ : __ etc. So, I'll have to create probably 14 CCK fields (monday_from, monday_to, tuesday_from...) or more to store the day of the week and workging hours (hours and minutes). 2. I need to add a view with exposed filters, where visitors can filter employees by day of the week and working hours. What kind of field should I use for working hours? How could views filtering described above be achieved? Any suggestions are greatly appreciated. Thank you!

    Read the article

  • Passing Values from a View to itself with parameters getting null values ?

    - by vsj
    Hi all, I am trying to get values from a view which i have the code below and I am taking the start date value from the view input text box and posting it back but I am still getting null except for the apikey and userkey.Here are the two views.. public ActionResult View1(string apiKey, string userId) { StartGoalViewModel vm = new StartGoalViewModel(); vm.ApiKey = apiKey; vm.UserId = userId; vm.GoalTypeId =1; vm.StartDate = null; return View(vm); } VIEW1.ASPX <% Html.BeginForm(); %> <%= Html.TextBox("name", Model.StartDate) %> <input type="submit" value="Start" /> <% Html.EndForm(); %> [HttpPost] public ActionResult VIEW1 (StartGoalViewModel fm) { // I get StartDate null... }

    Read the article

  • What is an alternative to eval in this situation?

    - by CppLearner
    Many of my view functions do similar things. For the most part, they reverse to a different views upon clicking a button / a text link. So I wrote a helper function render_reverse def render_reverse(f, args): # args are all string type return eval('reverse(' + f + ', ' + args + ')' ) eval is a bad practice, and is pretty slow. It takes 3 seconds to start redirecting, whereas calling reverse directly takes less than 1 second to start redirecting. What alternative do I have? By the way, the function above doesn't work properly. I was modelling after this line (which works) eval('reverse("homepage", args=["abcdefg"])') Thanks.

    Read the article

  • mod_rewite Rule: root/? root/app/views/home/home.php

    - by Jonathon David Oates
    I am shocking at mod_rewite, here's the scenario: I need a rule that rewrites mydomain.com to mydomain.com/app/views/home/home.php. The rule, or set of rules rather, must also rewite mydomain.com/signin to mydomain.com/app/views/signin/signin.php, and work in a similar fashion for any subdirectory, for example: mydomain.com/subdir must redirect to mydomain.com/app/views/subdir/subdir.php. The rules must also work with or without the trailing slash, for example: ….com or ….com/. Thank you all, your help is much appreciated! If you could outline how and why your solution works or direct me to a good resource that explains it, I'd be exceptionally grateful! Edit: I have got a simple .htaccess file with this: Options +FollowSymLinks RewriteEngine On RewriteRule ^$ http://mydomain.local/~Jay/some_awesome_app/app/views/home/home.php This does the redirect but changes the URL in the address bar too! I've not got a trailing [R] flag so why would this be?

    Read the article

  • Return template as string - Django

    - by Ninefingers
    Hi All, I'm still not sure this is the correct way to go about this, maybe not, but I'll ask anyway. I'd like to re-write wordpress (justification: because I can) albeit more simply myself in Django and I'm looking to be able to configure elements in different ways on the page. So for example I might have: Blog models A site update message model A latest comments model. Now, for each page on the site I want the user to be able to choose the order of and any items that go on it. In my thought process, this would work something like: class Page(models.Model) Slug = models.CharField(max_length=100) class PageItem(models.Model) Page = models.ForeignKey(Page) ItemType = models.CharField(max_length=100) InstanceNum = models.IntegerField() # all models have primary keys. Then, ideally, my template would loop through all the PageItems in a page which is easy enough to do. But what if my page item is a site update as opposed to a blog post? Basically, I am thinking I'd like to pull different item types back in different orders and display them using the appropriate templates. Now, I thought one way to do this would be to, in views.py, to loop through all of the objects and call the appropriate view function, return a bit of html as a string and then pipe that into the resultant template. My question is - is this the best way to go about doing things? If so, how do I do it? If not, which way should I be going? I'm pretty new to Django so I'm still learning what it can and can't do, so please bear with me. I've checked SO for dupes and don't think this has been asked before...

    Read the article

  • MVC2: Validate PartialView before Form Submit of Page containing Partial View

    - by Pascal
    I am using asp.net mvc2 and having a basic Page that includes a Partial View within a form <% using (Html.BeginForm()) { %> <% Html.RenderAction("partialViewActionName", "Controllername"); %> <input type="submit" value="Weiter" /> <% } %> When I submit the form, the httpPost Action of my Page is called, and AFTER that the httpPost Action of my Partial View is called [HttpPost] public virtual ActionResult PagePostMethod(myModel model) { // here I should know about the validation of my partial View // If partialView.ModelState is valid then // return View("success"); // else return View(model) } [HttpPost] public virtual ActionResult partialViewActionName(myModel model) { ModelState.AddModelError("Error"); return View(model); } But as I am doing the Validation in the httpPost Method of my Partial View (because I want to use my Partial View in several Places) I cant decide if my hole page is valid or not. Has anyone an Idea how I could do this? Isn´t it a common task to have several partial Views in a page but have the information about validation in the page action methods? Thanks very much for your help!!

    Read the article

  • Where is my Drupal View pager?

    - by anotherthink
    Hi, I have a Drupal 6 site where I've created a view that shows a list of nodes. Nothing complicated -- except that when I choose "use pager" -- "yes" (and choose the "full pager" option), the pager doesn't show up on the page. The first page of nodes shows up, but there's no way to get to other pages. Through googling, I saw that some people had an issue with the "Pager Element" item, so I changed that from 0 to 1 -- no luck. This shouldn't be very complicated, but I've been at it for a while! Help!? ETA: I've tracked it down to the following lines in /modules/views/theme/theme.inc: $pager_theme = views_theme_functions($pager_type, $view, $view->display_handler->display); $vars['pager'] = theme($pager_theme, $exposed_input, $view->pager['items_per_page'], $view->pager['element']); The first line returns an array; the second line returns nothing. I suspect now that this is a theming problem with the custom theme I'm using that may not have fully been correctly updated for Drupal 6 -- like, maybe I'm missing a pager template somehow? -- however, I'm quite new to Drupal and don't really understand how to further track down and fix the issue. Any advice would be much appreciated! ETA yet again: The pager also doesn't show up when using Garland, so it's not a theme issue after all. ALSO: I have a copy of this site set up on a development server as well, and that copy has working pagination! I've checked what I thought might be different -- files in the theme, what modules are enabled -- and it seems like pretty much everything is the same. The one thing that I know is different, however, is that the production server has a lower version of MySQL (lower than recommended for Drupal 6 -- we're waiting on the hosting company being able to change this later). Would it make sense that the old version of MySQL is unable to do pagination correctly in Drupal 6? If so, does anyone know a workaround I can do until we are able to update MySQL?

    Read the article

  • Custom view with nib as subview doesn't seem to be loading

    - by Ben Collins
    I've created a custom view that loads its content from a nib, like this: /* PricingDataView.h */ #import <UIKit/UIKIt.h> @interface PricingDataView : UIView { UIView *contentView; } @property (nonatomic, retain) IBOutlet UIView *contentView; @end /* PricingDataView.m */ #import "PricingDataView.h" @implementation PricingDataView @synthesize contentView; - (id)initWithFrame:(CGRect)frame { if ((self = [super initWithFrame:frame])) { [[NSBundle mainBundle] loadNibNamed:@"PricingDataView" owner:self options:nil]; [contentView setFrame:frame]; [self addSubview:contentView]; } return self; } /* ... */ In the nib file I set PricingDataView as the type of the File's Owner, and connected the contentView outlet in IB. I placed a regular UIView from the Interface Library onto the full-sized view shown to the user, and then changed it's class name to PricingDataView. It all builds, but at runtime, nothing is rendered where my custom view is supposed to be. I put breakpoints in PricingDataView.initWithFrame, but they don't hit, so I know I'm missing something that would cause the view to be initialized. What I'm curious about is that int the process of loading my other views from nibs, all the initialization happens for me, but not with this one. Why?

    Read the article

  • How to html encode the output of an NHaml view (or any MVC view)?

    - by jessegavin
    I have several views written in NHaml that I would like to render as encoded html. Here's one. %table.data %thead %tr %th Country Name %th ISO 2 %th ISO 3 %th ISO # %tbody - foreach(var c in ViewData.Model.Countries) %tr %td =c.Name %td =c.Alpha2 %td =c.Alpha3 %td =c.Number I know that NHaml provides syntax to Html encode the output for given lines using &=. However, in order to encode the entire view, I would essentially lose the benefit of writing my view in NHaml since it would have to look like this.... &= "<table class='data'> &= " <thead> So I was wondering if there was any cool way to be able to capture the rendered view as a string, then to html encode that string. Maybe something like the following??? public ContentResult HtmlTable(string format) { var m = new CountryViewModel(); m.Countries = _countryService.GetAll(); // Somehow render the view and store it as a string? // Not sure how to achieve this. var viewHtml = View("HtmlTable", m); // ??? return Content(viewHtml); } This question may actually have no particular relevance to the View engine that I am using I guess. Any help or thoughts would be appreciated.

    Read the article

  • How can use the currently displayed node to filter a block-level view on that node's page?

    - by Deane
    I have parent/child relationship set up via Node Reference. A Child record can have a Parent record selected from a Node Reference field (this is optional -- I can have Parent-less Children as well). I've created a Views block to appear on the Parent pages, below the content. It's going to show a table of all the Child nodes for that Parent. Problem is, right now it shows every Child node. I need to filter it for just the Parent being displayed. What I need to be able to do is add a filter to this View to effectively say, "Only show the Child nodes that are assigned to the Parent being displayed on this page." So, somehow I need to be able to get the Nid of the currently displaying node (which will be a Parent, in all cases when this block is displayed), and use that in a filter in my View. How exactly can I do this? (Initially I used an attachment view for this (as this page instructs). I created a page view to display the Parent, then an attachment view to display all the Children, then attached that under the page view. This worked, but it was almost absurdly complicated to set up, and it was an undesirable for a number of other reasons -- primarily that my Parent now has two dedicated URLs, it's own node-level page, and the similar page created by this view.) Using Drupal 6.15.

    Read the article

  • Drupal: Template Files, Modules and Content Types for Advanced Theme

    - by theandym
    Intro I am in the process of trying to convert my first HTML/CSS design into a theme for Drupal. I have used ModX for quite a few designs and appreciate the ability to create different page templates and custom variables to be assigned to those templates. However I seem to be having some issues making the transition. The site I am working on theming in Drupal is for a real estate agent. Each page/section will have a different set of content associated with it and will need to display only that content. For example, there will be a page for current listings, each of which will be formatted by a custom content type. However, when I call the content on the home page (or on other pages) I do not want to see this listing data. Layout The layout of the site and the regions associated with each page/section is as follows: Home Spotlight Featured 1 Featured 2 About Spotlight Bios - Profiles of each agent (each will be a node with name, contact info, pic, etc) listed on the page; multiple nodes listed Sidebar Listings Spotlight Listings - Profiles of properties (each will be a node with locations, basic info, pic, etc) listed on the page; multiple nodes listed Sidebar Services Spotlight Content - general paragraph text area Sidebar News/Blog News/Blog Items - List of stories with summaries and links to full article Sidebar Each page/section will use the same header and footer. Issue I have done some reading on Drupal, custom content types (and CCK), Views, and Pathauto. However I have not been able to get a clear picture of how to put it all together to accomplish what I am attempting. What I really would like to know is which modules to use, how best to use them, which elements I need to use where, and what template files I should be using to theme the elements I need to use. Any help or reference to useful resources would be much appreciated.

    Read the article

  • Drupal 6: How to quickly theme a view ?

    - by Pierre-Jean Coudert
    I've defined a view with the cck and view2 modules. I would like to quickly define a template specific to this view. Any tutorial or information on this ? What are the files I need to modify ? Here are my findings: (Edited) In fact there are two ways to theme a view : the "field" way and the "node" way. In "edit View", you can choose "Row style: Node", or "Row style: Fields". with the "Node" way, you can create a node-contentname.tpl.php wich will be called for each node in the view. You'll have access to your cck field values with $field_name[0]['value']. (edit2) You can use node-view-viewname.tpl.php wich will be only called for each node displayed from this view. with the "Field" way, you add a views-view-field--viewname--field-name-value.tpl.php for each field you want to theme individually. Thanks to previous responses, I've used the following tools : In the 'Basic Settings' block, the 'Theme: Information' to see all the different templates you can modify. The Devel module's "Theme developer" to quickly find the field variable names. View 2 documentation, especially the "Using Theme" page.

    Read the article

  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

    Read the article

  • What is the best way using multiple lines of <% %> Tag or <% %> Tag with multiple lines?

    - by Salil
    Sorry if the title is not enough to understand what i am asking about. I am rails developer and i used multiple lines of <% % in my views but now i realized that it's not best practice so i came here and like to you all excellent guys what is the correct way in ROR? For example if i required to something like following <% user =User.all %> <% name= [] %> <% count = 0 %> <% for user in users %> <% name << user.name %> <% count+=1%> <% end %> Can i do it as follows ? <% user =User.all name= [] count = 0 for user in users name << user.name count+=1 end %> I know better way of collecting element from array But above is just example. But my question is, is it possible and if yes which is the correct way?

    Read the article

< Previous Page | 23 24 25 26 27 28 29 30 31 32 33 34  | Next Page >